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µåÔåêÅÜÝ ‘ ÜÈåëôåÄð µåâÿå ’åÄåÆ µå „Ôåï½¾²ìåêê † ÇÈåÐ×ðÆ ÇÈåíúÜݾ’ð²ìåê àÒÊ·æ µåÁµåÑ–Ó ÔåêêÁ™ÐÜÈåÑÉ°±Áµð.

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Register Number

41-A

41

41 (2 - A)

1. ÇÈðîÐé¯æÄó Äå ‡â–’ð-ÁµåÐÔåϲµæØ

(a) 1

(b) 1.6725 × 10–27 kg

(c) 9.1072 × 10–31 kg

(d) 1.6750 × 10–27 kg

2. ’å’ðÛ²ìåê ×哾²ìåêê ____ ÄåêÆ ƒÔåÑÒÊ–Üݲµåê¼å¾Áµð.

(a) ’å’ðÛ²ìåê „’æ²µå (b) ŠÑð’æ±øÄóÄå ½²µåê µåêÕ’ð (c) ßð¡¢Äå ×哾²ìåêÑ–Ó …¼å²µå ŠÑð’æ±øÄó

˜µåâÿå ‡ÇÈåÜÝÀ½

(d) ’å ™Ôðê ×哾²ìåêÑ–Ó …¼å²µå ŠÑð’æ±øÄó ˜µåâÿå ‡ÇÈåÜÝÀ½

3. ²ìåìæÔåíúÁµðé ˜µåêÒÇÝÄåÑ–Ó ÔðêéÑ–ÅÒÁµå ’ðâÿå µð ôåÑ–ÜÈåêÔæ˜µå ƒ¸êÕÄå ½Ð¦Ï˜µåâÿåê ßðô梘µåê¼å¾Ôð ’æ²µå ÔðéÄðÒÁµå²µð

(a) §ÒÁµåê ˜µåêÒÇÝÄåÑ–Ó ’ðâÿå µð ôåÑ–ÜÝÁµæ µå ÇÈåÐÁ·µæÄå ’ðëé×嘵åâÿå ÜÈåÒ•ÿðϲìåêê ßðôåꢼå¾Áµð Ôåê¼åê¾ …Áµå²™ÒÁµå ƒ¸êÕÄå ˜µæ¼åÐ ßðôåꢼå¾Áµð, à阵昙 ƒ¸êÕÄå ½Ð¦Ï˜µåâÿåê ßðôåꢼå¾Áµð.

(b) ƒ²ìåìæÅé’å²µå ×哾²ìåêê ˜µåêÒÇÈåÄåêÆ ’å ™Ôðê Ôåìæ´µåê¼å¾Áµð à阵昙 ƒ¸êÕÄå µæ¼åÐ ßðô梘™ ƒ¸ê˜µåâÿå ½Ð¦Ï˜µåâÿåê ßðô梘µåê¼å¾Áµð.

(c) ŠÑð’æ±øÄó „’åÚÈ夸 ÊÑÔåíú ˜µåêÒÇÈåÄåêÆ ’å ™Ôðê Ôåìæ´µåê¼å¾Áµð Ôåê¼åê¾ ƒ¸êÕÄå ˜µæ¼åÐÔåÄåêÆ ßð¡¢ÜÈåê¼å¾Áµð Ôåê¼åê¾ à阵昙 ƒ¸êÕÄå ½Ð¦Ï˜µåâÿåê ßðôåꢼå¾Ôð.

(d) ˜µåêÒÇÝÄåÑ–Ó ’ðâÿ嘵ð ôåÑ–ÜÈåêÔ昵å, ƒ¸ê˜µæ¼åÐ ßðô梘µåêÔåíúÁµå²™ÒÁµå ÇÈåÐÁ·µæÄå ’ðëé×å ˜µåâÿå ×哾 ßðô梘µåê¼å¾Áµð. …Áµå²™ÒÁµæ ™ ƒ¸êÕÄå ˜µæ¼åÐ ßðô梘µåê¼å¾Áµð.

4. §ÒÁµåê H2O ƒ¸ê sp3 ßðñʖдµðñ¦ÿðéÚÈåÄó ÜÝÀ½˜µð §âÿåÇÈå®±²µð, VSPER (Valence Shell

Electron Repulsion) ÜÝÁµæÂÃÒ¼å „Á·µæ²µåÁµå ÔðêéÑ𠃸êÕÄå ¦ÿæÏÕê½ _____.

