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Robust Design: Statistical Analysis for Taguchi Methods
In the previous lecture, we saw how to set up the design of a series of experiments to test
different configurations of potential designs under different conditions of uncontrollable
factors (noise). In this set of notes, we will briefly see how to interpret the experimental
results. A more complete study of this requires more time spent in the study of Design of
Experiments; we will just look at some basics to get an understanding of the main
principles.
Analysis of the experimental results
Upon completion of the full array of experiments, we must analyze the results in order toselect the best design. The different designs are compared in terms of their signal-to-noise
ratio, or the S/N ratio. We shall not go into the complete details of the statistical analysis
in this course, but some insights are useful to understand how the method works.
We shall look at several methods, starting from the most basic to a somewhat analytical
method. For more complete details, you will need to study a course in design of
experiments (DOE).
I will use a few simple examples to explain these methods.
Example 1. Water Pump Design
The design of a water pump is being studied to set the optimum design parameters. The
evaluation criterion is water leakage during operation. The table below lists the factors
and the levels at which they are tested.
Table 1. Water pump design parameter levels.
Water pump design
Factor Level 1 Level 2
A: Cover design cover1 cover2
B: Gasket design gasket1 gasket2
C: Front bolt torque LSL USL
D: Sealant No Yes
E: Surface finish rough smooth
F: Back bolt torque LSL USL
G: Torque sequence Front, Back Back, Front
The outcome of the testing is measured in terms of the number of leaks in the pump
assembly. The tests are conducted using an L8(27) orthogonal array, and the raw results
are tabulated below. Leakage was rated on a scale from 0 5, where 0: no leaks, 5:
extremely high leaking.
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Table 2. Experimental results on the water pump designs
Cover Gasket Front
torque
Sealant Surface
finish
Back
torque
Torque
sequence
Trial
No.
A B C D E F G Test:
leaking
1 1 1 1 1 1 1 1 4
2 1 1 1 2 2 2 2 3
3 1 2 2 1 1 2 2 1
4 1 2 2 2 2 1 1 0
5 2 1 2 1 2 1 2 26 2 1 2 2 1 2 1 4
7 2 2 1 1 2 2 1 0
8 2 2 1 2 1 1 2 1
Method 1. Observation
This is the simplest analysis one can perform. For example, looking at leakage data, it
appears design configurations 4 and 7 are the best (zero leakage).
On analysis, we see that these two designs have different levels for factor A (i.e. different
cover designs), and therefore the likelihood that cover design does not affect the
performance is increased.
Secondly, three columns are at the same level: [B: new gasket design, E: high surface
finish, and G: back-front torque sequence] in the best configurations. Therefore thelikelihood that these particular levels of these factors increase the design quality is high.
At this simple level of analysis, interaction effects are mostly ignored, and only some
basic idea of the design quality is obtained, which may be used to reduce the number of
variables in future experiments.
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Method 2. Ranking method
We re-organize the data from the experimental runs in increasing order of the measured
statistic (Leaking intensity). Table 3 below shows this resulting data for our example.
Table 3. Ranking method
Cover Gasket Front
torque
Sealant Surface
finish
Back
torque
Torque
sequence
Trial
No.
A B C D E F G Test:
leaking4 1 2 2 2 2 1 1 0
7 2 2 1 1 2 2 1 0
3 1 2 2 1 1 2 2 1
8 2 2 1 2 1 1 2 1
5 2 1 2 1 2 1 2 2
2 1 1 1 2 2 2 2 3
1 1 1 1 1 1 1 1 4
6 2 1 2 2 1 2 1 4
Note the following:
(a) Parameter B, Gasket design, clearly has a strong affect on the design. The four best
designs all use the new gasket design, while the four worst use the existing gasket.
(b) If we partition the runs by gasket design, then factor E, or Surface finish, appears to
have consistent secondary affect on the performance (in the first four runs in Table ??,
Smooth surface finish pumps have lower leakage than rough; this trend is repeated in the
last four runs).
(c) From these observations, one may conclude that using a design with the new gasket
and smooth surface finish will result in a good design.
The observations of the ranking method can usually be identified by using first order
statistical data statistics about each parameter, without considering interaction affects.
We call this the main effect due to a factor X, or ME( X). The easiest MEs we can
compute are the mean values.
Let us denote ME1(X) and ME2(X) as the mean value of the output when the factor X
was at levels 1 and 2 respectively.
