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Restraints

Restraints · sed[x] = 2[5/2]=2.236 Differences 3 x 2.236 = 6.7 will be significant at 5% level 5 times out of 6 Precision. In an experiment is 10% of the mean (i.e. =m/10)

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Page 1: Restraints · sed[x] = 2[5/2]=2.236 Differences 3 x 2.236 = 6.7 will be significant at 5% level 5 times out of 6 Precision. In an experiment is 10% of the mean (i.e. =m/10)

Restraints

Page 2: Restraints · sed[x] = 2[5/2]=2.236 Differences 3 x 2.236 = 6.7 will be significant at 5% level 5 times out of 6 Precision. In an experiment is 10% of the mean (i.e. =m/10)

The Burning Question

Fixed or Random?

Page 3: Restraints · sed[x] = 2[5/2]=2.236 Differences 3 x 2.236 = 6.7 will be significant at 5% level 5 times out of 6 Precision. In an experiment is 10% of the mean (i.e. =m/10)

Facilities

Types of data.

Collection.

Measure or visual assess.

Time availability

Graduate students.

Short term grant.

Funding.

Never enough!

Page 4: Restraints · sed[x] = 2[5/2]=2.236 Differences 3 x 2.236 = 6.7 will be significant at 5% level 5 times out of 6 Precision. In an experiment is 10% of the mean (i.e. =m/10)

Factors and Factor Levels

Page 5: Restraints · sed[x] = 2[5/2]=2.236 Differences 3 x 2.236 = 6.7 will be significant at 5% level 5 times out of 6 Precision. In an experiment is 10% of the mean (i.e. =m/10)

Number of Factors

How many factors to include?

Often it is the more simple experiments that yield “best” results.

Two-way interactions can be difficult to interpret.

Generally include no more than 3 factors.

Page 6: Restraints · sed[x] = 2[5/2]=2.236 Differences 3 x 2.236 = 6.7 will be significant at 5% level 5 times out of 6 Precision. In an experiment is 10% of the mean (i.e. =m/10)

Number of Factor Levels

Explain the effect of increasing or decreasing levels.

• Usually only a few.

Predict values not included in actual study.

• Regression.

• Usually many factor levels.

Page 7: Restraints · sed[x] = 2[5/2]=2.236 Differences 3 x 2.236 = 6.7 will be significant at 5% level 5 times out of 6 Precision. In an experiment is 10% of the mean (i.e. =m/10)

Test different treatments to find “best”.

• Different insecticides, herbicides, etc.

• Determined by how many are available.

Fixed or Random?

Number of Factor Levels

Page 8: Restraints · sed[x] = 2[5/2]=2.236 Differences 3 x 2.236 = 6.7 will be significant at 5% level 5 times out of 6 Precision. In an experiment is 10% of the mean (i.e. =m/10)

Number of Replicates

The variation that is likely between factors and factor levels.

Degree of variability or heterogeneity over the experimental area.

Degree of precision required.

Page 9: Restraints · sed[x] = 2[5/2]=2.236 Differences 3 x 2.236 = 6.7 will be significant at 5% level 5 times out of 6 Precision. In an experiment is 10% of the mean (i.e. =m/10)

Precision

Number of

Replicates

Standard error of the

treatment mean

1 1.00

2 0.71

3 0.58

4 0.50

5 0.45

se[x] = /n

Page 10: Restraints · sed[x] = 2[5/2]=2.236 Differences 3 x 2.236 = 6.7 will be significant at 5% level 5 times out of 6 Precision. In an experiment is 10% of the mean (i.e. =m/10)

0

0.1

0.2

0.3

0.4

0.5

0.6

0.7

0.8

0.9

1

1 3 5 7 9 11

13

15

17

19

21

23

se[m

ean

]

Number of Replicates

Precision

Page 11: Restraints · sed[x] = 2[5/2]=2.236 Differences 3 x 2.236 = 6.7 will be significant at 5% level 5 times out of 6 Precision. In an experiment is 10% of the mean (i.e. =m/10)

What is the magnitude of

difference that needs detecting?

