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Review-Molecular Formula • Nicotine, a component of tobacco, has an empirical formula of C 5 H 7 N. The molar mass of nicotine is 162 g. What is its molecular formula? • A compound contain 64.9% C, 13.5% H, and 21.6% O. Its molecular mass is 74 g. Find the molecular formula.

Review-Molecular Formula Nicotine, a component of tobacco, has an empirical formula of C 5 H 7 N. The molar mass of nicotine is 162 g. What is its molecular

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Page 1: Review-Molecular Formula Nicotine, a component of tobacco, has an empirical formula of C 5 H 7 N. The molar mass of nicotine is 162 g. What is its molecular

Review-Molecular Formula

• Nicotine, a component of tobacco, has an empirical formula of C5H7N. The molar mass of nicotine is 162 g. What is its molecular formula?

• A compound contain 64.9% C, 13.5% H, and 21.6% O. Its molecular mass is 74 g. Find the molecular formula.

Page 2: Review-Molecular Formula Nicotine, a component of tobacco, has an empirical formula of C 5 H 7 N. The molar mass of nicotine is 162 g. What is its molecular

Unit 10:Chemical Equations

Page 3: Review-Molecular Formula Nicotine, a component of tobacco, has an empirical formula of C 5 H 7 N. The molar mass of nicotine is 162 g. What is its molecular

Chapter Objectives

• 1. To learn to write chemical equations

• 2. To correctly interpret chemical equations

Page 4: Review-Molecular Formula Nicotine, a component of tobacco, has an empirical formula of C 5 H 7 N. The molar mass of nicotine is 162 g. What is its molecular

Chemical Reactions

• In a chemical reaction, substances join together to form new substances

• The original substances present are called REACTANTS

• The new substances formed are called PRODUCTS

Page 5: Review-Molecular Formula Nicotine, a component of tobacco, has an empirical formula of C 5 H 7 N. The molar mass of nicotine is 162 g. What is its molecular

Discussion of Chemical Reactions

• The general form of an equation is:• Reactants Products• The is read as “yields” or “reacts

to produce”

Page 6: Review-Molecular Formula Nicotine, a component of tobacco, has an empirical formula of C 5 H 7 N. The molar mass of nicotine is 162 g. What is its molecular

Discussion of Chemical Reactions

• A + B C• Substance “A” and “B” react to

produce substance “C”

Page 7: Review-Molecular Formula Nicotine, a component of tobacco, has an empirical formula of C 5 H 7 N. The molar mass of nicotine is 162 g. What is its molecular

Additional Symbols in Chemical Reactions

•+ used to separate reactants or products

•(s) means chemical is in solid state

•(l) means chemical is in liquid state

Page 8: Review-Molecular Formula Nicotine, a component of tobacco, has an empirical formula of C 5 H 7 N. The molar mass of nicotine is 162 g. What is its molecular

Additional Symbols in Chemical Reactions

• (g) means chemical is in gas state• (aq) means chemical is dissolved

in water• *See Table 10-1 in book (page

278)

Page 9: Review-Molecular Formula Nicotine, a component of tobacco, has an empirical formula of C 5 H 7 N. The molar mass of nicotine is 162 g. What is its molecular

Other Symbols

means something is added to the reaction–Usually this is heat

• Pt means a catalyst (Pt) is added

Page 10: Review-Molecular Formula Nicotine, a component of tobacco, has an empirical formula of C 5 H 7 N. The molar mass of nicotine is 162 g. What is its molecular

Skeleton Equations

• Skeleton (Formula) Equation- the rough form of an equation

• It only shows the framework for the chemical reaction

Page 11: Review-Molecular Formula Nicotine, a component of tobacco, has an empirical formula of C 5 H 7 N. The molar mass of nicotine is 162 g. What is its molecular

Write Skeleton Equations

• Sodium metal reacts with Oxygen gas to form solid Sodium Oxide

• Solid sulfur reacts with Fluorine gas to form gaseous Sulfur Hexafluoride when heated

• Nitrogen reacts with Hydrogen to form Ammonia (NH3) gas. Heat is required.

