Solutions to Me n Mine Psa-ix

SOLUTIONS TO QUALITATIVE AND QUANTITATIVE REASONING

• MathematicsStand-alone MCQs ......................................................................................... 3Passage-based MCQs ................................................................................... 14

• ScienceStand-alone MCQs ....................................................................................... 22Passage-based MCQs ................................................................................... 42

• Social ScienceStand-alone MCQs ....................................................................................... 49Passage-based MCQs ................................................................................... 49

SOLUTIONS TO LANGUAGE CONVENTIONS

• EnglishGrammar and Usage MCQs ....................................................................... 50Vocabulary in Context MCQs .................................................................... 51Passage-based MCQs ................................................................................... 54

• Hindi

............................................................ 57

...................................................................... 60

.............................................................................. 62

SOLUTIONS TO PRACTICE PAPERS• Practice Paper-1 .......................................................................................... 68• Practice Paper-2 .......................................................................................... 71• Practice Paper-3 .......................................................................................... 74• Practice Paper-4 .......................................................................................... 78• Practice Paper-5 .......................................................................................... 82

3Solutions to PSA–IX

STAND-ALONE MCQs

1. (a) The greeting card is a two-dimensional object and that has six sides. Thus,the outlines of the card form a hexagon.

2. (a) Let the required number be x.

Then 1 1

1 1 22 2

x x

The option (a), that is, 11

2 fulfils our requirement.

3. (c) Let us check all the options one by one by taking the point (8, 30).Option (a): 30 = 3 × 8 + 2 30 = 26 which is wrongOption (b): 30 = 2.5 × 8 + 6 30 = 26 which is wrongOption (c): 30 = 3.5 × 8 + 2 30 = 30 which is trueOption (d): 30 = 3 × 8 + 6 30 = 30 which is trueBut option (d) is not true for (6, 23) as:

23 = 3 × 6 + 6 23 = 24 which is wrong.4. (d) From the given figure, it is clear that there is a quadrilateral whose two

angles are right angles. So by angle sum property of a quadrilateral, wehave

x + 60° + 2 × 90° = 360° x = 120°

5. (c) Required per cent Number of sold books

100Total number of books

80

100800

= 60.6. (a) t is the selling price of one toy, in rupees.

356t – 180 = 87

356t = 87 + 180 267

0.75356

t t .

7. (c) We know that x = 100x %

1

2 2.5 2.5 100% 250%2

Solutions to Qualitative andQuantitative Reasoning

MATHEMATICS

4 Solutions to PSA–IX

8. (b) The object in option (b) contains all the three views given especially sideview.

9. (d) Inside circumference of the tyre = outside circumference of the rim

= × diameter = 22

15 47.147

47.1 m.

10. (a) Kapil, Lily and Maya have grade A 2 times, 4 times and 8 times whereasthey have grade B 6 times, 4 times and 4 times respectively. This isrepresented only by the matrix in option (a).

11. (a) 8 – 2x > – 4 8 + 4 > 2x 6 > x, i.e., x < 6.12. (d) After distributing 2a(3a – 1) becomes 6a2 – 2a.

13. (a)2 22 3

2 24 6244 .

6 6y z zy z

y zz z

14. (a)3 – 9 3( – 3)

– 3 – 3.3 3

x xx x

x – 3 = x – 3If we replace x with any value of x, we always will get LHS and RHS equal.Therefore the given equation is true for all values of x.

15. (d) Let us check all the options one by one for (4, 14).Option (a): 14 = 2 × 4 14 = 8 which is wrong.Option (b): 14 = 4 + 2 14 = 6 which is wrong.Option (c): 14 = 5 × 4 14 = 20 which is wrong.Option (d): 14 = 3 × 4 + 2 14 = 14 which is true

16. (c)

2 2 2 2 2 2a ab b b bc c c ca aa b c

b c a

x x xx x x

2 2 2 2 2 2

– – –. .a ab b b bc c c ca aa b b c c ax x x

3 3 3 3 3 3– – –. .a b b c c ax x x3 3 3 3 3 3– – – 0a b b c c ax x

= 117. (b) The answers in questions 2 and 4 are not in standard conditions. So the

unitary method is not applicable for them.18. (c) Let PD = x and QC = y

AP = 6 – x and BQ = 4 – yPerimeter of APQB = Perimeter of PDCQ 6 – x + PQ + 4 – y + 3 = x + 9 + y + PQ 4 = 2(x + y) x + y = 2

Now, 6 –AP PDBQ QC 4 –

x xy y


6y – xy = 4x – xy 3y = 2x 3(2 – x) = 2x ( x + y = 2)

6 = 5x 65

x

6 246 – 6 –

5 5x

Required ratio =

24AP 6 – 5 4 : 1

6PD5

xx

.

19. (b) On translating to the right, only abscissa of point is affected, whiletranslating to the down only ordinate is affected.So, the new coordinates of the point M will be (r + 7, s – 3).

20. (c) In I quadrant, both abscissa and ordinate of a point are positive while inIII quadrant both of them are negative.

21. (b)

AB = 6 – 1 – 1 = 4 m, BC = 3.5 m = 7

m2

Length of brace2

2 2 2 7AC = AB + BC 4

2

49 113 1 10.6316 113

4 4 2 2

5.3 m.

22. (c) Area = length × breadth = 2x2 y4z × 5xy4 z3

= 10x3y8z4

23. (c) The top view will show a hexagonal face as top and six differentquadrilaterals faces as sides of the given solid.

24. (d)3 24 2

3 5 2 3 2 3 3

a b c aa b c aa b c a b c b c b c

25. (d) In the given equation, c is the dependent variable and n is the independentvariable. Thus, c changes as n changes. Hence, we can say that the valueof c is dependent on n.


26. (d) Let originally, length = a, breadth = b Original perimeter = 2(a + b) New perimeter = 2(2a + 2b)

= 2 × 2 (a × b) = 2 × Original perimeter.

27. (c) Let us check all the options one by one for r = 4, n = 66.Option (a) : 66 = 2 × 4 + 52 66 = 60 which is not trueOption (b) : 66 = 4 + 54 66 = 58 which is not trueOption (c) : 66 = 4 × 4 + 50 66 = 66 which is trueOption (d) : 66 = 4 × 4 + 54 66 = 70 which is not true.

28. (d)5 – 17 5(– 3.2) – 17 –16 –17

– 8.254 4 4

yx

29. (d) Each pair of adjacent angles of a parallelogram is supplementary. P + Q = 180° Q = 180° – 146° Q = 34°

30. (b) Let us check the truthness of equations in options for x = 10, y = 58.Option (a) : 58 = 4 × 10 + 2 58 = 42 which is not trueOption (b) : 58 = 6 × 10 – 2 58 = 58 which is trueOption (c) : 58 = 7 × 10 – 4 58 = 66 which is not trueOption (d) : 58 = 5 × 10 + 4 58 = 54 which is not true.

31. (a) Let the speeds of the slower and the faster cyclists be v1 and v2respectively.SAME DIRECTION OPPOSITE DIRECTIONSRelative speed = v2 – v1 Relative speed = v2 + v1

Relative distance = k Relative distance = kTime = r Time = t

2 1–

kr

v v ...(i)

2 1

kt

v v

...(ii)

From (i) and (ii), we have

2 1

2 1–v v rv v t

Using componendo and dividendo we have v2 : v1 = r + t : r – t

32. (a) Let the height of the cup be H, the radius of the cup be r, the depth of thewater be h.

2 21 1π H 8

3 3r r h

H : h = 8 : 1


33. (d) (a – 1)2 – ab + b – a + 1 – 6 (b + 1)2

= (a – 1)2 – b (a – 1) – (a – 1) – 6 (b + 1)2

= (a – 1)2 – (a – 1) (b + 1) – 6 (b + 1)2

Put a – 1 = x, b + 1 = y x2 – xy – 6y2 = x2 – 3xy + 2xy – 6y2

= x(x – 3y) + 2y(x – 3y) = (x – 3y) (x + 2y)= (a – 1 – 3b – 3) (a – 1 + 2b + 2)= (a – 3b – 4) (a + 2b + 1).

34. (a) The number set 756 in the given sequence is only one time.755945764598 756 764325678

35. (a) The given graph shows that any two points lying on the line are (– 3, 0)and (0, 3). For these two points, only the equation y = x + 3 holds true.

36. (a)

From the number line (above), 245

is represented by A.

37. (a) 5 hours = 5

2424

hours

5 hours = 5

24 of a day

5 hours 16

of a day.

38. (c) p is divided by 3 and hence multiplied by q2 to get 2

3p

q . Now 2

3p

q is

divided by 3 to get 21.

3 3p

q i.e., 2

.9

pq

39. (a) 1 complete turn = 360° = 4 × 90° = 4 right angles 2 complete turns = 8 right angles.

40. (a) Through three collinear points, one and only one line can be drawn.41. (c) 56 = 23 × 7

77 = 11 × 7 HCF (56,77) = 7Now, k – 8 = 7 gives k = 15.

42. (c) x = Prime number next to 23 = 29y = Prime number next to 41 = 43 x + y = 29 + 43 = 72

43. (d) 1 hour = 60 minutes = 60 × 60 = 3600 seconds

1 second = 1

3600 hour =

13600

of an hour.


44. (c) P7

Q gives P = 7Q

P + Q 7Q + Q 8Q 4

.P – Q 7Q – Q 6Q 3

45. (c) From first condition, a – b = c + d + 6From second condition, a + b = c – d – 3

Adding, 2a = 2c + 3 a – c = 3

1.52 .

46. (b) Let ? = x5 6 8 3 3 1 7

– 1 3 26 7 9 5 4 3 9

x

We first eliminate the symbol ‘ ’.

5 7 8 5 3 10 25

–6 6 9 8 4 3 9

x

35 25 5 5 36 15

– ×36 9 9 2 35 18

x x , x = 6

.7

47. (a) Required number =

137

752 8 300.1 28

48. (b) 1.5x = 0.04y 4 2

150 75y

x y x

2–– 73 7375

2 77 7775

yyy x y

yy x yy

49. (d) Let the operator number be m. One-third of one fourth of m13

of

14 3 4 12m m m

This is given to be 15.

15 12 1512m

m

Now, three-tenth of 3 3

12 15 54.10 10

m m

50. (b)


51. (b) B can take either the value 1 or 2. A can take only the value 5 to makethe same digit 5 in place of ones digit of the sum. Hence A = 5, B = 1.

52. (c) It is clear that P 0, Q 0.PQ × Q = 39So, Q can take value either 3 or 7.If Q = 7, then P × Q 3. So Q 7If Q = 3, then P × Q = 3 gives P = 1.Hence P = 1, Q = 3

53. (c) HCF × LCM = Product of two numbers = p1 p2

54. (b) 10 cows can graze 10 fields in 10 days100 cows will graze 10 fields in 1 day100 cows will graze 100 fields in 10 days

55. (c) 25 pages can be read by Sunita in d days 125 pages will be read by her in 5d days.

56. (b) We know that ‘Ring’ is worn in the finger. But ‘Ring’ is called ‘Necklace’,so ‘Necklace’ would be worn in the finger.

57. (b)

In the same way we will obtain the following

58. (c) Fraction of work done in 2 days 1p

Fraction of work done in 1 day 12p

Work to be done and days are in inverse proportion, so the woman can dothe whole work in 2p days.

59. (a) We know that the time taken and the work to be done are in inverseproportion. So the editor can edit the whole book in m days.

60. (b) Semi circumference = RThere will be two different pegs to the two end points of the circumference

Number of pegs πR= 1 10R 1

π

10


61. (a) 0x x is a positive value

So 2

0x , that is, x > 0

62. (d) An equation in the form ax + by + c = 0 is called ‘linear equation in twovariables’ if both a and b are not equal to zero. In other words at least oneof a and b must not be zero. This may also be written in brief as a2 + b2 0.

63. (c)

Simiarly we have:

64. (d)

Similarly, ‘PACK’ would be written as following

65. (b) The values x = 0, y = c together always satisfy the given equation y = mx + c.66. (c) The x-axis and y-axis on the cartesian plane are

always horizontal and vertical respectively as showin the adjoining figure. Hence required angle is 90°or 1 right angle.

67. (d) Let y-coordinate be y1.At x = x1 and y = y1, 4x + y = 6 gives y1 = 6 – 4x1

68. (b) The outcome in second toss does not depend upon the outcome shown up

in the first toss. So, P (head) = 1

.2

69. (c) The sum of lengths of any two sides of a triangle is always larger than thethird side. b + c > a, i.e., c > a – b, i.e., a – b < c .

70. (d) If the length of edge of cube is increased or decreased, the volume andtotal surface area of the cube increase or decrease in the same ratio butthe angle defined in the question remains unaltered.


71. (a) Let edge = a

1

3 3a V a V

Surface area = 6a2 = 6

21 23 36V V

.

72. (d)

2 2 3MN = AM – AN –

4 2a a

a

Area of rectangle ABCD = AB × MN = 3 3

.2 2a a

a

73. (c) The sum of any pair of opposite angles of a cyclic quadrilateral is 180°. Sorequired sum must be more than 180°.

74. (a) Any median of a triangle divides it into two triangles of equal bases andsame height, so these two triangles are of equal area.

