95
Exercise 4.7 Subject: Steam (B) distillation of stearic acid (A). Given: T = 200 o C. Vapor pressure of pure stearic acid at 200 o C = 0.40 kPa. Assumptions: Partial pressure of stearic acid in vapor = 70% of the pure vapor pressure. Find: Kilograms of acid distilled per kilogram of steam added as a function of total pressure from 3.3 kPa to 101.3 kPa. Analysis: p A = 0.7(0.4) = 0.28 kPa B A A B A A A A B B B B 0.28 (1) / (2) 284.5 , 18.02 Using Eqs. (1) and (2), kg A 0.28(284.5) = kg B (- = - = - = = = = = i i p P p P y p P M M yM pM yM pM P 4.42 = (3) 0.28)(18.02) 0.28 - P Solving Eq. (3) for values of P from 3.3 to 101.3 kPa gives the following results: P, kPa kg A/kg B 101.3 0.0438 75 0.0592 50 0.0890 25 0.1790 15 0.3006 10 0.4553 5 0.9376 3.3 1.4650 Exercise 4.7 (continued)

Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Embed Size (px)

DESCRIPTION

Seader - Operações Unitárias

Citation preview

Page 1: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 4

.7

S

ub

ject

:

Ste

am (

B)

dis

till

atio

n o

f st

eari

c ac

id (

A).

Giv

en:

T

= 2

00

oC

. V

apo

r p

ress

ure

of

pu

re s

tear

ic a

cid

at

20

0oC

= 0

.40

kP

a.

Ass

um

pti

on

s:

Par

tial

pre

ssu

re o

f st

eari

c ac

id i

n v

apo

r =

70

% o

f th

e p

ure

vap

or

pre

ssu

re.

Fin

d:

Kil

ogra

ms

of

acid

dis

till

ed

per

kil

og

ram

of

stea

m a

dd

ed a

s a

fun

ctio

n o

f to

tal

pre

ssu

re

fro

m 3

.3 k

Pa

to 1

01

.3 k

Pa.

An

aly

sis:

pA =

0.7

(0.4

) =

0.2

8 k

Pa

BA

AB

AA

AA

BB

BB

0.2

8

(1

)

/

(

2)

28

4.5

,

1

8.0

2

Usi

ng

Eq

s. (

1)

and

(2

),

kg

A0

.28(2

84

.5)

=k

g B

(-

=−

=−

=

==

==

ii

pP

pP

yp

P

MM

yM

pM

yM

pM

P

4.4

2=

(3

)0

.28

)(1

8.0

2)

0.2

8−

P

S

olv

ing E

q.

(3)

for

val

ues

of

P f

rom

3.3

to

10

1.3

kP

a giv

es t

he

foll

ow

ing r

esu

lts:

P,

kP

a

kg

A/k

g B

1

01

.3

0.0

43

8

75

0

.05

92

50

0

.08

90

25

0

.17

90

15

0

.30

06

10

0

.45

53

5

0

.93

76

3.3

1

.46

50

Ex

erci

se 4

.7 (c

on

tin

ued

)

Page 2: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 4

.8

S

ub

ject

:

Vap

or-

liq

uid

eq

uil

ibri

um

fo

r b

enze

ne

(A)

- to

luen

e (B

) sy

stem

at

1 a

tm

Giv

en:

A

ver

age

rela

tiv

e v

ola

tili

ty =

2.5

. V

apo

r p

ress

ure

dat

a.

Ass

um

pti

on

s:

Rao

ult

's a

nd

Dal

ton

's l

aws.

Fin

d:

x-

y d

iag

ram

fo

r α

A,B

= 2

.5.

x-y

dia

gra

m f

or

Rao

ult

's l

aw u

sin

g v

apo

r p

ress

ure

dat

a.

(a

) T

emp

erat

ure

fo

r 2

5 m

ol%

vap

ori

zati

on

of

a 7

0 m

ol%

A/3

0 m

ol%

B m

ixtu

re.

Co

mp

osi

tio

n o

f co

nd

ense

d v

apo

r an

d l

iqu

id r

esid

ue.

(b

) P

lot

of

Rao

ult

's l

aw K

-val

ues

as

a fu

nct

ion

of

tem

per

atu

re.

An

aly

sis:

F

or

a co

nst

ant

rela

tiv

e v

ola

tili

ty,

Eq

. (4

-8)

app

lies

. F

or

αA

,B =

2.5

,

yx

x

x

xA

A,B

A

AA

,B

A

A

=+

−=

+

α

α1

1

25

11

5�

�.

.

So

lvin

g t

his

eq

uat

ion

fo

r v

alu

es o

f x

A =

0 t

o 1

.0 g

ives

th

e fo

llo

win

g:

xA

yA

0.0

0

.00

00

0.1

0

.21

74

0.2

0

.38

46

0.3

0

.51

72

0.4

0

.62

50

0.5

0

.71

43

0.6

0

.78

95

0.7

0

.85

36

0.8

0

.90

91

0.9

0

.95

74

1.0

1

.00

00

Ex

erci

se 4

.8 (c

on

tin

ued

)

An

aly

sis:

(

con

tin

ued

)

T

o c

alcu

late

y-x

an

d T

-x-y

cu

rves

fro

m v

apo

r p

ress

ure

dat

a, u

sin

g R

aou

lt's

an

d D

alto

n's

law

s, E

q.

(2-4

4 )

ap

pli

es,

as w

ell

as t

he

sum

of

the

mo

le f

ract

ion

s in

th

e p

has

es i

n e

qu

ilib

riu

m.

Th

us,

Ky x

PT

PK

y x

PT

P

yy

xx

ss

AA A

A

BB B

B

AB

AB

,

(1

, 2

)

,

(3

, 4

)

==

==

+=

+=

��

��

11

Page 3: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 4

.8 (c

on

tin

ued

)

An

aly

sis:

(

con

tin

ued

)

Eq

uat

ion

s (1

) to

(4

) ca

n b

e re

du

ced

to

th

e fo

llo

win

g e

qu

atio

ns

for

the

mo

le

frac

tio

ns

of

ben

zen

e (A

) in

ter

ms

of

the

K-v

alu

es:

xK

KK

yK

xA

B

AB

AA

A

,

=− −

=1

(5,

6)

If t

he

giv

en v

apo

r p

ress

ure

dat

a in

Ex

erci

se 4

.6 f

or

ben

zen

e, a

nd

th

is e

xer

cise

fo

r to

luen

e ar

e

fitt

ed t

o A

nto

ine

equ

atio

ns,

we

ob

tain

:

PT

PT

s sA B

(

7)

(8

)

=−

+

� ���

=−

+

� ���

exp

.. .

exp

.. .

15

56

45

26

02

34

21

12

71

17

27

41

38

96

3

25

56

7

Wh

ere

vap

or

pre

ssu

re i

s in

to

rr a

nd

tem

per

atu

re i

s in

oC

. S

olv

ing,

Eq

s. (

1)

to (

8),

T,

oC

Ps o

f A

, to

rr

Ps o

f B

, to

rr

KA

KB

xA

yA

80

.1

75

9.9

2

90

.0

0.9

99

8

0.3

81

6

1.0

00

1

.000

8

2.5

8

17

.4

31

4.9

1

.075

5

0.4

14

4

0.8

86

0

.953

8

5.0

8

80

.8

34

2.7

1

.159

0

0.4

51

0

0.7

75

0

.899

8

7.5

9

48

.0

37

2.5

1

.247

4

0.4

90

1

0.6

73

0

.840

9

0.0

1

019

.1

40

4.4

1

.340

9

0.5

32

1

0.5

79

0

.776

9

2.5

1

094

.1

43

8.5

1

.439

6

0.5

76

9

0.4

90

0

.706

9

5.0

1

173

.4

47

4.9

1

.543

9

0.6

24

9

0.4

08

0

.630

9

7.5

1

256

.9

51

3.7

1

.653

9

0.6

76

0

0.3

31

0

.548

1

00

.0

13

45

.0

55

5.2

1

.769

7

0.7

30

5

0.2

59

0

.459

1

02

.5

14

37

.6

59

9.3

1

.891

6

0.7

88

5

0.1

92

0

.363

1

05

.0

15

35

.0

64

6.2

2

.019

8

0.8

50

3

0.1

28

0

.259

1

07

.5

16

37

.3

69

6.1

2

.154

4

0.9

15

9

0.0

68

0

.146

1

10

.0

17

44

.7

74

9.1

2

.295

7

0.9

85

6

0.0

11

0

.025

1

10

.5

17

66

.8

76

0.1

2

.324

8

1.0

00

1

0.0

00

0

.000

Plo

ts o

f y-

x an

d T

-x-y

bas

ed o

n t

he

abo

ve

tab

le f

rom

Rao

ult

's l

aw c

alcu

lati

on

s ar

e sh

ow

n o

n t

he

nex

t p

age.

W

hen

th

e y-x

plo

t is

co

mp

ared

to

th

e p

rev

iou

s y-

x p

lot

bas

ed o

n a

co

nst

ant

rela

tiv

e

vo

lati

lity

, it

is

seen

th

at,

for

a giv

en v

alu

e o

f x

for

ben

zen

e, t

he

val

ues

of

y fo

r b

enze

ne

are

in

fair

ly c

lose

ag

reem

ent.

F

rom

th

e ab

ov

e ta

ble

, th

e R

aou

lt's

law

αA

,B =

P

Ps

s

AB

/ r

ang

es f

rom

2.6

2

at 8

0.1

oC

to

2.3

2 a

t 1

10

.5oC

.

Ex

erci

se 4

.8 (c

on

tin

ued

)

An

aly

sis:

(

con

tin

ued

)

Page 4: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 4

.8 (c

on

tin

ued

)

An

aly

sis:

(

con

tin

ued

)

(a)

To

fin

d t

he

tem

per

atu

re a

t 2

5 m

ol%

vap

ori

zati

on

, st

arti

ng w

ith

a l

iqu

id

mix

ture

of

70

mo

l% b

enze

ne

and

30

mo

l% t

olu

ene,

ex

ten

d a

das

hed

, v

erti

cal

lin

e u

pw

ard

fro

m

po

int

M o

n t

he

T-y

-x d

iagra

m o

n t

he

pre

vio

us

pag

e u

nti

l p

oin

t B

is

reac

hed

. A

t th

is p

oin

t, u

sin

g

the

inv

erse

lev

er-a

rm r

ule

, th

e ra

tio

of

the

AB

lin

e le

ngth

to

th

e B

C l

ine

len

gth

is

25

/75

. T

he

tem

per

atu

re i

s 8

8oC

. T

he

ben

zen

e m

ole

fra

ctio

n o

f th

e eq

uil

ibri

um

vap

or

wh

en c

on

den

sed

is

the

sam

e as

th

e eq

uil

ibri

um

vap

or

at p

oin

t C

or

0.8

8.

Th

e b

enze

ne

mo

le f

ract

ion

in

th

e re

sid

ue

liq

uid

is t

he

sam

e as

th

e eq

uil

ibri

um

liq

uid

at

po

int

A o

r 0

.65

.

(b)

Th

e R

aou

lt's

law

K-v

alu

es a

re i

ncl

ud

ed i

n t

he

abo

ve

tab

le,

and

are

plo

tted

bel

ow

.

Ex

erci

se 4

.9

S

ub

ject

: V

apo

r-li

qu

id e

qu

ilib

riu

m f

or

n-h

epta

ne

(A)

- to

luen

e (B

) sy

stem

at

1 a

tm

Giv

en:

Vap

or

pre

ssu

re d

ata

for

n-h

epta

ne

and

to

luen

e, a

nd

ex

per

imen

tal

T-y

-x d

ata.

Ass

um

pti

on

s:

Rao

ult

's a

nd

Dal

ton

's l

aws

Fin

d:

(a)

x-y

plo

t b

ased

on

n-h

epta

ne,

th

e m

ost

vo

lati

le c

om

po

nen

t.

(b

) T

-x b

ub

ble

-po

int

plo

t.

(c

) α

A,B

an

d K

-val

ues

plo

tted

ag

ain

st t

emp

erat

ure

.

(d

) x-

y p

lot

bas

ed o

n t

he

aver

age

αA

,B.

(e

) C

om

par

iso

n o

f x-

y an

d T

-x-y

plo

ts w

ith

ex

per

imen

tal

dat

a.

An

aly

sis:

(

a) T

o c

alcu

late

y-x

an

d T

-x-y

cu

rves

fro

m v

apo

r p

ress

ure

dat

a, u

sin

g R

aou

lt's

an

d

Dal

ton

's l

aws.

E

q.

(2-4

4 )

ap

pli

es,

as w

ell

as t

he

sum

of

the

mo

le f

ract

ion

s in

th

e p

has

es i

n

equ

ilib

riu

m.

Th

us,

Ky x

PT

PK

y x

PT

P

yy

xx

ss

AA A

A

BB B

B

AB

AB

,

(1

, 2

)

,

(3

, 4

)

==

==

+=

+=

��

��

11

Eq

uat

ion

s (1

) to

(4

) ca

n b

e re

du

ced

to

th

e fo

llo

win

g e

qu

atio

ns

for

the

mo

le

frac

tio

ns

of

n-h

epta

ne

(A)

in t

erm

s o

f th

e K

-val

ues

:

xK

KK

yK

xA

B

AB

AA

A

,

=− −

=1

(5,

6)

If t

he

giv

en v

apo

r p

ress

ure

dat

a in

Ex

erci

se 4

.8 f

or

tolu

ene,

an

d t

his

ex

erci

se f

or

n-h

epta

ne

are

fitt

ed t

o A

nto

ine

equ

atio

ns,

we

ob

tain

:

PT

PT

s sA B

(

7)

(8

)

=−

+

� ���

=−

+

� ���

exp

..

.

exp

.. .

15

78

31

28

55

27

21

36

4

17

27

41

38

96

3

25

56

7

Wh

ere

vap

or

pre

ssu

re i

s in

to

rr a

nd

tem

per

atu

re i

s in

oC

. S

olv

ing,

Eq

s. (

1)

to (

8),

Page 5: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 4

.9 (c

on

tin

ued

) A

na

lysi

s:

(a)

(c

on

tin

ued

)

T,

oC

Ps o

f A

, to

rr

Ps o

f B

, to

rr

KA

KB

xA

yA

αA

,B

98

.4

76

0.0

5

28

.7

1.0

00

0

0.6

95

6

1.0

00

1

.000

1

.438

9

9.0

7

73

.0

53

8.3

1

.017

2

0.7

08

3

0.9

44

0

.961

1

.436

1

00

.0

79

5.9

5

55

.2

1.0

47

2

0.7

30

5

0.8

51

0

.891

1

.434

1

01

.0

81

9.2

5

72

.5

1.0

78

0

0.7

53

3

0.7

60

0

.819

1

.431

1

02

.0

84

3.1

5

90

.2

1.1

09

4

0.7

76

6

0.6

71

0

.745

1

.428

1

03

.0

86

7.6

6

08

.4

1.1

41

5

0.8

00

6

0.5

85

0

.668

1

.426

1

04

.0

89

2.6

6

27

.1

1.1

74

4

0.8

25

1

0.5

01

0

.588

.

1.4

23

1

05

.0

91

8.1

6

46

.2

1.2

08

0

0.8

50

3

0.4

18

0

.506

1

.421

1

06

.0

94

4.2

6

65

.8

1.2

42

4

0.8

76

1

0.3

38

0

.420

1

.418

1

07

.0

97

0.9

6

85

.9

1.2

77

5

0.9

02

5

0.2

60

0

.332

1

.415

1

08

.0

99

8.1

7

06

.5

1.3

13

3

0.9

29

6

0.1

84

0

.241

1

.413

1

09

.0

10

26

.0

72

7.5

1

.350

0

0.9

57

3

0.1

09

0

.147

1

.410

1

10

.0

10

54

.4

74

9.1

1

.387

4

0.9

85

6

0.0

36

0

.050

1

.408

1

10

.5

10

68

.9

76

0.1

1

.406

4

1.0

00

1

0.0

00

0

.000

1

.406

Fro

m t

his

tab

le,

an x

-y p

lot

is g

iven

bel

ow

.

(b)

Fro

m t

he

abo

ve

tab

le,

a T

-x-y

plo

t is

giv

en b

elo

w.

Th

e x-

curv

e is

th

e b

ub

ble

-po

int

curv

e,

wh

ile

the

y-cu

rve

is t

he

dew

-po

int

curv

e.

(c)

A g

rap

h o

f re

lati

ve

vo

lati

lity

an

d K

-val

ues

as

a fu

nct

ion

of

tem

per

atu

re i

s giv

en o

n t

he

nex

t

pag

e.

(d)

Fro

m t

he

abo

ve

tab

le,

the

arit

hm

etic

av

erag

e re

lati

ve

vo

lati

lity

, u

sin

g t

he

extr

eme

val

ues

is

: (α

A,B

) avg =

(1

.43

8 +

1.4

06

)/2

= 1

.42

2

Ex

erci

se 4

.9 (c

on

tin

ued

) A

na

lysi

s:

(a)

(c

on

tin

ued

)

Page 6: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 4

.9 (c

on

tin

ued

)

A

na

lysi

s:

(c)

an

d (

d)

(co

nti

nu

ed)

Rel

ati

ve

Vo

lati

lity

an

d K

-Va

lues

Fo

r a

con

stan

t re

lati

ve

vo

lati

lity

, E

q.

(4-8

) ap

pli

es.

Fo

r α

A,B

= 1

.42

2,

yx

x

x

xA

A,B

A

AA

,B

A

A

=+

−=

+

α

α1

1

14

22

10

42

2�

�.

.

So

lvin

g t

his

eq

uat

ion

fo

r v

alu

es o

f x

A =

0 t

o 1

.0 g

ives

th

e fo

llo

win

g:

x A

y A

0

0.0

00

0

0.1

0

.136

4

0.2

0

.262

3

0.3

0

.378

7

0.4

0

.486

7

0.5

0

.587

1

0.6

0

.680

8

0.7

0

.768

4

0.8

0

.850

5

0.9

0

.927

5

1

1.0

00

0

Ex

erci

se 4

.9 (c

on

tin

ued

)

A

na

lysi

s:

(c)

an

d (

d)

(co

nti

nu

ed)

y-x

Plo

t fo

r a

n a

ver

ag

e re

lati

ve

vo

lati

lity

0

0.1

0.2

0.3

0.4

0.5

0.6

0.7

0.8

0.91

00

.10.2

0.3

0.4

0.5

0.6

0.7

0.8

0.9

1

Mo

le f

rac

tio

n n

-hep

tan

e i

n l

iqu

id

Mole fraction n-heptane in vapor

(

e)

Rao

ult

’s l

aw c

alcu

lati

on

s co

mp

ared

to

ex

per

imen

tal

are

as f

oll

ow

s:

R

ao

ult

’s l

aw

Ex

pe

rim

en

tal

T

, oC

x

A

y A

xA

y A

11

0.7

5

-0.0

18

-0

.02

6

0.0

25

0

.048

1

06

.80

0

.276

0

.350

0

.129

0

.205

1

04

.50

0

.459

0

.547

0

.250

0

.349

1

02

.95

0

.589

0

.672

0

.354

0

.454

1

01

.35

0

.729

0

.793

0

.497

0

.577

9

9.7

3

0.8

76

0

.910

0

.692

0

.742

9

8.9

0

0.9

54

0

.967

0

.843

0

.864

9

8.5

0

0.9

92

0

.995

0

.940

0

.948

9

8.3

5

1.0

07

1

.005

0

.994

0

.993

Th

e R

aou

lt’s

law

val

ues

are

in

ver

y p

oo

r ag

reem

ent

wit

h t

he

exp

erim

enta

l v

alu

es.

Page 7: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 4

.9 (c

on

tin

ued

) A

na

lysi

s:

(e)

(c

on

tin

ued

)

Ex

erci

se 4

.9 (c

on

tin

ued

) A

na

lysi

s:

(e)

(c

on

tin

ued

)

Co

mp

ari

son

wit

h E

xp

erim

enta

l D

ata

Page 8: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 4

.10

S

ub

ject

:

Co

nti

nu

ou

s, s

ingle

sta

ge

dis

till

atio

n o

f A

an

d B

to

pro

du

ce a

dis

till

ate

and

bo

tto

ms.

Giv

en:

S

atu

rate

d l

iqu

id f

eed

of

50

mo

l% A

an

d 5

0 m

ol%

B f

ed t

o a

sti

ll a

t 4

0 m

ol/

h.

R

elat

ive

vo

lati

lity

= α

A,B

= 2

. B

ott

om

s ra

te =

30

mo

l/h

(a)

To

tal

con

den

ser

wit

h a

ref

lux

rat

io =

1.

(b

) N

o r

eflu

x.

Ass

um

pti

on

s:

Sti

ll i

s an

eq

uil

ibri

um

sta

ge.

Fin

d:

(a)

C

om

po

siti

on

of

the

two

pro

du

cts.

(b

) C

om

po

siti

on

of

the

two

pro

du

cts.

An

aly

sis:

F

rom

th

e d

efin

itio

n o

f th

e re

lati

ve

vo

lati

lity

,

αA

,BA

B

AB

AA

AA

==

− −=

yx

xy

yx

xy

1 12

��

��

(1

)

(a)

Dis

till

ate

= D

= F

- W

= 4

0 -

30

= 1

0 m

ol/

h

Mat

eria

l b

alan

ce f

or

A:

0

.5(4

0)

= 2

0 =

yA(1

0)

+ x

A(3

0)

(2)

S

olv

ing E

qs.

(1

) an

d (

2)

sim

ult

aneo

usl

y b

y e

lim

inat

ing

yA ,

we

ob

tain

:

33

20

2x

xA

A+

−=

(3

)

So

lvin

g E

q.

(3),

a q

uad

rati

c eq

uat

ion

, g

et o

nly

on

e p

ost

ive

roo

t:

x

A =

0.4

57

5,

x B =

0.5

42

5

for

the

bo

tto

ms

Su

bst

itu

tio

n i

nto

Eq

. (2

), g

ives

,

y

A =

0.6

27

5,

y B =

0.3

72

5

for

the

dis

till

ate

(b)

No

te t

hat

th

e so

luti

on

to

Par

t (a

) w

as i

nd

epen

den

t o

f th

e re

flu

x r

atio

. A

cco

rdin

gly

, th

e

solu

tio

n t

o P

art

(b)

is t

he

as f

or

Par

t (a

)

Ex

erci

se 4

.11

S

ub

ject

:

Dis

till

atio

n o

f an

ace

ton

e (A

) -

wat

er (

B)

mix

ture

th

at i

s p

arti

ally

vap

ori

zed

.

Giv

en:

F

eed

is

57

mo

l% A

an

d 4

3 m

ol%

B a

s a

liq

uid

at

12

5oC

an

d 6

87

kP

a.

It i

s fl

ash

ed

acro

ss a

val

ve

to t

he

colu

mn

pre

ssu

re o

f 1

01

.3 k

Pa,

wit

h a

res

ult

ing t

emp

erat

ure

of

60

oC

.

Vap

or-

liq

uid

eq

uil

ibri

um

dat

a at

co

lum

n p

ress

ure

. E

nth

alp

y d

ata

at c

olu

mn

co

nd

itio

ns.

Co

mp

osi

tio

ns

of

the

dis

till

ate

and

bo

tto

ms.

Ass

um

pti

on

s:

Fee

d i

s at

eq

uil

ibri

um

do

wn

stre

am o

f th

e fe

ed v

alv

e.

Wil

l h

ave

to c

hec

k i

f fe

ed

val

ve

op

erat

es a

dia

bat

ical

ly.

Giv

en h

eat

cap

acit

ies

are

for

the

liq

uid

an

d a

re c

on

stan

t.

Hea

ts o

f

vap

ori

zati

on

are

co

nst

ant.

N

o e

ffec

t o

f p

ress

ure

on

en

thal

py.

Fin

d:

Mo

le r

atio

of

liq

uid

to

vap

or

in t

he

feed

do

wn

stre

am o

f th

e v

alv

e.

Co

nst

ruct

an

H-x

-y

dia

gra

m.

An

aly

sis:

F

rom

th

e eq

uil

ibri

um

dat

a, a

t 6

0oC

, x

A =

0.5

0 a

nd

yA =

0.8

5 .

T

ake

a b

asis

of

F =

fee

d r

ate

= 1

km

ol/

s.

T

ota

l m

ater

ial

bal

ance

aro

un

d f

eed

val

ve:

F

= 1

= V

+ L

(1

)

Ace

ton

e m

ater

ial

bal

ance

aro

un

d f

eed

val

ve:

0.5

7(1

) =

0.8

5V

+ 0

.50

L

(2)

S

olv

ing E

qs.

(1

) an

d (

2)

sim

ult

aneo

usl

y,

V =

0.2

km

ol/

s an

d L

= 0

.8 k

mo

l/s

Th

eref

ore

, af

ter

the

val

ve,

mo

les

L/m

ole

s V

= 0

.8/0

.2 =

4

No

w c

hec

k w

het

her

val

ve

is o

per

atin

g a

dia

bat

ical

ly.

E

nth

alp

y o

f li

qu

id e

nte

rin

g v

alv

e =

0 (

as g

iven

)

E

nth

alp

y o

f fe

ed a

fter

th

e v

alv

e, u

sin

g g

iven

en

thal

pie

s =

27

,20

0(0

.2)

+ (

-5,2

70

)(0

.8)

= 1

22

4 k

J/s

T

her

efo

re,

the

enth

alp

y i

ncr

ease

s ac

ross

th

e v

alv

e b

y 1

22

4 k

J/s

To

co

nst

ruct

an

en

thal

py d

iagra

m f

or

1 a

tm p

ress

ure

, ta

ke

as a

n e

nth

alp

y d

atu

m,

A a

nd

B a

s

liq

uid

s at

25

oC

. T

his

is

a d

iffe

ren

t d

atu

m t

han

th

at u

sed

to

get

th

e giv

en e

nth

alp

y o

f th

e h

ot

feed

.

Pu

re A

: b

oil

s at

56

.7oC

.

Sin

ce C

P o

f li

qu

id =

13

4 k

J/k

mol-

K,

hL a

t 5

6.7

oC

= 1

34

(56

.7-2

5)=

42

48

kJ/

km

ol-

K

hV a

t 5

6.7

oC

=4

24

8 +

lat

ent

hea

t =

42

48

+ 2

97

50

= 3

39

98

kJ/

km

ol-

K

Pu

re B

: b

oil

s at

10

0oC

.

Sin

ce C

P o

f li

qu

id =

75

.3 k

J/k

mol-

K,

hL a

t 1

00

oC

= 7

5.3

(10

0-2

5)=

56

48

kJ/

km

ol-

K

hV a

t 1

00

oC

=5

64

8 +

lat

ent

hea

t =

56

48

+ 4

24

30

= 4

80

78

kJ/

km

ol-

K

Eq

uil

ibri

um

liq

uid

mix

ture

of

50

mo

l% A

an

d 5

0 m

ol%

B h

as a

bu

bb

le p

oin

t at

60

oC

. T

her

efo

re,

h

L =

0.5

(13

4)(

60

-25

) +

0.5

(75

.3)(

60

-25

) =

36

63

kJ/

km

ol-

K

Eq

uil

ibri

um

vap

or

mix

ture

of

85

mo

l% A

an

d 1

5 m

ol%

B h

as d

ew p

oin

t o

f 6

0oC

. T

her

efo

re,

h

V =

0.8

5[(

13

4)(

60

-25

) +

29

75

0]

+ 0

.15

[(7

5.3

)(6

0-2

5)

+ 4

24

30

] =

36

03

4 k

J/km

ol-

K

Cal

cula

tio

ns

for

oth

er e

qu

ilib

riu

m m

ixtu

res

are

do

ne

in a

sim

ilar

man

ner

an

d a

re s

um

mar

ized

in

the

foll

ow

ing t

able

:

Page 9: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 4

.11

(c

on

tin

ued

) A

na

lysi

s:

(co

nti

nu

ed)

T,

oC

x

A

x B

hL,

kJ/

km

ol

yA

y B

hV,

kJ/

km

ol

56

.7

1.0

00

0

.000

4

248

1

.000

0

.000

3

399

8

57

.1

0.9

20

0

.080

4

151

0

.944

0

.056

3

465

6

60

.0

0.5

00

0

.500

3

663

0

.850

0

.150

3

603

4

61

.0

0.3

30

0

.670

3

408

0

.837

0

.163

3

629

6

63

.0

0.1

76

0

.824

3

254

0

.805

0

.195

3

688

0

71

.7

0.0

68

0

.932

3

703

0

.692

0

.308

3

906

9

10

0.0

0

.000

1

.000

5

648

0

.000

1

.000

4

807

8

Fro

m t

his

tab

le,

the

h-x

-y p

lot

foll

ow

s, w

ith

tie

lin

es t

o c

on

nec

t th

e v

apo

r-li

qu

id e

qu

ilib

riu

m

alo

ng t

he

dew

-po

int

and

bu

bb

le-p

oin

t li

nes

.

En

thalp

y-C

om

po

siti

on

Plo

t

Ex

erci

se 4

.12

S

ub

ject

:

Vap

ori

zer

and

co

nd

ense

r h

eat

du

ties

fo

r b

enze

ne

(A)

-to

luen

e (B

) m

ixtu

res,

usi

ng a

n

enth

alp

y-c

on

cen

trat

ion

dia

gra

m.

Giv

en:

P

= 1

atm

. V

apo

r p

ress

ure

dat

a.

Sat

ura

ted

liq

uid

an

d v

apo

r en

thal

py d

ata.

Ass

um

pti

on

s:

Rao

ult

's l

aw.

Fin

d:

(a)

C

on

stru

ct a

n h

-x-y

plo

t.

(b

) H

eat

du

ty f

or

50

mo

l% v

apo

riza

tio

n o

f a

30

mo

l% A

mix

ture

, st

arti

ng f

rom

liq

uid

satu

rati

on

tem

per

atu

re.

Hea

t d

uty

to

co

nd

ense

th

e v

apo

r an

d s

ub

coo

l it

10

oC

.

An

aly

sis:

(

a)

Fir

st,

com

pu

te t

he

vap

or

and

liq

uid

eq

uil

ibri

um

co

mp

osi

tio

ns

at 1

atm

an

d

tem

per

atu

res

fro

m 6

0 t

o 1

00

oC

usi

ng R

aou

lt's

law

wit

h t

he

vap

or

pre

ssu

re d

ata.

E

q.

(2-4

4 )

ap

pli

es,

as w

ell

as t

he

sum

of

the

mo

le f

ract

ion

s in

th

e p

has

es i

n e

qu

ilib

riu

m.

Th

us,

Ky x

PT

PK

y x

PT

P

yy

xx

ss

AA A

A

BB B

B

AB

AB

,

(1

, 2

)

,

(3

, 4

)

==

==

+=

+=

��

��

11

Eq

uat

ion

s (1

) to

(4

) ca

n b

e re

du

ced

to

th

e fo

llo

win

g e

qu

atio

ns,

xK

KK

yK

xA

B

AB

AA

A

,

=− −

=1

(5,

6)

Vap

or

pre

ssu

re d

ata

in E

xer

cise

s 4

.6 f

or

ben

zen

e, a

nd

4.8

fo

r to

luen

e giv

e A

nto

ine

equ

atio

ns,

PT

PT

ss

AB

,

(

7,

8)

=−

+

� ���

=−

+

� ���

exp

.. .

exp

.. .

15

56

45

26

02

34

21

12

71

17

27

41

38

96

3

25

56

7

Wh

ere

vap

or

pre

ssu

re i

s in

to

rr a

nd

tem

per

atu

re i

s in

oC

. S

olv

ing,

Eq

s. (

1)

to (

8),

T,

oC

Ps o

f A

, to

rr P

s of

B,

torr

K

A

KB

xA

y A

80

.1

75

9.9

2

90

.0

0.9

99

8

0.3

81

6

1.0

00

1

.000

8

5.0

8

80

.8

34

2.7

1

.159

0

0.4

51

0

0.7

75

0

.899

9

0.0

1

019

.1

40

4.4

1

.340

9

0.5

32

1

0.5

79

0

.776

9

5.0

1

173

.4

47

4.9

1

.543

9

0.6

24

9

0.4

08

0

.630

1

00

.0

13

45

.0

55

5.2

1

.769

7

0.7

30

5

0.2

59

0

.459

1

05

.0

15

35

.0

64

6.2

2

.019

8

0.8

50

3

0.1

28

0

.259

1

10

.5

17

66

.8

76

0.1

2

.324

8

1.0

00

1

0.0

00

0

.000

Th

is c

ov

ers

the

tem

per

atu

re r

ang

e o

f co

-ex

iste

nce

of

vap

or

and

liq

uid

.

Page 10: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 4

.12

(c

on

tin

ued

) A

na

lysi

s:

(a)

(c

on

tin

ued

)

Mo

lecu

lar

wei

gh

ts a

re M

A =

78

an

d

MB =

92

F

or

a giv

en t

emp

erat

ure

, co

mp

ute

sat

ura

ted

liq

uid

-ph

ase

mix

ture

en

thal

pie

s in

kJ/

kg o

f

mix

ture

fro

m,

hx

Mh

xM

h

xM

xM

L

LL

=+

+−

AA

AB

AA

AB

AB

()

()

1 1

(9)

Sim

ilar

ly f

or

the

vap

or,

h

yM

hy

Mh

yM

yM

V

VV

=+

+−

AA

AB

AA

AB

AB

()

()

1 1

(10

)

Wil

l h

ave

to i

nte

rpo

late

an

d e

xtr

apo

late

giv

en s

atu

rate

d e

nth

alp

y d

ata.

L

iqu

id e

nth

alp

y d

ata

are

lin

ear

wit

h t

emp

erat

ure

, th

eref

ore

, it

is

fou

nd

th

at:

hT

hT

LL

AB

,

=−

=−

18

53

21

85

34

..

(

11

, 1

2)

Vap

or

enth

alp

y d

ata

are

no

t q

uit

e li

nea

r, b

ut

fit

the

foll

ow

ing q

uad

rati

c eq

uat

ion

s:

hT

Th

TT

VV

AB

,

=+

+=

++

42

70

85

00

02

54

11

08

50

00

25

22

..

..

(1

3,

14

)

T,

oC

x

A

yA

(hL) A

,

kJ/

kg

(hL) B

,

kJ/

kg

(hV) A

,

kJ/

kg

(hV) B

,

kJ/

kg

hL

,

kJ/

kg

hV

,

kJ/

kg

80

.1

1.0

00

1

.000

1

16

.2

11

4.2

5

11

.1

49

5.1

1

16

.2

51

1.1

8

5.0

0

.775

0

.899

1

25

.3

12

3.3

5

17

.3

50

1.3

1

24

.7

51

5.4

9

0.0

0

.579

0

.776

1

34

.5

13

2.5

5

23

.8

50

7.8

1

33

.6

51

9.7

9

5.0

0

.408

0

.630

1

43

.8

14

1.8

5

30

.3

51

4.3

1

42

.5

52

3.8

1

00

.0

0.2

59

0

.459

1

53

.0

15

1.0

5

37

.0

52

1.0

1

51

.5

52

7.7

1

05

.0

0.1

28

0

.259

1

62

.3

16

0.3

5

43

.8

52

7.8

1

60

.5

53

1.5

1

10

.5

0.0

00

0

.000

1

72

.4

17

0.4

5

51

.5

53

5.5

1

70

.4

53

5.5

Plo

ts o

f h

in

kJ/

kg m

ixtu

re a

s a

fun

ctio

n o

f sa

tura

ted

vap

or

and

liq

uid

mo

le f

ract

ion

s, a

nd

y-x

are

giv

en o

n t

he

nex

t p

age.

(b

) T

ake

a b

asis

of

1 k

mo

l o

f 3

0 m

ol%

A -

70

mo

l% B

fee

d m

ixtu

re.

Th

en,

kg A

= (

0.3

0)(

78

) =

23

.4 k

g

and

kg B

= (

0.7

0)(

92

) =

64

.4 k

g

or

87

.8 k

g t

ota

l fe

ed.

U

se y

-x d

iagra

m t

o o

bta

in c

om

po

siti

on

s o

f v

apo

r an

d l

iqu

id f

or

50

mo

l% v

apo

rize

d.

Fro

m t

he

equ

atio

n

abo

ve

Eq

. (4

-6),

th

e sl

op

e o

f th

e q

-lin

e is

[(V

/F)-

1]/

(V/F

) =

(0

.5-1

.0)/

0.5

= -

1.

Th

e co

nst

ruct

ion

is

sho

wn

on

th

e y-

x d

iag

ram

, w

her

e th

e in

ters

ecti

on

wit

h t

he

equ

ilib

riu

m c

urv

e

giv

es x

A =

0.2

2 a

nd

yA =

0.3

8.

Th

e m

ass

of

liq

uid

= (

0.2

2)(

0.5

)(7

8)

+ (

0.7

8)(

0.5

)(9

2)

= 4

4.5

kg.

Th

e m

ass

of

vap

or

= 8

7.8

- 4

4.5

= 4

3.3

kg.

On

th

e h

-x-y

dia

gra

m,

Po

int

A i

s th

e sa

tura

ted

liq

uid

feed

wit

h h

L =

15

0 k

J/k

g o

f fe

ed.

Po

int

C i

s th

e li

qu

id r

emai

nin

g a

fter

50

mo

l% v

apo

riza

tio

n,

wit

hh

L,

= 1

58

kJ/

kg.

Sin

ce 4

4.5

/87

.8 o

r 0

.50

7 o

f th

e fe

ed i

s le

ft a

s li

qu

id,

this

is

equ

ival

ent

to

(0.5

07

)(1

58

) =

80

kJ/

kg f

eed

. P

oin

t D

is

the

vap

or,

wit

h h

V =

54

0 k

J/k

g v

apo

rize

d.

Sin

ce 0

.49

3

Ex

erci

se 4

.12

(c

on

tin

ued

)

An

aly

sis:

(

b)

(co

nti

nu

ed)

of

the

feed

is

vap

ori

zed

, th

is i

s eq

uiv

alen

t to

(0

.49

3)(

54

0)

= 2

66

kJ/

kg f

eed

. T

her

efo

re,

the

ener

gy r

equ

ired

fo

r p

arti

al v

apo

riza

tio

n =

26

6 +

80

-

15

0 =

19

6 k

J/k

g o

f fe

ed.

P

oin

t B

is

the

com

bin

ed v

apo

r an

d l

iqu

id p

has

es a

fter

par

tial

vap

ori

zati

on

.

Po

int

E i

s

con

den

sed

vap

or

as s

atu

rate

d l

iqu

id,

wit

h a

n e

nth

alp

y o

f 1

45

kJ/

kg.

Th

is i

s eq

uiv

alen

t to

(0.4

93

)(1

45

) =

71

kJ/

kg o

f fe

ed.

Th

eref

ore

, th

e co

nd

ense

r d

uty

= 2

66

- 7

1 =

19

5 k

J/k

g f

eed

.

P

oin

t F

is

10

oC

su

bco

ole

d c

on

den

sate

, w

her

e th

e en

thal

py c

han

ge

fro

m s

atu

rati

on

, b

ased

on

a l

iqu

id s

pec

ific

hea

t o

f 1

.85

kJ/

kg-o

C,

is 1

.85

(10

)(0

.49

3)

= 9

kJ/

kg f

eed

. T

her

efo

re,

the

con

den

ser

du

ty i

s n

ow

19

5 +

9 =

20

4 k

J/k

g f

eed

.

Page 11: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 4

.12

(c

on

tin

ued

)

An

aly

sis:

(a

)

En

tha

lpy

– C

om

po

siti

on

Dia

gra

m

Ex

erci

se 4

.13

S

ub

ject

:

Aze

otr

op

e fo

r th

e ch

loro

form

-met

han

ol

syst

em a

t 1

01

.3 k

Pa.

Giv

en:

V

apo

r-li

qu

id e

qu

ilib

riu

m d

ata

fro

m S

ecti

on

13

, p

. 1

1 o

f P

erry

's H

and

bo

ok

, 6

th e

dit

ion

.

Fin

d:

Fro

m d

ata,

co

nst

ruct

y-x

an

d T

-x-y

plo

ts.

Aze

otr

op

e co

nd

itio

ns

An

aly

sis:

S

ee p

lots

bel

ow

. F

rom

th

ese

plo

ts,

a m

inim

um

-bo

ilin

g a

zeo

tro

pe

occ

urs

at

53

.5oC

wit

h a

co

mp

osi

tio

n o

f 6

5 m

ol%

ch

loro

form

an

d 3

5 m

ol%

met

han

ol.

Page 12: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 4

.14

S

ub

ject

:

Aze

otr

op

e fo

r th

e w

ater

-fo

rmic

aci

d s

yst

em a

t 1

01

.3 k

Pa.

Giv

en:

V

apo

r-li

qu

id e

qu

ilib

riu

m d

ata

fro

m S

ecti

on

13

, p

. 1

4 o

f P

erry

's H

and

bo

ok

, 6

th e

dit

ion

.

Fin

d:

Fro

m d

ata,

co

nst

ruct

y-x

an

d T

-x-y

plo

ts.

Aze

otr

op

e co

nd

itio

ns

An

aly

sis:

S

ee p

lots

bel

ow

. F

rom

th

ese

plo

ts,

a m

axim

um

-bo

ilin

g a

zeo

tro

pe

occ

urs

at

10

7.6

oC

wit

h a

co

mp

osi

tio

n o

f 4

2 m

ol%

wat

er a

nd

58

mo

l% f

orm

ic a

cid

.

Ex

erci

se 4

.15

Su

bje

ct:

P

arti

al v

apo

riza

tio

n o

f a

wat

er (

A)

-iso

pro

pan

ol

(B)

mix

ture

at

1 a

tm.

Giv

en:

V

apo

r-li

qu

id e

qu

ilib

riu

m d

ata

at 1

atm

an

d v

apo

r-p

ress

ure

dat

a.

Fin

d:

(a)

C

on

stru

ct T

-x-y

an

d

y-x

d

iag

ram

s.

(b

) C

om

po

siti

on

of

vap

or

wh

en a

60

mo

l% A

- 4

0 m

ol%

B m

ixtu

re i

s at

its

bu

bb

le p

oin

t.

(c

) C

om

po

siti

on

of

vap

or

and

liq

uid

fo

r 7

5 m

ol%

vap

ori

zati

on

of

mix

ture

in

Par

t (a

).

(d

) K

-val

ues

an

d α

-val

ues

at

80

an

d 8

9oC

.

(e

) C

om

par

iso

n o

f p

arts

(a)

, (b

), a

nd

(c)

to

res

ult

s fr

om

usi

ng R

aou

lt's

an

d D

alto

n's

law

s.

An

aly

sis:

(

a)

Th

e fo

llo

win

g a

re p

lots

of

the

giv

en e

qu

ilib

riu

m d

ata,

in

clu

din

g t

he

pu

re-

com

po

nen

t n

orm

al b

oil

ing p

oin

ts.

Page 13: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 4

.15

(c

on

tin

ued

)

An

aly

sis:

(

a)

con

tin

ued

Ex

erci

se 4

.15

(c

on

tin

ued

)

An

aly

sis:

(b)

Fro

m t

he

y-x

plo

t o

n t

he

pre

vio

us

pag

e, t

he

com

po

siti

on

of

the

firs

t b

ub

ble

of

vap

or

is 5

7 m

ol%

iso

pro

pan

ol

and

43

mo

l% w

ater

. S

ee t

he

q-l

ine

on

th

e d

iagra

m.

(c

) F

or

75

mo

l% v

apo

riza

tio

n,

use

th

e in

ver

se l

ever

-arm

ru

le o

n t

he

T-x

-y

dia

gra

m o

r p

lot

a q

-lin

e o

n t

he

y-x

dia

gra

m.

Fo

r th

e la

tter

, fr

om

th

e eq

uat

ion

ab

ov

e E

q.

(4-6

),

the

slo

pe

of

the

q-l

ine

is [

(V/F

)-1

]/(V

/F)

= (

0.7

5-1

.0)/

0.7

5 =

-0

.33

3.

Th

e co

nst

ruct

ion

is

sho

wn

on

th

e y-

x d

iag

ram

, w

her

e th

e in

ters

ecti

on

wit

h t

he

equ

ilib

riu

m c

urv

e giv

es x

A =

0.1

4 a

nd

yA =

0.5

0.

(d)

Can

no

t co

mp

ute

th

e K

-val

ues

or

α a

t 8

0oC

, b

ecau

se t

his

tem

per

atu

re i

s b

elo

w

the

low

est

bo

ilin

g m

ixtu

re,

wh

ich

is

the

azeo

tro

pe.

A

t 8

9oC

, th

e T

-x-y

dia

gra

m g

ives

th

e fo

llo

win

g c

om

po

siti

on

s fr

om

th

e li

ne

sho

wn

on

th

e

abo

ve

dia

gra

m:

y B =

0.3

5,

yA =

0.6

5

x B

= 0

.03

5,

xA =

0.9

65

Fro

m E

q.

(2-1

9)

for

the

def

init

ion

of

the

K-

val

ue,

B

BA

BA A

0.3

50

.65

01

00

.03

50

.96

5.6

7=

==

==

=K

yy x

Kx

Fro

m E

q.

(2-2

1)

for

the

def

init

ion

of

the

rela

tiv

e v

ola

tili

ty,

α,

no

tin

g t

hat

at

89

oC

an

d 1

atm

,

iso

pro

pan

ol

is m

ore

vo

lati

le,

α

B,A

B A

==

=K K

10

06

71

5.

(e)

To

cal

cula

te T

-x-y

cu

rves

fro

m v

apo

r p

ress

ure

dat

a, u

sin

g R

aou

lt's

an

d

Dal

ton

's l

aws,

Eq

. (2

-44

) a

pp

lies

, as

wel

l as

th

e su

m o

f th

e m

ole

fra

ctio

ns

in t

he

ph

ases

in

equ

ilib

riu

m.

Th

us,

Ky x

PT

PK

y x

PT

P

yy

xx

ss

AA A

A

BB B

B

AB

AB

,

(1

, 2

)

,

(3

, 4

)

==

==

+=

+=

��

��

11

Eq

uat

ion

s (1

) to

(4

) ca

n b

e re

du

ced

to

th

e fo

llo

win

g e

qu

atio

ns

for

the

mo

le

frac

tio

ns

of

ben

zen

e in

ter

ms

of

the

K-v

alu

es:

xK

KK

yK

xA

B

AB

AA

A

,

=− −

=1

(5,

6)

If t

he

giv

en v

apo

r p

ress

ure

dat

a ar

e fi

tted

to

An

toin

e eq

uat

ion

s, w

e o

bta

in:

Page 14: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 4

.15

(c

on

tin

ued

)

An

aly

sis:

(

e) c

on

tin

ued

PT

PT

s sA B

(

7)

(8

)

=−

+

� ���

=−

+

� ���

exp

..

.

exp

.. .

18

48

54

39

21

96

23

09

1

25

01

73

80

10

6

35

32

38

Wh

ere

vap

or

pre

ssu

re i

s in

to

rr a

nd

tem

per

atu

re i

s in

oC

. S

olv

ing,

Eq

s. (

1)

to (

8),

T,

oC

P

s of

B

Ps o

f A

K

B

KA

x B

y B

αB

-A

82

.5

76

0.0

3

92

.1

1.0

00

0

0.5

15

9

1.0

00

1

.000

1

.938

8

4.0

8

09

.5

41

6.2

1

.065

1

0.5

47

6

0.8

74

0

.931

1

.945

8

6.0

8

79

.9

45

0.2

1

.157

8

0.5

92

4

0.7

21

0

.835

1

.954

8

8.0

9

55

.7

48

6.6

1

.257

5

0.6

40

2

0.5

83

0

.733

1

.964

9

0.0

1

037

.3

52

5.3

1

.364

9

0.6

91

2

0.4

58

0

.626

1

.975

9

2.0

1

125

.0

56

6.6

1

.480

3

0.7

45

6

0.3

46

0

.513

1

.985

9

4.0

1

219

.3

61

0.6

1

.604

3

0.8

03

5

0.2

45

0

.394

1

.997

9

6.0

1

320

.5

65

7.4

1

.737

5

0.8

65

0

0.1

55

0

.269

2

.009

9

8.0

1

429

.1

70

7.2

1

.880

4

0.9

30

5

0.0

73

0

.138

2

.021

1

00

.0

15

45

.6

76

0.0

2

.033

6

1.0

00

0

0.0

00

0

.000

2

.034

Th

ese

resu

lts

are

plo

tted

bel

ow

. R

aou

lt’s

law

is

bad

ly i

n e

rro

r w

hen

co

mp

ared

to

th

e

exp

erim

enta

l d

ata.

Fo

r p

art

(b),

Rao

ult

's l

aw p

red

icts

a b

ub

ble

-po

int

vap

or

wit

h a

n i

sop

rop

ano

l m

ole

fra

ctio

n o

f

0.5

6.

By c

oin

cid

ence

, th

is c

om

par

es w

ell

wit

h t

he

resu

lt d

eter

min

ed w

ith

th

e ex

per

imen

tal

dat

a.

Fo

r p

art

(c),

ho

wev

er,

Rao

ult

's l

aw p

red

icts

iso

pro

pan

ol

mo

le f

ract

ion

s o

f 0

.28

fo

r th

e li

qu

id a

nd

0.4

3 f

or

the

vap

or.

T

hes

e ar

e d

rast

ical

ly d

iffe

ren

t fr

om

th

e v

alu

es o

f 0

.14

an

d 0

.50

, re

spec

tiv

ely

fro

m t

he

exp

erim

enta

l d

ata.

R

aou

lt's

law

can

no

t b

e u

sed

fo

r th

e is

op

rop

ano

l-w

ater

syst

em,

for

wh

ich

it

also

fai

ls t

o p

red

ict

an a

zeo

tro

pe.

Ex

erci

se 4

.15

(c

on

tin

ued

)

An

aly

sis:

(

e) c

on

tin

ued

Page 15: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 4

.16

S

ub

ject

:

Vap

ori

zati

on

of

mix

ture

s o

f n

-hex

ane

(H)

and

n-o

ctan

e (C

) at

1 a

tm

Giv

en:

T

-x-y

dia

gra

m i

n F

ig.

4.3

, an

d y

-x d

iagra

m i

n F

ig.

4.4

. 1

00

km

ol

mix

ture

.

Fin

d:

Tem

per

atu

re,

km

ol

of

vap

or,

mo

le f

ract

ion

s o

f H

in

liq

uid

an

d v

apo

r at

eq

uil

ibri

um

fo

r

var

iou

s fl

ash

co

nd

itio

ns.

An

aly

sis:

L

et z

H =

mo

le f

ract

ion

of

n-h

exan

e in

th

e fe

ed a

nd

Ψ =

V/F

.

U

se i

nv

erse

lev

er-a

rm r

ule

as

dis

pla

yed

by L

ine

DE

F i

n F

ig.

4.3

.

T

he

resu

lts

for

par

ts (

a) t

hro

ugh

(f)

are

as

foll

ow

s:

Giv

en

T,

oF

V

, k

mo

l y H

x

H

(a)

zH

= 0

.5,

Ψ =

0.2

1

96

2

0

0.8

0

0.4

3

(b)

zH

= 0

.4,

yH =

0.6

2

20

4

8.6

0

.60

0

.21

(c)

zH

= 0

.6,

xC =

0.7

2

10

7

3.7

0

.70

0

.30

(d)

zH

= 0

.5,

Ψ =

0.0

1

88

0

.0

0.8

4

0.5

0

(e)

zH

= 0

.5,

Ψ =

1.0

2

30

1

00

0

.50

0

.14

(f)

zH

= 0

.5,

T =

20

0oF

2

00

3

1

0.7

7

0.3

8

Ex

erci

se 4

.17

S

ub

ject

:

Der

ivat

ion

of

equ

ilib

riu

m f

lash

eq

uat

ion

s fo

r a

bin

ary m

ixtu

re (

1,

2).

Giv

en:

E

qs.

(5

), (

6),

an

d (

3)

of

Tab

le 4

.4.

Fin

d:

D

eriv

e giv

en e

qu

atio

ns

for

x 1,

x 2,

y 1,

y 2,

and

Ψ =

V/F

.

An

aly

sis:

F

irst

der

ive

the

equ

atio

n f

or

Ψ =

V/F

. F

rom

Eq

. (3

), T

able

4.4

,

zK

K

zK

K

11

1

12

2

1

11

11

11

0−

+−

+−

+−

=��

������

��

ΨΨ

(1)

So

lvin

g E

q.

(1)

for

Ψ,

and

sim

pli

fyin

g,

Ψ=

−−

−−

−−

+−

−−

zK

zK

zK

Kz

KK

11

12

11

21

21

11

1

11

11

1

������

����������

=−

−−

zK

KK

K

11

22

1

11

1

����

/

(3)

Su

bst

itu

tin

g E

q.

