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Think about the card games we played yesterday. Make a list of numbers that are not changed by the absolute value bars. Make another list of numbers that are changed by the absolute value bars. Write down a general rule that describes what absolute value does to any given number. 3 LaunchLaunch
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Solve Absolute Value Equations
© Evergreen Public Schools 2010
I can write and solve an absolute value equation from a given situation with one variable.
What do you think is the solution to |x + 1| = 5?
2
• Think about the card games we played yesterday.
• Make a list of numbers that are not changed by the absolute value bars.
• Make another list of numbers that are changed by the absolute value bars.
• Write down a general rule that describes what absolute value does to any given number.
x
3
LaunchLaunch
©Evergreen Public Schools 2010 4
Let’s think about |x|
5
• Share with your partner how you answered the questions.
• I will be asking you to tell us what your partner wrote.
• Think about the card games we played yesterday.
• If x is non-negative
• then just write it without the bars.
6
|7| = ?
Let’s think about |x|
|7| = 7
xxxx
x then ,0 if then ,0 if
• If x is non-negative then just write it without the bars.
• If x is negative
• then make it the opposite value.
7
|-4| = ?
Let’s think about |x|
|-4| = 4
Think about the card game yesterday
If we knew the answer was 7, what card could give us that answer?
A positive 7 A negative 7
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Let’s Solve 7 = |x|Since we do not know the value of x, use
the definition for either possibility…
9
x = 7 -x = 7
x = -7
So the solution is x = 7 or x = – 7How is this related to our card game?
Let’s Practice1. |x|= 32. |x|= 03. – |x|= 54. | – x|= 75. |x|= – 12
Private think time
Elbow Partner
10
Remember Round 4 of the Game?
If the dealer turned over a distance card of positive 5,
Starting cardDistance card
The two solutions are …
-7 - 5 5
212
0 11
and the caller turned over a negative of positive 7
Remember Round 4 of the Game?
So, you can add 2 to -7 and be 5 units from zero,
and you can add 12 to -7 and be 5 units
from zero.
-7 - 5 5
212
0
12
Let’s Solve: 5 = |x – 7|
Since we do not know the value of x – 7, use the definition for either possibility…x – 7 = 5
x = 12
So the solution is x = 12 or x = 2
The same solution as the previous slide, but a little faster.
x – 7 = – 5x = 2
13
1. |x – 1|= 02. |-x + 3|= 83. |9 – x|= 24. |2x – 9|= 75. |x – 1|= -¾
Private think time
Elbow Partner
14
Team Practice
1. |x – 1|= 02. |-x + 3|= 83. 3|9 – x|= 64. |2x – 9|= 75. |x – 1|= -3/4
1. x = 12. x = -5 or x =
11 3. x = -11 or x = 7 4. x = 1 or x = 8
5. no solution
15
Team Practice
©Evergreen Public Schools 2010 16
DebriefMake a mini poster to explain your
understanding of solving absolute value equations.
Write an absolute value equation.Show how the following are related• number line• equation• solution• explanation
©Evergreen Public Schools 2010 17
5
3
12
4
Did you hit the target? I can solve inequalities
in one variable.
Rate your understanding of the target from 1 to 5.5 is a bullseye!
©Evergreen Public Schools 2010 18
PracticePractice 5. ___
©Evergreen Public Schools 2010 19
Ticket OutSolve
210−x 16