75. (c)× 2 ×New curved surface area 2 1

Initial curved surface area

hr

r h

curved surface area will remain unaltered.76. (d) Initial volume = r2h

New volume = 2

22( )

r nnh r h

m m

2 Initial volume.n

m

77. (c) New edge of the cubical box = 2aNew surface area of a surface = (2a)2 = 4a2.

78. (d) Let original radius of the base of the cone = R Original area of the base = R2

New radius of the base = rR New area of the base = r2R2

= r2 × Original area.79. (b) Let original side of rhombus = a

Then original perimeter = 4a

New perimeter of rhombus = 4a – 10

4100

a 3610

a


New side = 1 36 94 10 10

a a

Required decrease

9–

10 100%

aa

a = 10%

80. (c) Triangles lying between same parallel lines and are on the same base haveequal base lengths and equal heights although they are neither similar norcongruent. A1 = A2

81. (d) Capacity = litres = 1000 cm3 r2 = 1000 r2 = 1000

Area of base = r2 = 21000π 1000 cm

.

82. (d) Capacity of p glasses = q litres = 1000q ml

Capacity of 1 glass 1000ml

qp

.

83. (b) To construct a unique triangle and a unique quadrilateral one requiresthree measurements and five measurements of corresponding polygon. m1 = 3 and m2 = 5 m1 : m2 = 3 : 5.

84. (a) Sum of exterior angles of a triangle (or a polygon) = 360° 8d = 360° d = 45°.

85. (c) The sum of each pair of opposite angles of a cyclic quadrilateral is 180°.So, a quadrilateral PQRS is said to be cyclic if P + R = 180° and/orQ + S = 180°.

86. (b) P (black or red) + P (blue or white or orange) = 1 P(black or red) = 1 – p

87. (c) When a pair of dice is rolled, the number of all possible outcomes= 62 = 36 1 + p + q = 36 p + q = 35.

88. (d) P (certain event) = 1P (impossible event) = 0 m = 1 and n = 0So m + n = 1, m – n = 0 and mn = 0

89. (a) In the given case, all possible outcomes are as follows:HHH, HHT, HTH, HTT, THH, THT, TTH, TTTComparing the above set of outcomes with the given set, we obtain x = H.

90. (c) We have the range of the probability p of an event of an experiment isgiven by 0 < p < 1 m = 0, n = 1


91. (c) A point circle is any point. A point is considered to have no length andbreadth. So length of the diameter of a point circle is zero.

92. (c) Because given observations are in increasing order,smallest observation = 35, largest observation = l Range = l – 35.

93. (d) Class-mark = 2

x y , class size = y – x.

Reqired ratio = (x + y) : (y – x)94. (a) Note that mid-points P, Q and R of sides respectively AB, BC and CA of

ABC divide the ABC into four congruent trianglesnamely, APR, BPQ, QRC and PQR.

ar(APR) = ar(BPQ) = ar(QRC) = ar(PQR)

So ar(parallelogram BPRQ) = 12

ar(ABC)

95. (d) In the adjoining figure, ABCD is a kite (none ofrectangle, rhombus, parallelogram) whose diagonal ACdivides it into two parts namely ABC and ADC, equalin area.

96. (b) Let lower class limit = x

Then, m = 2

l x x = 2m – l

97. (c) We take mid-points of lower and upper limits of classes as requiredabscissae. These mid-points are also called class-marks of the classes.

98. (b) Given 1 2 3 ........ nx x x xx

n

x1 + x2 + x3 + ... + xn = nx ...(i)

Required mean = 1 2 3 1 2 3

1.... ....n na x x x x x x x x

an n

= 1 2 3

1....

2

na x x x xa

n

=1

2x

aa

[Using (i)]


99. (b) After multiplication or division by a non-zero number, new LHS and newRHS of the equation will remain equal.

100. (c) The given situation is possible only if ABCD is a square. Moreover diagonalsare equal and perpendicular for only a square.

PASSAGE-BASED MCQs

1. (i) (d) We have prime numbers: 2, 3, 5, 7, 11, 13, ........(ii) (a) We have composite numbers: 4, 6, 8, 10, 12, 14 ......

2. (i) (c) Using option (c):ab ac

ad

= givesb c

d

abd + acd = abd + acd, which is true.

(ii) (d)79

= 1418

gives 7 × 18 = 9 × 14 or 126 = 126, which is true.

3. (i) (a) The leftmost and the right-most shaded triangles together cover 4 smallrectanges. Also the rest of shaded regions cover 2 small rectangles.

Required ratio = 6 : 10 = 3 : 5.(ii) (a) The measurements of PQ and PS do not matter to the desired ratio.

So answer will remain the same as in question (i).4. (i) (a) The sum of measures of an acute angle and its complementary angle

is 90º. Required angle = 90º – 75º = 15º.

(ii) (c) The sum of an acute (or obtuse) angle and its supplementary angle is180°.

Required angle = 180º – 89º = 91º.5. (i) (b) Area = length × breadth = ( 3 + a) × 8.

(ii) (c) Perimeter = 2(length + breadth) = 2(a + 3 + 8)/= 2a + 22.

6. (i) (d) Scientific notation = Hundreds digit × 102 + Tens digit × 101 + Onesdigit × 100

= b × 102 + c × 101 + a × 100.(ii) (b) Generlised form = Hundreds digit × 100 + Tens digit × 10 + Ones digit

× 1= b × 100 + c × 10 + a × 1.

7. (i) (b) Five squares will be seen when the solid figure is viewed from directlyabove.

(ii) (a) Three squares in the bottom, two squares in the middle and one squareon the top will be seen when the object is viewed from directly front.


8. (i) (a) 4 b 4 d 12 a 3 g 7 =4 ÷ 4 – 12 + 3 × 7= 1 – 12 + 21= 10.

(ii) (d) 0.4 g 0.1 a 0.06 b 0.3 d 0.1 = 0.4 × 0.1 + 0.06 ÷ 0.3 – 0.1= 0.04 + 0.2 – 0.1= 0.14.

9.

(i) (d) (ii) (b)10. Face Opposite face

100 800200 700600 2000700 200800 1002000 600

(i) (b) From above table the required value is 200.(ii) (b) The value at the bottom of the view (D) will be a value on the face

opposite to the face having 2000. This is 600 (see above table).

11. (i) (b) 12

cm = 1 m

1

5 cm2

=1 1

5 m1 22

= 11 m

(ii) (d) Height on scale : Actual height

= 512

cm : 11 m = 5.5cm11m

=5.5cm 1

1 : 2001100cm 200

12. (i) (c) Notice that a right squre pyramid has 5 faces of which one is squareand four are isosceles triangles.

(ii) (a) E = 4 sides of square and 4 sides of triangles = 8V = 4 vertices of square and 1 apex = 5F = 1 face of square and 4 faces of the triangles = 5


13. (i) (d) Required ratio =8 2

12 3 .

(ii) (d) Required ratio = 20 5

5 : 416 4

.

14. (i) (c) Number of numbers = 144 = 12.

(ii) (c) Number obtained in seventh step = 72 = 49

Its square root = 49 = 7

Required ratio = 49 : 7 = 7 : 1.

15. (i) (a)Circumference for large cake 2 30

2.Circumference for small cake 2 15

(ii) (a)

2 2

2 2Volume of small cake 15 thickness 15

1 : 4.Volume of large cake 30 thickness 15 2

16. Quantity of salt in the salt water = 2

100m

gm

Let x gm of salt to be added.

(i) (c)

2

2100100

mx m

m x

m2 + 100x = 2m2 + 2mx 2

gm100 – 2

mx

m .

(ii) (b)

2

50100100

mx

m x

m2 + 100 x = 50 m + 50 x x = 250 –

50m m

gm

17. (i) (d) 32 a 8 b 2 c 4 d 6 = 32 ÷ 8 × 2 + 4 – 6= 4 × 2 + 4 – 6 = 6.

(ii) (a) 8 d 8 b 12 a 3 c 24=8 – 8 × 12 ÷ 3 + 24= 8 – 8 × 4 + 24 = 0.

18. (i) (d) Each row or column adds a total of 12.(ii) (b) In each row, numbers from left to right are decreasing by 5.

19. (i) (c) a < b ... (i)b = c ... (ii)Substituting the value of b from (ii) in (i), we geta < c

(ii) (d) If a is negative, then b and c are either both negative, or both zero orboth positive.If a is positive, then b and c must be both positive.


20. (i) (c) To obtain area, we will take 1 unit2 as area of each square marked with

‘x’, 12

unit2 as area of each triangle marked with ‘y’, 1 unit2 as area of

each triangle marked with ‘y’, 1 unit2

as area of each quadrilateral markedwith ‘z’ and 0 as area of each trianglemarked with ‘t’.

Thus area of the polygon = 1 × 14 + 12

× 6

+ 1 × 4 + 0 × 4= 14 + 3 + 4= 21 units2.

(ii) (c) Area of square = side2 = 32 = 9 units2

21. (i) (a) Same-side interior angles are congruent only when transversal (hereline t) is perpendicular to parallel lines l1 and l2.

(ii) (b) Pair of alternate exterior angles (here 1 and 5) are always congruent.

22. = 21516 = 21516

53794

= 10878 = 10878 – 5379 = 5499

= 5499

18333

(i) (a) = 1833 × 2 = 3666.

(ii) (c) = 5379 + 1833 = 7212.

23. (i) (b) If x = 4, y = 3, then 4 > 3 but – 4 < – 3.

(ii) (a) If x = 100, y = 10, then 100 > 10 but 1

100 <

110

i.e., 0.01 < 0.1.

24. (i) (a) 8 + 2 ÷ 1 – 6 × 4 = 8 ÷ 2 × 1 + 6 – 4 = 4 × 1 + 6 – 4 = 6.(ii) (c) 7 × 16 + 8 – 19 ÷ 4 = 7 – 16 ÷ 8 + 19 × 4 = 7 – 2 + 19 × 4 = 81.

25. (i) (c) Rule: The same figure is joined to it and halved it with horizontal linesegment and then shaded its upper half part.

(ii) (d) Rule: The whole design is rotated by 180º and the head of the arrow isreplaced by its tail.

26. (i) (a) Rule: The sum of the two numbers on the top of design is equal to thesum of rest of the numbers.


(ii) (b) Rule: The sum of the two numbers on the botton of design is equal tothe sum of rest of the number.

27. (i) (c) 50 γ 5 δ 5 β 27 α 4 = 50 ÷ 5 × 5 – 27 + 4 = 10 × 5 – 27 + 4 = 27.(ii) (d) 6 α 7 β 10 γ 5 δ 3 = 6 + 7 – 10 ÷ 5 × 3

= 6 + 7 – 2 × 3= 7.

28. In Column I, ‘S’ is in common in ‘SBI’ and ‘ASD’. On the other hand in ColumnII, ‘ga’ is in common in ‘sa re ga’ and ‘ga da pa’. So ‘ga is code for ‘S’. Similarly,we can identify codes for other letters.(i) (c) BIRDS sa re ma pa ga.

(ii) (d) DREADED pa ma ni da pa ni pa.29. (i) (d) ‘A’ is in common in ‘TAP’ and ‘SAIL’

‘k’ is in common in ‘ksd’ and ‘kptm’(ii) (c) ‘T’ is in common in ‘TAP’ and ‘LOTUS’

‘s’ is in common in ‘ksd’ and ‘smcpx’.30. The positions of E and G in the adjoining figure

may be between B and A or left to B or E be inbetween B and A and G be left to B.

(i) (a) (ii) (d)

31. (i) (c) (ii) (d)

32. (i) (b) The crease works like the line of symmetry. So the sheet afterunfolding will look like as follows:

(ii) (d) The crease works as a line of symmetry. So the sheet afterunfolding will look like as follows:


33. (i) (b) The number common in the circles of English and French but not inthat of Spanish is 7.

(ii) (b) The number common in the English and Spanish but not in that ofFrench is 14.

34. (i) (c) In the adjoining figure, there are five triangles of which four aremarked with a, b, c, d and fifth is made up of all these four.

So the given figure censists of 10 triangles.(ii) (a) Eight triangles are on either side of vertical line and eight triangles are

without considering the vertical line. So the given figure has 24 triangles.35. (i) (d) If a square is devided into small identical squares, then the total

number of squares, if n small squares are along one side of the square,is given byn2+ (n – 1)2 + (n – 2)2+ ...... + 12

Required number of squares = 32 + 22 + 12 = 14.(ii) (d) Required number of squares = 1 (Inside triangle)

+ 3 (outside triangle)= 4

36. Letter Place from beginning

A 1st

D 4th

E 5th

H 8th

I 9th

N 14th

R 18th

(i) (b) HEAD = 8514 (ii) (a) RANI = 181149.

37. Letter Place from beginning

A 1 st

D 4 th

N 14 th

P 16 th

Z 26 th


(i) (a) PAN = 16 + 1 +14 = 31.

(ii) (d) AZAD = 1 + 26 + 1 + 4 = 32.

38. Letter Place from end

A (26 – 0)th = 26th

E (26 – 4)nd = 22nd

S (26 – 18)th = 8th

X (26 – 23)rd = 3rd

Y (23 – 24)th = 2nd

Z (26 – 25)th = 1st

(i) (c) YES = 2 × 22 × 8 = 352.(ii) (a) XYZA = 3 × 2 × 1 × 26 = 156.

39. (i) (d) Required number = No. of white triangles + No. of shaded triangles +No. of shaded squares

= 1 + 1 + 1 = 3.(ii) (c) Required number = No. of white shapes + No. of shaded shapes having

tail= 2 + 1 = 3.

