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Review of Trigonometry for Calculus 1Universitas
Saskatchewanensis
DEO
ET
PAT-
RIÆ
2002 Doug MacLean
Review of Trigonometry for Calculus
“Trigon” =triangle +“metry”=measurement=Trigonometry
so Trigonometry got its name as the science of measuring triangles.
When one first meets the trigonometric functions, they are presented in the context of ratios of sides of a right-angledtriangle, where a2 + o2 = h2:
a
o
h
α
We have
sinα = oh= opposite
hypotenuse,
cosα = ah= adjacent
hypotenuse, and
tanα = oa= opposite
adjacent,
which is often remembered with the “sohcahtoa” rule. If h = 1, we have sinα = o, cosα = a, so (sinα)2 + (cosα)2 = 1,so we know that the point (cosα, sinα) lies on the unit circle.
2 Review of Trigonometry for CalculusUniversitas
Saskatchewanensis
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PAT-
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2002 Doug MacLean
The Unit Circle:In Calculus, most references to the trigonometric functions are based on the unit circle, x2+y2 = 1. Points on this circledetermine angles measured from the point (0,1) on the x-axis, where the counter- clockwise direction is considered tobe positive.
Units of Angular MeasurementThe most natural unit of measurement for angles in Geometry is the right angle . The revolution is used in the
study of rotary motion, and is what the “r” stands for in “rpm”s. The degree , 1/90 of a right angle, was probably first
adopted for navigational purposes. The mil , 1/1600 of a right angle, is used by the military. However, the basic unitof measurement for angles in Calculus is the radian .
Definition: A radian is the angle subtended by a circular arc on a circle whose length equals the radius of thecircle. Thus, on the unit circle an angle whose size is one radian subtends a circular arc on the unit circle whose lengthis exactly one.
1 radian
x
y
(0,0) (1,0)
Figure 1.
Review of Trigonometry for Calculus 3Universitas
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2002 Doug MacLean
Radian measure and degreesSince the circumference of a circle is 2π times its radius, we have
2π radians = 360◦ = 4 right angles,
so
1 radian = 3602π
◦= 180
π
◦= 4 right angles
2π= 2π
right angles
or
1◦ = 2π360
radians = π180
radians = 190
right angles
In high school trigonometry, the trigonometric functions are used to solve problems concerning triangles and relatedgeometric figures. In the Calculus, the trigonometric functions are used in the analysis of rotating bodies. It turns outthat the degree, the unit of measurement of angles adopted by the Babylonians over 4,000 years ago, is not particularlywell adapted to the analysis of jet engines, radar systems and CAT scanners.
The radian is, because The sine and cosine functions live on the unit circle!If θ is a number, then cosθ and sinθ are defined to be the x- and y- coordinate, respectively, of the point on the unitcircle obtained by measuring off the angle θ (in radians!) from the point (0,1). If θ is positive, the angle is measuredoff in the counter-clockwise direction, and if θ is negative it is measured off in the clockwise direction. For an animatedinteractive look at these two functions, take a look at the applet Sine and Cosine Functions
4 Review of Trigonometry for CalculusUniversitas
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2002 Doug MacLean
x
y
(0,0) cos
sinθ
θ
θ
Figure 2.
The other trigonometric functions are now defined in terms of the first two:
tanθ = sinθcosθ
, cotθ = cosθsinθ
, secθ = 1cosθ
, cscθ = 1sinθ
.
Review of Trigonometry for Calculus 5Universitas
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2002 Doug MacLean
Fundamental Angles of the First Quadrant:
There are three acute angles for which the trigonometric function values are known and must be memorized by thestudent of Calculus. They are
(in radians) π6 , π
4 , and π3 ,
(in degrees) 30◦, 45◦, and 60◦,(in right angles) 1/3, 1/2, and 2/3.
In addition, the values of the trig functions for the angles 0 and π2 must be known. The following tables show how they
may be easily constructed, if one can count from zero to four. The first table is a template, the second shows how it maybe filled in, and the third contains the arithmetical simplifications of the values.
