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v Ring of charge that generates EM field around it [2 z r Dipole case: - charge modulated by cos - dipole moment P = Qa Q compute the wake function, we consider …

Ring of charge that generates EM field around it [2]

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To compute the wake function, we consider …. Ring of charge that generates EM field around it [2]. r. Q. v. z. Dipole case : - charge modulated by cos   - dipole moment P = Qa. Fourier transform with respect to t [3]. r. a. z. Charge density. NB:. unless v = c. - PowerPoint PPT Presentation

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Page 1: Ring of charge that generates EM field around it [2]

v

Ring of charge that generates EM field around it [2]

z

r

Dipole case: - charge modulated by cos - dipole moment P = Qa

Q

To compute the wake function, we consider …

Page 2: Ring of charge that generates EM field around it [2]

Fourier transform with respect to t [3]

z

r

a

Charge density ikzeara

Pzr

cos)(),,(

2

NB:k

v

k

c

unless v = c

Page 3: Ring of charge that generates EM field around it [2]

The case of v = c in vacuum

Region outside the beam pipe

Solution

22

2

22

2

2ln

2ln

2ln

2ln

kr

iAC

r

BrikAcB

Cr

BrikAE

kr

iAC

r

BrikAcB

Cr

BrikAE

r

AcB

r

AE

r

r

z

z

A, B, C unknown constants

Page 4: Ring of charge that generates EM field around it [2]

Physics of solution

When r , expect solution 0

Should drop ln r, so A = 0 and drop constant term C

2

2

2

2

2

2

2

2

0

0

r

BcB

r

BE

r

BcB

r

BE

cB

E

r

r

z

z

Questions - should Ez be zero? - only one unknown, B - expect 2 for v < c (see [1])

Page 5: Ring of charge that generates EM field around it [2]

To solve Maxwell’s in cylindrical coordinates [2][4]

Each component of E or B )()()()( tTzZrR

)(rR

)(

)(zZ ikze

)(tT tie

Ez Er E Bz Br B

cos cos cossin sin sin

Define

respectively, by inspection of Maxwell’s.

Get

Page 6: Ring of charge that generates EM field around it [2]

Substituting into Maxwell’s, get

zr

r

zrr

zr

zr

rzz

rzz

Bkr

kiEr

v

r

rB

r

Ekr

kiarva

PB

r

v

r

rE

r

Bkr

iE

c

vB

Ekr

ivBE

BvikEr

v

r

B

EvikBr

v

r

E

2

22

2

2

2

11

1)(

1

1

1

Vanish in vacuumfor v = c

Page 7: Ring of charge that generates EM field around it [2]

Need to construct solutions and match them at boundaries [1][2]

Solutions for Ez

v < c v = c

vacuum Modified Bessel r, 1/r

medium Modified Bessel Modified Bessel

vacuum vacuum

medium

Page 8: Ring of charge that generates EM field around it [2]

References

[1] A. M. Al-Khateeb, et al, Transverse resistive wall impedances and shielding effectiveness for beam pipes of arbitrary wall thickness, Phys. Rev. ST Accel. Beams 10, 064401 (2007) http://prst-ab.aps.org/pdf/PRSTAB/v10/i6/e064401

[2] Alex Chao, Physics of Collective Beam Instabilities in High Energy Accelerators (1993), pp. 4-6, 40-41, 51-52.

www.slac.stanford.edu/~achao/wileybook.html

[3] R. Gluckstern, CERN Yellow Report 2000-011 (2000), pp. 1-8.

http://doc.cern.ch/yellowrep/2000/2000-011/p1.pdf

[4] B. Zotter, New Results on the Impedance of Resistive Metal Walls of Finite Thickness, CERN-AB-2005-043, pp. 1-4, 15-20.

http://doc.cern.ch/archive/electronic/cern/preprints/ab/ab-2005-043.pdf