(3)

into

Eq

. (5

) o

f T

able

4.4

an

d s

imp

lify

ing g

ives

th

e re

qu

ired

eq

uat

ion

fo

r x 1

.

Th

en u

se y

1 =

K1x 1

an

d s

imp

lify

, fo

llo

wed

by x

2 =

1 -

x1

an

d

y 2 =

1-

y 1 .

Page 16: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 4

.18

S

ub

ject

:

Co

nd

itio

ns

for

Rac

hfo

rd-R

ice

equ

atio

n t

o b

e sa

tisf

ied

.

Giv

en:

E

q.

(3),

Tab

le 4

.4,

wh

ich

is

the

Rac

hfo

rd-R

ice

equ

atio

n.

Fin

d:

Co

nd

itio

ns

un

der

wh

ich

th

e eq

uat

ion

can

be

sati

sfie

d f

or

01

≤≤

V F.

An

aly

sis:

A

nec

essa

ry,

bu

t n

ot

suff

icie

nt,

co

nd

itio

n i

s th

at a

t le

ast

on

e K

-val

ue

is <

1 a

nd

at

leas

t o

ne

K-v

alu

e is

> 1

. I

f al

l K

-val

ues

are

> 1

, th

e su

m:

zK

K

ii

iiC

1

11

1

+−

=���

��

Ψ

wil

l b

e n

egat

ive

and

can

no

t b

e ze

ro.

If a

ll K

-val

ues

are

< 1

, th

e n

um

erat

or

in t

he

sum

wil

l b

e p

osi

tiv

e fo

r ea

ch t

erm

. W

ith

Ψ b

etw

een

0 a

nd

1,

the

term

Ψ(K

i -

1)

wil

l al

ways

be

< 1

. T

her

efo

re,

the

den

om

inat

or

wil

l b

e p

osi

tiv

e al

so

and

th

e su

m w

ill

be

po

siti

ve

and

can

no

t b

e ze

ro.

Ex

erci

se 4

.19

S

ub

ject

:

Fla

sh v

apo

riza

tio

n o

f a

ben

zen

e (A

) -

tolu

ene

(B)

mix

ture

fo

r α

A-B

= 2

.3.

Giv

en:

F

eed

is

40

mo

l% A

an

d 6

0 m

ol%

B.

Fin

d:

Per

cen

t o

f A

in

th

e eq

uil

ibri

um

vap

or

if 9

0%

of

the

tolu

ene

leav

es i

n t

he

liq

uid

by

gra

ph

ical

mea

ns.

An

aly

sis:

F

or

con

stan

t re

lati

ve

vo

lati

lity

, E

q.

(4-8

) ap

pli

es,

y

x

xA

A,B

A

AA

,B1

+=

α

α1

��

So

lvin

g t

his

eq

uat

ion

fo

r y

A a

s a

fun

ctio

n o

f x

A ,

xA

yA

0.1

0

.20

35

0.2

0

.36

51

0.3

0

.49

64

0.4

0

.60

53

0.5

0

.69

70

0.6

0

.77

53

0.7

0

.84

29

0.8

0

.90

20

0.9

0

.95

39

A p

lot

of

the

calc

ula

ted

eq

uil

ibri

um

cu

rve

is g

iven

bel

ow

. T

o u

se t

his

plo

t fo

r a

gra

ph

ical

solu

tio

n o

f th

e eq

uil

ibri

um

, d

raw

a q

-lin

e, u

sin

g t

he

foll

ow

ing e

qu

atio

n a

bo

ve

Eq

. (4

-6),

fo

r an

assu

med

val

ue

of

Ψ =

V/F

an

d c

hec

k t

he

resu

ltin

g %

rec

ov

ery o

f to

luen

e in

th

e li

qu

id.

Var

y Ψ

un

til

the

% r

eco

ver

y =

90

%.

Th

en c

om

pu

te,

for

the

corr

esp

on

din

g Ψ

, t

he

% r

eco

ver

y o

f

ben

zen

e in

th

e v

apo

r.

y

xz

xA

AA

A=

−� ���

+� ���

=−� ���

+� ���

Ψ

ΨΨ

Ψ

ΨΨ

11

11

04

0.

(1)

Page 17: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 4

.19

(co

nti

nu

ed)

An

aly

sis:

(

con

tin

ued

)

Bas

is:

F =

10

0 m

ole

s, 6

0 m

ole

s to

luen

e (B

).

Wan

t 0

.9(6

0)

= 5

4 m

ole

s B

in

liq

uid

. T

her

efo

re,

60

- 5

4 =

6 m

ole

s B

in

vap

or.

T

her

efo

re,

wan

t (n

B) V

= y

BV

= (

1 -

yA)1

00

Ψ =

6.

Th

en c

om

pu

te %

reco

ver

y o

f b

enze

ne

in v

apo

r =

(n

A) V

/40

x 1

00

% =

yAV

/40

x

10

0%

= 2

.5 y

x 1

00

%.

Th

e

foll

ow

ing a

re t

yp

ical

val

ues

fo

r th

e tr

ial

and

err

or

pro

ced

ure

, w

ith

th

e fi

nal

res

ult

at

the

bo

tto

m.

Ass

um

ed Ψ

y

A

xA

(nB) V

,

mo

les

% r

eco

ver

y

of

A i

n v

apo

r

0.3

0

.54

0

.35

1

3.8

4

0.5

0.2

0

.56

0

.36

8

.8

28

.0

0.1

5

0.5

75

0

.37

6

.4

21

.6

0.1

42

0

.58

0

.37

5

6.0

2

0.6

Ex

erci

se 4

.20

S

ub

ject

:

Fla

sh v

apo

riza

tio

n o

f a

ben

zen

e (A

) -

tolu

ene

(B)

mix

ture

.

Giv

en:

F

eed

is

40

mo

l% A

an

d 6

0 m

ol%

B.

V

apo

r p

ress

ure

dat

a.

Ass

um

pti

on

s:

Rao

ult

's l

aw (

idea

l so

luti

on

s).

Pre

ssu

re =

1 a

tm.

Fin

d:

Per

cen

t o

f A

in

th

e eq

uil

ibri

um

vap

or

if 9

0%

of

the

tolu

ene

leav

es i

n t

he

liq

uid

.

An

aly

sis:

B

asis

: F

= 1

00

mo

le w

ith

60

mo

les

B a

nd

40

mo

les

A.

Wan

t 0

.9(6

0)

= 5

4 m

ole

s B

in l

iqu

id.

Th

eref

ore

, 6

0 -

54

= 6

mo

les

B i

n v

apo

r.

Th

eref

ore

, w

ant

(nB) V

= y

BV

= (

1 -

yA)1

00

Ψ =

6.

Th

en c

om

pu

te %

rec

ov

ery o

f b

enze

ne

in v

apo

r =

(n

A) V

/40

x 1

00

% =

yAV

/40

x

10

0%

= 2

.5 y

x 1

00

%.

Th

e fo

llo

win

g t

rial

an

d e

rro

r p

roce

du

re c

an b

e u

sed

, b

ased

on

mat

eria

l

bal

ance

an

d e

qu

ilib

riu

m e

qu

atio

ns:

(1)

Gu

ess

a te

mp

erat

ure

. (

2)

Rea

d v

apo

r p

ress

ure

s fr

om

Fig

. 2

.4 a

nd

co

mp

ute

K-v

alu

es f

rom

Rao

ult

's l

aw (

Eq

. (3

), T

able

2.3

), K

PP

iis

=/

. (

3)

So

lve

for

Ψ =

V/F

usi

ng t

he

fift

h e

qu

atio

n i

n

Ex

erci

se 4

.17

,

Ψ=

−−

−=

−−

zK

KK

K

KK

K

K

AA

BB

A

AB

B

A

/1

1

1

0.4

0/

11

1

����

����

(4)

So

lve

for

yA f

rom

th

e th

ird

eq

uat

ion

in

Ex

erci

se 4

.17

,

y

KK

KK

KA

AB

AB

A=

−−

���

�/

(5)

Co

mp

ute

(n

B) V

= (

1 -

yA)1

00

Ψ .

If

th

e v

alu

e is

6,

then

tem

per

atu

re g

ues

s is

co

rrec

t.

Oth

erw

ise,

gu

ess

ano

ther

T,

and

rep

eat

step

s (1

) to

(5

).

If 6

, co

mp

ute

% r

eco

ver

y o

f b

enze

ne

in

the

vap

or

fro

m

2.5

yAΨ

x 1

00

%.

Gu

ess

T,

oF

P

s o

f A

,

psi

a

Ps o

f B

,

psi

a

KA

KB

Ψ

yA

Mo

les

B

in v

apo

r

19

5

20

.0

8.0

1

.36

0

.54

4

-0.7

9

20

5

23

.4

9.5

1

.59

0

.64

6

0.1

13

0

.59

6

4.6

20

5.5

2

3.6

9

.6

1.6

05

0

.65

3

0.1

61

0

.58

5

6.7

By i

nte

rpo

lati

on

,

T =

20

5.3

oF

to

ob

tain

6 m

ole

s o

f B

in

th

e v

apo

r.

Th

is c

orr

esp

on

ds

to Ψ

=

0.1

45

an

d y

A =

0.5

88

.

Fro

m a

bo

ve,

% r

eco

ver

y o

f b

enze

ne

in t

he

vap

or

= 2

.5(0

.58

8)(

0.1

45

)10

0%

= 2

1.3

%

Page 18: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 4

.21

S

ub

ject

:

Eq

uil

ibri

um

fla

sh o

f a

sev

en-c

om

po

nen

t m

ixtu

re.

Giv

en:

Fee

d m

ole

fra

ctio

ns

and

K-v

alu

es.

Fin

d:

Ψ =

V/F

b

y:

(a

) R

ach

ford

- R

ice

equ

atio

n,

fz

K

Kg

ii

i

iiC

iC

1

1

1

1

1

11

{}

{,

ΨΨ

=−

+−

==

=

��

��

��

(b

) A

lter

nat

ive

flas

h e

qu

atio

n,

fz

K Kg

ii

i iiC

iC

2

1

2

11

1{

}{

,}

ΨΨ

Ψ=

+−

==

=

��

��

M

ake

plo

ts o

f f{

Ψ} v

s. Ψ

fo

r ea

ch m

eth

od

an

d c

om

par

e.

An

aly

sis:

C

alcu

lati

on

s w

ith

a s

pre

adsh

eet,

fo

r v

alu

es o

f Ψ

fro

m 0

to

1.0

in

in

terv

als

of

0.1

:

(a)

I z

F

K

Ψ =

0

0.1

0.2

0.3

0.4

0.5

0.6

0.7

0.8

0.9

1

g{i,Ψ

1

0.0

079

16.2

-0

.120

-0.0

48

-0.0

30

-0.0

22

-0.0

17

-0.0

14

-0.0

12

-0.0

10

-0.0

09

-0.0

08

-0.0

07

2

0.1

321

5.2

-0

.555

-0.3

91

-0.3

02

-0.2

45

-0.2

07

-0.1

79

-0.1

58

-0.1

41

-0.1

27

-0.1

16

-0.1

07

3

0.0

849

2.6

-0

.136

-0.1

17

-0.1

03

-0.0

92

-0.0

83

-0.0

75

-0.0

69

-0.0

64

-0.0

60

-0.0

56

-0.0

52

4

0.2

690

1.9

8

-0.2

64

-0.2

40

-0.2

20

-0.2

04

-0.1

89

-0.1

77

-0.1

66

-0.1

56

-0.1

48

-0.1

40

-0.1

33

5

0.0

589

0.9

1

0.0

05

0.0

05

0.0

05

0.0

05

0.0

05

0.0

06

0.0

06

0.0

06

0.0

06

0.0

06

0.0

06

6

0.1

321

0.7

2

0.0

37

0.0

38

0.0

39

0.0

40

0.0

42

0.0

43

0.0

44

0.0

46

0.0

48

0.0

49

0.0

51

7

0.3

151

0.2

8

0.2

27

0.2

44

0.2

65

0.2

89

0.3

19

0.3

54

0.3

99

0.4

57

0.5

35

0.6

45

0.8

10

f{Ψ

}:

-0.8

05

-0.5

08

-0.3

45

-0.2

27

-0.1

30

-0.0

42

0.0

45

0.1

37

0.2

45

0.3

80

0.5

68

(b

)

I z

F

K

Ψ =

0

0.1

0.2

0.3

0.4

0.5

0.6

0.7

0.8

0.9

1

g{i,Ψ

1

0.0

079

16.2

0.1

28

0.0

51

0.0

32

0.0

23

0.0

18

0.0

15

0.0

13

0.0

11

0.0

10

0.0

09

0.0

08

2

0.1

321

5.2

0.6

87

0.4

84

0.3

73

0.3

04

0.2

56

0.2

22

0.1

95

0.1

74

0.1

58

0.1

44

0.1

32

3

0.0

849

2.6

0.2

21

0.1

90

0.1

67

0.1

49

0.1

35

0.1

23

0.1

13

0.1

04

0.0

97

0.0

90

0.0

85

4

0.2

690

1.9

8

0.5

33

0.4

85

0.4

45

0.4

12

0.3

83

0.3

57

0.3

35

0.3

16

0.2

99

0.2

83

0.2

69

5

0.0

589

0.9

1

0.0

54

0.0

54

0.0

55

0.0

55

0.0

56

0.0

56

0.0

57

0.0

57

0.0

58

0.0

58

0.0

59

6

0.1

321

0.7

2

0.0

95

0.0

98

0.1

01

0.1

04

0.1

07

0.1

11

0.1

14

0.1

18

0.1

23

0.1

27

0.1

32

7

0.3

151

0.2

8

0.0

88

0.0

95

0.1

03

0.1

13

0.1

24

0.1

38

0.1

55

0.1

78

0.2

08

0.2

51

0.3

15

f{Ψ

}:

0.8

05

0.4

57

0.2

76

0.1

59

0.0

78

0.0

21

-0.0

18

-0.0

41

-0.0

49

-0.0

38

0.0

00

Th

e v

alu

es o

f f{

Ψ} a

re p

lott

ed o

n t

he

nex

t p

age,

wh

ere

it i

s o

bse

rved

th

at t

he

Rac

hfo

rd-R

ice

and

Alt

ern

ativ

e eq

uat

ion

s giv

e th

e sa

me

resu

lt o

f Ψ

= 0

.55

. H

ow

ever

, th

e al

tern

ativ

e eq

uat

ion

als

o

has

a t

riv

ial

roo

t at

Ψ =

1.0

. W

ith

a N

ewto

n p

roce

du

re,

the

alte

rnat

ive

equ

atio

n m

ay c

on

ver

ge

to

the

triv

ial

roo

t.

Th

eref

ore

, th

e R

ach

ford

-Ric

e eq

uat

ion

is

pre

ferr

ed b

ecau

se o

f it

s u

niq

uen

ess.

Ex

erci

se 4

.21

(co

nti

nu

ou

s)

An

aly

sis:

(

con

tin

ued

)

Page 19: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 4

.22

S

ub

ject

: E

qu

ilib

riu

m f

lash

of

a h

yd

roca

rbo

n m

ixtu

re.

Giv

en:

1

00

km

ole

s o

f 2

5 m

o1

% n

C4

, 4

0 m

ol%

nC

5,

an

d 3

5 m

ol%

nC

6 .

K

-val

ues

in

Fig

. 2

.8

Ass

um

pti

on

s:

Am

ou

nts

are

per

ho

ur.

Fin

d:

Pre

ssu

re a

nd

liq

uid

an

d v

apo

r co

mp

osi

tio

ns

for

equ

ilib

riu

m a

t 2

40

oF

to

rec

ov

er,

in t

he

liq

uid

ph

ase,

80

% o

f th

e n

C6 i

n t

he

feed

.

An

aly

sis:

F

or

80

% r

eco

ver

y o

f n

C6 ,

th

e li

qu

id p

rod

uct

mu

st c

on

tain

(0

.35

)(0

.80

)(1

00

) =

28

km

ole

/h o

f n

C6 .

M

ust

so

lve

by t

rial

an

d e

rro

r b

y a

ssu

min

g v

alu

es o

f p

ress

ure

to

ob

tain

th

e K

-

val

ues

fro

m F

ig.

2.8

. T

hen

so

lve

the

Rac

hfo

rd-R

ice

equ

atio

n (

Eq

. (3

), T

able

4.4

),

f

zK

K

ii

iiC

{}

ΨΨ

=−

+−

==�

1

11

01

��

��

for

Ψ =

V/F

b

y a

no

nli

nea

r so

lver

, su

ch a

s N

ewto

n's

met

ho

d.

C

om

pu

te V

fro

m E

q.

(4),

Tab

le

4.4

.

Th

en s

olv

e E

qs.

(5

) an

d (

6),

Tab

le 4

.4 f

or

the

equ

ilil

bri

um

vap

or

and

liq

uid

co

mp

osi

tio

ns.

So

lve

for

the

liq

uid

, L

, fr

om

Eq

. (7

).

Rep

eat

this

pro

ced

ure

un

til

28

km

ol/

h

of

nC

6 a

re f

ou

nd

in

the

equ

ilib

riu

m l

iqu

id a

s co

mp

ute

d f

rom

n

xL

LnC

nC

66

=,

no

tin

g t

hat

eac

h a

ssu

med

pre

ssu

re

req

uir

es a

n i

tera

tiv

e p

roce

du

re t

o s

olv

e fo

r Ψ

fro

m t

he

Rac

hfo

rd-R

ice

equ

atio

n.

Th

e ca

lcu

lati

on

s

are

sum

mar

ized

in

th

e fo

llo

win

g t

able

:

Ass

um

ed P

, p

sia

10

0

11

0

11

7

K-v

alu

es:

n

C4

2.4

0

2.3

0

2.2

5

n

C5

1.2

0

1.0

8

1.0

0

n

C6

0.5

3

0.5

0

0.4

8

V/F

0

.70

6

0.4

82

0

.33

5

L,

km

ol/

h

29

.4

51

.8

66

.5

x o

f n

C4

0.5

24

0

.46

1

0.4

24

nL o

f n

C4 ,

km

ol/

h

15

2

4

28

Th

eref

ore

, th

e co

nv

erg

ed p

ress

ure

is

11

7 p

sia.

T

he

equ

ilib

riu

m v

apo

r an

d l

iqu

id c

om

po

siti

on

s in

term

s o

f am

ou

nts

are

:

Co

mp

on

ent

Vap

or

flo

ws,

km

ol/

h

Liq

uid

flo

ws,

km

ol/

h

n

C4

13

1

2

n

C5

13

2

7

n

C6

7

28

.

Ex

erci

se 4

.23

S

ub

ject

: E

qu

ilib

riu

m f

lash

vap

ori

zati

on

of

a h

yd

roca

rbo

n m

ixtu

re.

Giv

en:

E

qu

imo

lar

mix

ture

of

C2,

C3,

nC

4,

and

nC

5.

K-v

alu

es f

rom

Fig

. 2

.8 a

nd

2.9

Fin

d:

Am

ou

nts

an

d c

om

po

siti

on

s o

f eq

uil

ibri

um

liq

uid

an

d v

apo

r at

15

0oF

an

d 2

05

psi

a.

Co

nd

itio

ns

of

T a

nd

P w

her

e 7

0%

of

C2

and

no

mo

re t

han

5%

of

nC

4 i

s in

th

e v

apo

r.

An

aly

sis:

T

ake

as a

bas

is,

a fe

ed o

f 1

00

lb

mo

l/h

. F

rom

Fig

. 2

.8,

at 1

50

oF

an

d 2

05

psi

a, t

he

K-

val

ues

are

as

giv

en i

n t

he

tab

le b

elo

w.

T

hen

so

lve

the

Rac

hfo

rd-R

ice

equ

atio

n (

Eq

. (3

), T

able

4.4

),

fz

K

K

ii

iiC

{}

ΨΨ

=−

+−

==�

1

11

01

��

��

for

Ψ =

V/F

b

y a

no

nli

nea

r so

lver

, su

ch a

s N

ewto

n's

met

ho

d.

C

om

pu

te V

fro

m E

q.

(4),

Tab

le

4.4

. T

hen

so

lve

Eq

s. (

5)

and

(6

), T

able

4.4

fo

r th

e eq

uil

ilb

riu

m v

apo

r an

d l

iqu

id c

om

po

siti

on

s.

Th

e ca

lcu

lati

on

s ar

e su

mm

ariz

ed i

n t

able

bel

ow

, w

hic

h a

lso

in

clu

des

oth

er c

on

dit

ion

s o

f

T a

nd

P t

o o

bta

in 7

0%

of

C2

and

no

mo

re t

han

5%

of

nC

4 i

n t

he

vap

or.

T

hu

s, w

e d

esir

e

(0.7

)(2

5)

= 1

7.5

lb

mo

l/h

of

C2 i

n t

he

vap

or

and

25

- 1

7.5

= 7

.5 l

bm

ol/

hr

of

C2 i

n t

he

liq

uid

. A

t

the

sam

e ti

me

we

des

ire

no

mo

re t

han

(0

.05

)(2

5)

= 1

.25

lb

mo

l/h

of

nC

4 i

n t

he

vap

or,

corr

esp

on

din

g t

o 2

5 -

1.2

5 =

23

.75

lb

mo

l/h

of

nC

4 i

n t

he

liq

uid

. I

n s

earc

hin

g f

or

thes

e

oth

er c

on

dit

ion

s, w

e n

ote

th

at a

t th

e b

ase

con

dit

ion

s, 7

5.8

% o

f th

e C

2 g

oes

to

th

e v

apo

r, w

hic

h i

s

ver

y c

lose

to

th

e d

esir

ed 7

0%

. B

ut

30

% o

f th

e n

C4

als

o g

oes

to

th

e v

apo

r, w

hic

h i

s m

uch

hig

her

than

th

e d

esir

ed 5

%.

Th

e re

lati

ve

vo

lati

lity

of

C2 t

o n

C4 a

t th

e b

ase

con

dit

ion

s is

:

αC

nC

C nC

CC

nC

nC

CC

nC

nC

24

2 4

22

44

22

44

,

/ /

()

/(

)

()

/(

)

(.

/.

)

(.

/.

).

==

==

=K K

yx

yx

nn

nn

VL

VL

19

06

0

75

17

57

39

Bu

t w

e n

eed

a r

elat

ive

vo

lati

lity

of:

αC

nC

CC

nC

nC

24

22

44

,

()

/(

)

()

/(

)

(.

/.

)

(.

/.

).

==

=n

n

nn

VL

VL

17

57

5

12

52

37

54

43

Fo

r id

eal

solu

tio

ns,

wh

ere

the

Rao

ult

's l

aw K

-val

ue

app

lies

, E

q.

(2-2

1)

com

bin

ed w

ith

Eq

. (3

in

Tab

le 2

.3,

giv

es r

elat

ive

vo

lati

lity

as

ind

epen

den

t o

f p

ress

ure

an

d e

qu

al t

o t

he

rati

o o

f v

apo

r

pre

ssu

res,

wh

ich

dep

end

on

ly o

n t

emp

erat

ure

. I

n g

ener

al,

as t

he

tem

per

atu

re i

s re

du

ced

, th

e

rela

tiv

e v

ola

tili

ty i

ncr

ease

s.

Ass

um

e th

at t

he

hyd

roca

rbo

n m

ixtu

re,

alth

ou

gh

no

t an

id

eal

solu

tio

n,

Page 20: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 4

.23

(co

nti

nu

ed)

A

na

lysi

s:

(co

nti

nu

ed)

foll

ow

s th

ese

sam

e tr

end

s.

Th

us,

to

in

crea

se t

he

rela

tiv

e v

ola

tili

ty,

the

pre

ssu

re h

as l

ittl

e ef

fect

.

We

mu

st d

ecre

ase

the

tem

per

atu

re t

o o

bta

in t

he

des

ired

rel

ativ

e v

ola

tili

ty,

and

th

en a

dju

st t

he

pre

ssu

re t

o o

bta

in t

he

req

uir

ed c

om

po

siti

on

s.

Th

e b

ase

case

an

d c

alcu

lati

on

s le

adin

g t

o t

he

des

ired

sep

arat

ion

are

su

mm

ariz

ed i

n t

he

foll

ow

ing t

able

:

B

ase

Cas

e

D

esir

ed C

ase

T,

oF

1

50

-7

0

-40

-4

0

P,

psi

a 2

05

1

4.7

1

4.7

1

6.4

K-v

alu

es:

C

2

4.1

4

.0

7.5

6

.7

C

3

1.5

0

.46

1

.11

1

.00

nC

4

0.5

6

0.0

55

0

.16

5

0.1

48

nC

5

0.2

15

0

.07

7

0.0

28

0

.02

5

α o

f C

2 t

o n

C4

7.3

7

3

45

4

5

% C

2 t

o v

apo

r 7

5.8

7

0

% n

C4 t

o v

apo

r 3

0

4.9

Th

us,

at

-40

oF

an

d 1

6.4

psi

a, t

he

des

ired

70

% o

f th

e et

han

e is

fo

un

d i

n t

he

vap

or

pro

du

ct,

wit

h

on

ly 5

% o

f th

e n

-bu

tan

e.

Th

e co

mp

osi

tio

ns

of

the

vap

or

and

liq

uid

pro

du

cts

for

the

bas

e ca

se a

nd

th

e d

esir

ed c

ase

are

as

foll

ow

s:

Bas

e C

ase:

Des

ired

Cas

e:

Co

mp

on

ent

υ,

lbm

ol/

h

y l,

lb

mo

l/h

x

υ,

lbm

ol/

h

y l,

lb

mo

l/h

x

C2

19

.0

0.4

4

6

.0

0.1

1

17

.5

0.6

9

7

.5

0.1

0

C3

13

.4

0.3

1

11

.6

0.2

0

6

.4

0.2

5

18

.6

0.2

5

nC

4

7

.5

0.1

7

17

.5

0.3

1

1.2

2

0.0

5

2

3.7

8

0.3

2

nC

5

3

.5

0.0

8

21

.5

0.3

8

0.2

2

0.0

1

2

4.7

8

0.3

3

T

ota

l:

43

.4

1.0

0

56

.6

1.0

0

25

.34

1

.00

7

4.6

6

1.0

0

Ex

erci

se 4

.24

S

ub

ject

:

Co

oli

ng o

f a

reac

tor

effl

uen

t w

ith

rec

ycl

e li

qu

id f

rom

a p

arti

al c

on

den

sati

on

.

Giv

en:

R

eact

or

effl

uen

t te

mp

erat

ure

of

10

00

oF

an

d c

om

po

siti

on

in

lb

mo

l/h

of

20

00

H2,

20

00

CH

4,

50

0 b

enze

ne,

an

d 1

00

to

luen

e.

Par

tial

co

nd

ensa

tio

n c

on

dit

ion

s o

r 1

00

oF

an

d 5

00

psi

a, a

nd

com

po

nen

t K

-val

ues

at

thes

e co

nd

itio

ns.

T

wo

hea

t ex

chan

ger

s in

a r

ecycl

e lo

op

.

Fin

d:

(a)

C

om

po

siti

on

an

d f

low

rat

e o

f v

apo

r le

avin

g f

lash

dru

m i

n F

ig.

4.3

8.

(b

) P

roo

f th

at v

apo

r fl

ow

rat

e is

in

dep

end

ent

of

qu

ench

rat

e.

An

aly

sis:

(

a)

Ass

um

e th

at v

apo

r ra

te i

s in

dep

end

ent

of

qu

ench

rat

e.

Th

eref

ore

, co

nd

uct

th

e

flas

h c

alcu

lati

on

on

ju

st t

he

reac

tor

effl

uen

t at

th

e fl

ash

dru

m c

on

dit

ion

s o

f te

mp

erat

ure

an

d

pre

ssu

re.

Use

th

e R

ach

ford

-Ric

e eq

uat

ion

s (E

qs.

(3

) an

d (

6),

Tab

le 4

.4):

fz

K

K

ii

iiC

{}

ΨΨ

=−

+−

==�

1

11

01

��

��

(1

)

yz

K Ki

ii i

=+

−1

1��

(2

)

No

nli

nea

r E

q.

(1)

is s

olv

ed f

or

Ψ =

V/F

, f

oll

ow

ed b

y c

alcu

lati

on

of

V =

ΨF

, an

d t

hen

calc

ula

tio

ns

of

vap

or

mo

le f

ract

ion

s fr

om

Eq

. (2

).

Th

e giv

en i

np

ut

for

Eq

. (1

) is

:

Co

mp

on

ent

f, l

bm

ol/

h

z i

Ki

Hyd

rogen

2

,00

0

0.4

34

8

80

Met

han

e 2

,00

0

0.4

34

8

10

Ben

zen

e

50

0

0.1

08

7

0.0

10

To

luen

e

10

0

0.0

21

7

0.0

04

On

e m

eth

od

fo

r so

lvin

g E

q.

(1)

is t

o u

se a

sp

read

shee

t to

mak

e a

plo

t o

f f{

Ψ} v

s. Ψ

in

incr

emen

ts o

f 0

.1 f

rom

0.0

to

1.0

. T

hen

, u

se s

mal

ler

incr

emen

ts i

n Ψ

in

th

e v

icin

ity o

f f

}=

0

to o

bta

in t

he

solu

tio

n.

Th

e re

sult

s ar

e sh

ow

n i

n t

he

two

fig

ure

s o

n t

he

nex

t p

age.

T

he

con

ver

ged

solu

tio

n i

s

Ψ =

0.8

69

7.

Th

eref

ore

, V

= 0

.86

97

(4,6

00

) =

4,0

00

.6 l

bm

ol/

h.

Th

e co

mp

osi

tio

n o

f th

e

equ

ilib

riu

m v

apo

r fr

om

Eq

. (2

) is

as

foll

ow

s:

Co

mp

on

ent

z i

y i

xi

Hyd

rogen

0

.43

48

0

.49

90

0

.00

62

Met

han

e 0

.43

48

0

.49

25

0

.04

93

Ben

zen

e 0

.10

87

0

.00

78

0

.78

20

To

luen

e 0

.02

17

0

.00

07

0

.16

25

Page 21: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 4

.24

(c

on

tin

ued

)

A

na

lysi

s:

(a)

(c

on

tin

ued

)

Ex

erci

se 4

.24

(c

on

tin

ued

)

A

na

lysi

s:

(b)

Wh

en t

he

flas

h c

on

dit

ion

s o

f te

mp

erat

ure

an

d p

ress

ure

are

fix

ed,

the

com

po

siti

on

s o

f th

e

equ

ilib

riu

m v

apo

r an

d l

iqu

id a

re i

nd

epen

den

t o

f an

y r

ecycl

e o

f eq

uil

ibri

um

liq

uid

or

vap

or.

T

o

pro

ve

this

, d

raw

a m

ater

ial

bal

ance

en

vel

op

e ar

ou

nd

th

e sy

stem

in

Fig

. 4

.38

as

sho

wn

bel

ow

.

No

w,

the

flas

h e

qu

atio

ns

are

the

sam

e as

in

Tab

le 4

.3,

exce

pt

for

the

ener

gy b

alan

ce,

Eq

. (6

).

Bu

t, t

hat

eq

uat

ion

is

on

ly s

olv

ed a

fter

all

of

the

oth

er e

qu

atio

ns

are

solv

ed.

Th

us,

th

e re

sult

s fo

r

the

com

po

siti

on

s o

f th

e n

et v

apo

r an

d l

iqu

id p

rod

uct

s ar

e th

e sa

me

as w

hen

th

ere

is n

o r

ecycl

e.

Page 22: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 4

.25

S

ub

ject

:

Par

tial

co

nd

ensa

tio

n o

f a

gas

mix

ture

at

12

0oF

an

d 3

00

psi

a.

Giv

en:

G

as a

t 3

92

oF

an

d 3

15

psi

a, w

ith

a c

om

po

siti

on

in

km

ol/

h o

f 7

2.5

3 N

2,

7.9

8 H

2,

0.1

3

ben

zen

e, a

nd

15

0 c

ycl

oh

exan

e.

Th

e gas

is

coo

led

an

d p

arti

al c

on

den

sed

to

12

0oF

an

d 3

00

psi

a,

foll

ow

ed b

y p

has

e se

par

atio

n.

Fin

d:

E

qu

ilib

riu

m v

apo

r an

d l

iqu

id f

low

rat

es a

nd

co

mp

osi

tio

ns.

An

aly

sis:

T

he

flas

h c

alcu

lati

on

s ar

e m

ade

con

ven

ien

tly w

ith

a p

roce

ss s

imu

lato

r, u

sin

g a

n

app

rop

riat

e K

-val

ue

corr

elat

ion

. T

he

foll

ow

ing r

esu

lts

wer

e o

bta

ined

wit

h C

HE

MC

AD

, u

sin

g

the

Ch

ao-S

ead

er,

Gra

yso

n-S

tree

d (

CS

GS

) m

eth

od

fo

r K

-val

ues

.

Co

mp

on

ent

CS

GS

K

i f i

, k

mo

l/h

υ υυυ

i , k

mo

l/h

l i

, k

mo

l/h

Hyd

rogen

7

9.7

72

.53

7

0.8

2

1.7

1

Nit

rogen

7

.54

7

.98

6.3

6

1.6

2

Ben

zen

e 0

.02

4

0.1

3

0

.00

16

0

.12

84

Cycl

oh

exan

e 0

.02

2

15

0.0

0

1

.67

1

48

.33

Ex

erci

se 4

.26

S

ub

ject

:

Rap

id d

eter

min

atio

n o

f p

has

e co

nd

itio

n w

ith

ou

t m

akin

g a

fla

sh c

alcu

lati

on

.

Giv

en:

A

hyd

roca

rbo

n m

ixtu

re a

t 2

00

oF

an

d 2

00

psi

a, w

ith

a c

om

po

siti

on

in

lb

mo

l/h

of

12

5 C

3,

20

0 n

C4,

and

17

5 n

C5,

and

K-v

alu

es a

t th

ese

con

dit

ion

s.

Fin

d:

Ph

ase(

s) p

rese

nt

wit

ho

ut

mak

ing a

fla

sh c

on

dit

ion

.

An

aly

sis:

F

rom

Eq

. (4

-12

), h

ave

a su

bco

ole

d l

iqu

id i

f

zK

ii

iC

<=�

11

.

F

rom

Eq

. (4

-13

), h

ave

a su

per

hea

ted

vap

or

if

z K

i iiC

<=�

11

.

Co

mp

on

ent

f i

z i

Ki

z iK

i z i

/Ki

C3

12

5

0.2

5

2.0

56

0

.51

4

0.1

22

nC

4

20

0

0.4

0

0.9

25

0

.37

0

0.4

32

nC

5

17

5

0.3

5

0.5

20

0

.18

2

0.6

73

T

ota

l:

50

0

1.0

0

1

.06

6 >

1

1.2

27

> 1

Th

eref

ore

str

eam

is

par

tial

ly v

apo

rize

d.

Bo

th v

apo

r an

d l

iqu

id p

has

es p

rese

nt.

Ex

erci

se 4

.27

S

ub

ject

:

Det

erm

inat

ion

of

refl

ux

-dru

m p

ress

ure

fo

r a

spec

ifie

d t

emp

erat

ure

an

d t

ota

l d

isti

llat

e

(vap

or

and

liq

uid

ph

ases

) co

mp

osi

tio

n

Giv

en:

O

ver

hea

d p

arti

al c

on

den

sin

g s

yst

em o

f a

dis

till

atio

n c

olu

mn

th

at p

rod

uce

s v

apo

r

dis

till

ate,

liq

uid

dis

till

ate,

an

d l

iqu

id r

eflu

x.

Of

the

tota

l d

isti

llat

e, 1

0 m

ol%

is

vap

or.

R

eflu

x

dru

m t

emp

erat

ure

is

10

0oF

, an

d c

om

po

siti

on

of

tota

l d

isti

llat

e in

mo

le f

ract

ion

s is

0.1

0 C

2,

0.2

0

C3,

and

0.7

0 n

C4.

Ref

lux

pre

ssu

re i

s n

ot

giv

en,

bu

t K

-val

ues

at

10

0oF

an

d 2

00

psi

a ar

e giv

en.

Ass

um

pti

on

s:

K-v

alu

es a

re i

nv

erse

ly p

rop

ort

ion

al t

o p

ress

ure

.

Fin

d:

Pre

ssu

re i

n t

he

refl

ux

dru

m.

An

aly

sis:

A

s sh

ow

n i

n E

xer

cise

4.2

4,

the

com

po

siti

on

s o

f n

et e

qu

ilib

riu

m v

apo

r an

d l

iqu

id a

re

ind

epen

den

t o

f re

cycl

e o

r, i

n t

his

cas

e, r

eflu

x.

Th

eref

ore

, th

e fl

ash

eq

uat

ion

s ca

n b

e ap

pli

ed

usi

ng t

he

tota

l d

isti

llat

e co

mp

osi

tio

n a

s th

e fe

ed c

om

po

siti

on

. T

her

efo

re,

Ψ =

V/F

= 0

.10

. T

he

K-

val

ues

are

giv

en b

y:

KP

KP

KP

CC

nC

23

42

.72

00

,

,

=� ���

=� ���

=� ���

09

52

00

03

42

00

..

Su

bst

itu

tin

g t

hes

e eq

uat

ion

s in

to E

q.

(3),

Tab

le 4

.4,

fP

P

P

P

P

P

P

{}

..

..

..

..

..

..

=

−� ���

� ��� ��

+� ��� −

� ��� ��+

−� ���

� ��� ��

+� ��� −

� ��� ��+

−� ���

� ��� ��

+� ��� −

� ��� ��=

01

12

72

00

10

12

72

00

1

01

10

95

20

0

10

10

95

20

01

01

10

34

20

0

10

10

34

20

01

0

(1)

Eq

. (1

) is

a n

on

lin

ear

equ

atio

n t

hat

can

be

solv

ed b

y v

ario

us

mea

ns.

U

sin

g a

sp

read

shee

t, i

n a

man

ner

sim

ilar

to

th

at u

sed

to

so

lve

Ex

erci

se 4

.24

, w

e o

bta

in P

= 1

26

psi

a.

Page 23: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 4

.28

S

ub

ject

:

Co

mp

aris

on

of

flas

h c

alcu

lati

on

s u

sin

g t

hre

e d

iffe

ren

t K

-val

ue

corr

elat

ion

s.

Giv

en:

A

str

eam

at

7.2

oC

an

d 2

,62

0 k

Pa

wit

h t

he

ov

eral

l co

mp

osi

tio

n g

iven

bel

ow

.

Fin

d:

Ph

ase

con

dit

ion

s

An

aly

sis:

U

sin

g t

he

CH

EM

CA

D p

roce

ss s

imu

lato

r, t

he

foll

ow

ing r

esu

lts

are

ob

tain

ed u

sin

g t

he

So

ave-

Red

lich

-Kw

on

g (

SR

K),

Pen

g-R

ob

inso

n (

PR

), a

nd

Ben

edic

t-W

ebb

-Ru

bin

-Sta

rlin

g

(BW

RS

) co

rrel

atio

ns:

K-v

alu

es:

Co

mp

on

ent

SR

K

PR

B

WR

S

N2

17

.5

17

.6

16

.3

C1

5.7

3

5.7

1

6.0

0

C2

1.0

7

1.1

2

0.9

9

C3

0

.32

7

0

.33

7

0

.29

2

nC

4

0

.09

8

0

.10

2

0

.08

7

nC

5

0

.03

6

0

.03

2

0

.02

9

nC

6

0.0

09

6

0.0

11

0

0.0

07

1

Th

e K

-val

ues

fo

r th

e S

RK

an

d P

R c

orr

elat

ion

s ar

e in

rea

son

ably

go

od

agre

emen

t, d

evia

tin

g f

rom

each

oth

er b

y l

ess

than

15

%.

Ex

cep

t fo

r C

1,

the

BW

RS

co

rrel

atio

n p

red

icts

lo

wer

val

ues

, w

ith

the

big

ges

t d

evia

tio

n f

or

nC

6.

Pro

du

ct c

om

po

siti

on

s:

S

RK

:

PR

:

B

WR

:

Co

mp

on

en

t

f, k

mo

l/h

υ υυυ

,

km

ol/

h

l, k

mo

l/h

υ υυυ

,

km

ol/

h

l, k

mo

l/h

υ υυυ

,

km

ol/

h

l, k

mo

l/h

N2

1.0

0.7

0

0.3

0

0

.69

0

.31

0.6

7

0.3

3

C1

12

4.0

5

2.9

2

7

1.0

8

52

.06

71

.94

5

3.0

4

7

0.9

6

C2

8

7.6

1

1.1

3

7

6.4

6

10

.45

77

.15

9.6

3

7

7.9

7

C3

16

1.6

6.8

1

15

4.7

9

6

.42

1

55

.18

5.6

7

15

5.9

3

nC

4

17

6.2

2.3

1

17

3.8

9

2

.16

1

74

.04

1.8

8

17

4.3

2

nC

5

5

8.5

0.2

5

5

8.2

5

0

.26

58

.24

0.2

1

5

8.2

9

nC

6

3

3.7

0.0

5

3

3.6

5

0

.04

33

.66

0.0

3

3

3.6

7

To

tal:

6

42

.60

7

4.1

7

56

8.4

3

72

.08

5

70

.52

7

1.1

3

57

1.4

7

All

th

ree

corr

elat

ion

s p

red

ict

abo

ut

the

sam

e V

/F r

atio

, w

hic

h r

anges

fro

m 0

.11

07

to

0.1

15

4.

Ex

erci

se 4

.29

S

ub

ject

:

Eq

uil

ibri

um

fla

sh c

alcu

lati

on

s at

dif

fere

nt

tem

per

atu

res

and

pre

ssu

res

Giv

en:

M

ixtu

re o

f 1

00

km

ol

of

60

mo

l% b

enze

ne

(A),

25

mo

l% t

olu

ene

(B),

an

d 1

5 m

ol%

o-

xyle

ne

(C).

S

ou

rces

of

vap

or

pre

ssu

re d

ata.

Ass

um

pti

on

s:

Idea

l so

luti

on

s u

sin

g v

apo

r p

ress

ure

wit

h R

aou

lt's

law

.

Fin

d:

Am

ou

nts

an

d c

om

po

siti

on

s o

f v

apo

r an

d l

iqu

id p

rod

uct

s at

:

(a

) 1

00

oC

an

d 1

atm

.

(b

) 1

00

oC

an

d 2

atm

.

(c

) 1

05

oC

an

d 0

.1 a

tm.

(d

) 1

50

oC

an

d 1

atm

.

An

aly

sis:

I

nst

ead

of

Fig

ure

2.4

fo

r th

e v

apo

r p

ress

ure

s o

f b

enze

ne

and

to

luen

e an

d t

hre

e v

apo

r-

pre

ssu

re d

ata

po

ints

fo

r o

-xyle

ne,

use

th

e b

uil

t-in

vap

or

pre

ssu

re d

ata

in t

he

CH

EM

CA

D p

roce

ss

sim

ula

tor

wit

h i

dea

l K

-val

ues

. T

he

resu

lts

are

as f

oll

ow

s:

Ca

se

(a)

10

0oC

,

1 a

tm

(b)

10

0oC

,

2 a

tm.

(c)1

05

oC

,

0.1

atm

.

(d)

15

0oC

,

1 a

tm

Vap

or,

km

ol

67

.64

0

1

00

1

00

Liq

uid

, k

mo

l 3

2.3

6

10

0

0

0

Vap

or

mo

l fr

ac:

Ben

zen

e 0

.69

8

0

.60

0

.60

To

luen

e 0

.22

4

0

.25

0

.25

o

-Xyle

ne

0.0

78

0.1

5

0.1

5

Liq

uid

mo

l fr

ac:

Ben

zen

e 0

.39

5

0.6

0

To

luen

e 0

.30

5

0.2

5

o

-Xyle

ne

0.3

00

0

.15

On

ly i

n t

he

Cas

e (a

), a

re t

wo

ph

ases

fo

rmed

. A

t 1

atm

, th

e b

ub

ble

po

int

is 9

1.3

oC

an

d t

he

dew

po

int

is 1

07

.5oC

.

Page 24: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 4

.30

S

ub

ject

:

Pro

ve

that

, at

eq

uil

ibri

um

, v

apo

r is

at

its

dew

po

int

and

liq

uid

is

at i

ts b

ub

ble

po

int.

An

aly

sis:

A

fter

eq

uil

ibri

um

is

ach

iev

ed,

sep

arat

e th

e v

apo

r fr

om

th

e li

qu

id a

nd

an

alyze

the

sep

arat

e p

has

es.

Fo

r th

e li

qu

id:

Ap

ply

Eq

. (5

), T

able

4.4

,

xz K

ii

i

=+

−1

1��

(1

)

At

the

bu

bb

le p

oin

t, Ψ

= V

/F =

0 a

nd

, th

eref

ore

, fr

om

Eq

. (1

),

x i =

zi .

A

lso

, th

en,

Ki x

i = K

i zi

= y

i an

d,

ther

efo

re,

Kx

Kz

yi

i

iC

ii

iC

i

iC

==

==

==

��

�1

11

1,

wh

ich

is

the

bu

bb

le-p

oin

t eq

uat

ion

, E

q.

(4-1

2).

Fo

r th

e v

apo

r:

Ap

ply

Eq

. (6

), T

able

4.4

,

y

Kz K

ii

i i

=+

−1

1��

(2

)

At

the

dew

po

int,

Ψ =

V/F

= 1

an

d,

ther

efo

re,

fro

m E

q.

(2),

y i

= z

i .

Als

o,

then

, x i

= y

i /K

i =

zi /

Ki

and

, th

eref

ore

, y K

z Kx

i iiC

i iiC

i

iC

==

==

==

��

�1

11

1,

wh

ich

is

the

bu

bb

le-p

oin

t eq

uat

ion

, E

q.

(4-1

2).

Ex

erci

se 4

.31

S

ub

ject

:

Bu

bb

le-p

oin

t te

mp

erat

ure

of

feed

to

a d

isti

llat

ion

co

lum

n.

Giv

en:

Fee

d a

t 1

.72

MP

a (2

50

psi

a) w

ith

a c

om

po

siti

on

in

km

ol/

h b

elo

w.

K-v

alu

es i

n F

ig.

2.8

.

Fin

d:

Bu

bb

le-p

oin

t te

mp

erat

ure

.

An

aly

sis:

I

tera

te o

n t

emp

erat

ure

un

til

the

bu

bb

le-p

oin

t eq

uat

ion

, E

q.

(4-1

2),

is

sati

sfie

d,

Kz

ii

iC

==�

11

(1

)

Fo

r th

e fi

rst

gu

ess,

tak

e th

e te

mp

erat

ure

th

at g

ives

th

e K

-val

ue

for

nC

4 =

1.0

, th

at i

s 2

25

oF

. T

his

resu

lt a

nd

on

e fo

r 2

00

oF

is

as f

oll

ow

s:

T

= 2

25

oF

T

= 2

00

oF

Co

mp

on

ent

f i ,

km

ol/

h

z i

Ki

Kiz

i K

i K

izi

C2

1.5

0

.03

4

.8

0.1

44

4

.3

0.1

29

C3

10

.0

0.2

0

2.1

0

.42

0

1.9

0

.38

0

nC

4

18

.5

0.3

6

1.0

0

.36

0

0.8

1

0.2

92

nC

5

17

.5

0.3

4

0.4

4

0.1

50

0

.34

0

.11

6

nC

6

3.5

0

.07

0

.21

0

.01

5

0.1

5

0.0

11

Su

m:

51

.0

1.0

0

1

.08

9

0

.92

8

By l

inea

r in

terp

ola

tio

n,

T =

21

1oF

fo

r E

q.

(1)

to b

e sa

tisf

ied

.

Ex

erci

se 4

.32

S

ub

ject

:

Bu

bb

le a

nd

dew

po

int

pre

ssu

res

of

bin

ary m

ixtu

re a

t co

nst

ant

tem

per

atu

re.

Giv

en:

M

ixtu

re o

f 5

0 m

ol%

ben

zen

e (A

) an

d 5

0 m

ol%

to

luen

e (B

) at

90

oC

(1

94

oF

).

Vap

or

pre

ssu

res

fro

m F

ig.

2.4

(1

9.5

psi

a fo

r A

an

d 7

.9 p

sia

for

B).

Ass

um

pti

on

s:

Rao

ult

's l

aw f

or

K-v

alu

es.

Fin

d:

B

ub

ble

an

d d

ew p

oin

t p

ress

ure

s.

An

aly

sis:

S

ub

stit

uti

on

of

Rao

ult

's l

aw,

Eq

. (3

) in

Tab

le 2

.3,

into

Eq

s. (

4-1

2)

and

(4

-13

) fo

r th

e

bu

bb

le a

nd

dew

po

ints

, re

spec

tiv

ely,

giv

es,

Bu

bb

le p

oin

t:

K

zP

z

PP

zP

ii

iC

i

s

i

iC

is

i=

==

==

��

�1

1

10.

or

i=

1

C

(1

)

Dew

po

int:

z K

zP

P

z PP

i iiC

i i

s

iC

i is=

==

==

��

�1

1

10

1.

o

r

i=1

C

(2

)

Eq

. (1

) giv

es 1

3.7

0 p

sia

for

the

bu

bb

le p

oin

t.

E

q.

(2)

giv

es 1

5.8

psi

a fo

r th

e d

ew p

oin

t.

Page 25: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 4

.33

S

ub

ject

:

Bu

bb

le p

oin

t, d

ew p

oin

t, a

nd

fla

sh o

f a

wat

er (

W)

- ac

etic

aci

d (

A)

mix

ture

.

Giv

en:

E

qu

imo

lar

mix

ture

of

W a

nd

A a

t 1

atm

. C

orr

elat

ion

s o

f li

qu

id-p

has

e ac

tiv

ity

coef

fici

ents

fo

r W

an

d A

as

a fu

nct

ion

of

liq

uid

-ph

ase

mo

le f

ract

ion

s an

d t

emp

erat

ure

:

Ass

um

pti

on

s:

Mo

dif

ied

Rao

ult

's l

aw,

Eq

. (4

), T

able

2.3

ap

pli

es.

Fin

d:

Dew

po

int,

bu

bb

le

po

int,

an

d e

qu

ilib

riu

m v

apo

r an

d l

iqu

id a

t a

tem

per

atu

re h

alfw

ay

bet

wee

n t

he

bu

bb

le a

nd

dew

po

ints

.

An

aly

sis:

Th

e R

ach

ford

-Ric

e fl

ash

eq

uat

ion

s ca

n b

e u

sed

fro

m T

able

4.4

:

fz

K

K

ii

iiC

{}

ΨΨ

=−

+−

==�

1

11

01

��

��

(1

)

yz

K Ki

ii i

=+

−1

1��

(2

)

xz K

ii

i

=+

−1

1��

(3

)

wh

ere,

zW

= 0

.5 a

nd

zA =

0.5

an

d t

he

mo

dif

ied

Rao

ult

's l

aw i

s:

KP P

iiL

is

(4

)

An

toin

e v

apo

r p

ress

ure

eq

uat

ion

s ar

e giv

en i

n P

erry

's H

and

bo

ok

fo

r w

ater

an

d a

ceti

c ac

id:

log

..

()

.

log

..

()

.

PT

C

PT

C

s

o

s

o

W A

(5

)

(6

)

=−

+

=−

+

80

71

31

17

30

63

23

34

26

80

21

00

19

36

01

25

84

51

Th

e eq

uat

ion

s fo

r th

e li

qu

id-p

has

e ac

tiv

ity c

oef

fici

ents

, giv

en i

n t

he

Ch

emic

al E

ngin

eeri

ng

Sci

ence

art

icle

of

19

67

by S

ebas

tian

i an

d L

acq

uan

iti,

are

in

corr

ect.

T

hey a

re o

f th

e R

edli

ch-

Kis

ter

form

(se

e W

alas

, S

. M

., "

Ph

ase

Eq

uil

ibri

a in

Ch

emic

al E

ngin

eeri

ng

", B

utt

erw

ort

h,

19

85

,

pag

e 1

84

) an

d s

ho

uld

be:

log

log

γ γ

WA

WW

AW

AW

WW

AW

(7

)

(8

)

=+

−+

−−

=+

−+

−−

xB

Cx

Cx

xx

xB

Cx

Cx

xx

2 2

41

61

43

65

���

���

���

���

Ex

erci

se 4

.33

(c

on

tin

ued

)

A

na

lysi

s:

(co

nti

nu

ed)

wh

ere,

K)

(9

)

K)

(1

0)

(11

)

AT

BT

C

=+

=−

=

01

18

26

42

4

01

73

54

32

7

01

08

1

.. (

.. (

.

Sin

ce P

= 1

atm

an

d t

he

no

rmal

bo

ilin

g p

oin

ts o

f w

ater

an

d a

ceti

c ac

id a

re 1

00

oC

an

d 1

18

.1oC

,

resp

ecti

vel

y,

it m

igh

t b

e ex

pec

ted

th

at t

he

dew

an

d b

ub

ble

po

int

of

the

mix

ture

wo

uld

be

in t

he

vic

init

y o

f 1

00

oC

, u

nle

ss t

he

liq

uid

-ph

ase

acti

vit

y c

oef

fici

ents

are

mu

ch d

iffe

ren

t fr

om

1.

