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  • SATUAN ( UNIT)

    SURFACE FACILITIES

  • 1 L (liter) = 1000 cm3 1 m3 = 1000 L (liter)

    1 in3 = 16.387 cm3 1 U.S gal = 4 qt

    1 ft3 = 28.317 L (liter ) 1 U.S gal = 3.7854 L (liter)

    1 ft3 = 0.028317 m3 1 U.S gal = 3785.4 cm3

    1 ft3 = 7.481 U.S gal 1 British gal = 1.20094 U.S gal

    1 m3 = 264.17 U.S gal

    UNITS VOLUME

  • Volume & Density

    Commonly used in Europe

    Volume

    Mass Density

    stock tankat gravity specific : 131.5 - 141.5

    API oo

    o

    oAPI of water = 10 oAPI of Heavy oil 20 oAPI of Extra heavy Oil 10

  • 1 g mol ideal gas at 0 oC, 760 mm Hg = 22.4140 liters = 22 414 cm3

    1 lb mol ideal gas at 0 oC, 760 mm Hg = 359.05 ft3

    1 kg mol ideal gas at 0 oC, 760 mm Hg = 22.414 m3

    Density of dry air at 0 oC, 760 mm Hg = 1.2929 g/liter = 0.080711

    lbm/ft3

    Molecular weight of air = 28.97 lbm/ lb mol

    1 g/cm3 = 62.43 lbm / ft3 = 1000 kg / m3 = 350 lbm / bbl

    1 g / cm3 = 8.345 lbm / U.S . gal

    1 lbm / ft3 = 16.0185 kg / m3

    Volume & Density

    Commonly used in Europe

  • COMMONLY UNITS USED IN PETROLEUM

    INDUSTRY (1)

    Customary Units Metric Units

    Mscf , cuft (ft3) Std m3 (Sm3 ) , m3

    ft2 m2

    Lbm/cuft Kg/m3

    Btu/lbm-oF kJ/kg.K

    Btu/lbm kJ/kg

    ft m

  • Length -Basic

    -Secondary

    Meter (m)

    cm , km

    foot (ft)

    inch (in) , mile

    Area -Basic

    -Secondary

    m2

    cm2 , hectares (ha)

    ft2

    in2 , acres

    Volume -Basic

    -Secondary

    m3

    cm3 , liters (L)

    ft3

    US gallons (US gal),

    in3, UK gas, bbl

    Mass -Basic

    -Secondary

    kg, kmol

    grams (g)

    pounds (lb), lb-moles

    Lb/US gal , lb/UK gal

    Density -Basic

    -Secondary

    kg/m3

    g/cm3

    Lb/ft3

    Time -Basic

    -Secondary

    second (s)

    min (m), day (d),

    year (a)

    Second (sec)

    Min, day, yr

    Metric English

    BASIC DIMENSION

  • COMMONLY UNITS USED IN PETROLEUM

    INDUSTRY (2)

    Customary Units Metric Units

    Btu/ft2-D-oF kJ/m2.d.K

    Mscf/D Std m3/d

    B/D m3/d

    lbm kg

    Lbm/cuft Kg/m3

    psi kPa

  • COMMONLY UNITS USED IN PETROLEUM

    INDUSTRY (3)

    Customary Units Metric Units

    Btu (British Thermal Unit) kJ

    Btu/D kJ/d ; W

    kW kW

    oF oC

    oR K

    Ft/D m/d

  • COMMONLY UNITS USED IN PETROLEUM

    INDUSTRY (4)

    Customary Units Metric Units

    scf Std m3

    mile/hr Km/h

    ft2/D m2/d

    cp Pa.s

    cSt m/s2

    dyne/cm mN/m

  • Length

    Length 1 in = 2.540 cm 100 cm = 1 m (meter) 1 micron = 10-6 m = 10-4 cm = 10-3 mm = 1 m (micrometer) 1 A (angstrom) = 10-10 m = 10-4 m 1 mile = 5280 ft 1 m = 3.2808 ft = 39.37 in

