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Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Textbook Reference : Chapter # 14 Module # 2 CHM 1046 : General Chemistry and Qualitative Analysis

Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

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Page 1: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

Unit 12:Properties of Solutions

Dr. Jorge L. AlonsoMiami-Dade College –

Kendall CampusMiami, FL

Textbook Reference: •Chapter # 14•Module # 2

CHM 1046: General Chemistry and Qualitative Analysis

Page 2: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

Solutions

• Solutions (soln) are homogeneous mixtures of two or more pure substances.

• The solvent (solv) is present in greatest abundance.

• All other substances are solutes (solu).

Volumetric flask

{PrepASolu}

Page 3: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

Solutions• Solutions are homogeneous mixtures

of two or more pure substances.• In a solution, the solute (< 50%) is

dispersed uniformly throughout the solvent (> 50%).

Homogeneous Heterogeneous

Page 4: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

Student, Beware!: solution vs. reaction

Just because a substance disappears when it comes in contact with a solvent, it doesn’t mean the substance dissolved.

• Dissolution is a physical change—you can get back the original solute by evaporating the solvent.

• If you can’t, the substance didn’t dissolve, it reacted.

Mg (s) + 2 HCl (aq) H2 (g) + MgCl2 (aq)Cu(NO3)2 (s) Cu(NO3)2 (aq) H2O

H2O

Page 5: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

How Does a Solution of Salts in Water Form?

NaCl (s) Na+ (aq) + Cl- (aq)dissociation

+ H20

The intermolecular forces between solute and solvent particles must be strong enough to compete with those between solute particles and those between solvent particles.

Example: {NaCl + H2O*}

Page 6: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

Solubility in water

Covalent Compounds: many are insoluble gases, polar covalent are mostly soluble.

Ionic Compounds: many are soluble.SOLUBILITY RULES: for Ionic Compounds (Salts)1. All salts of alkali metals (IA) are soluble.2. All NH4

+ salts are soluble.

3. All salts containing the anions: NO3-, ClO3

-, ClO4-, (C2H3O2

-) are soluble.

4. All Cl-, Br-, and I- are soluble except for Ag+, Pb2+, and Hg22+ salts.

5. All SO42- are soluble except for Pb2+, Sr2+, and Ba2+.

6. All O2- are insoluble except for IA metals Ca2+, Sr2+, and Ba2+ salts.{Soluble metal oxides form hydroxides: CaO Ca 2+ + 2OH-}

7. All OH- are insoluble except for IA metals, NH4+ & slightly soluble Ca 2+ Ba2+ & Sr2+

6. All salts containing the anions: CO32-, PO4

3-, AsO43-, S2- and SO3

2- are insoluble except fro IA metals and NH4

+ salts. 7. For salts containing the anions not mentioned above (e.g., CrO4

2-, Cr2O72-, P3-,

C2O42- etc.) assume that they are insoluble except for IA metals and NH4

+ salts, unless, otherwise informed.

H2O

Elements: mostly insoluble solids, liquids & gases.

Page 7: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

Energetics of Solutions Heats (Enthalpy) of Solution (Hsoln)

Exothermic solution process

NH4NO3 (s) NH4+ (aq) + NO3

-(aq)

CaCl2 (s) Ca 2+(aq) + 2Cl- (aq)

H2O

Endothermic solution process

CaCl2+ H2O

NH4NO3

+H2O

Hsoln = - 81.3 kJ/mol

+ Heat

Hsoln = + 25.7 kJ/mol

Heat +H2O

Hot & Cold Packs

Page 8: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

(3) Formation of Ion-dipole

interactions

How Does a Solution Form? (3 events)

If an ionic salt is soluble in water, it is because the ion-dipole interactions are strong enough to overcome the lattice energy of the salt crystal.

H Lattice Energy

+788 kJ/mol Endothermic

NaCl

Crystal Lattice

H- bonding

H2OHvap

+41 kJ/mol Endothermic

Energy of Solution Hsoln = + or -

(1) Separation of solute molecules

(2) Separation of solvent molecules

Exothermic

Page 9: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

Energy Changes in SolutionThe enthalpy change of the overall process depends on H for each of these steps.

