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Course 3
11-2 Solving Multi-Step Equations 11-2 Solving Multi-Step Equations
Course 3
Warm Up
Problem of the Day
Lesson Presentation
Course 3
11-2 Solving Multi-Step Equations
Warm Up Solve.
1. 3x = 102
2. = 15
3. z – 100 = 21
4. 1.1 + 5w = 98.6
x = 34
y = 225
z = 121
w = 19.5
y 15
Course 3
11-2 Solving Multi-Step Equations
Problem of the Day
Ana has twice as much money as Ben, and Ben has three times as much as Clio. Together they have $160. How much does each person have? Ana, $96; Ben, $48; Clio, $16
Course 3
11-2 Solving Multi-Step Equations
Learn to solve multi-step equations.
Course 3
11-2 Solving Multi-Step Equations
To solve a multi-step equation, you may have to simplify the equation first by combining like terms.
Course 3
11-2 Solving Multi-Step Equations
Solve.
8x + 6 + 3x – 2 = 37
Additional Example 1: Solving Equations That
Contain Like Terms
11x + 4 = 37 Combine like terms.
– 4 – 4 Subtract 4 from both sides.
11x = 33
x = 3
Divide both sides by 11. 33 11
11x 11
=
Course 3
11-2 Solving Multi-Step Equations
Check
Additional Example 1 Continued
8x + 6 + 3x – 2 = 37
8(3) + 6 + 3(3) – 2 = 37 ?
24 + 6 + 9 – 2 = 37 ?
37 = 37 ?
Substitute 3 for x.
Course 3
11-2 Solving Multi-Step Equations
Solve.
9x + 5 + 4x – 2 = 42
Check It Out: Example 1
13x + 3 = 42 Combine like terms.
– 3 – 3 Subtract 3 from both sides.
13x = 39
x = 3
Divide both sides by 13. 39 13
13x 13
=
Course 3
11-2 Solving Multi-Step Equations
Check
Check It Out: Example 1 Continued
9x + 5 + 4x – 2 = 42
9(3) + 5 + 4(3) – 2 = 42 ?
27 + 5 + 12 – 2 = 42 ?
42 = 42 ?
Substitute 3 for x.
Course 3
11-2 Solving Multi-Step Equations
If an equation contains fractions, it may help to multiply both sides of the equation by the least common denominator (LCD) to clear the fractions before you isolate the variable.
Course 3
11-2 Solving Multi-Step Equations
Solve.
+ = –
Additional Example 2A: Solving Equations That
Contain Fractions
3 4
7 4
5n 4
Multiply both sides by 4 to clear fractions, and then solve.
7 4
–3 4
5n 4
4 + = 4 ( ) ( )
( ) ( ) ( ) 5n 4
7 4
–3 4
4 + 4 = 4
5n + 7 = –3
Distributive Property.
Course 3
11-2 Solving Multi-Step Equations
Additional Example 2A Continued
5n + 7 = –3
– 7 –7 Subtract 7 from both sides.
5n = –10
5n 5
–10 5
= Divide both sides by 5
n = –2
Course 3
11-2 Solving Multi-Step Equations
The least common denominator (LCD) is the smallest number that each of the denominators will divide into.
Remember!
Course 3
11-2 Solving Multi-Step Equations
Solve.
+ – =
Additional Example 2B: Solving Equations That
Contain Fractions
2 3
The LCD is 18.
x 2
7x 9
17 9
18( ) + 18( ) – 18( ) = 18( ) 7x 9
x 2
17 9
2 3
14x + 9x – 34 = 12
23x – 34 = 12 Combine like terms.
( ) ( ) x 2
2 3
7x 9
17 9
18 + – = 18
Distributive Property.
Multiply both sides by 18.
Course 3
11-2 Solving Multi-Step Equations
Additional Example 2B Continued
23x = 46
= 23x 23
46 23
Divide both sides by 23.
x = 2
+ 34 + 34 Add 34 to both sides.
23x – 34 = 12 Combine like terms.
Course 3
11-2 Solving Multi-Step Equations
Additional Example 2B Continued
6 9
6 9
= ?
Check
x 2
7x 9
17 9
+ – = 2 3
2 3
Substitute 2 for x. 7(2) 9
+ – = (2) 2
17 9
?
2 3
14 9
+ – = 2 2
17 9
?
2 3
14 9
+ – =
17 9
? 1
The LCD is 9. 6 9
14 9
+ – = 9 9
17 9
?
Course 3
11-2 Solving Multi-Step Equations
Solve.