40. (i) (a) In each pair of polygons except in option (a), both polygons are of samenumber of sides.

(ii) (d) All the figures except in option (d) are made up of line segments.41. (i) (b) The number inside a circle is the arithmetic mean of the numbers

outside of the circle.(ii) (c) The number inside a circle is obtained by subtracting the sum of left

and right numbers from the sum of top and bottom number of the circle.42. (i) (a) Each pair of figures except in option (a), loverlaps each other.

(ii) (d) Each set of figures except in option (d) contains only one circle.43. (i) (a) The numbers in each column add 12.

(ii) (d) The number in each bottom cell is half the product of two numbers inupper cells

44. (i) (c) Middle number = Sum of numbers in top and bottom cells– Sum of numbers in left and right cells.

= (2 + 6) – (1 + 5) = 2.(ii) (d) Middle number= Sum of remainig numbers –1

= (1 + 3 + 7 + 4) – 1 = 14.45. (i) (c) The number in centre of a circle is half the sum of square roots of all

outer numbers to the circle.

(ii) (b) ? = 4 9 16 25

72

.


46. (i) (c) From the left, second figure has no straight boundaries and fifth figureis not closed.

(ii) (b) From the left, figures first and second have not all straight boundaries,and figure fifth has no straight boundaries.

47. (i) (a) Rule:

14 × 4 = 56; reversed digits : 6517 × 3 = 51; reversed digits : 15Number in centre = 6515Using the above rule, we get

? = 7548(ii) (b) Rule: Middle number = Product of nos. in left and right

– product of numbers in top and bottom.48. We will agian use the formula used in Question 35.

(i) (a) Number of squares = 72 + 62 + 52 + 42 + 32 + 22 + 12 = 140.(ii) (a) Number of squares on the chessboard

=82 + 72 + 62 + 52 + 42 + 32 + 22 + 12 = 204.49. (i) (c) Required number = (one calculator and two mirrors) + 3 (atleast one

calculator and at most two mirrors) – 1= 3

(ii) (b) The left most box represents ‘a bottle as well as a calculator’. The leftmost and the right most boxes represent ‘a mirror as well as a bottle’.The left most box represents a mirror as well as a calculator’. Hencewe have been considered only two boxes.

50. (i) (b) Rule: Middle number = Sum of outer numbers.

5(ii) (b) Rule: Middle number = Sum of numbers in left and top

– Sum of numbers in right and bottom.


STAND-ALONE MCQs

1. (a) The average velocity would be zero because the total displacement of body iszero.

Average velocity =total displacement

0total time

2. (a) Taken time (t) = 60 sec.

Radius (r) = 2 cm

Distance = Circumference

= 2r

Speed =2 r

t

=22

2 2760

= 0.21 m/s

3. (c) Velocity (v) = 0

Height of body (h) = 10 m

g = 9.8 m/s

Then the velocity (v) of body is

2v = u2 – 2gh

0 = u2 – 2gh

u2 = – 2 × 9.8 ×10

u = 14 m/s

4. (c) Because total distance travelled is directly proportional to the square of time

s = ut + 12

gt2

s =12

gt2 ( u = 0)

s t2 ( where g is constant)

5. (c) Both, because uniform acceleration means the velocity increases by equalintervals of time however small intervals of time in a straight line.

SCIENCE


6. (d) For X1 distance S1 = ut + 212

at

X1 = 0 + 212

at (where u = 0) X1 = 212

at

v = u + at v = 0 + at

S2 = ut + 212

at X2 = at2 + 212

at ( u = v = at)

X2 = 232

at 1

2

XX

=

2

2

112

3 32

at

at

1 23X X

7. (a) Slope of line in (i) is greater than the slope of line in (ii).8. (b) Velocity in case of (ii) is less than the velocity in case of (i).9. (a) BC represents the body moving backward with uniform velocity because when

a moving body covers equal distance in equal intervals then this condition issaid to be uniform motion.

10. (c) As the velocity increases from u to v in a time t with a uniform acceleration aand covers the distance S.Sketching a rough diagram from the given information, we havein velocity-time graph,

Distance S = Area between velocity-time graph and time-axis i.e. Areaof trapezium ABNO.

=12

× (AO + BN) × ON

= 12

× (u + v) × t ...(i)

2s u v t

Also, acceleration is equal to the slopeof the graph

a = BPAP

= –BN PN

ON

i.e., –v u

at

By cross multiplication, v – u = at or–v u

ta

or v = u + at


Putting in equnation (i)

S = 1 –2

v uu v

a , =

2 2–2

v ua

2aS = v2 – u2, 2 2 2v u aS

S = 12

u u at t , = 1

22

u at t

12

S u at t

11. (a) Player completes circular path of radius r is 40s.

No. of revolution in 2 min 20 sec = 14040

= 3.5

after completing 3 full round displacement = 0The remaining path = 0.5because player travels along the diameter of circle as displacement is the 2r.

12. (a) In the adjoining speed time graph, the shaded portion gives distance travelled.13. (a) mass = 1 kg

F = 10NF = mg

10 = 1×gg = 10 m/s2

So the gravitational intensity will be 10 m/s2.14. (a) As F = mg

Here, gravitational force is acting on mass M1 soF = M1g

Also, the total mass of the two bodies= M1 + M2

Then, acceleration of the masses = Fm

= 1

1 2

M gM M

15. (a) When a man walks towards the shore the boat will move away from the shorebecause when he tries to pushes the force backward, boat also pushes theman in forward direction. So due to action force of man boat moves in oppositedirection.

16. (a) Mass of bullet = AVelocity of bullet = BMonentum of bullet P = mv = A.BMass of wood = CMass of system = A + C

Velocity of system =Momentum of bullet A.B

Mass of wood A + C


17. (c) In horizontal direction the resultant force exerted on M2 isF = M2a ... (i)

Both blocks are in contact so they have some acceleration so for the first blockF = (M1 + M2)a

a =1 2

FM M

... (ii)

Now puting the value of a in equation (i)F = M2 × a

F = 21 2

FM

M M

2

1 2

M FF

M M

18. (a) Mass of bullet (m) = 0.01 kg

Mass of gun (m) = 5.0 kg

Initial speed of bullet (u) = 250 m/s

Speed of gun recoils (v) = ?

v =muM

=0.01 (– 250)

5.0

= – 0.50 m/s

19. (a) Momentum of disc = M kg m/sDisc striking at wall = n/60Associated force would be

Force =Change in momentum of the body

Time taken =

×60 60

M n Mn

20. (a) The string will break below the stone due to reaction force.21. (c) When we increase the pull at P gradually the string will break above the

stone because froce is equal on stone but because of larger mass of stone andsmaller acceleration the string will break above the stone.

22. (a) Above problem explain the property of inertia.

23. (b) As m = 3 kg, 1V

= 10 m/s,. 2V

= 0 m/s, t = 0.25 sec, I = ?.

By the definition of impluse, I = Ft.And F = ma

= 2 1–V Vt

= 3 × 0 – 100.25

N


Thus, I = 3 × –10

0.250.25

Ns

= – 30 Ns.24. (a) The force exerted by both teams are equals then rope does not move but the

force applied by teams A is more than team B then the rope of weaker teamB will be pulled towards team A.

25. (b) Tennis ball suffers a greater change in momentum.26. (c) Acceleration, as F and m are given. From Newton’s second law F = ma.27. (b) F = ma (according to second law of motion).

a = 1N1kg

=21 kg m/s

1kg = 1 m/s2

28. (b) As m = 2 kg for each of the three objectsNet force = 2mg – mg

= mg = 2 kg × 9.8 m/s2

= 19.6 NTotal mass = 2 + 2 + 2 = 6 kg

Therefore, acceleration

a =Fm

= 219.6m/s

6Now, consider the blocks B and C

mg – T2 = maor mg – ma = T2

or T2 = m (g – a)

= 2 (9.8 – 19.6

6)

= 58.8 – 19.6

26

=39.2

3 = 13.06 N = 13 N (approx).

29. (c) A moves 3.5 m and B moves 2.5 m.30. (a) W = mg (weight of a man when lift is at rest)

F = ma (Resultant force applied in upward direction)

F = W' –W, where W' is apparent weight of man in lift.or ma = W' – mgor W' = ma + mg

W' = mg 1 (1 )a a

Wg g


31. (b) Mass (M) = 0.05 kg

Final velocity (v) = 400 ms–1

t = 1 secImpulse = m(v – u)

= 0.05 (400 – 0) = 20 kg m/s

I = F × t

F =It

= 201

= 20 N

32. (c) The coin falls behind because train is moving forward with acceleration.

33. (b) Mass of springs m1 = 10 kg

m2 = 20 kg

F = 200 N

F = m2a2 + m1a1

200 = 20 × a2 +10 × 12

200 = 20 × a2 + 120

200 – 120 = 20 × a2

80 = 20 × a2

a2 =8020 = 4 ms– 2

34. (a) A symbol of an element represents one atom of that element. Symbols arethe short form for the names of elements for example: Oxygen – O,Hydrogen – H, Phosphorus – P.

35. (d) Physical properties are those changes in which state of substance transformbut chemical composition and chemical nature of substance does not change.

36. (c) Ice is a form of solid so the space between particles is very small. Theseparticles have strong intermolecular force so that they have minimum kineticenergy.

37. (a) Movement of molecules is different for solid, liquids and gases because positionof molecules are different in them like molecules in solid have strongintermolecular force. In liquids these molecules have less intermolecular forcethan solid so that molecules can move. In gases molecules have leastintermolecular force hence molecules move in random motion.

Solid Liquid Gas


38. (b) Brass. Because mixture shows the properties of its constituents. It is a mixtureof copper and zinc.

39. (a) Water is a compound and compounds do not show the properties of itsconstituents.

40. (c) Firstly Kanada said that ‘All matter is composed of very small particles calledparmanu.

41. (a) Tyndall effect.42. (c) Antonie L. Lavoisier defined element as a basic form of matter.43. (b) Steel is a homogeneous mixture because it is mixture of uniform compostion

(Fe + C).44. (c) Both mitochondria and chloroplasts originate and develop in the same way.

They arise by the division of pre-existing organelles. Both are semiautonomousorganelles and contain DNA, RNA and 70s Ribosomes.

45. (b) The cytoplasmic connections from cell to cell are known as plasmodesmata.46. (a) Membrane occurs in cytoplasm, chloroplast and mitochondria.47. (d) Ribosomos are smallest organelles found either attached to endoplasmic

recticulum or freely in cytoplasm.48. (b) Microsomes are formed by distruption of cells. Microsomes are isolated by

centrifugation and used in enzymatic activity and protein synthesis.49. (d) Golgi apparatus synthesises some polysaccharides (cellulose and

hemicellulose) and it is involved in the formation of glycoproteins.50. (c) The inner membrane of mitochondria is usually highly convoluted forming a

series of infolding known as cristae.51. (a) Inner membrane of mitochondria contains succinic dehydrogenase and

cytochrome oxidase enzyme which involve in mitochondrial functions.52. (a) The presence of DNA in mitochondria and chloroplast supports the hypothesis

that mitochondria and chloroplast both originated as independent free livingorganism.

53. (c) When green tomatoes turn red then chloroplasts are disintegrated and getconverted into chromoplasts. Chromoplasts absorb light energy and pass iton to chlorophyll in the chloroplasts.

54. (b) Lysosomes are known as “suicidal bags” because of hydrolytic activity. Theyare involved in digestion of organelles and help in disposal of unwantedmeterials, hence they are called suicidal bags.

55. (d) Lysosomes are the cells of garbage disposal system because they help indisposal of unwanted materials.

56. (c) Lysosome is not directly involved in synthesis and secretion.57. (b) The arrangement of outer and central microtubules in a cilium is called the


9 + 2 pattern. Microtubules are arranged in nine sets of doublets around thecircumference with two single tubules in the centre.

58. (b) Nucleo-cytoplasmic traffic through nuclear pore is facilitated by nuclearlamina.

59. (b) Chromosome divide when force exerted on centromere.60. (b) Metacentric chromosomes have equal arms.61. (d) A telocentric chromosome differs from an acrocentric chromosome in that the

former has termianl and the latter has subterminal centromere.62. (c) Average thickness of unit cell membrane is 75Aº.63. (b) Metaphase represents the best stage in which one can view the shape, size

and number of chromosomes.In mitosis metaphase is stage of karyokinesis. During karyokinesis nucleusdivides into two daughter nuclei.

64. (c) Synthesis of RNA and protein takes place in G1 and G2 phases of the cellcycle.

65. (d) During G1 phase of cell cycle the daughter cells have the same number ofchromosomes and same amount of DNA.

66. (c) Mitosis is the process in which cell divides into two daughter nuclei but themechanism ensuring genetic continuity is formation of two cells with identicalDNA.

67. (d) Mitosis will be arrested at metaphase stage.68. (c) During mitosis metaphase differs from anaphase in having half number of

chromosomes and same number of chromatids.69. (b) In a plant cell, cytokinesis occurs by seperation of the cytoplasm from cell

centre to its periphery during cytokinesis cytoplasm following nuclear divisioninto two parts, each with a daughter nucleus.

70. (d) The term ‘karyokinesis’ is used for overall changes occuring in nucleus duringthe cell division.

