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Reaction Mechanisms

Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

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Page 1: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Reaction Mechanisms

Page 2: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Reaction Mechanisms  Consider the following reaction: 4 HBr(g) + O2(g) → 2H2O(g) + 2Br2(g)

There are five reactants…Typically more than 3 molecules colliding at any one time is very improbable.

So reaction having 5 reactants in the bal. equation must occur in more than one step.

Even a reaction containing 2 or 3 molecules can occur in more than one step.

The actual sequence of steps which make up an overall reaction is called a reaction mechanism!

Page 3: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Mechanism 1 .

HBr(g) + O2(g) → HOOBr(g) slow

 HBr(g) + HOOBr(g) → 2HOBr(g) fast

 2HOBr(g) +2HBr(g) → 2H2O(g)+ 2Br2(g) fast

 

         

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Reaction Path

Page 4: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Mechanism 1 Cancel out identical formulas to get the overall equation.

HBr(g) + O2(g) → HOOBr(g) slow

 HBr(g) + HOOBr(g) → 2HOBr(g) fast

 2HOBr(g) +2HBr(g) → 2H2O(g)+ 2Br2(g) fast

 

         

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Reaction Path

Page 5: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Mechanism 1 Cancel out identical formulas to get the overall equation.

HBr(g) + O2(g) → HOOBr(g) slow

 HBr(g) + HOOBr(g) → 2HOBr(g) fast

 2HOBr(g) +2HBr(g) → 2H2O(g)+ 2Br2(g) fast

 

         

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Reaction Path

Page 6: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Mechanism 1 Cancel out identical formulas to get the overall equation.

HBr(g) + O2(g) → HOOBr(g) slow

 HBr(g) + HOOBr(g) → 2HOBr(g) fast

 2HOBr(g) +2HBr(g) → 2H2O(g)+ 2Br2(g) fast

 

         

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Reaction Path

Page 7: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Mechanism 1 Intermediates are produced and then consumed and cross out from right (first) and left (second). HBr(g) + O2(g) → HOOBr(g) slow

 HBr(g) + HOOBr(g) → 2HOBr(g) fast

 2HOBr(g) +2HBr(g) → 2H2O(g)+ 2Br2(g) fast

 

         

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Reaction Path

Page 8: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Mechanism 1 What is left is the overall reaction.

HBr(g) + O2(g) → HOOBr(g) slow

 HBr(g) + HOOBr(g) → 2HOBr(g) fast

 2HOBr(g) +2HBr(g) → 2H2O(g)+ 2Br2(g) fast

 

         

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Reaction Path

Page 9: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Mechanism 1 What is left is the overall reaction.

HBr(g) + O2(g) → HOOBr(g) slow

 HBr(g) + HOOBr(g) → 2HOBr(g) fast

 2HOBr(g) +2HBr(g) → 2H2O(g)+ 2Br2(g) fast

 4HBr(g) + O2(g) → 2H2O(g)+ 2Br2(g)

         

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Reaction Path

Page 10: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Mechanism 1 Step 1, which is the slow step, is called the rate determining step and has the highest activation energy. HBr(g) + O2(g) → HOOBr(g) slow

 HBr(g) + HOOBr(g) → 2HOBr(g) fast

 2HOBr(g) +2HBr(g) → 2H2O(g)+ 2Br2(g) fast

 4HBr(g) + O2(g) → 2H2O(g)+ 2Br2(g)

         

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Reaction Path

Page 11: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Mechanism 1 HBr(g) + O2(g) → HOOBr(g) slow

 HBr(g) + HOOBr(g) → 2HOBr(g) fast

 2HOBr(g) +2HBr(g) → 2H2O(g)+ 2Br2(g) fast

 4HBr(g) + O2(g) → 2H2O(g)+ 2Br2(g)

  A potential energy diagram for this reaction might look like this.      

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Reaction Path

Page 12: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Mechanism 1 HBr(g) + O2(g) → HOOBr(g) slow

 HBr(g) + HOOBr(g) → 2HOBr(g) fast

 2HOBr(g) +2HBr(g) → 2H2O(g)+ 2Br2(g) fast

 4HBr(g) + O2(g) → 2H2O(g)+ 2Br2(g)

  A potential energy diagram for this reaction might look like this.      