{EnerSoln}

- +

Page 10: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

Exothermic solution process

Endothermic solution process

NH4NO3 (s) NH4+ (aq) + NO3

-(aq)

Hsoln = + 25.7 kJ/mol

CaCl2 (s) Ca 2+ (aq) + 2Cl- (aq)

Hsoln = - 81.3 kJ/mol

H2O

H2O

Why do Endothermic Reactions occur Spontaneously?

Page 11: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

Concentration of Solutions (General)

• SaturatedSolvent holds as much solute as is

possible at that temperature.Dissolved solute is in dynamic

equilibrium with solid solute particles.

• UnsaturatedLess than the maximum amount of

solute for that temperature is dissolved in the solvent.

{UnsatSoln}

Solubility of NaCl in H2O = 35.9 g/100 mL (25 °C)

NaC2H4O2 = 76 g/100 ml (0°C)

Page 12: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

• SupersaturatedSolvent holds more solute than is normally

possible at that temperature.These solutions are unstable; crystallization can

usually be stimulated by adding a “seed crystal” or scratching the side of the flask.

{*SuperSat1} {*SuperSat2}

Concentration of Solutions (General)

Page 13: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

1. Polarity2. Temperature

Factors Affecting Solubility

A. Solids and Liquids:

B. Gases :1. Molar Mass2. Pressure – Henry’s Law3. Temperature

Page 14: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

{Water + Oil}

Factors Affecting Solubility of Solids and Liquids: (1) Polarity

• Chemists use the axiom “like dissolves like”:Polar substances tend to dissolve in polar solvents.Nonpolar substances tend to dissolve in nonpolar solvents.

[Know molecular shapes and polar molecules]

(hydrocarbon chain)hydrophobic water-

hating, nonpolar,

hydrophilic water-loving, polar,

Page 15: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

• Chemists use the axiom “like dissolves like”:Polar substances tend to dissolve in polar solvents.Nonpolar substances tend to dissolve in nonpolar solvents.

Factors Affecting Solubility of Solids and Liquids: (1) Polarity

[Know molecular shapes and polar molecules]

Polar heads

Non-Polar tails

Polar Non-Polar

Page 16: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

Glucose (which has hydrogen bonding) is very soluble in water, while…..

Factors Affecting Solubility of Solids and Liquids: (1) Polarity

…..cyclohexane (which only has dispersion forces) is not.

Page 17: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

• Vitamin A is soluble in nonpolar compounds (like fats).

• Vitamin C is soluble in water. {*Iodine + Water then + CCl4 }

Factors Affecting Solubility of Solids and Liquids: (1) Polarity

Page 18: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

Generally, the solubility of solid solutes in liquid solvents increases with increasing temperature.

Factors Affecting Solubility of Solids and Liquids: (2) Temperature

Page 19: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

Factors Affecting Solubility of Gases in Solution: (1) Molar Mass

• Larger molecules have stronger London dispersion forces.

•In general, the solubility of gases in water increases with increasing molar mass.

g-MM

28 g/n

28 g/n

32 g/n

40 g/n

84 g/n

Why?

Which gas dissolves best in water?

Page 20: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

Factors Affecting Solubility of Gases in Solution:

(2) Pressure

{Henrys Law}

• The solubility of liquids and solids does not change appreciably with pressure.

• The solubility of a gas (Sg) in a liquid is directly proportional to its pressure (Pg).

Sg Pg α

Page 21: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

Henry’s Law:

where

• Sg is the solubility of the gas;

• Pg is the partial pressure of the gas above the liquid.

• k is the Henry’s law constant for that gas in that solvent;

Sg = kPg

Factors Affecting Solubility of Gases in Solution: (2) Pressure

@ 250C, PN2= 0.75 atm, SN2= 0.00053 M.

What is SN2 when PN2 = 1.50 atm?Ans.= 0.00106 M

Pg

Sg

{movie}

Sg Pg α

Page 22: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

• The opposite is true of gases:Gases in carbonated

soft drinks are less soluble when warmed.

Warm lakes have less O2 dissolved in them than cool lakes.

Factors Affecting Solubility of Gases in Solution: (3) Temperature

Page 23: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

Colligative Properties

Pure Solvent Solution: Solvent + Solute

How does the presence of a solute change the properties of a solvent?

1. Vapor pressure?

2. Boiling point?

3. Freezing (melting) point?

4. Osmotic pressure?

Page 24: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

Colligative Properties• Properties that depend only on the

CONCENTRATION (number of solute particles present), not on the identity of the solute particles.