71. (b) 1 cell 2 cell = 1 division2 cell 4 cell = 2 divisions4 cell 8 cell = 4 more divisions = 7 in totalproceed to 128 all = 127 divisions.

72. (b) Meiosis involves in two cycles of nuclear and cytoplasmic divisions, but fourdaughter cells are formed by single cell of DNA and chromosome replication.

73. (b) Meiosis involves in two division of nucleus and one division of chromosome.74. (b) Crossing-over occurs between non-sister chromatids of homologous

chromosomes. Crossing-over is the exchange of portion of chromatids betweenhomologous chromosomes.

75. (d) The terminalisation occurs during diplotene through metaphase.76. (a) 25.


77. (b) Mitosis differs from meosis in each chromosome duplicating itself at thebeginning of the process and the separation of the duplicates to the poles ofthe spindle.

78. (b) Collenchyma consists of living cells with additional cellulose in their wallswhich provide support and protection to the young stems and leaves.

79. (d) Sieve tubes are living cells without nucleus.80. (d) In collateral vascular bundle xylem and phloem stands are joined with

phleoem towards outside.81. (b) In a bicollateral vascular bundle xylem is sandwiched between phloem. When

two phloem poles occur in a conjoint vascular bundle separated from thecentral xylem by strips of cambia. They are bicollateral vascular bundles.

82. (b) Monocot root differs from dicot root in having well developed pith. Pith ofmonocot root is large and well developed and very small or absent in dicotroot.

83. (a) In dicot leaves mesophyll tissue is divided into spongy tissue and palisadetissue. Both tissues carry out photosynthesis.

84. (c) Bulliform cells are present in upper epidermis of monocot leaves.85. (a) The youngest layer of secondary phloem in woody dicot stem is located just

outside the vascular cambium.86. (b) Dendrochronology is the study of age of a tree by counting the number of

annual rings in the main stem.87. (b) There is no marked climatic variation at seashore so that trees at seashore

do not have annual rings.88. (a) Due to the presence of apical meristeme tree grow from tip and width wise

so that height of sign will remain same in between 1997 to 2007.89. (a) Connective tissue has matrix. Matrix consists gel like substance and protein

fibres. There are three type of fibres (i) white fibres (ii) yellow fibers and (iii)reticular fibres.

90. (d) Adipose tissue contains fat and oil. Adipose tissue occurs beneath the skinand surrounds the internal organs. These tissues have fatty acids which isstored as triglyceride. Tryglyceride forms fatty droplets that exclude waterso when water oxidised then adipose tissue provides water and energy duringoxidation.

91. (b) Adipose tissue forms a heat insulating layer beneath the skin and preventsheat loss.

92. (a) The major consituent of vertibrate bone is calcium phosphate.93. (b) If a bone is left in dilute HCl solution, its inorgainc salts are removed and

the organic matter is left behing. Such bone becomes soft and elastic.94. (a) The bone marrow of man will be more active.95. (d) Nissl’s granules are found in neuron. These granules are rough endolplasmic

reticulum and are the site of protein synthesis. So they are made up by RNA.


96. (b) Haemocyanin is a blood pigment which contains copper.97. (a) Red cell count is carried out by Haemocytometer.98. (b) Muscular tissue uses the greatest amount of energy in human beings. It forms

40 to 50% of the body weight. There are 600 muscles in human body. Thesemuscles take part in various functions of the body parts.

99. (c) In humans, heat production is increased by the increasing activity of skeletalmuscles.

100. (b) Cardiac muscles. These muscles contract itself throughout the life.101. (c) Nervous tissues of brain have least capacity for regeneration.102. (b) Afferent nerve fibre carries impulses from receptor to central nervous system.103. (c) Deficiency of magnesium element is cause of chlorosis in plants because it is

a consitituent of chlorophyll.104. (b) Phosphorus is needed in cell membrane, nucleic acid and energy transfer.105. (c) Rice can be hand over a number of year without adding any nitrogenous

manurus because there are nitrogen-fixing algae in the rice field.106. (d) Use of fertilizers in pond increase the amount of phytoplanktons because

fertilizers dicrease biological oxygen demand (BOD) of water by which aquaticanimals became dead and planktons grow fastly in the pond.

107. (b) This process is called biological control.108. (b) Waterlogging of soil makes it physiologically dry because this condition does

not allow to oxygen to enter the soil as oxygen is the main source of soil formaking it more productive.

109. (a) The difference is how they obtain food. Autotrophs make their food by selfand heterotrophs depend on other sources of food.

110. (d) Hybridisation is the process in which two genetically dissimilar parents arecrossed to produce and offspring with both the desired character.

111. (b) High-yielding varieties of wheat were primarily developed by cross breedingtraditional varieties with Mexican varieties.

112. (d) Removal of stamens in an inter-sexual flower before they dehisce is calledemasculation.

113. (b) “Father of White Revolution” in India is V. Kurian.114. (a) This technique is embryo transfer.115. (a) These are the major symptoms of rinder pest disease.116. (a) IPN (Infectious Pancreatic Necrosis) and VMS (Viral Haemorrhagic

Septicemia) are infectious diseases of fish. Diseases in fishes are caused dueto virus, bacteria, fungus etc.

117. (a) Aquaculture is the medium through which production of fishes, prawns,lobsters, crabs, molluscs can be incresed.


118. (b) Deuterium has equal number of protons and neutrons.119. (a) Isotopes have same atomic number but different atomic masses. Their physical

properties are different. But they have similar chemical properties.120. (c) Atomic number of element is 19. Its electronic confguration is K = 2, L = 8, M

= 8, N = 1. It has one valance electron which occupies N-shell.121. (c) Maximum number of electrons in any energy level is equal to 2n2 where n is

energy level.1st energy level can have 2n2 = 2 × 12 = 2 electrons

2nd energy level can have 2 × 22 = 8 electrons3rd energy level can have 2 × 32 = 18 electrons

So M. shell has 18 electrons.122. (b) R.A. Millikan experimentally proved charge on the electron. Particle

present in the atom possess negative charge of 1.6 × 10–19 coulombs and amass of 9.1 × 10–31 kg.

123. (c) X is more reactive because it has 6 valance electrons.X — K = 2, L = 8, M = 6, Y—K = 2, L = 8, M = 8

X has 6 valence electrons so it can gain 2 electrons to complete its octet andY has 8 valance electrons hence its octet is complete.

124. (b) The e/m value for cathode rays does not vary with the nature of gas.

125. (a) The new species of Y would be 234

90Y because when a -particle emits from

nucleus, it loses 4 units from atomic mass and 2 units from atomic number.126. (b) When a particle emits from nucleus then one unit increase in atomic number

so the daughter nuclide will be 228

90Th .

127. (c) The relative atomic mass of many elements are not whole number because ofexistence of isotopes and isotopes differ in mass and have same atomicnumber.

128. (a) Mg + O2 2MgO. O2 represents the atoms of oxygen joined together in amolecule.

129. (c) The chemical formula of a compound does not represent the state of moleculeof a compound. It represents the compound with the help of symbol andvalency of elements.

130. (c) According to law of conservation of mass, for a balanced chemical equationmass as well as atoms are conserved.

131. (c) (NH4)3 PO4 (Ammonium phosphate.)132. (c) In compound MSO4, valency of metal is + 2 (M2 + + SO4

2 –). Hence chloride ofmetal M will have MCl2 formula.


133. (a) Molecule is the smallest unit of a compound which exists independently.134. (c) The number of atoms in a molecule of a substance is called atomicity.

Atomicity of phosphorus is 4.135. (b) 2N represents two atoms of nitrogen.136. (a) The law of multiple proportion was discovered by John Dalton.137. (d) CaCO3 CO2 + CaO

10.0 g = 4.4 g + 5.6 g = 10.0 gMass of reactant = Mass of productThis observation follows law of conservation of mass.

138. (b) Mass of NaCl = 23 + 35.5= 58.5 g

58.5 g NaCl contains 23.0 Na

11.7g. NaCl contains = 23

11.758.5

= 4.6 gSo the mass of sodium in sodium chloride is 4.6 g.

139. (b) CaCO3 + 2HCl CaCl2 + H2O + CO2

Mass of CaCl2 = 40 + 35.5 × 2= 111

Mass of CaCO3 = 40 + 12 + 16 × 3= 40 + 12 + 48= 100

When 100 g CaCO3 is dissolved, 111 g of CaCl2 is formed

When 2.5 g of CaCO3 is dissolved 111

2.5 2.775100

g CaCl2 will be formed.

140. (d) CaCO3 + 2HCl CaCl2 + H2O + CO2

Molar mass of CaCO3 = 40 + 12 + 3 × 16 = 100Molar mass of CO2 = 12 + 2 × 16 = 44 100 g CaCO3 gives 44 g CO2

2.5 g CaCO3 will give 244

2.5 1.1 g CO100

At STP 44 g of CO2 occupies 22.414 litres volume

At STP 1.1 g of CO2 will occupy 22.414 1.1

44

= 0.5603 litre volume.

141. (b) Atomic mass of Zn = 65Atomic mass of Cl = 35.5


Percentage of Zn =65

10065 35.5

xx y

or65

10065 35.5

xx y

= 47.8 (As given in question)

or 6500x = 3107.9x + 1696.9yor 3396x = 1696.9y

orxy

=1696.93393

orxy

=12

x = 1 y = 2Compound will be ZnCl2

142.(c) Cu + 4HNO3 Cu(NO3)2 + 2NO2 + 2H2O143.(d) Mass of H2 = 2

Mass of H2O = 2 × 1 + 16 = 18

So the percentage of hydrogen in water = 2

10018

= 11.11

144.(b) N =molecular mass

molar mass Molecular mass = 60

Molor mass of CH2O = C + H2 + O= 12 + 1 × 2 + 16 = 30

n = 6030

= 2

Molecular formula of compound = (empirical formula) × 2= (CH2O) × 2= C2H4O2

145. (a) Atomic mass of helium = 4 4 g of helium = 1 gram-atom

8 g of helium = 2 gram-atoms146. (b) 2 g of H2 contain 6.022 × 1023 molecules

8 g = 236.022 10 8

4 = 24.088 × 1023 molecules

It has largest number of molecules than others.147. (c) 1 mole of N2.

1023 molecules of H2 = 23

232 10

0.336.022 10

g


1 mole H2O = 18 g1 mole N2 = 28 g

1022 atoms of oxygen = 22

2316 10

0.2636.022 10

g

148. (a) KE = 12

mv2

When velocity = 6v

KE = 12

m (6v)2 = 36 × 12

mv2

149. (b) Since momentum, Pm, so heavier mass has greater momentum150. (b) The maximum work done when the body lifted vertically upward because work

is done opposite to gravitational force.151. (a) Which one of the bullets will pierce the target with a greater distance, it

depends upon their kinetic energy.Here, we have,

For bullet P, m = 10 g and v = 20 m/s

so KE of P = 212

mv = 21 10

202 1000 J

=1

200 × 400 = 2J

For bullet Q, m = 20 g and v = 10 m/s

so KE of Q = 212

mv = 1 202 1000 × (10)2

=1

100 × 100 = 1 J

152. (c) The distance of the body inclined at 90º the work done is W = Fdcos

= F× d × cos 90º, W = 0153. (a) No, earth does not perform work on the moon.154. (a) m = 20 kg

h = 2 mg = 10 m/s2

K = mgh = 20 × 2 × 10 = 400 J.155. (d) As the given balls have the same radius i.e. volume but different masses and

are dropped from same height at same time so their PE, KE and total energyas well as momentum all depend upon their masses. Thus none of these arethe same.

156. (d) W = Fdcos When cos = 0 work done is maximum.


157. (a) Let rectangular components of the force 50 N are represented by OA and OB .

Here,OC = 50 NOA = 30 NOB = ?

From vector rule, OB AC

Applying Phythagoras theorem, in OAC,OC2 = OA2 + AC2

or (50)2 = (30)2 + AC2

or 2500 = 900 + AC2

or AC2 = 2500 – 900 = 1600

AC = 1600 = 40

Thus,OB = 40 N

158. (d) The force will remain zero because the radius of sphere is at 180º angle.159. (b) A steam engine converts heat energy into mechanical energy.161. (d) P = mv

or v =Pm

K =2

21 12 2

Pmv m

m

K =2

2Pm

When P is increased 100%, P becomes 2P, then

K =21 2

2P

mm

K =22P

mIncrease in kinetic energy

=2 2 22 3

–2 2

P P Pm m m

Percentage increase =

2

2

32 100

2

PmPm

= 300

162. (a) F = 20 N, d = 1 m, = 45ºW = Fd cos = 20 × 1 × cos 45º

= 20 × 1

12


W =20

2= 10 2J

Since the displacement is in the direction of force, therefore, work is positive, i.e.W = 10 2 joule .

163. (a) K = 20 J, m = 100 g = 0.1 kg

K = 12mv2

or 20 = 210.1

2v

or v2 = 400 v = 20 m/s

P = mv = 0.1 × 20 = 2 kg ms– 1

164. (b) As the train is accelerating with a uniform acceleration so due to inertia bobof the pedulum wants to mantain the same position but top portion of thestring moves forward with the ceiling of the train. Thus bob doesn’t pass thecentral position as previous one. Hence time period increases.

165. (d) As, T = 2lg

or l

Tg

When, l = length of simple pendulumg = gravitational acceleration.

