solution coulson chap 3

8/14/2019 solution coulson chap 3

1/13

Solution 3.1

Energy = 850)3100(P

P ==

x 10 5

= 11,412 J kg -1

Power =

s

kgkgJ

= 11,412

36001000

= 3170 W

Solution 3.2

liq H = = 210x22.4)10x22.4(2

3

100

0

100

0

3 t t dt t

= 420 10= 410 kJ kg -1

evap H = 40,683 J o! -1 ("ro #$$en%&x ')

=18

40683 = 2260 kJ kg -1

"ro #$$en%&x , *e s$e+& &+ *e o *e $o/r &s g& en y

C p = 32.243 1 .238 x 10 -4T 10.555 x 10 -6 T 2 3.5 6 x 10 - T 3

W*ere C p &s &n J o!-1 -1 n%T &s &n . ow 100o = 273.15 n% 200 o =373.15 .

vap H =

++15.373

15.273

3264 )10x5 6.310x555.1010x238.1243.32( dT T T T

= ++ )4

10x5 6.33

10x555.102

10x238.1243.32(43

62

4

15.373

15.273

T T T T

0o

200o

H liq

H evap

H vap


2/13

= 12,330.8 8 45.7

= 3385.1 kJ k o! -1

=18

1.3385

= 188.1 kJ kg -1

*ere ore, s$e+& &+ en * !$y

liq H = 410

evap H = 2260

vap H = 118.1

2778 kJ kg -1

"ro e !es 2876 kJ kg -1. Error = 8 kJ kg -1 (3.5 9).

Solution 3.3

!+/! &on o *e en * !$y o re + &ons

1. : 2 2

H F (kJ o! -1) -110.62 0 -3 3.77

H R = -3 3.77 (-110.62) = -283.15 kJ o! -1

2. ; 2 : 2 ; 2

0 0 -242.00

H R = -242.00 0 = -242.00 kJ o! -1 ; 2

3. ; 4 2 2 2 2; 2

-74.86 0 -3 3.77 -242.00

H R =


3/13

H R = C -3)

o + !+/! e *e e B, s/ r + *e *e o $o/r&s &on o *e ;2 /rne%.


4/13

Solution 3.4

Do!e+/! r we&g* o n& ro en ene = 123 n% ;2 = 2

Do! r !ow o n& ro en ene = )3600)(123(2500

= 5.646 x 10 3 k o! s -1

Do! r !ow o ; 2 = )3600)(2( 366 = 50.833 x 10-3 k o! s -1

P r & ! $ress/re o n& ro en ene = 20=1083.5010646.5es o /se *e energy ! n+e $rogr sE E AK 1, $ ge 2 or E AK>#I, #$$en%&x H, o o&% e%&o/s + !+/! &ons. ' ons$e+& &+ *e s n% *e s o re + &on + n e o/n% &n #$$en%&x '.

W* o!!ows &s n o/ !&ne so!/ &on o *&s $ro !e .

o!/ &on 1.T sat or !2 ro #n o&ne EF/ &on (#$$en%&x '),

2. H reaction ro *e ; ! *e o or &on,

1.5 r

W

200 o

50 o

10,000 yr -1 ; !;

2 !

2 2; !

D ss ! n+e (1 9 ex+ess) g& es ee%.!2 T

sat

5 9 ; 2 5 9

2

25 o


8/13

3. C pGs ro #$$en%&x ',

4. e + or ! n+e o 200o (4 9 ree ! 2),

5. ' / e $er /re 25 o ,

6. Hgnore $ress/re e e+ s on C pGs.

e + or

H - 1. ; 2 2 = ero ( % / e $er /re),

2. ! 2 T sat (no e s g s, H reaction or g ses),

3. H reaction 25o ( 6 9 ! 2 re + e%).

C - 1. ; ! ! 2 ; 2 (ex+ess) 2 200o ,

2. oo!&ng &n L +ke .

oo!er

H - 1. e + or o/ !e ;,

2. 4 9 ! 2 re + e% ( H reaction ).

C - 1. ens& !e *e o ; !, ; 2 (ex+ess) n% 2,

2. ;e o +oo!&ng w er.

*e+k on T sat

01.2732.1 78610.15)7505.1!n( = sat T

026.7610.1501.27

32.1 78 = sat T

01.2735.8

32.1 78 += sat T = 248.4

T sat = -24.6 o (W& *&n *e e $er /re !& & s)

*e ! 2 y nee% $re*e &ng.

Solution 3.7

#s P 2 M P critical , *e s& $!& &e% eF/ &on + n e /se%.

2 100 3 * -10.5 r, 20 o

5 r


9/13

= 1.4 or &r.

=

11

1

1

211

nn

P P

nn

v P w

w*erem

n= 11

n% p E

m

1= .

o $ress&on r &o = 10 ro "&g/re 3.7, E p = 86 9.m

P

P

T T

= 12

12

)86.0)(4.1(14.1 =m = 0.33, 4.1

33.011 ==

n .