Template:
θ(radians) 0 π6
π4
π3
π2
θ(degrees) 0 30 45 60 90
θ(right angles) 0 13
12
23 1
sinθ√
2
√2
√2
√2
√2
cosθ√
2
√2
√2
√2
√2
6 Review of Trigonometry for CalculusUniversitas
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2002 Doug MacLean
Fill in the Blanks:
θ(radians) 0 π6
π4
π3
π2
θ(degrees) 0 30 45 60 90
θ(right angles) 0 13
12
23 1
sinθ√
02
√1
2
√2
2
√3
2
√4
2
cosθ√
42
√3
2
√2
2
√1
2
√0
2
Simplify the Arithmetic:
θ(radians) 0 π6
π4
π3
π2
θ(degrees) 0 30 45 60 90
θ(right angles) 0 13
12
23 1
sinθ 0 12
√2
2
√3
2 1
cosθ 1√
32
√2
212 0
Review of Trigonometry for Calculus 7Universitas
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2002 Doug MacLean
Figure 3 shows these values on the first quadrant of the unit circle.
x
y
(0,1)( , )
( , )
( , )
(1,0)
— —
— —
— —
—
— —
—
2 22 2
2 2
1 32 2
3 1
ππ
π
π
√√ √
√
——
—
—
23
4
6
0
Figure 3.
8 Review of Trigonometry for CalculusUniversitas
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2002 Doug MacLean
Moving Beyond the First QuadrantThese values may now be used to find the values of the trig functions at the other basic angles in the other three quadrantsof unit circle. The same numerical values will appear, with the possible addition of minus signs. The following table givesthe values, and the diagram displays them. The student should be able to reproduce them instantaneously! To do this, itwill be necessary to be completely comfortable with the following identities, all of which are obvious from the symmetryof the unit circle:
x
y
θ
−θθ+π
π−θ
π/2−θ
Figure 4.
Review of Trigonometry for Calculus 9Universitas
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PAT-
RIÆ
2002 Doug MacLeansin(π − θ) ≡ sinθ, cos(π − θ) ≡ − cosθ
sin(θ +π) ≡ − sinθ, cos(θ +π) ≡ − cosθ
sin(−θ) ≡ − sinθ, cos(−θ) ≡ cosθ
sin(π2− θ
)≡ cosθ, cos
(π2− θ
)≡ sinθ
θ 0 π6
π4
π3
π2
2π3
3π4
5π6 π 7π
65π4
4π3
3π2
5π3
7π4
11π6
sinθ 0 12
√2
2
√3
2 1√
32
√2
212 0 −1
2 −√
22 −
√3
2 −1 −√
32 −
√2
2 −12
cosθ 1√
32
√2
212 0 −1
2 −√
22 −
√3
2 −1 −√
32 −
√2
2 −12 0 1
2
√2
2
√3
2
10 Review of Trigonometry for CalculusUniversitas
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2002 Doug MacLean
Figure 5 is left blank for the student to fill in:
x
y
(1,0)
( , )
( , )
( , )(0,1)
( , )
( , )
( , )
(-1,0)
( , )
( , )
( , )
(0,-1)
( , )
( , )
( , )
——
——
————
——
——
— —
— —
— — — —
— —
— —
—
— —
—
2 2
2 2
2 2
1 3
2 2
3 1
ππ
π
π
π
π
π
π
ππ
π
π
π
π
π
√
√ √
√
——
—
—
—
—
—
——
—
—
—
—
—
23
4
6
3
4
6
23
4
6
3
4
6
2
3
5
4
5
7
35
7
11
0
Figure 5.