166. (a) As water is denser medium compartively air so pendulum does not able tooscillate freely in water. Thus, time period increase.

167. (c) The bob will fall on to the earth due to the absence of the force exerted by thestring in the downward direction.

168. (a) As restoring force always acts towards mean position, i.e., central position sowhen bob is in central position the restoring force is negligible hence the forcesare balanced.

169. (b) As the time period of a simple pendulum depends upon itslength and the value of ‘g’ at the place of the experiment. Thegraph T vs L i.e T L is a parabola.

170. (b) T1 = 2lg

T2 = 24lg

1

2

TT =

2

24

lglg

1

2

TT =

4gg

1

2

TT = 2 T2 = 1

2T

T2 =2

1 s2


171. (d) Wavelength = 2L.172. (a) Speed = wavelength × frequency

Speed frequencySo sound wave is directly propotional to its frequency.

173. (c) Sound of frequency below 20 Hz is infrasonic.174. (a) The relation is

v n

175. (b) = 100 m

v = 25 m/sT = ?

v = T

T = 10025

= 4 s

176. (a) Particle A and G in long string produce transverse waves.177. (c) As both waves longitudinal in and tranverse propogate in solids so they will

propogate in metal.178. (c) T = 0.02 sec.

T = 1

frequency

Frequency = 1T

= 1

0.01 = 100.0 c/s

179. (a) The waves produced by supersonic jet planes are shock waves. These wavecauses large change in air pressure.

180. (a) Speed = 340 ms–1

Frequency = 500 HzWavelength = ?

Speed = Wavelength × frequency

Wavelength =speed

frequency

=340

0.68 m500

.

181. (d) The sensation of sound persist in out brain for 0.1 second. So to hear echothe time difference between original sound and reflected sound should be morethen that.


182. (b) Density of brine = 1.2 g/ccDensity of water = 1 g/ccMass of solution = 40 × 1.2 + 30 × 1 = 78 g

Volume of solution = 40 + 30 = 70 cc

Density of solution =Mass of solution

Volume of solution =

7870

= 1.11 g/cc

183. (a) Total volume of mixture = 60 + 40 = 100 cc. Volume of mixture = 100 cc

Density of mixture =60 1.4 40 0.8

100

=116

1.16100

g/cc

184. (a) Height of mercury = 13.5

So column of mercury =20

13.5 = 1.48 cm.

185. (b) Let volume of body be VB and mass MB

Mass of body = mass of water displaced by the bodyMB = volume of water × density of water

or MB = B2

V 13

( 23

part of body is inside the water

i.e., volume of displaced water is B2

V3

MB = B2V3

... (i)

Thus, mass of body = mass of liquid displaced by wateror MB = volume of liquid × density of liquid

or MB =14

VB × d ( 14

th part of body is inside the

water)

MB = BV .4

d... (ii)

From equations (i) and (ii)

BV .4

d= B2V

3

d =2 4

3

d =83

g/cc


186. (a) Since the ice cube will displace the water equal to its mass. Hence the waterlevel will remain same.

187. (d) Mass of the body = 50 kgand volume = 0.049 m3

density =50

0.49mv = 1020.4 kg/m3

Thus, the density of body is greater than the density of water. Hence bodywill sink in water.Therefore, buoyant force applied by displaced water of volume0.049 m3 = 0.049 ×1000 kgf = 49 kgf

188. (a) Density = mass

volume Volume is equalSo ratio of density of body A to density of body B = 1 : 4

189. (a) Relative Density =Density of metalDensity of water

2.7 =Density of metal

1000Density of metal =2700 kg/m3

Density of metal is more than that of water so it will sink in water.190. (d) Fluorine causes the mottling of teeth.191. (a) Helicobacter pylori cause peptic ulcer. These disease related to those persons

who are addicted to toxic substances.192. (b) Water may get infected by bacteria from excreta, sewer water, etc. Such water

causes cholera disease.193. (b) Vaccine is not available for dengue. It can be treated only by precautions from

mosquitoes.194. (c) Tetanus spreads through cut and wound.195. (c) Binomial system of nomenclature means that every organism has one

scientific name and consisting of a generic and specific name. This is becausethere are various type of organism on earth. So for identifying them scientistgave scientific name to each organism. Which is easily understood by allbiologist over the world.

196. (b) Division – class – order – family – genus – species197. (b) The classification of the group algae is based on the nature of pigments

because algae shows different colours in appearance such as red, brown, blue,green and yellow.

198. (a) Gymnosperms are naked-seeded plants.


199. (c) Common character of vertebrates is presence of notochord. It is present inembryo in primary stage. It is present between alimentary canal and nervecord. Hence the phylum name is chordata.

200. (d) Presence of segmented body. Protochordates are the group of first chordatesso they show chordates characters.

201. (a) Bryophyta is connecting link between thallophyta and pteridophyta becausebryophytes have characters of both classes.

202. (b) The source of edible seeds known as chilgoza in north India is Pinuswallichiana.

203. (d) Floral features are chiefly used in angiosperms identification becausereproductive parts are more stable and conservative than vegetative parts.

204. (b) Tapeworm, liver fluke and planarian have flattend body.

205. (a) Sepia have ink gland that when disturbed produces a jet of black ink whichacts as ‘smoke screen’ to dodge the attacking enemy.

206. (c) Karl von Frisch got Noble prize for decoding the language of bees andexplained their dances for communication.

207. (b) Paripatus is living fossil between Annilda and Arthropoda. Paripatus havecharacter of both the phyla and still in existence.

208. (a) Generally reptilians have three-chambered heart but crocodiles have four-chambered heart which is its advance character in reptilians.

209. (a) Archaeopteryx is connecting link between reptiles and birds.

210. (b) Musca—complete metamorphosis. This pair shows the certain phenomena.

211. (b) Mammary glands are kind of modification of sweat glands. It is milk producinggland in females which provide food for young ones.

212. (b) Bats have special sensory system called echolocation. It is the method by whichbats can detect objects in the dark.

213. (a) Biochemical cycles are also known as cycles of matters. The cyclic process bywhich chemical elements transferred from non-living nutrients pool to livingbeing.

214. (c) The leguminous plants are important in agriculture because they help innitrogen economy of the plant.

215. (c) The denitrification means conversion of ammonia and nitrates to gaseousnitrogen. This process is affected by dentrifying bacteria which use nitrogenas source of energy for other chemical reactions.

216. (c) When concentration of salts becomes very high in soil water such type of soilis physiologically dry soil. Such type of soil does not good for crop production.

217. (c) Ozone layer prevents ultraviolet rays of sunlight from reaching the earth. Itis not stable near the earth’s surface.


218. (b) Carbon monoxide is a pollutant because it is less stable than carbon dioxideand easily join other molecules. So molecules of carbon monoxide when enterthe body during breathing combines with haemoglobin easily.

219. (b) SO2, CO and Hydrocarbon gases are produced by motor vehicles. Only flyash is not produced by vehicles in Delhi.

PASSAGE-BASED MCQs

1. (i) (a) As we know that in a velocity-time graph, a straight line parallel to timeaxis shows uniform motion. So the part AB of this graph shows uniformmotion.

(ii) (b) According to graph velocity start increasing from 5 to 10s (second).(iii) (c) From graph, we see that CD represents the vilocity decreases uniformly.

Here, we have

1 10V

m/s, 2 0V

m/s and

t1 = 10 s, t2 = 20sThus, retardation of the body =

22 1

2 1

– 0 m / s – 10 m / s –10/

– 20 s – 20 s 10V V

m st t

= –1 m/s2

(iv) (d) Distance covered during 20 s= Area of rectangle OABI + Trapezium IBCF +

Triangle FCD

= OA × AB + 12

× (IB + FC) × IF + 12

× FD × FC

= 2 × 5 + 12

× (2 + 10) × 5 + 12

× 10 × 10

= 10 + 12

× 12 × 5 + 12

× 10 × 10

= 10 + 30 + 50= 90 m.

(v) (a) The graph parallel to x-axis show body at rest in distance time graphand uniform motion-velocity-time graph

2. (i) (b) B is fastest because slope of distance-time graph is more than A and C.(ii) (c) When B passes A, C has travelled 7.5 km as shown in graph.

(iii) (c) The point F shows B passing C so corresponding value of F on verticalaxis gives 5.5 km.

B


(iv) (d) The three objects crossed one another in different time so these objectsnever meet together.

3. (i) (b) When thread removed from the neck of the balloon as a result reactionforce acts on the balloon in the opposite direction, so balloon movestowards the wall B.

(ii) (a) When air escapes from the mouth of balloon with great speed, reactionforce acts on balloon in opposite direction of action force applied by balloonon air inside it.

(iii) (c) This activity demonstrate the 3rd law of motion. This law follows action-reaction force.

4. (i) (a) Other balance will weigh the same body as 5 kg because all balances givesame measure on earth.

(ii) (b) No, because weight of the body (measured by spring balance) on the moonis 1/6th that on the surface of the earth

(iii) (a) Grocer balance measure the same because it is independent of g.5. (i) (b) u = 20, v = 0 m/s, g = –10 m/s2 (in upward direction)

Using v2 = u2 – 2 gh

(0)2 = (20)2 – 2 × 10 × h

20 h = 400

h =400

2020

m


(ii) (a) Using v = u – gt0 = 20 – 10 × t

10t = 20

t = 2010

= 2 sec

(iii) (c) As ball takes the maximum height in 2s whenit is thrown by the boy from a tower. Therefore,it will take same time in returning to the boy.Thus, total time = 2s + 2s = 4s.

(iv) (d) If h = 60 + 20 = 80 m, velocity at optimum height= 0 m/s, g = +10 m/s2 (in downwardly), t =?

Using h = ut + 212

gt

80 = 0 × t + 12

× 10 × t2

80 = 5t2

16 = t2

t = 16 4s

Thus, total time taken in going optimum height and in arriving on theground = 2s + 4s = 6s

6. (i) (b) Chemical reaction takes place and new substances FeSO4 and Cu areobtained

(ii) (b) When iron nails dipped in copper sulphate solution the colour of layerbecome reddish brown because copper metal gets deposited on iron nails.

(iii) (b) A layer of copper is deposited on iron nails when they are dipped in coppersulphate solution is due to copper.

(iv) (b) Calcium (Ca) is most reactive among the four as it can displace all ofthree elements from their salt solutions.

(v) (d) When silver nail is dipped in copper sulphate solution no reaction takesplace because silver is less reactive than copper.

7. (i) (b) When a hot liquid is allowed to cool, the temprature of the liquid startsfalling down with the time untill it reachers at room temperature.

(ii) (b) Time-temperature graph is measure of rate of loss of energy.(iii) (d) Temprature remains same in freezing, melting and boiling.(iv) (a) Lengthier portion of temperature-time graph indicates the change of state

and requires less energy.(v) (c) The temperature of water remains constant till most of the liquid changes

into vapour state.(vi) (a) Variation of temperature of water from 0 ºC to 100 ºC is represented by

part BC in the graph in question.


(vii) (a) As variation of temperature with the time is recorded during experimentand plotted graph shown in question refers to part A to D.

8. (i) (b) When white of an egg is mixed with water a translucent colloidal solutionis obtained.

(ii) (a) A true solution of sugar in water is formed.(iii) (d) Detergent powder is totally soluble in water so there will be no residue

left after filtration.(iv) (b) Colloidal solution is translucent, leaves no residue and particles and does

not settle at the bottom.(v) (a) Salt solution is a true solution in which size of particles is of order

10– 8 cm9. (i) (b) We observe that magnet attracts iron filing whereas sulphur does not

get attracted.(ii) (c) Sulphur dissolves in CS2 forming yellow solution while iron filings settle

down due to gravity.(iii) (b) Heterogeneous mixture will be formed because its component can be

separated by simple physical method.(iv) (b) Iron sulphide is a compound.(v) (a) When a mixture of iron filings and sulphur powder is heated it converts

into a black shiny compound (iron sulphide)

10. (i) (b) Weight of protein in skin = 16

100 × 1 = 0.16

Total weight of bones = 16

= 0.16

(ii) (b) If the person weighing 50 kg, the quantity of water in his/her body

= 50 × 70

100 = 35 kg

=

1316

= 63

= 21

= 2 : 1

(iii) As shown in pie. chart

The distribution of proteins in the muscles = 13

The distribution of proteins in the bones = 16

So, the required ratio = 1 1 1 6 2

: = × = = 2 : 13 6 3 1 1


(iv) The percentage of prateins and other dry elements = 16 + 14 = 30%

The are of the circle should be subtend at centre an angle of 30

360100

108º

(v) (c) Body part without bone and skin

= 2 15 3 =

6 515

= 1115

11. (i) (a) Photosynthesis mainly occurs in leaf because it contains chlorophyll.(ii) (b) Light, CO2, H2O and temperature affect the rate of photosynthesis.

(iii) (a) Phloem transports food energy.(iv) (a) Palisade mesophyll has most chlorophylls which take part in

photosynthesis.(v) (c) Waxy cuticle of the leaf reflects back excess light.

12. (i) (c) Protoplasm without nucleus is known as cytoplasm.(ii) (d) Nucleoplasm is found inside nucleus.

(iii) (c) DNA is found in nucleus.(iv) (b) Nuclear membrane is double layered which separates the nucleoplasm

of a cell from cytoplasm.(v) (d) Nucleus is known as controller of all activities.