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Reaction Path

Page 13: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Mechanism 1

HBr(g) + O2(g) → HOOBr(g) slow

 HBr(g) + HOOBr(g) → 2HOBr(g) fast

 2HOBr(g) +2HBr(g) → 2H2O(g)+ 2Br2(g) fast

 4HBr(g) + O2(g) → 2H2O(g)+ 2Br2(g)

   highestA potential energy diagram for this Mechanism has three humpsThe slow step has the highest Ea

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Reaction Path

Ea

Ea(rev)

Page 14: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

The Rate Determining Step

The slowest step in the reaction mechanism is called the rate-determining step. It has the highest Ea.

To increase the rate, you must increase the rate of this step. Increasing the rate of a fast step will not increase the rate of the overall reaction.

Page 15: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Identifying a Catalyst in a Mechanism How to find a catalyst in a reaction mechanism??

A catalyst is used in one step; it speeds up the reaction, and then is regenerated in a later step. Therefore, a catalyst will cancel out but will be first found on the left side (with reactants) in an earlier step then on the right side.  

 

Page 16: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Identifying a Catalyst in a Mechanism A catalyst is not consumed in the reaction. It is used in one step; it speeds up the reaction, and then is regenerated in a later step. A catalyst will cancel out but will be on the left side in an earlier step then on the right side.  

C →→ C

 

 

Page 17: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Identifying a Catalyst in a Mechanism A catalyst is not consumed in the reaction. It is used in one step; it speeds up the reaction, and then is regenerated in a later step. A catalyst will cancel out but will be on the left side in an earlier step then on the right side.  

C →→ C

 

 

Page 18: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Identifying a Catalyst in a Mechanism A catalyst is not consumed in the reaction. It is used in one step; it speeds up the reaction, and then is regenerated in a later step. A catalyst will cancel out but will be on the left side in an earlier step then on the right side.  

C →→ C

 An intermediate is produced and then consumed. It will be on the right side in an earlier step then on the left side. 

 

Page 19: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Identifying a Catalyst in a Mechanism A catalyst is not consumed in the reaction. It is used in one step; it speeds up the reaction, and then is regenerated in a later step. A catalyst will cancel out but will be on the left side in an earlier step then on the right side.  

C →→ C

 An intermediate is produced and then consumed. It will be on the right side in an earlier step then on the left side. 

→ II →  

 

Page 20: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Identifying a Catalyst in a Mechanism A catalyst is not consumed in the reaction. It is used in one step; it speeds up the reaction, and then is regenerated in a later step. A catalyst will cancel out but will be on the left side in an earlier step then on the right side.  

C →→ C

 An intermediate is produced and then consumed. It will be on the right side in an earlier step then on the left side. 

→ II →  

 

Page 21: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Mechanism 2

1. A + B → C 2. C + D → CD 3. CD + E → ABE + D  Overall Equation: Catalyst: Intermediate:   

Page 22: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Mechanism 2

1. A + B → C 2. C + D → CD 3. CD + E → ABE + D  Overall Equation: Catalyst: Intermediate:   

Page 23: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Mechanism 2

1. A + B → C 2. C + D → CD 3. CD + E → ABE + D  Overall Equation: Catalyst: Intermediate:   C 

Page 24: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Mechanism 2

1. A + B → C 2. C + D → CD 3. CD + E → ABE + D  Overall Equation: Catalyst: Intermediate:   C 

Page 25: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Mechanism 2

1. A + B → C 2. C + D → CD 3. CD + E → ABE + D  Overall Equation: Catalyst: Intermediate:   C CD 

Page 26: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Mechanism 2

1. A + B → C 2. C + D → CD 3. CD + E → ABE + D  Overall Equation: Catalyst: Intermediate:   C CD 

Page 27: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Mechanism 2

1. A + B → C 2. C + D → CD 3. CD + E → ABE + D  Overall Equation: Catalyst: D Intermediate:   C CD 

Page 28: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Mechanism 2

1. A + B → C 2. C + D → CD 3. CD + E → ABE + D  Overall Equation: A + B + E → ABE Catalyst: D Intermediate:   C CD 

Page 29: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Mechanism 3

Step 1 Br2 → 2Br

Step 2 Br + OCl2 → BrOCl + Cl

Step 3 Br + Cl → BrCl

Overall Reaction: Intermediates:

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Reaction Path

Page 30: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Mechanism 3

Step 1 Br2 → 2Br

Step 2 Br + OCl2 → BrOCl + Cl

Step 3 Br + Cl → BrCl

Overall Reaction: Intermediates:

