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8/12/2019 Railway Curves 8
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TransitionCurve
ShiftedCircularCurve
OriginalCircularCurve
TC
CT
Figure 3.5
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( ) 180 / 2R*L tcir = 180 / 756.53*825*=
)6 /(2
RL x= )RL6 / x(tan 21=
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1000
15
200
3
100
1
200
)1(
100
1===
=
Figure 3.6
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2001
100
o
MA
N B S TC
M N B ST
1 2
1 2
LKCH =970.00
RL = 99.70
CH =1030.00RL = 99.85
CH =1000.00RL = 100.00
Figure 3.7
m60
1000
15x4000 ==
22tan
R R =
m x x 30
2
1
1000
154000 ==
m70.99
100
30100RL A ==
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m85.99
200
30100RL B ==
m1125.04000x8 / 60R8
CBB 2
2
===
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725.991
6
)70.9985.99(70.99 =
+
75.992
6
)70.998.99(70.99 =
+
775.9936
)70.9985.99(70.99 =
+
.9946
)70.9985.99(70.99 =
+
825.995
6
)70.9985.99(70.99 =
+
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APEX DISTANCE
OPTION I (Min. Radiuscomputed)
OPTION II
OPTIMUMOPTION
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OLD BRIDGE
NEW BRIDGE
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City A
City C
City B
Curves introducedfor taking thealignment topopulation centeri.e. city C
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I
R
R
T 1
TL
Figure 4.5
T 2
CL/2 CL/2
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RL x y
6
3
=
= RL x
x y
6
2
=
R L
RL L
t 66
2
==
R L
RL L
t 22
2
==
3
t
t =
)2(
3602
t
RCCL =
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22
tan)( L
S R +
+
22
tan)( LS R ++
R x2
21
1 = .......................
R2x
,R2
x 2323
22
12 +=+=
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c R
*2
360
=
11 *2360
c R
=
onsoand c
Rc
R 323212*
2360
;*2360
+=+=
CCL*R2
360i
=
I
I
ST
1
X
2
X
I
x1 x2
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t *2360
t *2
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ST
t
Figure 4.8
TC
Tangent at TC
t
360 0 - t 1
2
c2c1 t
I
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