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1
RATIO OF ELECTRON CHARGE TO MASS (e/m) LAB
INTRODUCTION
J. J. Thomson, using a device similar to a cathode ray tube (CRT, see 2nd lab),
discovered the electron and measured the ratio of its electric charge (e) to its
mass (m). Thomson's experiment was concerned with observing the deflection of a beam
of particles in a combined electric and magnetic field. Its result established: 1)
the existence of the electron; 2) the fact that the electron has a mass (me); 3) the
fact that the electron has a charge (e); 4) that both charge and mass are quantized;
5) the ratio of e/m. In this lab we will repeat Thomson's measurement by observing
the deflection of an electron beam by a magnetic field B→.
This lab will allow you to experiment with the same type of equipment used for the
discovery of the electron. J. J. Thomson's discovery opened the door to our present
understanding of nature and to the technical world we are living in. The electrons
orbiting around nuclei are what make matter what it is, allow chemists to develop
new compounds, and allow biological phenomena to be explained. The electrons
oscillating in a radio antenna enable radios to transmit information. The controlled
flow of electrons through a semiconductor allows a computer to process data; and it
is a beam of electrons that allows specimens to be seen with an electron microscope.
It is with a beam of very high energy electrons that scientists have established
that nucleons are made up of components which are called quarks and gluons.
Possibly, these new components of matter will shape the way mankind will live 100
years from now in a way similar to that in which Thomson's discovery is responsible
for the way we are living today.
There are two basic physical phenomena which play a significant role in the
experiment carried out in this lab: the existence of a magnetic field associated
with an electric current, and the deflection of a moving charged particle in a
magnetic field. Before we discuss the experiment itself we will briefly review these
two phenomena, and will also discuss the fact that the earth has its own magnetic
field.
2
x
y
z
rdl
dB
I
Figure 1 Biot Savert Law
MAGNETIC FIELDS AND FORCES
The forces between electric currents are called
magnetic forces, because the same phenomenon
accounts for the forces acting between magnetic
materials, such as pieces of magnetized iron.
William Gilbert, Queen Elizabeth I's physician,
noted that a magnet has two poles at which magnetic
effects seem to be concentrated. He also showed
that like poles repel each other, whereas unlike
poles attract each other. Today we explain the
forces between magnetic poles in exact analogy with
the electrostatic forces between charges (lst lab)
by introducing a magnetic field B→ represented by
field lines. As we shall see later, the relation
between magnetic field lines and magnetic forces is
more complicated than in the case of electrostatic forces.
The fact that electric currents are intimately related to the magnetic properties of
materials was realized by Oersted, when he placed a magnetic needle over a wire and
observed that the needle moved when current flowed through the wire. Ampere then
observed that two conductors act upon one another: sometimes they attract and
sometimes they repel. It was Faraday who observed that an electrical current
produced a region of "magnetic force"; this demonstrated that the current element
acts as a source of magnetic fields (See Fig. 1). J.B. Biot and F. Savart were the
first to report to the French Academy the dependence of the "magnetic force" due to
a current flowing in a long wire upon the distance from the wire. The following
relation, known as the Biot-Savart Law, gives the field intensity dB→ observed at a
distance r→ from an element of current I dl
→:
Biot-Savart Law d B→ = µo I
dl→ x r
→
r3 (1)
3
Figure 2 Right Hand Rule
The vector d B→ is tangential to the magnetic field
lines, which in the case of a straight wire conductor
are represented by concentric circles in a plane
perpendicular to the conductor. Figure 2 shows such a
B→ field and also illustrates (together with Fig. 5)
the "right hand rule", which gives the relation
between the directions of the 3 vectors B→, dl
→ and r
→.