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Thus:
ME1(B) = (2+3+4+4)/4 = 3.25ME2(B) = (0+0+1+1)/4 = 0.5
For comparison, let us look at the main effects due to Factors A and E:
ME1(A) = (4+3+1+0)/4 = 2
ME2(A) = (2+4+0+1)/4 = 1.75
ME1(E) = (1+1+4+4)/4 = 2.5
ME2(E) = (0+0+2+3)/4 = 1.25
These are consistent with the conclusions above and also with the conclusions form theobservation method.
Method 3. Column Effects Method
This method was suggested by Taguchi to perform a quick check on the relative
importance of each factor; the idea is to basically list out the ME1,2(X) for each parameter
(or for each column, if the column is assigned to study and interaction). In this sense, we
can look at this method as an extended form of the column ranking method.
Table 4. Column effects method (Taguchi).Front Surface TorqueCover Gasket
torque
Sealant
finish
Back
torque sequence
Trial No. A B C D E F G Test:
leaking
4 1 2 2 2 2 1 1 0
7 2 2 1 1 2 2 1 0
3 1 2 2 1 1 2 2 1
8 2 2 1 2 1 1 2 1
5 2 1 2 1 2 1 2 2
2 1 1 1 2 2 2 2 3
1 1 1 1 1 1 1 1 4
6 2 1 2 2 1 2 1 4
ME1(X) 8 13 8 7 10 7 8
ME2(X) 7 2 7 8 5 8 7
ME2(X) -ME1(X)
-1 -11 -1 1 -5 1 -1
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probabilistic evaluation, i.e. the probability that the two factors being compared have a
different enough affect on the output. When this probability is high enough (typically,higher than 95%), we may conclude that the two factors have significantly different
affect. From this, we can then decide which design configuration is more robust.
In this section, we shall take a brief look at ANOVA basics. We begin with a simplified
example, and build up to the case for design evaluations.
Example 1.Assume that we have designed a water pump, and test it for performance
several times; the criterion is flow rate. The test results are:
Table 5. Simple example of ANOVA computations
Run 1 2 3 4 5 6 7 8Flow rate 5 6 8 2 5 4 4 6
Let:
yi = i-th data value
N = total number of observations
T = total (sum) of all observations
T= average of all observations = T/N = y
For our case, N = 8, T = 40, T= 5.0
Since we are interested in variations about the mean (and in some cases, the variation of
the mean from zero), we further compute:
SST= total sum of squares = 52+ 6
2+ 8
2+ 2
2+ 5
2+4
2+ 4
2+ 6
2= 222
We denote (yi- y ) as the error, and therefore can compute the SSerror= SSe, as follows:
SSe= 02+ 1
2+ 3
2+ (-3)
2+ 0
2+(-1)
2+ (-1)
2+ 1
2= 22
Further, we may write the square of the mean as T
2
, and thus the sum-of-square of theerror due to deviation of mean from zero can be denoted as SSm= N(T
2) = 8x 25 =
200.
Notice that SST= SSe+ SSm
Further, we may think of the 8 observations to possess 7 degrees of freedom (since we
dont really know the population mean, and therefore yield one degree of freedom to
compute the sample mean, y , form the 8 data points). You may think of this as the data
set having 7 dof, and the mean having one dof. This notation is useful mostly in
computing sample variances, which is the measure of interest for us.
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We use the standard definition of variance, 2= SS/v, where SS is the sum of squares of
the quantity of interest, and v is the degree of freedom of this quantity. We shall denote
2with the symbol V.
Thus, for our data, Ve= SSe/ve= 22/7 = 3.14
Example 2.Consider the design of a water sprinkler, where the key design parameter is
the diameter of the sprinkler hole. If the hole is too small, the water is sprayed too far,
while if it is too large, the water pours out a very small speed. The measured parameter is
the exit velocity of the water, and three different values (levels) of the DP are to be
tested: diameter = 0.15mm, 0.25mm and 0.35mm.
We denote the factor under study, hole diameter, as factor A, and thus A can take kA
levels. Here kA= 3.
Several tests are performed on sprinklers at each level of A, and the data from the tests is
tabulated below. Using Ai to denote the sum of the observations at level Ai, we have:
Table 6. ANOVA for multiple data points at different levels
Level Diameter Water velocity Ai nAiiA =
Ai/ nAi
A1 0.15 2.2 1.9 2.7 2.0 8.8 4 2.2A2 0.25 1.5 1.9 1.7 - 5.1 3 1.7
A3 0.35 0.6 0.7 1.1 0.8 3.2 4 0.8
Further, the grand totals are as follows:
T = Ai= 17.1N = nAi= 11
T= 1.6
In this case, the variations have three components: (a) variation of the mean from zero,
(b) variations due to the different mean values for the three designs, and (c) variation of
each sprinkler type about the mean of that type.
