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INSTRUCTION MANUAL.
SHELL AND TUBE HEAT EXCHAGER
SET UP
DESCRIPTION
SPECIFICATIONS
INSTALLATION REQUIREMENTS
INSTALLATION AND CONNECTIONS
PRECAUTIONS
TROUBLE SHOOTING
EXPREMENTATION
THEORY
OPERATING PROCEDURE’
SYSTEM CONSTANTS
OBSERVATION TABLE
CALCULATIONS
SHELL AND TUBE HEAT EXCHANGER.
AIM:
To determine the overall and individual heat transfer coff. In 1.2 shell & tube heat
exchanger.
INTRODUCTION:
Shell & tube heat exchangers are mostly used in chemical industries as a condenser,
cooler and heater. When the heat transfer are becomes more than 10 m², one has to go
for shell & tube heat exchanger, which occupies less space, offers reasonable pressure
drop, compared to other types of heat exchangers. Because of its wide utility.
Mechanical design has been standardized. Standards of TEMA are available covering in
details of materials, methods of construction, technique of design, and determinations
for exchangers.
THEORY:
The film heat transfer coff. Is a function of cross-sectional area of the fluid path. Thus,
decreasing the cross sectional area could increase the fluid velocity. This is achieved in
multi pass heat exchangers at the cost of pressure drop & temperature gradient
affecting due to concurrent flow. The temperature profile for 1-2-pass heat exchangers
is shown in the fig. 1. The factor Ft is the temperature difference correction factor,
when it is multiplied by the counter flow LMTD; the product is correct mean
temperature difference. Fig.2 shows the factor Ft as a function of two dimentionsless
numbers h & z, which are defined as
Tco - Tci
Z = Thi - Tho
Tho - Thi
Z = Tci - Tco
The factor h is the heating effectiveness of the ratio of the actual temperature rise of
the cold fluid to the maximum possible temperature rise if the warm end approach were
zeros. (Based on counter current flow.) The factor Z is the ratio of fall in temperature of
the hot fluid to the rise in temperature of the cold fluid. Interpolation is permitted I
using fig.2.
By keeping the flow rate and physical properties constant in the shell side fluid and
varying the flow rate of the tube side fluid, and applying Wilson’s plot it is possible to
get the outside (shell side) film heat transfer coff. As subsequently the inside (tube side)
film heat transfer coff.
EXPERIMENTAL SET – UP
A standard 1-2 pass shell and tube heat exchanger consist of
(A) Shell :
1) I.D. = 154 mm
2) Thickness = 6 mm
3) Material = MS
4) Baffle = 25% cut.
5) Baffle spacing = 57mm.
(B) Tube :
1) OD =12.5 mm
2) Thickness = 1.5 mm
3) Pitch – 20 mm triangular
4) No. Of tubes = nos.
5) Length – 1000 mm
The hot water tank (200 ltrs cap.) is provided with 6 kWh. Heaters and hot water is
pumped by centrifugal pump. The flow rates of the fluids are known by pre calibrated
rotameters. The cold water tank is of 200 ltrs, Capacity with centrifugal pump.
Thermometers are provided at inlet & outlets of the heat exchanger to know
temperature of the shell & tube sides by pass valves are provided to vary flow rates.
PROCEDURE:
1. Admit water into hot & cold water tanks and keeps heater on.
2. When the temperature of hot water reaches to 60 to 70 C, admit it into tube side of
the exchanger at fixed known flow rate.
3. Admit cold water into shell side of the heat exchanger. At steady state. Note down
temperature and flow rates of the shell and tube side fluids.
4. Keep the flow rate and temp. Of hot fluid constant and vary flow rate of cold water
at uniform intervals. Repeat the above procedure and note down readings.
Sr. Shell side fluid tube side fluid
1.
2.
3.
4.
5.
Flow rate outlet
temp
Inlet
temp.
Flow rate outlet temp Inlet temp.
Kg/hr.Mc C t2 C t1 Kg/hr.Mc C T2 C T1
ENERGY BALANCE:
Q = mh. Cph (T1 – T2) = mc .Cpc (t2 – t1)
Tlm = (T1 – t2) – ( T2 – t1) ln (T1 – t2) (T2 – t1) R = (T1 – T2) (T2 - t1) S = ( T2 – t1) ( t2 – t1).Find out factor Ft from graph (Process heat transfer by KERN page no. 828)
t = Ft X Tlm.
COLD FLUID ( SHELL SIDE)
As = ID X C’B /Pt.
Gs = W/As.
At Ta ( average temp. of cold fluid t1 +t2/2) find out .
To find out equivalent dia. De refer fig. 28 page 828.Res = De. Gs/.
To find out factor Jh i.e. factor for heat transfer (dimentionless) refer fig. 28 page 828.
At Ta = t1+ t2/2 find out specific heat of fluid, k-cal/kg-c.
Hence thermal conductivity k= k-cal/kgc.
1/3(c/k). 1/3ho = jh X k/De X (c/k). X 1.
HOT FLUID (TUBE SIDE) Flow Area per tube A’t = П/4 di² …m².Flow area of fluid = no of tubes X flow area per tube/no. of passes. …m².Now mass velocity Gt = mass flow/ area = w/at. Kg/hr.m².
Velocity = Gt/3600ρ. Where ρ = density kg/m³.
At ta = T1+T2/2 , = ….KG/m.hr.
D = inside dia. Of tube = m.
Re = DGt/.Calculate Hi from fig. 25 page 828 . Hio = Hi X ID/OD.
Now CLEAN OVERALL HEAT TRANSFER COFFICIENT Uc = HioX Ho HioxHo. Design overall heat transfer coff.Ud =
= Q/At. here A = external surface /m.
dirt factor = Rd = Uc – Ud/Uc X Ud.
PRESSURE DROP.SHELL SIDE.Find out factor f, for shell side Re. f = m²/cm.No. of crosses = N+1 = 12L/B where L= tube length m , B = baffle spacing m. Ds= inside dia. Of shell. M .
Ps = 8jf(Ds/de)(L/lb)ρ²/2.
Tube side pressure drop. = Pt = 8jf (L’/di). t²ρ/2. N/m².
DISCUSSION:
Energy balance gives
Q = mh Cph ( t hi – t ho ) = mc Cpc ( t co – t ci )
Which is related with overall heat transfer coefficient by,
Q = Uo Ao Δtlm X FT.
Flow area per tube = a’t = /4 dt², m².
at = flow area of fluid = no. of tubes X flow area/tube No. of passes.
= Nt a’t /n m².
Now mass velocity of the tube side fluid,
= Gt = mc/at,
and get Rei = dt Gt/µ.
Now Gt = Vi/.
Vi = Gi/ m/hr. plot the graph of 1/Uo Vs 1/Vi