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Reaction Path

Page 31: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Mechanism 3

Step 1 Br2 → 2Br

Step 2 Br + OCl2 → BrOCl + Cl

Step 3 Br + Cl → BrCl

Overall Reaction: Br2 + OCl2 → BrOCl + BrCl Intermediates:

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Reaction Path

Page 32: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Mechanism 3

Step 1 Br2 → 2Br

Step 2 Br + OCl2 → BrOCl + Cl

Step 3 Br + Cl → BrCl

Overall Reaction: Br2 + OCl2 → BrOCl + BrCl Intermediates: Br Cl

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Reaction Path

Page 33: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Mechanism 3

Step 1 Br2 → 2Br

Step 2 Br + OCl2 → BrOCl + Cl

Step 3 Br + Cl → BrCl

Overall Reaction: Br2 + OCl2 → BrOCl + BrCl Intermediates: Br Cl

ΔH =Ea (forward) =  Ea (reverse) =The enthalpy of BrThe enthalpy of BrCl

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Reaction Path

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Page 34: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Mechanism 3

Step 1 Br2 → 2Br

Step 2 Br + OCl2 → BrOCl + Cl

Step 3 Br + Cl → BrCl

Overall Reaction: Br2 + OCl2 → BrOCl + BrCl Intermediates: Br Cl

ΔH = 200 kJEa (forward) =  Ea (reverse) =The enthalpy of Br  The enthalpy of BrCl

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Reaction Path

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Page 35: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Mechanism 3

Step 1 Br2 → 2Br

Step 2 Br + OCl2 → BrOCl + Cl

Step 3 Br + Cl → BrCl

Overall Reaction: Br2 + OCl2 → BrOCl + BrCl Intermediates: Br Cl

ΔH = 200 kJEa (forward) =  Ea (reverse) =The enthalpy of Br  The enthalpy of BrCl

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Reaction Path

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600

Page 36: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Mechanism 3

Step 1 Br2 → 2Br

Step 2 Br + OCl2 → BrOCl + Cl

Step 3 Br + Cl → BrCl

Overall Reaction: Br2 + OCl2 → BrOCl + BrCl Intermediates: Br Cl

ΔH = 200 kJEa (forward) = 600 kJ  Ea (reverse) =The enthalpy of Br  The enthalpy of BrCl

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Reaction Path

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Page 37: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Mechanism 3

Step 1 Br2 → 2Br

Step 2 Br + OCl2 → BrOCl + Cl

Step 3 Br + Cl → BrCl

Overall Reaction: Br2 + OCl2 → BrOCl + BrCl Intermediates: Br Cl

ΔH = 200 kJEa (forward) = 600 kJ  Ea (reverse) = 400 kJThe enthalpy of Br  The enthalpy of BrCl

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Reaction Path

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Page 38: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Mechanism 3

Step 1 Br2 → 2Br

Step 2 Br + OCl2 → BrOCl + Cl

Step 3 Br + Cl → BrCl

Overall Reaction: Br2 + OCl2 → BrOCl + BrCl Intermediates: Br Cl

ΔH = 200 kJEa (forward) = 600 kJ  Ea (reverse) = 400 kJThe enthalpy of Br 300 kJ  The enthalpy of BrCl

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Reaction Path

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Page 39: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Mechanism 3

Step 1 Br2 → 2Br

Step 2 Br + OCl2 → BrOCl + Cl

Step 3 Br + Cl → BrCl

Overall Reaction: Br2 + OCl2 → BrOCl + BrCl Intermediates: Br Cl

ΔH = 200 kJEa (forward) = 600 kJ  Ea (reverse) = 400 kJThe enthalpy of Br 300 kJ  The enthalpy of BrCl 400 kJ

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Reaction Path

800

200

400

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Page 40: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Mechanism 4

The following mechanism shows how chlorine-containing fluorocarbons destroy the ozone layer. Ozone is O3 and O

 1. CFCl3 → CFCl2 + Cl

 2. Cl + O3 → ClO + O2

 3. ClO + O → Cl + O2

 Overall Reaction: Intermediates:  

Page 41: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Mechanism 4

The following mechanism shows how chlorine-containing fluorocarbons destroy the ozone layer. Ozone is O3 and O

 1. CFCl3 → CFCl2 + Cl

 2. Cl + O3 → ClO + O2

 3. ClO + O → Cl + O2

 Overall Reaction: Intermediates:  

Page 42: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Mechanism 4

The following mechanism shows how chlorine-containing fluorocarbons destroy the ozone layer. Ozone is O3 and O

