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Simplify a.b. Simplify. 3ab 23ab 2 = = 1 1x 31x 3 Use the definition of negative exponent. = x 3 Identity Property of Multiplication ALGEBRA 1 LESSON 8-1 = 1 x 3 Multiply by the reciprocal of, which is x 3. 1 x 3 Rewrite using a division symbol. = 1 x –3 Zero and Negative Exponents 3ab –2 1 b 2 Use the definition of negative exponent. = 3a x –3
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Simplify.
a. 3–2
Simplify.19=
ALGEBRA 1 LESSON 8-1
(–22.4)0b. Use the definition of zero as an exponent.
= 1
Zero and Negative Exponents
8-1
=Use the definition of negative exponent.
1 32
Let’s try:
Turn to page 395. Let’s try:A.Answer: 1 81B.Answer: 1C. Answer: 1 -64D. Answer: 1 7E.Answer: - 1 9
Simplify
a. b.
Simplify.3ab 2=
= 1 1x 3
Use the definition of negative exponent.
= x 3
Identity Property of Multiplication
ALGEBRA 1 LESSON 8-1
= 1 • x 3
Multiply by the reciprocal of , which is x 3.
1 x3
Rewrite using a division symbol.
= 1 x –3
Zero and Negative Exponents
3ab –2 1 b2
Use the definition of negative exponent.
= 3a
8-1
1 x –3
Evaluate 4x 2y –3 for x = 3 and y = –2.
Method 1: Write with positive exponents first.
Substitute 3 for x and –2 for y.4(3)2
(–2)3=
36–8 –41
2= = Simplify.
ALGEBRA 1 LESSON 8-1Zero and Negative Exponents
8-1
4x 2y –3 = Use the definition of negative exponent.4x 2
y 3
(continued)
Method 2: Substitute first.
4x 2y –3 = 4(3)2(–2)–3 Substitute 3 for x and –2 for y.
4(3)2
(–2)3= Use the definition of negative exponent.
36–8 –41
2= = Simplify.
ALGEBRA 1 LESSON 8-1Zero and Negative Exponents
8-1
22.
23.
24.
25.
26.
27. 4c3
28.
29.
30.
31.
32.
ALGEBRA 1 LESSON 8-1Zero and Negative Exponents
pages 397–399 Exercises
1. –1
2.
3.
4. –
5.
6. –
7.
8. –
9. 1
10.
1 16 1 25
1 25
1 16
1 81
1 64
1 12
1 78
11. –
12. –
13. –2
14. 3; 4
15. 0; –3
16. –5
17. 3a
18.
19. x 7
20. c
21.
1 64 1 64
5 x 4
1 a 4
1 25p
3 x 2 y 7a 3b 2 w 1 x 5 y 7
7st 3 5
6 ac 3
x 2 8z 7
y 7 x 5
y 7 t 11
14 m 2t 5
33.
34.
35. –
36. 1
37.
38.
39.
40.
41. –
42.
43. –27
1 2519
19
3 25 1 10025818125
2527
1 25
8-1
ALGEBRA 1 LESSON 8-1Zero and Negative Exponents
44. –
45. a. $20.48; $.32b. No; the value of the
allowance rapidly becomes very great.
46. neg.
47. pos.
48. pos.
49. neg.
50. neg.
51. 10–1
52. 10–2
53. 10–3
27 400
54. 10–4
55. 10–5
56. 0.00157. 0.00000158. 0.759. 0.0360. 0.000561. a. 5–2, 5–1, 50, 51, 52
b. 54
c.
62. In –30, 3 is raised to the zero power, and then the opposite is determined. In (–3)0, the number –3 is raised to the zero power.
a n 1
63. 45
64. 6
65. 40
66.
67. –
68. 16
69.
70.
71.
72. –1
1 243
14
2918
1 16
8-1