+ = –
Check It Out: Example 2A
1 4
5 4
3n 4
Multiply both sides by 4 to clear fractions, and then solve.
( ) ( ) 5 4
–1 4
3n 4
4 + = 4
( ) ( ) ( ) 3n 4
5 4
–1 4
4 + 4 = 4
3n + 5 = –1
Distributive Property.
Course 3
11-2 Solving Multi-Step Equations
Check It Out: Example 2A Continued
3n + 5 = –1
– 5 –5 Subtract 5 from both sides.
3n = –6
3n 3
–6 3
= Divide both sides by 3.
n = –2
Course 3
11-2 Solving Multi-Step Equations
Solve.
+ – =
Check It Out: Example 2B
1 3
The LCD is 9.
x 3
5x 9
13 9
9( ) + 9( )– 9( ) = 9( ) 5x 9
x 3
13 9
1 3
5x + 3x – 13 = 3
8x – 13 = 3 Combine like terms.
( ) x 3
1 3
5x 9
13 9
9 + – = 9( ) Distributive Property.
Multiply both sides by 9.
Course 3
11-2 Solving Multi-Step Equations
8x = 16
= 8x 8
16 8
Divide both sides by 8.
x = 2
+ 13 + 13 Add 13 to both sides.
8x – 13 = 3 Combine like terms.
Check It Out: Example 2B Continued
Course 3
11-2 Solving Multi-Step Equations
3 9
3 9
= ?
Check
x 3
5x 9
13 9
+ – = 1 3
1 3
Substitute 2 for x. 5(2) 9
+ – = (2) 3
13 9
?
1 3
10 9
+ – = 2 3
13 9
?
The LCD is 9. 3 9
10 9
+ – = 6 9
13 9
?
Check It Out: Example 2B Continued
Course 3
11-2 Solving Multi-Step Equations
On Monday, David rides his bicycle m miles in 2 hours. On Tuesday, he rides three times as far in 5 hours. If his average speed for two days is 12 mi/h, how far did he ride on the second day? Round your answer to the nearest tenth of a mile.
Additional Example 3: Travel Application
David’s average speed is his combined speeds for the two days divided by 2.
average speed = Day 1 speed Day 2 speed +
2
Course 3
11-2 Solving Multi-Step Equations
Additional Example 3 Continued
Multiply both sides by the LCD 10.
+
Multiply both sides by 2. 2
2 = 2(12)
3m5
m2
m2
10 = 10(24) 3m5
+
m 2
Substitute for Day 1 speed
and for Day 2 speed. 3m 5
m2
2 = 12
3m5
+
1
1
Course 3
11-2 Solving Multi-Step Equations
Additional Example 3 Continued
5m + 6m = 240
On the second day David rode 3 times m (3m) or approximately 65.5 miles.
Combine like terms. Divide both sides by 11.
m ≈ 21.82
Simplify.
240 11
11m11
=
Course 3
11-2 Solving Multi-Step Equations
On Saturday, Penelope rode her scooter m miles in 3 hours. On Sunday, she rides twice as far in 7 hours. If her average speed for two days is 20 mi/h, how far did she ride on Sunday? Round your answer to the nearest tenth of a mile.
Check It Out: Example 3
Penelope’s average speed is her combined speeds for the two days divided by 2.
average speed = Day 1 speed Day 2 speed +
2
Course 3
11-2 Solving Multi-Step Equations
Check It Out: Example 3 Continued
Multiply both sides by the LCD 21.
+
Multiply both sides by 2. 2
2 = 2(20)
2m7
m3
m 3
Substitute for Day 1 speed
and for Day 2 speed. 2m 7
m3
21 = 21(40) 2m7
+
m3
2 = 20
2m7
+
1
1
Course 3
11-2 Solving Multi-Step Equations
Check It Out: Example 3 Continued
7m + 6m = 840
On Sunday Penelope rode 2 times m, (2m), or approximately 129.2 miles.
Combine like terms. Divide both sides by 13.
m ≈ 64.62
Simplify.
840 13
13m13
=
Course 3
11-2 Solving Multi-Step Equations
Solve.
1. 6x + 3x – x + 9 = 33
2. –9 = 5x + 21 + 3x
3. + =
5. Linda is paid double her normal hourly rate for each hour she works over 40 hours in a week. Last week she worked 52 hours and earned $544. What is her hourly rate?
Lesson Quiz
x = –3.75
x = 3
x = 28 5 8
x 8
33 8
6x 7
4. – = 2x 21
25 21
$8.50
x = 1 9 16