(a) As before, we can compute, for the entire data set,
SST= 2.22+ + 0.8
2= 31.9, and
SSm= variation of the mean about 0 is N( T)2= T
2/N = 26.583
(b) The variations due to the different mean values of the three designs can be written:
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SSA = nAi( iA - T)2
=N
T
n
AAk
i Ai
i2
1
2
= 8.82/4 + 5.1
2/3 + 3.2
2/4 17.12/11 = 4.007
(c) Variations of the pumps, or the sum-of-squares of the error:
A Aik
j
n
i
jije AySS1 1
2)(
= 02+ (-0.3)
2+ 0.5
2+ (-0.2)
2+ 0.2
2+ 0
2+ (-0.2)
2+ (-0.1)
2+ 0.3
2+ 0
2= 0.600
You can verify that SST= SSm+ SSA+SSe
Table 7 summarizes the data statistics:
Table 7. ANOVA statistics for the sprinkler example
Source SS v V
m 26.583 1 26.583
A 4.007 2 2.0035
e 0.6 8 0.075
T 31.19 11
The F test
Let us first look at a generic form of the F test before applying it to Taguchi methods. We
are given two sets of data (they may be observation values from two sets of experiments).
We can then compute the sample variance for each of these sets; these measures are
estimates of the true variance of the data sets (note that since we only have a finite
number of readings, we dont really know the population variance, we only know the
sample variance).
Now, can we comment, by looking at the variance values of the two sets, whether they
arise out of different samples from the same population, or whether they are actually data
sets from two totally different distributions?
Notice the parallel question for Taguchi designs: we are interested to know whether two
designs are significantly different in their measured behavior, or not.
To answer this, we need to know several things:
(i) What is the size of the sample of the first set of data?
(ii) What is the size of the sample of the second set?
(iii) If we say that the two sets are samples from the same population, how confident do
we want to be in our statement?
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Intuitively, the first two factors are important because as our sample size increases, our
estimate of the Variance moves closer to the true variance.
The third factor is important for the obvious reason if we want to be more confident
that the two are from different populations, then the two samples must have very different
variancevalues.
The actual F test is based on the most remarkable theorem in statistics, called the Central
Limit Theorem (CLT). Roughly, the CLT states that:
Central Limit Theorem:
(a) No matter what is the population distribution from which we take samples, the sample
means will be normally distributed(b) As the sample sizes increase, the mean of the sample means approaches the mean of
the population
(c) The variance of the mean of the samples is smaller than the variance of the
population. In particular, if the population has variance = 2, then the variance of thesample means = 2/N, where N is the sample size. [As N increases, the mean is so closeto the true mean that it almost does not have any variance, hence the name central limit]
Using this theorem, F-test tables have been constructed, and can be used to estimate if
two sets of sample variances belong to the same population or not. You can find these
tables in many statistics text-books.
The convention in ANOVA is to write the confidence as (1-risk), and to denote the risk
as a parameter, . A commonly used value is = 0.05 (which corresponds to 95%confidence).
Example 3. We now look at some examples of the application of ANOVA to Taguchi
method of design. Let us first consider a simple 2-factor experiment to get familiar with
the ideas. Assume that a candy manufacturer is testing different combinations of sugar
and vegetable oil to test for plasticity of the resulting candy, and tests at two levels for
each factor. At each combination of settings, the plasticity is tested two times. The
resulting data is as follows:
A = % sugar; A1= 3.5, A2= 4.5
B = % oil; B1= 1.2, B2= 1.8
Table 8. Data from candy experiments
A1 A2
B1 6, 8 3, 4
B2 7, 8 9, 10
The numbers in each cell represent the two test data at that setting. In the ANOVA
analysis, the variations this time are composed of four sources:
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(i) variation due to A (ii) variation due to B (iii) variation due to interaction of A and B
(iv) variation due to error.
Thus, SST= SSA+ SSB+ SSAXB+ SSe
We may compute them as follows:
A1 = sum of all outputs at level A1 = 29; B1 = 21; A2 = 26; B2 = 34
nA1= nA2= 4; nB1= nB2= 4, N = 8;
SST=N
Ty
N
i
i
2
1
2
= 62+ + 10
2 55
2/8 = 40.875
N
T
n
ASS
Ak
i Ai
i
A
2
1
2
= 292/4 + 26
2/4 55
2/8 = 1.125
Likewise, SSB= 212/4 + 34
2/4 55
2/8 = 21.125
Computing SSAXBrequires some care: if we just total up all the sum-of-squares of each
combination of Ai and Bi, this total will include all the terms of SSA and SSB also. Inorder to isolate these lower order terms, we need to subtract out these values. In other
words:
BA
c
i AXB
i
AXB SSSSN
T
n
AXBSS
i
2
1
2)(, where c is the number of different
combinations of Ai, Bj. In our example, c = 4; A1B1 = 14; A2B2 = 7; A1B2 = 15 and
A2B2 = 19.
