Shear-Strength-of-Soil.pdf

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    CEL 610 Foundation Engineering

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    Strength of different

    materials

    Steel Concrete Soil

    Tensile Compressive Shear

    Presence of pore waterComplex

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    Shear failure of soils

    Soils generally fail in shear

    Embankment

    Strip footing

    Failure surface

    Mobilized shear

    resistance

    At failure, shear stress along the failure surface

    (mobilized shear resistance) reaches the shear strength.

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    Shear failure of soils

    Soils generally fail in shear

    Retaining

    wall

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    Shear failure of soils

    Soils generally fail in shear

    Retaining

    wall

    Mobilized

    shear

    resistance

    Failure

    surface

    At failure, shear stress along the failure surface

    (mobilized shear resistance) reaches the shear strength.

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    failure surface

    The soil grains slideover each other alongthe failure surface.

    ruindividual grains.

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    At failure, shear stress along the failure surface ()reaches the shear stren th .

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    Mohr-Coulomb Failure Criterion

    in terms oftotal stresses

    tancf

    Cohesion Friction angle

    cf

    f failure, under normal stress of .

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    Mohr-Coulomb Failure Criterion

    in terms ofeffective stresses

    'tan'' cf

    u

    =

    Effectivecohesion Effective

    pressure

    cr c on ang ef

    f failure, under normal effective stress of .

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    Mohr-Coulomb Failure Criterion

    Shear strength consists of two

    com onents: cohesive and frictional.

    ''' ff f frictional

    c c

    component

    f '

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    .

    , .

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    Mohr Circle of stress

    1

    33

    Soil element

    1

    '

    3

    '

    1

    ,

    2''''

    '

    '

    3

    '

    1

    '

    3

    '

    1'2

    22os

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    Mohr Circle of stress

    1

    11

    Soil element

    33

    Soil elementSoil element

    33 33

    1

    11

    '

    3

    '

    1

    '

    3

    '

    1'2

    2

    '

    3

    '

    1

    2

    '

    3

    '

    1 '

    3'

    1

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    Mohr Circle of stress

    1

    11

    Soil element

    33

    Soil elementSoil element

    33 33

    1

    11

    , '

    3

    '

    1

    '

    3

    '

    1'2

    2

    '

    3

    '

    1

    2

    '

    3

    '

    1 '

    3'

    1

    PD = Pole w.r.t. plane

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    Mohr Circles & Failure Envelo e

    Failure surface

    'tan'' c

    X XY

    Y

    Soil elements at different locations

    Y ~ stable

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    Mohr Circles & Failure Envelo e

    The soil element does not fail if

    within the envelope

    Y

    cc

    c

    Initially, Mohr circle is a point

    c+

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    Mohr Circles & Failure Envelo eAs loading progresses, Mohr

    circle becomes larger

    Yc

    cc

    .. and finally failure occurs

    when Mohr circle touches the

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    Orientation of Failure Plane

    11 Failure envelope

    , f33

    33

    1

    1

    '3

    '

    1 '

    3'

    1

    2

    PD = Pole w.r.t. plane

    Therefore, =

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    Mohr circles in terms of total & effective stresses

    v uv

    = Xh

    Xu

    +Xh

    effective stresses

    total stresses

    oru

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    Failure envelopes in terms of total & effective

    v uv

    = Xh

    Xu

    +Xh

    If X is onfailure

    Failure envelope interms of total stressesFailure envelope in terms

    of effective stresses

    effective stressestotal stresses

    orccu

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    Mohr Coulomb failure criterion with Mohr circle

    v = 1 Failure envelope in termsof effective stresses

    X

    h = 3

    effective stresses

    c X is on failure 13

    Therefore,

    2

    '2

    '' 3131

    SinCotc

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    Mohr Coulomb failure criterion with Mohr circle

    '''

    '

    3

    '

    1

    '

    3

    '

    1

    22

    '''' ''2'3131 oscin

    '''' '' 31

    ''

    '1'' CosSin '1'131 SinSin

    ''

    '2''