Review of Trigonometry for Calculus 11Universitas
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2002 Doug MacLean
Periodicity All six trig functions have period 2π , and two of them, tan and cot have period π :
sin(θ + 2π) ≡ sin(θ)cos(θ + 2π) ≡ cos(θ)
tan(θ +π) ≡ tan(θ)cot(θ +π) ≡ cot(θ)
sec(θ + 2π) ≡ sec(θ)csc(θ + 2π) ≡ csc(θ)
12 Review of Trigonometry for CalculusUniversitas
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2002 Doug MacLean
Identities of the sine and cosine functionsThe identity
sin2 θ + cos2 θ ≡ 1
is obvious as a result of our use of the unit circle. It really should be written as
(sinθ)2 + (cosθ)2 ≡ 1
but centuries of tradition have developed the confusing convention of writing sin2 θ for the square of sinθ. This identityleads to a number of other important identities and formulas:
tan2 θ ≡ sec2 θ − 1
sec2 θ ≡ 1+ tan2 θ + 1
cot2 θ ≡ csc2 θ − 1
csc2 θ ≡ 1+ cot2 θsinθ = ±
√1− cos2 θ
In addition to this fundamental knowledge, the student should be completely comfortable in deriving the trig identitieswhich result from the fundamental identities for the sines and cosines of sums and differences of angles. First we need:
Review of Trigonometry for Calculus 13Universitas
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2002 Doug MacLean
The Law of Cosines: c2 = a2 + b2 − 2ab cosγ
a
c
bw
z
γπ−γ
We have w = b sin(π − γ) = b sinγ, and z = b cos(π − γ) = −b cosγ, so
c2 = w2 + (a+ z)2 = (b sinγ)2 + (a− b cosγ)2 = b2 sin2 γ + a2 − 2ab cosγ + b2(cosγ)2 = a2 + b2 − 2ab cosγ
Next we compute c2 slightly differently:
a
c
b h
x yα β
x = b cosα, y = a cosβ, h = b sinα = a sinβ,x2 = b2 − h2, y2 = a2 − h2, so
c2 = (x +y)2 = x2 + 2xy +y2 =b2 − h2 + 2(b cosα)(a cosβ)+ a2 − h2 =a2 + b2 − 2h2 + 2ab cosα cosβ =a2 + b2 − 2ab sinα sinβ+ 2ab cosα cosβ =a2 + b2 − 2ab(sinα sinβ− cosα cosβ)
so cosγ = sinα sinβ− cosα cosβ = − cos(π − γ) = − cos(α+ β).Therefore
cos(α+ β) = cosα cosβ− sinα sinβ
14 Review of Trigonometry for CalculusUniversitas
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2002 Doug MacLean
We collect the angle sum and difference formulae:
sin(α+ β) ≡ sinα cosβ+ sinβ cosα (1)
sin(α− β) ≡ sinα cosβ− sinβ cosα (2)
cos(α+ β) ≡ cosα cosβ− sinα sinβ (3)
cos(α− β) ≡ cosα cosβ+ sinα sinβ (4)
If we add (1) and (2) and divide by 2, we get
sinα cosβ ≡ 12(sin(α+ β)+ sin(α− β))
If we add (3) and (4) and divide by 2,we get
cosα cosβ ≡ 12(cos(α+ β)+ cos(α− β))
and if we subtract (3) from (4) we get
sinα sinβ ≡ 12(cos(α− β)− cos(α+ β))
Review of Trigonometry for Calculus 15Universitas
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2002 Doug MacLean
Double Angle Formulae:If we let β = α in (1) and (3) and divide by 2, we get:
sin 2α ≡ 2 sinα cosα (5)
cos 2α ≡ cos2α− sin2α = 2 cos2α− 1 = 1− 2 sin2α (6)
(6) leads to the two identities:
cos2α ≡ 1+ cos 2α2
(7)
sin2α ≡ 1− cos 2α2
(8)
which in turn lead to the formulas
cosα = ±√
1+ cos 2α2
sinα = ±√
1− cos 2α2
.
16 Review of Trigonometry for CalculusUniversitas
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2002 Doug MacLean
These in turn lead to the
Half-Angle Formulae:
cosα2
= ±√
1+ cosα2
(9)
sinα2
= ±√
1− cosα2
(10)
The above identities may be used to compute the exact values of trig functions at many other angles, such as π8 = 1
2π4
and π12 , but in practice one usually uses a calculator or computer to get extremely accurate values of the trig functions.
