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7/13/2011 H. Esteban Physical Properties of Solutions

Solutions & Colligative Properties

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Page 1: Solutions & Colligative Properties

7/13/2011 H. Esteban

Physical Properties of Solutions

Page 2: Solutions & Colligative Properties

7/13/2011 H. Esteban

A solution is a homogenous mixture of 2 or more substances

The solute is the substance present in the smaller amount

The solvent is the substance present in the larger amount

Determines the state of matter in which the solution exists

Page 3: Solutions & Colligative Properties

7/13/2011 H. Esteban

Types of Solutions according to components

Page 4: Solutions & Colligative Properties

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Types of Solutions according to amount of solute present

saturated solution contains the maximum amount of a solute that will dissolve in a given solvent at a specific temperature.

unsaturated solution contains less solute than the solvent has the capacity to dissolve at a specific temperature.supersaturated solution contains more solute than is present in a saturated solution at a specific temperature.

Page 5: Solutions & Colligative Properties

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Mass percent. (m/m)

Volume percent. (v/v)

Mass/volume percent. (m/v)

Isotonic saline is prepared by dissolving 0.9 g of NaCl in 100 mL of water and is

said to be:

0.9% NaCl (mass/volume)

Solution Concentrations

Page 6: Solutions & Colligative Properties

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Solution Concentrations

10 % (v/v)8.03 % (m/m)7.89% (m/v)

•Mole fraction•Mole Percent•Molarity•Molality

Page 7: Solutions & Colligative Properties

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Solution Concentrations

= Amount of component i (in moles)

Total amount of all components (in moles)

1 + 2 + 3 + …n = 1

Mole % i = i x 100%

Page 8: Solutions & Colligative Properties

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Solution Concentrations

Molarity (M) = Amount of solute (in moles)Volume of solution (in liters)

Molality (m) = Amount of solute (in moles)

Mass of solvent (in kilograms)

Page 9: Solutions & Colligative Properties

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Separation of Solute

must overcome IMF or ion-ion attractions in solute

requires energy, ENDOTHERMIC ( + DH)

Separation of Solvent

must overcome IMF of solvent particles

requires energy, ENDOTHERMIC (+ DH)

Interaction of Solute & Solvent

attractive bonds form between solute particles and solvent particles

“Solvation” or “Hydration” (where water = solvent)

releases energy, EXOTHERMIC (- DH)

Page 10: Solutions & Colligative Properties

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Intermolecular Forces and the Solution Process

DHsoln = DH1 + DH2 + DH3

Page 11: Solutions & Colligative Properties

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Intermolecular Forces and the Solution Process

Page 12: Solutions & Colligative Properties

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“like dissolves like”

Two substances with similar intermolecularforces are likely to be soluble in each other.

• non-polar molecules are soluble in non-polar solvents

CCl4 in C6H6

• polar molecules are soluble in polar solvents

C2H5OH in H2O

• ionic compounds are more soluble in polar solvents

NaCl in H2O or NH3 (l)12.2

Page 13: Solutions & Colligative Properties

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Factors affecting solubility

1. Temperature

For Solids; solubility increases with increasing temperature (with some exception)

Page 14: Solutions & Colligative Properties

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Factors affecting solubility

for Gases; solubility decreases with increasing temperature

Page 15: Solutions & Colligative Properties

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Factors affecting solubility

2. Pressure

i) Solids/Liquids - Very little effect

Solids and Liquids are already close together, extra pressure will not increase solubility.

ii) Gas - Solubility increases with Pressure.

Increase pressure squeezes gas solute into solvent

Page 16: Solutions & Colligative Properties

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The solubility of a gas in a liquid is proportional to the pressure of the gas over the solution.

c = kP

c = solubility of the gas (M)k = Henry’s Law ConstantP = partial pressure of gas

Page 17: Solutions & Colligative Properties

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The solubility of pure N2 (g) at 25oC and 1.00 atmpressure is 6.8 x 10-4 mol/L. What is the solubility of N2 under atmospheric conditions if the partial

pressure of N2 is 0.78 atm?

Step 1: Use the first set of data to find “k” for N2 at 25°C

Step 2: Use this constant to find the solubility (concentration) when P is

0.78 atm:

44 16.8 10

6.8 101.00

c x Mk x M atm

P atm

4 1 4(6.8 10 )(0.78 ) 5.3 10c kP x M atm atm x M

Page 18: Solutions & Colligative Properties

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Exercises:

1. A 11.3 ml sample of methanol ( CH3OH d = 0.793g/ml) is dissolved in enough water to produce 75.0ml of a solution with a density of 0.980 g/ml. What is the solution concentration expressed as (a) mole fraction of H2O; (b) molarity; (c) molality?

2. Laboratory ammonia is 14.8 NH3 (aq) with a density of 0.8980 g/ml. What is XNH3 in this solution?

3. A 10.00% by mass aqueous solution of sucrose C12H22O11, has a density of 1.040 g/ml. What is (a) the molarity; (b) the molality, and (c) the mole fraction of C12H22O11 in the solution?

Page 19: Solutions & Colligative Properties

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4. In which solvent is I2 likely to be more soluble, water or CCl4? Explain.

5. Henry’s Law. At 0 degree Celsius and an O2 pressure of 1.00 atm, the aqueous solubility of O2(g) is 48.9 ml O2 per Liter. What is the molarity of O2 in a saturated water solution when the O2 is under its normal partial pressure in air , 0.2095 atm?