    2231

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    Determination of shear strength parameters of ,

    specimens taken from

    representative undisturbedsamples

    os common a ora ory es s

    to determine the shear strengthparameters are,

    . ane s ear es

    2. Torvane

    3. Pocket penetrometer

    1.Direct shear test

    2.Triaxial shear test

    4. Fall cone

    5. Pressuremeter

    6. Static cone enetrometer

    Other laboratory tests include,

    Direct simple shear test, torsional

    7. Standard penetration test

    r ng s ear es , p ane s ra n r ax a

    test, laboratory vane shear test,laboratory fall cone test

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    Laboratory tests

    Field conditions

    A re resentative

    zvc

    soil samplez

    vc +

    hc hchc

    vc vc

    Before construction er an ur ng

    construction

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    Laboratory testsvc +

    Simulating field conditionsin the laboratory

    hchc

    vc0 vc +

    hchc00vc

    vc0

    Step 1Representative vc

    Set the specimen in

    the apparatus andtaken from the

    site

    ep

    Apply theapp y e n a

    stress conditioncorresponding field

    stress conditions

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    Direct shear test

    c ema c agram o e rec s ear appara us

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    Direct shear test

    rec s ear es s mos su a e or conso a e ra ne es s

    specially on granular soils (e.g.: sand) or stiff clays

    plates

    Components of the shear box Preparation of a sand specimen

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    Direct shear test

    Preparation of a sand specimen Pressure plate

    eve ng t e top sur ace

    of specimenSpecimen preparation

    completed

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    Direct shear test

    Test procedure

    Pressure plate

    ee aP

    Porous

    plates

    S

    Proving ring

    o measure

    shear force

    Step 1: Apply a vertical load to the specimen and wait for consolidation

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    Direct shear test

    PTest procedure

    Pressure plate

    ee a

    Porous

    plates

    S

    Proving ring

    o measure

    shear force

    Step 1: Apply a vertical load to the specimen and wait for consolidation

    Step 2: Lower box is subjected to a horizontal displacement at a constant rate

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    Direct shear test

    Shear box

    Dial gauge tomeasure vertical

    Proving ringto measure

    Loadin frame to Dial au e to

    shear force

    apply vertical load measure horizontaldisplacement

    Di t h t t

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    Direct shear test

    Analysis of test results

    (P)forceNormal

    stressNormal

    sampletheofsectioncrossofArea

    sur aces ngat t eeve operes stanceearstressShear

    Note: Cross-sectional area of the sample changes with the horizontal

    dis lacement

    Direct shear tests on sands

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    Direct shear tests on sandsStress-strain relationshi

    ss,

    Dense sand/

    ea

    rstr c ayf

    Loose sand/

    Sh NC clayf

    Shear displacement

    on

    Dense sand/OC Clayh

    eight

    p

    leExpans

    Loose sand/NC Claangein

    thesa

    ssion Shear displacement

    C of

    Com

    pre

    Di t h t t d

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    Direct shear tests on sands

    ,

    =arstres

    Normal stress = 2Normal stress = 3

    f1

    Sh f2f3

    Shear displacement

    re,f

    atfailu

    Mohr Coulomb failure envelope

    rstres

    S

    he

    Normal stress,

    Di t h t t d

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    Direct shear tests on sands

    Sand is cohesionless

    hence c = 0drained and pore water

    pressures are,

    Therefore,

    = and c = c = 0

    Di t h t t l

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    Direct shear tests on clays

    In case of clay, horizontal displacement should be applied at a veryslow rate to allow dissipation of pore water pressure (therefore, one

    Failure envelopes for clay from drained direct shear tests

    ,f Overconsolidated clay (c 0)

    tfailu

    r

    Normally consolidated clay (c = 0)

    s

    tress

    Shear

    Normal force,

    I t f t t di t h t

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    Interface tests on direct shear apparatus

    n many oun a on es gn pro ems an re a n ng wa pro ems,

    is required to determine the angle of internal friction between soil

    and the structural material (concrete, steel or wood)

    PP

    Soil SSoil S

    Foundation materialFoundation material

    tan'c Where,ca = a es on,

    = angle of internal friction

    S

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    Triaxial Shear Test

    Piston (to apply deviatoric stress)