Review of Trigonometry for Calculus 17Universitas
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2002 Doug MacLean
Identities of the Other Four Trigonometric FunctionsThese may all be derived from the preceding:For example,
tan(α+ β) ≡ sin(α+ β)cos(α+ β) ≡
sinα cosβ+ sinβ cosαcosα cosβ− sinα sinβ
≡sinα cosβ+ sinβ cosα
cosα cosβcosα cosβ− sinα sinβ
cosα cosβ≡ tanα+ tanβ
1− tanα tanβ,
tan(α+ π2) ≡ sin(α+ π
2 )cos(α+ π
2 )≡ cosα− sinα
≡ −1tanα
(thus the formula for slopes of perpendicluar lines).
tan(α− β) ≡ sin(α+ β)cos(α+ β) ≡
tanα+ tanβ1+ tanα tanβ
,
tan(2α) ≡ 2 tanα1− tan2α
,
and tanα2=
sinα2
cosα2
=±√
1− cosα2
±√
1+ cosα2
= ±1− cosα1+ cosα
18 Review of Trigonometry for CalculusUniversitas
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2002 Doug MacLean
Inverse Trigonometric Functions
Definition: If h is a real number, the inverse sine or Arcsin of h is that number between −π/2 and π/2whose sine is h.
This is often called the Primary angle whose sine is h. It may be found geometrically by drawing the horizontal liney = h and observing the points where it intersects the unit circle. If there are two such points, the one on the rightdetermines the Primary Angle . The point on the left determines another angle whose sine is also h; this angle is
called the Secondary Angle . There are, of course, infinitely many other angles whose sine is h, they may all beobtained by adding integer multiples of 2π to the Primary or Secondary Angles. Geometrically, this is the same as goingcompletely around the unit circle a number of times and ending up at the same point.
Definition: If k is a real number, the inverse cosine or Arccos of k is that number between 0 and π whosecosine is k.
This is often called the Primary angle whose cosine is k. It may be found geometrically by drawing the verticalline x = k and observing the points where it intersects the unit circle. If there are two such points, the upper onedetermines the Primary Angle . The lower point determines another angle whose cosine is also k; this angle is called
the Secondary Angle . There are, of course, infinitely many other angles whose cosine is k, they may all be obtained byadding integer multiples of 2π to the Primary or Secondary Angles. Geometrically, this is the same as going completelyaround the unit circle a number of times and ending up at the same point.
Review of Trigonometry for Calculus 19Universitas
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2002 Doug MacLean
Java Applets:For an animated interactive look at these two functions, take a look at the applets ArcSine Applet and ArcCosine Applet
x
y
=Arcsin h
y=h
θ
θ
x
y
=Arcsin h
x=hθ
θ
Figure 6.
20 Review of Trigonometry for CalculusUniversitas
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2002 Doug MacLean
AppendixIt is useful to know how the values of sinθ and cosθ for standard values of θ are derived, in addition to having memo-
rized them. First we begin with θ = π4= 45◦:
hh/2 h/2
x x
π/4 π/4
In a right angled isosceles triangle, the base angles are both equal toπ4
, and the hypotenuse h is equal to√x2 + x2 = x√2.
Therefore both the sine and cosine ofπ4
are equal toxh= xx√
2= 1√
2=
√2
2.
Review of Trigonometry for Calculus 21Universitas
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2002 Doug MacLean
Next we look at θ = π6= 30◦ and θ = π
3= 60◦ : we take an equilateral triangle whose sides are all of length x, and all
of whose angles areπ3
, and draw the perpendicular from the top vertex to the base, and in so doing bisecting the angle
at the top vertex.
π/3 π/3
π/6 π/6
x/2 x/2
x x
x
h
The perpendicular bisector has length h =√x2 −
(x2
)2
=√x2 − x
2
4= x
√1− 1
4= x
√34= x
√3
2
so we have
sinπ6=
x2
x= 1
2and cos
π6= x
√3
2
x=
√3
2.
Also, sinπ3= x
√3
2
x=
√3
2and cos
π3=
x2
x= 1
2.