13. (i) (b) They swell up due to endosmosis.(ii) (b) The solution present inside dry raisins is hypertonic.

(iii) (b) Root of the plants take water from soil by process of osmosis.(iv) (c) Solvent can pass through the semipermeable membrane.(v) (b) If Amoeba is kept in marine water it will shrink after sometime due to

the outward movement of water from cell.(vi) (d) Diffusion involves in respiration process as movement of CO2 and O2 gases

from region of high concentration to lower concetration takes place (fromlungs to blood and blood to tissue).

14. (i) (d) Use of fishes to control aquatic weeds is not preventive measure; it is acontrolling method.

(ii) (d) Use of microorganisms to eliminate weeds is better for crop productivity.(iii) (d) Cochineal is used to control prickly pear weed (Opuncia).(iv) (d) 2, 4-D is used for destroying the weeds.(v) (c) Malathion is used to kill insects.

15. (i) (c) It is called law of conservation of mass.(ii) (b) The law of conservation of mass states that mass can neither be created

nor destroyed.


(iii) (b) BaCl2 + Na2SO4 BaSO4 + 2NaClWhite precipitate of BaSO4 is formed.

(iv) (c) In the reaction mass of reactants and the products remain same.(v) (a) During the reaction exchange of ions of chloride and sulphate takes place.

(vi) (a) The law of conservation of mass was stated by Antoine Lavoisier.16. (i) (a) It shows that most of the parts of atom is hollow.

(ii) (c) It shows that centre of atom is positively charged.(iii) (b) Whole mass of atom is concentrated in the nucleus.(iv) (c) The density of nucleus is very high because its size is very small and

whole mass of atom is concentrated in it.17. (i) (a) P hdg P h ( d and g are constant)

(ii) (b) Figure B shows that pressure in liquid remains same in all direction.(iii) (b) No, because water flows from same height.

18. (i) (b) For side A = area = l × b = 25 × 5 = 125 cm2

For side B area = 25 × 10 = 250 cm2

For side C area = 10 × 5 = 50 cm2

Side B covers more area so it will exert less pressure.(ii) (d) All bricks have same mass so it will feel heavier in all conditions.

(iii) (c) Area of side C = 10 × 5 = 50 cm2

We know that 1

PA

Hence side C will exert maximum pressure.(iv) (a) Given m = 5 kg

Pressure exerted by surface A

P = F mgA A

P = –25 9.8392 Nm

0.25 0.05

Pressure exerted by surface B = –25 9.81960 Nm

0.25 0.1

Pressure exerted by surface C = – 25 9.89800 Nm

0.1 0.05

19. (i) (b) Buoyant force will act on bob upward so the length of rubber string willreduce.

(ii) (c) The weight will be less than 200 g due to buoyant force.20. (i) (a) Pinna collects sound from surroundings.

(ii) (b) Tympanic membrane is also called eardrum.


(iii) (c) The amplitute of vibration are amplified several times with the help ofhammer, anvil, stirrup.

21. (i) (a) In situation A no work done hence car has no energy to move(ii) (c) Because car is moving hence it shows kinetic energy and due to storing

energy it shows potential energy also.(iii) (a) When the spring is wound, it acquires potential energy.

22. (i) (b) Paramecium is a unicellular organism. This is the most primitive type ofanimal having single cell.

(ii) (a) All green plants are autorophs because they make their food themselvesby process of photosynthesis.

(iii) (a) Cyanobacteria are prokaryotes.23. (i) (b) Onion is monocotyledonous plant because they have adventitious root,

leaves have parallel veins, stem is not woody.(ii) (b) There are four free petals in a mustard flower.

(iii) (c) Stem of onion is eaten as vegetable.(iv) (a) Plants of angiosperm group bear flower, seeds enclosed in fruit, and plants

have tap and fibrous roots.(v) (c) Style is a part of gynoecium.

24. (i) (c) Eggs of culex mosquito are laid in cluster in water.(ii) (b) Larva of culex is at 45º angle to water surface.

(iii) (a) Larva of anopheles is parallel to water surface.(iv) (b) Anopheles mosquito causes malaria.(v) (a) Standing water is a breeding site of mosquito.

(vi) (d) Female mosquitoes live one or many months.(vii) (a) The colour of a culex pupa is greyish.

25. (i) (b) Oxygen is used for release of energy and carbon dioxide by breakdown offood.

(ii) (c) Fixation of CO2 is done by photosynthesis process in presence ofchlorophyll through these process carbon enters the carbon cycle.

(iii) (a) The site of photosynthesis process is chloroplast while respiration ismitochondria in the cell.

(iv) (d) Auto and factory emission, volcanic eruption, decomposition add carbondioxide in nature.

(v) (b) Combustion of fuels to provide energy four various purpose also releaseCO2 and other gases.


STAND-ALONE MCQs22. (b) Scorched Earth Policy is a kind of feeling that the important things of a place

should not fall in the hands of the enemies.31. (d) (a), (b) and (c) are contributary factors but even the land kept for grazing

could not feed the cattle because continuous grazing in a small areadeteriorated the quality of pasture.

84. (b) The Indian Constitution provides for the establishment of an Election Com-mission to conduct these elections.

85. (a) He is not elected by the people or by the members of Legislative Assemblies ofState. Chief Election Commissioner does not enjoy any power of appointment.

86. (b) is correct whereas options (a), (c) and (d) are not associated with election.87. (b) Right to Property is not a Fundamental Right now. It is only a legal right.

It was taken out of the list of Fundamental Rights by 44th amendment ofthe Indian Constitution. Options (a), (b) and (c) are Fundamental Rightswhich have been included in the Constitution of India.

88. (b) Statements (ii) and (iii) are justified because Permanent executives areaccountable to their code of conduct and Political executives are accountableto the people.

89. (c) Before Independence, communal electorate was prevalent in India. Now ithas been replaced by the new Constitution of India which provides for jointelectorate. The voting procedure in India is secret. Only the voter knows forwhich candidate has he/she voted.

90. (c) Rajya Sabha has not more than 250 members.91. (b) No, right is limited to the extent that it does not harm other. No body be

given the right to kill others. Therefore, reasonable restrictions are placedon the enjoyment of rights by the citizens.

92. (a) Because options (b), (c) and (d) are related to the powers of the Prime Minister.93. (d) When an election is held for the legislature which has been dissolved ear-

lier, it is called mid-term election. Direct and Indirect elections are themethods of conducting an election.

94. (c) It is necessary to keep the voters list up to date because some people mayhave moved away from the area where they voted last.

PASSAGE-BASED MCQs

9. (iii) (b) Madhurima is right. The Registar, by questioning and interfering in herpersonal affairs, is violating her right to freedom. Also the social ques-tion of adopting the husband’s surname has roots in a religious practicewhich treats women as weaker and inferior. Compelling Madhurima tochange her name is a violation of her right to equality and right tofreedom of religion.

SOCIAL SCIENCE


GRAMMAR AND USAGE MCQs I. 1 (i) (b) have is the most appropriate verb as we talk of many people and not

just one person.(ii) (c) Something ranges from one limit to another. So, the word ‘from’ is used

with ranging.(v) (b) We try to stay away from something. The word ‘away’ is used here.

2. (iii) (b) Incidence was of past and we talk of a single earthquake. So was is thecorrect verb here.

(iv) (d) Who, whom, whose is used in the context of a person. Here we talk of anearthquake. So which is the most correct word used here.

(v) (b) Earthquake caused building to shake. Only word made (past tense ofmake) is the best fit.

(vi) (c) An activity is referred for certain period of time, so we use continuoustense of shake i.e shaking is correct verb.

(viii) (b) Here we talk of moving in a particular direction. So ‘towards’ is best fittingwith East.

3. (i) (c) We live in a house and not on or at the house. So, in is the correctpreposition.

(ii) (d) With the past tense was, we use past participle of the verb. So hidden isthe right verb from used here.

(iv) (c) No conditional conjection is required, simple connector and is used.(v) (a) Something is full of any object. Here we talk of bushes full of flowers. So

of is the right preposition.(vii) (b) We talk of an activity just completed. So simple past tense of finish is

used here. This finished is the right form of verb for this sentence.4. (i) (c) Article ‘the’ is always used with the superlative form most.

(iv) (b) Something is caused by somebody or due to something. The only articleavailable from options is by. So this is the correct option.

(vi) (d) When we talk of a quantity in terms of fraction we use the article of likeone-third of population. Thus of is the right preposition.

(vii) (c) Same reason as that of (iv) above.5. (i) (c) Here, we talk of an activity that has been done in the past and has

occurred this year also. So ‘dried’ is the right form of verb used here.

Solutions to Language Conventions

ENGLISH


(ii) (b) Simple conjunctin ‘and’ is used to link same types of objects like hand-pumps and wells.

(v) (d) In this sentence, short is not to be used in terms of height but deficiencyof water due to river dryness is being discussed. Thus, shortage is theright word used here.

6. (i) (b) Something gets spread in an area. Thus in is the correct option.(ii) (c) Here we talk of a place where something has happened. Which , when

and why are interrogative words. Thus where is the right choice.(vi) (c) When we talk about an activity going on from a specific period of time,

the preposition Since is used.

Parts II and III are self explanatory and can be done using general grammarknowledge.IV. 1. (b) Here we talk of a definite country India, thus definite article the is used

before country.2. (c) The sentence tells about a plant whose various parts are used as

medicines. Thus whose is the correct choice.3. (a) Since we talk of tree in general and twigs are plural, we use plural verb

in present tense ‘are’ before very effective.4. (b) Paste is used in the treatment of something. Thus in is to be put before

the treatment to complete the sentence.5. (d) Where, which and whose are interrogative words and are not relevant

in this sentence. Thus option ‘with’ is the right answer put before neemleaves.

V. 1. (b) Anybody can be a heir to some will. Thus to is the right choice.5. (c) Preference shows comparison of something to other. Thus to is the right

answer.6. (b) Putup means to stay, thus up is used to complete this sentence telling

the plan of stay for the night.7. (d) There is always a fight over something. Thus over is the correct option.8. (b) Someone is releived from duty or charge.

10. (b) Takes away means taking something without asking.11. (a) Abundant means something existing in large quantities of something.12. (c) One has affection (personal feeling) for someone.13. (d) One gives assurance of something like help to somebody.20. (c) One can be a slave of somebody else.

VOCABULARY IN CONTEXT MCQs 1. (c) Crude when used for oil means in its natural state without being refined.

Thus unrefined is the correct meaning.3. (a) Yield when used with a crop means the produce or the output.


4. (b) Adopt means to make changes as per the situation. To change means tomodify.

6. (a) Devastating means destructing, and disastrous is harmful that inturnmeans destructing.

7. (b) Enchanted means got very happy, delighted also means excessively happy.8. (c) Fatal means something causing death. Thus deadly is the correct meaning.

10. (b) Jaunty means lively and fungiving. Thus, cheerful is right choice whichmakes same sense.

11. (b) Indicted means to charge officially with a crime. Thus accuse is the rightword as synonym here.

14. (c) Massacre mean killing of a large number of people cruely like animalsslaughter without any reason.

15. (a) Voracious means eating or wanting large amount of food. Thus hungrysuitably matches this word.

16. (b) Mayhem denotes confusion and state of disorder due to sudden shockingevent. Thus havoc is the right answer.

17. (d) Precarious means not very safe and certain i.e. critical in nature.20. (c) Immense means extremely large or excessive. Thus extreme can be a close

meaning.21. (a) Impulse means a sudden strong wish to do something without thinking.

Thus urge is the right synonym.23. (c) Lured means to get attracted towards something which can be rewarding,

same is the meaning for tempted.24. (d) Manifest means to show something clearly to someone. Thus demonstrate

is the correct synonym.25. (a) Scream means a loud and high pitched cry.

II. 1. Loathe means to hate i.e. dislike.2. Cladestine means not openly visible i.e. hidden.3. Erudite is a person showing great knowledge i.e. learned.4. Haughty means behaving in an unfriendly way towards others due to self-

superiority i.e. arrogant.5. imprudent means not wise or sensible i.e. unwise.6. Malevolent means showing a desire to harm other. A wicked person also think

the same.7. Nimble means able to move quickly and easily. Thus quick is the correct

synonym for it.8. Peril means something which can be harmful i.e. dangerous.9. Queer means unusual or strange.

10. Reprimand is to disapprove strongly i.e rebuke.11. Timid means not brave but nervous and unconfident i.e. shy.


12. Ironic means something humorously said that you actually don’t mean i.e.sarcastic.

13. Stringent means very strict that must be hard to challenge.

14. Turn-up means to arrive, to come to the forefront or to showup.15. Shallow denote something not very solid or significant or substantial but

superficial.16. Combat means fight during the time of war between nations.17. Intimidate means to threaten someone to do what you want i.e. frighten by

threats.18. Tepid means slightly luke warm, sometimes in a way that is not very pleasant.19. Destitute is a person without money, food and other things necessary for life

or we can say a poor person.20. Ascend is to rise, to go up, to climb or to mount up.21. Synopsis is a brief summary of a piece of writing or a report.22. Ponder is to consider something carefully or to think deeply.23. Abundant is something in excess or quantity which is plenty.24. Shiver is to shake slightly in fear or cold i.e. tremble.25. Vigour means energy, force, enthusiasm or strength.