To

chec

k t

his

, a

ctiv

ity c

oef

fici

ents

are

co

mp

ute

d f

rom

Eq

s. (

7)

and

(8

) w

ith

a s

pre

ad s

hee

t at

10

0oC

,

wit

h t

he

foll

ow

ing r

esu

lt a

s a

plo

t.

It i

s se

en t

hat

in

th

e v

icin

ity o

f m

ole

fra

ctio

ns

equ

al t

o 0

.5,

the

coef

fici

ents

are

no

t la

rge,

bu

t ar

e ab

ou

t 1

.2.

Page 26: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 4

.33

(c

on

tin

ued

)

A

na

lysi

s:

(co

nti

nu

ed)

A

t th

e b

ub

ble

po

int,

Ψ =

V/F

= 0

, an

d E

q.

(1),

co

mb

ined

wit

h (

4),

bec

om

es:

fT

zP

T

Pz

PT

P

ss

{}

{}

{}

=−� ��

� +−� ��

� =

WW

WA

AA

(1

2)

11

γ

Als

o,

at t

he

bu

bb

le p

oin

t, x

i = z

i = 0

.5.

Th

en,

the

on

ly u

nk

no

wn

in

Eq

. (1

2)

is T

.

So

lvin

g n

on

lin

ear

Eq

. (1

2),

wit

h E

qs.

(5

) to

(1

1),

by t

rial

an

d e

rro

r w

ith

a s

pre

adsh

eet,

sta

rtin

g

fro

m a

gu

ess

of

T =

10

0oC

, q

uic

kly

lea

ds

to a

bu

bb

le-p

oin

t te

mp

erat

ure

of

10

1.6

oC

. T

he

com

po

siti

on

of

the

vap

or

bu

bb

le i

s o

bta

ined

fro

m E

q.

(2),

wh

ich

at

the

bu

bb

le p

oin

t re

du

ces

to y

i

= x

iKi =

ziK

i..

Th

e K

-val

ues

at

the

bu

bb

le p

oin

t ar

e co

mp

ute

d t

o b

e K

W =

1.3

64

an

d K

A =

0.6

36

,

giv

ing y

W =

0.6

82

an

d y

A =

0.3

18

.

At

the

dew

po

int,

Ψ =

V/F

=1

, an

d E

q.

(1),

co

mb

ined

wit

h (

4),

bec

om

es:

f{x

W,

xW

, T

} =

zP

xx

TP

Tz

P

xx

TP

Ts

sW

WW

AW

A

AW

AA

γγ

{,

,}

{}

{,

,}

{}

−� ��

� +−

� ���

=1

10

wh

ere

bec

ause

yi =

zi =

0.5

, T

, x

W ,

an

d x

A =

(1

- x

W)

are

left

as

un

kn

ow

ns.

T

he

liq

uid

ph

ase

mo

le f

ract

ion

s ar

e fr

om

Eq

. (3

), x

i =

zi /

Ki .

So

lvin

g t

hes

e eq

uat

ion

s b

y t

rial

an

d e

rro

r w

ith

a

spre

ad s

hee

t, s

tart

ing f

rom

T =

10

5oC

, x W

= 0

.4 a

nd

xA =

0.6

, q

uic

kly

lea

ds

to a

dew

-po

int

tem

per

atu

re o

f 1

05

.8oC

. T

he

K-v

alu

es a

t th

e d

ew p

oin

t ar

e co

mp

ute

d t

o b

e K

W =

1.5

78

an

d K

A =

0.7

32

, w

ith

xW

= 0

.31

69

an

d x

A =

0.6

83

2.

Th

e eq

uil

ibri

um

fla

sh c

alcu

lati

on

is

carr

ied

ou

t at

T =

(1

01

.6 +

10

5.8

)/2

= 1

03

.7oC

. I

n

this

cas

e, t

he

val

ues

of

Ψ,

x W,

and

xA

are

co

mp

ute

d f

rom

Eq

s. (

1)

and

(3

), w

her

e th

e v

apo

r

pre

ssu

res

are

com

pu

ted

fro

m E

qs.

(5

) an

d (

6)

to b

e 8

67

to

rr f

or

W a

nd

47

3 f

or

A.

Val

ues

of

yW

and

yA a

re o

bta

ined

fro

m E

q.

(2).

U

sin

g,

agai

n,

a sp

read

shee

t w

ith

a t

rial

an

d e

rro

r p

roce

du

re,

the

foll

ow

ing r

esu

lt i

s q

uic

kly

ob

tain

ed:

V/F

= 0

.49

x W

= 0

.41

00

x

A =

0.5

90

0

y W =

0.5

93

7

yA =

0.4

06

3

Ex

erci

se 4

.34

S

ub

ject

:

Bu

bb

le p

oin

t, d

ew p

oin

t, a

nd

fla

sh o

f a

tolu

ene

(1)

- n

-bu

tan

ol

(2)

mix

ture

.

Giv

en:

F

eed

of

z 1 =

0.4

an

d z

2 =

0.6

at

1 a

tm.

Liq

uid

-ph

ase

acti

vit

y c

oef

fici

ents

fo

r 1

an

d 2

as

a

fun

ctio

n o

f li

qu

id-p

has

e m

ole

fra

ctio

ns

fro

m t

he

van

Laa

r eq

uat

ion

s.

Ass

um

pti

on

s:

Mo

dif

ied

Rao

ult

's l

aw,

Eq

. (2

-72

) ap

pli

es.

Fin

d:

Dew

po

int,

bu

bb

le

po

int,

an

d e

qu

ilib

riu

m v

apo

r an

d l

iqu

id a

t a

tem

per

atu

re h

alfw

ay

bet

wee

n t

he

bu

bb

le a

nd

dew

po

ints

.

An

aly

sis:

Th

e R

ach

ford

-Ric

e fl

ash

eq

uat

ion

s ca

n b

e u

sed

fro

m T

able

4.4

:

fz

K

K

ii

iiC

{}

ΨΨ

=−

+−

==�

1

11

01

��

��

(1

)

yz

K Ki

ii i

=+

−1

1��

(2

)

xz K

ii

i

=+

−1

1��

(3

)

Th

e m

od

ifie

d R

aou

lt's

law

is:

KP P

iiL

is

(4

)

An

toin

e v

apo

r p

ress

ure

(in

to

rr)

equ

atio

ns

are

ob

tain

ed b

y f

itti

ng t

he

vap

or

pre

ssu

re d

ata

for

tolu

ene

that

are

giv

en i

n E

xer

cise

4.8

an

d f

rom

Per

ry's

Han

db

oo

k f

or

n-b

uta

no

l:

PT

C

PT

C

s

o

s

o

1

2

(5

)

(6

)

=−

+

� ��� ��

=−

+

exp

..

()

.

log

..

()

.

17

27

41

38

96

3

25

56

7

73

63

66

13

05

19

8

17

34

27

Th

e v

an L

aar

equ

atio

ns,

Tab

le 2

.9,

wit

h t

he

giv

en c

on

stan

ts a

re:

ln. . .

ln. . .

γ γ

1 2

(7

)

(8

)

=

+� ��

� ��

=

+� ��

� ��

08

55

10

85

5

13

06

13

06

11

30

6

08

55

1 2 2 1

x x x x

Page 27: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 4

.34

(c

on

tin

ued

)

A

na

lysi

s:

(co

nti

nu

ed)

Sin

ce P

= 1

atm

an

d t

he

no

rmal

bo

ilin

g p

oin

ts o

f to

luen

e an

d n

-bu

tan

ol

are

11

0.8

oC

an

d

11

7oC

, re

spec

tiv

ely,

it m

igh

t b

e ex

pec

ted

th

at t

he

dew

an

d b

ub

ble

po

int

of

the

mix

ture

wo

uld

be

in t

he

vic

init

y o

f 1

10

oC

, u

nle

ss t

he

liq

uid

-ph

ase

acti

vit

y c

oef

fici

ents

are

mu

ch d

iffe

ren

t fr

om

1.

To

ch

eck

th

is,

act

ivit

y c

oef

fici

ents

are

co

mp

ute

d f

rom

Eq

s. (

7)

and

(8

), w

ith

a s

pre

ad s

hee

t, w

ith

the

foll

ow

ing r

esu

lt a

s a

plo

t.

It i

s se

en t

hat

in

th

e v

icin

ity o

f m

ole

fra

ctio

ns

equ

al t

o 0

.5,

the

coef

fici

ents

are

no

t la

rge,

bu

t ar

e ab

ou

t 1

.3.

At

the

bu

bb

le p

oin

t, Ψ

= V

/F =

0,

and

Eq

. (1

), c

om

bin

ed w

ith

(4

), b

eco

mes

:

fT

zP

T

Pz

PT

P

ss

{}

{}

{}

=−� ��

� +−� ��

� =

11

12

22

(9

)1

10

γγ

Ex

erci

se 4

.34

(c

on

tin

ued

)

An

aly

sis:

(

con

tin

ued

)

Als

o,

at t

he

bu

bb

le p

oin

t, x

1 =

z1 =

0.4

an

d x

2 =

z2 =

0.6

. T

hen

, th

e o

nly

un

kn

ow

n i

n E

q.

(9)

is T

. S

olv

ing n

on

lin

ear

Eq

. (9

), b

y t

rial

an

d e

rro

r w

ith

a s

pre

adsh

eet,

sta

rtin

g f

rom

a g

ues

s o

f

T =

10

0oC

, q

uic

kly

lea

ds

to a

bu

bb

le-p

oin

t te

mp

erat

ure

of

10

6.9

oC

. T

he

com

po

siti

on

of

the

vap

or

bu

bb

le i

s o

bta

ined

fro

m E

q.

(2),

wh

ich

at

the

bu

bb

le p

oin

t re

du

ces

to y

i = x

iKi =

ziK

i..

Th

e

K-v

alu

es a

t th

e b

ub

ble

po

int

are

com

pu

ted

to

be

K1 =

1.3

63

an

d K

2 =

0.7

58

, giv

ing y

1 =

0.5

45

and

y2 =

0.4

55

.

At

the

dew

po

int,

Ψ =

V/F

=1

, an

d E

q.

(1),

co

mb

ined

wit

h (

4),

bec

om

es:

f{x 1

, x 2

, T

} =

zP

xx

PT

zP

xx

PT

ss

1

11

21

2

21

22

γγ

{,

}{

}{

,}

{}

−� ��

� +−

� ���

=1

10

wh

ere

bec

ause

y1 =

z1 =

0.4

an

d y

2 =

z2 =

0.6

, x 1

, a

nd

x2 =

(1 -

x1)

are

left

as

un

kn

ow

ns.

T

he

liq

uid

ph

ase

mo

le f

ract

ion

s ar

e fr

om

Eq

. (3

), x

i =

zi /

Ki .

So

lvin

g t

hes

e eq

uat

ion

s b

y t

rial

an

d

erro

r w

ith

a s

pre

ad s

hee

t, s

tart

ing f

rom

T =

10

5oC

, x 1

= 0

.2 a

nd

x2 =

0.8

, q

uic

kly

lea

ds

to a

dew

-

po

int

tem

per

atu

re o

f 1

09

.7oC

. T

he

K-v

alu

es a

t th

e d

ew p

oin

t ar

e co

mp

ute

d t

o b

e K

1 =

1.7

93

an

d

K2 =

0.7

72

, w

ith

x1 =

0.2

23

1 a

nd

x2 =

0.7

76

9.

Th

e eq

uil

ibri

um

fla

sh c

alcu

lati

on

is

carr

ied

ou

t at

T =

(1

09

.7 +

10

6.9

)/2

= 1

08

.3oC

. I

n

this

cas

e, t

he

val

ues

of

Ψ,

x 1,

and

x2

are

co

mp

ute

d f

rom

Eq

s. (

1)

and

(3

), w

her

e th

e v

apo

r

pre

ssu

res

are

com

pu

ted

fro

m E

qs.

(5

) an

d (

6)

to b

e 7

14

to

rr f

or

1 a

nd

53

9 t

orr

fo

r 2

. V

alu

es o

f y 1

and

y2

are

ob

tain

ed f

rom

Eq

. (2

).

Usi

ng,

agai

n,

a sp

read

shee

t w

ith

a t

rial

an

d e

rro

r p

roce

du

re,

the

foll

ow

ing r

esu

lt i

s q

uic

kly

ob

tain

ed:

V/F

= 0

.60

4

x 1 =

0.2

94

9

x 2 =

0.7

05

1

y 1 =

0.4

68

9

y 2 =

0.5

31

1

Page 28: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 4

.35

S

ub

ject

:

Bu

bb

le p

oin

t, d

ew p

oin

t, a

nd

aze

otr

op

e o

f an

eth

yl

acet

ate

(A)

- et

hyl

alco

ho

l (E

)

mix

ture

.

Giv

en:

L

iqu

id m

ixtu

re o

f 8

0 m

ol%

A -

20

mo

l% E

at

10

1.3

kP

a (1

atm

).

Liq

uid

-ph

ase

acti

vit

y

coef

fici

ents

fo

r A

an

d E

as

a fu

nct

ion

of

liq

uid

-ph

ase

mo

le f

ract

ion

s fr

om

th

e v

an L

aar

equ

atio

ns.

Ass

um

pti

on

s:

Mo

dif

ied

Rao

ult

's l

aw,

Eq

. (2

-72

) ap

pli

es.

Fin

d:

(a)

Bu

bb

le-p

oin

t te

mp

erat

ure

an

d v

apo

r co

mp

osi

tio

n.

(b

) D

ew p

oin

t.

(c)

Tem

per

atu

re

and

co

mp

osi

tio

n o

f p

oss

ible

aze

otr

op

e.

An

aly

sis:

Th

e R

ach

ford

-Ric

e fl

ash

eq

uat

ion

s ca

n b

e u

sed

fro

m T

able

4.4

:

fz

K

K

ii

iiC

{}

ΨΨ

=−

+−

==�

1

11

01

��

��

(1

)

yz

K Ki

ii i

=+

−1

1��

(2

)

xz K

ii

i

=+

−1

1��

(3

)

Th

e m

od

ifie

d R

aou

lt's

law

fro

m E

q.

(2-7

2)

is:

KP P

iiL

is

(4

)

An

toin

e v

apo

r p

ress

ure

(in

to

rr)

equ

atio

ns

are

ob

tain

ed f

rom

Sec

tio

n 1

3 o

f P

erry

's H

and

bo

ok

:

log

..

()

.

log

..

()

.

PT

C

PT

C

s

o

s

o

A E

(5

)

(6

)

=−

+

=−

+

71

01

79

12

44

95

1

21

78

81

75

86

70

12

81

59

0

19

37

68

Th

e v

an L

aar

equ

atio

ns,

Tab

le 2

.9,

wit

h t

he

giv

en c

on

stan

ts a

re:

ln. . .

ln. . .

γ γ

A

A E

E

E A

(7

)

(8

)

=

+� ��

� ��

=

+� ��

� ��

08

55

10

85

5

07

53

07

53

10

75

3

08

55

x x x x

Ex

erci

se 4

.35

(c

on

tin

ued

)

A

na

lysi

s:

(co

nti

nu

ed)

(a)

Sin

ce P

= 1

atm

an

d t

he

no

rmal

bo

ilin

g p

oin

ts o

f et

hyl

acet

ate

and

eth

yl

alco

ho

l ar

e

77

.1oC

an

d 7

8.4

oC

, re

spec

tiv

ely,

it m

igh

t b

e ex

pec

ted

th

at t

he

bu

bb

le a

nd

dew

po

ints

of

the

mix

ture

wo

uld

be

in t

he

vic

init

y o

f 7

0oC

, u

nle

ss t

he

liq

uid

-ph

ase

acti

vit

y c

oef

fici

ents

are

mu

ch

dif

fere

nt

fro

m 1

. T

o c

hec

k t

his

, a

ctiv

ity c

oef

fici

ents

are

co

mp

ute

d f

rom

Eq

s. (

7)

and

(8

), w

ith

a

spre

ad s

hee

t, w

ith

th

e fo

llo

win

g r

esu

lt a

s a

plo

t.

It i

s se

en t

hat

th

e co

effi

cien

ts a

re n

ot

larg

e, b

ut

are

as h

igh

as

2.3

5.

At

the

bu

bb

le p

oin

t, Ψ

= V

/F =

0,

and

Eq

. (1

), c

om

bin

ed w

ith

(4

), b

eco

mes

:

fT

zP

T

Pz

PT

P

ss

{}

{}

{}

=−� ��

� +−� ��

� =

AA

AE

EE

(9

)1

10

γγ

Page 29: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 4

.35

(c

on

tin

ued

)

An

aly

sis:

(

con

tin

ued

)

Als

o,

at t

he

bu

bb

le p

oin

t, x

A =

zA =

0.8

an

d x

E =

zE =

0.2

. T

hen

, th

e o

nly

un

kn

ow

n i

n E

q.

(9)

is T

. S

olv

ing n

on

lin

ear

Eq

. (9

), b

y t

rial

an

d e

rro

r w

ith

a s

pre

adsh

eet,

sta

rtin

g f

rom

a g

ues

s o

f

T =

70

oC

, q

uic

kly

lea

ds

to a

bu

bb

le-p

oin

t te

mp

erat

ure

of

73

.5oC

. T

he

com

po

siti

on

of

the

vap

or

bu

bb

le i

s o

bta

ined

fro

m E

q.

(2),

wh

ich

at

the

bu

bb

le p

oin

t re

du

ces

to y

i = x

iKi =

ziK

i..

Th

e K

-

val

ues

at

the

bu

bb

le p

oin

t ar

e co

mp

ute

d t

o b

e K

A =

0.9

13

an

d K

E =

1.3

50

, giv

ing

yA =

0.7

30

an

d

y E =

0.2

70

.

(b

) A

t th

e d

ew p

oin

t, Ψ

= V

/F =

1,

and

Eq

. (1

), c

om

bin

ed w

ith

(4

), b

eco

mes

:

f{x A

, x E

, T

} =

zP

xx

PT

zP

xx

PT

ss

A

AA

EA

E

EA

EE

γγ

{,

}{

}{

,}

{}

−� ��

� +−

� ���

=1

10

wh

ere

bec

ause

yA =

zA =

0.8

an

d y

E =

zE =

0.2

, x

A ,

an

d x

E =

(1 -

xA)

are

left

as

un

kn

ow

ns.

T

he

liq

uid

ph

ase

mo

le f

ract

ion

s ar

e fr

om

Eq

. (3

), x

i =

zi /

Ki .

So

lvin

g t

hes

e eq

uat

ion

s b

y t

rial

an

d

erro

r w

ith

a s

pre

ad s

hee

t, s

tart

ing f

rom

T =

70

oC

, x

A =

0.8

an

d x

E =

0.2

, q

uic

kly

lea

ds

to a

dew

-

po

int

tem

per

atu

re o

f 7

4.3

oC

. T

he

K-v

alu

es a

t th

e d

ew p

oin

t ar

e co

mp

ute

d t

o b

e K

A =

0.9

22

an

d

KE =

1.5

08

, w

ith

xA =

0.8

67

4 a

nd

xE =

0.1

32

6.

(c)

To

det

erm

ine

the

exis

ten

ce o

f an

aze

otr

op

e, w

her

e y i

= x

i ,

a se

ries

of

bu

bb

le-p

oin

t

calc

ula

tio

ns

can

be

mad

e, u

sin

g t

he

pro

ced

ure

in

par

t (a

), s

tart

ing f

rom

say,

xA =

0.0

5 i

n

incr

emen

ts o

f 0

.05

. I

f, i

n t

he

ran

ge

of

xA

fro

m 0

.05

to

0.9

5,

the

K-v

alu

e o

f A

sw

itch

es f

rom

mo

re

than

1 t

o l

ess

than

1,

then

an

aze

otr

op

e ex

ists

in

th

is r

ange.

T

he

calc

ula

tio

ns

can

th

en b

e re

fin

ed.

Th

e re

sult

fro

m a

sp

read

shee

t is

a m

inim

um

-bo

ilin

g a

zeo

tro

pe

at 7

2.4

6oC

wit

h a

co

mp

osi

tio

n o

f

54

.4 m

ol%

A a

nd

45

.6 m

ol%

B.

Th

is c

om

par

es t

o e

xp

erim

enta

l v

alu

es f

rom

Per

ry's

Han

db

oo

of

71

.8oC

at

a co

mp

osi

tio

n o

f 5

4 m

ol%

A.

Ex

erci

se 4

.36

S

ub

ject

:

Bu

bb

le p

oin

t, d

ew p

oin

t, a

nd

aze

otr

op

e o

f a

wat

er (

W)

- fo

rmic

aci

d (

F)

mix

ture

.

Giv

en:

L

iqu

id m

ixtu

re o

f 5

0 m

ol%

W -

50

mo

l% F

at

10

7oC

. L

iqu

id-p

has

e ac

tiv

ity

coef

fici

ents

fo

r W

an

d F

as

a fu

nct

ion

of

liq

uid

-ph

ase

mo

le f

ract

ion

s fr

om

th

e v

an L

aar

equ

atio

ns.

Ass

um

pti

on

s:

Mo

dif

ied

Rao

ult

's l

aw,

Eq

. (2

-72

) ap

pli

es.

Fin

d:

(a)

Bu

bb

le-p

oin

t p

ress

ure

. (

b)

Dew

po

int

pre

ssu

re.

(c)

A

zeo

tro

pic

pre

ssu

re a

nd

com

po

siti

on

at

10

7oC

.

An

aly

sis:

Th

e R

ach

ford

-Ric

e fl

ash

eq

uat

ion

s ca

n b

e u

sed

fro

m T

able

4.4

:

fz

K

K

ii

iiC

{}

ΨΨ

=−

+−

==�

1

11

01

��

��

(1

)

yz

K Ki

ii i

=+

−1

1��

(2

)

xz K

ii

i

=+

−1

1��

(3

)

Th

e m

od

ifie

d R

aou

lt's

law

fro

m E

q.

(2-7

2)

is:

KP P

iiL

is

(4

)

An

toin

e v

apo

r p

ress

ure

(in

to

rr)

equ

atio

ns

are

ob

tain

ed f

rom

Sec

tio

n 1

3 o

f P

erry

's H

and

bo

ok

:

log

..

()

.

log

..

()

.

PT

C

PT

C

s

o

s

o

W F

(5

)

(

6)

=−

+

=−

+

80

71

31

17

30

63

0

23

34

26

69

44

59

12

95

26

0

21

80

0

Th

e v

an L

aar

equ

atio

ns,

Tab

le 2

.9,

wit

h t

he

giv

en c

on

stan

ts a

re:

ln.

(.

)

(.

)

ln.

(.

)

(.

)

γ γ

W

A E

F

E A

(7

)

(8

)

=−

+− −

� ��� ��

=−

+− −

� ��� ��

02

93

5

10

29

35

02

75

7

02

75

7

10

27

57

02

93

5

x x x x

Page 30: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 4

.36

(c

on

tin

ued

)

A

na

lysi

s:

(co

nti

nu

ed)

(a)

Sin

ce T

= 1

07

oC

an

d t

he

no

rmal

bo

ilin

g p

oin

ts o

f w

ater

an

d f

orm

ic a

cid

are

10

0oC

and

10

0.8

oC

, re

spec

tiv

ely,

it m

igh

t b

e ex

pec

ted

th

at t

he

bu

bb

le a

nd

dew

po

int

pre

ssu

res

of

the

mix

ture

wo

uld

be

in t

he

vic

init

y o

f 1

atm

, u

nle

ss t

he

liq

uid

-ph

ase

acti

vit

y c

oef

fici

ents

are

mu

ch

dif

fere

nt

fro

m 1

. T

o c

hec

k t

his

, a

ctiv

ity c

oef

fici

ents

are

co

mp

ute

d f

rom

Eq

s. (

7)

and

(8

), w

ith

a

spre

ad s

hee

t, w

ith

th

e fo

llo

win

g r

esu

lt a

s a

plo

t.

It i

s se

en t

hat

th

e co

effi

cien

ts l

ie b

etw

een

0.7

and

1.0

At

the

bu

bb

le p

oin

t, Ψ

= V

/F =

0,

and

Eq

. (1

), c

om

bin

ed w

ith

(4

), b

eco

mes

:

fP

zP

Pz

P

P

ss

{}

{}

{}

=−� ��

� +−� ��

� =W

WW

O

FF

F

OC

C

(

9)

11

07

11

07

γ

Ex

erci

se 4

.36

(c

on

tin

ued

)

An

aly

sis:

(

con

tin

ued

)

Als

o,

at t

he

bu

bb

le p

oin

t, x

W =

zW

= 0

.5 a

nd

xF =

zF =

0.5

. T

hen

, th

e o

nly

un

kn

ow

n i

n E

q.

(9)

is P

. E

qu

atio

n (

9)

is l

inea

r in

P a

nd

, th

us,

can

be

solv

ed d

irec

tly t

o g

ive

a b

ub

ble

-po

int

pre

ssu

re o

f 7

19

to

rr.

Th

e K

-val

ues

at

the

bu

bb

le p

oin

t ar

e 1

.01

5 f

or

W a

nd

0.9

84

. T

he

com

po

siti

on

of

the

vap

or

bu

bb

le i

s o

bta

ined

fro

m E

q.

(2),

wh

ich

at

the

bu

bb

le p

oin

t re

du

ces

to y

i

= x

iKi =

ziK

i .

Th

is g

ives

y W

= 0

.50

8 a

nd

yF =

0.4

92

.

(b

) A

t th

e d

ew p

oin

t, Ψ

= V

/F =

1,

and

Eq

. (1

), c

om

bin

ed w

ith

(4

), b

eco

mes

:

f{x W

, x

F,

P} =

zP

xx

Pz

P

xx

Ps

sW

WW

FW

oF

FW

FF

oC

γ{

,}

{}

{,

}{

}1

07

11

07

10

−� ��

� +−

� ���

=

wh

ere

bec

ause

yW

= z

W =

0.5

an

d y

F =

zF =

0.5

, x

W ,

an

d x

F =

(1 -

xW

) ar

e le

ft a

s u

nk

no

wn

s.

Th

e

liq

uid

ph

ase

mo

le f

ract

ion

s ar

e fr

om

Eq

. (3

), x

i =

zi /

Ki .

So

lvin

g t

hes

e eq

uat

ion

s b

y t

rial

an

d

erro

r w

ith

a s

pre

ad s

hee

t, s

tart

ing f

rom

P

= 7

60

to

rr,

xW

= 0

.5 a

nd

xF =

0.5

, q

uic

kly

lea

ds

to a

dew

-po

int

pre

ssu

re o

f 7

25

.2 t

orr

. T

he

K-v

alu

es a

t th

e d

ew p

oin

t ar

e co

mp

ute

d t

o b

e K

W =

1.0

06

and

KF =

0.9

77

, w

ith

xW

= 0

.49

7 a

nd

xF =

0.5

12

.

(c)

To

det

erm

ine

the

exis

ten

ce o

f an

aze

otr

op

e, w

her

e y i

= x

i ,

a se

ries

of

bu

bb

le-p

oin

t

calc

ula

tio

ns

can

be

mad

e, u

sin

g t

he

pro

ced

ure

in

par

t (a

), s

tart

ing f

rom

say,

x W =

0.0

5 i

n

incr

emen

ts o

f 0

.05

. I

f, i

n t

he

ran

ge

of

xW

fro

m 0

.05

to

0.9

5,

the

K-v

alu

e o

f W

sw

itch

es f

rom

mo

re t

han

1 t

o l

ess

than

1,

then

an

aze

otr

op

e ex

ists

in

th

is r

ange.

T

he

calc

ula

tio

ns

can

th

en b

e

refi

ned

. T

he

resu

lt f

rom

a s

pre

adsh

eet

is a

max

imu

m-b

oil

ing a

zeo

tro

pe

at 7

18

.2 t

orr

wit

h a

com

po

siti

on

of

44

.5 m

ol%

W a

nd

55

.5 m

ol%

F.

Page 31: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 4

.37

S

ub

ject

:

Bu

bb

le p

oin

t, d

ew p

oin

t, a

nd

eq

uil

ibri

um

fla

sh o

f a

tern

ary m

ixtu

re.

Giv

en:

M

ixtu

re o

f 4

5 m

ol%

n-h

exan

e (1

), 2

5 m

ol%

n-h

epta

ne,

an

d 3

0 m

ol%

n-o

ctan

e.

Ass

um

pti

on

s:

Ap

pli

cab

ilit

y o

f S

-R-K

met

ho

d f

or

esti

mat

ing K

-val

ues

.

Fin

d:

(a)

B

ub

ble

-po

int

tem

per

atu

re a

t p

ress

ure

s o

f 5

, 1

, an

d 0

.5 a

tm.

Dew

-po

int

tem

per

atu

re a

t p

ress

ure

s o

f 5

, 1

, an

d 0

.5 a

tm.

(b

) T

emp

erat

ure

an

d p

has

e co

mp

osi

tio

ns

for

flas

h o

f V

/F =

0.5

at

5,

1,

and

0.5

atm

.

(c

) n

-oct

ane

in t

he

vap

or

if 9

0%

of

the

n-h

exan

e is

vap

ori

zed

at

1 a

tm.

An

aly

sis:

T

he

foll

ow

ing r

esu

lts

are

ob

tain

ed w

ith

th

e C

HE

MC

AD

sim

ula

tor.

(a

) B

ub

ble

-po

int

and

dew

-po

int

tem

per

atu

res:

Pre

ssu

re,

atm

0

.5

1

5

Bu

bb

le-p

oin

t T

, oF

1

47

1

87

3

07

Dew

-po

int

T,

oF

1

78

2

16

3

30

(b

) 5

0 m

ol%

vap

ori

zati

on

of

feed

:

Pre

ssu

re,

atm

0

.5

1

5

Tem

per

atu

re,

oF

1

62

2

01

3

18

Vap

or

mo

le f

ract

ion

s:

n-H

exan

e 0

.61

5

0.5

99

0

.55

4

n-H

epta

ne

0.2

31

0

.23

3

0.2

39

n-O

ctan

e 0

.15

4

0.1

68

0

.20

7

Liq

uid

mo

le f

ract

ion

s:

n-H

exan

e 0

.28

5

0.3

01

0

.34

6

n-H

epta

ne

0.2

69

0

.26

7

0.2

61

n-O

ctan

e 0

.44

6

0.4

32

0

.39

3

Mo

les

V/m

ole

F

0.5

0

.5

0.5

Mo

les

L/m

ole

F

0.5

0

.5

0.5

(c

) B

y i

tera

tio

n o

n t

he

iso

ther

mal

fla

sh c

alcu

lati

on

, fo

r 9

0 m

ol%

of

n-h

exan

e to

vap

or,

nee

d a

tem

per

atu

re o

f 2

10

.2oF

at

1at

m.

Th

is g

ives

80

.1 m

ol%

vap

ori

zati

on

wit

h 6

5%

vap

ori

zati

on

of

n-o

ctan

e.

Ex

erci

se 4

.38

S

ub

ject

:

Vap

ori

zati

on

of

colu

mn

bo

tto

ms

in a

par

tial

reb

oil

er.

Giv

en:

1

50

km

ol/

h o

f b

ub

ble

-po

int

liq

uid

, L

1,

at 7

58

kP

a, w

ith

a m

ola

r co

mp

osi

tio

n o

f 1

0%

pro

pan

e, 4

0%

n-b

uta

ne,

an

d 5

0%

n-p

enta

ne

leav

ing b

ott

om

sta

ge

of

a d

isti

llat

ion

co

lum

n a

nd

pas

sin

g t

o a

reb

oil

er w

her

e al

l b

y 5

0 k

mo

l/h

is

vap

ori

zed

to

VB.

Ass

um

pti

on

s:

Pre

ssu

re i

n r

ebo

iler

= 7

58

kP

a.

S-R

-K m

eth

od

fo

r K

-val

ues

an

d e

nth

alp

ies.

Fin

d:

C

om

po

siti

on

s an

d a

mo

un

ts o

f b

oil

up

an

d b

ott

om

s, B

, an

d r

ebo

iler

du

ty,

QR,

fro

m a

sim

ula

tio

n p

rogra

m

An

aly

sis:

U

se f

lash

mo

du

le o

f th

e C

HE

MC

AD

sim

ula

tor.

F

eed

(L

1)

tem

per

atu

re i

s co

mp

ute

d

fro

m a

bu

bb

le-p

oin

t ca

lcu

lati

on

at

75

8 k

Pa

to b

e 7

4.9

oC

. F

lash

co

nd

itio

ns

are

P =

75

8 k

Pa

and

V/F

= (

15

0 -

50

)/1

50

= 0

.66

67

. T

he

resu

lt i

s a

tem

per

atu

re o

f 8

7.5

oC

wit

h a

reb

oil

er d

uty

of

2.2

2 x

10

6 k

J/h

, an

d c

om

po

siti

on

s as

fo

llo

ws

in t

erm

s o

f co

mp

on

ent

flo

w r

ates

:

Co

mp

on

ent:

B

ott

om

s, k

mo

l/h

B

oil

up

, k

mo

l/h

P

rop

ane

1

.94

13

.06

n

-Bu

tan

e 1

5.3

9

4

4.6

1

n

-Pen

tan

e 3

2.6

7

4

2.3

3

T

ota

l 5

0.0

0

10

0.0

0

Ex

erci

se 4

.39

S

ub

ject

:

Bu

bb

le-p

oin

t an

d e

qu

ilib

riu

m f

lash

tem

per

atu

res

for

a te

rnar

y m

ixtu

re.

Giv

en:

M

ixtu

re a

t 5

0 p

sia

wit

h a

co

mp

osi

tio

n i

n m

ole

fra

ctio

ns

of

0.0

05

met

han

e, 0

.59

5 e

than

e,

and

0.4

00

n-b

uta

ne.

Fin

d:

(a)

B

ub

ble

-po

int

tem

per

atu

re.

(b

) T

emp

erat

ure

an

d p

has

e co

mp

osi

tio

ns

for

25

mo

l% v

apo

riza

tio

n.

An

aly

sis:

I

nst

ead

of

usi

ng F

igs.

2.8

an

d 2

.9 f

or

K-v

alu

es,

use

S-R

-K m

eth

od

wit

h t

he

CH

EM

CA

D

sim

ula

tor,

wit

h t

he

foll

ow

ing r

esu

lts:

(a

) B

ub

ble

-po

int

tem

per

atu

re =

-6

1oF

. U

se o

f F

igs.

2.8

an

d 2

.9 g

ives

-6

0oF

.

(b

) F

lash

tem

per

atu

re f

or

25

mo

l% v

apo

riza

tio

n =

-4

3.6

oF

, w

ith

co

mp

osi

tio

ns:

Co

mp

on

ent

Vap

or

mo

le f

ract

ion

L

iqu

id m

ole

fra

ctio

n

M

eth

ane

0.0

17

9

0.0

00

7

E

than

e 0

.95

59

0

.47

47

n

-Bu

tan

e 0

.02

62

0

.52

46

Page 32: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 4

.40

S

ub

ject

:

Hea

tin

g a

nd

ex

pan

sio

n o

f a

hyd

roca

rbo

n m

ixtu

re.

Giv

en:

1

00

lb

mo

l/h

of

a m

ixtu

re a

t 1

50

oF

an

d 2

60

psi

a, w

ith

a m

ole

fra

ctio

n c

om

po

siti

on

of

0.0

3 e

than

e, 0

.20

pro

pan

e, 0

.37

n-b

uta

ne,

0.3

5 n

-pen

tan

e, a

nd

0.0

5 n

-hex

ane.

M

ixtu

re i

s h

eate

d

to 2

60

oF

at

25

0 p

sia,

fo

llo

wed

by e

xp

ansi

on

to

10

0 p

sia.

Ass

um

pti

on

s:

Ex

pan

sio

n i

s ad

iab

atic

.

S-R

-K m

eth

od

fo

r K

-val

ues

an

d e

nth

alp

ies

Fin

d:

U

sin

g a

sim

ula

tio

n p

rogra

m,

fin

d f

or

each

str

eam

in

th

e p

roce

ss,

the

mo

l% v

apo

r, a

nd

vap

or

and

liq

uid

ph

ase

mo

le f

ract

ion

s.

An

aly

sis:

U

sin

g t

he

CH

EM

CA

D p

roce

ss s

imu

lato

r, t

he

foll

ow

ing r

esu

lts

are

ob

tain

ed.

Th

e fe

ed i

s al

l li

qu

id.

Th

e st

ream

s le

avin

g t

he

hea

ter

and

th

e v

alv

e ar

e al

l v

apo

r.

Th

e fi

nal

tem

per

atu

re i

s 2

35

oF

.

Ex

erci

se 4

.41

S

ub

ject

:

Eq

uil

ibri

um

vap

or

and

liq

uid

str

eam

s le

avin

g t

he

feed

sta

ge

of

a d

isti

llat

ion

co

lum

n

Giv

en:

F

eed

str

eam

, F

, a

nd

str

eam

s V

F+

1 a

nd

LF

-1 as

su

mm

ariz

ed b

elo

w.

Pre

ssu

re =

78

5 k

Pa.

Ass

um

pti

on

s:

VF

+1 i

s at

its

dew

po

int

and

LF

-1 i

s at

its

bu

bb

le p

oin

t.

Ad

iab

atic

co

nd

itio

ns.

Fin

d:

Co

mp

osi

tio

n a

nd

am

ou

nts

of

str

eam

s V

F a

nd

LF.

An

aly

sis:

U

sin

g t

he

S-R

-K m

eth

od

fo

r K

-val

ues

, w

ith

th

e C

HE

MC

AD

pro

cess

sim

ula

tor,

th

e

foll

ow

ing r

esu

lts

are

ob

tain

ed:

Str

eam

F

V

F+

1

LF

-1

VF

LF

Tem

per

atu

re,

oC

6

4.3

7

3.1

6

8.5

7

0.0

7

0.0

Ph

ase

con

dit

ion

L

iqu

id

Vap

or

Liq

uid

V

apo

r L

iqu

id

Flo

w r

ate,

km

ol/

h:

P

rop

ane

32

.0

58

.8

15

.0

69

.6

36

.2

n

-Bu

tan

e 6

4.0

9

8.0

4

5.0

8

9.9

1

17

.1

n

-Pen

tan

e 6

4.0

3

9.2

4

0.0

3

4.5

1

08

.7

To

tal

16

0.0

1

96

.0

10

0.0

1

94

.0

26

2.0

Ex

erci

se 4

.42

S

ub

ject

:

Ad

iab

atic

fla

sh a

cro

ss a

val

ve

of

a h

yd

roca

rbo

n m

ixtu

re.

Giv

en:

F

eed

mix

ture

, o

f co

mp

osi

tio

n b

elo

w,

at 2

50

oF

an

d 5

00

psi

a.

Pre

ssu

re e

xit

ing v

alv

e =

30

0 p

sia.

Fin

d:

(a)

P

has

e co

nd

itio

n o

f fe

ed.

(b

) T

emp

erat

ure

do

wn

stre

am o

f v

alv

e.

(c

) M

ole

fra

ctio

n v

apo

rize

d a

cro

ss v

alv

e.

(d

) M

ole

fra

ctio

n c

om

po

siti

on

s o

f v

apo

r an

d l

iqu

id p

has

es d

ow

nst

ream

of

val

ve.

An

aly

sis:

U

se C

HE

MC

AD

pro

cess

sim

ula

tor

wit

h S

-R-K

met

ho

d f

or

K-v

alu

es a

nd

en

thal

pie

s.

Res

ult

s ar

e as

fo

llo

ws:

Str

eam

F

eed

V

apo

r fr

om

val

ve

Liq

uid

fro

m v

alv

e

Tem

per

atu

re,

oF

2

50

2

07

.6

20

7.6

Pre

ssu

re,

psi

a 5

00

3

00

3

00

Ph

ase

con

dit

ion

L

iqu

id

Vap

or

Liq

uid

Mo

le f

ract

ion

of

feed

1

.00

0

.40

43

0

.59

57

Mo

le f

ract

ion

s:

E

thyle

ne

0.0

2

0.0

34

8

0.0

09

9

E

than

e 0

.03

0

.04

91

0

.01

71

P

rop

yle

ne

0.0

5

0.0

65

8

0.0

39

3

P

rop

ane

0.1

0

0.1

26

0

0.0

82

3

Is

ob

uta

ne

0.2

0

0.1

95

3

0.2

03

2

n

-Bu

tan

e 0

.60

0

.52

90

0

.64

82

Ex

erci

se 4

.43

S

ub

ject

an

d t

o F

ind

: A

lgo

rith

m f

or

flas

h c

alcu

lati

on

wh

en Ψ

= V

/F a

nd

P a

re s

pec

ifie

d.

Giv

en:

Is

oth

erm

al f

lash

alg

ori

thm

of

Fig

. 4

-19

a, a

nd

eq

uat

ion

s o

f T

able

4.4

.

An

aly

sis:

S

pec

ify f

eed

rat

e an

d c

om

po

siti

on

, an

d v

alu

es o

f Ψ

= V

/F a

nd

P.

Use

th

e is

oth

erm

al

flas

h a

lgo

rith

m o

f F

ig.

4-1

9a

as a

n i

nn

er l

oo

p.

Gu

ess

the

flas

h t

emp

erat

ure

an

d e

nte

r th

e in

ner

loo

p.

If

the

calc

ula

ted

Ψ =

V/F

is

no

t th

e sp

ecif

ied

val

ue,

gu

ess

a n

ew v

alu

e o

f T

= s

ay 1

.05

tim

es t

he

init

ial

gu

ess

of

T,

and

rep

eat

the

inn

er l

oo

p.

Fo

r th

e n

ext

and

su

bse

qu

ent

iter

atio

ns,

k,

app

ly t

he

fals

e p

osi

tio

n m

eth

od

to

pro

vid

e a

new

gu

ess

of

T:

TT

TT

kk

kk

kk

k+

++

++

=+

−−

−2

11

11

ΨΨ

ΨΨ

spec

��

��

�/

Th

is a

ssu

mes

th

at T

is

a li

nea

r fu

nct

ion

of

Ψ =

V/F

. I

tera

te u

nti

l th

e co

mp

ute

d Ψ

= V

/F

is w

ith

in

say 0

.1%

of

the

spec

ifie

d v

alu

e.

Page 33: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 4

.44

S

ub

ject

an

d t

o F

ind

: A

lgo

rith

ms

for

flas

h c

alcu

lati

on

s w

ith

6 d

iffe

ren

t se

ts o

f sp

ecif

ied

var

iab

les

giv

en i

n t

he

tab

le b

elo

w.

Giv

en:

Is

oth

erm

al f

lash

alg

ori

thm

of

Fig

. 4

-19

a, a

nd

eq

uat

ion

s o

f T

able

4.4

.

Ass

um

pti

on

: A

ll f

lash

es a

re a

dia

bat

ic.

An

aly

sis:

T

he

equ

atio

ns

to b

e so

lved

fo

r ea

ch a

lgo

rith

m a

re t

ho

se f

or

the

stan

dar

d a

dia

bat

ic

flas

h p

roce

du

re,

wh

ere

the

spec

ific

atio

ns

are

ou

tlet

P a

nd

Q =

0.

Rac

hfo

rd-R

ice

Eq

. (3

), T

able

4.4

:

fz

K

K

ii

iiC

1

1

1

11

0=

+−

==���

��

Ψ

(1

)

Ad

iab

atic

en

erg

y b

alan

ce,

Eq

. (4

-19

):

fh

hh

VL

F2

1 10

00

=+

−−

ΨΨ

()

,

(2

)

Fo

r ea

ch o

f th

e 6

alg

ori

thm

s, w

e m

ust

ch

oo

se a

tea

r v

aria

ble

, th

e o

utp

ut

var

iab

le f

or

f 1,

and

th

e

ou

tpu

t v

aria

ble

fo

r f 2

. I

f K

-val

ues

are

co

mp

osi

tio

n-d

epen

den

t, t

hen

ou

ter

loo

p i

tera

tio

ns

wit

h f

1

are

nec

essa

ry a

s in

Fig

. 4

.19

. N

ote

th

at t

he

spec

ific

atio

n o

f h

F i

s eq

uiv

alen

t to

sp

ecif

yin

g T

F o

r

Q =

0.

In

so

me

case

s, i

t m

ay b

e n

eces

sary

to

so

lve

f 1 a

nd

f 2

sim

ult

aneo

usl

y.

Ou

tpu

t V

aria

ble

in

Cas

e S

pec

ific

atio

ns

Fin

d

Tea

r

Var

iab

le

f 1

f 2

1

hF ,

P

Ψ,

Τ

TV

Ψ

TV

2

hF ,

T

Ψ,

P

Ψ

PV

Ψ

3

hF ,

Ψ

T,

P

TV

PV

TV

4

Ψ,

T

hF ,

P

hF{T

F}

PV

hF

5

Ψ,

P

hF ,

T

hF{T

F}

TV

hF

6

T,

P

hF ,

Ψ

hF{T

F}

Ψ

hF

As

an e

xam

ple

of

on

e o

f th

e al

go

rith

ms,

co

nsi

der

Cas

e 1

, w

hic

h i

s eq

uiv

alen

t to

th

e st

and

ard

adia

bat

ic f

lash

sp

ecif

icat

ion

. T

he

algo

rith

m i

s sh

ow

n i

n d

iag

ram

fo

rm o

n t

he

foll

ow

ing p

age.

Ex

erci

se 4

.44

(c

on

tin

ued

)

A

na

lysi

s:

(co

nti

nu

ed)

Page 34: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.5

S

ub

ject

: N

eed

fo

r te

stin

g o

r p

ilo

tin

g a

dis

till

atio

n s

epar

atio

n.

Fin

d:

C

ircu

mst

ance

s th

at r

equ

ire

lab

ora

tory

or

pil

ot-

pla

nt

test

ing o

f a

pro

po

sed

dis

till

atio

n.

An

aly

sis:

L

abo

rato

ry a

nd

/or

pil

ot-

pla

nt

test

ing i

s re

com

men

ded

fo

r:

1

. A

new

mix

ture

no

t p

rev

iou

sly s

epar

ated

by d

isti

llat

ion

.

2.

A s

har

p a

nd

cri

tica

l se

par

atio

n.

3.

A m

ixtu

re w

ith

un

cert

ain

vap

or-

liq

uid

eq

uil

ibri

a d

ata.

4.

A l

ack

of

exp

erie

nce

wit

h t

ray e

ffic

ien

cy f

or

the

mix

ture

.

Ex

erci

se 7

.6

S

ub

ject

: E

con

om

ic t

rad

eoff

in

dis

till

atio

n.

Fin

d:

R

easo

ns

for

trad

eoff

bet

wee

n t

rays

and

ref

lux

.

An

aly

sis:

I

t is

wel

l k

no

wn

th

at f

or

a giv

en s

epar

atio

n,

as t

he

nu

mb

er o

f tr

ays

is i

ncr

ease

d,

the

refl

ux

rat

io c

an b

e d

ecre

ased

. T

hu

s, a

s th

e to

wer

hei

gh

t is

in

crea

sed

, th

e v

apo

r an

d l

iqu

id t

raff

ic

up

an

d d

ow

n t

he

colu

mn

can

be

dec

reas

ed.

Th

eref

ore

, th

e co

lum

n d

iam

eter

can

be

dec

reas

ed.

Als

o t

he

con

den

ser

and

reb

oil

er d

uti

es a

nd

siz

es,

and

th

e u

tili

ty r

equ

irem

ents

can

be

dec

reas

ed.

Th

eref

ore

, th

ere

is a

tra

deo

ff.

Ex

erci

se 7

.7

Su

bje

ct:

McC

abe-

Th

iele

met

ho

d f

or

bin

ary d

isti

llat

ion

.

Fin

d:

R

easo

ns

for

the

surv

ival

of

the

McC

abe-

Th

iele

gra

ph

ical

met

ho

d.

An

aly

sis:

F

or

a b

inar

y m

ixtu

re,

the

McC

abe-

Th

iele

met

ho

d s

ho

ws

clea

rly t

he

ease

or

dif

ficu

lty

of

the

sep

arat

ion

. P

inch

ed r

egio

ns

are

read

ily s

een

. T

he

effe

ct o

f fe

ed l

oca

tio

n i

s re

adil

y s

een

.

Th

e m

eth

od

is

reas

on

ably

acc

ura

te.

Aze

otr

op

es a

re r

ead

ily a

cco

mm

od

ated

.

Ex

erci

se 7

.8

Su

bje

ct:

Sep

arat

ion

of

eth

yl

alco

ho

l an

d w

ater

at

1 a

tm.

wit

h t

wo

co

un

terc

urr

ent

casc

ades

.

Giv

en:

O

ne

casc

ade

(a)

wit

h g

iven

liq

uid

fee

d t

o t

op

sta

ge

and

giv

en v

apo

r fe

ed t

o b

ott

om

stag

e.

An

oth

er c

asca

de

(b)

wit

h t

ota

l co

nd

ense

r an

d r

eflu

x,

and

giv

en v

apo

r fe

ed t

o b

ott

om

stag

e.

Vap

or-

liq

uid

eq

uil

ibri

um

dat

a fo

r 1

atm

.

Ass

um

pti

on

s:

Co

nst

ant

mo

lar

ov

erfl

ow

to

giv

e st

raig

ht

op

erat

ing l

ines

on

a y

-x d

iagra

m.

Fin

d:

(a

) C

om

po

siti

on

s o

f V

4 a

nd

L1 f

or

4 s

tages

in

cas

cad

e (a

).

(b

) N

um

ber

of

equ

ilib

riu

m s

tages

fo

r 8

5 m

ol%

alc

oh

ol

in e

xit

vap

or

of

casc

ade

(a).

(c

) C

om

po

siti

on

s o

f D

an

d L

1 f

or

4 s

tages

in

cas

cad

e (b

).

(d

) N

um

ber

of

equ

ilib

riu

m s

tages

fo

r 5

0 m

ol

alco

ho

l in

D o

f ca

scad

e (b

).

An

aly

sis:

F

rom

th

e giv

en v

apo

r-li

qu

id e

qu

ilib

riu

m d

ata,

in

th

e co

mp

osi

tio

n r

ange

of

inte

rest

,

eth

yl

alco

ho

l is

mo

re v

ola

tile

th

an w

ater

. T

her

efo

re,

the

y an

d x

co

ord

inat

es i

n a

y-x

plo

t p

erta

in

to e

thyl

alco

ho

l.

(a)

Sin

ce L

= 1

00

mo

l an

d V

= 1

00

mo

l, t

he

slo

pe

of

the

op

erat

ing l

ine

fro

m E

qs.

(7

-6)

or

(7-1

1)

= L

/V =

10

0/1

00

= 1

. T

he

term

inal

po

ints

on

th

e o

per

atin

g l

ine

as (

y, x

) ar

e: (

?,

0.7

) at

th

e to

p

and

(0

.3,

?)

at t

he

bo

tto

m.

To

det

erm

ine

the

com

po

siti

on

s o

f V

4 a

nd

L1 f

or

4 s

tages

, th

is

op

erat

ing l

ine

is l

oca

ted

so

th

at e

xac

tly 4

sta

ges

are

ste

pp

ed o

ff i

n a

y-x

dia

gra

m,

as s

ho

wn

bel

ow

.

Fro

m t

he

dia

gra

m,

the

eth

ano

l co

mp

osi

tio

ns

are

76

mo

l% i

n V

4

and

24

mo

l% i

n L

1.

Page 35: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.8 (c

on

tin

ued

) A

na

lysi

s:

(co

nti

nu

ed)

(b

)

It i

s im

po

ssib

le t

o o

bta

in a

n o

ver

hea

d v

apo

r w

ith

85

mo

l% e

than

ol.

W

ith

an

in

fin

ite

nu

mb

er o

f st

ages

, th

e h

igh

est

con

cen

trat

ion

of

eth

ano

l in

th

e o

ver

hea

d v

apo

r co

rres

po

nd

s to

th

at

in e

qu

ilib

riu

m w

ith

th

e to

p l

iqu

id f

eed

co

nta

inin

g 7

0 m

ol%

eth

ano

l.

Fro

m t

he

giv

en v

apo

r-li

qu

id

equ

ilib

riu

m d

ata,

th

e h

igh

est

con

cen

trat

ion

is

an e

than

ol

mo

le f

ract

ion

of

0.8

2.

(c)

Sin

ce t

he

bo

tto

m v

apo

r fe

ed,

V0

= 1

00

mo

l an

d D

=

50

mo

l, b

y o

ver

all

mat

eria

l

bal

ance

, L

1 =

V0 -

D =

10

0 -

50

= 5

0 m

ol.