    Failure planeO-ring

    impervious

    membrane

    at failure PorousstonePerspex

    sample

    cell

    Water

    pedestal

    Cell pressure

    Back pressure Pore pressure or

    volume change

    T i i l Sh T t

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    Triaxial Shear Test

    Specimen preparation (undisturbed sample)

    Sampling tubes

    Sample extruder

    T i i l Sh T t

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    Triaxial Shear Test

    Specimen preparation (undisturbed sample)

    Edges of the sample

    are carefull trimmed

    Setting up the sample

    in the triaxial cell

    T i i l Sh T t

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    Triaxial Shear Test

    Specimen preparation (undisturbed sample)

    Sample is coveredCell is com letel

    membrane and sealed

    filled with water

    Tria ial Shear Test

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    Triaxial Shear Test

    Specimen preparation (undisturbed sample)

    Provin rin to

    measure the

    deviator load

    Dial gauge to

    measure vertical

    displacement

    Types of Triaxial Tests d i t i t

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    Types of Triaxial Tests deviatoric stress =cStep 1 Step 2

    cc c c

    +Under all-around cell pressure c

    cShearing (loading)

    Is the drainage valve open? Is the drainage valve open?

    yes no yes no

    samplenconsolidated

    sample

    ra ne

    loading

    n ra ne

    loading

    Types of Triaxial Tests

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    Types of Triaxial Tests

    Step 1 Step 2

    - u u c ear ng oa ng

    Is the drainage valve open?

    yes no

    Is the drainage valve open?

    Consolidatedsam le

    Unconsolidated Drained Undrainedoa ng

    CD test UU test

    Consolidated- drained test (CD Test)

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    ( )

    Step 1: At the end of consolidation

    , ,

    =

    hC 0 hC =Step 2: During axial stress increase

    hC

    VC +

    V = VC + =1hC 0 h = hC = 3Drainage

    VC + f Vf= VC + f=1f

    hC 0

    hf

    = hC

    =3fDrainage

    Consolidated- drained test (CD Test)

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    Consolidated- drained test (CD Test)

    =

    3 = hC

    Deviator stress (q or d) = 13

    Consolidated- drained test (CD Test)

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    Volume chan e of sam le durin consolidation

    f

    the

    p

    ansion

    hange E

    Time

    olum

    e

    ample

    sion

    Compre

    Consolidated- drained test (CD Test)

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    Stress-strain relationshi durin shearin

    ,d

    Dense sand

    r

    stres

    d)fLoose sand

    eviato or NC Clayd)f

    Axial strainon

    Dense sand

    or OC claange

    ple

    Expans

    lumec

    thesa

    ssion Axial strain

    oose san

    or NC clay

    V of

    Com

    pre

    CD tests How to determine strength parameters c and

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    ess,

    Confining stress = 3c1 3 d f

    iatorst

    Confining stress = 3ad)fbon n ng s ress = 3b

    3De

    Axial strain d fa

    ss,

    Mohr Coulomb

    arstr

    Sh

    or 3c 1c3a 1a(d)fa3b 1b

    (d)fb

    CD tests

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    reng parame ers c an o a ne rom es s

    Since u = 0 in CD

    =Therefore, c = c

    and = , cd and d are usedto denote them

    CD tests Failure envelopes

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    For sand and NC Clay, cd = 0

    ,

    d

    stres

    o r ou om

    failure envelope

    hea

    r

    or3a 1ad fa

    Therefore one CD test would be sufficient to determine of sand or NC clay

    CD tests Failure envelopes

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    For OC Clay, cd 0

    or3 1

    c

    Some practical applications of CD analysis for

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    p pp y

    1. Embankment constructed very slowly, in layers over a soft clay

    deposit

    Soft clay

    = in situ drainedshear strength

    Some practical applications of CD analysis for

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    p pp y

    2. Earth dam with steady state seepage

    Core

    = drained shear

    Some practical applications of CD analysis for

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    p pp y

    3. Excavation or natural slope in clay

    = In situ drained shear strengthNote: CD test simulates the long term condition in the field.