Page 12: Review-Molecular Formula Nicotine, a component of tobacco, has an empirical formula of C 5 H 7 N. The molar mass of nicotine is 162 g. What is its molecular

Types of Reactions

• There are five general types of reactions:

• Synthesis• Decomposition• Single Displacement• Double Displacement• Combustion

Page 13: Review-Molecular Formula Nicotine, a component of tobacco, has an empirical formula of C 5 H 7 N. The molar mass of nicotine is 162 g. What is its molecular

Synthesis Reactions

• Synthesis reactions are also called combination reactions

• A synthesis reaction occurs when two substances combine to form a new compound

Page 14: Review-Molecular Formula Nicotine, a component of tobacco, has an empirical formula of C 5 H 7 N. The molar mass of nicotine is 162 g. What is its molecular

Synthesis Reaction Continued

• The general form of a synthesis reaction is:

• A + X AX• Substance “AX” is the only

substance formed

Page 15: Review-Molecular Formula Nicotine, a component of tobacco, has an empirical formula of C 5 H 7 N. The molar mass of nicotine is 162 g. What is its molecular

Examples of Synthesis Reactions

•2 Mg (s) + O2 (g) 2 MgO (s)

•Fe (s) + Cl2 (g) FeCl2 (s)

•U (s) + 3 F2 (g) UF6 (g)

Page 16: Review-Molecular Formula Nicotine, a component of tobacco, has an empirical formula of C 5 H 7 N. The molar mass of nicotine is 162 g. What is its molecular

Decomposition Reaction

• In decomposition reactions, one substance breaks down (decomposes) into two or more simpler substances

Page 17: Review-Molecular Formula Nicotine, a component of tobacco, has an empirical formula of C 5 H 7 N. The molar mass of nicotine is 162 g. What is its molecular

Decomposition Reactions Cont.

• General Form of Decomposition Reaction:

• AX A + X

Page 18: Review-Molecular Formula Nicotine, a component of tobacco, has an empirical formula of C 5 H 7 N. The molar mass of nicotine is 162 g. What is its molecular

Examples of Decomposition Reactions

• 2 HgO (s) 2 Hg (l) + O2 (g)

• Ca(OH)2 CaO (s) + H2O (g)

• H2SO4 (aq) SO3 (g) + H2O (l)

Page 19: Review-Molecular Formula Nicotine, a component of tobacco, has an empirical formula of C 5 H 7 N. The molar mass of nicotine is 162 g. What is its molecular

Single Replacement Reaction

• In a single replacement reaction (also called a displacement reaction), an element reacts with a compound

•A + BX AX + B

Page 20: Review-Molecular Formula Nicotine, a component of tobacco, has an empirical formula of C 5 H 7 N. The molar mass of nicotine is 162 g. What is its molecular

Examples of Single Replacement Reactions

• Mg + Zn(NO3)2 Mg(NO3)2 + Zn

• Mg + 2 AgNO3 Mg(NO3)2 (aq) + 2 Ag

Page 21: Review-Molecular Formula Nicotine, a component of tobacco, has an empirical formula of C 5 H 7 N. The molar mass of nicotine is 162 g. What is its molecular

Rules for Single Replacement Reactions

•Not all single replacement reactions occur

•You can determine if a reaction will occur by knowing the activity series of metals

Page 22: Review-Molecular Formula Nicotine, a component of tobacco, has an empirical formula of C 5 H 7 N. The molar mass of nicotine is 162 g. What is its molecular

Rules for Single Replacement

• The activity series tell you if one metal can replace another metal in a reaction

• The Activity Series is ordered• Any metal that is above another

metal in the activity series WILL REPLACE the less reactive metal

Page 23: Review-Molecular Formula Nicotine, a component of tobacco, has an empirical formula of C 5 H 7 N. The molar mass of nicotine is 162 g. What is its molecular

Activity Series• Li• K• Ca• Na• Mg• Al• Zn

• Fe• Pb• H*• Cu• Hg• Ag

Page 24: Review-Molecular Formula Nicotine, a component of tobacco, has an empirical formula of C 5 H 7 N. The molar mass of nicotine is 162 g. What is its molecular

Predict if the following reactions will occur

• 1. Fe + H2O

• 2. Mg + LiNO3

• 3. Na + AgCl

Page 25: Review-Molecular Formula Nicotine, a component of tobacco, has an empirical formula of C 5 H 7 N. The molar mass of nicotine is 162 g. What is its molecular

Double Displacement Reactions

• In a double displacement reaction, two compounds react

• The compounds swap elements with each other

Page 26: Review-Molecular Formula Nicotine, a component of tobacco, has an empirical formula of C 5 H 7 N. The molar mass of nicotine is 162 g. What is its molecular

Double Displacement Cont

• Compounds contain a positive and negative part

• In a double displacement, the positive parts swap places with each other as do the negative parts