B

ecau

se o

f th

e as

sum

pti

on

of

con

stan

t m

ola

r

ov

erfl

ow

, L

= L

R =

L1

= 5

0 m

ol.

B

y m

ater

ial

bal

ance

aro

un

d t

he

con

den

ser

or

bec

ause

of

con

stan

t m

ola

r o

ver

flo

w,

V =

V4 =

LR +

D

= 5

0 +

50

= 1

00

mo

l.

Th

e sl

op

e o

f th

e o

per

atin

g

lin

e fr

om

Eq

s. (

7-6

) o

r (7

-11

) =

L/V

= 5

0/1

00

= 0

.5.

To

det

erm

ine

the

com

po

siti

on

s o

f D

an

d L

1

for

4 s

tages

, an

o

per

atin

g l

ine

of

this

slo

pe

is l

oca

ted

so

th

at e

xac

tly 4

sta

ges

are

ste

pp

ed o

ff i

n a

y-x

dia

gra

m,

as s

ho

wn

bel

ow

. F

rom

th

e d

iagra

m,

the

eth

ano

l co

mp

osi

tio

ns

are

45

mo

l% i

n D

and

16

mo

l% i

n L

1.

(d)

Sin

ce t

he

dis

till

ate

is 5

0 m

ol%

eth

ano

l, 2

5 m

ole

s o

f et

han

ol

and

25

mo

les

of

wat

er

leav

e in

th

e d

isti

llat

e.

Bec

ause

th

e fe

ed i

s 3

0 m

ole

s o

f et

han

ol

and

70

mo

les

of

wat

er,

L1 ,

th

e

leav

ing l

iqu

id,

con

tain

s 5

mo

les

of

eth

ano

l an

d 4

5 m

ole

s o

f w

ater

. T

hu

s, t

he

term

inal

po

ints

on

the

op

erat

ing l

ine,

bec

ause

of

the

tota

l co

nd

ense

r, a

s (y

, x)

, ar

e: (

0.5

, 0

.5)

at t

he

top

an

d

(0.3

, 0

.1 )

at

the

bo

tto

m.

Ho

wev

er,

po

int

(0.3

, 0

.1)

abo

ve

the

equ

ilib

riu

m l

ine

is i

mp

oss

ible

.

Page 36: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.9

Su

bje

ct:

Sep

arat

ion

of

air

in a

reb

oil

ed s

trip

per

Giv

en:

R

ebo

iled

str

ipp

er w

ith

to

tal

reb

oil

er o

per

atin

g a

t 1

atm

. L

iqu

id a

ir (

79

.1 m

ol%

N2 a

nd

20

.9 m

ol%

O2)

fed

to

to

p s

tage.

6

0%

of

O2

in t

he

feed

is

dra

wn

off

in

vap

or

pro

du

ct f

rom

th

e

reb

oil

er.

Bo

tto

ms

vap

or

pro

du

ct c

on

tain

s 0

.2 m

ol%

N2.

Vap

or-

liq

uid

eq

uil

ibri

a d

ata

are

giv

en.

Ass

um

pti

on

s:

Fee

d i

s a

satu

rate

d l

iqu

id.

Fin

d:

(a)

Mo

l% N

2 i

n v

apo

r fr

om

to

p s

tage.

(b

) M

ole

s o

f v

apo

r gen

erat

ed i

n r

ebo

iler

per

10

0 m

ole

s o

f fe

ed.

(c

) N

um

ber

of

equ

ilib

riu

m s

tages

req

uir

ed.

An

aly

sis:

(a

) T

ake

a b

asis

of

F =

10

0 m

ol/

h.

Th

eref

ore

, 7

9.1

mo

l/h

of

N2

an

d 2

0.9

mo

l/h

of

O2 i

n

the

feed

. B

ott

om

s p

rod

uct

vap

or

con

tain

s 0

.6(2

0.9

) =

12

.54

mo

l/h

of

O2 a

nd

(0

.2/9

9.8

)(1

2.5

4)

=

0.0

25

mo

l/h

N2.

By m

ater

ial

bal

ance

, th

e o

ver

hea

d v

apo

r co

nta

ins

20

.9 -

12

.54

= 8

.36

mo

l/h

O2

and

79

.1 -

0.0

25

= 7

9.0

75

mo

l/h

of

N2.

Th

e m

ol%

N2 i

n t

he

ov

erh

ead

vap

or

= 7

9.0

75

/(8

.36

+

79

.07

5)

x 1

00

% =

90

.4 %

.

(b

) A

ssu

me

con

stan

t m

ola

r o

ver

flo

w.

Th

en b

ecau

se t

he

feed

is

assu

med

to

be

a sa

tura

ted

liq

uid

, th

e m

ole

s o

f v

apo

r gen

erat

ed i

n t

he

reb

oil

er p

er 1

00

mo

les

of

feed

= m

ol/

h o

f o

ver

hea

d

vap

or

= 8

.36

+ 7

9.0

75

= 8

7.4

35

mo

les

per

10

0 m

ole

s o

f fe

ed.

(c)

Use

a y

-x d

iagra

m f

or

N2 b

ecau

se i

t is

th

e m

ore

vo

lati

le.

Th

e sl

op

e o

f th

e o

per

atin

g

lin

e is

L/V

= 1

00

/87

.43

5 =

1.1

4.

At

the

top

of

the

colu

mn

, th

e o

per

atin

g l

ine

term

inat

es a

t a

(y-x

)

of

(0.9

04

, 0

.79

1).

A

t th

e b

ott

om

of

the

colu

mn

, w

ith

a t

ota

l re

bo

iler

, th

e o

per

atin

g l

ine

term

inat

es a

t a

(y-x

) o

f (0

.00

2,

0.0

02

).

To

det

erm

ine

the

nu

mb

er o

f eq

uil

ibri

um

sta

ges

, it

is

con

ven

ien

t to

use

tw

o d

iagra

ms,

th

e u

sual

on

e an

d a

sec

on

d o

ne

for

just

th

e v

ery l

ow

mo

le

frac

tio

n r

egio

n s

o a

s to

gai

n a

ccu

racy

in

th

e re

gio

n o

f th

e lo

wer

en

d o

f th

e o

per

atin

g l

ine.

F

rom

the

two

dia

gra

ms,

it

is s

een

th

at j

ust

les

s th

an 8

eq

uil

ibri

um

sta

ges

are

req

uir

ed.

Ex

erci

se 7

.9 (c

on

tin

ued

) A

na

lysi

s (d

) (

con

tin

ued

):

Page 37: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.10

S

ub

ject

: S

tage

com

po

siti

on

dat

a fo

r d

isti

llat

ion

of

an A

-B m

ixtu

re.

Giv

en:

S

atu

rate

d l

iqu

id f

eed

of

40

mo

l% A

. T

est

resu

lts

for

vap

or

and

liq

uid

co

mp

osi

tio

ins

for

3 s

ucc

essi

ve

stag

es b

etw

een

th

e fe

ed s

tage

and

a t

ota

l co

nd

ense

r.

_

__

__

__

__

__

_M

ol

% A

__

__

__

__

__

__

_

T

est

1

T

est

2

Sta

ge

Vap

or

Liq

uid

V

apo

r L

iqu

id

M +

2

79

.5

68

.0

75

.0

68

.0

M +

1

74

.0

60

.0

68

.0

60

.5

M

67

.9

51

.0

60

.5

53

.0

Ass

um

pti

on

:

Co

nst

ant

mo

lar

ov

erfl

ow

.

Fin

d:

R

eflu

x r

atio

an

d o

ver

hea

d c

om

po

siti

on

fo

r ea

ch t

est.

An

aly

sis:

T

est

1:

By m

ater

ial

bal

ance

fo

r co

mp

on

ent

A a

rou

nd

sta

ge

M +

1,

Vy

Lx

Vy

Lx

MM

MM

+=

++

++

21

1

(1

)

So

lvin

g E

q.

(1)

for

L/V

an

d s

ub

stit

uti

ng f

or

y an

d x

val

ues

fro

m a

bo

ve

tab

le,

L V

yy

xx

MM

MM

=− −

=− −

=+

++

1

21

07

40

06

79

06

80

06

00

07

63

..

..

.

Fro

m E

q.

(7-7

), r

eflu

x r

atio

= R

= L

/D =

(L

/V)/

(1 -

L/V

) =

0.7

63

/(1

- 0

.76

3)

= 3

.22

D/V

= (

L/V

)/(L

/D)

= 0

.76

3/3

.22

= 0

.23

7.

No

tin

g t

hat

sta

ges

in

th

e re

ctif

yin

g s

ecti

on

are

co

un

ted

her

e fr

om

th

e b

ott

om

up

in

stea

d o

f th

e to

p d

ow

n,

Eq

. (7

-5)

bec

om

es,

yL V

xD V

xM

MD

++

=+

12

(2)

So

lvin

g E

q.

(2)

for

x D ,

x

yL V

x

DV

D

MM

=

−� ��� ��

=−

=+

+1

20

74

00

76

30

68

0

02

37

09

33

/

.(

.)(

.)

..

Th

eref

ore

th

e co

mp

osi

tio

n o

f th

e d

isti

llat

e is

93

.3 m

ol%

A a

nd

6.7

mo

l% B

.

T

est

2:

Bec

ause

y

xy

xM

MM

M+

++

==

12

1

an

d

,

op

erat

ion

is

at t

ota

l re

flu

x,

i.e.

ref

lux

rat

io =

in

fin

ity.

In t

his

cas

e, E

q.

(2)

can

no

t b

e so

lved

fo

r x D

bec

ause

D/V

= 0

. W

e ca

n n

ot

det

erm

ine

the

com

po

siti

on

of

the

dis

till

ate.

W

e d

o k

no

w t

hat

it

mu

st a

t le

ast

75

mo

l% A

.

Ex

erci

se 7

.11

S

ub

ject

: F

ive

pro

ced

ure

s fo

r co

nti

nu

ou

s d

isti

llat

ion

of

a m

ixtu

re o

f b

enze

ne

(A)

and

to

luen

e

(B).

Giv

en:

O

per

atio

n a

t 1

atm

to

pro

du

ce a

dis

till

ate

of

80

mo

l% b

enze

ne

(i.e

. y D

= 0

.8)

fro

m a

satu

rate

d l

iqu

id f

eed

of

70

mo

l% b

enze

ne

(xF

= 0

.7)

. P

roce

du

res

are:

1

. N

o c

olu

mn

. J

ust

a p

arti

al c

on

den

ser

on

to

p o

f a

par

tial

reb

oil

er.

Fee

d i

s to

th

e

reb

oil

er.

Ref

lux

rat

io,

L/D

= 0

.5.

Vap

or

dis

till

ate

is t

ota

lly c

on

den

sed

.

2

. S

ame

as 1

ex

cep

t th

at o

ne

equ

ilib

riu

m s

tage

sits

bet

wee

n t

he

con

den

ser

and

reb

oil

er.

3

. S

ame

as 1

ex

cep

t tw

o e

qu

ilib

riu

m s

tages

bet

wee

n t

he

con

den

ser

and

reb

oil

er.

4

. S

ame

as 3

ex

cep

t th

at r

eflu

x b

yp

asse

s th

e to

p e

qu

ilib

riu

m s

tage.

5

. S

ame

as 2

ex

cep

t th

at f

eed

is

sen

t to

th

e st

age

bet

wee

n t

he

con

den

ser

and

th

e re

bo

iler

.

Ass

um

pti

on

s:

Co

nst

ant

mo

lar

ov

erfl

ow

. C

on

stan

t re

lati

ve

vo

lati

lity

= α

Α,Β

= 2

.5.

Fin

d:

F

or

each

pro

ced

ure

, d

eter

min

e:

(a

) M

ole

s o

f d

isti

llat

e p

er 1

00

mo

les

of

feed

.

(b

) M

ole

s o

f to

tal

vap

or

gen

erat

ed p

er m

ole

of

dis

till

ate.

(c

) M

ole

per

cen

t o

f b

enze

ne

in t

he

bo

tto

ms

(res

idu

e).

(d

) y

-x d

iagra

m,

ind

icat

ing c

om

po

siti

on

s o

f d

isti

llat

e, r

eflu

x,

and

res

idu

e.

Als

o,

(e)

Fo

r m

axim

izat

ion

of

ben

zen

e re

cov

ery (

in t

he

dis

till

ate)

, w

hic

h p

roce

du

re i

s p

refe

rred

.

An

aly

sis:

F

or

each

pro

ced

ure

, th

e p

arti

al c

on

den

ser

and

th

e p

arti

al r

ebo

iler

are

eq

uil

ibri

um

stag

es.

Ben

zen

e is

th

e m

ore

vo

lati

le c

om

po

nen

t, s

o t

he

y-x

dia

gra

m i

s b

ased

on

ben

zen

e.

Bec

ause

th

e re

lati

ve

vo

lati

lity

= c

on

stan

t =

2.5

, th

e eq

uil

ibri

um

rel

atio

nsh

ip i

s giv

en b

y E

q.

(7-3

),

yx

x

x

x=

+−

=+

α

α1

1

25

11

5(

)

.

.

(1)

Tak

e as

a b

asis

, 1

00

mo

l/s

of

feed

. T

her

efo

re,

the

feed

co

nta

ins

70

mo

l/s

of

A a

nd

30

mo

l/s

of

B.

Fro

m t

he

refl

ux

rat

io,

L =

0.5

D,

V =

L +

D =

1.5

D.

Th

eref

ore

, D

/V =

2/3

an

d L

/V =

1/3

. U

se a

sub

scri

pt

of

C

for

stre

ams

leav

ing t

he

con

den

ser,

R f

or

stre

ams

leav

ing t

he

reb

oil

er,

1 f

or

the

top

stag

e w

hen

use

d,

and

2 f

or

the

seco

nd

sta

ge

wh

en u

sed

.

Pro

ced

ure

1:

So

lve

wit

h m

ater

ial

bal

ance

s an

d E

q.

(1).

T

he

liq

uid

lea

vin

g t

he

par

tial

co

nd

ense

r is

in

equ

ilib

riu

m w

ith

th

e v

apo

r d

isti

llat

e o

f y C

= y

D =

0.8

. S

olv

ing E

q.

(1),

xy

yy

CC

CC

=+

−=

+−

()

.

..

(.

).

1

08

08

25

10

80

61

5

(2)

Ben

zen

e m

ater

ial

bal

ance

aro

un

d c

on

den

ser,

Page 38: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

yV

yD

xL

yy

D Vx

L VR

CC

RC

C=

+=� ��� ��+� ��� ��

=� ��� ��+

� ��� ��

=

or

0

80

2 30

61

51 3

07

38

..

.

Ex

erci

se 7

.11

(c

on

tin

ued

) A

na

lysi

s:

P

roce

du

re 1

(c

on

tin

ued

)

Th

e v

apo

r fr

om

th

e re

bo

iler

is

in e

qu

ilib

riu

m w

ith

th

e li

qu

id b

ott

om

s (r

esid

ue)

.

Fro

m t

he

left

-

han

d p

art

of

Eq

. (2

),

0.7

38

(1)

0.7

38

2.5

(10

.53

00

.73

8)

==

=+

α−

+−

R

RR

R

y

yy

x

Ov

eral

l to

tal

mat

eria

l b

alan

ce,

F =

10

0 =

D +

B

(3)

Ov

eral

l b

enze

ne

mat

eria

l b

alan

ce,

xFF

= y

CD

+ x

RB

or

7

0 =

0.8

D +

0.5

30

B

(4)

So

lvin

g E

qs.

(3

) an

d (

4),

D =

62

.9 m

ol/

s o

r 6

2.9

mo

l/1

00

mo

l fe

ed,

and

B

= 3

7.1

mo

l/s.

Th

eref

ore

, v

apo

r gen

erat

ed =

V =

1.5

D =

1.5

(62

.9)

= 9

4.4

mo

l/s.

Th

e o

per

atin

g l

ine

for

the

y-x

dia

gra

m p

asse

s th

rou

gh

th

e (y

, x)

po

int

(0.8

, 0

.8)

wit

h a

slo

pe,

L/V

= 1

/3,

as s

ho

wn

in

th

e d

iagra

m b

elo

w.

Ex

erci

se 7

.11

(c

on

tin

ued

) A

na

lysi

s:

(c

on

tin

ued

)

Pro

ced

ure

2:

Th

e sl

op

e an

d t

op

po

int

of

the

op

erat

ing l

ine

are

the

sam

e as

fo

r P

roce

du

re 1

. W

e ju

st

hav

e to

ste

p o

ff o

ne

mo

re s

tage.

T

her

efo

re f

rom

th

e re

sult

s ab

ov

e, w

e h

ave:

y C =

0.8

0

x C =

0.6

15

y 1

= 0

.73

8

x 1 =

0.5

30

Ben

zen

e m

ater

ial

bal

ance

aro

un

d S

tage

1,

yV

xL

yV

xL

RC

+=

+1

1

(5)

So

lvin

g f

or

y R,

11

1(

)0

.73

8(0

.53

00

.61

5)

0.7

10

3

��

��

=+

−=

+−

=�

��

��

��

�R

C

Ly

yx

xV

Th

e v

apo

r fr

om

th

e re

bo

iler

is

in e

qu

ilib

riu

m w

ith

th

e li

qu

id b

ott

om

s (r

esid

ue)

.

Fro

m t

he

left

-

han

d p

art

of

Eq

. (2

),

0.7

10

(1)

0.7

10

2.5

(10

.49

50

.71

0)

==

=+

α−

+−

R

RR

R

y

yy

x

Ov

eral

l to

tal

mat

eria

l b

alan

ce,

F =

10

0 =

D +

B

(6)

Ov

eral

l b

enze

ne

mat

eria

l b

alan

ce,

xFF

= y

CD

+ x

RB

or

7

0 =

0.8

D +

0.4

95

B

(7)

So

lvin

g E

qs.

(6

) an

d (

7),

D =

67

.2 m

ol/

s o

r 6

7.2

mo

l /

mo

l fe

ed,

and

B

= 3

2.8

mo

l/s.

Th

eref

ore

, v

apo

r gen

erat

ed =

V =

1.5

D =

1.5

(67

.2)

= 1

00

.8 m

ol/

s

Th

e o

per

atin

g l

ine

for

the

y-x

dia

gra

m p

asse

s th

rou

gh

th

e (y

, x)

po

int

(0.8

, 0

.8)

wit

h a

slo

pe,

L/V

= 1

/3,

as s

ho

wn

in

th

e d

iagra

m b

elo

w.

Page 39: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.11

(c

on

tin

ued

) A

na

lysi

s:

(c

on

tin

ued

)

Pro

ced

ure

3:

T

he

slo

pe

and

to

p p

oin

t o

f th

e o

per

atin

g l

ine

are

the

sam

e as

fo

r P

roce

du

res

1 a

nd

2.

We

just

hav

e to

ex

ten

d P

roce

du

re 2

by s

tep

pin

g o

ff a

sec

on

d e

qu

ilib

riu

m s

tage.

F

rom

ab

ov

e, t

he

resu

lts

for

the

con

den

ser

and

sta

ge

1 a

re:

y C =

0.8

0

x C =

0.6

15

y 1

= 0

.73

8

x 1 =

0.5

30

y 2

= 0

.71

0

x2 =

0.4

95

Ben

zen

e m

ater

ial

bal

ance

aro

un

d S

tage

2,

yV

xL

yV

xL

R+

=+

12

2

(8)

So

lvin

g f

or

y R,

y

yx

xL V

R=

+−� ��� ��

=+

−� ��� ��

=2

21

07

10

04

95

05

30

1 30

69

8(

).

(.

.)

.

Th

e v

apo

r fr

om

th

e re

bo

iler

is

in e

qu

ilib

riu

m w

ith

th

e li

qu

id b

ott

om

s (r

esid

ue)

.

Fro

m t

he

left

-

han

d p

art

of

Eq

. (2

),

0.6

98

(1)

0.6

98

2.5

(10

.48

00

.69

8)

==

=+

α−

+−

R

RR

R

y

yy

x

Ov

eral

l to

tal

mat

eria

l b

alan

ce,

F =

10

0 =

D +

B

(10

)

Ov

eral

l b

enze

ne

mat

eria

l b

alan

ce,

xFF

= y

CD

+ x

RB

or

7

0 =

0.8

D +

0.4

80

B

(11

)

So

lvin

g E

qs.

(1

0)

and

(1

1),

D =

68

.8 m

ol/

s o

r 6

8.8

mo

l /

10

0 m

ol

feed

, an

d

B =

31

.2 m

ol/

s.

Th

eref

ore

, v

apo

r gen

erat

ed =

V =

1.5

D =

1.5

(68

.8)

= 1

03

.2 m

ol/

s

Th

e o

per

atin

g l

ine

for

the

y-x

dia

gra

m p

asse

s th

rou

gh

th

e (y

, x)

po

int

(0.8

, 0

.8)

wit

h a

slo

pe,

L/V

= 1

/3,

as s

ho

wn

in

th

e d

iagra

m b

elo

w.

Ex

erci

se 7

.11

(c

on

tin

ued

) A

na

lysi

s:

(c

on

tin

ued

)

Pro

ced

ure

4:

If

th

e re

flu

x b

yp

asse

s th

e to

p s

tage,

th

e v

apo

r an

d l

iqu

id p

ass

thro

ugh

th

at s

tage

wit

ho

ut

chan

ge.

T

her

efo

re,

this

pro

ced

ure

is

the

sam

e as

Pro

ced

ure

2,

i.e.

ju

st o

ne

stag

e in

th

e co

lum

n.

Pro

ced

ure

5:

Th

e sl

op

e an

d t

op

po

int

of

the

op

erat

ing l

ine

are

the

sam

e as

fo

r P

roce

du

re 1

. W

e ju

st

hav

e to

ad

d t

he

feed

to

th

e st

age

in t

he

colu

mn

. T

her

efo

re f

rom

th

e re

sult

s ab

ov

e, w

e h

ave:

y C =

0.8

0

x C =

0.6

15

y 1

= 0

.73

8

x 1 =

0.5

30

Ben

zen

e m

ater

ial

bal

ance

aro

un

d S

tage

1,

wh

ich

no

w i

ncl

ud

es t

he

feed

,

x FF

+ y

Vx

Ly

Vx

LR

C+

=+

11

(1

2)

So

lvin

g f

or

y R,

yy

V Vx

L Vx

L Vx

F V

V V

L V

L VV

RC

F=� ��� ��+� ��� ��−� ��� ��−� ��� ��

=� ��� ��+

� ��� ��−

� ��� ��−� ��� ��

11

07

38

05

30

06

15

07

01

00

..

..

(1

3)

Bec

ause

th

e fe

ed i

s a

satu

rate

d l

iqu

id,

, V

VL

L=

=+

and

1

00

Fro

m a

bo

ve,

V

= 1

.5D

an

d

L/V

= 1

/3.

Als

o,

LV

LV

VV

//

//

/=

+=

+1

00

13

10

0

Th

eref

ore

, E

q.

(13

) b

eco

mes

,

yV

VV

DR

=+

+� ��

� ��−� ��� ��−� ��� ��

=−

=−

07

38

05

30

1 3

10

00

61

51 3

07

01

00

07

10

17

07

10

11

33

..

..

..

.

(14

)

Page 40: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Th

e v

apo

r fr

om

th

e re

bo

iler

is

in e

qu

ilib

riu

m w

ith

th

e li

qu

id b

ott

om

s (r

esid

ue)

.

Fro

m t

he

left

-

han

d p

art

of

Eq

. (2

),

xy

yy

RR

RR

=+

−2

51

.(

)

(1

5)

Ov

eral

l to

tal

mat

eria

l b

alan

ce,

F =

10

0 =

D +

B

(16

)

Ov

eral

l b

enze

ne

mat

eria

l b

alan

ce,

xFF

= y

CD

+ x

RB

or

7

0 =

0.8

D +

xRB

(1

7)

So

lvin

g E

qs.

(1

4),

(1

5),

(1

6),

an

d (

17

),

y R =

0.5

65

, x R

= 0

.34

2,

D =

78

.3 m

ol/

s o

r 7

8.3

mo

l/1

00

mo

l fe

ed,

B

= 2

1.7

mo

l/s

Th

eref

ore

, v

apo

r gen

erat

ed =

V =

1.5

D =

1.5

(78

.3)

= 1

17

.5 m

ol/

s

Th

e re

ctif

yin

g s

ecti

on

op

erat

ing l

ine

for

the

y-x

dia

gra

m p

asse

s th

rou

gh

th

e (y

, x)

po

int

(0.8

, 0

.8)

wit

h a

slo

pe,

L/V

= 1

/3,

th

e q

-lin

e (f

eed

lin

e) i

s a

ver

tica

l li

ne,

an

d t

he

stri

pp

ing s

ecti

on

op

erat

ing l

ine

pas

ses

thro

ugh

t th

e (y

, x)

po

int

(0.5

65

, 0

.34

2)

and

th

e in

ters

ecti

on

of

the

oth

er t

wo

lin

es,

as s

ho

wn

in

th

e d

iagra

m o

n t

he

foll

ow

ing p

age.

Th

e re

sult

s fr

om

th

e 5

pro

ced

ure

s ar

e su

mm

ariz

ed a

s fo

llo

ws:

Pro

ced

ure

D

/10

0 m

ole

s o

f fe

ed

V/m

ole

of

D

x o

f b

enze

ne

in B

1

62

.9

1.5

0

.53

0

2

67

.2

1.5

0

.49

5

3

68

.8

1.5

0

.48

0

4

67

.2

1.5

0

.49

5

5

78

.3

1.5

0

.34

2

Ex

erci

se 7

.11

(c

on

tin

ued

) A

na

lysi

s: P

roce

du

re 5

:

(co

nti

nu

ed)

(e)

Pro

ced

ure

5 i

s re

com

men

ded

bec

ause

it

pro

du

ces

by f

ar t

he

mo

st d

isti

llat

e, w

hic

h

corr

esp

on

ds

to t

he

hig

hes

t re

cov

ery o

f b

enze

ne.

Page 41: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.12

S

ub

ject

: D

isti

llat

ion

of

a m

ixtu

re o

f b

enze

ne

(A)

and

to

luen

e (B

) at

10

1 k

Pa.

Giv

en:

C

olu

mn

co

nsi

stin

g o

f a

par

tial

reb

oil

er,

on

e th

eore

tica

l p

late

, an

d a

to

tal

con

den

ser.

Pro

du

ce a

dis

till

ate

of

75

mo

l% b

enze

ne

fro

m a

sat

ura

ted

liq

uid

fee

d o

f 5

0 m

ol%

ben

zen

e.

Ass

um

pti

on

s:

Co

nst

ant

mo

lar

ov

erfl

ow

. C

on

stan

t re

lati

ve

vo

lati

lity

= α

Α,Β

= 2

.5.

Fin

d:

Nu

mb

er o

f m

ole

s o

f d

isti

llat

e p

er 1

00

mo

les

of

feed

fo

r:

(a

) F

eed

to

th

e re

bo

iler

an

d n

o r

eflu

x.

(b

) F

eed

to

th

e re

bo

iler

an

d a

ref

lux

rat

io,

L/D

= 3

.

(c

) F

eed

to

th

e p

late

an

d a

ref

lux

rat

io o

f 3

.

(d

) S

ame

as (

c) e

xce

pt

a p

arti

al c

on

den

ser.

(e

) F

eed

to

th

e re

bo

iler

wit

h m

inim

um

ref

lux

.

(f

) F

eed

to

th

e re

bo

iler

wit

h t

ota

l re

flu

x.

An

aly

sis:

E

ith

er a

gra

ph

ical

or

anal

yti

cal

met

ho

d c

an b

e u

sed

. B

ecau

se t

he

rela

tiv

e v

ola

tili

ty i

s

assu

med

co

nst

ant,

use

an

an

alyti

cal

met

ho

d.

Fo

r ea

ch p

art,

th

e th

eore

tica

l p

late

an

d t

he

par

tial

reb

oil

er a

re e

qu

ilib

riu

m s

tages

. B

enze

ne

is t

he

mo

re v

ola

tile

co

mp

on

ent,

so

th

e y-

x d

iagra

m i

s

bas

ed o

n b

enze

ne.

Bec

ause

th

e re

lati

ve

vo

lati

lity

= c

on

stan

t =

2.5

, th

e eq

uil

ibri

um

rel

atio

nsh

ip i

s

giv

en b

y E

q.

(7-3

),

yx

x

x

x=

+−

=+

α

α1

1

25

11

5(

)

.

.

(1)

Tak

e as

a b

asis

, 1

00

mo

les

of

feed

. T

her

efo

re,

the

feed

is

50

mo

les

of

A a

nd

50

mo

les

of

B.

(a)

Wit

h n

o r

eflu

x,

sep

arat

ion

occ

urs

on

ly i

n t

he

reb

oil

er.

Th

e v

apo

r le

avin

g t

he

reb

oil

er

is t

ota

lly c

on

den

sed

to

bec

om

e th

e d

isti

llat

e w

ith

yD =

xD =

0.7

5.

So

lve

Eq

. (1

) fo

r eq

uil

ibri

um

x,

xy

yy

BD

DD

=+

−=

+−

()

.

..

(.

).

1

07

50

07

50

25

10

75

00

54

5

(

2)

Bec

ause

th

e d

isti

llat

e an

d b

ott

om

s h

ave

ben

zen

e m

ole

fra

ctio

ns

gre

ater

th

an t

he

mo

le f

ract

ion

of

the

feed

(0

.5),

it

is i

mp

oss

ible

to

ob

tain

a d

isti

llat

e w

ith

a b

enze

ne

mo

le f

ract

ion

of

0.7

5.

(b)

Fro

m t

he

refl

ux

rat

io,

L =

3D

, V

= L

+ D

= 4

D.

Th

eref

ore

, D

/V =

1/4

an

d L

/V =

3/4

.

Use

a s

ub

scri

pt

of

D f

or

dis

till

ate,

R f

or

refl

ux

, B

fo

r st

ream

s le

avin

g t

he

reb

oil

er,

and

1 f

or

the

theo

reti

cal

pla

te,

wh

en u

sed

. W

ith

1 t

heo

reti

cal

pla

te,

fro

m p

art

(a),

y 1 =

0.7

5

x D =

0.7

5

x 1 =

0.5

45

Ben

zen

e m

ater

ial

bal

ance

aro

un

d p

late

1,

yV

xL

yV

xL

BD

+=

+1

1

(3)

So

lvin

g f

or

y B

yy

xx

L VB

D=

+−� ��� ��

=+

−� ��� ��=

11

07

50

05

45

07

50

3 40

59

6(

).

(.

.)

.

Ex

erci

se 7

.12

(c

on

tin

ued

) A

na

lysi

s:

(b)

(co

nti

nu

ed)

Th

e m

ole

fra

ctio

n o

f b

enze

ne

in t

he

bo

tto

ms

pro

du

ct i

s in

eq

uil

ibri

um

wit

h y

B =

0.5

96

.

Th

eref

ore

,

the

form

of

Eq

. (2

) ap

pli

es,

xy

yy

BB

BB

=+

−=

+−

()

.

..

(.

).

1

05

96

05

96

25

10

59

60

37

1

Ov

eral

l to

tal

mat

eria

l b

alan

ce,

F =

10

0 =

D +

B

(4)

Ov

eral

l b

enze

ne

mat

eria

l b

alan

ce,

xFF

= x

DD

+ x

BB

or

5

0 =

0.7

5D

+ 0

.37

1B

(5

)

So

lvin

g E

qs.

(4

) an

d (

5),

D =

34

.2 m

ole

s o

r 3

4.2

mo

l/1

00

mo

l fe

ed,

an

d

B =

65

.8 m

ole

s.

(c)

Wit

h t

he

feed

to

th

e th

eore

tica

l p

late

, th

e fo

llo

win

g r

esu

lts

app

ly f

rom

par

t (b

), y

1 =

0.7

5

x D

= 0

.75

x 1

= 0

.54

5

Ben

zen

e m

ater

ial

bal

ance

aro

un

d S

tage

1,

wh

ich

no

w i

ncl

ud

es t

he

feed

,

x FF

+ y

Vx

Ly

Vx

LB

D+

=+

11

(6

)

So

lvin

g f

or

y B,

yy

V Vx

L Vx

L Vx

F V

V V

L V

L VV

BD

F=� ��� ��+� ��� ��−� ��� ��−� ��� ��

=� ��� ��+

� ��� ��−

� ��� ��−� ��� ��

11

07

50

05

45

07

50

05

01

00

..

..

(7

)

Bec

ause

th

e fe

ed i

s a

satu

rate

d l

iqu

id,

, V

VL

L=

=+

and

1

00

Fro

m a

bo

ve,

V

= 4

D

and

L

/V =

3/4

. A

lso

, L

VL

VV

V/

//

//

=+

=+

10

03

41

00

Th

eref

ore

, E

q.

(7)

bec

om

es,

yV

VV

DB

=+

+� ��

� ��−� ��� ��−� ��� ��

=−

=−

07

50

05

45

3 4

10

00

75

03 4

05

01

00

05

96

45

05

96

11

25

..

..

..

..

(8

)

Th

e v

apo

r fr

om

th

e re

bo

iler

is

in e

qu

ilib

riu

m w

ith

th

e li

qu

id b

ott

om

s (r

esid

ue)

.

Fro

m t

he

left

-

han

d p

art

of

Eq

. (2

),

xy

yy

BB

BB

=+

−2

51

.(

)

(9

)

Ov

eral

l to

tal

mat

eria

l b

alan

ce,

F =

10

0 =

D +

B

(10

)

Ov

eral

l b

enze

ne

mat

eria

l b

alan

ce,

xFF

= x

DD

+ x

BB

or

5

0 =

0.7

5D

+ x

BB

(1

1)

So

lvin

g E

qs.

(8

), (

9),

(1

0),

an

d (

11

),

y B =

0.6

47

,

x B

= 0

.42

3,

D

= 2

3.5

mo

les

or

23

.5 m

ol/

10

0 m

ol

feed

,

B =

76

.5 m

ole

s

(d)

W

ith

a p

arti

al c

on

den

ser,

th

e m

ole

fra

ctio

n o

f th

e li

qu

id r

eflu

x i

s th

at i

n e

qu

ilib

riu

m

wit

h t

he

vap

or

dis

till

ate.

T

her

efo

re,

fro

m t

he

abo

ve

resu

lts,

y D =

0.7

5

x R =

0.5

45

y 1

= 0

.59

6

x 1 =

0.3

71

Ben

zen

e m

ater

ial

bal

ance

aro

un

d t

he

theo

reti

cal

pla

te,

wh

ich

in

clu

des

th

e fe

ed,

x FF

+ y

Vx

Ly

Vx

LB

R+

=+

11

(1

2)

So

lvin

g f

or

y B,

yy

V Vx

L Vx

L Vx

F V

V V

L V

L VV

BR

F=� ��� ��+� ��� ��−� ��� ��−� ��� ��

=� ��� ��+

� ��� ��−

� ��� ��−� ��� ��

11

05

96

03

71

05

45

05

01

00

..

..

(1

3)

Page 42: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.12

(c

on

tin

ued

) A

na

lysi

s:

(d)

(co

nti

nu

ed)

Bec

ause

th

e fe

ed i

s a

satu

rate

d l

iqu

id,

, V

VL

L=

=+

and

1

00

Fro

m a

bo

ve,

V

= 4

D

and

L

/V =

3/4

. A

lso

, L

VL

VV

V/

//

//

=+

=+

10

03

41

00

Th

eref

ore

, E

q.

(13

) b

eco

mes

,

yV

VV

DB

=+

+� ��

� ��−� ��� ��−� ��� ��

=−

=−

05

96

03

71

3 4

10

00

54

53 4

05

01

00

04

66

12

90

46

63

23

..

..

..

..

(1

4)

Th

e v

apo

r fr

om

th

e re

bo

iler

is

in e

qu

ilib

riu

m w

ith

th

e li

qu

id b

ott

om

s (r

esid

ue)

.

Fro

m t

he

left

-

han

d p

art

of

Eq

. (2

),

xy

yy

BB

BB

=+

−2

51

.(

)

(1

5)

Ov

eral

l to

tal

mat

eria

l b

alan

ce,

F =

10

0 =

D +

B

(16

)

Ov

eral

l b

enze

ne

mat

eria

l b

alan

ce,

xFF

= y

DD

+ x

BB

o

r

50

= 0

.75

D +

xBB

(1

7)

So

lvin

g E

qs.

(1

4),

(1

5),

(1

6),

an

d (

17

),

y B =

0.4

05

, x B

= 0

.21

4,

D =

53

.4 m

ole

s o

r 5

3.4

/10

0 m

ol

feed

,

B

= 4

6.6

mo

les

(e)

At

min

imu

m r

eflu

x,

wit

h t

he

feed

sen

t to

th

e st

ill

po

t (p

arti

al r

ebo

iler

), a

n i

nfi

nit

e n

um

ber

of

theo

reti

cal

pla

tes

is n

eed

ed b

etw

een

th

e co

nd

ense

r an

d r

ebo

iler

. T

his

par

t is

no

t co

mp

lete

ly

spec

ifie

d.

In

ord

er t

o c

om

pu

te t

he

dis

till

ate,

we

mu

st a

ssu

me

a b

ott

om

s b

enze

ne

mo

le f

ract

ion

less

th

an t

hat

in

th

e fe

ed.

Su

pp

ose

we

cho

ose

th

at m

ole

fra

ctio

n t

o b

e 0

.45

. T

hen

th

e o

per

atin

g

lin

e w

ill

inte

rsec

t th

e eq

uil

ibri

um

lin

e at

x =

0.4

5,

crea

tin

g t

he

pin

ch z

on

e o

f in

fin

ite

stag

es.

Th

e

val

ue

of

y at

th

e in

ters

ecti

on

is

giv

en b

y E

q.

(1):

y=

+=

25

04

5

11

50

45

06

72

.(

.)

.(

.)

.

Th

eref

ore

th

e o

per

atin

g l

ine

pas

ses

thro

ugh

th

e tw

o p

oin

ts,

as {

y, x

},

of

{0

.75

, 0

.75

} a

nd

{0

.67

2,

0.4

50

}.

Th

eref

ore

, th

e sl

op

e =

L/V

= (

0.7

5 -

0.6

72

)/(0

.75

- 0

.45

) =

0.2

60

. N

ow

co

mp

ute

the

ov

eral

l m

ater

ial

bal

ance

s:

Ov

eral

l to

tal

mat

eria

l b

alan

ce,

F =

10

0 =

D +

B

(18

)

Ov

eral

l b

enze

ne

mat

eria

l b

alan

ce,

xFF

= y

DD

+ x

BB

o

r

50

= 0

.75

D +

0.4

5B

(1

9)

So

lvin

g E

qs.

(1

8)

and

(1

9),

D

= 1

6.6

7 m

ole

s o

r 1

6.6

7 m

ol/

10

0 m

ol

feed

, an

d B

= 8

3.3

3 m

ole

s

Cal

cula

tio

ns

for

oth

er v

alu

es o

f th

e b

enze

ne

mo

le f

ract

ion

in

th

e b

ott

om

s ca

n b

e m

ade

in t

he

sam

e m

ann

er.

(f)

At

tota

l re

flu

x,

ther

e is

no

dis

till

ate,

bu

t th

ere

is a

bo

ilu

p.

Th

e m

ole

s o

f d

isti

llat

e p

er 1

00

mo

les

of

feed

= 0

.

Ex

erci

se 7

.13

Su

bje

ct:

Dis

till

atio

n o

f a

mix

ture

of

ben

zen

e an

d t

olu

ene

at 1

01

kP

a fo

r sp

ecif

ied

ref

lux

rati

o a

nd

pro

du

ct c

om

po

siti

on

s.

Giv

en:

F

eed

of

30

kg/h

of

satu

rate

d l

iqu

id f

eed

co

nta

inin

g 4

0 m

ass%

ben

zen

e an

d 6

0 m

ass%

tolu

ene.

D

isti

llat

e to

co

nta

in 9

7 m

ass%

ben

zen

e an

d b

ott

om

s to

co

nta

in 9

8 m

ass%

to

luen

e.

Ref

lux

rat

io =

3.5

an

d f

eed

is

to o

pti

mal

sta

ge.

T

able

of

vap

or-

liq

uid

eq

uil

ibri

um

dat

a in

mo

le

frac

tio

ns.

At

10

1 k

Pa.

Ass

um

pti

on

s:

To

tal

con

den

ser

and

par

tial

reb

oil

er.

Sat

ura

ted

liq

uid

ref

lux

. C

on

stan

t m

ola

r

ov

erfl

ow

.

Fin

d:

(a

) F

low

rat

es o

f d

isti

llat

e an

d b

ott

om

s.

(b

) N

um

ber

of

equ

ilib

riu

m s

tages

nee

ded

.

An

aly

sis:

F

irst

so

lve

the

mat

eria

l b

alan

ce i

n m

ass

un

its.

T

hen

co

nv

ert

to m

ole

s an

d m

ole

frac

tio

ns

so t

hat

th

e M

cCab

e-T

hie

le m

eth

od

can

be

use

d f

or

par

t (b

).

Ov

eral

l to

tal

mas

s b

alan

ce:

3

0 =

D +

B

(1

)

Ov

eral

l b

enze

ne

mas

s b

alan

ce:

0

.40

(30

) =

12

= 0

.97

D +

0.0

2B

(2

)

So

lvin

g E

qs.

(1

) an

d (

2):

D

= 1

2.1

kg/h

B =

17

.9 k

g/h

Co

nv

erti

ng t

o m

ole

s w

ith

mo

lecu

lar

wei

gh

ts o

f 7

8.1

1 f

or

ben

zen

e an

d 9

2.1

3 f

or

tolu

ene,

Ben

zen

e

To

luen

e

Pro

du

ct

km

ol/

h

Ma

ss f

ract

ion

M

ole

fra

ctio

n

Ma

ss f

ract

ion

M

ole

fra

ctio

n

Dis

till

ate

0.1

54

0

.97

0

.97

4

0.0

3

0.0

23

5

Bo

tto

ms

0.1

96

0

.02

0

.02

6

0.9

8

0.9

76

5

To

tal:

0

.35

0

1.0

0

1.0

00

1

.00

1

.00

00

(b)

B

ecau

se b

enze

ne

is t

he

mo

re v

ola

tile

co

mp

on

ent

of

the

feed

, th

e x

and

y c

oo

rdin

ates

wil

l b

e

tho

se o

f b

enze

ne

in t

he

dia

gra

m o

n t

he

nex

t p

age.

.

In m

ole

s, t

he

feed

co

nsi

sts

of:

Co

mp

on

ent

km

ol/

h

Mo

le f

ract

ion

Ben

zen

e 0

.15

4

0.4

4

To

luen

e 0

.19

6

0.5

6

To

tal:

0.3

50

1

.00

Fo

r a

satu

rate

d l

iqu

id f

eed

, th

e q

-lin

e is

ver

tica

l an

d p

asse

s th

rou

gh

x =

0.4

4.

Th

e sl

op

e o

f th

e

rect

ifyin

g o

per

atin

g l

ine,

L/V

, is

ob

tain

ed f

rom

Eq

. (7

-7),

usi

ng t

he

spec

ifie

d r

eflu

x r

atio

= 3

.5,

L/V

= R

/(1

+ R

) =

3.5

/4.5

= 0

.77

8

Fo

r sa

tura

ted

liq

uid

ref

lux

, th

e re

ctif

yin

g o

per

atin

g l

ine

pas

ses

thro

ugh

th

e p

oin

t {0

.97

4,

0.9

74

}.

See

th

e M

cCab

e-T

hie

le c

on

stru

ctio

n o

n t

he

nex

t p

age,

wh

ere

it i

s se

en t

hat

sli

gh

tly m

ore

th

an 1

0

stag

es +

a p

arti

al r

ebo

iler

act

ing a

s an

eq

uil

ibri

um

sta

ge

are

req

uir

ed.

Th

e to

p 5

sta

ges

are

in

th

e

rect

ifyin

g s

ecti

on

.

Page 43: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.13

(c

on

tin

ued

) A

na

lysi

s:

(b)

(co

nti

nu

ed)

McC

ab

e-T

hie

le D

iag

ram

Ex

erci

se 7

.14

S

ub

ject

: D

isti

llat

ion

of

a m

ixtu

re o

f b

enze

ne

and

ch

loro

ben

zen

e w

ith

sp

ecif

ied

nu

mb

er o

f

equ

ilib

riu

m s

tages

, b

oil

up

rat

io,

and

ref

lux

rat

io.

Giv

en:

F

eed

is

a sa

tura

ted

liq

uid

of

54

.5 m

ol%

ben

zen

e.

Co

lum

n c

on

tain

s tw

o e

qu

ilib

riu

m

pla

tes

wit

h f

eed

to

th

e b

ott

om

pla

te.

Co

lum

n i

s eq

uip

ped

wit

h t

ota

l co

nd

ense

r an

d p

arti

al

reb

oil

er.

Bo

ilu

p i

s V

/F =

0.8

55

. R

eflu

x r

atio

, L

/V =

0.5

. V

apo

r-li

qu

id e

qu

ilib

riu

m d

ata

giv

en.

Fin

d:

C

om

po

siti

on

s o

f d

isti

llat

e an

d b

ott

om

s, a

ssu

min

g c

on

stan

t m

ola

r o

ver

flo

w.

An

aly

sis:

T

ake

as a

bas

is,

F =

10

0 m

ol/

s.

Th

eref

ore

, v

apo

r gen

erat

ed i

n r

ebo

iler

= 0

.85

5(1

00

)

= 8

5.5

mo

l/s.

S

ince

th

e fe

ed i

s a

satu

rate

d l

iqu

id,

this

vap

or

rate

co

nti

nu

es u

p t

he

colu

mn

to

th

e

con

den

ser.

L

/V =

0.5

, w

hic

h i

s th

e sl

op

e o

f th

e o

per

atin

g l

ine.

T

her

efo

re,

L =

0.5

(85

.5)

= 4

2.7

5

mo

l/s.

T

her

efo

re,

the

dis

till

ate

rate

= 8

5.5

- 4

2.7

5 =

42

.75

mo

l/s.

P

assi

ng t

o t

he

reb

oil

er i

s a

liq

uid

rat

e o

f 4

2.7

5 +

10

0 =

14

2.7

5 m

ol/

s.

Th

e b

ott

om

s ra

te =

14

2.7

5 -

85

.5 =

57

.25

mo

l/s.

T

he

slo

pe

of

the

stri

pp

ing s

ecti

on

op

erat

ing l

ine

is L

V/=

14

2.7

5/8

5.5

= 1

.67

. T

he

q-l

ine

is a

ver

tica

l li

ne

bec

ause

th

e fe

ed i

s a

satu

rate

d l

iqu

id.

To

so

lve

for

the

com

po

siti

on

s o

f th

e d

isti

llat

e

and

bo

tto

ms

on

a M

cCab

e-T

hie

le d

iagra

m,

we

mu

st l

oca

te t

he

op

erat

ing l

ines

to

ob

tain

th

ree

equ

ilib

riu

m s

tages

th

at s

atis

fy a

n o

ver

all

ben

zen

e m

ater

ial

bal

ance

giv

en b

y,

x FF

= 5

4.4

= x

DD

+ x

BB

= 4

2.7

5x D

+ 5

7.2

5x B

(1

)

So

lvin

g E

q.

(1),

x B =

0.9

52

- 0

.74

67

xD

(2)

Th

eref

ore

, an

ap

pro

ach

to

so

lvin

g t

his

ex

erci

se i

s to

ass

um

e a

val

ue

of

x D a

nd

th

en c

om

pu

te t

he

val

ue

of

x B f

rom

Eq

. (2

).

Th

en c

on

stru

ct t

he

McC

abe-

Th

iele

dia

gra

m w

ith

th

e ab

ov

e o

per

atin

g

lin

es a

nd

q-l

ine

to s

ee i

f t

hre

e st

ages

are

req

uir

ed w

ith

th

e fe

ed t

o t

he

seco

nd

pla

te.

See

plo

t b

elo

w,

wh

ere

ben

zen

e m

ole

fra

ctio

ns

are

plo

tted

bec

ause

it

is t

he

mo

re v

ola

tile

com

po

nen

t.

It i

s se

en t

hat

fo

r b

enze

ne,

xD =

0.9

0 a

nd

xB =

0.2

8.

Page 44: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.14

(c

on

tin

ued

)

M

cCa

be-

Th

iele

Dia

gra

m

Ex

erci

se 7

.15

Su

bje

ct:

E

ffec

t o

f lo

ss o

f p

late

s in

a d

isti

llat

ion

co

lum

n s

epar

atin

g a

ben

zen

e-to

luen

e m

ixtu

re.

Giv

en:

S

atu

rate

d v

apo

r fe

ed o

f 1

3,6

00

kg/h

of

40

wt%

ben

zen

e an

d 6

0 w

t% t

olu

ene.

C

olu

mn

wit

h 1

4 p

late

s ab

ov

e th

e fe

ed l

oca

tio

n.

Pla

te e

ffic

ien

cy i

s 5

0%

. R

eflu

x r

atio

is

3.5

. P

rev

iou

sly,

wit

h 1

0 p

late

s in

th

e st

rip

pin

g s

ecti

on

, co

lum

n c

ou

ld a

chie

ve

a d

isti

llat

e o

f 9

7 w

t% b

enze

ne

and

a

bo

tto

ms

of

98

wt%

to

luen

e.

Vap

or-

liq

uid

eq

uil

ibri

um

dat

a in

Ex

erci

se 7

.13

.

Ass

um

pti

on

s:

Co

nst

ant

mo

lar

ov

erfl

ow

. T

ota

l co

nd

ense

r an

d p

arti

al r

ebo

iler

.

Fin

d:

(a

) I

f co

lum

n w

ith

10

in

op

erab

le p

late

s ca

n y

ield

a d

isti

llat

e o

f 9

7 w

t% b

enze

ne,

assu

min

g t

hat

we

no

lo

nger

can

ach

iev

e th

e 9

8 w

t% b

ott

om

s p

rod

uct

.

(b

) T

he

dis

till

ate

flo

w r

ate.

(c

) T

he

com

po

siti

on

of

the

bo

tto

ms.

An

aly

sis:

(a)

Fir

st c

on

ver

t th

e fe

ed t

o k

mo

l/h

an

d m

ole

fra

ctio

ns,

usi

ng m

ole

cula

r w

eigh

ts o

f

78

.11

fo

r b

enze

ne

and

92

.13

. T

he

resu

lt i

s:

Co

mp

on

ent

km

ol/

h

Mo

le f

ract

ion

Ben

zen

e 6

9.6

5

0.4

4

To

luen

e 8

8.5

7

0.5

6

T

ota

l:

15

8.2

2

1.0

0

Fo

r a

dis

till

ate

of

97

wt%

ben

zen

e, t

he

mo

le f

ract

ion

fo

r b

enze

ne,

th

e m

ore

vo

lati

le o

f th

e tw

o

com

po

nen

ts,

is,

xD

=

+

=

97

78

11

97

78

11

3

92

13

09

74

.

..

.

Wit

h a

ref

lux

rat

io o

f 3

.5,

fro

m E

q.

(7-7

), t

he

slo

pe

of

the

rect

ifyin

g s

ecti

on

op

erat

ing l

ine

is,

L/V

= R

/(1

+ R

) =

3.5

/4.5

= 0

.77

8

Th

e q

-lin

e is

a h

ori

zon

tal

lin

e at

y =

0.4

4.

Fo

r 1

4 p

late

s w

ith

50

% e

ffic

ien

cy,

the

colu

mn

has

th

e

equ

ival

ent

of

7 e

qu

ilib

riu

m s

tages

+ 1

fo

r th

e p

arti

al r

ebo

iler

.

Th

e M

cCab

e-T

hie

le c

on

stru

ctio

n i

s sh

ow

n o

n t

he

nex

t p

age,

wh

ere

it i

s se

en t

hat

it

is p

oss

ible

to

ob

tain

th

e d

esir

ed d

isti

llat

e co

mp

osi

tio

n.

(b)

and

(c)

F

rom

th

e M

cCab

e-T

hie

le d

iagra

m,

the

mo

le f

ract

ion

of

ben

zen

e in

th

e b

ott

om

s is

x B =

0.2

4.

A

s a

wei

gh

t fr

acti

on

, th

is c

orr

esp

on

ds

to,

02

47

81

1

02

47

81

10

76

92

13

02

11

.(

.)

.(

.)

.(

.)

.+

=w

eigh

t fr

acti

on

or

21

.1 w

t% b

enze

ne

Co

mp

ute

th

e d

isti

llat

e ra

te b

y o

ver

all

mo

lar

mat

eria

l b

alan

ces.

Ov

eral

l to

tal

mas

s b

alan

ce:

1

58

.22

= D

+ B

(1)

Ov

eral

l b

enze

ne

mas

s b

alan

ce:

6

9.6

5 =

0.9

74

D +

0.2

40

B

(2)

So

lvin

g E

qs.