Pure solvent Solvent + Solute

1. Vapor pressure lowering

2. Boiling point elevation

3. Freezing point depression

4. Osmotic pressure

PA = XA PA

Tb = Kb m

Tf = Kf m

= MRT

Page 25: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

Ways of Expressing Concentrations of Solutions

(1) Mass Percentage (%)

(2) Parts per Million (ppm) & Parts per Billion (ppb)

(3) Mole Fraction (X)

(4) Molarity (M)

(5) Molality (m)

Page 26: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

ppm =mass of solu A in solution

total mass of solution 106

Parts per Million (ppm)

ppb =mass of solu A in solution

total mass of solution 109

Mass % of A =mass of solu A in solution

total mass of solution 100 or 102

Mass Percentage (%) (parts per Hundred)

50. g of NaCl in 100.mL of H2O %3.3310333.010g.150

g.50 22

0.0005 g of NaCl in 100.mL of H2O

ppm510000005.010g.100

g0005.0 66

0.000,000,5 g of NaCl in 100.mL of H2O

ppb510)105(10g.100

g5,000,000.0 999

Parts per Billion (ppb)

hundred

million

billion

Page 27: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

moles of substance Atotal moles in solution (A+B+∙∙∙)XA =

Mole Fraction (X)

You can calculate the mole fraction of either the solvent or of the solute — make sure you find the one you need for your calculations!

What are the mole fractions of methanol and water in a solution containing 128g CH3OH (MW=32.0) and 202 mL of H2O (MW=18.0)? Which is the solute and the solvent?

OH2.11g0.18

OH1

mL00.1

g00.1mL202OH? 2

22

OHCH00.4

g0.32

OHCH1g128OHCH? 3

33

263.02.1100.4

00.4

OHOHCH

OHCH

23

3OHCH3

737.0

2.1100.4

2.11

OHOHCH

OH

23

2OH2

1263.0737.0OHCHOH 32

Mole fraction of Solvent:Mole fraction of Solute:

Page 28: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

mol of soluteL of solution

M =

Molarity (M)

• Because volume is temperature dependent, molarity can change with temperature.

{The volume of most substances expand with increasing temperature}

M0.11

mL1000

L1mL202

g791.0

mL00.1g128

g0.32

OHCH1g128 3

OH 2

OH 2LOHCHL

OHCHM

3

3

What is the molarity of a solution containing 128g CH3OH (MW=32.0, d=0.791g/mL@25 C) and 202 mL of H2O (MW=18.0, d=1.00g/mL@25C)?

Page 29: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

moles of solutekg of solvent

m =

Molality (m)

Because both moles and mass do not change with temperature, molality (unlike molarity) is not temperature dependent.

What is the molality of a solution containing 128g CH3OH (MW=32.0, d=0.791g/mL@25 C) and 202 mL of H2O (MW=18.0, d=1.00g/mL@25C)?

m

gkg

g

gOHCH

g

8.19

10001

OH 202

0.321

128

2

3

OH 2

3

kg

OHCHm

Page 30: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

Problem: What is the molality (m) of a 2.0M NaCl solution at 250C if its density is 1.2 g/mL?

Changing Molarity to MolalityIf we know the density of the solution, we can calculate the molality from the molarity, and vice versa.

mol of soluteL of solution

M =mol of solutekg of solvent

m =

soln 1

22

L

NaClM

solv ?

2?

kg

NaClm

Lkg 1soln ?

NaClkgNaCl 2? = 1.8 m NaCl

solv 1.1

2?

kg

NaClm

NaCl 12.01000

1

1

0.58kg

g

kgg

OHNaCl 2.11000

1

1

2.1

1

10002

kgg

kg

mL

g

L

mL

Page 31: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

Colligative Properties• Properties that depend only on the number of

solute particles present, not on the identity of the solute particles.

Pure solvent Solvent + Solute

1. Vapor pressure lowering

2. Boiling point elevation

3. Freezing point depression

4. Osmotic pressure

PA = XA PA

Tb = Kb m

Tf = Kf m

= MRT

Page 32: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

1. Vapor Pressure (Pvap ) Lowering

Because of solute-solvent intermolecular attraction, higher concentrations of nonvolatile solutes make it harder for solvent to escape to the vapor phase.

Therefore, the vapor pressure of a solution (PA ) is lower than that of the pure solvent (PA).