Page 27: Review-Molecular Formula Nicotine, a component of tobacco, has an empirical formula of C 5 H 7 N. The molar mass of nicotine is 162 g. What is its molecular

Examples

• PbCl2 (s) + Li2SO4 (aq) PbSO4 (s) + 2 LiCl (aq)

• ZnBr2 (aq) + 2 AgNO3 (aq) Zn(NO3)2 (aq) + 2 AgBr (s)

Page 28: Review-Molecular Formula Nicotine, a component of tobacco, has an empirical formula of C 5 H 7 N. The molar mass of nicotine is 162 g. What is its molecular

Combustion Reactions

• In a combustion reaction, a Hydrocarbon (compound containing Hydrogen and Carbon) reacts with Oxygen (O2)

• The products are CO2 and H2O

Page 29: Review-Molecular Formula Nicotine, a component of tobacco, has an empirical formula of C 5 H 7 N. The molar mass of nicotine is 162 g. What is its molecular

Example

•2 C6H6 + 15 O212 CO2 + 6 H2O•*Combustion Reactions

commonly require large coefficients

Page 30: Review-Molecular Formula Nicotine, a component of tobacco, has an empirical formula of C 5 H 7 N. The molar mass of nicotine is 162 g. What is its molecular

Ionic Equations

• Most ionic compound dissociate (or break apart) when dissolved in water to form its component ions

• For example: NaCl (aq) really looks like Na+(aq) and Cl- (aq)

Page 31: Review-Molecular Formula Nicotine, a component of tobacco, has an empirical formula of C 5 H 7 N. The molar mass of nicotine is 162 g. What is its molecular

Soluble Vs. Precipitate

• Soluble means that the compound breaks down into its ions in water

• Ex) NaCl is soluble so it forms Na+ and Cl-

• Insoluble means that the compound doesn’t break down in water

Page 32: Review-Molecular Formula Nicotine, a component of tobacco, has an empirical formula of C 5 H 7 N. The molar mass of nicotine is 162 g. What is its molecular

Precipitate Reactions

• In double replacement reactions, often one of the product will be insoluble

• The insoluble product is referred to as a precipitate

• Precipitate Rules are on the EOC sheet

Page 33: Review-Molecular Formula Nicotine, a component of tobacco, has an empirical formula of C 5 H 7 N. The molar mass of nicotine is 162 g. What is its molecular

Practice• Determine if soluble or insoluble:

• A) NaCl B) K2O

• C) Fe(NO3)3 D) AgCl

• E) BaS F) Cd(OH)2

• G) FeCl3 H) PbCO3

Page 34: Review-Molecular Formula Nicotine, a component of tobacco, has an empirical formula of C 5 H 7 N. The molar mass of nicotine is 162 g. What is its molecular

Ionic Equations Continued• To write a Complete Ionic

Equation:• Write the aqueous substances as

ions (leave any substances in gas, liquids, & solids alone)

• Example:

• AgNO3 (aq) + NaCl (aq) AgCl (s) + NaNO3 (aq)

Page 35: Review-Molecular Formula Nicotine, a component of tobacco, has an empirical formula of C 5 H 7 N. The molar mass of nicotine is 162 g. What is its molecular

Writing Ionic Equations • 1. (NH4)2S (aq) + Cd(NO3)2

(aq) NH4NO3 (???) + CdS (???)

• 2. Zn(NO3)2 (aq) + (NH4)2S (aq) ZnS (???) + NH4NO3 (???)

Page 36: Review-Molecular Formula Nicotine, a component of tobacco, has an empirical formula of C 5 H 7 N. The molar mass of nicotine is 162 g. What is its molecular

Spectator Ions

• Spectator Ions-Ions that are not directly involved in a reaction

• Spectator ions show up on both sides of the equation

• Spectator Ions cancel out

Page 37: Review-Molecular Formula Nicotine, a component of tobacco, has an empirical formula of C 5 H 7 N. The molar mass of nicotine is 162 g. What is its molecular

NET Ionic Equations

• Net Ionic Equation-Indicate the particles that actually take part in a reaction

• The Net Ionic Equation does NOT include spectator ions

• Net Ionic Equations must be balanced according to atoms and charge

Page 38: Review-Molecular Formula Nicotine, a component of tobacco, has an empirical formula of C 5 H 7 N. The molar mass of nicotine is 162 g. What is its molecular

Write Net Ionic Equations

• 1. (NH4)2S (aq) + Cd(NO3)2 (aq)

• 2. Zn(NO3)2 (aq) + (NH4)2S (aq)