    Thus, cd and d should be used to evaluate the longterm behavior of soils

    Consolidated- Undrained test (CU Test)

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    Step 1: At the end of consolidation

    , ,

    =

    hC 0 hC =Step 2: During axial stress increase

    hC

    VC + No

    V VC 1

    hC udrainage h = hC u = 3

    VC + f Vf= VC + fuf=1fhCodrainage uf hf= hC uf=3f

    Volume chan e of sam le durin consolidation

    Consolidated- Undrained test (CU Test)

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    Volume chan e of sam le durin consolidation

    fthe

    p

    ansion

    hange E

    Time

    olum

    e

    amp

    le

    sion

    Compre

    Stress strain relationshi durin shearin

    Consolidated- Undrained test (CU Test)

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    Stress-strain relationshi durin shearin

    ,d

    Dense sand

    r

    stres

    d)fLoose sand

    eviato or NC Clayd)f

    Axial strain

    Loose sand

    /NC Clay

    +

    u-

    Axial strain

    or OC clay

    CU tests How to determine strength parameters c and

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    = ess,

    Confining stress = 3b

    iatorst

    3

    3a

    De

    Axial strain Total stresses at failure

    d fa

    tres

    s, cuMohr Coulomb

    failure envelope in

    terms of total stresses

    h

    ear

    S

    or ccu 3b 1b3a 1a

    (d)fa

    CU tests How to determine strength parameters c and 1 = 3 + (d)f - uf

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    1 3 ( d)f uf

    Mohr Coulomb failure

    envelo e in terms of

    =3 - ufuf

    s,

    Mohr Coulombeffective stresses

    Effective stresses at failure

    rstre cua ure enve ope nterms of total stresses

    She

    or ccu 3b 1bC ufa

    ufb

    (d)fa3b 1b3a 1a

    (d)fa 3a 1a

    CU tests

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    reng parame ers c an o a ne rom es s

    Shear strength

    parameters in terms

    parameters in terms

    of effective stressesof total stresses are

    ccu andcuare c and

    c = c and =

    CU tests Failure envelopes

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    or san an ay, ccu an c =

    Mohr Coulomb failure

    Mohr Coulomb enve ope n erms o

    effective stresses

    ress, cufailure envelope in

    terms of total stresses

    ear

    st

    S or3a

    (d)fa,

    cu and = d) of sand or NC clay

    Some practical applications of CU analysis for

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    1. Embankment constructed rapidly over a soft clay deposit

    Soft clay

    = in situ undrainedshear strength

    Some practical applications of CU analysis for

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    2. Rapid drawdown behind an earth dam

    Core

    = Undrained shear

    Some practical applications of CU analysis for

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    3. Rapid construction of an embankment on a natural slope

    Note: Total stress arameters from CU test c and can be used for

    = In situ undrained shear strengthstability problems where,

    Soil have become fully consolidated and are at equilibrium with

    the existing stress state; Then for some reason additional

    stresses are applied quickly with no drainage occurring

    Unconsolidated- Undrained test (UU Test)

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    Initial specimen conditionSpecimen conditionduring shearing

    C = 3 =

    No 3 + dNo 3

    Initial volume of the sample = A0 H0

    Volume of the sample during shearing = A H

    Since the test is conducted under undrained condition,

    =

    A (H0H) = A0 H0A

    A 0

    A (1 H/H0

    ) = A0

    z

    Unconsolidated- Undrained test (UU Test)

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    0

    Step 2: After application of hydrostatic cell pressureC = 3 =

    3 = 3 -uc

    No

    c 3 3 c

    c 3Increase of cell pressure

    increase of cell pressureSkemptons pore water

    pressure parameter, B

    Note: If soil is fully saturated, then B = 1 (hence, uc

    = 3

    )

    Unconsolidated- Undrained test (UU Test)

    St 3 D i li ti f i l l d

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    Step 3: During application of axial load

    + 1 = 3 + d -uc ud3

    drainage 3 = 3 -uc ud= +uc ud

    ud = ABdIncrease of pwp due to

    increase of deviator stressIncrease of deviator

    stress

    Skemptons pore water

    pressure parameter, A

    Unconsolidated- Undrained test (UU Test)

    C bi i t 2 d 3

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    Combining steps 2 and 3,

    uc = B 3 ud = ABdTotal pore water pressure increment at any stage, u

    u = uc + udu = B [3 + Ad]

