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Quiz 2.2A 1. - Wikispaces - kolczynskikolczynski.cmswiki.wikispaces.net/file/view/quiz+solutions+2.2.pdf · Quiz 2.2B 1. (a) See graph below, left. (b) 853 is 3 standard deviations

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Page 1: Quiz 2.2A 1. - Wikispaces - kolczynskikolczynski.cmswiki.wikispaces.net/file/view/quiz+solutions+2.2.pdf · Quiz 2.2B 1. (a) See graph below, left. (b) 853 is 3 standard deviations

© 2011 BFW Publishers The Practice of Statistics, 4/e- Chapter 2 89

Quiz 2.2A

1. (a) See graph below, left. (b) 48.7 is 3 standard deviations below 63.1, so 99.7/2 or 49.85%

or the scores are between 63.1 and 48.7. 67.9 is 1 standard deviation above the mean, so 68/2 or

34% of the scores are between 63.1 and 67.9. Thus 49.85 + 34 = 83.85% of the scores are

between 48.7 and 67.9. (c) z-score for 60 is 60 63.1

0.654.8

, which (by Table A) has a

percentile of 0.2578, so about 26% of the runners have weights below 60 kg. (d) z-score for 70

is 70 63.1

1.444.8

, which (by Table A) has 1 – .9251 = 0.0749 or about 7.5% of the scores

above it. (e) The 45th

percentile corresponds to z = – 0.13. This corresponds to a weight of

–0.13(4.8) + 63.1 = 62.476 kg. So about 45% of the runners have weights below 62.5 kg.

2. (a) Proportion = 0.7340. See graph below, right. b) z = 0.44. 3. The normal probability plot

is roughly linear, so the distribution of lactic acid in the cheese samples is approximately

Normal.

Quiz

2.2B

1. (a) See graph below, left. (b) 853 is 3 standard deviations above 544, so 99.7/2 or 49.85% or

the scores are between 544 and 853. 338 is 2 standard deviations below the 544, so 95/2 or

47.5% of the scores are between 338 and 544. Thus 49.85 + 47.5 = 97.35% of the scores are

between 338 and 853. (c) z-score for 500 is 500 544

0.43103

, which (by Table A) has 0.3336

or 33.36% of the scores below it. (d) z-score for 800 is 800 544

2.49103

, which (by Table A)

has 1 – .9936 = 0.0064 or 0.64% of the scores above it. e) The 34th

percentile corresponds to

z = – 0.41. This corresponds to a score of – 0.41(103) + 544 = 502. So about 34% of the

applicants have GRE scores below 502. 2. (a) Proportion = 0.3027. See graph below, right.

(b) z = 0.77. 3. The normal probability plot is roughly linear, so the distribution of squirrel

weights is approximately Normal. (Some students may argue that there is slight skew to the

right, based on the lowest two or three values for squirrel weight.)

80757065605550

Body Weight, kg

Z

-1.51

0.734

0.840

900800700600500400300200

GRE Score Z0.51

0.303

2.840