Variance of plot = 2

sed[x] = 22/n

Differences 3 x sed[x] will be

significant at 5% level 5 times out of 6

Precision

Page 12: Restraints · sed[x] = 2[5/2]=2.236 Differences 3 x 2.236 = 6.7 will be significant at 5% level 5 times out of 6 Precision. In an experiment is 10% of the mean (i.e. =m/10)

What is the magnitude of

difference that needs detecting?

Variance of plot = 252 , n = 4

sed[x] = 2[5/2]=2.236

Differences 3 x 2.236 = 6.7 will be

significant at 5% level 5 times out of 6

Precision

Page 13: Restraints · sed[x] = 2[5/2]=2.236 Differences 3 x 2.236 = 6.7 will be significant at 5% level 5 times out of 6 Precision. In an experiment is 10% of the mean (i.e. =m/10)

In an experiment is 10% of the mean

(i.e. =m/10)

sed[x] = 2(m/10)2/4 = 0.07m

3 x 0.07 = 0.21

A true difference of 21% of the mean value will

be significant at the 5% level 5 times out of 6.

sed[x] = (m2/200)/ = 0.07m

Precision

Page 14: Restraints · sed[x] = 2[5/2]=2.236 Differences 3 x 2.236 = 6.7 will be significant at 5% level 5 times out of 6 Precision. In an experiment is 10% of the mean (i.e. =m/10)

To detect a true difference of 15% how

many reps would be needed?

sed[x] = 2(m/10)2/n

3 x 2(m/10)2/n < 0.15m

18 x (m2/102) /n < 0.152m2

n > [18 x (1/10)2/0.152 = 8

Precision

Page 15: Restraints · sed[x] = 2[5/2]=2.236 Differences 3 x 2.236 = 6.7 will be significant at 5% level 5 times out of 6 Precision. In an experiment is 10% of the mean (i.e. =m/10)

Plot Size

Bigger plots and more

replicates are always best.

Usually a compromise has to

be reached to fit restraints.

Machinery availability.

Physical yields.

Page 16: Restraints · sed[x] = 2[5/2]=2.236 Differences 3 x 2.236 = 6.7 will be significant at 5% level 5 times out of 6 Precision. In an experiment is 10% of the mean (i.e. =m/10)

Plot Size

Layout se[x] se[x] se[plot]

1 x 100 r/1 r1.00 p0.10

2 x 50 r/2 r0.71 p0.14

4 x 25 r/4 r0.50 p0.20

5 x 20 r/5 r0.45 p0.22

10 x 10 r/10 r0.32 p0.32

Page 17: Restraints · sed[x] = 2[5/2]=2.236 Differences 3 x 2.236 = 6.7 will be significant at 5% level 5 times out of 6 Precision. In an experiment is 10% of the mean (i.e. =m/10)

Machinery Available

Page 18: Restraints · sed[x] = 2[5/2]=2.236 Differences 3 x 2.236 = 6.7 will be significant at 5% level 5 times out of 6 Precision. In an experiment is 10% of the mean (i.e. =m/10)
Page 19: Restraints · sed[x] = 2[5/2]=2.236 Differences 3 x 2.236 = 6.7 will be significant at 5% level 5 times out of 6 Precision. In an experiment is 10% of the mean (i.e. =m/10)
Page 20: Restraints · sed[x] = 2[5/2]=2.236 Differences 3 x 2.236 = 6.7 will be significant at 5% level 5 times out of 6 Precision. In an experiment is 10% of the mean (i.e. =m/10)
Page 21: Restraints · sed[x] = 2[5/2]=2.236 Differences 3 x 2.236 = 6.7 will be significant at 5% level 5 times out of 6 Precision. In an experiment is 10% of the mean (i.e. =m/10)
Page 22: Restraints · sed[x] = 2[5/2]=2.236 Differences 3 x 2.236 = 6.7 will be significant at 5% level 5 times out of 6 Precision. In an experiment is 10% of the mean (i.e. =m/10)
Page 23: Restraints · sed[x] = 2[5/2]=2.236 Differences 3 x 2.236 = 6.7 will be significant at 5% level 5 times out of 6 Precision. In an experiment is 10% of the mean (i.e. =m/10)
Page 24: Restraints · sed[x] = 2[5/2]=2.236 Differences 3 x 2.236 = 6.7 will be significant at 5% level 5 times out of 6 Precision. In an experiment is 10% of the mean (i.e. =m/10)
Page 25: Restraints · sed[x] = 2[5/2]=2.236 Differences 3 x 2.236 = 6.7 will be significant at 5% level 5 times out of 6 Precision. In an experiment is 10% of the mean (i.e. =m/10)
Page 26: Restraints · sed[x] = 2[5/2]=2.236 Differences 3 x 2.236 = 6.7 will be significant at 5% level 5 times out of 6 Precision. In an experiment is 10% of the mean (i.e. =m/10)
Page 27: Restraints · sed[x] = 2[5/2]=2.236 Differences 3 x 2.236 = 6.7 will be significant at 5% level 5 times out of 6 Precision. In an experiment is 10% of the mean (i.e. =m/10)
Page 28: Restraints · sed[x] = 2[5/2]=2.236 Differences 3 x 2.236 = 6.7 will be significant at 5% level 5 times out of 6 Precision. In an experiment is 10% of the mean (i.e. =m/10)