If the thumb of the right hand is pointed along the
direction of the current I→, the fingers curl in the
direction B→. To increase the strength of B
→ in a
given volume, one usually uses a solenoid. In this
case the field B→ generated by each winding of the
coil will add up inside the solenoid, as shown in
Figure 3. The same figure also shows the similarity
between the fields of a solenoid and of a permanent
magnet. Notice that the magnetic field inside the
solenoid is nearly uniform. (This is true only when
the length of the solenoid is large compared to its
diameter). The solenoid is the classic device for
generating a magnetic field. It is the analog of the
parallel plate capacitor, which is the classic device
for generating a uniform electric field throughout a
given volume. Magnetic fields of a specific shape can
be generated by a system of coils.
Solenoid Permanent MagnetFigure 3
4
y
x
RR R
R
I I
Figure 4 Helmholtz Coil
Two parallel coils separated by a distance equal to the
radius of the coils (Figure 4 ) are known as Helmholtz
coils. They are frequently used because they generate a
magnetic field that is uniform over an appreciable
region about its midpoint. We will be using a system of
Helmholtz coils to carry out this lab's experiment. If
each one of the coils, with radius R, has N turns and
carries a current I, then the field at the center of
the system is,
Helmholtz Coils BC = .714 µo N IR
(2)
The following table explains all of the symbols in
equation (2).
Quantity Units
[Bc] Tesla = 104 Gauss = NA m
mo (permeability constant) = 4 π x 10-7 Tesla mA
= 4 π x 10-7 V mA sec
[R] meters (m)
[I] amps (A)
[N] number of turns in coil
Let us now look at the force exerted by a magnetic field B→ on a moving charged
particle. It was the American physicist H. A. Rowland who first observed that a
particle with charge q and velocity v→ moving in a magnetic field B
→ will be
subjected to a force F→. The direction of this force is perpendicular to the
velocity v→ and to B
→. If a particle enters a volume with both an electric field E
→
and a magnetic field B→ then the total force on the particle is given by the Lorentz
law.
Lorentz Law F→ = q E
→ + q ( v
→ x B
→) (3)
This is an extremely important relation, connecting mechanics (force F→) to
5
Figure 5 Right Hand Rule
Particle Orbit
Center
Guiding
F
F F
F
r = mv/qB
B-field is uniform into page
Figure 6 Motion of ChargedParticles in a Magnetic Field
electromagnetism (the fields E→ and B
→). The
magnetic force is the cross product of two
vectors. Figure 5 reminds you once more of
the "right-hand rule" which is defined for
positive charge. You must be familiar with
this rule in order to carry out this
experiment.
As mentioned in the introduction, in this
experiment we will observe the deflection of
electrons in a magnetic field. To simplify
the experiment we will choose the direction
of the electron beam ( v→) to be perpendicular
to B→. In this case the force acting on the
electrons (charge q) is simply,
| |F→mag = q | |v→ | |B→ or Fmag = qvB (4)
According to the right-hand rule, F→mag is
perpendicular to v→ and consequently the
electrons would move in a circle as shown
in Figure 6, if they had a positive
charge. Since they have a negative charge,
the electrons will actually rotate in the
opposite direction from that shown in the
figure. (Remember from mechanics: if a→ ⊥
v→ then it must be a circular motion). The
centrifugal force responsible for
describing a circular motion is given by:
Fcenter =mv2
r(5)
6
Observed Field Hypothetical Magnet Current Loop Inside Earth
Figure 7
By equating Egs. 3 and 4
Fcenter = Fmag(6)
mv2
r = qvB
we can calculate the radius of curvature of the circular motion of a charged
particle moving perpendicularly to a magnetic field:
r = mq vB (7)
This simple relation is the basic equation that we will use to carry out the
measurement of e/m. By measuring the radius of curvature r, of an electron beam of
known velocity v→, deflected by a magnetic field B
→, we can calculate the ratio q/m.
Before we describe how to do this experiment, there is one last topic to cover: the
earth's magnetic field! This field will have an effect on our electron beam, hence
we must properly take account of it - otherwise, our measurement of e/m will be
wrong.