(1

) an

d (

2):

D

= 4

3.1

6 k

mo

l/h

B =

11

5.0

6 k

mo

l/h

By w

eigh

t, D

= 4

3.1

6[0

.97

4(7

8.1

1)

+ 0

.02

6(9

2.1

3)]

= 3

,38

7 k

g/h

Page 45: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.15

(c

on

tin

ued

) A

na

lysi

s:

(a)

(co

nti

nu

ed)

McC

ab

e-T

hie

le D

iag

ram

Ex

erci

se 7

.16

S

ub

ject

: E

ffec

t o

n t

he

sep

arat

ion

of

A f

rom

B b

y d

isti

llat

ion

wh

en 3

of

7 t

heo

reti

cal

pla

tes

rust

an

d d

rop

to

th

e b

ott

om

of

the

colu

mn

.

Giv

en:

. C

olu

mn

has

7 t

heo

reti

cal

pla

tes

+ p

arti

al r

ebo

iler

.

Sat

ura

ted

liq

uid

fee

d o

f 1

00

km

ol/

h

of

50

mo

l% A

is

sen

t to

pla

te 5

fro

m t

he

top

. D

isti

llat

e co

nta

ins

90

mo

l% A

. T

he

L/V

= 0

.75

in

the

rect

ifyin

g s

ecti

on

. V

apo

r-li

qu

id e

qu

ilib

riu

m d

ata.

Ass

um

pti

on

s:

C

on

stan

t m

ola

r o

ver

flo

w.

To

tal

con

den

ser.

Fin

d:

Cas

e 1

: C

olu

mn

bef

ore

th

e 3

pla

tes

rust

an

d d

rop

.

(a)

Co

mp

osi

tio

n o

f th

e b

ott

om

s p

rod

uct

.

(b)

Th

e L

/V i

n t

he

stri

pp

ing s

ecti

on

.

(c)

Th

e k

mo

l/h

of

bo

tto

ms

pro

du

ct.

Cas

e 2

:

If p

late

s 5

, 6

, an

d 7

co

un

ted

do

wn

fro

m t

he

top

are

lo

st:

(a)

Co

mp

osi

tio

n o

f b

ott

om

s p

rod

uct

.

Cas

e 3

:

Sam

e as

Cas

e 2

, ex

cep

t re

pla

ce r

eflu

x w

ith

th

e sa

me

mo

lar

flo

w r

ate

of

pro

du

ct

con

tain

ing 8

0 m

ol%

A:

(a)

Co

mp

osi

tio

n o

f d

isti

llat

e.

(b)

Co

mp

osi

tio

n o

f b

ott

om

s.

An

aly

sis:

C

ase

1:

Ap

ply

th

e M

cCab

e-T

hie

le m

eth

od

in

ter

ms

of

com

po

nen

t A

, w

hic

h i

s

mo

re v

ola

tile

th

an B

. T

he

rect

ifyin

g s

ecti

on

op

erat

ing l

ine

pas

ses

thro

ugh

[0

.90

, 0

.90

] w

ith

a

slo

pe

of

0.7

5.

Th

e q

-lin

e is

ver

tica

l th

rou

gh

x =

0.5

0.

Ste

p o

ff 4

sta

ges

in

th

e re

ctif

yin

g s

ecti

on

.

Th

en,

by t

rial

an

d e

rro

r, f

ind

an

xB w

ith

a c

orr

esp

on

din

g s

trip

pin

g s

ecti

on

op

erat

ing l

ine

that

giv

es 4

eq

uil

ibri

um

sta

ges

in

th

e st

rip

pin

g s

ecti

on

. T

he

resu

lt i

s sh

ow

n o

n t

he

foll

ow

ing p

age,

wh

ere:

(a

) B

ott

om

s co

nta

ins

7 m

ol%

A a

nd

93

mo

l% B

.

(b

) T

he

slo

pe

of

the

stri

pp

ing s

ecti

on

op

erat

ing l

ine

fro

m t

he

coo

rdin

ates

of

the

lin

e is

:

{[0

.90

0.7

5(0

.90

0.5

0]

0.0

7}/(

0.5

0/

1.2

00

7)

3.

=−

−−

−=

LV

(c

) B

y m

ater

ial

bal

ance

s, F

= D

+ B

an

d

Fx F

= 5

0 =

0.9

D +

0.0

7B

. S

olv

ing t

hes

e tw

o

equ

atio

ns,

d

isti

llat

e fl

ow

rat

e =

51

.8 k

mo

l/h

an

d b

ott

om

s fl

ow

rat

e =

48

.2 k

mo

l/h

C

ase

2:

W

e n

ow

hav

e 4

eq

uil

ibri

um

sta

ges

an

d a

par

tial

reb

oil

er,

wit

h t

he

feed

bei

ng

sen

t to

th

e re

bo

iler

. A

ssu

me

that

uti

lity

rat

es a

re s

uch

th

at L

/V a

nd

L

V/ar

e th

e sa

me

as i

n C

ase

1.

Th

en,

on

th

e M

cCab

e-T

hie

le d

iagra

m,

the

val

ues

of

x D a

nd

xB m

ust

sh

ift

so t

hat

5 s

tages

are

step

ped

off

, w

ith

th

e fi

fth

, w

hic

h i

s th

e re

bo

iler

, in

ters

ecti

ng t

he

stri

pp

ing s

ecti

on

op

erat

ing l

ine

at t

he

45

o l

ine.

T

his

is

sho

wn

on

th

e M

cCab

e-T

hie

le d

iagra

m o

n t

he

foll

ow

ing p

age.

(a)

Fro

m t

his

dia

gra

m,

the

mo

le f

ract

ion

s o

f b

enze

ne

in t

he

dis

till

ate

and

bo

tto

ms

are

0.8

0 a

nd

0.2

1,

resp

ecti

vel

y.

Cas

e 3

:

Sin

ce t

he

dis

till

ate

com

po

siti

on

in

Cas

e 2

is

80

mo

l% b

enze

ne,

th

e re

sult

s w

ou

ld b

e th

e

sam

e as

Cas

e 2

if

an 8

0 m

ol%

ben

zen

e st

ream

fro

m a

no

ther

co

lum

n w

ere

use

d a

s re

flu

x.

Page 46: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.16

(c

on

tin

ued

)

A

na

lysi

s:

Cas

e 1

(c

on

tin

ued

)

Ex

erci

se 7

.16

(c

on

tin

ued

)

A

na

lysi

s:

Cas

e 2

(c

on

tin

ued

)

Page 47: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.17

S

ub

ject

: D

isti

llat

ion

of

a m

ixtu

re o

f b

enze

ne

and

to

luen

e w

ith

dif

fere

nt

feed

co

nd

itio

ns.

Giv

en:

C

olu

mn

wit

h 7

eq

uil

ibri

um

pla

tes,

to

tal

con

den

ser,

an

d p

arti

al r

ebo

iler

. F

eed

is

50

mo

l% b

enze

ne

and

50

mo

l% t

olu

ene.

O

per

atio

n a

t 1

01

kP

a to

pro

du

ce a

dis

till

ate

of

96

mo

l%

ben

zen

e.

Eq

uil

ibri

um

dat

a fr

om

Ex

erci

se 7

.13

.

Ass

um

pti

on

s:

Co

nst

ant

mo

lar

ov

erfl

ow

. U

se a

bas

is o

f 1

00

mo

l/s

for

the

feed

.

Fin

d:

(a

) F

or

a sa

tura

ted

liq

uid

fee

d s

ent

to t

ray 5

fro

m t

he

top

, (1

) m

inim

um

ref

lux

rat

io,

R =

L/D

, (2

) b

ott

om

s co

mp

osi

tio

n f

or

twic

e th

e m

inim

um

ref

lux

rat

io,

and

(3

) m

ole

s o

f p

rod

uct

s p

er

10

0 m

ole

s o

f fe

ed.

(b

) S

ame

as (

a) e

xce

pt

feed

is

satu

rate

d v

apo

r to

tra

y 5

fro

m t

he

top

.

(c

) F

or

a sa

tura

ted

vap

or

feed

to

th

e re

bo

iler

an

d a

ref

lux

rat

io,

L/V

, o

f 0

.9,

det

erm

ine,

(1

)

bo

tto

ms

com

po

siti

on

an

d (

2)

mo

les

of

pro

du

cts

per

10

0 m

ole

s o

f fe

ed.

An

aly

sis:

(a

)

(1)

Fo

r a

satu

rate

d l

iqu

id f

eed

, m

inim

um

ref

lux

co

rres

po

nd

s to

a p

inch

po

int

loca

ted

at

the

inte

rsec

tio

n o

f a

ver

tica

l q

-lin

e p

assi

ng t

hro

ugh

xF =

0.5

an

d t

he

equ

ilib

riu

m c

urv

e.

Fro

m t

he

equ

ilib

riu

m d

ata,

th

is i

nte

rsec

tio

n i

s at

y =

0.7

2 a

nd

x =

0.5

. T

hen

, th

e sl

op

e o

f th

e re

ctif

yin

g

sect

ion

op

erat

ing l

ine,

(L

/V) m

in i

s (0

.96

- 0

.72

)/(0

.96

- 0

.50

) =

0.5

22

. F

rom

a r

earr

angem

ent

of

Eq

. (7

-7),

Rm

in =

(L

/V) m

in /

[1 -

(L

/V) m

in ]

= 0

.52

2/(

1 -

0.5

22

) =

1.0

92

.

(2)

Ref

lux

rat

io =

2(1

.09

2)

= 2

.18

. F

rom

Eq

. (7

-7),

th

e sl

op

e o

f th

e re

ctif

yin

g s

ecti

on

op

erat

ing l

ine

= L

/V =

R/(

1 +

R)

= 2

.18

/3.1

8 =

0.6

86

. T

o d

eter

min

e th

e b

ott

om

s co

mp

osi

tio

n,

use

a M

cCab

e-T

hie

le d

iagra

m i

n t

erm

s o

f b

enze

ne,

th

e m

ore

vo

lati

le c

om

po

nen

t.

Th

e q

-lin

e an

d

the

rect

ifyin

g s

ecti

on

op

erat

ing l

ine

are

fix

ed a

nd

4 t

rays

are

step

ped

off

fro

m t

he

top

, st

arti

ng a

t

the

dis

till

ate

mo

le f

ract

ion

fo

r b

enze

ne,

xD ,

of

0.9

6.

Th

en,

the

stri

pp

ing s

ecti

on

op

erat

ing l

ine

is

po

siti

on

ed b

y t

rial

an

d e

rro

r so

th

at 3

mo

re s

tages

plu

s th

e re

bo

iler

sta

ge

are

step

ped

off

to

arr

ive

at t

he

po

int

wh

ere

the

assu

med

lo

cati

on

of

the

stri

pp

ing s

ecti

on

op

erat

ing l

ine

inte

rsec

ts t

he

45

o

lin

e.

Th

e re

sult

is

sho

wn

on

th

e n

ext

pag

e w

her

e it

is

seen

th

at x

B =

0.1

8.

(3)

Th

e p

rod

uct

s ar

e n

ow

co

mp

ute

d b

y o

ver

all

mat

eria

l b

alan

ces:

F

= 1

00

= D

+ B

an

d

50

= x

DD

+ x

BB

= 0

.96

D +

0.1

8B

. S

olv

ing t

hes

e tw

o e

qu

atio

ns,

D =

4

1.0

mo

l/1

00

mo

l fe

ed a

nd

B =

59

.0 m

ol/

10

0 m

ol

feed

.

Ex

erci

se 7

.17

(c

on

tin

ued

) A

na

lysi

s:

(a)

(co

nti

nu

ed)

(b

)

(

1)

Fo

r a

satu

rate

d v

apo

r fe

ed,

min

imu

m r

eflu

x c

orr

esp

on

ds

to a

pin

ch p

oin

t lo

cate

d a

t

the

inte

rsec

tio

n o

f a

ho

rizo

nta

l q

-lin

e p

assi

ng t

hro

ugh

xF =

y =

0.5

an

d t

he

equ

ilib

riu

m c

urv

e.

Fro

m t

he

equ

ilib

riu

m d

ata,

th

is i

nte

rsec

tio

n i

s at

y =

0.5

0 a

nd

x =

0.2

93

. T

hen

, th

e sl

op

e o

f th

e

rect

ifyin

g s

ecti

on

op

erat

ing l

ine,

(L

/V) m

in i

s (0

.96

- 0

.50

)/(0

.96

- 0

.29

3)

= 0

.69

0.

Fro

m a

rear

ran

gem

ent

of

Eq

. (7

-7),

Rm

in =

(L

/V) m

in /

[1 -

(L

/V) m

in ]

= 0

.69

/(1

- 0

.69

) =

2.2

3.

(2)

Ref

lux

rat

io =

2(2

.23

) =

4.4

6.

Fro

m E

q.

(7-7

), t

he

slo

pe

of

the

rect

ifyin

g s

ecti

on

op

erat

ing l

ine

= L

/V =

R/(

1 +

R)

= 4

.46

/5.4

6 =

0.8

17

. T

o d

eter

min

e th

e b

ott

om

s co

mp

osi

tio

n,

use

a M

cCab

e-T

hie

le d

iagra

m i

n t

erm

s o

f b

enze

ne,

th

e m

ore

vo

lati

le c

om

po

nen

t.

Th

e q

-lin

e an

d

the

rect

ifyin

g s

ecti

on

op

erat

ing l

ine

are

fix

ed a

nd

4 t

rays

are

step

ped

off

fro

m t

he

top

, st

arti

ng a

t

the

dis

till

ate

mo

le f

ract

ion

fo

r b

enze

ne,

xD ,

of

0.9

6.

Th

en,

the

stri

pp

ing s

ecti

on

op

erat

ing l

ine

is

Page 48: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

po

siti

on

ed b

y t

rial

an

d e

rro

r so

th

at 3

mo

re s

tages

plu

s th

e re

bo

iler

sta

ge

are

step

ped

off

to

arr

ive

at t

he

po

int

wh

ere

the

assu

med

lo

cati

on

of

the

stri

pp

ing s

ecti

on

op

erat

ing l

ine

inte

rsec

ts t

he

45

o

lin

e.

Th

e re

sult

is

sho

wn

bel

ow

, w

her

e it

is

seen

th

at x

B =

0.0

8.

Ex

erci

se 7

.17

(c

on

tin

ued

) A

na

lysi

s:

(b)

(co

nti

nu

ed

(3

) T

he

pro

du

cts

are

no

w c

om

pu

ted

by o

ver

all

mat

eria

l b

alan

ces:

F

= 1

00

= D

+ B

an

d

50

= x

DD

+ x

BB

= 0

.96

D +

0.0

8B

. S

olv

ing t

hes

e tw

o e

qu

atio

ns,

D =

4

7.7

mo

l/1

00

mo

l fe

ed a

nd

B =

52

.3 m

ol/

10

0 m

ol

feed

.

Ex

erci

se 7

.17

(c

on

tin

ued

) A

na

lysi

s:

(co

nti

nu

ed)

(c)

(

1)

A s

atu

rate

d v

apo

r fe

ed i

s fe

d t

o t

he

reb

oil

er.

Th

e sl

op

e o

f th

e re

ctif

yin

g s

ecti

on

op

erat

ing l

ine,

(L

/V),

is

0.9

. T

o d

eter

min

e th

e b

ott

om

s co

mp

osi

tio

n,

use

a M

cCab

e-T

hie

le

dia

gra

m i

n t

erm

s o

f b

enze

ne,

th

e m

ore

vo

lati

le c

om

po

nen

t.

Th

e q

-lin

e an

d t

he

rect

ifyin

g s

ecti

on

op

erat

ing l

ine

are

fix

ed a

nd

7 t

rays

are

step

ped

off

fro

m t

he

top

, s

tart

ing a

t th

e d

isti

llat

e m

ole

frac

tio

n f

or

ben

zen

e, x

D ,

of

0.9

6.

Th

en,

the

stri

pp

ing s

ecti

on

op

erat

ing l

ine

is p

osi

tio

ned

by t

rial

and

err

or

so t

hat

th

e re

bo

iler

sta

ge

is s

tep

ped

off

to

arr

ive

at t

he

po

int

wh

ere

the

assu

med

lo

cati

on

of

the

stri

pp

ing s

ecti

on

op

erat

ing l

ine

inte

rsec

ts t

he

45

o l

ine.

T

he

resu

lt i

s sh

ow

n b

elo

w,

wh

ere

it

is s

een

th

at x

B =

0.0

7.

(2)

Th

e p

rod

uct

s ar

e n

ow

co

mp

ute

d b

y o

ver

all

mat

eria

l b

alan

ces:

F

= 1

00

= D

+ B

an

d

50

= x

DD

+ x

BB

= 0

.96

D +

0.0

7B

. S

olv

ing t

hes

e tw

o e

qu

atio

ns,

D =

4

8.3

mo

l/1

00

mo

l fe

ed a

nd

B =

51

.7 m

ol/

10

0 m

ol

feed

.

Page 49: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.18

S

ub

ject

: C

on

ver

sio

n o

f a

dis

till

atio

n c

olu

mn

to

a r

ebo

iled

str

ipp

er t

o o

bta

in v

ery p

ure

tolu

ene

fro

m a

mix

ture

of

ben

zen

e an

d t

olu

ene

at 1

01

kP

a.

Giv

en:

A

co

lum

n w

ith

8 t

heo

reti

cal

pla

tes,

a t

ota

l co

nd

ense

r, a

nd

a p

arti

al r

ebo

iler

. F

eed

con

tain

s 3

6 m

ol%

ben

zen

e an

d 6

4 m

ol%

to

luen

e.

Reb

oil

er p

rod

uce

s 1

00

km

ol/

h o

f v

apo

r.

To

ob

tain

nea

rly p

ure

to

luen

e b

ott

om

s, f

eed

is

intr

od

uce

d t

o t

he

top

pla

te a

s a

satu

rate

d l

iqu

id,

wit

h

no

ref

lux

. V

apo

r-li

qu

id e

qu

ilib

riu

m d

ata

are

in E

xer

cise

7.1

3.

Ass

um

pti

on

s:

Co

nst

ant

mo

lar

ov

erfl

ow

.

Fin

d:

(a)

Min

imu

m f

eed

rat

e an

d c

orr

esp

on

din

g b

ott

om

s co

mp

osi

tio

n.

(b)

Bo

tto

ms

rate

an

d c

om

po

siti

on

fo

r a

feed

rat

e 2

5%

ab

ov

e th

e m

inim

um

.

An

aly

sis:

(a

)

T

he

min

imu

m f

eed

rat

e co

rres

po

nd

s to

a r

ate

equ

al t

o t

he

bo

ilu

p r

ate

so a

s to

giv

e an

LV/

= 1

.0.

Th

us,

th

e m

inim

um

fee

d r

ate

= 1

00

km

ol/

h.

Un

der

th

ese

con

dit

ion

s, n

o b

ott

om

s

pro

du

ct i

s w

ith

dra

wn

an

d t

he

reb

oil

er p

erfo

rms

as a

to

tal

reb

oil

er.

Th

e v

apo

r le

avin

g t

he

top

of

the

colu

mn

has

th

e sa

me

com

po

siti

on

as

the

feed

. T

her

efo

re,

we

con

sid

er o

nly

a t

ota

l o

f 8

equ

ilib

riu

m s

tages

.

In

th

e M

cCab

e-T

hie

le d

iagra

m b

elo

w,

the

stri

pp

ing s

ecti

on

op

erat

ing l

ine

is c

oin

cid

ent

wit

h t

he

45

o l

ine.

T

he

8 s

tages

are

ste

pp

ed o

ff f

rom

th

e to

p a

t y

= 0

.36

an

d x

= 0

.36

. T

he

mo

le

frac

tio

n o

f b

enze

ne

in t

he

reb

oil

er i

s fo

un

d t

o b

e 0

.00

8 f

rom

th

e lo

w c

on

cen

trat

ion

reg

ion

plo

t.

Th

eref

ore

, th

e co

rres

po

nd

ing t

olu

ene

mo

le f

ract

ion

= 0

.99

2,

wh

ich

is

qu

ite

pu

re.

No

te t

hat

2 d

iagra

ms

bel

ow

are

use

d,

wit

h t

he

seco

nd

, c

ov

erin

g t

he

stag

es a

t th

e b

ott

om

of

the

colu

mn

in

th

e lo

w c

on

cen

trat

ion

reg

ion

. T

o o

bta

in a

ccu

racy

in

th

is l

ow

-en

d r

egio

n,

the

vap

or-

liq

uid

eq

uil

ibri

um

dat

a fo

r x

= 0

.1 a

nd

x =

0.2

wer

e fi

tted

to

a q

uad

rati

c eq

uat

ion

pas

sin

g t

hro

ugh

the

ori

gin

, w

ith

th

e re

sult

, y

= 2

.35

x -

2.5

x2 .

Ex

erci

se 7

.18

(c

on

tin

ued

) A

na

lysi

s:

(a)

(c

on

tin

ued

)

Page 50: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.18

(c

on

tin

ued

) A

na

lysi

s:

(co

nti

nu

ed)

(b)

F =

Fee

d r

ate

= L

= 1

.25

(10

0)

= 1

25

km

ol/

h.

V=

Vap

or

rate

= 1

00

km

ol/

h.

Th

eref

ore

,

wit

h n

o c

on

den

ser

and

co

nst

ant

mo

lar

ov

erfl

ow

, B

= F

-V

= 1

25

- 1

00

= 2

5 k

mo

l/h

. T

he

slo

pe

of

the

stri

pp

ing s

ecti

on

op

erat

ing l

ine

= L

/V=

12

5/1

00

= 1

.25

. T

he

q-l

ine

is v

erti

cal

for

a

satu

rate

d l

iqu

id f

eed

, p

assi

ng t

hro

ugh

xF =

0.3

6.

Th

e st

rip

pin

g s

ecti

on

op

erat

ing l

ine

is

po

siti

on

ed b

y t

rial

an

d e

rro

r so

th

at 8

+ 1

eq

uil

ibri

um

sta

ges

wil

l b

e st

epp

ed o

ff.

Bec

ause

par

t (a

)

sho

ws

that

a v

ery l

ow

mo

le f

ract

ion

of

ben

zen

e is

ob

tain

ed i

n t

he

bo

tto

ms,

it

is s

usp

ecte

d t

hat

th

e

op

erat

ing l

ine

wil

l in

ters

ect

the

45

o l

ine

alm

ost

at

the

ori

gin

. I

f th

is w

ere

tru

e, t

hen

th

e o

per

atin

g

lin

e, w

ith

a s

lop

e o

f 1

.25

, w

ou

ld i

nte

rsec

t th

e v

erti

cal

q-l

ine

at 1

.25

(0.3

6)

= 0

.45

. U

se t

his

as

a

firs

t ap

pro

xim

atio

n a

nd

ad

just

it

do

wn

war

d u

nti

l o

nly

9 s

tages

can

be

step

ped

off

. T

he

fin

al

resu

lt i

s sh

ow

n i

n t

he

two

plo

ts o

n t

he

nex

t p

age,

wh

ere

the

seco

nd

plo

t is

fo

r th

e lo

w

con

cen

trat

ion

reg

ion

. A

s se

en,

the

mo

le p

erce

nt

of

ben

zen

e in

th

e b

ott

om

s =

0.0

04

, giv

ing 9

9.6

mo

l% t

olu

ene

in t

he

bo

tto

ms.

T

he

ov

erh

ead

vap

or

con

tain

s 0

.44

9 m

ole

fra

ctio

n b

enze

ne.

B

y

mat

eria

l b

alan

ces,

F =

12

5 =

D +

B

and

0.3

6F

= 0

.44

9D

+ 0

.00

4B

, D

= 1

00

.0 a

nd

B

= 2

5.0

km

ol/

h.

Ex

erci

se 7

.18

(c

on

tin

ued

) A

na

lysi

s:

(b

) (

con

tin

ued

)

Lo

w-c

on

cen

tra

tio

n R

egio

n

Page 51: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.19

S

ub

ject

: N

orm

al a

nd

ab

no

rmal

op

erat

ion

of

a d

isti

llat

ion

co

lum

n s

epar

atin

g a

met

han

ol

-

wat

er m

ixtu

re a

t 1

01

kP

a.

Giv

en:

C

olu

mn

wit

h 7

th

eore

tica

l p

late

s, a

to

tal

con

den

ser,

an

d a

par

tial

reb

oil

er.

A f

eed

of

10

0 k

mo

l/h

of

50

mo

l% m

eth

ano

l in

wat

er i

s se

nt

to p

late

3 f

rom

th

e b

ott

om

. D

uri

ng n

orm

al

op

erat

ion

, d

isti

llat

e is

90

mo

l% m

eth

ano

l an

d b

ott

om

s is

5 m

ol%

met

han

ol,

wit

h a

ref

lux

rat

e o

f

1 m

ole

per

mo

le d

isti

llat

e.

Du

rin

g a

bn

orm

al o

per

atio

n,

the

foll

ow

ing d

ata

are

ob

tain

ed:

Str

eam

k

mo

l/h

m

ol%

met

ha

no

l

Fee

d

10

0

51

Bo

tto

ms

62

1

2

Dis

till

ate

53

8

0

Ref

lux

9

4

-

Vap

or-

liq

uid

eq

uil

ibri

um

dat

a ar

e giv

en a

t 1

01

kP

a, w

her

e m

eth

ano

l is

th

e m

ore

vo

lati

le s

pec

ies.

Ass

um

pti

on

s:

Co

nst

ant

mo

lar

ov

erfl

ow

.

Fin

d:

M

ost

pro

bab

le c

ause

fo

r ab

no

rmal

op

erat

ion

.

R

eco

mm

end

ed f

urt

her

tes

ts.

If

9

0 m

ol%

met

han

ol

dis

till

ate

cou

ld b

e o

bta

ined

by i

ncr

easi

ng t

he

refl

ux

rat

io f

or

a

con

stan

t v

apo

r ra

te.

An

aly

sis:

F

irst

det

erm

ine

wh

eth

er t

he

no

rmal

op

erat

ion

can

be

ver

ifie

d b

y t

he

McC

abe-

Th

iele

met

ho

d.

Wit

h L

/D =

R =

1,

fro

m E

q.

(7-7

), t

he

slo

pe

of

the

rect

ifyin

g o

per

atin

g l

ine

= L

/V =

R/(

1 +

R)

= 1

/2 =

0.5

. A

lso

, x F

= 0

.5,

x D =

0.9

0,

and

xB =

0.0

5.

W

hat

is

no

t k

no

wn

is

the

ph

ase

con

dit

ion

of

the

feed

. I

f a

satu

rate

d l

iqu

id f

eed

is

assu

med

, giv

ing a

ver

tica

l q

-lin

e as

sh

ow

n i

n t

he

plo

t b

elo

w,

ste

pp

ing s

tages

up

fro

m t

he

bo

tto

m,

wit

h t

he

feed

sta

ge

to p

late

3 f

rom

th

e b

ott

om

, le

ss t

han

2 t

heo

reti

cal

pla

tes

are

nee

ded

in

th

e

rect

ifyin

g s

ecti

on

, w

hil

e 4

are

pre

sen

t.

Th

e co

nst

ruct

ion

is

sho

wn

on

th

e n

ext

pag

e.

Th

eref

ore

, it

ap

pea

rs t

hat

th

e fe

ed i

s n

ot

a sa

tura

ted

liq

uid

, b

ut

is p

arti

ally

vap

ori

zed

.

Ex

erci

se 7

.19

(c

on

tin

ued

) A

na

lysi

s:

No

rmal

Op

erat

ion

(co

nti

nu

ed)

B

y t

rial

an

d e

rro

r, u

sin

g q

-lin

es o

f v

ario

us

slo

pes

, th

e fo

llo

win

g M

cCab

e-T

hie

le d

iagra

m i

s

con

sist

ent

wit

h t

he

giv

en d

ata.

It

sh

ow

s a

q-l

ine

wit

h a

slo

pe

of

-0.3

4.

s

lop

e =

/(

1)

T

her

efo

re,

slo

pe/

(slo

pe-

1)=

-0

m

.34

/(-0

.34

-1.0

)=0

.25

Fro

m E

q.

(7-1

9o

lar

frac

tio

n v

apo

rize

),

= 1

d0

.7.

51

02

5

=

−=

−=

qq

q

q

Page 52: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.19

(c

on

tin

ued

) A

na

lysi

s:

No

rmal

op

erat

ion

(c

on

tin

ued

)

T

he

mat

eria

l b

alan

ce f

or

the

no

rmal

op

erat

ion

is

as f

oll

ow

s, u

sin

g t

he

ov

eral

l b

alan

ces,

F =

10

0 =

D +

B

and

0

.5F

= 0

.5(1

00

) =

50

= x

DD

+ x

BB

= 0

.90

D +

0.0

5B

.

Str

eam

k

mo

l/h

m

ol%

met

ha

no

l

Fee

d

10

0

50

Bo

tto

ms

47

.06

5

Dis

till

ate

52

.94

9

0

Ref

lux

5

2.9

4

90

Ex

erci

se 7

.19

(c

on

tin

ued

) A

na

lysi

s:

Ab

no

rmal

op

erat

ion

F

or

the

abn

orm

al o

per

atio

n,

firs

t ch

eck

th

e o

ver

all

tota

l m

ater

ial

bal

ance

usi

ng t

he

giv

en

dat

a.

F =

10

0 k

mo

l/h

.

D +

B =

53

+ 6

2 =

11

5 k

mo

l/h

. T

her

efo

re,

it a

pp

ears

th

at w

e h

ave

11

5 -

10

0 =

15

km

ol/

h m

ore

flo

w o

ut

of

the

dis

till

atio

n s

yst

em.

No

w c

hec

k t

he

met

han

ol

ov

eral

l

mat

eria

l b

alan

ce u

sin

g t

he

giv

en d

ata.

M

eth

ano

l fl

ow

rat

e in

= 0

.51

(10

0)

= 5

1 k

mo

l/h

. M

eth

ano

l

flo

w r

ate

ou

t =

0.8

0(5

3)

+ 0

.12

(62

) =

49

.84

km

ol/

h.

Th

eref

ore

, th

e m

eth

ano

l b

alan

ce i

s cl

ose

,

wit

h o

nly

ab

ou

t a

2%

dis

crep

ancy

. N

ow

ch

eck

th

e w

ater

ov

eral

l m

ater

ial

bal

ance

usi

ng t

he

giv

en

dat

a.

Wat

er f

low

in

= 0

.49

(10

0)

= 4

9 k

mo

l/h

. W

ater

flo

w o

ut

= 0

.20

(53

) +

0.8

8(6

2)

= 6

5.1

6

km

ol/

h.

Th

eref

ore

, w

e h

ave

65

.16

- 4

9 =

16

.16

km

ol/

h m

ore

wat

er o

ut

than

in

. T

his

is

a

sign

ific

ant

dis

crep

ancy

. I

t ap

pea

rs c

erta

in t

hat

wat

er i

s le

akin

g i

nto

th

e d

isti

llat

ion

syst

em.

Tw

o

po

ssib

ilit

ies

are:

(1

) le

akag

e o

f co

nd

ense

r co

oli

ng w

ater

in

to t

he

con

den

sate

, o

r (2

) le

akag

e o

f

reb

oil

er s

team

in

to t

he

bo

ilu

p v

apo

r.

A r

ebo

iler

ste

am l

eak

may

no

t b

e se

rio

us

bec

ause

th

e st

eam

mig

ht

no

t get

to

th

e to

p o

f th

e co

lum

n t

o d

ilu

te t

he

met

han

ol

pro

du

ct.

A c

on

den

ser

coo

lin

g w

ater

leak

co

uld

be

ver

y s

erio

us

bec

ause

par

t o

f it

wo

uld

en

d u

p i

n t

he

dis

till

ate,

th

ereb

y d

ilu

tin

g t

he

met

han

ol

pro

du

ct.

Bec

ause

of

the

imp

ure

met

han

ol

dis

till

ate

for

the

abn

orm

al o

per

atio

n,

it

app

ears

th

at a

co

nd

ense

r co

oli

ng w

ater

lea

k i

s th

e fa

ult

. C

hec

k t

his

nex

t.

W

e n

ote

th

at t

he

dis

till

ate

flo

w r

ate

for

the

abn

orm

al o

per

atio

n i

s al

mo

st e

xac

tly t

he

sam

e

as t

hat

fo

r th

e n

orm

al o

per

atio

n.

A f

low

rat

e eq

ual

to

th

at o

f h

e le

akag

e p

asse

s o

ut

the

bo

tto

m o

f

the

colu

mn

. I

n n

orm

al o

per

atio

n,

the

wat

er p

assi

ng o

ut

in t

he

dis

till

ate

= 0

.1(5

3)

= 5

.3 k

mo

l/h

,

wh

ile

for

the

abn

orm

al o

per

atio

n,

the

wat

er p

assi

ng o

ut

in t

he

dis

till

ate

= 0

.2(5

3)

= 1

0.6

km

ol/

h.

Th

us,

an

ad

dit

ion

al 5

.3 k

mo

l/h

of

wat

er l

eav

es i

n t

he

dis

till

ate.

F

or

the

abn

orm

al o

per

atio

n,

the

ov

erh

ead

vap

or

rate

= 5

3 +

94

= 1

47

km

ol/

h a

nd

, th

eref

ore

, 5

3/1

47

x 1

00

% =

36

% o

f th

e

ov

erh

ead

vap

or

(to

tal

con

den

sate

) is

dis

till

ate.

T

hu

s, i

f 1

5 k

mo

l/h

of

wat

er l

eak

ed i

nto

th

e

ov

erh

ead

vap

or,

th

en,

we

wo

uld

ex

pec

t 0

.36

(15

) =

5.4

km

ol/

h w

ou

ld b

e ex

pec

ted

to

lea

ve

wit

h

the

dis

till

ate.

T

his

co

mp

ares

ver

y w

ell

wit

h t

he

5.3

km

ol/

h a

dd

itio

nal

wat

er c

alcu

late

d a

bo

ve

by

mat

eria

l b

alan

ce.

If

the

deg

ree

of

frac

tio

nat

ion

wit

hin

th

e co

lum

n i

s ab

ou

t th

e sa

me

as f

or

the

no

rmal

op

erat

ion

, it

co

uld

be

con

clu

ded

th

at a

co

nd

ense

r co

oli

ng w

ater

lea

k i

s to

bla

me.

T

o c

hec

k t

he

coo

lin

g w

ater

lea

k,

cou

ld m

eter

th

e co

oli

ng w

ater

in

an

d o

ut

of

the

con

den

ser

and

see

if

ther

e is

a d

iffe

ren

ce.

If

th

e v

apo

r ra

te i

s k

ept

con

stan

t an

d t

he

refl

ux

rat

e is

in

crea

sed

, th

en t

he

dis

till

ate

rate

mu

st b

e d

ecre

ased

. A

ssu

me

a v

apo

r ra

te o

f 1

47

km

ol/

h,

wit

h 3

0 k

mo

l/h

to

dis

till

ate

and

11

7

km

ol/

h t

o r

eflu

x.

Th

en,

30

/11

7 x

10

0%

= 2

5.6

% o

f th

e o

ver

hea

d v

apo

r is

dis

till

ate.

T

her

efo

re,

the

wat

er l

eak

to

th

e d

isti

llat

e w

ou

ld b

e 0

.25

6(1

5)

= 3

.84

km

ol/

h.

If

the

frac

tio

nat

ion

wer

e

oth

erw

ise

the

sam

e as

fo

r n

orm

al o

per

atio

n s

o t

hat

th

e o

ver

hea

d v

apo

r w

as 9

0 m

ol%

met

han

ol,

the

dil

uti

on

wit

h l

eak

age

wo

uld

res

ult

in

0.1

(30

- 3

.84

) +

3.8

4 =

6.4

6 k

mo

l/h

of

wat

er i

n 3

0

km

ol/

h.

Th

us,

met

han

ol

pu

rity

= (

30

- 6

.46

)/3

0 x

10

0%

= 7

8.5

mo

l%.

Ho

wev

er,

the

hig

her

refl

ux

rat

io w

ou

ld i

ncr

ease

th

e fr

acti

on

atio

n,

so a

s to

in

crea

se t

he

pu

rity

ab

ov

e th

is v

alu

e.

A

furt

her

in

crea

se i

n f

ract

ion

atio

n c

ou

ld b

e ac

hie

ved

, if

th

e fe

ed w

ere

con

den

sed

to

a s

atu

rate

d

liq

uid

an

d a

dd

itio

nal

hea

t w

as t

ran

sfer

red

in

th

e re

bo

iler

. B

ut,

ev

en i

f a

pu

re m

eth

ano

l o

ver

hea

d

vap

or

wer

e ac

hie

ved

, th

e m

eth

ano

l p

uri

ty a

fter

dil

uti

on

wit

h t

he

wat

er l

eak

age

wo

uld

be

:

(30

- 3

.84

)/3

0 x

10

0%

= 8

7.2

mo

l% m

eth

ano

l.

Mu

st e

lim

inat

e th

e le

ak.

Page 53: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.20

S

ub

ject

: E

ffec

t o

n r

eflu

x a

nd

bo

ilu

p c

om

po

siti

on

s o

f re

du

cin

g t

he

feed

rat

e to

a d

isti

llat

ion

colu

mn

wh

en t

he

refl

ux

an

d b

oil

up

rat

e ar

e h

eld

co

nst

ant

Giv

en:

C

olu

mn

wit

h 3

th

eore

tica

l p

late

s, a

to

tal

con

den

ser,

an

d a

par

tial

reb

oil

er.

Fee

d i

s a

satu

rate

d l

iqu

id o

f 5

0 m

ol%

A a

nd

50

mo

l% B

, fe

d t

o t

he

bo

tto

m t

ray.

A

t a

feed

rat

e o

f 1

00

km

ol/

h,

des

ired

pro

du

cts

of

dis

till

ate

wit

h 9

0 m

ol%

A a

nd

bo

tto

ms

of

20

mo

l% A

can

be

ach

iev

ed,

wh

en a

ref

lux

co

rres

po

nd

ing t

o L

/V =

0.7

5 i

s u

sed

. R

elat

ive

vo

lati

lity

of

A t

o B

is

con

stan

t at

3.0

.

Ass

um

pti

on

s:

Co

nst

ant

mo

lar

ov

erfl

ow

.

Sat

ura

ted

liq

uid

ref

lux

.

Fin

d:

C

om

po

siti

on

s o

f re

flu

x a

nd

bo

ilu

p w

hen

fee

d r

ate

is i

nad

ver

ten

tly r

edu

ced

to

25

km

ol/

h,

wh

ile

kee

pin

g t

he

refl

ux

an

d b

oil

up

flo

w r

ates

co

nst

ant.

An

aly

sis:

F

irst

, v

erif

y t

he

sep

arat

ion

fo

r a

feed

rat

e o

f 1

00

km

ol/

h.

Th

is i

s sh

ow

n i

n t

he

McC

abe-

Th

iele

plo

t b

elo

w i

n t

erm

s o

f m

ole

fra

ctio

ns

of

A,

the

mo

re v

ola

tile

co

mp

on

ent.

T

he

equ

ilib

riu

m c

urv

e is

co

mp

ute

d f

rom

Eq

. (7

-3),

yx

x

x

x=

+−

=+

α α1

1

3

12

()

Th

e giv

en m

ole

fra

ctio

ns

are:

x F

= 0

.50

x D

= 0

.90

x B

= 0

.20

Th

e re

ctif

icat

ion

sec

tio

n o

per

atin

g l

ine

has

a s

lop

e o

f 0

.75

an

d p

asse

s th

rou

gh

po

int

{0

.9,

0.9

}.

Th

e q

-lin

e is

ver

tica

l at

x =

0.5

. T

he

plo

t sh

ow

s al

mo

st p

erfe

ct a

gre

emen

t w

ith

th

e d

esir

ed

sep

arat

ion

fo

r a

feed

rat

e o

f 1

00

km

ol/

h.

Ex

erci

se 7

.20

(c

on

tin

ued

) A

na

lysi

s:

(co

nti

nu

ed)

Fo

r th

e b

ase

case

of

F =

10

0 k

mo

l/h

, th

e m

ater

ial

bal

ance

eq

uat

ion

s ar

e

F =

D +

B

and

x

FF

= 5

0 =

xDD

+ x

BB

= 0

.90

D +

0.2

0B

. S

olv

ing,

thes

e eq

uat

ion

s, a

lon

g w

ith

V =

L +

D,

V/L

= 0

.75

, V

VL

LF

==

+,

and

, g

ives

th

e fo

llo

win

g r

esu

lts:

Str

eam

F

low

ra

te,

km

ol/

h

Mo

l% A

M

ol%

B

Fee

d

10

0.0

0

50

5

0

Dis

till

ate

4

2.8

6

90

1

0

Bo

tto

ms

5

7.1

4

20

8

0

Ref

lux

, L

1

28

.58

Ov

erh

ead

vap

or,

V

17

1.4

4

Liq

uid

to

reb

oil

er,

L

22

8.5

8

Vap

or

fro

m r

ebo

iler

, V

1

71

.44

W

hen

th

e fe

ed r

ate

is r

edu

ced

to

25

km

ol/

h,

the

refl

ux

rat

e, L

, is

mai

nta

ined

at

12

8.5

8

km

ol/

h a

nd

th

e b

oil

up

, V

, is

mai

nta

ined

at

17

1.4

4 k

mo

l/h

. T

her

efo

re b

y m

ater

ial

bal

ance

s,

L=

L +

F =

12

8.5

8 +

25

= 1

53

.58

an

d B

= L

-V=

15

3.5

8 -

17

1.4

4 =

-1

7.8

6 k

mo

l/h

. T

his

is

imp

oss

ible

. T

her

efo

re,

the

colu

mn

can

no

t b

e o

per

ated

wit

h t

he

sam

e b

oil

up

rat

e.

Th

at r

ate

wo

uld

hav

e to

be

red

uce

d t

o a

chie

ve

a d

esir

ed b

ott

om

s ra

te,

e. g

. th

e 5

7.1

4 %

of

the

feed

, as

in

the

bas

e ca

se o

r 0

.57

14

(25

) =

14

.29

km

ol/

h.

If

this

wer

e d

on

e, w

e w

ou

ld n

ow

hav

e, V

=L

- B

=

15

3.5

8 -

14

.29

= 1

39

.29

km

ol/

h =

V.

Th

us,

in

th

e re

ctif

yin

g s

ecti

on

, L

/V =

12

8.5

8/1

39

.29

=

0.9

23

an

d i

n t

he

stri

pp

ing s

ecti

on

, L

/V=

15

3.5

8/1

39

.29

= 1

.10

3.

Th

e re

sult

ing d

isti

llat

e an

d

bo

tto

ms

com

po

siti

on

s ar

e d

eter

min

ed b

y p

osi

tio

nin

g t

he

op

erat

ing l

ines

so

th

at 3

sta

ges

+ a

reb

oil

er c

an b

e st

epp

ed o

ff.

Th

e re

sult

is

sho

wn

bel

ow

, w

her

e th

e m

ole

fra

ctio

ns

of

A a

re 0

.93

in

the

dis

till

ate

and

ref

lux

, 0

.18

in

th

e b

ott

om

s, a

nd

0.3

8 i

n t

he

reb

oil

er v

apo

r.

Page 54: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.20

(c

on

tin

ued

) A

na

lysi

s:

(co

nti

nu

ed)

Ex

erci

se 7

.21

Su

bje

ct:

Dis

till

atio

n o

f a

satu

rate

d v

apo

r o

f m

alei

c an

hyd

rid

e (A

) an

d b

enzo

ic a

cid

(B

)

un

der

vac

uu

m a

t 1

3.3

kP

a.

Giv

en:

F

eed

co

nta

ins

90

mo

l% A

an

d 1

0 m

ol%

B.

Dis

till

ate

to c

on

tain

99

.5 m

ol%

an

hyd

rid

e

and

bo

tto

ms

to c

on

tain

0.5

mo

l% a

cid

. V

apo

r p

ress

ure

dat

a.

Ass

um

pti

on

s:

Rao

ult

's l

aw t

o c

om

pu

te K

-val

ues

fro

m v

apo

r p

ress

ure

dat

a.

Co

nst

ant

mo

lar

ov

erfl

ow

.

Fin

d:

N

um

ber

of

theo

reti

cal

pla

tes

nee

ded

if

a re

flu

x r

atio

, L

/D =

1.6

tim

es m

inim

um

.

An

aly

sis:

F

irst

co

mp

ute

an

eq

uil

ibri

um

y,

x cu

rve

usi

ng R

aou

lt's

law

wit

h t

he

vap

or

pre

ssu

re

dat

a.

Eq

. (2

-44

) a

pp

lies

, as

wel

l as

th

e su

m o

f th

e m

ole

fra

ctio

ns

in t

he

ph

ases

in

eq

uil

ibri

um

.

Th

us,

Ky x

PT

PK

y x

PT

P

yy

xx

ss

AA A

A

BB B

B

AB

AB

,

(1

, 2

)

,

(3

, 4

)

==

==

+=

+=

��

��

11

E

qu

atio

ns

(1)

to (

4)

can

be

red

uce

d t

o t

he

foll

ow

ing e

qu

atio

ns

for

the

mo

le f

ract

ion

s o

f

mal

eic

anh

yd

rid

e (A

) in

ter

ms

of

the

K-v

alu

es:

xK

KK

yK

xA

B

AB

AA

A

,

=− −

=1

(5,

6)

If t

he

giv

en v

apo

r p

ress

ure

dat

a ar

e fi

tted

to

An

toin

e eq

uat

ion

s, w

e o

bta

in:

PT

PT

s sA B

(

7)

(8

)

=−

+

� ��� ��

=−

+

� ��� ��

exp

.. .

exp

.. .

16

65

41

40

88

12

20

39

24

23

01

55

93

36

97

32

14

34

Wh

ere

vap

or

pre

ssu

re i

s in

to

rr a

nd

tem

per

atu

re i

s in

oC

. S

olv

ing,

Eq

s. (

1)

to (

8),

In s

olv

ing t

he

equ

atio

ns,

P =

13

.3 k

Pa

or

99

.8 t

orr

. T

he

resu

lts

are

tab

ula

ted

on

th

e n

ext

pag

e.

Bel

ow

th

e ta

ble

is

a M

cCab

e-T

hie

le p

lot

of

y A v

ersu

s x A

fo

r d

eter

min

ing t

he

min

imu

m r

eflu

x f

or

x D =

0.9

95

an

d a

ho

rizo

nta

l q

-lin

e at

y =

0.9

0,

wh

ich

in

ters

ects

th

e eq

uil

ibri

um

cu

rve

at

x =

0.5

72

. T

her

efo

re,

the

slo

pe

of

the

rect

ifyin

g s

ecti

on

op

erat

ing l

ine

at m

inim

um

ref

lux

is

(L/V

) min

= (

0.9

95

- 0

.90

)/(0

.99

5 -

0.5

72

) =

0.2

25

. F

rom

a r

earr

angem

ent

of

Eq

. (7

-7),

Rm

in =

(L

/V) m

in/[

1 -

(L

/V) m

in]

= 0

.22

5/(

1-0

.22

5)

= 0

.29

0.

Th

eref

ore

, th

e re

flu

x r

atio

fo

r o

per

atio

n

= 1

.6R

min

= 1

.6(0

.29

0)

= 0

.46

4.

Page 55: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.21

(c

on

tin

ued

) A

na

lysi

s:

(c

on

tin

ued

)

T,

oC

P

s of

A,

torr

Ps o

f B

, to

rr

KA

K

B

xA

y A

13

5.3

99

.8

13

.1

1.0

00

0

.13

1

1.0

00

1

.00

0

13

6.5

10

4.1

1

3.8

1

.04

3

0.1

38

0

.95

3

0.9

93

1

37

.8

1

08

.9

14

.6

1.0

92

0

.14

7

0.9

03

0

.98

6

14

0.3

11

8.8

1

6.3

1

.19

1

0.1

64

0

.81

4

0.9

70

1

42

.8

1

29

.5

18

.2

1.2

97

0

.18

3

0.7

33

0

.95

1

14

5.3

14

0.9

2

0.3

1

.41

1

0.2

03

0

.65

9

0.9

31

1

47

.8

1

53

.1

22

.6

1.5

34

0

.22

6

0.5

92

0

.90

8

15

0.3

16

6.2

2

5.1

1

.66

5

0.2

51

0

.53

0

0.8

82

1

52

.8

1

80

.2

27

.9

1.8

05

0

.27

9

0.4

72

0

.85

3

15

7.8

21

1.1

3

4.2

2

.11

5

0.3

43

0

.37

1

0.7

84

1

60

.3

2

28

.1

37

.8

2.2

86

0

.37

9

0.3

26

0

.74

4

16

2.8

24

6.3

4

1.8

2

.46

8

0.4

19

0

.28

4

0.7

00

1

65

.3

2

65

.6

46

.2

2.6

61

0

.46

3

0.2

44

0

.65

0

16

7.8

28

6.1

5

0.9

2

.86

7

0.5

10

0

.20

8

0.5

96

1

70

.3

3

07

.9

56

.1

3.0

85

0

.56

2

0.1

73

0

.53

5

17

2.8

33

1.1

6

1.8

3

.31

7

0.6

19

0

.14

1

0.4

68

1

75

.3

3

55

.6

68

.0

3.5

63

0

.68

1

0.1

11

0

.39

5

17

7.8

38

1.6

7

4.7

3

.82

4

0.7

48

0

.08

2

0.3

13

1

80

.3

4

09

.2

81

.9

4.1

00

0

.82

1

0.0

55

0

.22

4

18

2.8

43

8.3

8

9.9

4

.39

2

0.9

01

0

.02

8

0.1

25

1

85

.3

4

69

.1

98

.5

4.7

01

0

.98

7

0.0

04

0

.01

7

18

5.7

47

4.2

9

9.9

4

.75

1

1.0

01

0

.00

0

0.0

00

Ex

erci

se 7

.21

(c

on

tin

ued

) A

na

lysi

s:

(c

on

tin

ued

)

Page 56: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.21

(c

on

tin

ued

)

A

na

lysi

s:

(c

on

tin

ued

)

N

ow

det

erm

ine

the

tray

req

uir

emen

ts f

or

actu

al o

per

atio

n.

Usi

ng E

q.

(7-7

), w

ith

th

e

op

erat

ing r

eflu

x r

atio

of

0.4

64

, L

/V =

R/(

1 +

R)

= 0

.46

4/(

1 +

0.4

64

) =

0.3

17

. B

ecau

se s

uch

hig

h

pu

rity

dis

till

ate

and

bo

tto

ms

pro

du

cts

are

to o

bta

ined

, u

se 3

McC

abe-

Th

iele

dia

gra

ms.

T

he

firs

t

dia

gra

m i

s fo

r th

e h

igh

pu

rity

reg

ion

of

com

po

nen

t A

fro

m y

an

d x

= 0

.9 t

o 1

.0.

Th

e o

per

atin

g

lin

e fo

r th

e re

ctif

yin

g s

ecti

on

beg

ins

at {

0.9

95

, 0

.99

5} a

nd

, w

ith

a s

lop

e o

f 0

.31

7,

inte

rsec

ts t

he

ver

tica

l ax

is f

or

x =

0.9

0 a

t y

= 0

.96

5.

Th

e en

tire

reg

ion

is

cov

ered

in

th

e se

con

d d

iagra

m,

the

feed

sta

ge

is l

oca

ted

op

tim

ally

. T

he

low

co

nce

ntr

atio

n r

egio

n i

s co

ver

ed i

n t

he

thir

d d

iagra

m.

Fro

m t

hes

e th

ree

dia

gra

ms,

it

is s

een

th

at 8

th

eore

tica

l p

late

s p

lus

a p

arti

al r

ebo

iler

are

nee

ded

.

Th

e fe

ed i

s se

nt

to p

late

4 f

rom

th

e to

p.

Ex

erci

se 7

.21

(c

on

tin

ued

) A

na

lysi

s:

(c

on

tin

ued

)

Page 57: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.21

(c

on

tin

ued

) A

na

lysi

s:

(c

on

tin

ued

)

Ex

erci

se 7

.22

S

ub

ject

: D

isti

llat

ion

of

a m

ixtu

re o

f A

an

d B

bas

ed o

n b

oil

up

, ra

ther

th

an r

eflu

x,

req

uir

emen

ts.

Giv

en:

A

bu

bb

le-p

oin

t fe

ed m

ixtu

re o

f 5

mo

l% A

an

d 9

5 m

ol%

B.

Dis

till

ate

to c

on

tain

35

mo

l% A

an

d a

bo

tto

ms

to c

on

tain

0.2

mo

l% A

. R

elat

ive

vo

lati

lity

, α

A,B

= 6

= a

co

nst

ant.

Co

lum

n e

qu

ipp

ed w

ith

par

tial

co

nd

ense

r an

d p

arti

al r

ebo

iler

.

Ass

um

pti

on

s:

C

on

stan

t m

ola

r o

ver

flo

w.