 1. CFCl3 → CFCl2 + Cl

 2. Cl + O3 → ClO + O2

 3. ClO + O → Cl + O2

 Overall Reaction: CFCl3 + O3 + O → CFCl2 + 2O2 + Cl

 Intermediates:  

Page 43: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Mechanism 4

The following mechanism shows how chlorine-containing fluorocarbons destroy the ozone layer. Ozone is O3 and O

 1. CFCl3 → CFCl2 + Cl

 2. Cl + O3 → ClO + O2

 3. ClO + O → Cl + O2

 Overall Reaction: CFCl3 + O3 + O → CFCl2 + 2O2+ Cl

Intermediates: Cl ClO Formula of activated complex in step 2:  

Page 44: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Determine the Missing Step of the Mechanism

Mechanism 5 

A + B → C 

C + D → B + AD 

 Overall: A + D + E → ADE   

Page 45: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Determine the Missing Step of the Mechanism

Mechanism 5 

A + B → C 

C + D → B + AD 

 Overall: A + D + E → ADE   

Page 46: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Determine the Missing Step of the Mechanism

Mechanism 5 

A + B → C 

C + D → B + AD 

 Overall: A + D + E → ADE   

Put in step 3 so that you get the overall reaction

Page 47: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Determine the Missing Step of the Mechanism

Mechanism 5 

A + B → C 

C + D → B + AD 

AD Overall: A + D + E → ADE   

Put in AD to cancel

Page 48: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Determine the Missing Step of the Mechanism

Mechanism 5 

A + B → C 

C + D → B + AD 

AD + → Overall: A + D + E → ADE   

Put in AD to cancel

Page 49: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Determine the Missing Step of the Mechanism

Mechanism 5 

A + B → C 

C + D → B + AD 

AD + E → Overall: A + D + E → ADE   

Put in E

Page 50: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Determine the Missing Step of the Mechanism

Mechanism 5 

A + B → C 

C + D → B + AD 

AD + E → ADE Overall: A + D + E → ADE   

Put in ADE

Page 51: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules
Page 52: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Determine the Missing Step of the Mechanism

Mechanism 6 

 C + D → CD

 CD + E → ABE + D

 Overall: A + B + E → ABE   

Page 53: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Determine the Missing Step of the Mechanism

Mechanism 6 

 C + D → CD

 CD + E → ABE + D

 Overall: A + B + E → ABE   

Page 54: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Determine the Missing Step of the Mechanism

Mechanism 6 

 C + D → CD

 CD + E → ABE + D

 Overall: A + B + E → ABE   

Page 55: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Determine the Missing Step of the Mechanism

Mechanism 6 

 C + D → CD

 CD + E → ABE + D

 Overall: A + B + E → ABE   

Page 56: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Determine the Missing Step of the Mechanism

Mechanism 6 

→ C 

C + D → CD 

CD + E → ABE + D Overall: A + B + E → ABE   

Page 57: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Determine the Missing Step of the Mechanism

Mechanism 6 

→ C 

C + D → CD 

CD + E → ABE + D Overall: A + B + E → ABE   

Page 58: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Determine the Missing Step of the Mechanism

Mechanism 6 

A + B → C 

C + D → CD 

CD + E → ABE + D Overall: A + B + E → ABE   

Page 59: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Determine the Missing Step of the Mechanism

Mechanism 7 

CFCl3 → CFCl2 + Cl

 

 ClO + O → Cl + O2

 Overall: O + CFCl3 + O3 → CFCl2 + 2O2 + Cl  

 

Page 60: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Determine the Missing Step of the Mechanism

Mechanism 7 

CFCl3 → CFCl2 + Cl

 

 ClO + O → Cl + O2

 Overall: O + CFCl3 + O3 → CFCl2 + 2O2 + Cl  

 

Page 61: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Determine the Missing Step of the Mechanism

Mechanism 7 

CFCl3 → CFCl2 + Cl

  Cl

 ClO + O → Cl + O2

 Overall: O + CFCl3 + O3 → CFCl2 + 2O2 + Cl  

 

Page 62: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Determine the Missing Step of the Mechanism

Mechanism 7 

CFCl3 → CFCl2 + Cl

  Cl

 ClO + O → Cl + O2

 Overall: O + CFCl3 + O3 → CFCl2 + 2O2 + Cl  

 

Page 63: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Determine the Missing Step of the Mechanism