THE EARTH'S MAGNETIC FIELD
The earth's magnetic field is the field of a magnetic dipole, which means that it is
equivalent to the external field of a huge bar magnet. The lines of force of such a
field are directed not towards the geographic poles but rather towards the magnetic
7
B
e-
Helmholtz Coils
Electron Gun
Glass Enclosurewith Low PressureMercury
Figure 8 e/m Experiment Setup - Main Aparatus
poles (The magnetic north
pole is located near the
geographic south pole.)
They are also directed
(except at the equator)
towards or away from the
center of the earth - as
shown in Figure 7.
The intensity of the field
at the surface is on the
order of one Gauss.
Sediments of magnetic
materials (iron, cobalt,
nickel) can drastically
change the local pattern of this field which has been carefully mapped, most
recently with the use of satellites. After centuries of research, the earth's
magnetic field remains one of the best described and least understood of all
planetary phenomena. The history of the earth's magnetic field has been traced back
3.6 million years, and it has been established that during this time the earth's
field has reversed nine times. To establish such a fact two elements were necessary:
the magnetic "memory" of volcanic rocks, together with the presence in the same
rocks of atomic clocks that begin to run just when their magnetism is acquired. The
memory elements themselves are magnetic "domains", tiny bodies in which magnetism is
uniform. These bodies consist of iron and titanium oxide. At temperatures above a
few hundred degrees (depending upon the chemical composition) these domains are
nonmagnetic. When a domain cools it becomes magnetized in the direction of the
surrounding magnetic field. The atomic clocks that record the time of the lava
solidification are based on the radioactive decay of potassium 40 into argon 40.
This decay (transformation of potassium into argon) takes place at a constant rate
similar to the decay rate of an RC circuit (see second lab). The argon is trapped
within the crystal structure of the minerals, and if the minerals are not heated or
changed in some way, it accumulates there. The amount of trapped argon is a function
of the amount of potassium present, and the length of time since the decay and
entrapment process began. The potassium-argon dating method has now been
successfully applied to rocks from nearly 100 magnetized volcanic formations, with
ages ranging from the present back to 3.6 million years; nine earth magnetic field
reversals were observed during this time. You should not worry about the earth's
8
Accelerating Voltage
E
GridFilament
e
e Beam
Figure 9 Electron Gun
magnetic field changing during your experiment; the data of volcanic rocks shows
thaw it takes about 5000 years for a
field reversal to take place. You must,
however, be aware that there is an earth
magnetic field B→
E which affects this
experiment.
EXPERIMENT 1
Measure the ratio of the electron's
charge to the electron's mass in
Coulomb/kg.
As described above, the basic relation for this measurement is given by Eq. 7:
r = mq vB
(7)
This relation tells us that in carrying out the measurement of e/m we need three
basic elements:
1) a beam of electrons with known velocity v→.
2) a magnetic field (uniform over the region where the electrons will
describe a circular trajectory).
3) a way to observe the electron's path, so that we can measure the radius of
curvature.
Figure 8 shows a schematic drawing of the equipment used to measure e/m.
THE ELECTRON GUN
We generate a beam of electrons with an electron gun, very similar to the one
described in the 2nd lab for the CRT. It is shown schematically in Figure 9. The
electrons are accelerated to a final velocity v→, such that their kinetic energy is
equal to the work done by the accelerating potential V:
mv2
2 = qV
Electron velocity: v = (2 qm V)1/2 (8)
9
mAA V
e
0.5m
Glass Bulb
Axis of Rotation
Pins
Electron Gun
Electron Orbit
Power Supply
Helmholtz Coils
Field Filament
Anode
Figure 10 e/m Experiment Setup
B
B
E
C
Axis of Helmholtz Coils
Figure 11Alignment of e/m Apparatus withEarth's Magnetic Field
Figure 10 shows a view of the electrical connections for the equipment used.
The electron gun is controlled by 2 knobs. The "ANODE" knob, which sets the
accelerating potential, and the "FILAMENT" knob, which sets the current in the
filament, thereby controlling the
electron beam current Ianode.
THE MAGNETIC FIELD
The magnetic field is generated by
a set of Helmholtz coils. Formula
1 gives the value of the field at
the center of the system. The
number of turns for each coil is N
= 72. With a ruler, you can
measure the radius of the coils or
the distance between them, and
then calculate the value of B→.