    Skemptons pore

    water pressureu = B [3 + A(13]equa on

    Unconsolidated- Undrained test (UU Test)

    , ,

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    Step 1: Immediately after sampling

    0V0 = ur

    0 -ur h0 = ur C

    C -ur uc = -ur cNo

    drainage

    VC C r -C rh = ur

    (Sr= 100% ; B = 1)

    Step 3: During application of axial load

    V = C + + ur -c uC C

    No

    drainage-ur c u h = C + ur -c u

    Step 3: At failure Vf= C + f+ ur -c uf= 1fC + fhf= C + ur -c uf

    = 3f-u

    r

    cu

    f

    C

    drainage

    Unconsolidated- Undrained test (UU Test)

    , ,

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    Step 3: At failure Vf= C + f+ ur -c uf= 1f + hf= C + ur -c uf

    = 3f -ur c ufC

    drainage

    Mohr circle in terms of effective stresses do not depend on the cell

    pressure.

    Therefore, we get only one Mohr circle in terms of effective stress for

    different cell pressures

    3 1f

    Unconsolidated- Undrained test (UU Test)

    , ,

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    Step 3: At failure Vf= C + f+ ur -c uf= 1f + hf= C + ur -c uf

    = 3f -ur c ufC

    drainage

    Mohr circles in terms of total stresses

    Failure envelope, u = 0

    uaub

    cu

    3b 1b3a 1af

    3 1 or

    Unconsolidated- Undrained test (UU Test)

    Effect of degree of saturation on failure envelope

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    Effect of degree of saturation on failure envelope

    S < 100% S > 100%

    3b b3a a3c c

    Some practical applications of UU analysis for

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    1. Embankment constructed rapidly over a soft clay deposit

    Soft clay

    = in situ undrainedshear strength

    Some practical applications of UU analysis for

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    2. Large earth dam constructed rapidly with

    no change in water content of soft clay

    Core

    = Undrained shear

    Some practical applications of UU analysis for

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    3. Footing placed rapidly on clay deposit

    = In situ undrained shear strength

    Note: UU test simulates the short term condition in the field.

    , ubehavior of soils

    Unconfined Compression Test (UC Test)

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    1 = VC +

    = 0

    Unconfined Compression Test (UC Test)

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    1 = VC + fs,

    arstre

    3 = 0Sh

    qu

    Normal stress,

    f= 1/2 = qu/2 = cu

    Various correlations for shear strength

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    For NC clays, the undrained shear strength (cu) increases with theeffective overburden pressure,0

    )(0037.011.0'

    PIcu

    Skempton (1957)

    Plasticity Index as a %

    For OC clays, the following relationship is approximately true

    8.0

    '

    0

    '

    0

    )(OCR

    edConsolidatNormally

    u

    idatedOverconsol

    u

    Ladd (1977)

    For NC clays, the effective friction angle () is related to PI as follows

    )log(234.0814.0' IPSin Kenny (1959)

    Shear strength of partially saturated soils

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    In the previous sections, we were discussing the shear strength of saturated soils. However, in most of the cases, we will encounter

    WaterPore water

    pressure, u

    Air pressure, ua

    Effective

    ore wa er

    pressure, uw

    stress, Effectivestress,

    Saturated soils Unsaturated soils

    Pore water pressure can be negative in unsaturated soils

    Shear strength of partially saturated soils

    Bishop (1959) proposed shear strength equation for unsaturated soils as

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    Bishop (1959) proposed shear strength equation for unsaturated soils as

    follows

    'tan)()(' waanf uuuc Where,

    n ua = Net normal stress

    u u = Matric suction

    = a parameter depending on the degree of saturation

    ( = 1 for fully saturated soils and 0 for dry soils)

    Fredlund et al (1978) modified the above relationship as follows

    b

    waanf uuuc tan)('tan)(' ,

    tanb = Rate of increase of shear strength with matric suction

    Shear strength of partially saturated soils

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    bwaanf uuuc tan)('tan)('

    Same as saturated soils Apparent cohesion

    Therefore, strength of unsaturated soils is much higher than the strength

    - ua

    How it become possible

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    b'' waanf

    Same as saturated soils Apparent cohesion

    due to matric suction

    Apparent - uacohesion

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