Fin

d:

U

sin

g a

lgeb

raic

met

ho

ds,

(a)

Min

imu

m n

um

ber

of

equ

ilib

riu

m s

tages

.

(b

) M

inim

um

bo

ilu

p r

atio

, V

B =

VB

/.

(c

) N

um

ber

of

equ

ilib

riu

m s

tages

fo

r a

bo

ilu

p r

atio

= 1

.2 t

imes

min

imu

m.

An

aly

sis:

F

rom

a r

earr

angem

ent

of

the

equ

ilib

riu

m e

qu

atio

n,

Eq

. (7

-3),

xy

yy

y

y=

+−

=−

α(

)1

65

(1

)

(a

) F

or

min

imu

m s

tages

, h

ave

tota

l re

flu

x,

so t

hat

y =

x f

or

pas

sin

g s

trea

ms.

B

egin

calc

ula

tio

ns

fro

m t

he

top

. y

D =

y1 =

0.3

5.

Fro

m E

q.

(1),

x1 =

0.3

5/[

6 -

5(0

.35

)] =

0.0

82

4.

Th

eref

ore

, y 2

= x

1 =

0.0

82

4.

Fro

m E

q.

(1),

x2 =

0.0

82

4/[

6-5

(0.0

82

4)]

= 0

.01

47

. T

her

efo

re,

y 3 =

x2 =

0.0

14

7.

Fro

m E

q.

(1),

x3 =

0.0

14

7/[

6-5

(0.0

14

7)]

= 0

.00

25

. T

his

is

clo

se t

o b

ut

no

t

qu

ite

equ

al t

o t

he

des

ired

val

ue

of

0.0

02

. T

hu

s, w

e n

eed

ju

st s

ligh

tly m

ore

th

an 3

min

imu

m

equ

ilib

riu

m s

tages

.

(b)

Fo

r m

inim

um

bo

ilu

p r

atio

, th

e st

rip

pin

g s

ecti

on

op

erat

ing l

ine

con

nec

ts t

he

two

po

ints

fo

r {y,

x} o

f {0

.00

2,

0.0

02

} a

nd

{y

in e

qu

ilib

riu

m w

ith

x =

0.0

5}.

Fro

m a

rea

rran

gem

ent

of

Eq

. (1

), t

he

y in

eq

uil

ibri

um

wit

h x

= 0

.05

is:

y

= α

x/[1

+

x(α

− 1

)] =

6(0

.05

)/[1

+ 0

.05

(6 −

1)]

= 0

.24

. T

he

slo

pe

of

the

op

erat

ing l

ine

= (

LV/

) =

(0

.24

-

0.0

02

)/(0

.05

- 0

.00

2)

= 4

.96

. F

rom

a r

earr

angem

ent

of

Eq

. (7

-12

), (

VB) m

in =

1/

[(L

V/)

- 1

] =

1/(

4.9

6 -

1)

= 0

.25

3.

(c)

Th

e b

oil

up

rat

io =

VB =

1.2

(0.2

53

) =

0.3

03

6.

Fro

m E

q.

(7-1

2),

th

e sl

op

e o

f th

e

stri

pp

ing s

ecti

on

op

erat

ing l

ine

= L

V/=

(V

B +

1)/

VB =

(0

.30

36

+ 1

)/0

.30

36

= 4

.29

4.

Th

is l

ine

inte

rsec

ts t

he

ver

tica

l q

-lin

e (x

F

= 0

.05

) at

0.0

02

+ 4

.29

4(0

.05

- 0

.00

2)

= 0

.20

81

. T

her

efo

re,

the

slo

pe

of

the

rect

ifyin

g l

ine

= L

/V =

(0

.35

- 0

.20

81

)/(0

.35

- 0

.05

) =

0.4

73

0.

Fro

m a

rea

rran

gem

ent

of

Eq

. (7

-8),

R =

(L

/V)/

[1 -

(L

/V)]

= 0

.47

3/(

1 -

0.4

73

) =

0.8

97

5.

Th

e eq

uat

ion

fo

r th

e re

ctif

yin

g

sect

ion

op

erat

ing l

ine,

usi

ng E

q.

((7

-9),

wit

h a

mo

dif

icat

ion

fo

r a

par

tial

co

nd

ense

r as

det

erm

ined

fro

m F

ig.

7.1

8,

is,

y

R

Rx

Ry

xn

nD

n+

=+

� ��� ��

++

� ��� ��

=+

11

1

10

47

30

18

4.

.5

(2)

Page 58: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.22

(c

on

tin

ued

) A

na

lysi

s:

(c)

(c

on

tin

ued

)

Th

e eq

uat

ion

fo

r th

e st

rip

pin

g s

ecti

on

op

erat

ing l

ine,

usi

ng E

q.

(7-1

2)

is,

y

V

Vx

Vx

xm

B

B

m

B

Bm

+=

+� ��� ��

−� ��� ��

=−

1

11

42

94

00

06

59

..

(3)

We

can

no

w c

alcu

late

sta

ge

by s

tage

do

wn

fro

m t

he

top

, st

arti

ng f

rom

yD =

0.3

5,

alte

rnat

ing

bet

wee

n t

he

equ

ilib

riu

m c

urv

e, E

q.

(1)

and

th

e ap

pro

pri

ate

op

erat

ing l

ine,

Eq

. (2

) o

r (3

).

We

beg

in u

sin

g E

q.

(2),

bu

t sw

itch

to

Eq

. (3

), w

hen

x <

xF =

0.0

5.

Th

e ca

lcu

lati

on

s ar

e te

rmin

ated

wh

en x

< x

B =

0.0

02

. T

he

calc

ula

tio

ns

can

be

do

ne

wit

h a

sp

read

shee

t, w

ith

th

e fo

llo

win

g

resu

lts,

giv

en a

s m

ole

fra

ctio

ns

of

A l

eav

ing a

n e

qu

ilib

riu

m s

tage.

T

he

op

tim

al f

eed

sta

ge

is t

he

top

pla

te.

Eq

uil

ibri

um

sta

ge

y A

xA

Par

tial

co

nd

ense

r 0

.35

0

0.0

82

4

1

0.2

23

0

.04

58

2

0.1

90

0

.03

76

3

0.1

55

0

.02

96

4

0.1

21

0

.02

24

5

0

.08

94

0

.01

61

6

0

.06

26

0

.01

10

7

0

.04

07

0.0

07

01

8

0

.02

35

0.0

04

00

Par

tial

reb

oil

er

0

.01

06

0.0

01

78

Th

e ca

lcu

lati

on

s sh

ow

th

at b

esid

es t

he

par

tial

co

nd

ense

r an

d p

arti

al r

ebo

iler

, 8

eq

uil

ibri

um

sta

ges

are

nee

ded

in

th

e co

lum

n.

Ex

erci

se 7

.23

S

ub

ject

: D

isti

llat

ion

of

a m

ixtu

re o

f m

eth

ano

l an

d w

ater

wit

h a

su

bco

ole

d l

iqu

id f

eed

.

Giv

en:

L

iqu

id f

eed

of

14

,46

0 k

g/h

met

han

ol

and

10

,44

0 k

g/h

wat

er a

t q

= 1

.12

. D

isti

llat

e o

f 9

9

mo

l% m

eth

ano

l an

d a

bo

tto

ms

of

99

mo

l% w

ater

are

des

ired

. C

olu

mn

has

a t

ota

l co

nd

ense

r an

d

a p

arti

al r

ebo

iler

. O

per

atio

n a

t 1

atm

wit

h a

ref

lux

rat

io o

f L

/D =

R =

1.0

. V

apo

r-li

qu

id

equ

ilib

riu

m d

ata

in E

xer

cise

of

7.1

9.

Ass

um

pti

on

s:

Co

nst

ant

mo

lar

ov

erfl

ow

.

Fin

d:

F

eed

sta

ge

loca

tio

n a

nd

nu

mb

er o

f eq

uil

ibri

um

sta

ges

.

An

aly

sis:

F

irst

, d

eter

min

e fe

ed c

om

po

siti

on

in

mo

l%.

Usi

ng m

ole

cula

r w

eigh

ts o

f 3

2.0

4 f

or

met

han

ol

and

18

.02

fo

r w

ater

,

Co

mp

on

ent

kg

/h

km

ol/

h

Mo

l%

Met

han

ol

14

,46

0

4

51

.3

4

3.7

9

Wat

er

10

,44

0

5

79

.4

5

6.2

1

T

ota

l:

24

,90

0

1,0

30

.7

10

0.0

0

Usi

ng t

he

vap

or-

liq

uid

eq

uil

ibri

um

dat

a, a

y-x

plo

t fo

r th

e M

cCab

e-T

hie

le m

eth

od

is

mad

e an

d

smo

oth

ed w

ith

a s

pre

adsh

eet,

no

tin

g t

hat

met

han

ol

is t

he

mo

re v

ola

tile

. T

her

efo

re,

x F =

0.4

37

9,

x D =

0.9

9,

xB =

0.0

1.

Fro

m E

q.

(7-2

6),

slo

pe

of

q-l

ine

= q

/(q

- 1

) =

1.1

2/(

1.1

2 -

1)

= 9

.33

3.

Th

eref

ore

, o

n t

he

McC

abe-

Th

iele

dia

gra

m,

a li

ne

is d

raw

n w

ith

a s

lop

e o

f 9

.33

3 t

hat

in

ters

ects

th

e p

oin

t {0

.43

8,0

.43

8}.

Fro

m E

q.

(7-7

), t

he

slo

pe

of

the

rect

ifyin

g s

ecti

on

op

erat

ing l

ine

= L

/V =

R/(

R +

1)

= 1

/(1

+ 1

) =

0.5

. T

his

lin

e is

dra

wn

on

th

e M

cCab

e-T

hie

le d

iagra

m w

ith

a s

lop

e o

f 0

.5 t

hat

in

ters

ects

th

e

po

int

{0

.99

,0.9

9}.

Th

e st

rip

pin

g s

ecti

on

op

erat

ing l

ine

is d

raw

n t

o i

nte

rsec

t th

e p

oin

t

{0

.01

,0.0

1} a

nd

th

e p

oin

t w

her

e th

e q

-lin

e in

ters

ects

th

e re

ctif

yin

g s

ecti

on

op

erat

ing l

ine.

In t

he

McC

abe-

Th

iele

gra

ph

s b

elo

w,

the

firs

t fo

r th

e h

igh

mo

le-f

ract

ion

reg

ion

, it

is

seen

th

at t

he

spec

ifie

d r

eflu

x r

atio

is,

fo

rtu

nat

ely,

abo

ve

the

min

imu

m v

alu

e fo

r th

e sp

ecif

ied

dis

till

ate

mo

le

frac

tio

n.

Fro

m t

he

plo

ts,

it i

s se

en t

hat

20

th

eore

tica

l st

ages

plu

s a

par

tial

reb

oil

er a

re n

eed

ed.

Th

e o

pti

mal

feed

sta

ge

is n

um

ber

17

do

wn

fro

m t

he

top

.

Page 59: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.23

(c

on

tin

ued

) A

na

lysi

s:

(co

nti

nu

ed)

Ex

erci

se 7

.23

(c

on

tin

ued

) A

na

lysi

s:

(co

nti

nu

ed)

Page 60: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.24

S

ub

ject

: P

arti

al s

epar

atio

n o

f a

ben

zen

e-to

luen

e m

ixtu

re w

ith

a p

arti

al r

ebo

iler

an

d a

par

tial

con

den

ser.

Giv

en:

S

atu

rate

d l

iqu

id f

eed

of

69

.4 m

ol%

ben

zen

e (B

) in

to

luen

e (T

) fe

d t

o a

par

tial

reb

oil

er.

Vap

or

fro

m t

he

reb

oil

er p

asse

s to

a p

arti

al c

on

den

ser.

V

apo

r fr

om

th

e p

arti

al c

on

den

ser

pas

ses

to

a to

tal

con

den

ser.

R

eflu

x f

rom

th

e p

arti

al c

on

den

ser

is s

ent

to t

he

par

tial

reb

oil

er.

Dis

till

ate

is t

o

con

tain

90

mo

l% b

enze

ne

(yD =

0.9

) at

a r

ate

of

25

mo

les

per

10

0 m

ole

s o

f fe

ed.

Th

e re

lati

ve

vo

lati

lity

of

ben

zen

e w

ith

res

pec

t to

to

luen

e =

α =

2.5

.

Fin

d:

M

ole

s o

f v

apo

r gen

erat

ed i

n t

he

reb

oil

er p

er 1

00

mo

les

of

feed

by a

nal

yti

cal

and

gra

ph

ical

met

ho

ds.

An

aly

sis:

F

irst

co

mp

ute

ov

eral

l m

ater

ial

bal

ance

. T

he

tota

l co

nd

ense

r n

eed

no

t b

e co

nsi

der

ed.

Bas

is:

10

0 m

ole

s o

f fe

ed.

Ov

eral

l to

tal

mat

eria

l b

alan

ce:

F

= 1

00

= D

+ B

= 2

5 +

B

(1)

So

lvin

g E

q.

(1),

B =

75

mo

les

Ov

eral

l b

enze

ne

mat

eria

l b

alan

ce:

F

x F =

69

.4 =

Dy D

+ B

x B

= 2

5(0

.9)

+ 7

5x B

(2

)

So

lvin

g E

q.

(2),

xB =

0.6

25

An

aly

tica

l M

eth

od

:

W

rite

mat

eria

l b

alan

ces

aro

un

d t

he

par

tial

reb

oil

er a

nd

par

tial

co

nd

ense

r, u

sin

g s

ub

scri

pts

B f

or

stre

ams

leav

ing t

he

reb

oil

er a

nd

D f

or

stre

ams

leav

ing t

he

par

tial

co

nd

ense

r.

Par

tial

reb

oil

er:

T

ota

l m

ater

ial

bal

ance

: F

+ L

D =

B +

VB

or

10

0 +

LD =

75

+ V

B

(3)

B

enze

ne

mat

eria

l b

alan

ce:

Fx F

+ L

Dx D

= B

x B +

VBy B

o

r 6

9.4

+ L

Dx D

= 7

5(0

.62

5)

+ V

By B

= 4

6.9

+ V

By B

(4

)

Par

tial

co

nd

ense

r:

T

ota

l m

ater

ial

bal

ance

: V

B =

D +

LD =

75

+ L

D

(5)

B

enze

ne

mat

eria

l b

alan

ce:

VBy B

= D

y D +

LDx D

= 7

5(0

.9)

+ L

Dx D

= 6

7.5

+ L

Dx D

(

6)

Ass

um

e eq

uil

ibri

um

in

th

e p

arti

al c

on

den

ser

and

par

tial

reb

oil

er.

Usi

ng t

he

giv

en α

wit

h i

ts

def

init

ion

in

Eq

. (7

-2).

F

or

the

par

tial

co

nd

ense

r,

α =

2.5

= y

D (

1 -

xD)/

x D(1

- y

D)

= 0

.9(1

- x

D)/

x D(1

-0

.9)

= 9

(1 -

xD)/

x D

(7)

So

lvin

g E

q.

(7),

xD =

0.7

83

Fo

r th

e p

arti

al r

ebo

iler

,

α =

2.5

= y

B (

1 -

xB)/

x B(1

- y

B)

= y

B (

1 -

0.6

25

)/0

.62

5(1

- y

B)

= 0

.6 y

B/(

1 -

yB)

(8)

So

lvin

g E

q.

(8),

yB =

0.8

06

Eq

s. (

3)

thro

ugh

(6

), a

re 4

eq

uat

ion

s in

2 u

nk

no

wn

s, V

B a

nd

LD.

We

on

ly n

eed

2 o

f th

e 4

equ

atio

ns.

U

sin

g E

qs.

(3

) an

d (

4),

10

0 +

LD =

75

+ V

B

(3

)

6

9.4

+ L

D(0

.78

3)

= 4

6.9

+ V

B(0

.80

6)

(9)

So

lvin

g E

qs.

(3

) an

d (

9),

LD =

98

mo

les

/10

0 m

ole

s o

f fe

ed a

nd

V

B =

12

3 m

ole

s/1

00

mo

les

of

feed

E

xer

cise

7.2

4 (c

on

tin

ued

) A

na

lysi

s:

(co

nti

nu

ed)

Gra

ph

ica

l M

eth

od

:

O

n t

he

McC

abe-

Th

iele

dia

gra

m b

elo

w,

the

equ

ilib

riu

m c

urv

e is

ob

tain

ed f

rom

Eq

. (7

-3),

yx

x

x

x=

+−

=+

α

α1

1

25

11

5(

)

.

.

Th

e re

ctif

icat

ion

sec

tio

n o

per

atin

g l

ine

is l

oca

ted

, as

sh

ow

n,

so t

hat

tw

o e

qu

ilib

riu

m s

tep

s, o

ne

for

the

par

tial

co

nd

ense

r an

d o

ne

for

the

par

tial

reb

oil

er,

are

step

ped

off

bet

wee

n x

C =

0.9

(fr

om

the

tota

l co

nd

ense

r) a

nd

xB =

0.6

25

. T

he

mea

sure

d s

lop

e o

f th

e o

per

atin

g l

ine

= L

D/V

B =

0.8

.

Co

mb

inin

g t

his

wit

h E

q.

(3),

V

B =

12

5 m

ole

s/1

00

mo

les

of

feed

, w

hic

h i

s cl

ose

to

th

e an

alyti

cal

val

ue.

Page 61: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.25

S

ub

ject

: R

ecti

fica

tio

n o

f a

mix

ture

of

ben

zen

e an

d c

hlo

rob

enze

ne

at t

ota

l re

flu

x.

Giv

en:

F

eed

of

10

0 k

mo

l o

f 2

0 m

ol%

ben

zen

e an

d 8

0 m

ol%

ch

loro

ben

zen

e.

Co

lum

n h

as 4

theo

reti

cal

pla

tes,

a t

ota

l co

nd

ense

r, a

ref

lux

dru

m,

and

a s

till

to

vap

ori

ze t

he

feed

. A

t an

op

erat

ing p

ress

ure

of

1 a

tm,

rela

tiv

e v

ola

tili

ty o

f b

enze

ne

wit

h r

esp

ect

to c

hlo

rob

enze

ne

= α

=

4.1

3.

Op

erat

e at

to

tal

refl

ux

wit

h h

old

up

s o

nly

in

th

e re

flu

x d

rum

an

d t

he

stil

l.

Wan

t li

qu

id i

n

the

stil

l w

ith

0.1

mo

l% b

enze

ne.

Ass

um

pti

on

s:

Per

fect

mix

ing t

o g

ive

un

ifo

rm c

om

po

siti

on

s in

th

e re

flu

x d

rum

an

d t

he

stil

l.

Fin

d:

M

ole

s o

f li

qu

id i

n t

he

stil

l at

ste

ady s

tate

.

An

aly

sis:

T

his

ex

erci

se c

an b

e so

lved

an

alyti

call

y o

r gra

ph

ical

ly.

Sin

ce b

enze

ne

is t

he

mo

re

vo

lati

le c

om

po

nen

t, E

q.

(7-3

) giv

es t

he

equ

ilib

riu

m r

elat

ion

at

the

stil

l o

r an

y o

f th

e 4

pla

tes,

n,

as,

yx

x

x

xn

n

n

n

n

=+

−=

+

α

α1

1

41

3

13

13

()

.

.

(1

)

At

tota

l re

flu

x,

nu

mb

erin

g s

tages

up

fro

m t

he

bo

tto

m,

x n

+1

= y

n

(2)

An

aly

tica

l M

eth

od

:

S

tart

at

the

bo

tto

m,

stag

e 1

, w

ith

x1 =

0.0

01

. S

olv

e fo

r y 1

(v

apo

r le

avin

g t

he

stil

l) w

ith

Eq

. (1

).

Th

en,

fro

m E

q.

(2),

x2 =

y1.

Co

nti

nu

e in

th

is m

ann

er,

solv

ing a

lter

nat

ely E

q.

(1)

and

then

Eq

. (2

), u

nti

l y 5

(v

apo

r le

avin

g t

he

top

pla

te)

is r

each

ed.

Th

en,

x in

th

e re

flu

x d

rum

= y

5.

Th

e re

sult

s fr

om

a s

pre

adsh

eet

are,

Eq

uil

bri

um

sta

ge

x

y

1 (

stil

l)

0.0

01

00

0

.00

41

2

2 (

bo

tto

m p

late

0

.00

41

2

0.0

16

79

3

0.0

16

79

0

.06

58

7

4

0.0

65

87

0

.22

55

4

5 (

top

pla

te)

0.2

25

54

0

.54

60

3

refl

ux

dru

m

0.5

46

03

By o

ver

all

tota

l m

ater

ial

bal

ance

, F

= 1

00

= D

+ B

(3)

By o

ver

all

ben

zen

e m

ater

ial

bal

ance

,

Fx F

= (

10

0)(

0.2

0)

= 2

0 =

Dx D

+ B

x B =

D(0

.54

60

3)

+ B

(0.0

01

)

(4)

So

lvin

g E

qs.

(3

) an

d (

4),

D =

dis

till

ate

in r

eflu

x d

rum

= 3

6.5

1 k

mo

les

B

= b

ott

om

s in

sti

ll =

63

.49

km

ole

s

Ex

erci

se 7

.25

(co

nti

nu

ed)

Gra

ph

ica

l M

eth

od

:

O

n t

he

McC

abe-

Th

iele

plo

t o

n t

he

nex

t p

age,

th

e eq

uil

ibri

um

cu

rve

is c

om

pu

ted

fro

m E

q.

(1).

T

he

rect

ific

atio

n s

ecti

on

op

erat

ing l

ine

is t

he

45

o l

ine.

F

ive

stag

es a

re s

tep

ped

off

fro

m t

he

bo

tto

ms

of

x B =

0.0

01

. T

he

resu

ltin

g y

5 is

ess

enti

ally

th

e sa

me

as t

hat

fo

r th

e an

alyti

cal

met

ho

d.

Th

us,

agai

n,

B

= b

ott

om

s in

sti

ll =

63

.49

km

ole

s.

Page 62: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.25

(c

on

tin

ued

) A

na

lysi

s:

Gra

ph

ical

met

ho

d

(co

nti

nu

ed)

Ex

erci

se 7

.26

S

ub

ject

: D

isti

llat

ion

of

ace

ton

e an

d i

sop

rop

ano

l, t

akin

g i

nto

acc

ou

nt

tray

eff

icie

ncy

.

Giv

en:

S

atu

rate

d l

iqu

id f

eed

of

50

mo

l% a

ceto

ne

and

50

mo

l% i

sop

rop

ano

l.

Co

lum

n i

s

equ

ipp

ed w

ith

a t

ota

l co

nd

ense

r, a

nd

a p

arti

al r

ebo

iler

. R

eflu

x r

atio

, L

/D,

is 0

.5.

Mu

rph

ree

vap

or

effi

cien

cy =

50

%.

Vap

or-

liq

uid

eq

uil

ibri

um

dat

a at

1 a

tm a

re g

iven

, w

ith

ace

ton

e b

ein

g t

he

mo

re

vo

lati

le c

om

po

nen

t.

Ass

um

pti

on

s:

Co

nst

ant

mo

lar

ov

erfl

ow

.

Fin

d:

N

um

ber

of

actu

al t

rays

req

uir

ed t

o a

chie

ve

a d

isti

llat

e o

f 8

0 m

ol%

ace

ton

e an

d a

bo

tto

ms

of

25

mo

l% a

ceto

ne,

in

sert

ing t

he

feed

at

the

op

tim

al l

oca

tio

n.

An

aly

sis:

I

n t

he

McC

abe-

Th

iele

dia

gra

m b

elo

w,

the

equ

ilib

riu

m c

urv

e is

plo

tted

fro

m t

he

giv

en

dat

a.

Th

e q

-lin

e is

ver

tica

l, p

assi

ng t

hro

ugh

x =

0.5

. T

he

rect

ific

atio

n o

per

atin

g l

ine

has

a s

lop

e,

L/V

, fr

om

Eq

. (7

-9),

of

R/(

R +

1)

= 0

.5/1

.5 =

0.3

33

. T

his

op

erat

ing l

ine

pas

ses

thro

ugh

th

e p

oin

t,

y =

0.8

, x

= 0

.8.

Fro

m E

q.

7-9

), t

he

equ

atio

n f

or

the

rect

ifyin

g s

ecti

on

op

erat

ing l

ine

is,

yR

Rx

Rx

xx

D=

+

� ��� ��

++

� ��� ��

=+

=+

1

1

10

33

30

66

70

80

33

30

53

3.

.(

.)

..

Fro

m t

his

eq

uat

ion

, th

e in

ters

ecti

on

of

the

rect

ifyin

g s

ecti

on

op

erat

ing l

ine

and

th

e v

erti

cal

q-l

ine

is a

t y

= 0

.33

3(0

.5)

+ 0

.53

3 =

0.7

0.

Th

e st

rip

pin

g s

ecti

on

op

erat

ing l

ine

pas

ses

thro

ugh

th

e {y,

x}

po

ints

{0

.70

, 0

.50

} a

nd

{0

.25

, 0

.25

},

giv

ing i

t th

e eq

uat

ion

, y

= 1

.80

x-0

.20

.

Ex

cep

t fo

r th

e re

bo

iler

sta

ge,

th

e st

ages

are

ste

pp

ed o

ff f

rom

an

eff

icie

ncy

lin

e, w

hic

h f

or

a

Mu

rph

ree

vap

or

effi

cien

cy o

f 0

.5 i

s p

osi

tio

ned

ver

tica

lly h

alf

way

bet

wee

n t

he

equ

ilib

riu

m c

urv

e

and

th

e o

per

atin

g l

ine,

as

go

ver

ned

by E

q.

(7-4

1),

E

MV =

0.5

= (

y n -

yn

+1)/

(yn*

- y

n+

1),

wh

ere

y n+

1

is t

he

loca

tio

n o

n t

he

op

erat

ing l

ine,

yn i

s th

e lo

cati

on

on

th

e ef

fici

ency

lin

e, a

nd

yn*

is

the

loca

tio

n o

n t

he

equ

ilib

riu

m l

ine.

H

ow

ever

, th

e re

bo

iler

is

assu

med

to

hav

e a

10

0%

eff

icie

ncy

.

As

seen

in

th

e p

lot,

ju

st o

ver

8 t

rays

are

req

uir

ed p

lus

the

par

tial

reb

oil

er.

Th

e fe

ed p

late

is

4

fro

m t

he

top

.

Page 63: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.26

(c

on

tin

ued

) A

na

lysi

s (

con

tin

ued

)

Ex

erci

se 7

.27

S

ub

ject

: D

isti

llat

ion

of

carb

on

dis

ulf

ide

and

car

bo

n t

etra

chlo

rid

e.

Giv

en:

P

arti

ally

vap

ori

zed

fee

d (

q =

0.5

) o

f 4

0 m

ol%

CS

2.

Op

erat

ion

wit

h a

ref

lux

rat

io,

L/D

,

of

4 a

nd

a M

urp

hre

e v

apo

r ef

fici

ency

of

80

%.

P

arti

al r

ebo

iler

an

d t

ota

l co

nd

ense

r.

Vap

or-

liq

uid

equ

ilib

riu

m d

ata.

Ass

um

pti

on

s:

Co

nst

ant

mo

lar

ov

erfl

ow

.

Fin

d:

F

or

a d

isti

llat

e o

f 9

5 m

ol%

CS

2 a

nd

a b

ott

om

s o

f 5

mo

l% C

S2,

det

erm

ine:

(a

) M

inim

um

ref

lux

rat

io,

min

imu

m b

oil

up

rat

io,

and

min

imu

m n

um

ber

of

stag

es.

(b

) N

um

ber

of

tray

s.

An

aly

sis:

(

a) I

n t

he

McC

abe-

Th

iele

plo

t o

n t

he

nex

t p

age,

rec

tify

ing s

ecti

on

an

d s

trip

pin

g

sect

ion

op

erat

ing l

ines

are

sh

ow

n f

or

det

erm

inin

g m

inim

um

ref

lux

an

d b

oil

up

rat

ios.

N

ote

th

at

the

q-l

ine

has

a s

lop

e giv

en i

n E

q.

(7-2

6)

as q

/(q

- 1

) =

0.5

/(0

.5 -

1)

= -

1 a

nd

in

ters

ects

th

e p

oin

t

{0

.4,

0.4

}.

Th

e re

ctif

yin

g s

ecti

on

op

erat

ing l

ine

inte

rsec

ts t

he

po

int

{0

.95

, 0

.95

} a

nd

th

e p

oin

t

wh

ere

the

equ

ilib

riu

m c

urv

e an

d t

he

q-l

ine

inte

rsec

t.

Th

e sl

op

e o

f th

at l

ine

is m

easu

red

to

be

L/V

= 0

.64

2.

Fro

m E

q.

(7-9

), L

/V =

R/(

R +

1).

R

earr

angin

g,

Rm

in =

(L

/V)/

[1 -

(L

/V)]

= 0

.64

2/(

1 -

0.6

42

) =

1.7

9

Th

e st

rip

pin

g s

ecti

on

op

erat

ing l

ine

inte

rsec

ts t

he

po

int

{0

.05

, 0

.05

} a

nd

th

e p

oin

t w

her

e th

e

equ

ilib

riu

m c

urv

e an

d t

he

q-l

ine

inte

rsec

t.

Th

e sl

op

e o

f th

at l

ine

is m

easu

red

to

be

LV/

=

2.0

43

. F

rom

Eq

. (7

-14

), L

V/=

(V

B +

1)/

VB.

Rea

rran

gin

g,

()

()

mn

min

i

10

.95

1

2.0

43

1/

19

��

==

=�

�−

�=

−�

B

V BL

VV

Th

e M

cCab

e-T

hie

le p

lot

for

min

imu

m s

tages

at

tota

l re

flu

x i

s al

so s

ho

wn

on

th

e n

ext

pag

e.

Th

e

op

erat

ing l

ines

are

co

inci

den

t w

ith

th

e 4

5o l

ine.

It

is

seen

th

at 6

eq

uil

ibri

um

sta

ges

are

nee

ded

.

(b

) F

or

a re

flu

x r

atio

, R

= L

/D,

of

4,

the

slo

pe

of

the

rect

ifyin

g s

ecti

on

op

erat

ing l

ine

fro

m E

q.

(7-9

) is

L/V

= R

/(R

+ 1

) =

4/5

= 0

.8.

Th

is l

ine

and

th

e st

rip

pin

g s

ecti

on

op

erat

ing l

ine

are

sho

wn

on

th

e th

ird

McC

abe-

Th

iele

dia

gra

m b

elo

w.

E

xce

pt

for

the

reb

oil

er s

tage,

th

e st

ages

are

step

ped

off

fro

m a

n e

ffic

ien

cy l

ine,

wh

ich

fo

r a

Mu

rph

ree

vap

or

effi

cien

cy o

f 0

.8 i

s

po

siti

on

ed 8

0%

of

the

ver

tica

l d

ista

nce

fro

m t

he

op

erat

ing l

ine

to t

he

equ

ilib

riu

m c

urv

e, a

s

go

ver

ned

by E

q.

(7-4

1),

E

MV =

0.8

= (

y n -

yn

+1)/

(yn*

- y

n+

1),

wh

ere

y n+

1 i

s th

e lo

cati

on

on

th

e

op

erat

ing l

ine,

yn i

s th

e lo

cati

on

on

th

e ef

fici

ency

lin

e, a

nd

yn*

is

the

loca

tio

n o

n t

he

equ

ilib

riu

m

lin

e.

Ho

wev

er,

the

reb

oil

er i

s as

sum

ed t

o h

ave

a 1

00

% e

ffic

ien

cy.

As

seen

in

th

e p

lot,

ju

st o

ver

9 t

rays

are

req

uir

ed p

lus

the

par

tial

reb

oil

er.

Cal

l it

10

tra

ys

plu

s th

e re

bo

iler

. T

he

feed

pla

te i

s 7

fro

m t

he

top

.

Page 64: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.27

(c

on

tin

ued

) A

na

lysi

s:

(a)

(co

nti

nu

ed)

Ex

erci

se 7

.27

(c

on

tin

ued

) A

na

lysi

s:

(a)

(co

nti

nu

ed)

Page 65: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.27

(c

on

tin

ued

) A

na

lysi

s:

(b)

(co

nti

nu

ed)

Ex

erci

se 7

.28

S

ub

ject

: P

reli

min

ary d

esig

n c

alcu

lati

on

s fo

r th

e d

isti

llat

ion

of

a b

enze

ne-

tolu

ene

mix

ture

.

Giv

en:

B

ub

ble

-po

int

feed

of

50

mo

l% b

enze

ne

and

50

mo

l% t

olu

ene.

E

qu

ipm

ent

to i

ncl

ud

e a

par

tial

reb

oil

er,

tota

l co

nd

ense

r, a

nd

a b

ub

ble

-cap

tra

y c

olu

mn

wit

h a

n o

ver

all

pla

te e

ffic

ien

cy o

f

65

%.

Co

lum

n t

o o

per

ate

at 1

atm

to

pro

du

ce a

dis

till

ate

of

95

mo

l% b

enze

ne

and

a b

ott

om

s o

f

95

mo

l% t

olu

ene.

V

apo

r-li

qu

id e

qu

ilib

riu

m d

ata

fro

m E

xer

cise

7.1

3.

En

thal

py d

ata

fo

r re

bo

iler

.

Ass

um

pti

on

s:

Co

nst

ant

mo

lar

ov

erfl

ow

an

d s

atu

rate

d l

iqu

id r

eflu

x.

Fin

d:

(a)

Min

imu

m r

eflu

x r

atio

(in

fin

ite

stag

es).

(b

) M

inim

um

nu

mb

er o

f ac

tual

pla

tes

(to

tal

refl

ux

).

(c

) N

um

ber

of

actu

al p

late

s fo

r R

= 1

.5 R

min

.

(d

) K

ilo

gra

ms

per

ho

ur

of

pro

du

cts

for

a fe

ed o

f 9

07

.3 k

g/h

.

(e

) K

g/h

of

satu

rate

d s

team

at

27

3.7

kP

a fo

r re

bo

iler

hea

t d

uty

usi

ng g

iven

en

thal

py d

ata.

(f

) R

igo

rou

s en

thal

py b

alan

ce a

rou

nd

th

e re

bo

iler

.

An

aly

sis:

M

cCab

e-T

hie

le p

lots

are

mad

e in

ter

ms

of

ben

zen

e m

ole

fra

ctio

ns,

sin

ce b

enze

ne

is

the

mo

re v

ola

tile

co

mp

on

ent.

T

he

equ

ilib

riu

m c

urv

e is

plo

tted

fro

m t

he

dat

a in

Ex

erci

se 7

.13

.

(a)

Fo

r a

satu

rate

d l

iqu

id f

eed

, m

inim

um

ref

lux

co

rres

po

nd

s to

a p

inch

po

int

loca

ted

at

the

inte

rsec

tio

n o

f a

ver

tica

l q

-lin

e p

assi

ng t

hro

ugh

xF =

0.5

an

d t

he

equ

ilib

riu

m c

urv

e as

sh

ow

n

in t

he

McC

abe-

Th

iele

dia

gra

m b

elo

w.

Fro

m t

he

equ

ilib

riu

m d

ata,

th

is i

nte

rsec

tio

n i

s at

y =

0.7

2

and

x =

0.5

. T

hen

, th

e sl

op

e o

f th

e re

ctif

yin

g s

ecti

on

op

erat

ing l

ine,

(L

/V) m

in i

s (0

.95

- 0

.72

)/(0

.95

- 0

.50

) =

0.5

11

. F

rom

a r

earr

angem

ent

of

Eq

. (7

-7),

Rm

in =

(L

/V) m

in /

[1 -

(L

/V) m

in ]

= 0

.51

1/(

1 -

0.5

11

) =

1.0

45

.

(b

) T

he

McC

abe-

Th

iele

plo

t fo

r m

inim

um

sta

ges

at

tota

l re

flu

x i

s sh

ow

n b

elo

w.

Th

e

op

erat

ing l

ines

are

co

inci

den

t w

ith

th

e 4

5o l

ine.

E

qu

ilib

riu

m s

tages

are

ste

pp

ed o

ff s

tart

ing f

rom

x B =

0.0

5 t

o x

D =

0.9

5.

It

is s

een

th

at j

ust

les

s th

an 7

eq

uil

ibri

um

sta

ges

are

nee

ded

. C

all

it N

t = 7

.

Fro

m E

q.

(6-2

1),

fo

r an

ov

eral

l p

late

eff

icie

ncy

of

65

%,

i.e.

Eo =

0.6

5,

the

actu

al m

inim

um

nu

mb

er o

f p

late

s =

Na =

Nt /

Eo =

7/0

.65

= 1

0.8

.

(c

) O

per

atin

g r

eflu

x r

atio

= R

= 1

.5 R

min

= 1

.5(1

.04

5)

= 1

.57

. F

rom

Eq

. (7

-7),

th

e sl

op

e

of

the

op

erat

ing l

ine

for

the

rect

ifyin

g s

ecti

on

= L

/V =

R/(

1 +

R)

= 1

.57

(1 +

1.5

7)

= 0

.61

1.

On

the

McC

abe-

Th

iele

dia

gra

m o

n t

he

nex

t p

age,

th

e re

ctif

yin

g s

ecti

on

op

erat

ing l

ine

has

th

is s

lop

e

and

pas

ses

thro

ugh

th

e p

oin

t, y

=0

.95

, x=

0.9

5.

th

e st

rip

pin

g s

ecti

on

op

erat

ing l

ine

pas

ses

thro

ugh

the

po

int,

y=

0.0

5,

x=0

.05

an

d i

nte

rsec

ts t

he

ver

tica

l q

-lin

e at

th

e p

oin

t w

her

e th

e re

ctif

yin

g

sect

ion

op

erat

ing l

ine

inte

rsec

ts t

he

q-l

ine.

A

s se

en,

the

equ

ilib

riu

m s

tages

are

ste

pp

ed o

ff

star

tin

g a

t th

e to

p,

wit

h a

sw

itch

fro

m t

he

rect

ifyin

g s

ecti

on

to

th

e st

rip

pin

g s

ecti

on

to

min

imiz

e

the

nu

mb

er o

f st

ages

an

d,

thu

s, l

oca

tin

g t

he

op

tim

al f

eed

sta

ge.

T

he

resu

lt i

s ju

st o

ver

10

equ

ilib

riu

m s

tages

plu

s a

par

tial

reb

oil

er.

Cal

l it

11

eq

uil

ibri

um

sta

ges

plu

s a

par

tial

reb

oil

er.

Ap

ply

ing E

q.

(6-2

1),

Na =

11

/0.6

5 =

16

.9 o

r 1

7 a

ctu

al p

late

s p

lus

the

par

tial

reb

oil

er.

Page 66: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.28

(co

nti

nu

ed)

An

aly

sis:

(c

on

tin

ued

)

Ex

erci

se 7

.28

(co

nti

nu

ed)

An

aly

sis:

(c

on

tin

ued

)

Page 67: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.28

(co

nti

nu

ed)

An

aly

sis:

(c

on

tin

ued

)

Ex

erci

se 7

.28

(co

nti

nu

ed)

An

aly

sis:

(c

on

tin

ued

)

(d

)

MW

of

ben

zen

e =

78

.11

. M

W o

f to

luen

e =

92

.14

.

Let

F =

km

ol/

h o

f fe

ed.

Th

en b

y m

ass

mat

eria

l b

alan

ce w

ith

an

eq

uim

ola

r fe

ed,

0.5

F (

78

.11

) +

0.5

F(9

2.1

4)

= 9

07

.3

So

lvin

g,

F =

10

.66

km

ol/

h.

Fo

r th

e eq

uim

ola

r fe

ed,

the

com

po

nen

t fl

ow

rat

es i

n t

he

feed

are

:

5.3

3 k

mo

l/h

eac

h f

or

ben

zen

e an

d t

olu

ene

Nex

t ca

lcu

late

th

e d

isti

llat

e an

d b

ott

om

s fl

ow

rat

es f

rom

,

ov

eral

l to

tal

mo

le b

alan

ce:

F =

nF =

10

.66

= D

+ B

(1)

ov

eral

l b

enze

ne

mo

le b

alan

ce:

Fx F

= 5

.33

= 0

.95

D +

0.0

5B

(2)

So

lvin

g E

qs.

(1

) an

d (

2),

D =

5.3

3 k

mo

l/h

an

d B

= 5

.33

km

ol/

h

Th

eref

ore

in

ter

ms

of

mas

s fl

ow

rat

es,

tota

l to

tal

dis

till

ate

rate

is,

mD =

0.9

5(5

.33

)(7

8.1

1)

+ 0

.05

(5.3

3)(

92

.14

) =

42

0.1

kg/h

Th

eref

ore

th

e b

ott

om

s ra

te =

mB =

90

7.3

- 4

20

.1 =

48

7.2

kg/h

(

e)

Fir

st c

om

pu

te t

he

km

ol/

h o

f v

apo

r le

avin

g t

he

reb

oil

er,

usi

ng t

he

assu

mp

tio

n o

f

con

stan

t m

ola

r o

ver

flo

w.

Fro

m p

art

(c),

th

e re

flu

x r

atio

= 1

.57

. T

her

efo

re,

the

refl

ux

rat

e =

1.5

7(5

.33

) =

8.3

7 k

mo

l/h

. B

elo

w t

he

feed

sta

ge,

th

e li

qu

id r

ate

= 8

.37

+ 1

0.6

6 =

19

.03

km

ol/

h.

Th

e v

apo

r ra

te l

eav

ing t

he

reb

oil

er =

19

.03

- 5

.33

= 1

3.7

0 k

mo

l/h

. F

rom

th

e p

lot

abo

ve,

th

e

com

po

siti

on

of

the

reb

oil

er v

apo

r =

12

mo

l% b

enze

ne.

N

egle

ctin

g t

he

sen

sib

le h

eat

and

usi

ng

the

enth

alp

y d

ata

giv

en,

afte

r co

nv

erti

ng f

rom

Btu

/lb

mo

l to

kJ/

km

ol,

th

e re

bo

iler

hea

t d

uty

is,

QR =

2.3

24

[0.1

2(1

3.7

)(1

8,1

30

- 4

,90

0)

+ 0

.88

(13

.7)(

21

,83

0 -

8,0

80

)] =

43

6,0

00

kJ/

km

ol.

Fro

m P

erry

's H

and

bo

ok

, la

ten

t h

eat

of

vap

ori

zati

on

of

stea

m a

t 2

73

.7 k

Pa

(40

4 K

) =

2,1

72

kJ/

kg

Th

eref

ore

, w

e n

eed

43

6,0

00

/2,1

72

= 2

00

.7 k

mo

l/h

or

3,6

16

kg/h

.

(f

) A

rig

oro

us

enth

alp

y b

alan

ce a

rou

nd

th

e re

bo

iler

tak

es i

nto

acc

ou

nt

the

sen

sib

le h

eat

effe

ct s

ince

th

e te

mp

erat

ure

of

the

liq

uid

en

teri

ng t

he

reb

oil

er i

s n

ot

the

sam

e as

th

e te

mp

erat

ure

s

of

the

equ

ilib

riu

m l

iqu

id a

nd

vap

or

leav

ing t

he

reb

oil

er.

Let

N =

co

nd

itio

ns

leav

ing t

he

reb

oil

er

and

N-1

be

the

con

dit

ion

s le

avin

g t

he

stag

e ab

ov

e th

e re

bo

iler

. T

hen

,

QV

HL

HL

HR

NV

NL

NL

NN

N=

+−

−−

11

No

te t

hat

in

th

e si

mp

lifi

ed e

nth

alp

y b

alan

ce o

f p

art

(e),

th

e fo

llo

win

g e

qu

atio

n w

as

app

lied

,

QV

HH

RN

VL

NN

=−

Sin

ce,

VL

LN

NN

=−

−1,

this

is

equ

ival

ent

to a

ssu

min

g H

HL

LN

N=

−1

Page 68: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.29

S

ub

ject

: P

reli

min

ary d

esig

n f

or

the

dis

till

atio

n o

f a

mix

ture

of

eth

ano

l an

d w

ater

at

1 a

tm.

Giv

en:

B

ub

ble

-po

int

feed

co

nta

inin

g 2

0 m

ol%

eth

ano

l in

wat

er.

Un

it c

on

sist

ing o

f a

per

fora

ted

-tra

y c

olu

mn

, p

arti

al r

ebo

iler

, an

d t

ota

l co

nd

ense

r.

Dis

till

ate

to c

on

tain

85

mo

l%

alco

ho

l an

d a

97

% r

eco

ver

y o

f al

coh

ol.

V

apo

r-li

qu

id e

qu

ilib

riu

m d

ata.

Ass

um

pti

on

s:

Co

nst

ant

mo

lar

ov

erfl

ow

.

Fin

d:

(a)

M

ola

r co

nce

ntr

atio

ns

in t

he

bo

tto

ms

pro

du

ct.

(b

) M

inim

um

val

ues

of

L/V

, L

/D,

an

d V

B/B

.

(c

) M

inim

um

nu

mb

er o

f eq

uil

ibri

um

sta

ges

an

d a

ctu

al p

late

s fo

r E

o =

0.5

5.

(d

) N

um

ber

of

actu

al p

late

s fo

r L

/V =

0.8

0.

An

aly

sis:

F

rom

th

e v

apo

r-li

qu

id e

qu

ilib

riu

m d

ata

for

1 a

tm.,

it

is s

een

th

at e

than

ol

is m

ore

vo

lati

le t

han

wat

er f

or

eth

ano

l m

ole

fra

ctio

ns

in t

he

liq

uid

fro

m 0

to

0.8

94

3,

wh

ich

is

the

azeo

tro

pe

con

cen

trat

ion

. T

he

dis

till

ate

com

po

siti

on

is

wit

hin

th

is r

egio

n.

(a

) T

ake

a b

asis

of

F =

10

0 k

mo

l/h

.

Ov

eral

l to

tal

mat

eria

l b

alan

ce:

F =

10

0 =

D +

B

(1

)

Eth

ano

l re

cov

ery:

0

.97

Fx F

= 0

.97

(10

0)(

0.2

0)

= 1

9.4

= D

x D =

0.8

5D

(2

)

So

lvin

g E

q.

(2),

D =

22

.82

km

ol/

h.

Fro

m E

q.

(1),

B =

10

0 -

22

.82

= 7

7.1

8 k

mo

l/h

Eth

ano

l in

bo

tto

ms

= 2

0 -

19

.4 =

0.6

km

ol/

h

Th

eref

ore

, et

han

ol

mo

le f

ract

ion

in

bo

tto

ms

= 0

.6/7

7.1

8 =

0.0

07

77

Wat

er m

ole

fra

ctio

n i

n b

ott

om

s =

1.0

- 0

.00

77

7 =

0.9

92

23

(b)

In

th

e M

cCab

e-T

hie

le d

iagra

m o

n t

he

nex

t p

age,

th

e giv

en e

qu

ilib

riu

m d

ata

are

plo

tted

. F

or

a b

ub

ble

-po

int

liq

uid

fee

d,

the

q-l

ine

is v

erti

cal

at x

F =

0.2

. T

he

min

imu

m r

eflu

x i

n

term

s o

f L

/V i

s o

bta

ined

fro

m t

he

slo

pe

of

the

rect

ifyin

g s

ecti

on

op

erat

ing l

ine,

wh

ich

pas

ses

thro

ugh

th

e p

oin

t, y

= x

D =

0.8

5 a

nd

is

tan

gen

t to

th

e eq

uil

ibri

um

cu

rve,

rat

her

th

an b

ein

g d

raw

n

thro

ugh

th

e in

ters

ecti

on

of

the

q-l

ine

and

th

e eq

uil

ibri

um

cu

rve

bec

ause

th

at w

ou

ld c

ause

th

e

op

erat

ing l

ine

to m

ista

ken

ly c

ross

ov

er t

he

equ

ilib

riu

m c

urv

e.

Th

e sl

op

e o

f th

e o

per

atin

g l

ine

= (

L/V

) min

= 0

.65

.

Fro

m E

q.

(7-2

7),

Rm

in =

(L

/D) m

in =

0.6

5/(

1-0

.65

) =

1.8

6.

Th

e li

qu

id r

ate

in t

he

rect

ifyin

g s

ecti

on

= L

= 1

.86

D =

1.8

6(2

2.8

2)

= 4

2.4

4 k

mo

l/h

.

Bel

ow

th

e fe

ed p

late

, L

= L

+ F

= 4

2.4

4 +

10

0 =

14

2.4

4 k

mo

l/h

.

Vap

or

rate

fro

m t

he

reb

oil

er =

VB =

L

- B

= 1

42

.44

- 7

7.1

8 =

65

.26

km

ol/

h.

Th

eref

ore

, b

oil

up

rat

io =

V

B/B

= 6

5.2

6/7

7.1

8 =

0.8

46

.

(c)

In

th

e se

con

d M

cCab

e-T

hie

le d

iagra

m o

n t

he

nex

t p

age,

th

e m

inim

um

nu

mb

er o

f

stag

es i

s d

eter

min

ed b

y s

tep

pin

g o

ff s

tages

bet

wee

n t

he

equ

ilib

riu

m c

urv

e an

d t

he

45

o li

ne

(to

tal

refl

ux

) fr

om

th

e p

oin

ts 0

.85

an

d 0

.00

77

7 o

n t

he

45

o l

ine.

Th

e re

sult

is

app

rox

imat

ely 1

0

min

imu

m e

qu

ilib

riu

m s

tages

. F

or

a st

age

effi

cien

cy o

f 0

.55

, u

sin

g E

q.

(6-2

1),

N

a =

Nt/E

o =

10

/0.5

5 =

18

.2 m

inim

um

pla

tes.

Ex

erci

se 7

.29

(c

on

tin

ued

) A

na

lysi

s:

(b a

nd

c)

(co

nti

nu

ed)

Page 69: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.29

(c

on

tin

ued

) A

na

lysi

s:

(b a

nd

c)

(co

nti

nu

ed)

Ex

erci

se 7

.29

(c

on

tin

ued

) A

na

lysi

s:

(co

nti

nu

ed)

(d)

Fo

r an

op

erat

ing r

eflu

x r

atio

= L

/V =

0.8

, th

e re

flu

x r

atio

, R

= L

/D =

0.8

/(1

-0.8

) =

4.

On

th

e

McC

abe-

Th

iele

dia

gra

m b

elo

w,

the

rect

ifyin

g s

ecti

on

op

erat

ing l

ine

has

a s

lop

e o

f 0

.8 a

nd

pas

ses

thro

ugh

th

e p

oin

t, y

=0

.85

, x=

0.8

5.

th

e st

rip

pin

g s

ecti

on

op

erat

ing l

ine

pas

ses

thro

ugh

th

e p

oin

t,

y=0

.00

77

7,

x=0

.07

77

an

d i

nte

rsec

ts t

he

ver

tica

l q

-lin

e at

th

e p

oin

t w

her

e th

e re

ctif

yin

g s

ecti

on

op

erat

ing l

ine

inte

rsec

ts t

he

q-l

ine.

A

s se

en,

the

equ

ilib

riu

m s

tages

are

ste

pp

ed o

ff s

tart

ing a

t th

e

top

, w

ith

a s

wit

ch f

rom

th

e re

ctif

yin

g s

ecti

on

to

th

e st

rip

pin

g s

ecti

on

to

min

imiz

e th

e n

um

ber

of

stag

es a

nd

, th

us,

lo

cati

ng t

he

op

tim

al f

eed

sta

ge.

T

he

resu

lt i

s ju

st l

ess

than

15

eq

uil

ibri

um

stag

es.

Cal

l it

14

eq

uil

ibri

um

sta

ges

plu

s a

par

tial

reb

oil

er.

Ap

ply

ing E

q.

(6-2

1),

Na =

14

/0.5

5 =

25

.5 o

r 2

6 a

ctu

al p

late

s p

lus

the

par

tial

reb

oil

er a

s an

eq

uil

ibri

um

sta

ge.

Page 70: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.30

S

ub

ject

: R

eco

ver

y b

y d

isti

llat

ion

wit

h o

pen

ste

am o

f so

lven

t A

fro

m w

ater

in

tw

o f

eed

s.

Giv

en:

T

wo

sat

ura

ted

liq

uid

fee

ds,

eac

h c

on

tain

ing 5

0 k

mo

l/h

of

A.

Fee

d 1

co

nta

ins

40

mo

l%

A a

nd

Fee

d 2

co

nta

ins

60

mo

l% A

. U

nit

co

nsi

sts

of

a co

lum

n a

nd

a t

ota

l co

nd

ense

r.

Op

en s

team

is u

sed

in

lie

u o

f a

par

tial

reb

oil

er.

Rel

ativ

e v

ola

tili

ty =

3.0

fo

r A

wit

h r

esp

ect

to w

ater

.

Dis

till

ate

is t

o c

on

tain

95

mo

l% A

wit

h a

95

% r

eco

ver

y.