The magnetic field is aligned
along the axis of the coil system
(see Figure 11), and its direction is determined by the "right-hand rule" (see Fig.
2). As mentioned previously, the earth also has a magnetic field, which cannot be
neglected in this experiment. Each apparatus
has been individually aligned, with the help
of a compass needle, in such a way that B→C
of the coil is in the same direction as B→E
of the earth (see Fig. 11).
Consequently, the magnetic field BT that
will deflect the electrons is:
B→T = B
→E ± B
→C (9)
where the ± sign depends upon the direction
of the current in the coil. The knob labeled
"FIELD", on the power supply (see Fig. 10),
will allow you to vary the strength of B→C,
1 0
while the meter above the knob gives a reading of the current I through both coils.
ELECTRON TRAJECTORY
Electrons are infinitesimally small objects (radius < 10-16cm) that cannot be seen
by the naked eye. In order to observe their trajectory without blocking their path,
the electron gun is installed in a glass enclosure (25 cm diameter) which contains
low pressure mercury (Hg) gas. The electrons (with 50 eV K.E.) will excite the Hg
atoms (requiring 2 eV) which then emit a blue light. The electron trajectory can be
observed (in a darkened room) as a ring of blue light. The glass bulb also contains,
along one of its diameters, a set of pins. The distances from the anode slit of the
electron gun are:
.065 m, .078 m, .090 m, .103 m and .115 m.
Some of these pins are still covered with a fluorescent material which emits light
when struck by the electron beam.
By varying the "FIELD" control knob you change the current I in the Helmholtz coils,
producing different values of B→C, and forcing the electrons to describe different
orbits. Certain values of B→C will allow the electron beam to strike the calibrated
pins. Knowing B→C and the radius of the electron beam will allow you to determine
e/m, provided the accelerating potential is known. The equations summarized below
are used in calculating e/m.
Eq.(7) r = mq vB
Eq.(8) v = (2 qm V)1/2
Eq.(9) B→T = B
→E ± B
→C
We can combine these equations and write,
B→C =
1r √2V mq ± B
→E
In this equation there are two unknowns: (q/m) and B→E. It will require a minimum of
two measurements (r1 and r2 for values of B→
Cl and B→C2) to determine both. The
measurement will be carried out by varying B→C, measuring r and plotting B
→C (
1r)
(i.e. B→C on the vertical axis and (
1r) on the horizontal). The data must fit a
1 1
straight lines with:
Intercept = ± BE
Slope = √2V mqor
em = 2V
(Slope)2(7)
Make a linear-least-squares fit to the data and calculate the half thickness. This
may be easily performed using MatLab or with some calculators. You can check out Dr
Erlenmeyer's Least-Squares fit web page and the corresponding Theory page for more
details. The measurement will be done for both orientations of BC: one with BT = BE
+ BC and one with BT = BE - BC
PROCEDURE
Measure the diameter of the Helmholtz coils with the meter stick. To calculate the
magnetic field of the center of the coils you need, according to Eq. 2, the radius
R. the number of windings N = 72, as seen in Fig. 4.2, and the current in
each coil.
BC = .714 (µo N / R) I (2)
Express this equation as BC = constant x I, and calculate the value of the constant
as well as its units, using mo = 4p x 10-7 Tesla meter/Amp.
The equipment is wired up according to the diagram in Figure l0.
(1) Turn both "FIELD" and "FILAMENT" controls fully counterclockwise, before
turning the power switch either ON or OFF.
(2) Switch the power supply ON.
(3) Turn the "ANODE" so that the meter directly above reads 50V anode voltage.