  • CONVERSION UNIT length

    1 in = 2.540 cm

    1 m (meter) = 100 cm

    1 micron = 10-6 m = 10-4 cm = 10-3 mm = 1 m

    1 A (angstrom) = 10-10 m = 10-4 m

    1 mile = 5280 ft = 1.61 km

    1 m = 3.2808 ft = 39.37 in

    1 ft = 0.305 m = 12 in = 30.5 cm

  • CONVERSION UNIT Volume

    1 m3 = 35.32 ft2 = 6.29 bbl = 1000 L

    1 L = 0.001 m3 = 1000 cm3 = 0.035 ft3

    1 bbl (API) = 0.159 m3 = 159 L = 5.61 ft3

    1 ft3 = 0.0283 m3 = 28.3 L

  • CONVERSION UNIT Density

    1 g/cm3 = 62.43 lbm/cuft = 1000 kg/m3

    1 g/cm3 = 8.345 lbm/USgal

    1 g/cm3 = 350 lbm/bbl

    1 lbm/cuft = 16.0185 kg/m3

  • CONVERSION UNIT Pressure

    1 bar = 14.50 psi = 0.987 atm = 1.02 kg/cm2

    1 bar = 100 000 N/m2 = 100 kPa

    1 psi = 6.86 kPa

  • Unit Pressure

    1 bar = 1 x 105 Pa (pascal) = 1 x 105 N/m2 1 psia = 1 lbf / in

    2 1 psia = 2.0360 in Hg at 0oC 1 psia = 2.311 ft H2 O at 70

    o F 1 psia = 51.715 mmHg at 0 oC (Hg = 13.5955 g / cm

    3 ) 1 atm = 14.696 psia = 1.01325 x 105 N / m2 = 1.01325 bar 1 atm = 760 mm Hg at 0 oC = 1.01325 x 105 Pa 1 atm = 29.921 in Hg at 0 oC 1 atm = 33.90 ft H2 O at 4

    oC 1 psia = 6.89476 x 104 g / cm . s2

  • CONVERSION UNIT Mass

    1 lbm = 453.59 g = 0.45359 kg

    1 lbm = 16 oz = 7000 grains

    1 grain = 64.79891 mg

    1 kg = 1000 g = 2.2046 lbm

    1 ton (short) = 2000 lbm

    1 ton(long) = 2240 lbm

    1 ton(metric) = 1000 kg

  • Viscosity

    1 cp = 10-2 g / cm. s (poise)

    1 cp = 2.4191 lbm / ft. H

    1 cp = 6.7197 x 10-4 lbm /ft. s

    1 cp = 10-3 Pa.s = 10-3 kg / m. s = 10-3 N. s / m2

    1 cp = 2.0886 x 10-5 lbf . s / ft2

    1 Pa.s = 1 N. s / m2 = 1 kg / m. s = 1000 cp

  • Viscosity

    1 cp = 10-2 g / cm. s (poise)

    1 cp = 2.4191 lbm / ft. h

    1 cp = 6.7197 x 10-4 lbm /ft. s

  • Unit Power

    1 hp = 0.74570 kw

    1 hp = 550 ft . Lbf / s

    1 hp = 0.7068 btu / s

    1 watt (W) = 14.340 cal /min

    1 btu / h = 0.29307 W (watt)

    1 J / s (joule/s) = 1 W

  • Unit, Standard

    ft , lb, s, lbf :

    Length = ft

    Area = ft2

    Viscosity = lbm /ft. s

    Pressure = lbf / ft2

    Time = s

    Flow rate = ft3 / s

    s / ft

    )ft(A

    )s/ft ( Q

    (luas)A

    (rate) Q ) v ( Velocity

    2

    3

    Work (W) = Q ( P1 - P2 )

    = Q (P)

    = Q (ft3/s) x P (lbf / ft2)

    = ft.lbf/s x (hp /550 ft.lbf/s)

    Work (hp) = (1/550) Q (P)

    P = pressure loss (lbf/ft2)

    Q = oil flow rate (ft3/s)