Ass

um

pti

on

s:

Co

nst

ant

mo

lar

ov

erfl

ow

. O

pen

ste

am e

nte

rs b

ott

om

sta

ge

as s

atu

rate

d v

apo

r.

Bo

th f

eed

s en

ter

at o

pti

mal

lo

cati

on

s.

Fin

d:

F

or

an o

ver

all

pla

te e

ffic

ien

cy o

f 7

0%

an

d a

n R

= L

/D =

1.3

3 t

imes

min

imu

m,

det

erm

ine

the

nu

mb

er o

f ac

tual

pla

tes.

C

om

pu

te t

he

bo

tto

ms

com

po

siti

on

. D

eter

min

e an

alyti

call

y t

he

loca

tio

n o

f al

l th

ree

op

erat

iin

g l

ines

.

An

aly

sis:

T

he

tota

l fl

ow

rat

e o

f F

eed

1 =

50

/0.4

= 1

25

km

ol/

h.

Th

e to

tal

feed

rat

e o

f F

eed

2 =

50

/0.6

= 8

3.3

km

ol/

h.

Th

e to

tal

feed

rat

e o

f A

= 5

0 +

50

= 1

00

km

ol/

h.

Fo

r a

reco

ver

y o

f 9

5%

of

A i

n t

he

dis

till

ate,

th

e fl

ow

rat

e o

f A

in

th

e d

isti

llat

e =

0.9

5(1

00

) =

95

km

ol/

h.

Wit

h a

mo

le

frac

tio

n o

f 0

.95

fo

r A

in

th

e d

isti

llat

e, t

he

tota

l fl

ow

rat

e o

f th

e d

isti

llat

e =

95

/0.9

5 =

10

0 k

mo

l/h

.

Fro

m E

q.

(7-3

) fo

r α

= 3

, th

e eq

uil

ibri

um

mo

le f

ract

ion

s o

f A

are

rel

ated

by,

yx

x

x

x=

+−

=+

α α1

1

3

12

()

(1

)

Eq

uat

ion

(1

) is

plo

tted

in

th

e M

cCab

e-T

hie

le d

iagra

m o

n t

he

nex

t p

age.

B

ecau

se F

eed

2 i

s ri

cher

in A

th

an F

eed

1,

Fee

d 2

en

ters

th

e co

lum

n a

bo

ve

Fee

d 1

. A

t m

inim

um

ref

lux

, th

e p

inch

con

dit

ion

wil

l o

ccu

r at

eit

her

Fee

d 1

or

Fee

d 2

. A

ssu

me

that

th

e p

inch

occ

urs

at

Fee

d 2

. F

or

a

satu

rate

d l

iqu

id f

eed

, u

sin

g E

q.

(1),

th

e u

pp

er s

ecti

on

op

erat

ing l

ine

wil

l in

ters

ect

the

equ

ilib

riu

m

curv

e fo

r x F

= 0

.6 a

t y

= 3

(0.6

)/[1

+ 2

(0.6

)] =

0.8

18

. T

her

efo

re,

the

slo

pe

of

this

op

erat

ing l

ine

is,

(L/V

) min

= (

0.9

5 -

0.8

18

)/(0

.95

0 -

0.6

) =

0.3

77

Co

rres

po

nd

ingly

, u

sin

g E

q.

(7-1

7),

R =

L/D

= (

L/V

) min

/[1

- (

L/V

) min

] =

0.3

77

/(1

- 0

.37

7)

= 0

.60

5

and

Lm

in =

0.6

05

(10

0)

= 6

0.5

km

ol/

h.

No

w c

hec

k t

he

mid

dle

sec

tio

n t

o s

ee i

f th

e o

per

atin

g l

ine

ther

e is

bel

ow

th

e eq

uil

ibri

um

cu

rve.

Th

e li

qu

id r

ate

in t

he

mid

dle

sec

tio

n =

L' =

L +

F2 =

60

.5 +

83

.3 =

14

3.8

km

ol/

h.

Th

e v

apo

r ra

te i

n t

he

mid

dle

sec

tio

n =

V' =

V =

L +

D =

60

.5 +

10

0 =

16

0.5

km

ol/

h.

Th

eref

ore

th

e sl

op

e o

f th

e o

per

atin

g l

ine

in t

he

mid

dle

sec

tio

n =

L'/

V' =

14

3.8

/16

0.5

= 0

.89

6.

As

seen

in

th

e M

cCab

e-T

hie

le d

iagra

m o

n t

he

nex

t p

age,

th

is o

per

atin

g l

ine

do

es n

ot

cro

ss o

ver

the

equ

ilib

riu

m c

urv

e.

Th

eref

ore

, th

e p

inch

do

es o

ccu

r at

Fee

d 2

(th

e u

pp

er f

eed

).

Fo

r an

op

erat

ing r

eflu

x r

atio

of

1.3

3 t

imes

min

imu

m,

L =

1.3

3(6

0.5

) =

80

.5 k

mo

l/h

.

Th

e v

apo

r ra

te i

n t

he

up

per

sec

tio

n =

L +

D =

80

.5 +

10

0 =

18

0.5

km

ol/

h.

Ex

erci

se 7

.30

(c

on

tin

ued

) A

na

lysi

s:

(co

nti

nu

ed)

T

her

efo

re t

he

up

per

sec

tio

n o

per

atin

g l

ine

has

a s

lop

e, L

/V =

80

.5/1

80

.5 =

0.4

46

an

d p

asse

s

thro

ugh

th

e p

oin

t y

= x

= 0

.95

. I

t in

ters

ects

th

e v

erti

cal

q-l

ine

at x

= 0

.6 a

nd

fo

r th

e sl

op

e o

f

0.4

46

= (

0.9

5 -

y)/

(0.9

5 -

0.6

), y

= 0

.79

4.

Fo

r th

e m

idd

le s

ecti

on

, L

' =

L +

F2

= 8

0.5

+ 8

3.3

= 1

63

.8 k

mo

l/h

an

d V

' =

V =

18

0.5

km

ol/

h

Th

eref

ore

, th

e m

idd

le s

ecti

on

op

erat

ing l

ine

has

a s

lop

e o

f L

'/V

' =

16

3.8

/18

0.5

= 0

.90

8 a

nd

inte

rsec

ts t

he

q-l

ine

for

x =

0.6

at

y =

0.7

94

. I

t in

ters

ects

th

e v

erti

cal

q-l

ine

at x

= 0

.4 a

nd

fo

r th

e

slo

pe

of

0.9

08

= (

0.7

94

- y

)/(0

.6 -

0.4

), y

= 0

.61

3.

Fo

r th

e lo

wer

sec

tio

n,

L"

= L

' +

F1 =

16

3.8

+ 1

25

= 2

88

.8 k

mo

l/h

an

d V

"=V

' =

18

0.5

km

ol/

h

Th

eref

ore

, th

e lo

wer

sec

tio

n o

per

atin

g l

ine

has

a s

lop

e o

f L

"/V

" =

28

8.8

/18

0.5

= 1

.60

an

d

inte

rsec

ts t

he

q-l

ine

for

x =

0.4

an

d y

= 0

.61

3.

As

seen

in

Fig

. 7

.27

(c),

th

e m

ole

fra

ctio

n o

f A

in

the

bo

tto

ms,

xB ,

is

det

erm

ined

fro

m t

he

inte

rsec

tio

n o

f th

e o

per

atin

g l

ine

for

the

low

er s

ecti

on

wit

h t

he

y-ax

is.

Th

us,

1

.60

= (

0.6

13

- 0

)/(0

.4 -

xB).

S

olv

ing,

x B =

0.0

16

9 f

or

com

po

nen

t A

.

Sin

ce t

he

bo

tto

ms

con

tain

s 5

km

ol/

h o

f A

, th

e b

ott

om

s ra

te =

B =

5/0

.01

69

= 2

95

.9 k

mo

l/h

.

Th

us,

th

e b

ott

om

s co

nta

ins

29

0.9

km

ol/

h o

f w

ater

. B

ut,

th

e fl

ow

rat

e o

f w

ater

en

teri

ng i

n t

he

two

feed

s =

12

5 +

83

.3 -

10

0 =

10

8.3

km

ol/

h.

Th

eref

ore

, th

e o

pen

ste

am f

low

rat

e =

29

0.9

+ 5

- 1

08

.3 =

18

7.6

km

ol/

h

In t

he

McC

abe-

Th

iele

dia

gra

m o

n t

he

nex

t p

age,

th

e th

ree

op

erat

ing l

ines

are

dra

wn

an

d t

he

equ

ilib

riu

m s

tages

are

ste

pp

ed o

ff s

o a

s to

pla

ce t

he

two

fee

ds

at t

hei

r o

pti

mal

lo

cati

on

s.

As

seen

, th

e n

um

ber

of

equ

ilib

riu

m s

tages

req

uir

ed =

Nt =

14

. F

rom

Eq

. (6

-21

), f

or

a p

late

effi

cien

cy o

f 7

0%

, th

e ac

tual

nu

mb

er o

f tr

ays

= N

a =

Nt /

Eo =

14

/0.7

= 2

0 p

late

s.

Page 71: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.30

(c

on

tin

ued

) A

na

lysi

s:

(co

nti

nu

ed)

Ex

erci

se 7

.31

S

ub

ject

: D

isti

llat

ion

of

a m

ixtu

re o

f n

-hex

ane

and

n-o

ctan

e in

a c

olu

mn

wit

h a

n

inte

rco

ole

r.

Giv

en:

S

atu

rate

d l

iqu

id f

eed

of

40

mo

l% h

exan

e in

oct

ane.

In

terc

oo

ler

at s

eco

nd

sta

ge

fro

m t

he

top

rem

ov

es h

eat

so a

s to

co

nd

ense

50

mo

l% o

f th

e v

apo

r ri

sin

g f

rom

th

e th

ird

. D

isti

llat

e is

to

con

tain

95

mo

l% o

f h

exan

e an

d b

ott

om

s is

to

co

nta

in 5

mo

l% o

f h

exan

e.

Ref

lux

rat

io,

L/D

, at

the

top

, is

eq

ual

to

0.5

. V

apo

r-li

qu

id e

qu

ilib

riu

m d

ata

for

1 a

tm i

s p

lott

ed i

n F

ig.

4.4

.

Ass

um

pti

on

s:

Co

nst

ant

mo

lar

ov

erfl

ow

. T

ota

l co

nd

ense

r an

d p

arti

al r

ebo

iler

. O

per

atin

g

pre

ssu

re o

f 1

atm

.

Fin

d:

(a

) E

qu

atio

ns

to l

oca

te o

per

atin

g l

ines

.

(b

) N

um

ber

of

equ

ilib

riu

m s

tages

if

op

tim

al f

eed

sta

ge

loca

tio

n i

s u

sed

.

An

aly

sis:

F

irst

co

mp

ute

ov

eral

l m

ater

ial

bal

ance

. T

ake

a b

asis

of

F =

10

0 k

mo

l/h

.

O

ver

all

tota

l m

ole

bal

ance

:

F

= 1

00

= D

+ B

(1)

O

ver

all

hex

ane

mo

le b

alan

ce:

F

x F =

40

= D

x D +

Bx B

= 0

.95

D +

0.0

5B

(2

)

So

lvin

g E

qs.

(1

) an

d (

2),

D

= 3

8.9

km

ol/

h

and

B

= 6

1.1

km

ol/

h

(a

) F

or

a re

flu

x r

atio

of

0.5

, in

th

e se

ctio

n a

bo

ve

the

inte

rco

ole

r, L

= 0

.5D

= 1

9.4

5

km

ol/

h.

Th

e o

ver

hea

d v

apo

r ra

te i

s V

= L

+ D

=

19

.45

+ 3

8.9

= 5

8.3

5 k

mo

l/h

. T

he

slo

pe

of

the

op

erat

ing l

ine

= L

/V =

19

.45

/58

.35

= 0

.33

3.

Usi

ng E

q.

(7-6

), t

he

equ

atio

n f

or

the

op

erat

ing l

ine

is,

y

= 0

.33

3x

+ D

x D/V

=

0.3

33

x +

(3

8.9

)(0

.95

)/(5

8.3

5)

= 0

.33

3x

+ 0

.63

3

(3)

No

w c

on

sid

er t

he

sect

ion

of

stag

es b

etw

een

th

e in

terc

oo

ler

at s

tage

2 f

rom

th

e to

p a

nd

th

e fe

ed

stag

e.

Bec

ause

50

mo

l% o

f th

e v

apo

r fr

om

th

is s

ecti

on

is

con

den

sed

at

stag

e 2

by t

he

inte

rco

ole

r,

the

vap

or

rate

in

th

is s

ecti

on

= V

' =

2V

= 2

(58

.35

) =

11

6.7

km

ol/

h.

Th

e li

qu

id r

ate

in t

his

sec

tio

n

is L

' =

V' -

D =

11

6.7

- 3

8.9

= 7

7.8

km

ol/

h.

Th

e sl

op

e o

f th

e o

per

atin

g l

ine

= L

'/V

' =

77

.8/1

16

.7

= 0

.66

7.

In

th

is s

ecti

on

, b

y h

exan

e m

ater

ial

bal

ance

, yV

' =

xL

' +

xDD

o

r,

y

= (

L'/

V')

x +

Dx D

/V' =

0.6

67

x +

(3

8.9

)(0

.95

)/1

16

.7 =

0.6

67

x +

0.3

17

(4

)

In t

he

sect

ion

bel

ow

th

e fe

ed s

tage,

fo

r a

satu

rate

d l

iqu

id f

eed

, L

"= L

' +

F =

7

7.8

+ 1

00

= 1

77

.8

km

ol/

h.

Th

e v

apo

r ra

te =

V"

= V

' =

11

6.7

km

ol/

h.

Th

e sl

op

e o

f th

e o

per

atin

g l

ine

= L

"/V

" =

17

7.8

/11

6.7

= 1

.52

4.

Fro

m E

q.

(7-1

1),

y

= (

L"/

V")

x -

Bx B

/V”

= 1

.52

4x

- (6

1.1

)(0

.05

)/1

16

.7 =

1.5

24

x -

0.0

26

(5

)

(b)

A M

cCab

e-T

hie

le d

iagra

m i

n t

erm

s o

f h

exan

e, t

he

mo

re v

ola

tile

co

mp

on

ent,

is

sho

wn

on

th

e n

ext

pag

e, w

her

e th

e eq

uil

ibri

um

cu

rve

is o

bta

ined

fro

m F

ig.

4.4

an

d t

he

op

erat

ing

lin

es f

or

the

thre

e se

ctio

ns

are

dra

wn

fro

m E

qs.

(3

), (

4),

an

d (

5).

T

he

q-l

ine

is v

erti

cal,

pas

sin

g

thro

ugh

x =

0.4

.

No

te t

hat

th

e u

pp

er a

nd

mid

dle

sec

tio

n o

per

atin

g l

ines

bo

th p

ass

thro

ugh

th

e

po

int

{0

.95

, 0

.95

}.

Th

e th

eore

tica

l st

ages

are

ste

pp

ed o

ff s

tart

ing f

rom

th

e to

p,

swit

chin

g t

o t

he

mid

dle

sec

tio

n o

per

atin

g l

ine

afte

r st

age

2,

and

sw

itch

ing t

o t

he

stri

pp

ing s

ecti

on

so

as

to l

oca

te

the

feed

sta

ge

op

tim

ally

. T

he

resu

lt i

s ju

st s

ligh

tly l

ess

than

5

eq

uil

ibri

um

sta

ges

or,

say

, 4

stag

es p

lus

a p

arti

al r

ebo

iler

.

Page 72: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.31

(co

nti

nu

ed)

An

aly

sis:

(co

nti

nu

ed)

Ex

erci

se 7

.32

S

ub

ject

: D

isti

llat

ion

of

a m

ixtu

re o

f et

hyl

alco

ho

l an

d w

ater

at

1 a

tm u

sin

g o

pen

ste

am

inst

ead

of

a re

bo

iler

.

Giv

en:

1

00

km

ol/

h o

f a

satu

rate

d l

iqu

id f

eed

co

nta

inin

g 1

2 m

ol%

eth

yl

alco

ho

l in

wat

er.

Dis

till

ate

to c

on

tain

85

mo

l% a

lco

ho

l w

ith

a r

eco

ver

y o

f 9

0%

. R

eflu

x r

atio

, L

/D =

3 w

ith

satu

rate

d l

iqu

id r

eflu

x.

Fee

d s

tage

loca

ted

op

tim

ally

. V

apo

r-li

qu

id e

qu

ilib

riu

m d

ata

in E

xer

cise

7.2

9.

Ass

um

pti

on

s:

C

on

stan

t m

ola

r o

ver

flo

w.

To

tal

con

den

ser.

Fin

d:

(a)

O

pen

ste

am r

equ

irem

ent,

km

ol/

h

(b

) N

um

ber

of

equ

ilib

riu

m s

tages

(c

) O

pti

mal

fee

d s

tage

loca

tio

n.

(d

) M

inim

um

ref

lux

rat

io.

An

aly

sis:

F

irst

co

mp

ute

mat

eria

l b

alan

ce.

Bec

ause

th

e et

han

ol

mo

le f

ract

ion

in

th

e d

isti

llat

e is

less

th

an t

hat

of

the

azeo

tro

pe

(89

.43

mo

l% i

n E

xer

cise

7.2

9),

th

e et

han

ol

is a

lway

s th

e m

ore

vo

lati

le c

om

po

nen

t.

Th

e fe

ed c

on

tain

s 1

2 k

mo

l/h

of

eth

ano

l an

d 8

8 k

mo

l/h

of

wat

er.

Fo

r a

90

%

reco

ver

y,

the

dis

till

ate

con

tain

s 0

.9(1

2)

= 1

0.8

km

ol/

h o

f et

han

ol.

S

ince

th

e d

isti

llat

e is

85

mo

l%

eth

ano

l, t

he

tota

l d

isti

llat

e ra

te =

D =

10

.8/0

.85

= 1

2.7

km

ol/

h.

Th

e b

ott

om

s co

nta

ins

12

- 1

0.8

=

1.2

km

ol/

h o

f et

han

ol.

T

he

dis

till

ate

con

tain

s 1

2.7

- 1

0.8

= 1

.9 k

mo

l/h

of

wat

er.

Th

e b

ott

om

s

con

tain

s 8

8 -

1.9

+ o

pen

ste

am =

89

.9 +

op

en s

team

in

km

ol/

h.

(a

) F

or

a re

flu

x r

atio

of

3,

L =

3D

= 3

(12

.7)

= 3

8.1

km

ol/

h.

Ov

erh

ead

vap

or

rate

= V

= L

+ D

= 3

8.1

+ 1

2.7

= 5

0.8

km

ol/

h.

Bel

ow

th

e fe

ed s

tage,

L' =

L +

F =

38

.1 +

10

0 =

13

8.1

km

ol/

h.

Bo

ilu

p r

ate

= V

' =

V =

50

.8 k

mo

l/h

= f

low

rat

e o

f o

pen

ste

am.

(b)

Th

e b

ott

om

s ra

te =

13

8.1

km

ol/

h.

Th

e b

ott

om

s co

nsi

sts

of

1.2

km

ol/

h o

f et

han

ol

and

13

8.1

- 1

.2 =

13

6.9

km

ol/

h o

f w

ater

. T

he

mo

le f

ract

ion

of

eth

ano

l in

th

e b

ott

om

s =

1.2

/13

8.1

=

0.0

08

7.

Th

e M

cCab

e-T

hie

le d

iagra

m i

s giv

en o

n t

he

nex

t p

age,

wh

ere

the

equ

ilib

riu

m c

urv

e is

ob

tain

ed f

rom

Ex

erci

se 7

.29

an

d t

he

q-l

ine

is v

erti

cal

at x

= 0

.12

. T

he

rect

ifyin

g s

ecti

on

op

erat

ing l

ine

pas

ses

thro

ugh

th

e p

oin

t {0

.85

, 0

.85

}an

d h

as a

slo

pe,

L/V

= 3

8.1

/50

.8 =

0.7

5.

Th

e

stri

pp

ing s

ecti

on

op

erat

ing l

ine

has

a s

lop

e, L

'/V

' =

13

8.1

/50

.8 =

2.7

2 a

nd

, as

sh

ow

n i

n F

ig.

7.2

7(c

), p

asse

s th

rou

gh

th

e p

oin

t x

= x

B =

0.0

08

7 a

t y

= 0

. B

ecau

se t

he

stag

es a

re s

o c

row

ded

at

the

hig

h m

ole

fra

ctio

n e

nd

, a

seco

nd

McC

abe-

Th

iele

dia

gra

m i

s sh

ow

n f

or

the

regio

n a

bo

ve

y =

x

= 0

.7.

As

sho

wn

, w

ith

th

e u

se o

f th

e tw

o d

iagra

ms,

ju

st l

ess

than

20

eq

uil

ibri

um

sta

ges

are

nee

ded

. (c)

Fro

m t

he

firs

t M

cCab

e-T

hie

le p

lot,

th

e o

pti

mal

fee

d s

tage

is S

tage

18

fro

m t

he

top

.

(d)

Fro

m t

he

thir

d M

cCab

e-T

hie

le d

iagra

m o

n t

he

nex

t p

age,

th

e m

inim

um

ref

lux

in

term

s o

f L

/V i

s o

bta

ined

fro

m t

he

slo

pe

of

the

rect

ifyin

g s

ecti

on

op

erat

ing l

ine,

wh

ich

pas

ses

thro

ugh

th

e p

oin

t, y

= x

D =

0.8

5 a

nd

is

tan

gen

t to

th

e eq

uil

ibri

um

cu

rve,

rat

her

th

an b

ein

g d

raw

n

thro

ugh

th

e in

ters

ecti

on

of

the

q-l

ine

and

th

e eq

uil

ibri

um

cu

rve

bec

ause

th

at w

ou

ld c

ause

th

e

op

erat

ing l

ine

to m

ista

ken

ly c

ross

ov

er t

he

equ

ilib

riu

m c

urv

e.

Th

e sl

op

e o

f th

e o

per

atin

g l

ine

=

(L/V

) min

= 0

.66

7.

F

rom

Eq

. (7

-27

), R

min

= (

L/D

) min

= 0

.66

7/(

1-0

.66

7)

= 2

.0.

Page 73: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.32

(c

on

tin

ued

) A

na

lysi

s:

(b

, c,

an

d d

)

(co

nti

nu

ed)

Ex

erci

se 7

.32

(c

on

tin

ued

)

A

na

lysi

s:

(b

, c,

an

d d

)

(co

nti

nu

ed)

Page 74: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.32

(c

on

tin

ued

)

A

na

lysi

s:

(b

, c,

an

d d

)

(co

nti

nu

ed)

Ex

erci

se 7

.33

S

ub

ject

: D

isti

llat

ion

of

a m

ixtu

re o

f is

op

rop

yl

alco

ho

l an

d w

ater

at

1 a

tm u

sin

g e

ith

er a

par

tial

reb

oil

er o

r o

pen

ste

am.

Giv

en:

B

ub

ble

-po

int

feed

co

nta

inin

g 1

0 m

ol%

iso

pro

pyl

alco

ho

l in

wat

er.

Dis

till

ate

to c

on

tain

67

.5 m

ol%

iso

pro

pyl

alco

ho

l w

ith

a 9

8%

rec

ov

ery.

Vap

or-

liq

uid

eq

uil

ibri

um

dat

a ,

wit

h a

n

azeo

tro

pe

at 6

8.5

4 m

ol%

alc

oh

ol.

Ass

um

pti

on

s:

Co

nst

ant

mo

lar

ov

erfl

ow

. T

ota

l co

nd

ense

r.

Fin

d:

F

or

a re

flu

x r

atio

, R

= L

/D =

1.5

tim

es m

inim

um

, d

eter

min

e n

um

ber

of

stag

es,

if:

(a

) P

arti

al r

ebo

iler

is

use

d.

(b

) O

pen

sat

ura

ted

st

eam

is

use

d.

and

(c

) M

inim

um

nu

mb

er o

f eq

uil

ibri

um

sta

ges

.

An

aly

sis:

In

th

e co

mp

osi

tio

n r

egio

n o

f o

per

atio

n,

the

alco

ho

l is

th

e m

ost

vo

lati

le c

om

po

nen

t.

Fir

st,

com

pu

te t

he

dis

trib

uti

on

of

the

alco

ho

l.

Tak

e a

bas

is o

f 1

00

km

ol/

h o

f fe

ed.

Th

en,

the

feed

co

nta

ins

10

km

ol/

h a

lco

ho

l an

d 9

0 k

mo

l/h

of

wat

er.

Fo

r a

reco

ver

y o

f 9

8 m

ol%

,

alco

ho

l, d

isti

llat

e co

nta

ins

9.8

km

ol/

h o

f al

coh

ol.

F

or

an a

lco

ho

l p

uri

ty o

f 6

7.5

mo

l%,

the

dis

till

ate

rate

= D

= 9

.8/0

.67

5 =

14

.52

km

ol/

h.

Wat

er i

n t

he

dis

till

ate

= 1

4.5

2 -

9.8

= 4

.72

km

ol/

h.

Alc

oh

ol

in t

he

bo

tto

ms

= 1

0 -

9.8

= 0

.2 k

mo

l/h

.

(a

) W

ith

a p

arti

al r

ebo

iler

, n

o o

ther

wat

er e

nte

rs t

he

syst

em.

Th

eref

ore

, w

ater

in

th

e

bo

tto

ms

= 9

0 -

4.7

2 =

85

.28

km

ol/

h.

To

tal

bo

tto

ms

rate

= B

= 8

5.2

8 +

0.2

= 8

5.4

8 k

mo

l/h

.

Mo

le f

ract

ion

of

alco

ho

l in

bo

tto

ms

= 0

.2/8

5.4

8 =

0.0

02

3.

Th

e m

inim

um

ref

lux

is

det

erm

ined

fro

m t

he

McC

abe-

Th

iele

dia

gra

m o

n t

he

nex

t p

age,

wh

ere

the

equ

ilib

riu

m c

urv

e is

dra

wn

fro

m t

he

giv

en d

ata

and

th

e q

-lin

e is

ver

tica

l, p

assi

ng t

hro

ugh

x =

0.1

0.

Th

e re

ctif

yin

g

sect

ion

op

erat

ing l

ine

for

min

imu

m r

eflu

x u

sual

ly i

s a

stra

igh

t li

ne

that

co

nn

ects

th

e d

isti

llat

e

mo

le f

ract

ion

on

th

e 4

5o l

ine

to t

he

inte

rsec

tio

n o

f th

e eq

uil

ibri

um

cu

rve

and

th

e q

-lin

e as

sh

ow

n

by t

he

das

hed

lin

e o

n t

he

dia

gra

m.

Ho

wev

er,

in t

his

cas

e th

e li

ne

mis

tak

enly

cro

sses

ov

er t

he

equ

ilib

riu

m c

urv

e.

Th

eref

ore

, in

stea

d,

the

op

erat

ing l

ine

is d

raw

n t

angen

t to

th

e eq

uil

ibri

um

curv

e fr

om

th

e p

oin

t x

= x

D =

0.6

75

as

sho

wn

on

th

e d

iagra

m b

y a

so

lid

lin

e.

Th

e sl

op

e o

f th

e

op

erat

ing l

ine

= L

/V =

0.4

67

.

Fro

m E

q.

(7-2

7),

Rm

in =

(L

/D) m

in =

0.4

67

/(1

-0.4

67

) =

0.8

76

.

Th

e o

per

atin

g r

eflu

x r

atio

= R

= 1

.5R

min

= 1

.5(0

.87

6)

= 1

.31

4.

Fro

m E

q.

(7-7

), L

/V =

R/(

1+

R)

=

1.3

14

/(1

+1

.31

4)

= 0

.56

8.

On

a s

et o

f th

ree

McC

abe-

Th

iele

dia

gra

ms

on

th

e n

ext

pag

e, t

he

rect

ifyin

g s

ecti

on

op

erat

ing l

ine

has

th

is s

lop

e an

d p

asse

s th

rou

gh

th

e p

oin

t, y

=0

.67

5,

x=0

.67

5.

the

stri

pp

ing s

ecti

on

op

erat

ing l

ine

pas

ses

thro

ugh

th

e p

oin

t, y

=0

.00

23

, x=

0.0

02

3 a

nd

in

ters

ects

the

ver

tica

l q

-lin

e at

th

e p

oin

t w

her

e th

e re

ctif

yin

g s

ecti

on

op

erat

ing l

ine

inte

rsec

ts t

he

q-l

ine.

A

s

seen

, th

e eq

uil

ibri

um

sta

ges

are

ste

pp

ed o

ff s

tart

ing a

t th

e to

p,

wit

h a

sw

itch

fro

m t

he

rect

ifyin

g

sect

ion

to

th

e st

rip

pin

g s

ecti

on

to

min

imiz

e th

e n

um

ber

of

stag

es a

nd

, th

us,

lo

cati

ng t

he

op

tim

al

feed

sta

ge.

T

o a

chie

ve

accu

racy

, o

ne

dia

gra

m c

ov

ers

the

hig

h-c

on

cen

trat

ion

reg

ion

, o

ne

the

Page 75: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

mid

dle

re

gio

n,

and

o

ne

the

low

-co

nce

ntr

atio

n

regio

n.

T

he

resu

lt

is

bet

wee

n

14

an

d

15

equ

ilib

riu

m s

tages

. C

all

it 1

4 s

tages

plu

s a

par

tial

reb

oil

er.

Ex

erci

se 7

.33

(co

nti

nu

ed)

An

aly

sis:

(a

) (

con

tin

ued

)

Ex

erci

se 7

.33

(co

nti

nu

ed)

An

aly

sis:

(a

) (

con

tin

ued

)

Page 76: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.33

(co

nti

nu

ed)

An

aly

sis:

(a

) (

con

tin

ued

)

Ex

erci

se 7

.33

(co

nti

nu

ed)

An

aly

sis:

(a

) (

con

tin

ued

)

Page 77: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.33

(co

nti

nu

ed)

An

aly

sis:

(

con

tin

ued

)

(b

) W

hen

op

en (

liv

e) s

team

is

use

d w

ith

th

e sa

me

refl

ux

rat

io,

the

rect

ific

atio

n s

ecti

on

op

erat

ing l

ine

and

th

e q

-lin

e ar

e id

enti

cal

to p

art

(a)

for

a p

arti

al r

ebo

iler

. T

hu

s, t

he

par

t (a

)

McC

abe-

Th

iele

dia

gra

m f

or

the

hig

h c

on

cen

trat

ion

reg

ion

ap

pli

es f

or

op

en s

team

.

H

ow

ever

, th

e st

rip

pin

g s

ecti

on

op

erat

ing l

ine

and

th

e b

ott

om

s m

ole

fra

ctio

n c

han

ge

as

foll

ow

s.

Th

e li

qu

id r

ate

in t

he

rect

ific

atio

n s

ecti

on

= L

= 1

.31

4D

= 1

.31

4(1

4.5

2)

= 1

9.0

8 k

mo

l/h

.

Th

e v

apo

r ra

te i

n t

he

rect

ifyin

g s

ecti

on

= V

= L

+ D

= 1

9.0

8 +

14

.52

= 3

3.6

km

ol/

h.

Th

e li

qu

id

rate

bel

ow

th

e fe

ed s

tage

= L

' =

L +

F =

1

9.0

8 +

10

0 =

11

9.0

8 k

mo

l/h

. T

he

vap

or

rate

in

th

e

stri

pp

ing s

ecti

on

= V

' =

V =

33

.6 k

mo

l/h

= o

pen

ste

am f

low

rat

e.

Th

e b

ott

om

s ra

te =

B =

L' =

11

9.0

8 k

mo

l/h

. T

he

mo

le f

ract

ion

of

iso

pro

pan

ol

in t

he

bo

tto

ms

= 0

.2/1

19

.08

= 0

.00

16

8.

Th

e

chan

ge

to t

he

par

t (a

) M

cCab

e-T

hie

le d

iagra

ms

on

th

e p

rece

din

g p

age

for

the

mid

dle

con

cen

trat

ion

reg

ion

is

extr

emel

y s

mal

l b

ecau

se t

he

loca

tio

n o

f th

e st

rip

pin

g s

ecti

on

op

erat

ing

lin

e ch

anges

on

ly s

ligh

tly.

H

ow

ever

, th

e ch

ange

is i

mp

ort

ant

in t

he

low

-co

nce

ntr

atio

n r

egio

n.

Th

e n

ew M

cCab

e-

Th

iele

dia

gra

m f

or

the

low

co

nce

ntr

atio

n r

egio

n i

s sh

ow

n b

elo

w.

Th

e o

per

atin

g l

ine

for

the

stri

pp

ing s

ecti

on

has

a s

lop

e o

f L

'/V

' =

11

9.0

8/3

3.6

= 3

.54

an

d p

asse

s th

rou

gh

th

e p

oin

t {y

= 0

, x

= 0

.00

16

8}.

Th

e n

um

ber

of

stag

es r

emai

ns

abo

ut

the

sam

e as

fo

r p

art

(a).

T

hu

s, w

ith

ou

t a

reb

oil

er,

use

15

eq

uil

ibri

um

sta

ges

in

th

e co

lum

n.

Ex

erci

se 7

.33

(co

nti

nu

ed)

An

aly

sis:

(

c)

(co

nti

nu

ed)

(c

) T

he

min

imu

m n

um

ber

of

stag

es i

s d

eter

min

ed a

s sh

ow

n i

n t

he

McC

abe-

Th

iele

dia

gra

ms

on

th

e n

ext

pag

e b

y s

tep

pin

g o

ff

stag

es b

etw

een

th

e eq

uil

ibri

um

cu

rve

and

th

e 4

5o l

ine

fro

m

x B =

0.0

02

3 a

nd

xD =

0.6

75

. T

he

nu

mb

er o

f m

inim

um

eq

uil

ibri

um

sta

ges

= j

ust

mo

re t

han

8 e

qu

ilib

riu

m s

tages

.

Page 78: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.33

(co

nti

nu

ed)

An

aly

sis:

(

c)

(co

nti

nu

ed)

Ex

erci

se 7

.33

(co

nti

nu

ed)

An

aly

sis:

(

c)

(co

nti

nu

ed)

Page 79: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.34

S

ub

ject

: S

trip

pin

g o

f is

op

rop

yl

alco

ho

l fr

om

wat

er a

t 1

atm

usi

ng e

ith

er a

par

tial

reb

oil

er o

r

op

en (

liv

e) s

team

.

Giv

en:

B

ub

ble

-po

int

liq

uid

fee

d c

on

tain

ing 1

0 m

ol%

alc

oh

ol.

V

apo

r o

ver

hea

d t

o c

on

tain

40

mo

l% a

lco

ho

l.

Bo

ilu

p,

V/F

= 0

.24

6.

Vap

or-

liq

uid

eq

uil

ibri

um

dat

a fr

om

Ex

erci

se 7

.33

.

Ass

um

pti

on

s:

Co

nst

ant

mo

lar

ov

erfl

ow

.

Fin

d:

D

eter

min

e th

e n

um

ber

of

equ

ilib

riu

m s

tages

fo

r: (

1)

Par

tial

reb

oil

er,

(2)

Op

en s

team

.

An

aly

sis:

T

ake

a b

asis

of

F =

10

0 k

mo

l/h

. V

apo

r ra

te l

eav

ing t

op

of

colu

mn

= V

= 0

.24

6F

= D

=

0.2

46

(10

0)

= 2

4.6

km

ol/

h.

Alc

oh

ol

in o

ver

hea

d v

apo

r =

0.4

(24

.6)

= 9

.84

km

ol/

h.

Wat

er i

n t

he

ov

erh

ead

vap

or

= 2

4.6

- 9

.84

= 1

4.7

6 k

mo

l/h

.

(1)

W

ith

a p

arti

al r

ebo

iler

, b

ott

om

s ra

te =

B =

F -

D =

10

0 -

24

.6 =

75

.4 k

mo

l/h

. A

lco

ho

l in

bo

tto

ms

= 1

0 -

9.8

4 =

0.1

6 k

mo

l/h

. M

ole

fra

ctio

n o

f al

coh

ol

in b

ott

om

s =

xB =

0.1

6/7

5.4

=

0.0

02

1.

Wit

h i

sop

rop

ano

l as

th

e m

ost

vo

lati

le c

om

po

nen

t, t

he

McC

abe-

Th

iele

dia

gra

m i

s giv

en

bel

ow

, w

her

e th

e eq

uil

ibri

um

cu

rve

is o

bta

ined

fro

m t

he

dat

a in

Ex

erci

se 7

.33

an

d t

he

q-l

ine

is

ver

tica

l th

rou

gh

x =

0.1

0.

Th

e st

rip

pin

g s

ecti

on

op

erat

ing l

ine

pas

ses

thro

ugh

th

e p

oin

t

{x=

0.0

02

1,

y=0

.00

21

}w

ith

a s

lop

e =

L/V

= F

/V =

10

0/2

4.6

= 4

.06

5.

It

also

pas

ses

thro

ugh

th

e

po

int

{x=

0.1

, y=

0.4

}.

Fro

m t

he

plo

t, t

he

nu

mb

er o

f eq

uil

ibri

um

sta

ges

= j

ust

les

s th

an 3

. C

all

it

2 e

qu

ilib

riu

m s

tages

in

th

e co

lum

n +

par

tial

reb

oil

er.

(2)

T

he

op

en s

team

rat

e =

V =

24

.6 k

mo

l/h

. T

he

liq

uid

rat

e =

L =

10

0 k

mo

l/h

. T

her

efo

re,

the

slo

pe

of

the

stri

pp

ing s

ecti

on

op

erat

ing l

ine

is t

he

sam

e as

fo

r p

art

(1),

i.e

.

L./

V =

10

0/2

4.6

= 4

.06

5.

No

w t

he

mo

le f

ract

ion

of

alco

ho

l in

th

e b

ott

om

s =

xB =

0.1

6/1

00

=

0.0

01

6.

Th

us,

as

sho

wn

in

th

e M

cCab

e-T

hie

le d

iagra

m b

elo

w,

the

op

erat

ing l

ine

pas

ses

thro

ugh

the

po

ints

{x=

0.0

01

6,

y=0

}an

d {

x=0

.10

, y=

0.4

0},

wit

h t

he

slo

pe

of

4.0

65

. N

ow

, T

he

nu

mb

er

of

equ

ilib

riu

m s

tag

es i

s eq

ual

to

3,

all

of

them

in

th

e co

lum

n.

Ex

erci

se 7

.34

(c

on

tin

ued

)

A

na

lysi

s:

Par

tial

Reb

oil

er C

ase:

Page 80: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.34

(c

on

tin

ued

)

A

na

lysi

s:

Op

en S

team

Cas

e:

E

xer

cise

7.3

5

Su

bje

ct:

Dis

till

atio

n o

f tw

o f

eed

s o

f m

ixtu

res

of

wat

er a

nd

ace

tic

acid

at

1 a

tm.

Giv

en:

F

eed

1 i

s a

bu

bb

le-p

oin

t li

qu

id o

f 1

00

km

ol/

h c

on

tain

ing 7

5 m

ol%

wat

er.

Fee

d 2

is

50

mo

l% v

apo

rize

d o

f 1

00

km

ol/

h c

on

tain

ing 5

0 m

ol%

wat

er.

Un

it c

on

sist

s o

f a

pla

te c

olu

mn

, to

tal

con

den

ser,

an

d p

arti

al r

ebo

iler

. D

isti

llat

e is

to

co

nta

in 9

8 m

ol%

wat

er.

Bo

tto

ms

is t

o c

on

tain

5

mo

l% w

ater

. R

eflu

x r

atio

, L

/D =

R =

1.2

tim

es m

inim

um

. V

apo

r-li

qu

id e

qu

ilib

riu

m d

ata.

Ass

um

pti

on

s:

C

on

stan

t m

ola

r o

ver

flo

w.

Fin

d:

O

pti

mal

fee

d s

tage

loca

tio

ns

and

nu

mb

er o

f eq

uil

ibri

um

sta

ges

.

An

aly

sis:

W

ater

is

the

mo

re v

ola

tile

co

mp

on

ent.

C

om

pu

te f

low

rat

es o

f d

isti

llat

e an

d b

ott

om

s.

Ov

eral

l to

tal

mat

eria

l b

alan

ce:

F

1 +

F2 =

10

0 +

10

0 =

20

0 =

D +

B

(1)

Ov

eral

l w

ater

bal

ance

: (

0.7

5)(

10

0)

+ 0

.5(1

00

) =

12

5 =

xDD

+ x

BB

= 0

.98

D +

0.0

5B

(2)

So

lvin

g E

qs.

(1

) an

d (

2),

D

= 1

23

.66

km

ol/

h

an

d

B

= 7

6.3

4 k

mo

l/h

.

Ass

um

e th

e m

inim

um

ref

lux

is

con

tro

lled

by t

he

up

per

fee

d.

Th

is i

s v

erif

ied

in

th

e

McC

abe-

Th

iele

dia

gra

m b

elo

w,

wh

ere

the

equ

ilib

riu

m c

urv

e is

plo

tted

fro

m t

he

dat

a, t

he

q-l

ine

for

Fee

d 1

is

ver

tica

l th

rou

gh

th

e p

oin

t, x

= 0

.75

, th

e q

-lin

e fo

r F

eed

2 h

as a

slo

pe

of

-1 s

tart

ing

fro

m x

= 0

.50

, an

d t

he

op

erat

ing l

ine

for

the

up

per

sec

tio

n b

etw

een

Fee

d 1

an

d t

he

con

den

ser

is

dra

wn

th

rou

gh

th

e tw

o p

oin

ts,

{x=

0.9

8,

y=0

.98

} a

nd

th

e in

ters

ecti

on

of

the

equ

ilib

riu

m c

urv

e an

d

the

q-l

ine

for

Fee

d 1

. F

rom

th

e p

lot,

fo

r th

e u

pp

er s

ecti

on

, L

/V =

(0

.98

-0.8

28

)/(0

.98

-0.7

5)

=

0.6

61

. F

rom

Eq

. (7

-27

), R

= L

/D =

(L

/V)/

[1 -

(L

/V)]

= 0

.66

1/(

1 -

0.6

61

) =

1.9

5.

Th

eref

ore

,

L =

1.9

5D

= 1

.95

(12

3.6

6)

= 2

41

.1 k

mo

l/h

an

d

V =

L +

D =

24

1.1

+ 1

23

.66

= 3

64

.8 k

mo

l/h

.

In t

he

mid

dle

sec

tio

n,

bet

wee

n t

he

two

fee

ds,

L' =

L +

F1 =

24

1.1

+ 1

00

= 3

41

.1 k

mo

l/h

an

d

V' =

V =

36

4.8

km

ol/

h.

Th

eref

ore

, th

e sl

op

e o

f th

e m

idd

le s

ecti

on

op

erat

ing l

ine

= L

'/V

' =

34

1.1

/36

4.8

= 0

.93

5.

As

seen

in

th

e d

iagra

m b

elo

w,

this

lin

e d

oes

no

t ca

use

a p

inch

ed r

egio

n a

t

Fee

d 2

. T

her

efo

re,

the

assu

mp

tio

n i

s co

rrec

t an

d R

min

= 1

.95

.

Fo

r an

op

erat

ing r

eflu

x r

atio

of

1.2

tim

es m

inim

um

, L

= 1

.2(2

41

.1)

= 2

89

.3 k

mo

l/h

.

Th

e v

apo

r ra

te i

n t

he

up

per

sec

tio

n =

V =

L +

D =

28

9.3

+ 1

23

.66

= 4

13

km

ol/

h.

Th

eref

ore

th

e u

pp

er s

ecti

on

op

erat

ing l

ine

has

a s

lop

e, L

/V =

28

9.3

/41

3 =

0.7

00

an

d p

asse

s

thro

ugh

th

e p

oin

t y

= x

= 0

.98

. I

t in

ters

ects

th

e v

erti

cal

q-l

ine

at x

= 0

.75

an

d,

for

the

slo

pe

of

0.7

00

= (

0.9

8 -

y)/

(0.9

8 -

0.7

5),

at

y =

0.8

19

.

Fo

r th

e m

idd

le s

ecti

on

, L

' =

L +

F1

=

28

9.3

+1

00

= 3

89

.3 k

mo

l/h

an

d V

' =

V =

41

3

km

ol/

h.

Th

eref

ore

, th

e m

idd

le s

ecti

on

op

erat

ing l

ine

has

a s

lop

e o

f L

'/V

' =

38

9.3

/41

3 =

0.9

43

and

in

ters

ects

th

e q

-lin

e fo

r x

= 0

.75

at

y =

0.8

19

. I

t in

ters

ects

th

e q

-lin

e fo

r F

eed

2 a

t y

= 0

.54

3.

Fo

r th

e lo

wer

sec

tio

n,

L"

= L

' +

0.5

F2 =

38

9.3

+ 5

0 =

43

9.3

km

ol/

h

and

V"=

V' -

0.5

F2=

41

3 -

50

= 3

63

km

ol/

h.

Th

eref

ore

, th

e lo

wer

sec

tio

n o

per

atin

g l

ine

has

a s

lop

e o

f L

"/V

" =

43

9.3

/36

3 =

1.2

10

an

d i

nte

rsec

ts t

he

q-l

ine

for

Fee

d 2

at

y =

0.5

43

an

d t

he

45

o l

ine

at x

B =

0.0

5.

In t

he

McC

abe-

Th

iele

dia

gra

ms

bel

ow

an

d o

n t

he

nex

t p

age

for

the

hig

h,

mid

dle

, an

d l

ow

mo

le

frac

tio

n r

egio

ns,

th

e th

ree

op

erat

ing l

ines

are

dra

wn

an

d t

he

equ

ilib

riu

m s

tages

are

ste

pp

ed o

ff s

o

as t

o p

lace

th

e tw

o f

eed

s at

th

eir

op

tim

al l

oca

tio

ns.

A

s se

en,

the

nu

mb

er o

f eq

uil

ibri

um

sta

ges

req

uir

ed =

ju

st l

ess

than

33

eq

uil

ibri

um

sta

ges

. C

all

it 3

2 e

qu

ilib

riu

m s

tages

in

th

e co

lum

n a

nd

a

par

tial

reb

oil

er.

Op

tim

al f

eed

sta

ges

are

lo

cate

d a

t S

tages

17

an

d 2

7 f

rom

th

e to

p.

Page 81: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.35

(co

nti

nu

ed)

An

aly

sis:

(c

on

tin

ued

)

Ex

erci

se 7

.35

(c

on

tin

ued

) A

na

lysi

s:

(co

nti

nu

ed)

Page 82: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.35

(c

on

tin

ued

) A

na

lysi

s:

(co

nti

nu

ed)

Ex

erci

se 7

.35

(c

on

tin

ued

) A

na

lysi

s:

(co

nti

nu

ed)

Page 83: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.36

S

ub

ject

: D

isti

llat

ion

at

1 a

tm o

f a

mix

ture

of

met

han

ol

(M)

and

eth

ano

l (E

) to

ob

tain

a

dis

till

ate,

bo

tto

ms,

an

d a

liq

uid

sid

estr

eam

.

Giv

en:

10

0 k

mo

l/h

of

a 2

5 m

ol%

vap

ori

zed

mix

ture

of

75

mo

l% m

eth

ano

l in

eth

ano

l.

Dis

till

ate

is 9

6 m

ol%

met

han

ol

and

bo

tto

ms

is 5

mo

l% m

eth

ano

l.

Un

it c

on

sist

s o

f a

tota

l

con

den

ser,

pla

te c

olu

mn

, an

d p

arti

al r

ebo

iler

. S

ides

trea

m i

s 1

5 k

mo

l/h

of

20

mo

l% m

eth

ano

l.

Ref

lux

rat

io,

R =

1.2

tim

es m

inim

um

.

Ass

um

pti

on

s:

C

on

stan

t m

ola

r o

ver

flo

w.

Rao

ult

's l

aw K

-val

ues

.

Fin

d:

N

um

ber

of

theo

reti

cal

stag

es a

nd

op

tim

al l

oca

tio

ns

of

feed

an

d s

ides

trea

m.

An

aly

sis:

F

irst

co

mp

ute

th

e m

ater

ial

bal

ance

.

Ov

eral

l to

tal

mat

eria

l b

alan

ce:

F

= 1

00

= D

+ B

+ S

= D

+ B

+ 1

5

(1

)

Ov

eral

l m

eth

ano

l m

ater

ial

bal

ance

: 7

5 =

0.9

6D

+ 0

.05

B +

0.2

0(1

5)

(2

)

So

lvin

g E

qs.

(1

) an

d (

2),

D

= 7

4.4

5 k

mo

l/h

an

d

B =

10

.55

km

ol/

h

N

ow

det

erm

ine

the

equ

ilib

riu

m c

urv

e.

At

1 a

tm (

14

.69

6 p

sia)

, m

eth

ano

l b

oil

s at

64

.7oC

and

eth

ano

l b

oil

s at

78

.4oC

. F

rom

Fig

. 2

.4,

the

vap

or

pre

ssu

re o

f et

han

ol

at 6

4.7

oC

= 8

.2 p

sia.

Th

e v

apo

r p

ress

ure

of

met

han

ol

at 7

8.4

oC

= 2

5 p

sia.

F

or

the

Rao

ult

's l

aw K

-val

ue,

Eq

. (2

-44

)

app

lies

. C

om

bin

ing t

his

eq

uat

ion

wit

h t

he

def

init

ion

of

the

rela

tiv

e v

ola

tili

ty o

f E

q.

(2-2

1),

giv

es,

for

met

han

ol

wit

h r

esp

ect

to t

he

less

vo

lati

le e

than

ol,

αΜ

,Ε =

(P

s ) M/

(Ps ) E

.

At

64

.7oC

, α

Μ,Ε

= 1

4.6

96

/8.2

= 1

.79

. A

t 7

8.4

oC

, α

Μ,Ε

= 2

5/1

4.6

96

= 1

.70

. S

ince

th

ese

val

ues

are

clo

se (

wit

hin

abo

ut

5%

), u

se a

n e

qu

ilib

riu

m c

urv

e b

ased

on

a c

on

stan

t α

= (

1.7

0 +

1.7

9)/

2 =

1.7

45

. F

rom

Eq

.

(7-3

), t

he

curv

e is

co

mp

ute

d f

rom

,

y =

αx/

[1 +

x(α

-1)]

= 1

.74

5x/

(1+

0.7

45

x)

(3)

Th

e M

cCab

e-T

hie

le d

iagra

m o

n t

he

nex

t p

age

sho

ws

the

op

erat

ing l

ines

fo

r d

eter

min

ing t

he

min

imu

m r

eflu

x r

atio

. I

t as

sum

es t

hat

th

e p

inch

reg

ion

occ

urs

at

the

feed

sta

ge

and

no

t at

th

e

sid

estr

eam

sta

ge.

F

rom

Eq

. (7

-18

), q

fo

r 2

5 m

ol%

vap

ori

zed

= 0

.75

. F

rom

Eq

. (7

-26

), t

he

slo

pe

of

the

q-l

ine

= q

/(q

-1)

= 0

.75

/(0

.75

-1)

= -

3.

Th

e u

pp

er s

ecti

on

op

erat

ing l

ine

inte

rsec

ts t

he

q-l

ine

and

eq

uil

ibri

um

cu

rve

at y

=0

.82

3 a

nd

x=

0.7

27

.

Th

us,

slo

pe

of

the

up

per

sec

tio

n o

per

atin

g l

ine

=

L/V

= (

0.9

6-0

.82

3)/

(0.9

6-0

.72

7)

= 0

.58

8.

Fro

m E

q.

(7-2

7),

Rm

in =

(L

/V)/

[1 -

(L

/V)]

= 0

.58

8/(

1-

0.5

88

) =

1.4

27

. T

her

efo

re,

L =

1.4

27

(74

.45

) =

10

6.3

km

ol/

h

and

V

= L

+ D

= 1

06

.3 +

74

.45

=

18

0.7

5 k

mo

l/h

. I

n t

he

mid

dle

sec

tio

n b

etw

een

th

e fe

ed s

tage

and

sid

estr

eam

sta

ge,

fo

r 2

5 m

ol%

vap

ori

zati

on

, L

' =

L +

0.7

5(1

00

) =

10

6.3

+ 7

5 =

18

1.3

km

ol/

h

and

V

' =

V -

0.2

5(1

00

) =

18

0.7

5 -

25

= 1

55

.75

km

ol/

h.

Th

us,

L'/

V' =

18

1.3

/15

5.7

5 =

1.1

64

. T

he

mid

dle

sec

tio

n o

per

atin

g l

ine

has

this

slo

pe

and

pas

ses

thro

ugh

y=

0.8

23

an

d x

=0

.72

7.

