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Series and Parallel Wiring GET A CALCULATOR!!!!!

Series and Parallel Wiring GET A CALCULATOR!!!!!

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Page 1: Series and Parallel Wiring GET A CALCULATOR!!!!!

Series and Parallel WiringGET A CALCULATOR!!!!!

Page 2: Series and Parallel Wiring GET A CALCULATOR!!!!!

SERIES CIRCUITSThe same current through each

resistor.

EQUIVALENT RESISTANCE: What is the net resistance? What one resistor could replace a group of resistors?

For resistors wired in series, the equivalent resistance is given by:

Req = R1 + R2 + R3 + …

Page 3: Series and Parallel Wiring GET A CALCULATOR!!!!!

PARALLEL CIRCUIT

Same voltage across each resistor.

For resistors wired in parallel, the equivalent resistance is given by:

...R

1

R

1

R

1

R

1

321eq

Page 4: Series and Parallel Wiring GET A CALCULATOR!!!!!

Example: What is the equivalent resistance of a 10 W, 20 W, and 30 W resistor wired in series? In parallel?

Series: Req = 10 W + 20 W + 30 W = 60 WParallel 1 / Req = 1/10 W + 1/20 W + 1/30 W

Req = 5.45 WThere’s much less resistance if resistors are

wired in parallel than if they’re wired in series.

With less resistance, the charge pump will able to push much more current around the circuit.

Page 5: Series and Parallel Wiring GET A CALCULATOR!!!!!

Circuits and Ohm’s Law: V = IRSeries: Req = 10 W + 20 W + 30 W = 60 WParallel 1 / Req = 1/10 W + 1/20 W + 1/30 W

Req = 5.45 WIf the circuits were supplied 12 V by a battery, what is the current in the series circuit?

I = V/R

I = 12 V / 60 = W 0.2 A

In the parallel circuit?

I = V / R = 12 V / 5.45 = W 2.2 A

Page 6: Series and Parallel Wiring GET A CALCULATOR!!!!!

In a circuit with 3 light bulbs wired in series, if the current in the first bulb is 0.12 A, what is the current in the 2nd bulb? In the 3rd bulb?

The current is the same for all resistors wired in series to each other!

If the circuit is supplied 9 V from a battery and the voltage across the 1st bulb is 1 V and across the 2nd bulb is 6 V, what is the voltage across the 3rd bulb?

In a series circuit, the sum of voltages across each resistor is equal to the voltage across the whole circuit!

Page 7: Series and Parallel Wiring GET A CALCULATOR!!!!!

Ohm’s Law V = IRA 6 W and a 4 W resistor are wired in parallel across a 9 V battery. Determine the current in the circuit.

- First find the equivalent resistance, then the current.

R = 2.4 WI = V / R

I = 3.75 A

How much current goes through the 6 W resistor?

- Resistors in parallel have the same voltage (pressure) across them, even if they have different resistance.

I = V / R

I = 9 V / 6 W = 1.5 A

How much current goes through the 4 W resistor?

I = 9 V / 4 W = 2.25 A

Page 8: Series and Parallel Wiring GET A CALCULATOR!!!!!

Characteristics of Series and Parallel Wiring

Series: If one component goes out,They all go out!

As more resistors are added, the equivalent resistanceIncreases!

which means that the current in that part of the circuitDecreases!

Parallel: If one component goes out,The rest still work!

As more resistors are added, the equivalent resistanceDecreases!

which means that the current in that part of the circuitIncreases!

Page 9: Series and Parallel Wiring GET A CALCULATOR!!!!!
Page 10: Series and Parallel Wiring GET A CALCULATOR!!!!!

For maximum resistance- use series wiring.

For minimum resistance- use parallel wiring.

The flow of water is a very good analogy to the flow of charges in both series and parallel circuits.

Page 11: Series and Parallel Wiring GET A CALCULATOR!!!!!

Schematic diagramssymbols to represent circuit components.

wires:

Charge pumps:

Resistors:

Switches:

Ground:

All devices connected to a circuit (light bulbs, TV’s, toasters, etc.) resist the flow of charges and are sometimes drawn as a resistor in the circuit (if you’re considering the unit as a whole).

Page 12: Series and Parallel Wiring GET A CALCULATOR!!!!!
Page 13: Series and Parallel Wiring GET A CALCULATOR!!!!!

For resistors wired “in series” the same current flows through each one, however the potential difference, voltage, is additive

Voltage gain through battery

=

Sum of Voltage drop through resistors

For resistors wired “in parallel”, the potential difference, voltage, is the same for each of them, however the current is additive.

Total Current pushed by battery

=

Sum of Current going through all the resistors

Page 14: Series and Parallel Wiring GET A CALCULATOR!!!!!