III. 1. Dear means expensive or costly and cheap means not highy priced.2. Liability means something a person owes where as assets are something a

person owns.3. Virtuous means having better state and vicious means in very bad and severe

state.4. Lend is to give and borrow it to take from someone.5. Repel is to drive away something or somebody and attract is to go near.6. Synthetic is artificial, man-made and natural is god-made.7. Adaptable is to change as per the situation and rigid is something which

cannot be changed easily i.e. stubborn.8. Relinquish means to stop having something i.e. to leave and possess means

to carry something.9. Enormous is large or huge and tiny is very small or minute.

10. Hostile means aggressive or quarrelsome and is not friendly.11. Valuable means something useful and precious and worthless is unuseful or

not required.12. Confuess is to admit or accept and deny is to nullify or to say that something

is not true.


13. Hindrance is an obstacle or hurdle and aid is a help in doing something.

14. Hollow is empty from inside and solid is filled from inside.

PASSAGE-BASED MCQs

I. 1. Option (c) is the correct answer as latest medical reports present this fact.2. Option (d) is the correct answer as it was called a dismal fact.3. Option (b), the fact is given in the 5th line of the passage.4. Option (a), reason is given in the 6th line of the passage.5. Option (d), reason is given in the 10th line of the passage.6. Option (c), there is a doubt on the predictions of immortality.7. Option (c), since the scientific fraternity rarely take this problem seriously.

II. 1. Option (d), since no other option supports the reason.2. Option (c), evil denotes something that can cause harm.3. Option (a), reason is given in the 9th line of the passage.4. Option (b), reason is given in the 8th line of the passage.5. Option (b), reason is given in the 8th line of the passage.6. Option (b), infancy is very early stage of life.7. Option (a), the passage clearly explains how a religion got developed.8. Option (d), reason is given in the 9th line of the passage.9. Option (c), glorious is something that increases the fame and reputation or

we can say praiseworthly.III. 1. Option (c), reason is given in the 1st line of the passage.

2. Option (b), rest of the options are discarded from the fact that it is theperformance that matters.

3. Option (a), it is a general saying for something new which is emerginggradually.

4. Option (b), reason is given in the last line of the passage.7. Option (a), passage highlights the partical aspects of education in society.8. Option (b), author emphasizes on the lifelong learning.

IV. 1. Option (c), reason is given in the 1st line of the passage.2. Option (a), reason is given in the 4th line of the passage.3. Option (b), tender means something soft and delicate.4. Option (d), reason is given in the 6th line of the passage.5. Option (b), reason is given in the 2nd line of the second paragraph of the

passage.6. Option (c), reason is given in the 9th line of the passage.

V. 1. Option (d), other options do not support the author’s views2. Option (b), reason is given in the 6th line of the passage.


3. Option (c), reason is given in the 7th line of the passage.6. Option (a), reason is given in the last line of the first paragraph of this

passage.7. Option (b), other options support the passage.8. Option (c), reason is given in the 1st line of the second paragraph of this

passage.VI. 1. Option (c), reason is given in the 3rd & 4th line of the passage.

2. Option (d), reason is given in the 9th line of the passage.3. Option (a), reason is given in the 3rd & 4th line of the passage.5. Option (b), millions of trees will have to be planted in order to meet future

requirements.VII. 1. Option (d), the opening words of the passage supports the reason.

2. Option (a), reason is given in the 6th line of the first paragraph of the passage.3. Option (b), reason is given in the 2nd line of the 2nd paragraph of the passage.4. Option (a), last paragraph completely explains the reason.

VIII.1. Option (a), reason is given in the 2nd line of the passage.2. Option (b), reason is given in the 1st line of the second.3. Option (d), other options do not support the statement.4. Option (d), reason is given in the last 3rd line of the passage.

IX. 1. Option (d), these are facts given in the first paragraph of the passage.2. Option (a), reason is given in the introductory lines of the passage.3. Option (b), reason is given in the third line of the second paragraph.4. Option (c), reason is given in the fifth line of the fourth paragraph.5. Option (d), it means illegal.

X. 1. Option (c), reason is given in the third line of the first paragraph.2. Option (a), reason is given in the last line of the first paragraph.3. Option (b), reason is given in the fifith line of the second paragraph.4. Option (d), reason is given in the third line of the third paragraph.5. Option (b), deserted means left alone unoccupied, seperated from the rest.

XI. 1. Option (a), reason is given in the first two lines of the second paragraph.2. Option (b), reason is given in the fifth line of the second paragraph.3. Option (c), reason is given in the fifth line of the third paragraph.4. Option (a), reason author feared that his duties would be irksome.5. Option (a), option (b) and (c) do not support the passage7. Option (c), here lose means he losses sense for surroundings and get involved

completely in something.


8. Option (b), reason is given in the second line of the last paragraph.XII. 1. Option (c), it is a fact given in the beginning line of the passage.

2. Option (c), other options are not supporting the text given in the passage.3. Option (b), reason is given in the fifth line of the passage.6. Option (b), adverse means something that causes harm or creates difficulty,

opposite is something that facilitates or supports.7. Option (b), here inducing means increasing more improvements, which also

means augmenting something.XIII.1. Option (b), scenairo is repeated every year but is enacted or implemented.

2. Option (c), reason is given in fourth line of the second passage.4. Option (b), as rest of the options do not reflect the facts given in the passage.6. Option (b), reason is given by the fact that passenger subsidy accounted for

nearly 90% of the railway losses.8. Option (d), reason is given in the last fourth line of this passage.


HINDI












PRACTICE PAPER-1

Solutions to Practice Papers

SECTION-A1. (d) Plasmodium, a malarial parasitic protozoan is found in mosquitoes

(Anopheles). It completes its half life cycle in mosquito and after bitingPlasmodium enters in human body and completes its some stages of life cycleand causes malaria.

2. (a) The radius of the earth at equator is 6678 km.3. (c) Tritium atom prossesses 1 proton. It is an isotope of hydrogen with mass

number 3. The nucleus contains 2 neutrons and 1 proton 31 H .

7. (c) Ozone (O3) is found in stratosphere. It is the second layer of atmosphere.Temperature remians constant within stratosphere. It absorbs ultravioletrediations of the sun.

8. (c) Green plants use carbon dioxide gas for preparation of food. Green plantsconvert CO2 into glucose in presence of sunlight and releases oxygen.

6CO2 + 12H2O Sunlight

Chlorophyll in plant cellC6H12O6 + 6O2 + 6H2O

9. (d) Carbon dioxide gas is responsible for global warming because excess productionof CO2 increases temperature of atmosphere which is cause of melting ofglacier and rising sea level.

10. (a) In respiration process plants take in oxygen which enters through the tissuevia intercellular space or dissolves in tissue fluids.

11. (b) Neon gas is used to glow sign boards.12. (d) Ionosphere helps in radio-transmission because this layer contains ions.

SECTION-B

19. (b) a + 1 is a whole number for every whole number a.

20. (d) In the numbers aa and bb, neither bases nor exponents are same.

21. (c) For cxn to be a linear polynomial exponent of x must be unity (or n = 1) and cmust be non-zero real number (or c 0).

22. (b) A point is also called ‘point circle’.

23. (d) If an icecream parlour should be set up at a point equidistant from A, B andC, then every customer at A, B and C feels convenience to reach the parlour.


24. (d) Kind of Triangle Situation of the desired point

Acute angle Interior of ABCRight angle On the ABCObtuse angle Exterior of ABC

25. (a) Through three non-collinear points, one and only one circle can be passed.26. (c) The number of 1’s is increasing by one in every next term.27. (c) Shaded area = Area of rectangle – Total of areas of two white triangles

=18 × 12 – 2 × 12

× 8 × 6

=168 cm2

28. (a) Area = 12

× base × altitude = 12

× 10 × 10 = 50 cm2

29. (a) There should be 3 letters in English Alphabet between 3rd and 2nd letters aswell as 2nd and 1st letters.

30. (d) There should be one letter in English Alphabet between 4th and 2nd letters.31. (c) There should be 1 letter in English Alphabet between 1st and 2nd letters as

well as 2nd and 3rd letters.32. (d) Words should be alphabetically from third letter to 1st one.33. (a) In other figures, the black spot is nearer the arrow.34. (c) In others there is no black spot.35. (a) In others, arrows indicate anticlockwise direction.

36. (c) Other designs are made up of only the segments 4, 5, 6.

SECTION-C

37. (c) The activity was done in the past (he saw).39. (d) The burglars are plural and incedence occured in the past.40. (b) Activity had just occured, so past perfect tense is used.41. (b) Article ‘the’ is used before any designated post.43. (c) Simple past tense ‘was’ is used as incidence was of year 2000.44. (b) ‘In’ is used with any year date like ‘in 2012’.45. (d) Intervene means to indulge in others matters without being asked i.e. to

interfere.46. (a) Assimilate means to accumulate or collect something.47. (b) Erect means in an upright position i.e. straight.48. (c) Paused means to stop someone from doing something for a short time.49. (a) Immortal means one which can never die i.e. alive for ever.


50. (b) Disaster means an incident that causes harm or damage which is also calledas calamity.

51. (c) Recede means to decrease in intensity or size i.e. diminish.52. (a) Agitate means to make someone angry, irritated, annoyed.53. (a) One has to spent hours in order to get a unique idea.54. (d) The passage informs us about the working of the cartoonist.55. (c) The reason is given in the fourth line of the second paragraph.57. (a) One cannot assume to become a cartoonist.60. (a) Witty means to think unusual or unimaginable.

OR37383940414243

44

4546

4748

495051

5253545556


57585960

PRACTICE PAPER-2

SECTION-A

1. (a) Alcohol affects liver. Liver breaks down alcohol to remove it from body butmore drinking of alcohol damages liver by which liver cannot do its properfunctions.

2. (b) Iron sulphide is a compound as it has a definite composition of Fe and Sand these elements do not retain their properties in FeS.

3. (c) In a spring balance, stretching of spring depends on the force applied on spring.7. (b) Most of diseases enter our body through contaminated water. For example,

cholera, typhoid, jaundice, etc.8. (d) When a mosquito bites a healthy human being, the sporozoites (infectious

form) are injected into the body. They reach the liver and start multiplyingasexually within the liver cells. By bursting the liver cells the parasites arereleased into the blood.

9. (b) Japanese encephalitis virus enters our body through mosquito bite.10. (b) The main source of typhoid infection is contaminated food and water. Thus

infection caused by bacteria which are transmitted from faeces to ingestion.11. (d) HIV virus targets lymph nodes because it is centre of lymphocytes production.

Lymphoytes are responsible for immunity of our body.12. (a) Tuberculosis spreads through air because droplets which come out from

coughing of TB patients are transmitted by wind current.

SECTION-B

19. (c) Area of shaded part = Area of square – Area of triangle

= 82 – 12

× 8 × 3 = 52 cm2.

20. (b) ‘know’ has four distinct letters. So H will denote ‘hour’.21. (a) Let the operations were applied on the number x. Then the wrong operations,

that are,

12

1126

x give x = 660.

Correct answer = 660

6+12 = 122.


22. (a) Let list price = ` 100Then discounted price (SP) = ` (100 – x)When SP = ` (100 – x), list price = ` 100

When SP = ` y, list price = ` 100

100 –yx

23. (a) 3 5 7 9 11 133 6 11 18 27 38 51.

24. (c) 3 5 7 9 112 5 10 17 26 37.

25. (b) First term = – –

11 b a c ax x

1.

1

a

b c a b c

a a

xx x x x xx x

26. (b) Let radius of the inner circle be x. The line segmentsmade after joining centres of outer circles form a squareof side 2r long.

Diagonal of the square = 2 2rBut from figure, it is 2x + 2r.

2x + 2r = 2 2r

x = 2 – 1 r.

27. (c) 4 6 8 10 12 142 6 12 20 30 42 56.

28. (d) The given pattern is:13–1, 23–1, 33–1, 43–1, 53–1.

29. (a) In other line segments from up to down are in increasing order in counting.

30. (d) In others, square is in between two other designs.

31. (b) In others, the same design is reducing its size from left to right.

32. (c) In others, the middle design is the largest one.

Description for Q 33-36.The positions of E and G in the given figure may be between B and A or left to B or Ebe in between B and A and G be left to B.

33. (a) It is clear from figure that D is the tallest.

34. (d) Shortest is either B or G.

35. (a) C’s position is after D and F.

36. (b) There are exactly three objects right to A.


SECTION-C

37. (c) Man already expressed his desire to the peon, so use simple past tense.40. (a) Peon told the officer his intention of what he is going to do.42. (a) Tonic is always for somebody. Thus preposition ‘for’ is used.43. (c) It’s a general fact about morning that is always true.44. (a) Since subject is singular (He), verb is plural (gets). Here energy is neither

given nor be collected from somebody. Thus ‘gets’ is the correct alternative.45. (b) Emulate is to copy or follow exactly the same of something. Thus imitate is

the right meaning.46. (c) Spontaneous means something done unplanned in an sudden way in instant

or moment. Thus instinctive is the correct meaning.47. (a) Indifference means lack of interest or feeling towards something. Thus

disinterest matches perfectly.48. (d) Averse means not liking or wanting something i.e. not in favour of doing

something i.e. opposed to something.49. (c) Virtuous means very well behaved in a good condition, vicious very bad, cruel

or fierce state.51. (b) Repel means to drive away in order to avoid. Thus attract is the correct

antonym for it.52. (a) Capacious means having a lot of space to hold where as limited means

restricted to something in small amount.53. (a) It was referred as Karai plant in the third line of the first paragraph of the

passage.54. (b) Reason is given in the third line of the second paragraph.55. (c) Government ban is due to it being an endangered species.56. (d) Forest mafia has put the forest department in a great trouble dut to this

extraction.59. (b) This is a fact given in the second line of the second paragraph.60. (b) Alarming mean something that makes you cautious of checking something,

it is a signal of danger.OR

38394041424344


45.