{PureSolv}

{*Solution}PA = XA PA

Page 33: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

Raoult’s Law:

PA = XA P Awhere• XA is the mole fraction of solvent A

• P A is the normal vapor pressure of the pure solvent A at that temperature

• P A is the new vapor pressure of solution at that temperature

Consider: XA= 1 XA= 0.9 XA= 0.5

{VapPress.WaterVsEthGlycol}

Page 34: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

2. Freezing Point Depression & 3. Boiling Point Elevation

Nonvolatile solute-solvent interactions also cause solutions to have higher boiling points and lower freezing points than the pure solvent.

f.pt. Pure solventf.pt. Solutionb.pt.

f.pt.

Page 35: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

Freezing Point Depression

• The change in freezing point is proportional to the molality of the solution :

Tf = Kf m

• Here Kf is the molal freezing point depression constant of the solvent.

Tf is subtracted from the normal freezing point of the solvent.

{f.pt. Equil} {f.pt. Lower}

Page 36: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

Boiling Point Elevation

The change in boiling point is proportional to the molality of the solution:

Tb = Kb m

where Kb is the molal boiling point elevation constant, a property of the solvent.

Tb is added to the normal boiling point of the solvent.

Page 37: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

Freezing Point Depression & Boiling Point Elevation

Note that in both equations, T does not depend on what the solute is, but only on how many particles are dissolved.

Tf = Kf m

Tb = Kb m

Page 38: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

Osmosis• The movement of water from an area of high

concentration to lower concentration (diffusion) across a semipermeable membrane (SPM), until a homogeneous solution has been formed (equilibrium). The SPM allows smaller particles (water) to pass through, but blocks other larger particles.

• Diffusion of water across a SPM.

Diffusion• The movement of particles from an area of high

concentration to lower concentration until a homogeneous solution has been formed.

Page 39: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

OsmosisIn osmosis, there is net movement of solvent from the area of higher solvent concentration (lower solute concentration) to the area of lower solvent concentration (higher solute concentration).

{*OsmoPress}

SolventSolution

Page 40: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

{*OsmoSemiPerMemb}

Solution side (Low Conc. H2O)

Solvent side (High Conc. H2O)SPM

Page 41: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

Osmosis in Cells• If the water concentration outside the cell is more than that inside the cell, the solution is hypotonic (low in solute).

• Water will flow into the cell, and hemolysis results.

{EggOsmoPres}

H2O

H2O H2O

H2O

H2O

H2O

H2O

H2O

H2O

H2O

H2O

H2O

High Water

Low Water

H2O

H2O

H2O

H2O

H2O

(high solute)

(low solute)

Page 42: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

Osmosis in Blood Cells• If the water

concentration outside the cell is lower than that inside the cell, the solution is hypertonic (high in solute).

• Water will flow out of the cell, and crenation results.

• Isotonic: equal concentrations.

H2O

H2OH2O

H2O

H2O

H2O

H2O

H2O

H2O

H2O

(salt water)

(salt water)

(salt water)

(salt

water)

High Water

(high solute)

(low solute)

H2O

H2O

H2O

H2O

Page 43: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

3. Osmotic Pressure• The pressure required to stop osmosis,

known as osmotic pressure, , is

nV

= ( )RT

where M is the molarity of the solution

V = n RT

= MRT

Page 44: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

Reverse Osmosis

The method of purifying liquid by pushing it through a semi-permeable membrane. Pressure is utilized to reverse the natural osmotic flow through a synthetic membrane so that pure water molecules pass through and impurities are flushed away.

{RevOsmo}

Membrane

H2O H2O H2O

Contaminated water

Reverse Osmosis {RevOsmo}

Membrane

H2O H2O H2OPure H2O

Contaminated water

Page 45: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

Determining Molar Mass from Colligative Properties

K

ΔT m

b

b

We can use the effects of a colligative property such as freezing point depression to determine the molar mass (MM) of a compound.

A solution of an unknown nonvolatile electrolyte was prepared by dissolving 0.250g of the substance in 40.0 g of CCl4. The b. pt. of the resultant solution was 0.357 0C higher than that of the pure solvent. What is MM of solute? The Kb for CCl4 is 5.02 0C/m.