(4) Use the "FILAMENT" control to increase the filament current slowly, until
the center meter reads about .8 mA. This meter indicates the anode current
between the filament and anode; it should not exceed 1.0 mA. The anode current
may drift (as the equipment warms up) over the first 15 minutes, changing the
anode voltage. If necessary, reset the controls to keep the filament current at
.8 mA and the anode voltage at 50V. You are now ready to start the experiment
if the room is darkened. If the small lamp is properly placed on top of the
power supply, it illuminates the meters and also gives enough light for you to
1 2
write in your notebook. Stand on a lowered stool, if necessary, so that you can
look down into the tube. You should see the electron beam as a thin blue line
emerging from the anode slit. If necessary, rotate the tube on its axis so that
the electrons move towards your right as you look down. Increase the coil
current using the FIELD control and you should see the electron beam bend into
a circle. If the beam bends the wrong way, turn the FIELD control fully
counterclockwise, reducing the coil current to zero, and interchanse the lead
at the power supply connections. If the electron beam does not stay flat in a
circle, rotate the glass tube slightly on its axis until the electron beam
forms a flat circle.
Your equipment is now ready to take data.
* Vary the current in the Helmholtz coils (FIELD knob) until the outer edge of the
electron beam matches the outer edge of each pin in the tube.
* Record in your labbook the coil current settings for each measurement
corresponding to an electron orbit of radius r. The distances from the anode to
the pins (the diameter of the electron orbit) are
.065 m, .078 m, .090 m, .103 m, and .115 m.
* Calculate the field B→C using Eq. 2.
* Plot B→C as a function of 1/r.
* Rotate the glass tube 180° on its axis, reduce the coil current to zero, and
interchange the leads at the power supply. The electron beam now moves towards
your left as you look down. Obtain a new set of current values for matching the
outer edge of the electron beam to the outer edges of the pins in the tube. Make
a second plot of B→C as a function of 1/r. Your partner should repeat the above
measurements with an anode voltage of 60 volts.
Your writeup should include a plot of B→
C vs. (1/r) for both measurements. In
addition: Calculate e/m in Coul/kg for each slope measurement (beam clockwise and
counterclockwise), and also give the average value and the percentage error. Show
that the dimensions of the relation you are using to calculate e/m (Eq. 9) are
indeed Coul/kg. An important relation that allows you to relate units of mechanics,
such as kg, m, sec. to units of electricity-and magnetism, such as A, V, is the
following energy relation.
Joule = N m = Kg m2
sec2 = AVS = Coul V
1 3
* Calculate the earth's magnetic field B→E (in Gauss) at the location of your e/m
apparatus, this is given by the intercept of the line fitted through your data
points and the BC axis. Sketch for both measurements:
1) the direction of the electron beam.
2) the direction of the centripetal force and the Lorentz force acting on the
electron beam.
3) the direction of the current in the Helmholtz coils.
4) the direction of the field B→C.
Indicate if it was the measurement with (BE + BC) or with (BE - BC).
* The beam of electrons also represents a current and consequently must generate a
magnetic field B→
E. Does this field point in the same or in the opposite
direction as the field generated by the Helmholtz coils? Remember that an
electric current is defined for positive charge carriers.
EXPERIMENT 2
Each one of your setups has a permanent magnetic bar. One end of the bar has a
colored tape collar. By observing the motion of the electron beam in the magnetic
field of the permanent magnet, determine if the end with the colored collar is the
north or the south pole. Enter in your lab notebook the color of your permanent
magnet and its polarity. For A-2O, A-25 and A-90 students: Choose any point in the
vicinity of the bar magnet, and with the equipment you have, determine the intensity
of the field at this point.
Observe that the electron bean describes a spiral traiectory when the velocity
vector is not perpendicular to the field B→
C of the coils. (It may be useful to
reduce the velocity of the electrons). If the electron velocity
vector v is represented by a component parallel to B→C ( v
→||) and one component
perpendicular to B→C ( v
→⊥ ), which one of these two components will contribute to
the circular motion of the beam, and which one will simply describe a translational
motion?
1 4
How does the radius of the spiral motion depend upon the angle θ between v→
and B→C?
Sections of this writeup were taken from:
The Feynman Lectures on Physics, Vol. II, Feynman, Leighton, Sands/Addison-Wesley
Physics, J. Orear/MacMillan