46.47.

48.49.50.51.52.53.54.55.56.57.58.59.60.

PRACTICE PAPER-3

SECTION-A

1. (d) Cardiac muscles has 1–2 nuclei2. (c) Quantity of absorbed water = 7 g – 5g = 2 g

Percentage of water absorbed = 2

100 40%5

3. (b) m = 50 kgHeight of steps = 15 cm = 0.15 m.

No. of steps = 45.Total height = 0.15 × 45 = 6.75

Power =wt

=mght

P =50 10 6.75

9

= 375 W = 0.375 kWSo used power is 37 kW.


7. (c) J.J Thomson discovered electron.

8. (d) Atomic mass of electron is 1

1836 the mass of proton.

9. (c) Isomers vary in number of neutrons because isotopes contain different masses.

10. (c) 1249 12 04 6Be + nC

11. (d) Atomic mass is equal to number of neutorns + protons.12. (b) Atomic mass of helium ion is 4. Hence mass of helium ion is 4 times to the

mass of hydrogen atom.

SECTION-B

19. (b) The measure of ABC is independent of octagon ABPQRSTU.

20. (b) a bb c

ac = b2

Now, a4 : b4 = 4

4ab

= 2 2

4.a ab

=

2 42 2

2 4 :a b

a cc b

21. (b) Let a = 2, b = 3, c = 4The statement “(abc)3 = (abc)2 (abc)” is true for each of abc = 234 andabc = 2 × 3 × 4.

22. (b) From first figure, 3 dots cannot be opposite 4 dots as well as 5 dots. Fromsecond figure, 3 dots cannot be opposite 2 dots as well as 6 dots. Hence 1 dotis opposite 2 dots.

23. (c) Figures (i) and (iii) tell us yellow and orange are on opposite faces as theseare small faces. Figure (i) and (ii) tell us Green and Red are on opposite faces.So the face with question mark ‘?’ should be either Blue or Violet.

24. (d) Using 1st and 3rd column, we have, B = 13. Similarly we can obtain the valuesof A and C.

25. (a) 7 × (–1) + 6 × 1 = – 7 + 6 = –1 = .

26. (a)

5 5 5 5 536 41 46 51 56 61 .

27. (a)

3 5 7 9 11 130 3 8 15 24 35 48 .

28. (c) Display Number Number of Soup Cans

1 1=1

2 1 + 22 =5

3 1 + 22 + 32 =14

4 1 + 22 + 32 + 42 =30

5 1 + 22 + 32 + 42 + 52 =55


29. (d) The number in 3rd cell of each row is the sum of numbers in remaining twocells.

30. (b) Each column adds 18.

31. (a) The middle number of each column is the mean of the remaining two numbersof the column.

32. (c) The middle number of each row is obtained by subtracting 1st number from3rd number of the same row.

33. (b)

34. (c)

35. (a)

36. (c)

SECTION-C

37. (b) The action was completed recently, so use past perfect tense.

38. (a) The action happened in the past and is still going on. So use past continuoustense.

39. (c) Same as the explanation of 38.

40. (d) It is interrogative phrase in simple present. Explanation is same as that of37.

41. (a) General fact are made in simple present tense.

42. (c) This sentence is contradicitory to previous sentence. So ‘but’ is used.


45. (b) Mettle is the ability and determination to do something successfully in spiteof difficult conditions. Thus courage is the correct option.

46. (d) Lapse is a small mistake or an error.

47. (a) Mandatory is ‘required by law’ or necessary. We can also call it compulsory.

48. (c) Amity is the friendly relationship between people or nations

49. (b) Provocation is the act of making somebody angry or upset where as pacificationis making somebody calm and quiet.

50. (b) Gain is to profit and Lose is to take away something.

51. (a) Stringent is harsh and strict and Lenient is soft and not strict.

52. (c) Adaptable is one who changes easily and rigid is one who is stubborn andcannot change his view point easily.

53. (b) This fact is given in the second line of the first paragraph.

54. (c) Non-English speaking countries have shown eagerness to pick up thislanguage.

55. (d) These are facts given in the second paragraph.

56. (b) Ample means more than required i.e., quite sufficient.

57. (a) This fact is revealed in the first line of the third paragraph.

58. (d) All the three options support the fact given.

60. (b) Author disapprove of cynicism towards the study of English.OR

37.38.

39.

40.41.42.

43.44.45.

46.


47.

48.

49.

50.

51.

52.53

54.

55.56.

57.

58.59.

60.

PRACTICE PAPER-4

SECTION-A

1. (c) Brass is a solid solution containing 70% of copper and 30% of zinc.

2. (c) Cell wall is made up of cellulose.

3. (b) Relative density of ice is 0.9 so it floats on water.

7. (b) Particles of suspension is visible through naked eye because it is heterogeneousmixture in which solid particles are insoluble in a solvent.

8. (b) Dust particle in air is an example of colloidal solution because dust particlescan be seen if light is passed through them.

9. (c) When light is passed through a solution, its path illuminated. The solution iscolloidal solution.

10. (d) Shaving cream foam is an example of solution of gas in liquid.

11. (a) Salt solution will not scatter light because it is a true solution.

12. (c) Electric chimney is based on electrophoresis. Smoke particles get attractedtowards charged electrode.


SECTION-B

19. (b) None of the numbers 1, 2, 4 and 5 is opposite to face 3 as shown in the givenfigures.

20. (b) From the given figures, it is clear that the colour opposite to blue will neitherbe white nor green nor orange nor yellow. So it should be red.

21. (b) There are three squences in the given pattern as below:

22. (c) The true series is

2 2 2 2 24 8 16 32 64 128.

23. (a)

24. (d)

25. (a)

26. (b)

AE = 12 – 10 = 2 m.

27. (b) a + b + c = 180º

The sum of all the exterior angles of any polygon including triangle

= 360º

= 2 × 180º

= 2 (a + b + c).


28. (b) 2805 11002.55 1

Dividing numerator by 10 and multiplying denominator by 10 to both sides,

we have 280.5 110

1125.5 10

.

29. (d) The numbers outside the figure add a number equal to the number insidethe figure.

30. (a) 10 + 5 –12 = 3

5 + 4 – 7 = 2

3 + 4 – 5 = 2

31. (d) Middle number = sum of above and below numbers

– Sum of left and right numbers.

32. (d) Inside number = mean of all outside numbers.

33. (a) After placing the design of option (a), the vertical line will become a line ofsymmetry.

34. (b) After placing the design of option (b), the vertical line will become a line ofsymmetry.

35. (b) After placing the design of option (b), the vertical line will become a line ofsymmetry.

36. (b) After placing the design (b), we get the figure as shown.

SECTION-C

37. (b) The action has been taken before, so use of present perfect tense.38. (a) The wise was expressed to do action in this time. So future perfect tense is

used.39. (c) Same as the explanation of 38.41. (b) Option (a) and (d) are not appropriate. No comparison with other object, so

we cannot consider (i). We use an objective with ‘very’. Thus costly is the rightchoice.

42. (c) One is afraid of some noun not a verb. Thus option (c) is the right choice.45. (b) Amused means something that is funny or makes laugh whereas saddened

means something that is unhappy and unpleasent.


46. (c) Friendly means behaving in a kind and pleasent way whereas Hostile meansbehaving in an arrogant and rude way.

47. (d) Abounds means something that exist in great number or quantities. Lacksmeans something that is present in very small quantities or is almost absent.

48. (b) Reluctant means not liking to do something or try to avoid something. Willingmeans showing interst in doing something.

49. (a) Scintillating means very bright and shining.50. (c) Adversity means a difficult or unpleasant situation, misfortune also means

an unpleasant event or condition.51. (d) Error is a mistake or wrong done and Blunder is also carelessness in doing

something in wrong way.52. (c) Massacre is the killing of great number of people and slaughter is also the

killing of animals for meat.53. (c) This fact is given in the second line of the first paragraph.54. (a) Common language is the means of communication between the Eskimos

located for away.55. (d) Only this fact is not mentioned in the passage.56. (c) This fact is given in the first line of the second paragraph.57. (c) Economic system of Eskimos works lika a commune.60. (c) This is the only fact which is false.

OR

37.

38.

39.

40.41.42.43.44.45.46.47.48.


49.50.

51.

52.

53.

54.55.56.

57.58.

59.60.

PRACTICE PAPER-5

SECTION-A

1. (c) In uniform circular motion body is moving at a distance so that speed remainsconstant but velocity continuously changes its direction.

2. (b) 1 mole of H2O2 = 2 × 1 + 2 × 16 = 34 g34 g of H2O2 = 1 mole

17 g of H2O2 =1

34 × 17 =

12

= 0.5 mole

3. (d) The common name of Indian honey bee is Apis cerana indica.7. (b) If moon stops its revolution, it will fall towards the earth.

8. (c) F = 1 22G

m md

F 21d

F = 21

16

= 36 times


9. (b) m1 = m2 = 1 kgd = 1 mG = 6.67 × 10–11 m2/kg2.

F = 1 22G

m md

= 6.67 × 10–11 × 21 11

F = 6.67 × 10–11 N

10. (c) g = 2GMr

= 2

GM

R h( r = R + h)

= Acceleration due to gravity does not depend upon mass.11. (d) Force of gravitation between two bodies does not depend upon sum of their

masses. It depends upon product of their masses.12. (c) For the earth escape velocity is 11.2 km/s.

SECTION-B

19. (b) The prescribed sets of numbers are: 742, 746, 741, 746.

20. (c) Figure (i): Neither 1 nor 6 is opposite to 3

Figure (iii): Neither 1 nor 5 is oppposite to 3

Figure (iv): Neither 2 nor 6 is opposite to 3

Hence 4 is opposite to 3.

21. (b)

22. (a) Married Unmarried

Enginneer Ramesh SureshDoctor Mukesh Lokesh

23. (a) Let Sunil’s son can do the whole work in x days.

1 1 1 1 – 5 55 5 – 5

m mx

x m x m m

24. (b) (3 – 15 ÷ 11) × 8 + 6 = (3 × 15 + 11) ÷ 8 – 6= 56 ÷ 8 – 6= 1


25. (b)

26. (b) Volume of cone =1

π3 × radius2 × height

= 21π. .

3h r = 21

3πrh .

27. (c) Let x be the semiperimeter of the given triangle. Then

x =

2 2

a b c s

Area = ( – ) ( – ) ( – )x x a x b x c =

– – –2 2 2 2s s s s

a b c

=

– 2 – 2 – 22 2 2 2s s a s b s c

= 1

– 2 – 2 – 24

s s a s b s c

28. (d) a > b

–

100 – 1100

a b a xx

b b

.100bx

a b

29. (d) The whole figure has been rotated anticlockwise by 90º.

30. (c) The lower half design has been blacked and the black point has been shiftedfrom left to right.

31. (d) One link from each zigzag line has been removed. The symbol ‘+’ has beenconverted to ‘–’ and its place has been changed from right to left.

32. (c) The same design is put vertically in the middle of the given design and abright square is shown in the centre.

33. (c) – 6 8 10 123 9 17 27 39

34. (b) 4 4 4 4 4– 5 –1 3 7 11 15.


35. (d) There are two sequences:

5 7 94 9 16 25 .

1 1 12 3 4 5 .

36. (b) There are three sequences:

SECTION-C

37. (c) Somebody was asked to do ‘as’ was instructed.38. (d) ‘Till’ is used to represent a condition to occur at a certain time.40. (b) Here, two phrases are contradictory to each other and joined by conjunction

‘or’ to make sentence.43. (b) The word ‘than’ is use to compare two things. Here what a person did is better

than what was expected of him.44. (c) The two events are independent as well as complimentary to each other and

are joined by conjunction ‘and’.45. (c) Benevolence means very kind, helpful and generous. Thus this word also means

kindness.46. (b) Annihilated means completely damaged and no more exist i.e. destroyed.47. (a) Propensity shows a general tendencey to a particular kind of behaviour. This

shows a natural tendency.48. (b) Garrulous is a person who speaks execessive, more than is required. Thus

talkative is correct synonym for it.49. (a) Obeying is to follow an order where as ordering is to give a command.50. (b) Vanity means a feeling of pride whereas humility is the feeling of inferiority

or humbleness.51. (d) Pertinent means appropriate to a particular situation and irrelevant means

not in context of a particular situation.52. (c) Lucid means clearly expressed and obscure is difficult to understand i.e.

unclear.53. (c) Health is made from consuming nutritive things which is mentioned in the

second line of the passage.54. (a) Only scented flowers smell good.56. (b) It is a fact mentioned in the first line of the third paragraph.58. (b) This fact is given in the third line of the first paragraph.60. (d) Fourth line of the third paragraph mentions this fact.


OR37.

38.

39.40.

41.42.43.

44.45.

46.47.

48.

49.50.51.

52.53.54.55.

56.57.58.59.60.

Documents

Solutions to Me n Mine Psa-ix