In

th

e lo

wer

sec

tio

n o

per

atin

g l

ine

bel

ow

th

e

sid

estr

eam

, fo

r a

liq

uid

sid

estr

eam

flo

w r

ate

of

15

km

ol/

h,

L"

= L

' -

S =

18

1.3

- 1

5 =

16

6.3

km

ol/

h

and

V

" =

V' =

15

5.7

5 k

mo

l/h

.

Th

us,

L"/

V"

= 1

66

.3/1

55

.75

= 1

.06

8.

Th

is l

ine

pas

ses

thro

ugh

th

e p

oin

t y=

0.0

5 a

nd

x =

0.0

5 w

ith

th

e sl

op

e o

f 1

.06

8.

It

also

in

ters

ects

th

e m

idd

le

sect

ion

op

erat

ing l

ine

at t

he

sid

estr

eam

co

mp

osi

tio

n,

x s =

0.2

0.

Th

ese

thre

e o

per

atin

g l

ines

are

dra

wn

in

th

e M

cCab

e-T

hie

le d

iagra

m,

sho

win

g t

hat

th

e m

idd

le s

ecti

on

op

erat

ing l

ine

lies

bel

ow

Ex

erci

se 7

.36

(co

nti

nu

ed)

An

aly

sis:

(co

nti

nu

ed)

the

equ

ilib

riu

m c

urv

e.

Th

eref

ore

, th

e as

sum

pti

on

th

at t

he

min

imu

m r

eflu

x i

s co

ntr

oll

ed b

y t

he

feed

sta

ge

is v

erif

ied

an

d t

he

min

imu

m r

eflu

x r

atio

is

1.4

27

.

Fo

r ac

tual

op

erat

ion

, re

flu

x r

atio

= 1

.2R

min

= 1

.2(1

.42

7)

= 1

.71

2.

Ref

lux

rat

e in

up

per

sect

ion

= L

= 1

.2L

min

= 1

.2(1

06

.3)

= 1

27

.6 k

mo

l/h

. V

apo

r ra

te =

V

= L

+ D

= 1

27

.6 +

74

.45

=

20

2.0

5 k

mo

l/h

. S

lop

e o

f u

pp

er s

ecti

on

op

erat

ing l

ine

= L

/V =

12

7.6

/20

2.0

5 =

0.6

32

. F

or

con

stan

t m

ola

r o

ver

flo

w,

the

flo

w r

ates

in

th

e o

ther

sec

tio

ns

are:

Mid

dle

sec

tio

n:

L' =

20

2.6

km

ol/

h

V' =

17

7.0

5 k

mo

l/h

L

'/V

' =

1.1

44

Lo

wer

sec

tio

n:

L"

= 1

87

.6 k

mo

l/h

V

" =

17

7.0

5 k

mo

l/h

L

"/V

" =

1.0

60

Page 84: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.36

(co

nti

nu

ed)

An

aly

sis:

(co

nti

nu

ed)

In t

he

McC

abe-

Th

iele

dia

gra

ms

bel

ow

, u

pp

er,

mid

dle

, an

d l

ow

er o

per

atin

g l

ines

are

bas

ed o

n t

hes

e v

alu

es s

tart

ing f

rom

th

e u

pp

er l

ine,

wh

ich

pas

ses

thro

ugh

th

e p

oin

t x

= 0

.96

on

th

e

45

o l

ine.

E

qu

ilib

riu

m s

tages

are

ste

pp

ed o

ff s

tart

ing f

rom

th

e d

isti

llat

e co

mp

osi

tio

n a

nd

swit

chin

g o

per

atin

g l

ines

at

the

app

rop

riat

e ti

mes

to

det

erm

ine

the

op

tim

al f

eed

sta

ge

and

sid

estr

eam

sta

ge

loca

tio

ns.

A

sep

arat

e M

cCab

e-T

hie

le d

iagra

m i

s u

sed

fo

r th

e u

pp

er s

ecti

on

to

ach

iev

e b

ette

r ac

cura

cy.

As

seen

19

eq

uil

ibri

um

sta

ges

plu

s a

par

tial

reb

oil

er a

re r

equ

ired

. T

he

op

tim

al f

eed

sta

ge

is 9

fro

m t

he

top

an

d t

he

op

tim

al s

ides

trea

m s

tage

is 1

7 f

rom

th

e to

p.

Ex

erci

se 7

.36

(co

nti

nu

ed)

An

aly

sis:

(co

nti

nu

ed)

Page 85: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.37

S

ub

ject

: D

isti

llat

ion

at

1 a

tm o

f a

mix

ture

of

tolu

ene

and

ph

eno

l fo

r a

giv

en b

oil

up

rat

io,

wit

h a

n a

lter

nat

ive

usi

ng a

n i

nte

rreb

oil

er.

Giv

en:

1

,00

0 k

mo

l/h

of

a sa

tura

ted

liq

uid

fee

d o

f 2

5 m

ol%

to

luen

e.

Dis

till

ate

is 9

8 m

ol%

tolu

ene

and

bo

tto

ms

is 2

mo

l% t

olu

ene.

T

he

bas

e u

nit

co

nsi

sts

of

a to

tal

con

den

ser,

a p

late

colu

mn

, an

d a

par

tial

reb

oil

er,

wit

h a

bo

ilu

p r

atio

, V

B =

VB

/=

1.1

5 t

imes

min

imu

m.

Th

e

alte

rnat

ive

un

it a

dd

s an

in

terr

ebo

iler

mid

way

in

th

e st

rip

pin

g s

ecti

on

to

pro

vid

e 5

0%

of

the

bo

ilu

p.

A t

able

of

T

-y-x

p

has

e eq

uil

ibri

um

dat

a

Ass

um

pti

on

s:

C

on

stan

t m

ola

r o

ver

flo

w.

Fin

d:

F

or

each

un

it,

det

erm

ine

the

nu

mb

er o

f th

eore

tica

l st

ages

. F

or

the

alte

rnat

ive

un

it,

det

erm

ine

the

tem

per

atu

re o

f th

e in

terr

ebo

iler

sta

ge.

An

aly

sis:

To

luen

e is

th

e m

ore

vo

lati

le u

nit

.

Ba

se u

nit

:

F

rom

th

e M

cCab

e-T

hie

le d

iagra

m b

elo

w,

the

min

imu

m b

oil

up

rat

io i

s d

eter

min

ed f

rom

the

slo

pe

of

the

stri

pp

ing s

ecti

on

op

erat

ing l

ine

that

in

ters

ects

th

e eq

uil

ibri

um

cu

rve

at t

he

feed

com

po

siti

on

of

x F =

0.2

5.

() m

in

0.8

15

0.0

2/

3.4

6

0.2

50

.02

−=

=−

LV

Fro

m E

q.

(7-2

8),

()

()

min

min

11

0.4

07

3.4

61

/1

==

=−

−B

VL

V

Ex

erci

se 7

.37

(co

nti

nu

ed)

An

aly

sis:

B

ase

Ca

se (

con

tin

ued

)

Fo

r co

lum

n o

per

atio

n,

VB =

1.1

5(V

B) m

in =

1.1

5(0

.40

7)

= 0

.46

8

Fro

m E

q.

(7-1

2),

th

e sl

op

e o

f th

e st

rip

pin

g s

ecti

on

op

erat

ing l

ine

is,

LV

V

VB

B

/.

..

=+

=+

=1

04

68

1

04

68

31

4

As

sho

wn

in

th

e M

cCab

e-T

hie

le d

iagra

m,

bel

ow

, a

lin

e o

f th

is s

lop

e is

dra

wn

th

rou

gh

th

e p

oin

t

x =

y =

0.0

2 u

nti

l it

in

ters

ects

th

e q

-lin

e.

Eq

uil

ibri

um

sta

ges

are

ste

pp

ed o

ff,

star

tin

g f

rom

th

e

dis

till

ate

po

int

at y

= x

= 0

.98

. T

he

op

tim

al f

eed

sta

ge

loca

tio

n i

s lo

cate

d a

s sh

ow

n a

t st

age

5

fro

m t

he

top

. T

he

tota

l n

um

ber

of

stag

es r

equ

ired

is

just

les

s th

an 8

, w

ith

on

e o

f th

ose

sta

ges

bei

ng t

he

par

tial

reb

oil

er.

Page 86: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.37

(co

nti

nu

ed)

An

aly

sis:

B

ase

Ca

se (

con

tin

ued

)

Ex

erci

se 7

.37

(co

nti

nu

ed)

An

aly

sis:

(

con

tin

ued

)

Alt

ern

ati

ve

un

it w

ith

In

terr

ebo

iler

:

F

or

colu

mn

op

erat

ion

wit

h a

n i

nte

rreb

oil

er t

hat

pro

vid

es 5

0%

of

the

reb

oil

er d

uty

, th

e

op

erat

ing b

oil

up

rat

io b

etw

een

th

e re

bo

iler

an

d t

he

inte

rreb

oil

er i

s 5

0%

of

0.4

68

or

0.2

34

.

Fro

m E

q.

(7-1

2),

th

e sl

op

e o

f th

e o

per

atin

g l

ine

in t

his

reg

ion

is:

LV

V

VB

B

/.

..

=+

=+

=1

02

34

1

02

34

52

7

Bet

wee

n t

he

inte

rreb

oil

er a

nd

th

e fe

ed s

tage,

th

e sl

op

e o

f th

e o

per

atin

g l

ine

rem

ain

s at

3.1

4,

bas

ed o

n a

mat

eria

l b

alan

ce a

rou

nd

th

e co

lum

n s

ecti

on

fro

m t

he

bo

tto

ms

to t

he

regio

n b

etw

een

the

inte

rreb

oil

er a

nd

th

e fe

ed s

tage.

T

hes

e tw

o o

per

atin

g l

ines

are

sh

ow

n i

n t

he

McC

abe-

Th

iele

dia

gra

m b

elo

w,

wh

ere

bo

th p

ass

thro

ugh

th

e p

oin

t y

= x

= 0

.02

. S

tep

pin

g o

ff s

tages

fro

m t

he

bo

tto

m,

it i

s se

en t

hat

3 s

tages

are

nee

ded

bel

ow

th

e fe

ed s

tage.

T

he

firs

t st

age

is t

he

par

tial

reb

oil

er.

Th

e in

terr

ebo

iler

is

loca

ted

at

the

seco

nd

eq

uil

ibri

um

sta

ge.

A

to

tal

of

8 e

qu

ilib

riu

m

stag

es i

s re

qu

ired

, ju

st s

ligh

tly m

ore

th

an t

hat

wh

en a

ll o

f th

e h

eat

inp

ut

is t

o t

he

par

tial

reb

oil

er

at t

he

bo

tto

m o

f th

e co

lum

n.

T

he

vap

or

com

po

siti

on

of

the

inte

rreb

oil

er s

tage

is 0

.34

5,

wh

ich

fro

m t

he

giv

en T

-y-x

ph

ase

equ

ilib

riu

m d

ata

corr

esp

on

ds

to a

tem

per

atu

re o

f ap

pro

xim

atel

y 1

73

oC

. T

he

inte

rreb

oil

er

cou

ld a

lso

be

loca

ted

at

the

thir

d s

tage

fro

m t

he

bo

tto

m.

Th

e w

ou

ld i

ncr

ease

th

e n

um

ber

of

stag

es b

y a

bo

ut

hal

f o

f a

stag

e an

d l

ow

er t

he

tem

per

atu

re o

f th

e in

terr

ebo

iler

sta

ge

to 1

62

oC

.

Page 87: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.37

(co

nti

nu

ed)

An

aly

sis:

(

con

tin

ued

)

Alt

ern

ati

ve

un

it w

ith

In

terr

ebo

iler

:

Ex

erci

se 7

.38

S

ub

ject

: E

ffec

t o

f th

e ad

dit

ion

of

an i

nte

rco

nd

ense

r an

d i

nte

rreb

oil

er t

o a

dis

till

atio

n

colu

mn

sep

arat

ing n

-bu

tan

e an

d n

-pen

tan

e.

Giv

en:

D

isti

llat

e an

d b

ott

om

s co

mp

osi

tio

ns

of

actu

al o

per

atio

n (

bef

ore

ad

dit

ion

of

inte

rco

nd

ense

r an

d i

nte

rreb

oil

er)

com

par

ed t

o d

esig

n s

pec

ific

atio

n.

Ass

um

pti

on

s:

C

on

stan

t m

ola

r o

ver

flo

w.

Co

nst

ant

rela

tiv

e v

ola

tili

ty.

Co

lum

n i

s la

rge

eno

ugh

in d

iam

eter

to

han

dle

in

crea

sed

ref

lux

an

d b

oil

up

. R

aou

lt's

law

(id

eal

solu

tio

ns

and

id

eal

gas

law

).

Fin

d:

W

het

her

th

e ad

dit

ion

can

im

pro

ve

the

op

erat

ion

bec

ause

of

the

incr

ease

d r

eflu

x a

nd

bo

ilu

p p

rod

uce

d b

y t

he

inte

rco

nd

ense

r an

d i

nte

rreb

oil

er.

An

aly

sis:

F

irst

, es

tim

ate

the

aver

age

rela

tiv

e v

ola

tili

ty f

or

nC

4/n

C5.

Ass

um

e a

dis

till

ate

tem

per

atu

re o

f 1

20

oF

so

th

at c

oo

lin

g w

ater

can

be

use

d i

n t

he

con

den

ser.

T

his

co

rres

po

nd

s to

a

satu

rati

on

pre

ssu

re o

f ab

ou

t 7

0 p

sia.

U

sin

g F

ig.

2.8

wit

h E

qs.

(2

-21

) an

d (

2-4

4),

th

e re

lati

ve

vo

lati

lity

of

bu

tan

e w

ith

res

pec

t to

pen

tan

e is

α =

1.1

/0.3

8 =

2.9

. A

ssu

min

g a

5 p

si p

ress

ure

dro

p,

giv

es a

bo

tto

ms

pre

ssu

re o

f 7

5 p

sia

and

a c

orr

esp

on

din

g t

emp

erat

ure

of

20

0oF

. U

sin

g F

ig.

2.8

wit

h E

qs.

(2

-21

) an

d (

2-4

4),

α =

2.1

/0.9

= 2

.3.

Tak

e th

e av

erag

e re

lati

ve

vo

lati

lity

as

2.6

an

d

dra

w a

y-x

eq

uil

ibri

um

cu

rve

usi

ng E

q.

(7-3

),

yx

x

x

x=

+−

=+

α

α1

1

26

11

6(

)

.

.

(1)

Th

e eq

uil

ibri

um

cu

rve,

bas

ed o

n E

q.

(1)

is s

ho

wn

bel

ow

in

a M

cCab

e-T

hie

le d

iagra

m.

In

clu

ded

on

th

e d

iagra

m a

re a

rbit

rary

op

erat

ing l

ines

an

d a

q-l

ine

for

an e

qu

imo

lar

feed

th

at i

s 5

0 m

ol%

vap

ori

zed

. U

sin

g t

hes

e li

nes

, 1

5 e

qu

ilib

riu

m s

tages

are

ste

pp

ed o

ff

bet

wee

n t

he

com

po

siti

on

s o

f

the

actu

al o

per

atio

n,

x D =

1 -

0.1

34

9 =

0.8

65

1 a

nd

xB =

0.0

42

8.

Th

e sl

op

e, L

/V,

of

the

rect

ifyin

g

sect

ion

op

erat

ing l

ine

is 0

.52

.

Page 88: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.38

(c

on

tin

ued

) A

na

lysi

s:

Act

ua

l o

per

ati

on

bef

ore

ad

dit

ion

(co

nti

nu

ed)

Ex

erci

se 7

.38

(c

on

tin

ued

) A

na

lysi

s:

Ad

dit

ion

(co

nti

nu

ed)

W

hen

an

in

terr

ebo

iler

is

add

ed b

etw

een

th

e re

bo

iler

an

d t

he

feed

sta

ge

and

an

inte

rco

nd

ense

r is

ad

ded

bet

wee

n t

he

feed

sta

ge

and

th

e o

ver

hea

d c

on

den

ser,

th

e co

lum

n i

s m

ade

up

of

4 s

ecti

on

s in

stea

d o

f 2

. E

ach

sec

tio

n h

as i

ts o

wn

op

erat

ing l

ine

as s

ho

wn

in

th

e M

cCab

e-

Th

iele

dia

gra

m b

elo

w.

In

ord

er t

o m

ain

tain

th

e sa

me

refl

ux

rat

io a

nd

bo

ilu

p r

atio

, th

e

inte

rco

nd

ense

r is

des

ign

ed t

o c

on

den

se a

mo

lar

flo

w r

ate

equ

al t

o t

hat

pro

du

ced

by t

he

inte

rreb

oil

er.

Th

us,

in

Sec

tio

n 2

bet

wee

n t

he

inte

rco

nd

ense

r an

d t

he

feed

sta

ge,

th

e L

/V r

atio

is

hig

her

th

an t

he

val

ue

in S

ecti

on

1 b

etw

een

th

e o

ver

hea

d c

on

den

ser

and

th

e in

terc

on

den

ser.

Th

us,

the

two

op

erat

ing l

ines

ab

ov

e th

e fe

ed s

tage

hav

e d

iffe

ren

t sl

op

es,

bu

t b

y m

ater

ial

bal

ance

bo

th

lin

es p

ass

thro

ugh

th

e d

isti

llat

e co

mp

osi

tio

n o

n t

he

45

o l

ine.

C

orr

esp

on

din

gly

, in

S

ecti

on

3 b

etw

een

th

e in

terr

ebo

iler

an

d t

he

feed

sta

ge,

th

e L

/V r

atio

is l

ow

er t

han

th

e v

alu

e in

Sec

tio

n 4

bet

wee

n t

he

reb

oil

er a

nd

th

e in

terr

ebo

iler

. T

hu

s, t

he

two

op

erat

ing l

ines

bel

ow

th

e fe

ed s

tage

hav

e d

iffe

ren

t sl

op

es,

bu

t b

y m

ater

ial

bal

ance

bo

th l

ines

pas

s

thro

ugh

th

e b

ott

om

s co

mp

osi

tio

n o

n t

he

45

o l

ine.

A

lso

no

te t

hat

by m

ater

ial

bal

ance

, th

e

op

erat

ing l

ines

fo

r S

ecti

on

s 1

an

d 4

in

ters

ect

on

th

e 4

5o l

ine,

an

d t

he

op

erat

ing l

ines

fo

r S

ecti

on

s

2 a

nd

3 i

nte

rsec

t o

n t

he

45

o li

ne.

S

tart

ing f

rom

x D

= 0

.99

74

, st

ages

are

ste

pp

ed o

ff f

rom

th

e to

p

bet

wee

n t

he

op

erat

ing l

ine

for

Sec

tio

n 1

an

d t

he

equ

ilib

riu

m c

urv

e fo

r a

few

sta

ges

bef

ore

sw

itch

to t

he

op

erat

ing l

ine

for

Sec

tio

n 2

. T

hen

5 s

tages

are

ste

pp

ed o

ff u

nti

l th

e fe

ed s

tage

is r

each

ed.

Th

en,

4 s

tages

are

ste

pp

ed o

ff b

etw

een

th

e o

per

atin

g l

ine

for

Sec

tio

n 3

an

d t

he

equ

ilib

riu

m c

urv

e

bef

ore

sw

itch

ing t

o t

he

op

erat

ing l

ine

for

Sec

tio

n 4

.

T

he

swit

ches

are

mad

e to

mai

nta

in t

he

sam

e n

um

ber

of

tota

l st

ages

, 1

5,

and

th

e sa

me

loca

tio

n f

or

the

feed

sta

ge.

O

ther

co

mb

inat

ion

s o

f ar

bit

rary

op

erat

ing l

ines

an

d a

q-l

ine

can

be

use

d t

o i

llu

stra

te t

he

po

ten

tial

of

an i

nte

rco

nd

ense

r an

d i

nte

rreb

oil

er.

Th

e im

po

rtan

t th

ing t

o n

ote

is t

hat

th

e ad

dit

ion

of

an i

nte

rco

nd

ense

r an

d i

nte

rreb

oil

er i

ncr

ease

s th

e d

ista

nce

bet

wee

n t

he

equ

ilib

riu

m c

urv

e an

d t

he

op

erat

ing l

ines

fo

r S

ecti

on

s 2

an

d 3

so

th

at t

he

step

s in

Sec

tio

ns

2 a

nd

3 a

cco

mp

lish

lar

ger

co

mp

osi

tio

n c

han

ges

.

Page 89: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.38

(c

on

tin

ued

) A

na

lysi

s:

Ad

dit

ion

(co

nti

nu

ed)

Ex

erci

se 7

.39

S

ub

ject

: D

isti

llat

ion

of

a m

ixtu

re o

f p

ara-

dic

hlo

rob

enze

ne

(P)

and

ort

ho

-dic

hlo

rob

enze

ne

(O),

tw

o c

lose

-bo

ilin

g i

som

ers,

usi

ng t

he

McC

abe-

Th

iele

dia

gra

m,

wit

h t

he

Kre

mse

r eq

uat

ion

to

accu

rate

ly c

alcu

late

th

e se

par

atio

ns

at t

he

two

en

ds

of

the

colu

mn

.

Giv

en:

F

eed

of

62

mo

l% P

an

d 3

8 m

ol%

O t

hat

is

slig

htl

y v

apo

rize

d w

ith

q =

0.9

. D

isti

llat

e is

liq

uid

of

98

mo

l% P

. B

ott

om

s is

96

mo

l% O

. P

ress

ure

s at

to

p a

nd

bo

tto

m a

re 2

0 p

sia

and

15

psi

a, r

esp

ecti

vel

y.

Ref

lux

rat

io,

R =

1.1

5 t

imes

min

imu

m.

Ass

um

pti

on

s:

C

on

stan

t m

ola

r o

ver

flo

w.

To

tal

con

den

ser

and

par

tial

reb

oil

er.

Av

erag

e

rela

tiv

e v

ola

tili

ty b

ased

on

Rao

ult

's l

aw.

Fin

d:

N

um

ber

of

theo

reti

cal

stag

es f

rom

McC

abe-

Th

iele

dia

gra

m,

usi

ng K

rem

ser

sup

ple

men

t

for

the

two

en

ds

of

the

colu

mn

.

An

aly

sis:

Fro

m a

sim

ula

tio

n p

rogra

m o

r h

and

bo

ok

, th

e te

mp

erat

ure

s at

th

e to

p a

nd

bo

tto

m o

f

the

colu

mn

, b

ased

on

th

e giv

en p

ress

ure

s an

d p

rod

uct

co

mp

osi

tio

ns,

are

det

erm

ined

to

be

app

rox

imat

ely 3

50

an

d 3

80

oF

. F

rom

vap

or

pre

ssu

re d

ata,

e.g

. fr

om

CH

EM

CA

D,

usi

ng E

q.

(7-1

),

αα

P,O

oP O

P,O

oP O

at

35

0F

=

and

at

380

F

=

P P

P P

s s

s s=

==

=1

56

5

13

41

11

67

23

16

19

98

11

59

. ..

. ..

Tak

e th

e av

erag

e re

lati

ve

vo

lati

lity

as

(1.1

67

+ 1

.15

9)/

2 =

1.1

63

.

Fro

m E

q.

(7-2

6),

th

e sl

op

e o

f th

e q

-lin

e =

q/(

q -

1)

= 0

.9/(

0.9

- 1

) =

-9

. F

eed

is

10

mo

l%

vap

ori

zed

.

Ap

ply

th

e F

ensk

e-U

nd

erw

oo

d-G

illi

lan

d m

eth

od

to

ob

tain

an

in

itia

l es

tim

ate

of

refl

ux

an

d s

tage

req

uir

emen

ts.

Can

use

th

e S

HO

R m

od

el i

n C

HE

MC

AD

. T

he

resu

lts

are:

Nm

in =

48

, R

min

= 9

.37

R

= 1

.15

Rm

in =

10

.77

N

= 1

03

(1

02

+ r

ebo

iler

)

N

of

feed

= s

tage

50

fro

m t

he

top

To

co

nst

ruct

th

e eq

uil

ibri

um

cu

rve

for

the

McC

abe-

Th

iele

met

ho

d,

use

Eq

. (7

-3),

yx

x

x

xP

P-O

P

PP

-O

P

P1

+1

+=

−=

α

α1

11

63

01

63

��

.

.

(1

)

Fro

m E

q.

(7-9

), t

he

slo

pe

of

the

rect

ifyin

g s

ecti

on

op

erat

ing l

ine

is,

L/V

= R

/(R

+1

) =

10

.77

/(1

0.7

7 +

1)

= 0

.91

50

Page 90: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.39

(c

on

tin

ued

) A

na

lysi

s:

(co

nti

nu

ed)

Th

is l

ine

pas

ses

thro

ugh

x =

0.9

8 o

n t

he

45

o l

ine.

T

he

equ

atio

n f

or

this

lin

e is

giv

en b

y E

q.

(7-9

),

yL V

xR

xx

xD

=� ��� ��

++

� ��� ��

=+

+

� ��� ��

=+

1

10

91

51

11

77

10

98

09

15

00

83

26

..

(.

).

.

(2)

Bel

ow

th

e fe

ed s

tage,

wit

h 1

0 m

ol%

vap

ori

zati

on

of

the

feed

, L

V/.

=1

05

35

. F

rom

a

rear

ran

gem

ent

of

Eq

. (7

-12

), t

he

bo

ilu

p r

atio

, V

B,

is 1

8.6

91

6.

T

he

equ

atio

n o

f th

e st

rip

pin

g

sect

ion

op

erat

ing l

ine

is g

iven

by E

q.

7-1

4),

yL V

xV

xx

xB

D=� ��� ��

−� ��� ��

=−� ��

� ��=

−1

10

53

51

18

69

16

00

41

05

35

00

02

14

..

(.

).

.

(3)

T

he

equ

atio

n f

or

the

q-l

ine

is g

iven

by E

q.

(7-2

6),

yq

qx

qz

xx

F=

� ��� ��

−−

� ��� ��

=−

� ��� ��

−−

� ��� ��

=−

+1

1

1

09

09

1

1

09

10

62

96

2.

..

(.

).

(4)

Bas

ed o

n E

qs.

(1

) to

(4

), t

he

McC

abe-

Th

iele

dia

gra

m i

n t

erm

s o

f P

, th

e m

ore

vo

lati

le c

om

po

nen

t,

is d

raw

n b

elo

w f

or

thre

e re

gio

ns:

(2

) x

= 0

.2 t

o 0

.4,

(3)

x =

0.4

to

0.6

, an

d (

4)

x =

0.6

to

0.8

, in

ord

er t

o g

ain

acc

ura

cy.

In

th

ese

thre

e re

gio

ns,

28

sta

ges

are

ste

pp

ed o

ff i

n t

he

rect

ifyin

g s

ecti

on

up

to

x =

0.8

, an

d 3

4.3

sta

ges

are

ste

pp

ed o

ff i

n t

he

stri

pp

ing s

ecti

on

do

wn

to

x =

0.2

.

L

et r

egio

n (

1)

exte

nd

fro

m x

= 0

.8 t

o 0

.98

(i.

e. x

D).

A

pp

ly t

he

Kre

mse

r eq

uat

ion

, E

q.

(7-3

9)

to t

his

reg

ion

. A

pp

ly t

his

eq

uat

ion

to

th

e h

eav

y c

om

po

nen

t, O

. O

bta

in t

he

K-v

alu

e fo

r O

fro

m t

he

top

α o

f 1

.16

7,

tak

ing t

he

K-v

alu

e fo

r P

= 1

.00

. T

her

efo

re,

KO =

1/1

.16

7 =

0.8

57

.

Th

eref

ore

, th

e ab

sorp

tio

n f

acto

r, A

= L

/KV

=

0.9

15

/0.8

57

= 1

.06

7.

Oth

er q

uan

titi

es n

eed

ed i

n

Eq

. (7

-39

) ar

e: x

o =

1 -

(x D

) P =

1 -

0.9

8 =

0.0

2

y 1 =

xo =

0.0

2

Fro

m E

q.

(2),

fo

r x N

= 0

.8,

yN

+1 f

or

P =

0.8

15

3.

Th

eref

ore

, fo

r O

, y N

+1 =

1 -

0.8

15

3 =

0.1

84

7.

NA

A

yx

K

yx

K

AR

o

o=

+−� ��� ��

− −

� ��� ��

��� �� =

+−� ��

� ��− −

� ��� ��

��� �� =

log

log

..

..

(.

)

..

(.

).

11

11

10

67

11

10

67

01

84

70

02

08

57

00

20

02

08

57

12

36

N+

1

1

log

log

.06

7

L

et r

egio

n (

5)

exte

nd

fro

m x

= 0

.04

(i.

e. x

B)

to 0

.20

. A

pp

ly t

he

Kre

mse

r eq

uat

ion

, E

q.

(7-4

0)

to t

his

reg

ion

. A

pp

ly t

his

eq

uat

ion

to

th

e li

gh

t co

mp

on

ent,

P.

Ob

tain

th

e K

-val

ue

for

P

fro

m t

he

bo

tto

m α

of

1.1

59

, ta

kin

g t

he

K-v

alu

e fo

r O

= 1

.00

. T

her

efo

re,

KP =

1.1

59

. T

her

efo

re,

the

abso

rpti

on

fac

tor

in t

he

stri

pp

ing s

ecti

on

is

AL

KV

==

=/

./

..

10

53

51

15

90

90

85

. O

ther

val

ues

nee

ded

in

Eq

. (7

-40

) ar

e x 1

= x

B =

0.0

4

and

xN

+1 =

0.2

0.

Th

eref

ore

,

N

AA

xx

K

xx

K

A

S=

+−

− −

� ��� ��

��� ��

� ��� ��

=

+−

− −

� ��� ��

��� ��

� ��� ��

=

log

/ /lo

g.

..

./

.

..

/.

.

10

90

85

10

90

85

02

00

04

11

59

00

40

04

11

59

13

5

1

11

��

��

N+

1

log

1lo

g1

0.0

98

5

Ex

erci

se 7

.39

(c

on

tin

ued

) A

na

lysi

s:

(co

nti

nu

ed)

Su

mm

ing t

he

abo

ve

resu

lts,

N

um

ber

of

equ

ilib

riu

m s

tages

in

th

e re

ctif

yin

g s

ecti

on

= 2

8 +

23

.6 =

51

.6 s

tages

N

um

ber

of

equ

ilib

riu

m s

tages

in

th

e st

rip

pin

g s

ecti

on

= 3

4.3

+ 1

3.5

= 4

7.8

sta

ges

C

all

it 9

9 s

tages

in

th

e co

lum

n p

lus

a p

arti

al r

ebo

iler

wit

h t

he

feed

to

sta

ge

52

fro

m t

he

top

.

Th

is c

om

par

es t

o 1

02

sta

ges

in

th

e co

lum

n p

lus

a p

arti

al r

ebo

iler

wit

h t

he

feed

to

sta

ges

50

fro

m t

op

as

det

erm

ined

by t

he

Fen

ske-

Un

der

wo

od

-Gil

lila

nd

met

ho

d.

Page 91: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.39

(c

on

tin

ued

) A

na

lysi

s:

(co

nti

nu

ed)

E

xer

cise

7.3

9 (c

on

tin

ued

)

A

na

lysi

s:

(co

nti

nu

ed)

Page 92: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.40

S

ub

ject

: U

se o

f a

McC

abe-

Th

iele

dia

gra

m t

o d

eter

min

e st

age

req

uir

emen

ts f

or

the

dis

till

atio

n o

f ai

r in

to n

itro

gen

an

d o

xygen

usi

ng a

Lin

de

do

ub

le c

olu

mn

.

Giv

en:

A

s sh

ow

n i

n F

ig.

7.4

5,

the

dis

till

atio

n c

on

sist

s o

f an

up

per

co

lum

n (

UC

) o

per

atin

g a

t 1

atm

, o

n t

op

of

a lo

wer

co

lum

n (

LC

) o

per

atin

g a

t 4

to

5 a

tm.

Co

mp

ress

ed a

ir,

con

tain

ing 7

9

mo

l% N

2 i

s co

nd

ense

d t

o s

up

ply

hea

t in

th

e re

bo

iler

of

LC

, an

d t

hen

is

fed

as

liq

uid

air

to

an

inte

rmed

iate

tra

y o

f L

C.

Bo

tto

ms

liq

uid

fro

m L

C,

con

tain

ing a

bo

ut

55

mo

l% N

2,

is t

he

feed

to

an

inte

rmed

iate

tra

y i

n U

C.

Th

e re

bo

iler

of

UC

is

the

con

den

ser

for

LC

.

Co

nd

ensa

te f

rom

th

e to

p

of

LC

is

nea

rly p

ure

N2

, w

hic

h i

s se

nt

as r

eflu

x t

o t

he

top

of

UC

. T

he

reb

oil

er a

t th

e b

ott

om

of

UC

pro

vid

es a

lmo

st p

ure

O2

bo

ilu

p f

or

UC

. N

earl

y p

ure

liq

uid

O2 i

s w

ith

dra

wn

fro

m t

he

UC

reb

oil

er s

um

p a

t th

e b

ott

om

of

UC

. T

he

UC

has

no

co

nd

ense

r.

Nea

rly p

ure

gas

eou

s N

2 l

eav

es

the

top

of

UC

.

Th

is i

s co

nsi

sten

t w

ith

th

e fa

ct t

hat

N2 w

ith

a n

orm

al b

oil

ing p

oin

t o

f -

19

5.8

oC

(77

.4 K

) is

mo

re v

ola

tile

th

an O

2 w

ith

a n

orm

al b

oil

ing p

oin

t o

f -1

83

oC

(9

0.2

K).

Ass

um

pti

on

s:

C

on

stan

t m

ola

r o

ver

flo

w.

Co

nst

ant

rela

tiv

e v

ola

tili

ty a

t ea

ch p

ress

ure

.

Fin

d:

C

on

stru

ctio

n l

ines

on

a M

cCab

e-T

hie

le d

iagra

m t

hat

en

able

th

e d

eter

min

atio

n o

f st

age

req

uir

emen

ts.

An

aly

sis:

I

n L

C,

the

N2 c

om

po

siti

on

ran

ges

fro

m 5

5 m

ol%

at

the

bo

tto

m t

o a

bo

ut

99

mo

l% a

t

the

top

, w

ith

a f

eed

of

79

mo

l%.

Bas

ed o

n c

alcu

lati

on

s u

sin

g K

-val

ues

fro

m t

he

SR

K e

qu

atio

n o

f

stat

e at

4.5

atm

, th

e av

erag

e re

lati

ve

vo

lati

lity

in

LC

is

2.5

. I

n U

C,

the

N2 c

om

po

siti

on

ran

ges

fro

m a

bo

ut

1 m

ol%

at

the

bo

tto

m t

o 9

9 m

ol%

at

the

top

, w

ith

a f

eed

of

55

mo

l%.

B

ased

on

calc

ula

tio

ns

usi

ng K

-val

ues

fro

m t

he

SR

K e

qu

atio

n o

f st

ate

at 1

atm

, th

e av

erag

e re

lati

ve

vo

lati

lity

in

UC

is

4.0

. U

sin

g E

q.

(7-3

), e

qu

ilib

riu

m c

urv

es f

or

thes

e co

nst

ant

α c

ases

are

sh

ow

n

in t

he

McC

abe-

Th

iele

dia

gra

m o

n t

he

nex

t p

age.

H

ow

ever

, so

as

no

t to

clu

tter

th

e d

iagra

m,

the

curv

e fo

r U

C a

t 1

atm

is

bas

ed o

n N

2,

usi

ng,

yx

x

x

xN

NO

N

NN

O

N

N2

22

2

22

2

2

21

+1

+3

=−

=−

α

α1

4

(1

)

wh

ile

the

curv

e fo

r L

C a

t 4

.5 a

tm i

s b

ased

on

O2,

usi

ng,

yx

x

x

x

x

xO

ON

O

OO

N

O

O

O

O2

22

2

22

2

2

2

2

21

+1

+1

-0

.6=

−=

−=

α

α1

12

5 12

51

04

��

(/

.) /

.

.

(2

)

No

te t

hat

th

e eq

uil

ibri

um

cu

rve

for

1 a

tm i

s ab

ov

e th

e 4

5o li

ne,

wh

ile

that

fo

r 4

.5 a

tm i

s b

elo

w

the

45

o l

ine.

T

yp

ical

op

erat

ing l

ines

an

d q

-lin

es a

re s

ho

wn

fo

r d

eter

min

ing t

he

stag

e

req

uir

emen

ts.

Ex

erci

se 7

.40

(c

on

tin

ued

) A

na

lysi

s:

(co

nti

nu

ed)

Page 93: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.41

S

ub

ject

: C

om

par

iso

n o

f m

easu

red

wit

h p

red

icte

d p

late

eff

icie

ncy

fo

r d

isti

llat

ion

of

a

met

han

ol-

wat

er m

ixtu

re.

Giv

en:

P

erfo

rman

ce d

ata

for

a d

isti

llat

ion

co

lum

n.

Vap

or-

liq

uid

eq

uil

ibri

um

dat

a.

Ass

um

pti

on

s:

P

arti

al r

ebo

iler

is

an e

qu

ilib

riu

m s

tage.

C

on

stan

t m

ola

r o

ver

flo

w.

Fin

d:

(a)

O

ver

all

pla

te e

ffic

ien

cy f

rom

per

form

ance

dat

a.

(b

) P

red

icte

d p

late

eff

icie

ncy

fro

m D

rick

amer

-Bra

dfo

rd c

orr

elat

ion

.

(c

) P

red

icte

d p

late

eff

icie

ncy

fro

m O

'Co

nn

ell

corr

elat

ion

.

(d

) P

red

icte

d e

ffic

ien

cy f

rom

Ch

an-F

air

corr

elat

ion

.

An

aly

sis:

(a

) C

on

ver

t th

e p

erfo

rman

ce d

ata

for

feed

an

d p

rod

uct

flo

w r

ates

an

d

com

po

siti

on

s fr

om

mas

s u

nit

s in

to m

ole

un

its,

mo

lecu

lar

wei

gh

ts o

f 3

2.0

4 f

or

met

han

ol

and

18

.02

fo

r w

ater

. T

he

resu

lts

are

as f

oll

ow

s:

F

low

ra

te,

lbm

ol/

h:

M

ole

fra

ctio

n:

Co

mp

on

ent

Fee

d

Dis

till

ate

B

ott

om

s F

eed

D

isti

lla

te

Bo

tto

ms

Met

han

ol

7

09

.1

70

2.7

6.4

0

.36

0

0.9

15

0

.00

53

Wat

er

12

60

.8

6

5.3

1

19

5.5

0

.64

0

0.0

85

0

.99

47

To

tal:

1

96

9.9

7

68

.0

12

01

.9

1.0

00

1

.00

0

1.0

00

0

Use

th

e M

cCab

e-T

hie

le m

eth

od

, b

ased

on

met

han

ol

mo

le f

ract

ion

s, t

o f

ind

th

e n

um

ber

of

equ

ilib

riu

m s

tages

nee

ded

. T

he

slo

pe

of

the

rect

ifyin

g s

ecti

on

op

erat

ing l

ine

is g

iven

by E

q.

(7-

7).

L

/V =

R/(

R +

1)=

0.9

47

/(1

.94

7)=

0.4

86

. T

his

lin

e in

ters

ects

th

e 4

5o l

ine

at x

= 0

.91

5.

Th

e sl

op

e o

f th

e st

rip

pin

g s

ecti

on

op

erat

ing l

ine

is g

iven

by E

q.

(7-1

2).

LV

VV

BB

//

=+

1��

= (

1.1

38

+ 1

)/1

.13

8 =

1.8

8.

Th

is l

ine

inte

rsec

ts t

he

45

oi l

ine

at x

= 0

.00

56

.

Th

e M

cCab

e-T

hie

le d

iagra

m i

s giv

en b

elo

w i

n t

wo

par

ts t

o a

chie

ve

accu

racy

. F

rom

th

e tw

o p

arts

of

the

dia

gra

m,

it i

s o

bse

rved

th

at t

he

two

op

erat

ing l

ines

do

no

t in

ters

ect

on

th

e q

-lin

e.

Th

is i

s

pro

bab

ly b

ecau

se t

he

assu

mp

tio

n o

f co

nst

ant

mo

lar

ov

erfl

ow

is

no

t v

alid

an

d t

he

op

erat

ing l

ines

hav

e so

me

curv

atu

re.

Ass

um

ing t

he

feed

sta

ge

in t

he

actu

al c

olu

mn

is

nea

r th

e o

pti

mal

lo

cati

on

,

the

qu

esti

on

able

McC

abe-

Th

iele

dia

gra

m g

ives

5 e

qu

ilib

riu

m s

tages

in

th

e st

rip

pin

g s

ecti

on

, o

ne

of

wh

ich

is

the

par

tial

reb

oil

er,

and

4.2

eq

uil

ibri

um

sta

ges

in

th

e re

ctif

yin

g s

ecti

on

. T

hu

s, t

he

tota

l eq

uil

ibri

um

sta

ges

in

th

e co

lum

n =

Nt =

8.2

+ t

he

par

tial

reb

oil

er.

Th

e co

lum

n c

on

tain

s 1

2

pla

tes

+ t

he

par

tial

reb

oil

er.

Fro

m E

q.

(6-2

1),

th

e o

ver

all

pla

te e

ffic

ien

cy i

s,

Eo =

Nt /

Na =

8.2

/12

= 0

.68

or

68

%.

Th

e co

lum

n c

on

tain

s 5

pla

tes

in t

he

rect

ifyin

g s

ecti

on

. T

his

is

equ

ival

ent

to a

pla

te e

ffic

ien

cy i

n

that

sec

tio

n o

f 4

.2/5

= 0

.84

or

84

%.

Th

e st

rip

pin

g s

ecti

on

co

nta

ins

6 p

late

s p

lus

the

feed

pla

te.

Ex

erci

se 7

.41

(co

nti

nu

ed)

An

aly

sis:

(a

) (

con

tin

ued

)

Th

eref

ore

, th

e ef

fici

ency

in

th

is s

ecti

on

is

4/7

= 0

.57

or

57

%.

No

te t

hes

e re

sult

s ar

e su

bje

ct t

o d

egre

e o

f cu

rvat

ure

of

the

op

erat

ing l

ines

an

d t

he

pla

cem

ent

of

the

feed

in

th

e M

cCab

e-T

hie

le m

eth

od

. I

n t

he

McC

abe-

Th

iele

met

ho

d,

if o

ne

mo

re e

qu

ilib

riu

m

stag

e is

ad

ded

to

th

e st

rip

pin

g s

ecti

on

, so

as

to g

ive

5 s

tages

plu

s th

e p

arti

al r

ebo

iler

, th

en t

he

rect

ifyin

g s

ecti

on

on

ly n

eed

s 3

.8 e

qu

ilib

riu

m s

tages

. T

hen

th

e o

ver

all

pla

te e

ffic

ien

cy i

s 7

3%

,

wit

h

71

% i

n t

he

stri

pp

ing s

ecti

on

an

d 7

6%

in

th

e re

ctif

yin

g s

ecti

on

. T

his

sti

ll d

oes

no

t ac

cou

nt

for

the

effe

ct o

f cu

rvat

ure

of

the

op

erat

ing l

ines

.

Page 94: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.41

(co

nti

nu

ed)

An

aly

sis:

(a

) (

con

tin

ued

)

(b

) F

rom

Eq

. (7

-42

),

Eo =

13

.3 -

66

.7 l

og µ

T

ake

the

vis

cosi

ty a

s th

at o

f th

e fe

ed =

0.3

4 c

P

E

o =

13

.3 -

66

.7 l

og (

0.3

4)

= 4

4.6

%

Th

is i

s p

oo

r ag

reem

ent

wit

h t

he

per

form

ance

dat

a.

(c

) F

rom

Eq

. (7

-43

), E

o =

50

.3(α

µ)-0

.22

6

At

the

feed

co

mp

osi

tio

n,

x =

0.3

6 a

nd

y =

0.7

1.

Th

eref

ore

, fr

om

Eq

s (2

-19

) an

d (

2-2

1 c

om

bin

ed,

the

rela

tiv

e v

ola

tili

ty i

s, α

= (

y/x

)/[(

1 -

y)/

(1 -

x)]

= (

0.7

1/0

.36

)/(0

.29

/0.6

4)

= 4

.4

Ex

erci

se 7

.41

(co

nti

nu

ed)

An

aly

sis:

E

o =

50

.3[(

4.4

)(0

.34

)]-0

.22

6 =

45

.9%

No

w c

orr

ect

for

len

gth

of

liq

uid

pat

h f

rom

Fig

. 7

.5.

Co

lum

n d

iam

eter

= 6

ft.

A

ssu

me

len

gth

of

liq

uid

pat

h =

70

% o

f co

lum

n d

iam

eter

= 0

.7(6

) =

4.2

ft.

F

rom

Fig

. 7

.5,

corr

ecti

on

to

be

add

ed =

10

%.

Th

eref

ore

co

rrec

ted

Eo =

45

.9 +

10

= 5

5.9

%

Th

is a

lso

ap

pea

rs t

o b

e lo

w.

(d

) F

rom

Eq

. (6

-56

),

NO

G =

- l

n (

1 -

EO

V).

T

her

efo

re,

EO

V =

1 -

ex

p(-

NO

G)

Use

Eq

s. (

6-6

2,

(6-6

4),

(6

-66

), a

nd

(6

-67

) as

in

Ex

amp

le 6

.7.

Car

ry o

ut

the

calc

ula

tio

ns

at t

he

bo

tto

m t

ray b

ased

on

met

han

ol

dif

fusi

on

. C

on

dit

ion

s ar

e:

G

as

Liq

uid

Mo

lar

flo

w r

ate,

km

ol/

h

63

0

1,1

92

Mo

lecu

lar

wei

gh

t 1

8.5

1

8.0

Den

sity

, k

g/m

3

0.6

57

9

40

Est

imat

e li

qu

id d

iffu

siv

ity o

f m

eth

ano

l in

wat

er a

t 2

12

oF

= 3

73

K.

Fro

m P

erry

's H

and

bo

ok

, D

L =

1.6

x 1

0-5

cm2/s

at

25

oC

. T

he

vis

cosi

ty o

f w

ater

at

21

2oF

= 0

.25

cP

. U

sin

g E

q.

(3-3

9)

to c

orr

ect

for

tem

per

atu

re a

nd

vis

cosi

ty,

DL =

1.6

x 1

0-5

(3

73

/29

8)(

1/0

.25

) =

8 x

10

-5 c

m2/s

Est

imat

e gas

dif

fusi

vit

y o

f m

eth

ano

l in

wat

er v

apo

r fr

om

Eq

. (3

-36

).

T =

37

3 K

MA

B =

2/[

(1/3

2)

+ (

1/1

8)]

= 2

3.

Usi

ng T

able

3.1

,

=+

+=

��

15

92

31

46

11

31

31

31

..

()

..

,.

= w

ater

meth

ano

lV

V

DV

=+

=0

00

14

33

73

15

11

47

23

31

31

31

03

01

75

12

13

13

2

.(

)

(.

/.

)[

..

].

.

//

/cm

2/s

Req

uir

ed t

ray d

imen

sio

ns:

D

T =

6 f

t,

A =

3.1

4(6

)2/4

= 2

8.3

ft2

= 2

.63

m2

Aa =

0.9

1 A

=

0.9

1(2

.63

) =

2.3

9 m

2 =

23

,90

0 c

m2,

Lw =

42

.5 i

n.

= 1

.08

m

Tra

y c

on

dit

ion

s:

φε

= 1

- 0

.61

7 =

0.3

83

, q

L =

47

,30

0/(

60

)(8

.33

) =

94

.6 g

pm

= 5

,97

0 c

m3/s

Fro

m E

q.

(6-5

4),

C

l = 0

.36

2 +

0.3

17

ex

p[-

3.5

(2)]

= 0

.36

2

Fro

m E

q.

(6-5

1),

h l

=+� ��

� �� �� �

� �� �==

03

83

20

03

62

94

6

42

50

38

31

21

30

8

23

..

..

(.

)(.

).

.

/

in

. c

m2

f =

0.4

0,

Fro

m E

q.

(6-6

4),

t L

= (

3.0

8)(

23

,90

0)/

5,9

70

= 1

2.3

s

Page 95: Separation Process Principles- 2n - Seader &Amp; Henley - Solutions Manual

Ex

erci

se 7

.41

(co

nti

nu

ed)

An

aly

sis:

(d

)

(co

nti

nu

ed)

Th

e co

nti

nu

ity e

qu

atio

n i

s,

63

0(1

8.5

)(2

.20

5)/3

60

0,

so

,ft/

s6

.8 f

t/s

28

.3(0

.91)

(0.6

57

/16

.02

)

VV

aa

Va

aV

mm

UA

UA

==

= 2

.07

m/s

Fro

m E

q.

(6-6

5),

t G

==

(.

)(.

)

(.

)(.

)(.

)()

.0

61

73

08

03

83

68

25

41

20

02

4 s

Fro

m b

elo

w E

q.

(6-6

7),

F=

Ua

0.5

= 2

.07

(0.6

57

)0.5

= 1

.68

(k

g/m

)0.5

/s

Fro

m E

q.

(6-6

7),

ka

L=

×+

=−

78

81

01

68

04

25

14

85

05

.(8

)(

..

).

. s

-1

Fro

m E

q.

(6-6

6),

k

aG

=−

=1

03

00

30

04

00

84

20

40

30

88

53

12

2

12

,(

.)

..

(.

)

..

/

/ s

-1

Fro

m E

q.

(6-6

3),

N

ka

tL

LL

==

=1

48

12

31

82

.(

.)

.

Fro

m E

q.

(6-6

2),

N

ka

tG

GG

==

=8

53

00

24

20

5.

(.

).

Fro

m t

he

vap

or-

liq

uid

eq

uil

ibri

um

dat

a at

th

e b

ott

om

of

the

colu

mn

,

Km

eth

anol =

0.1

56

/0.0

24

6 =

6.3

4

Ab

sorp

tio

n f

acto

r =

KV

/L =

(6

.34

)(6

30

)/1

,19

2 =

3.3

5

Fro

m E

q.

(6-6

1),

1

11

20

5

33

5

18

20

48

80

18

40

67

2N

N

KV

L

NO

GG

L

=+

=+

=+

=(

/)

.

. ..

..

N

OG =

1/0

.67

2 =

1.4

88

Th

us,

th

e gas

-ph

ase

resi

stan

ce i

s m

ore

im

po

rtan

t th

an t

he

liq

uid

-ph

ase

resi

stan

ce.

Fro

m E

q.

(6-5

6),

1

exp

()

1e

0.7

74

or

xp

(1

.48

77

.4)

%8

=−

−=

−−

=V

OG

OE

N

Th

is i

s in

ver

y g

oo

d a

gre

emen

t w

ith

th

e p

erfo

rman

ce d

ata.

E

xer

cise

7.4

2

Su

bje

ct:

Est

imat

ion

of

effi

cien

cies

, E

MV a

nd

Eo f

rom

EO

V f

or

met

han

ol-

wat

er m

ixtu

re,

as

mea

sure

d w

ith

a s

mal

l O

lder

shaw

co

lum

n.

Giv

en:

C

olu

mn

co

nd

itio

ns

fro

m E

xer

cise

7.4

1.

Fin

d:

E

MV a

nd

Eo

An

aly

sis:

Cas

e 1

: A

ssu

me

com

ple

te m

ixin

g o

n t

he

tray

s.

E

MV =

EO

V =

0.6

5 o

r 6

5%

Cas

e 2

: A

ssu

me

plu

g f

low

of

liq

uid

wit

h n

o l

on

git

ud

inal

dif

fusi

on

. T

ake

con

dit

ion

s at

th

e to

p o

f th

e co

lum

n.

Fro

m E

q.

(7-7

),

L/V

= R

/(R

+ 1

) =

0.9

47

/(1

+ 0

.94

7)

= 0

.48

6

Fro

m E

q.

(6-3

3),

λ

= m

/(L

/V)

Fro

m t

he

vap

or-

liq

uid

eq

uil

ibri

um

dat

a giv

en i

n E

xer

cise

7.4

1,

m =

dy/

dx

= (

1 -

0.9

15

)/(1

- 0

.79

3)

= 0

.41

λ =

0.4

1/0

.48

6 =

0.8

44

Fro

m E

q.

(6-3

2),

[]

[]

{}

11

exp

()

1ex

p0

.84

4(0

.65

0.7

54

or

)1

0.8

75

.4

44

%=

λ−

=−

OV

MV

EE

Th

e ac

tual

val

ue

of

EM

V

pro

bab

ly l

ies

inb

etw

een

6

5%

an

d 7

5.4

%,

or

say 7

0%

.

Fro

m E

q.

(6-3

7),

ass

um

ing t

hat

th

e eq

uil

ibri

um

an

d o

per

atin

g l

ines

are

str

aigh

t,

[]

[]

log

1(

1)lo

g1

0.7

0(0

.84

41)

log

log

(0.8

44

)0

.68

or

68

%+

λ−

+−

==

λ=

o

MV

EE