(a) ²µðé•ÿæ¼åÍ’å (b) ½Ð’ðëéÅé²ìåê

(c) ôå¼åê‘ÚÈæÉ×åÖ¤ (d) ÜÈð”þÖé²µó ÇÈæÓÄå²µó

5. Zn2+ ƒ²ìåìæÄå꘵åâÿåê Ê »ÕÑÓÁµåÔåíú, Cu2+

ƒ²ìåìæÄå꘵åâÿåê Ê » ßðëÒÁ™Ôð, ‹’ðÒÁµå²µð,

(a) Cu2+ ƒ²ìåìæÄå꘵åâÿåê Áµåðëšéôå²µå ÇÈåÐÁµðé×åÁµåÑ–Ó ×哾²ìåêÄåêÆ àé²™ ’ðëâÿåêä¼å¾Áµð Ôåê¼åê¾ Ê »Á™ÒÁµå ˜µðëéôå²™ÜÈåê¼å¾Áµð,

Zn2+ „²ìåìæÄå꘵åâÿåê Áµåðëšéôå²µå ÇÈåÐÁµðé×åÁµåÑ–Ó ×哾²ìåêÄåêÆ àé²™ ’ðëâÿåêäÔåíúÁ™ÑÓ, àé˜µæ ™ ƒÁµåê Ô帤²µåà¼åÔæ ™ ˜µðëéôå²™ÜÈåê¼å¾Áµð.

(b) Cu2+ ƒ²ìåìæÄåê µåâÿåê ¼åÔåêÍ ÔðêéÑð Ê–Áµå Êðâÿå“Äå ×哾²ìåêÄåêÆ àé²™’ðëâÿåêä¼å¾Áµð Ôåê¼åê¾ Ô庤é²ìåêÔæ ™ ’æ¸ê¼å¾Áµð,

Zn2+ ¼åÄåÆ ÔðêéÑð Ê–Áµå Êðâÿå’åÄåêÆ ßæÁµåê ßðëé µåÑê Ê– µåê¼å¾Áµð àé µæ ™ ƒÁµåê Ôå ¤ ²µåà¼åÔæ ™ ’æ¸ê¼å¾Áµð.

(c) Cu2+ ƒ²ìåìæÄåê µåâÿåê ™- ™ ÜÈæ µå¹ð ¼å²µåÑê ÜÈæ’æ µåêÔåÚÈåê± ×哾²ìåêÄåêÆ àé²™ ’ðëâÿåêä¼å¾Ôð Ôåê¼åê¾ Ô庤é²ìåêÔæ ™

’æ¸ê¼å¾Ôð, Zn2+ ™- ™ ÜÈæ µå¹ð ¼å²µåÑê ÜÈæ’æ µåÁµåÚÈåê± ×哾²ìåêÄåêÆ àé²™ ’ðëâÿåêä¼å¾Áµð àé µæ ™ Ôå ¤²µåà¼åÔæ ™ ’æ¸ê¼å¾Áµð.

(d) Cu2+ §ÒÁµåê •ÿæÑ– 3 ´™ ’å’ðÛ²ìåêÄåêÆ ßðëÒÁ™Áµð Ôåê¼åê¾ ™-´™ ÜÈæ µå¹ð ÜÈæÁ·µåùÏ.

Zn2+ÄåÑ–Ó ÇÈåÐôðëéÁµåÄð ÜÈæÁ·µåùÏÕÑÓ ‹’ðÒÁµå²µð ƒÁµåê ÜÈåÒÇÈåÔ昙 3 ™ ’å’ðÛ˜µåâÿåÄåêÆ ¼åêÒÊ–Áµð.

41 (3 - A)

1. The rest mass of proton is

(a) 1

(b) 1.6725 × 10–27 kg

(c) 9.1072 × 10–31 kg

(d) 1.6750 × 10–27 kg

2. The energy of an orbital

depends on

(a) the shape of the orbital.

(b) the spin of the electron.

(c) the presence of other electrons

in the higher energy.

(d) the presence of other electrons

in the lower energy.

3. The atomic radii increases on

moving from top to bottom in

any group – the reason being

(a) moving down in a group

the number of principal

shell increases and

therefore, the size of the

atom increases, hence

atomic radii increases.

(b) the ionization energy

decreases down the group

hence the size of the atom

increases, hence atomic

radii increases.

(c) electron affinity decreased

down the group and causes

the increase in the size of

the atom and hence atomic

radii increases.

(d) moving down in a group

the energy of principal

shell increases due to

which atomic size

increases, hence the atomic

radii increases.

4. If a H2O molecule undergoes

sp3 hybridization state the

geometry of the molecule based

on the VSPER (Valence Shell

Electron Repulsion) Theory is

(a) linear

(b) trigonal

(c) tetrahedral

(d) square planar

5. Cu2+ ions are coloured whereas

Zn2+ ions are colourless,

because

(a) Cu2+ ions absorb energy in

the visible region and

appear coloured, Zn2+ ions

do not absorb energy in the

visible region hence it

appears colourless.

(b) Cu2+ ions absorbs the light

energy that falls on it and

appears coloured, Zn2+

transmits the light energy

that falls on it hence it

appears colourless.

(c) Cu2+ ions absorb energy

which is sufficient to bring

about d-d transition and

appears coloured, Zn2+

absorbs energy which is

not sufficient to bring

about d-d transition hence

it appears colourless.

(d) Cu2+ has one vacant 3d

orbital and d-d transition is

possible. In Zn2+ there is

no excitation possible

because it has completely

filled 3d orbitals.