On-farm Testing

Page 29: Restraints · sed[x] = 2[5/2]=2.236 Differences 3 x 2.236 = 6.7 will be significant at 5% level 5 times out of 6 Precision. In an experiment is 10% of the mean (i.e. =m/10)

Guard Rows and

Discard Rows

Mechanical damage usually occurs around the edges.

Avoid “edge effect”.

Guard rows can be used to “buffer” treatment effects.

Guard rows do not have to be the same species as is in trial.

Page 30: Restraints · sed[x] = 2[5/2]=2.236 Differences 3 x 2.236 = 6.7 will be significant at 5% level 5 times out of 6 Precision. In an experiment is 10% of the mean (i.e. =m/10)

Discard Rows

Page 31: Restraints · sed[x] = 2[5/2]=2.236 Differences 3 x 2.236 = 6.7 will be significant at 5% level 5 times out of 6 Precision. In an experiment is 10% of the mean (i.e. =m/10)
Page 32: Restraints · sed[x] = 2[5/2]=2.236 Differences 3 x 2.236 = 6.7 will be significant at 5% level 5 times out of 6 Precision. In an experiment is 10% of the mean (i.e. =m/10)

?

Page 33: Restraints · sed[x] = 2[5/2]=2.236 Differences 3 x 2.236 = 6.7 will be significant at 5% level 5 times out of 6 Precision. In an experiment is 10% of the mean (i.e. =m/10)

Examples

Page 34: Restraints · sed[x] = 2[5/2]=2.236 Differences 3 x 2.236 = 6.7 will be significant at 5% level 5 times out of 6 Precision. In an experiment is 10% of the mean (i.e. =m/10)

Jeannie’s Oriental Mustard

Oriental mustard (Brassica juncea

L.) is a new crop to the PNW

Growers have little experience

growing the crop.

Design an experiment to determine

the optimum growing conditions to

maximize productivity.

Page 35: Restraints · sed[x] = 2[5/2]=2.236 Differences 3 x 2.236 = 6.7 will be significant at 5% level 5 times out of 6 Precision. In an experiment is 10% of the mean (i.e. =m/10)

Four cultivars.

◦ 2 oilseed and 2 condiment.

2 planting dates.

3 seeding rates.

5 nitrogen levels.