Mechanism 7 

CFCl3 → CFCl2 + Cl

 Cl + O3

 ClO + O → Cl + O2

 Overall: O + CFCl3 + O3 → CFCl2 + 2O2 + Cl  

 

Page 64: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Determine the Missing Step of the Mechanism

Mechanism 7 

CFCl3 → CFCl2 + Cl

 Cl + O3 → ClO + O2

 ClO + O → Cl + O2

 Overall: O + CFCl3 + O3 → CFCl2 + 2O2 + Cl  

 

Page 65: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Determine the Missing Step of the Mechanism

Mechanism 7 

CFCl3 → CFCl2 + Cl

 Cl + O3 → ClO + O2

 ClO + O → Cl + O2

 Overall: O + CFCl3 + O3 → CFCl2 + 2O2 + Cl  

 

Page 66: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Determine the Missing Step of the Mechanism

Mechanism 7 

CFCl3 → CFCl2 + Cl

 Cl + O3 → ClO + O2

 ClO + O → Cl + O2

 Overall: O + CFCl3 + O3 → CFCl2 + 2O2 + Cl  

 

Page 67: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Determine the Missing Step of the Mechanism

Mechanism 7 

CFCl3 → CFCl2 + Cl

 Cl + O3 → ClO + O2

 ClO + O → Cl + O2

 Overall: O + CFCl3 + O3 → CFCl2 + 2O2 + Cl  

 

Page 68: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Determine the Missing Step of the Mechanism

Mechanism 7 

CFCl3 → CFCl2 + Cl

 Cl + O3 → ClO + O2

 ClO + O → Cl + O2

 Overall: O + CFCl3 + O3 → CFCl2 + 2O2 + Cl  

 

Page 69: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Reaction IntermediateNotes:• An intermediate doesn’t accumulate (like a

product) because as soon as it is formed, it gets used up again.

• Intermediates are not necessarily unstable (in other circumstances, they may last a while).

• An activated complex is very unstable and short-lived. It doesn’t usually obey bonding “rules.”

Page 70: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

HOMEWORK

Hebden Textbook Page 28 Questions #47-53

Page 71: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Reaction Mechanism

Review Questions

Page 72: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Provincial Exam Questions

Page 73: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Provincial Exam Questions

Page 74: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Provincial Exam Questions

Page 75: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

PE Diagram for a Reaction Mechanism

AC (Step 1) AC (Step 2)

AC (Step 3)

HOOBr

PE HBr + O2

HOBr

H2O + Br2

Reaction ProceedsLabel this diagram: RDS, Ea (Overall Rxn), Ea (Step 2), ∆H.

Page 76: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

PE Diagram for a Reaction Mechanism

Notes:• each “hump” is a step• the higher the hump (greater Ea), the slower the

step• the highest hump (greatest Ea) is for the RDS• AC’s are found at top of humps, intermediates

in middle “valleys”, products in the final “valley”

• the Ea for the forward overall rxn is vertical distance from reactants to top of highest hump

Page 77: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

PE Diagram for a Reaction Mechanism

• The Ea for the overall forward reaction is the difference in energy between the reactants and the top of the highest peak.

Page 78: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

PE Diagram for a Reaction Mechanism

Example: Given the following Potential Energy Diagram for a reaction mechanism:

PE

Reaction Proceeds

Page 79: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

PE Diagram for a Reaction Mechanism

1. This mechanism has steps

2. Ea for overall rxn = ______kJ

3. Ea (reverse rxn) = kJ

4. The overall rxn is thermic

5. H = kJ

6. H for reverse rxn = kJ

7. Ea (step1)=

8. RDS for forward rxn is step ________

Page 80: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

PE Diagram for a Reaction Mechanism

If asked for Ea for a particular step, you use:

Ea= PE (activated complex for that step)-PE (reactants for THAT PARTICULAR step)

If asked for Ea for overall reaction, use:

Ea= PE (highest energy activated complex)-PE (original reactantsd)

Rate determining step is simply the one with the highest numerical value of Ea you find.

Page 81: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

CatalystsCatalyst: an introduced substance which

produces an alternate mechanism with a lower activation energy.

Page 82: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

Provincial Exam Questions

Page 83: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

HOMEWORK

• Hebden Textbook

• Page 30 Questions 54-55

• Page34 Exercises 56-61

Page 84: Reaction Mechanisms Consider the following reaction: 4 HBr (g) +O 2(g) →2H 2 O (g) +2Br 2(g) There are five reactants… Typically more than 3 molecules

WE ARE DONE UNIT 1!