Section10_Circuit_Analysis2_soln.notebook 1 April 03, 2012 R 1 R 2 R 3 Section 10: Circuit Analysis II Combination Circuits Series Parallel Circuits 1. An 8.0 Ω (R 1 ) is connected in series with 2 resistors that are connected in parallel. One of the parallel resistors (R 3 ) has a resistance of 3.0 Ω. The circuit is connected to a 120 V power supply and draws a total current of 12 A. Solve the circuit. R1 I1 V1 R2 I2 V2 R3 I3 V3 R23 I23 V23 Rt IT VT

Section10 Circuit Analysis2 soln.notebook Pages/Paula Kelly_files/Physics... · 2012-04-04 · Section10_Circuit_Analysis2_soln.notebook 1 April 03, 2012 1 R 2 R R 3 Section 10: Circuit

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Section10_Circuit_Analysis2_soln.notebook

April 03, 2012

R2 R3

Section 10: Circuit Analysis II Combination Circuits Series Parallel Circuits

1. An 8.0 Ω (R1) is connected in series with 2 resistors that are connected in parallel. One of the parallel resistors (R3) has a resistance of 3.0 Ω. The circuit is connected to a 120 V power supply and draws a total current of 12 A. Solve the circuit.

R1 I1 V1

R2 I2 V2

R3 I3 V3

R23 I23 V23

Rt IT VT

Section10_Circuit_Analysis2_soln.notebook

April 03, 2012

2. Solve the circuit.

R1 I1 V1

R2 I2 V2

R3 I3 V3

R4 I4 V4

R5 I5 V5

R34 I34 V34

R234 I234 V234

R11 I11 Vll

Rt It

Section10_Circuit_Analysis2_soln.notebook

April 03, 2012

3. Solve the circuit.

Section10_Circuit_Analysis2_soln.notebook

April 03, 2012

4. The voltmeter in the circuit to the right measures a potential difference of 22 V across the 40 Ω resistor. Solve the circuit.

Section10_Circuit_Analysis2_soln.notebook

April 03, 2012

Section10_Circuit_Analysis2_soln.notebook

April 03, 2012

5. The circuit below contains three identical light bulbs. Compare the brightness of bulb 1and bulb 3 when switch, S, (i) is closed (ii) is opened.

When the switch is open, bulb 2 will not light. Bulb 1 and 3 will be in series and each will have the same brightness b/c each bulb will have the same voltage drop across it.

When the switch is close, all three bulbs will light. Bulb 2 and 3 are in parallel and their equivalent resistance is less than the individual resistance. This means that the total resistance of the circuit is decreased and therefor the total current of the circuit will increase. Hence the voltage drop across bulb 1 will be greater than before (bulb is brighter). As a result the current through Bulb 2 and 3 will be less. Therefore, bulb 3 will be less bright b/c of the smaller voltage drop across it.

Section10_Circuit_Analysis2_soln.notebook

April 03, 2012

6. R1, R2, and R3 are connected in parallel and the combination is connected in series with R4 and R5. Find the current through and the voltage drop across each of the resistors if the circuit has a 42 V source, and the values of the resistors are as follows:

R1 = 75 Ω R2 = 150 Ω R3 = 120 Ω R4 = 48 Ω R5 = 36 Ω

Section10_Circuit_Analysis2_soln.notebook

April 03, 2012

Section10_Circuit_Analysis2_soln.notebook

April 03, 2012

Section10_Circuit_Analysis2_soln.notebook

April 03, 2012

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