Tb = Kb m m 0.0711 m

0.357

0

0

/C02.5

C

solu10 x 2.84 CCl of kg 0.0400 CCl of kg

solu 3-

4

4

0711.0

g#

MM

g/ 88.0 10 x 2.84

g 0.250

3-

solvkg

moles m where

MM

g# )( moles

Page 46: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

Determining Molar Mass from Colligative Properties

We can use the effects of a colligative property such as osmotic pressure to determine the molar mass of a compound.

= MRT

Liter

moles M where

MM

g# )( moles

RT

M

/L 10x 8.28 K 982K

atm L 0.082

torr760

atm 1 torr1.54

3-

L 8.28x10 M 3-

7-10 x .144 mL 00.5

mL 1000

L1

g#

MM

g8.45x10

10x 4.14mg 1000

g 1x mg .503

3

7-

The osmotic pressure of a protein solution was measured @ 250C to be 1.54 torr. The solution contained 3.50 mg of protein dissolved in water to make 5.00 mL of solution. Determine the molar mass (MM) of the protein.

Page 47: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions = MRT

Vapor pressure lowering:

Boiling point elevation:

Freezing point depression:

Osmotic pressure:

Tf = Kf m

PA = XA PA

Colligative Properties & Molar Mass

= PA

Tb = Kb m = Kb

= Kf

= RT

lnso

solu

LMW

g#

solv

solu

KgMW

g#

solv

solu

KgMW

g#

ABA

A

MWg

#

1

1

Page 48: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

Colligative Properties of ElectrolytesSince these properties depend on the number of particles dissolved, solutions of electrolytes (which dissociate in solution) should show greater changes than those of nonelectrolytes.

You would expect a 1 M solution of CaCl2 to show three times the change in freezing point that a 1 M solution of C6H12O6, however …………….

CaCl2 (s) Ca 2+ (aq) + 2Cl- (aq)H2O

C6H12O6 (s) C6H12O6 (aq) H2O1η 1 η molecules

1η 3 η ions

Non-electrolyte:

Electrolyte:

Page 49: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

van’t Hoff Factor

One mole of NaCl in water does not really give rise to two moles of ions.

Some Na+ and Cl− reassociate for a short time, so the true concentration of particles is somewhat less than two times the concentration of NaCl.

• Reassociation is more likely at higher concentration.• Therefore, the number of particles present is concentration

dependent.

Page 50: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

The van’t Hoff FactorWe modify the previous equations for Colligative Properties by

multiplying them by the van’t Hoff factor, i• Equations

Vapor pressure lowering:

Boiling point elevation:

Freezing point depression:

Osmotic pressure: = i MRT

Tb = i Kb m

Tf = i Kf m

PA = i XAPA

Page 51: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

Colloidal Dispersion

homogeneous mixtures of particles larger than individual ions or molecules, but too small to be settled out by gravity.

Page 52: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

Tyndall Effect

The scattering of light by colloids.

Page 53: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

Colloids in Biological SystemsSome molecules have a polar, hydrophilic (water-loving) end and a nonpolar, hydrophobic (water-hating) end.

Sodium stearate is one example of such a molecule.

Non- Polar Tail

Polar Head

Soap Micelles in water solution

H2O

H2O

H2O

H2O

H2O

H2O

H2O

H2O

H2OH2O

H2OH2O

H2O

H2O

H2O

H2O

Page 54: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

Colloids in Biological SystemsThese molecules can aid in the emulsification of fats and oils in aqueous solutions.

{Cotton Fabric Softener}

{Micelle}

Page 55: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

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Suspension:heterogenous fluid containing solid particles that are sufficiently large for sedimentation. Usually they must be larger than 1 micrometre.[1] The internal phase (solid) is dispersed throughout the external phase (fluid) through mechanical agitation, with the use of certain excipients or suspending agents.

Page 56: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

Page 57: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

Page 58: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

Page 59: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

Page 60: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

Page 61: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

2006 (A)

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Page 63: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

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Page 64: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

Page 65: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

2003 A

Page 66: Solutions Unit 12: Properties of Solutions Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL Textbook Reference: Chapter # 14 Module #

Solutions

Na+(aq) + C2H3O2

_

(aq) NaC2H3O2(s)

Energetics of Solutions Heats of Solution (Hsoln)

crystallization

Recyclable Hot Pack: Super Saturated Solution of Sodium Acetate

heating

{HotPack Na Acet}

∆Hsoln = - 67 kJ/n