    1 hp = 550 ft . Lbf / s

  • Unit Heat, Energy and Work

    1 J = 1 N.m = 1 kg.m2 / s2

    1 btu = 1055.06 J = 1.05506 kJ

    1 btu = 252.16 cal

    1 btu = 778.17 ft.lbf

    1 hp.h = 0.7457 kW.h

    1 hp.h = 2544.5 btu

    1 hp = 2544.5 btu/h

    1 ft.lbf = 1.35582 J

    kW.h = 0.060 US$

    = 600 Rupiah

    Assumption 1 US$ = Rp 10.000

  • OIL FLOW IN PIPES

    W = Q ( P1 - P2 ) = Q (P)

    P = pressure loss (psi)

    Q = oil flow rate (bbl/D)

    P1 P2

    Q

    PIPE

    1 btu = 778.17 ft.lbf

    1 hp = 550 ft.lbf / s

    What is power required to

    flow (Horse Power) oil in

    pipes above.

    Flow Rate

    Pressure

  • GAS FLOW IN PIPES

    W = Q ( P1 - P2 ) = Q (P)

    P = pressure loss (psi)

    Q = Gas flow rate (MMSCF/D)

    P1 P2

    Q

    PIPE

    1 btu = 778.17 ft.lbf

    1 hp = 550 ft.lbf / s

    1 hp = 2544.5 btu/h

    Cuft/D

    BTU/D $/D

    hp P P

    Hp ~ Q x P

    ( P )

  • GAS FLOW IN PIPES

    W = Q ( P1 - P2 ) = Q (P)

    P1 P2

    Q

    PIPE

    1 btu = 778.17 ft.lbf

    1 hp = 550 ft.lbf / s

    )/ft(lb p /s)q(ft 550 W(hp)

    hp/550 s / ft.lb ft

    lb p

    s

    ft q W

    2f

    3

    f2f

    3

    START WITH BASIC UNITS

  • Gas Flow in Pipes

    Scf

    ft

    V

    V B

    3

    Standard

    cond pipe

    g

    Q = Gas flow rate, MMSCF/D

    D = Inside Pipe diameter, in

    P1 P2

    Qg

    PIPE

    Pipe

    conditions

    P and T

    Cuft = ft3

    Standard

    Conditions

    14.7 psi &

    60 oF

    SCF

    Given :

    What is gas velocity in pipes

    ? ( ft/s)

    : Bg

    bbl/scf) (res p

    T z 0.00502 B

    (cuft/scf) p

    T z 0.0282 B

    g

    g

  • P Q B 1667 P 144 Q B 86400

    10

    550

    1 HP

    P(psi) 144 ft

    in 144 x

    in

    lbP

    ft

    lbp

    Q B 86400

    10

    scf

    cuftB x

    MMscf

    scf 10 x

    s 86400

    D x

    D

    MMscfQ

    s

    ftq

    550/)/ft(lb p /s)q(ft W(hp)

    550/)/ft.lb hp/(550 s / ft.lb ft

    lb p

    s

    ft q W

    gggg

    6

    2

    2

    2

    f

    2

    f

    gg

    6

    g

    6

    g

    3

    2

    f

    3

    ff2

    f

    3

    hpsx

    1 btu = 778.17 ft.lbf

    1 hp = 550 ft.lbf / s

  • Gas velocity in pipes

    (Assignment # 1, 11 - 9 2013)

    P1 P2

    Q

    Q = Gas flow rate = 60 MMscf/D

    D = Inside Diameter of pipes (20 in)

    PIPE

    A D Q

    A

    Q V

    g

    g

  • Q = Gas flow rate = 60 MMscf/D

    D = Inside Diameter of pipes (20 in)

    A D Q

    A

    Q V

    g

    g

    If pressure and temperature in the pipe are equal to 600 psia and

    120 F, respectively, and SG gas = 0.6. Determine velocity of gas

    in the pipe ( ft/sec )

  • 1) Derives equation no (1) below :

    d

    Q 20 N 1)

    gg

    Re

    d ( in ) inside pipe diameter , (cp) , o (lbm/cuft) , v (velocity) , f (friction factor, dimensionless) , Hp (horse power) , Qg (Mscf / D)

    P ( psi) , v = q / A ( q = flow rate), Nre = Reynold Number.

    Assignment #1, 11-09-2012

    Due 11 09 - 2013

    P QConstant Hp )2 g

    2) Find constant of equation no 2 below :