Thus SSAXB= 142/2 + 7
2/2 + 15
2/2 + 19
2/2 55
2/8 1.125 21.125 = 15.125
SSe= SST- SSA- SSB- SSAXB= 3.5
To compute the variances, we need the degrees of freedom:
vT= N 1 = 8 1 = 7
vA= 1; vB= 1 (each factor has only two levels, so only one dof)
vAXB= vAvB= [(how many times we can change A)x( for each value of A, how many
times we can change B)] = 1x1 = 1
The remaining degrees of freedom belong to the noise, ve= vT vA vB VAXB= 4. You
can think of this as follows. The noise is attributed to the variations of statistics around
the mean at each setting; at each combination of A i, Bj, we have two data points, or one
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free value of data contributing to the noise. Since there are four settings, the dof of noise
is 4.
From this data, we can now construct the ANOVE table, as shown below. For
significance analysis, it is conventional to compare the variance of the source with that of
the error term.
Table 9. ANOVA data for the candy example
Source SS v V F
Confidence
=c,
Fc;1;4
A 1.125 1 1.125 1.29 < 90%
B 21.125 1 21.125 24.14 > 99%AXB 15.125 1 15.125 17.29 > 95%
e 3.5 4 0.875
Total, T 40.875 7
From this analysis, one may conclude that the amount of sugar has relatively little impact
on the plasticity. The plasticity is very sensitive to the amount of oil. Further, the
interaction of sugar and oil amounts is quite significant.
There is an interesting relationship between ANOVA calculations as above, and using the
orthogonal array. Since we performed 8 experiments, corresponding to a typical L8array,
we can tabulate the data as follows:
Table 10. The L8orthogonal array interpretation of the Candy example data
Trial No. A B AXB D E F G Plasticity
1 1 1 1 1 1 1 1 6
2 1 1 1 2 2 2 2 8
3 1 2 2 1 1 2 2 7
4 1 2 2 2 2 1 1 8
5 2 1 2 1 2 1 2 3
6 2 1 2 2 1 2 1 4
7 2 2 1 1 2 2 1 98 2 2 1 2 1 1 2 10
We can now use the first column of this table to compute SSA, and from there, Variance
of A.
If we compute the SS in the third column, we get:
SScolumn3= [(6+8+9+10)2/4 +(7+8+3+4)
2/4 55
2/8 ] = 15.125, which is exactly the SSAXB
as we computed earlier.
Further, if we also carry out the SS computations for the dummy columns D, E, F and G,
we shall find that each column gives us precisely one component of the SSe, and that:SSD+ SSE+ SSF+ SSG= SSe.
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[The reason that this happens is because we had precisely one test data for each
experimental run.]
Thus, the sum of the SS for all columns is exactly equal to SST.
What factors to compare?
We may look at each of columns D, , G as four components of error, each with 1 dof.
However, a better estimate of the error is obviously the sum of the error terms from the
four columns. This is called pooling.
Taguchi used pooling up to estimate the relative significance of the effect of columns
(factors, or their interactions). The idea is as follows: compare the lowest column effectto the next lowest to see if they are significantly different. If not, then pool their effect
and compare with the next larger column effect, until a significant factor is discovered.
Using this strategy, our F-test table will appear like the following:
Table 11. Pooling up to compute significance of columns
Source SS v V F
Confidence
=c,
Fc;1;4
A 1.125 1 1.125
B 21.125 1 21.125 22.83 > 99%AXB 15.125 1 15.125 16.35 > 95%
eD 3.125 1 3.125
eE 0.125 1 0.125
eF 0.125 1 0.125
eG 0.125 1 0.125
Total, T 40.875 7
Here, the pooling takes place in the sequence eG, eF, eE, eA, eD. At the end, we are
comparing the pooled effect of these, V = (0.125+0.125+0.125+1.125+3.125)/5, with thenext higher variance. Compare this table with Table 9.
In general, some of the remaining columns of the orthogonal array may actually have
been assigned to other factors. In this case, the Taguchi method merely shifts the
comparison (instead of using variance of the error term) to the insignificant factors, once
again, using the strategy of pooling up.
References:
Taguchi Techniques for Quality Engineering, P. J. Ross, Mc-Graw Hill, 1996
Product Design, Kevin Otto and Kristin Wood, Prentice Hall, New Jersey, 2001
Taguchi Methods, Glen Stuart Peace, Addison Wesley, 1993