3 Replicates.

Jeannie’s Oriental Mustard

Page 36: Restraints · sed[x] = 2[5/2]=2.236 Differences 3 x 2.236 = 6.7 will be significant at 5% level 5 times out of 6 Precision. In an experiment is 10% of the mean (i.e. =m/10)

Jeannie’s Oriental Mustard

Page 37: Restraints · sed[x] = 2[5/2]=2.236 Differences 3 x 2.236 = 6.7 will be significant at 5% level 5 times out of 6 Precision. In an experiment is 10% of the mean (i.e. =m/10)

9&10

7&8

5&6

3&4

1-2

Late Planting Early Planting

Jeannie’s Oriental Mustard

Page 38: Restraints · sed[x] = 2[5/2]=2.236 Differences 3 x 2.236 = 6.7 will be significant at 5% level 5 times out of 6 Precision. In an experiment is 10% of the mean (i.e. =m/10)

9&10

7&8

5&6

3&4

1-2

Late Planting Early Planting

I II III I II III

Jeannie’s Oriental Mustard

Page 39: Restraints · sed[x] = 2[5/2]=2.236 Differences 3 x 2.236 = 6.7 will be significant at 5% level 5 times out of 6 Precision. In an experiment is 10% of the mean (i.e. =m/10)

9&10 75lb 25lb 75lb 50lb 0lb 25lb

7&8 0lb 0lb 25lb 70lb 50lb 100lb

5&6 25lb 50lb 100lb 25lb 75lb 75lb

3&4 50lb 75lb 50lb 0lb 100lb 0lb

1-2 100lb 100lb 0lb 100lb 25lb 50lb

Late Planting Early Planting

I II III I II III

Jeannie’s Oriental Mustard

Page 40: Restraints · sed[x] = 2[5/2]=2.236 Differences 3 x 2.236 = 6.7 will be significant at 5% level 5 times out of 6 Precision. In an experiment is 10% of the mean (i.e. =m/10)

9&10 75lb 25lb 75lb 50lb 0lb 25lb

7&8 0lb 0lb 25lb 70lb 50lb 100lb

5&6 25lb 50lb 100lb 25lb 75lb 75lb

3&4 50lb 75lb 50lb 0lb 100lb 0lb

1-2 100lb 100lb 0lb 100lb 25lb 50lb

Late Planting Early Planting

I II III I II III

Jeannie’s Oriental Mustard

Page 41: Restraints · sed[x] = 2[5/2]=2.236 Differences 3 x 2.236 = 6.7 will be significant at 5% level 5 times out of 6 Precision. In an experiment is 10% of the mean (i.e. =m/10)

1

2

Ari

d 3

g

Ari

d 4

g

Ari

d 5

g

Jeannie’s Oriental Mustard

Page 42: Restraints · sed[x] = 2[5/2]=2.236 Differences 3 x 2.236 = 6.7 will be significant at 5% level 5 times out of 6 Precision. In an experiment is 10% of the mean (i.e. =m/10)

1

2

Ari

d 3

g

Ari

d 4

g

Ari

d 5

g

Am

ula

t 4 g

Am

ula

t 5

g

Am

ula

t 3 g

P. G

old

5 g

P. G

old

3 g

P. G

old

4 g

Ko

dia

k 5

g

Ko

dia

k 3

gK

od

iak 4

g

Jeannie’s Oriental Mustard

Page 43: Restraints · sed[x] = 2[5/2]=2.236 Differences 3 x 2.236 = 6.7 will be significant at 5% level 5 times out of 6 Precision. In an experiment is 10% of the mean (i.e. =m/10)

1

2

Ari

d 3

g

Ari

d 5

g

Ari

d 4

g

Jeannie’s Oriental Mustard

Page 44: Restraints · sed[x] = 2[5/2]=2.236 Differences 3 x 2.236 = 6.7 will be significant at 5% level 5 times out of 6 Precision. In an experiment is 10% of the mean (i.e. =m/10)

1

2

Ari

d 3

g

Am

ula

t 4 g

P. G

old

5 g

Ko

dia

k 5

g

Ko

dia

k 3

g

Ko

dia

k 4

g

P. G

old

4 g

P. G

old

3 g

Am

ula

t 5 g

Am

ula

t 3 g

Ari

d 5

g

Ari

d 4

g

Jeannie’s Oriental Mustard

Page 45: Restraints · sed[x] = 2[5/2]=2.236 Differences 3 x 2.236 = 6.7 will be significant at 5% level 5 times out of 6 Precision. In an experiment is 10% of the mean (i.e. =m/10)

Revision of

Experimental Design

and More Examples