33.0

2 110

)27320(

+=T = 626 = 353 o

Hn $r + &+e *e +o $ressor +y!&n%er wo/!% e & e% w& * +oo!&ng L +ke .

1v = 100 3 * -1 = 0.0278 3 s-1

( ) =

11014.1

4.1)0278.0)(10( 4.114.1

5w

= .6 kW ( y 10 kW)

Solution 3.8

>/rner o$er &ng $ress/re, 600 k -2 reF/&re%. ke /rner s o$er &ng 1 . = 102

k -2 g or 600 k -2 g.

; 2 &s +o $resse% ro 120 k -2 o 600 k -2.

;2 or

; !

10,000 kg * -1 ; !

;2 !

2 2; !


10/13

Press/re r &o = 5120600 =

Hn er e%& e $ress/re = 268)600)(120(21 == P P k -2

o e "or ; 2 *e &n!e e $er /re w&!! no e *e s e s *e &n er+oo!er o/ !e so *e

+oo! s ge s*o/!% e + !+/! e% se$ r e!y.

# er& ! ! n+e g& es *e ;2 !ow. *e 1 9 ex+ess ; 2 &s &gnore% &n *e ; !

+o $ressor + !+/! &on.

D er& ! ! n+e

; ! $ro%/+e% = )3600)(5.36(000,10

= 0.0761 k o! s -1

; 2 reF/&re% = 01.120761.0 = 0.0384 k o! s-1

! 2 reF/&re% =

20761.0

= 0.0381 k o! s -1

Ex+ess ; 2 = 0.0384 0.0381 = 0.0003 k o! s -1

*e s& $!& &e% eF/ &ons (3.36 n% 3.38 ) + n e /se% s&n+e +on%& &ons re r re o e%

ro +r& &+ !.

ke 4.1= s&n+e o * ;2 n% ; ! re %& o &+ g ses.

408.0)7.0)(4.1(

)14.1( ==m (3.36 )

68.1408.01

1 ==n (3.38 )

=

11

1

1

211

nn

P P

nn

v P w (3.31)

; 2

1s ge

=

2732 8

1012010013.1

4.222

3

5

1v = 0.0823 3 kg -1

=

1120268

168.168.1

)0823.0)(10120(68.1

168.1

31

w = ,3 1 J kg -1


11/13

2n% ge

=

273323

1026810013.1

4.222

3

5

1v = 0.03 3 kg -1

=

1268600

168.168.1

)03.0)(10268(68.1

168.1

32

w = 10,204 J kg -1

Power = ( ,3 1 10,204)(0.0384)(2) = 1505 W = 1.505 kW

; !

ke o * s ges s $er or &ng eF/ ! work w& * *e s e &n!e e $er /re.

5.246)600)(3.101(21 === P P P i k -2 (3.3 )

= 273323

10013.110013.1

4.225.36

5

5

1v = 1. 27 3

kg-1

=

13.101

600168.1

68.1)27.1)(10013.1(

68.1168.1

51

w = 510,173 J kg -1

Power = (510,173)(0.0761)(36.5) = 1,417,082 W = 1417 kW

H &s ne+ess ry o %& &%e y *e e &+&en+y o ge *e + / ! $ower / & &s +!e r *

es +*o&+e &s o +o $ress *e ;2 n% o$er e *e /rner /n%er $ress/re.

*e+k

e $er /re o s /r e% !2 600 k -2.

01.2732.1 78

610.1532.13310600

!n3

=

T

412.8610.1501.27

32.1 78 =T T = 262 27.01 = 28 = 16 o

Solutions 3.9 and 3.10 .

e er o ex $!e 3.17 n% *e worke% so!/ &on o $ro !e 3.12


12/13

Solution 3.11

T s T t C p

re s (o ) ( o ) (kW o -1)

Pre*e er 20 50 30

50 o 20 o

on%enser 1 ; 70 60 135

70 o 60 o

on%enser 2 ; 65 55 110

65 o 55 o

e o&!er 1 85 87 700

87 o 85 o

e o&!er 2 75 77 45077 o 75 o

oo!er ; 55 25 1

55 o 25 o

"or T min = 10 o

5+= out int T T (+o!%)

5= out int T T (*o )

re y$e T act T int

1 20 50 25 55

2 ; 70 60 65 55

3 ; 65 55 60 50

4 85 87 0 2

5 75 77 80 82

6 ; 55 25 50 20

1

4

5

2

3

6

00 kW

1350 kW

1100 kW

1400 kW

00 kW

30 kW


13/13

nke% re s

(o ) kW s+ %e #%%

2 0 2300

0 1400 -1400 00

82 0 -1400 00

80 00 -2300 0

65 0 -2300 0

60 -550 -1750 550

55 -1225 -525 1775

50 -400 -125 2175

25 725 -850 1450

20 5 -855 1445

( ) ( )( T C C H H pC p

= ;o C &!& &es = 2300 kW

o!% C &!& &es = 1445 kW

P&n+* = 60 82o

;

;

;

4

5

6

3

1

2

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solution coulson chap 3