41 (4 - A)

6. K2Cr2O7 §ÒÁµåê ÇÈåÐÊÑ ‡¼å”ÚÈ夸 ’æ²µå’å. ÜÈåÒ’ðëéôåÄå ²µåëÇÈåÁµåÑ–Ó Cr Äå ‡¼å”ÚÈ夸 ÜÝÀ½ ‹Äåê ?

(a) Cr+1 (b) Cr+2

(c) Cr+3 (d) Cr+6

7. K4[Fe(CN)6] ÄåÑ–Ó ’åʖ̸Áµå EAN

(ÇÈå²™¹æÔåê’æ²™ ƒ¸êÜÈåÒ•ÿðÏ) ŠÚÈåê± ? (a) 35 (b) 36 (c) 54 (d) 86

8. §ÒÁµåê ÔåÜÈåê¾ÕÄå ƒ¸ê¼åë’å’ð” ÜÈåÔåêÄæ ™ Åé´µåÑÉ®± §ÒÁµåê „“Þ µðñÜÝÒ˜µó ‹¦ÿðÒ¯óÄå ÜÈåÔåìæÄåÔæÁµå ¼åë’åÔåÄåêÆ _____ ÅÒÁµå ʷ昙ÜÝ, ’åÒ´µåê à ™²ìåêÊßåêÁµåê.

(a) ÇÈåн ƒ²ìåìæÄó µð ƒÁµåê ÇÈå µðÁµåê’ðëéÒ µå ŠÑð’æ±øÄó µåâÿå ÜÈåÒ•ÿðÏ

(b) ƒÁµå²µå ‡¼å”ÚÈ夸 ÜÈåÒ•ÿðÏ (c) ÇÈåн ƒ²ìåìæÄó µð ƒÁµåê ’åâÿðÁµåê’ðëÒ µå

ŠÑð’æ±øÄó µåâÿå ÜÈåÒ•ÿðÏ (d) ƒÁµå²µå ÔðêéÑ–²µåêÔå §®ê± ‰ê¹æ¼åÍ’å „Ôðé×å

9. àéÑ–²ìåêÒÄå † ÔåêêÒÁ™Äå ˜µåê¸Á™ÒÁµæ ™ „Á·µåêÅ’å µðñÕÒ µó ‡ÇÈå’å²µå¸ÁµåÑ–Ó ÜÈæÁ·µæ²µå¸ ˜µæâ–²ìåê ÊÁµåÑ昙 80% àéÑ–²ìåêÒ Ôåê¼åê¾ 20% „ÔåêÓ¦Äå’åÁµå Õê×åиÔåÄåêÆ ÊâÿåÜÈåÑ昵åê¼å¾Áµð.

(a) ÜÈåÔåêêÁµåÐÁµå „âÿåÁµåÑ–Ó, àéÑ–²ìåêÒ ‡¼å¾Ôåê ‡Üݲµæ´µåêÕ’ð µð ÜÈåßæ²ìåê Ôåìæ´µåê¼å¾Áµð ƒÁ¿·µåÔæ Äð²µåÔ昵åê¼å¾Áµð.

(b) àéÑ–²ìåêÒ ÜÈåêÑÊ·å ÁµåßåÄåØéÑÔåÑÓ (c) ÜÈæ²µå¦Äå’åÁµåÒ¼åÑÓÁµðé §¼å¾ µå

ÁµåÑ–Ó²ìåêë ÜÈåßå àéÑ–²ìåêÒ ²µå’å¾ÁµåÑ–Ó ’岵嘵åêÔåíúÁ™ÑÓ

(d) àéÑ–²ìåêÒÄå ÇÈæÓÔå’å¼ð (¼ðéÑ–ÜÈåêÔå ×哾) ¦Ñ¦Äå’å“”Ò¼å ÜÈåÖÑÉ ÔåϼæÏÜÈå ßðëÒÁ™Áµð.

10. Åé²™Äå ÁµæÐÔå¸Áµå ÜÈæÒÁµåмð ÔåêÒ¦ê ˜µå µð¶²ìåê ÜÈæÒÁµåмð ™Ò¼å ßðôåê¢ ’æ²µå¸

(a) 0 °C ²™ÒÁµå 4 °C Ôå²µð µð ’åêÁ™ÜÝÁµæ˜µå Åé²™Äå ’å꘵åêšÕ’ð

(b) Åé²™ÄåÑ–Ó²µåêÔå ¦Ñ¦Äå’åÁµå ÊÒÁ·µå ²µåÒÁ·µåùИµåâÿåÄåêÆ ‡Ò®ê Ôåìæ µåê¼å¾Áµð.

(c) ÇÈåÐÊÑ ÜÈåßåÔðéÑðÅÞ²ìåê ÊÒÁ·µå µåâÿåê ÜÈå »Áµæ˜™²µåê¼å¾Ôð Ôåê¼åê¾ ÁµåÐÔåÜÝÀ½²ìåêÑ–Ó Åé²™Äå ƒ¸ê˜µåâÿåÄåêÆ ÜÈåÕêéÇÈå’𔠼岵åê¼å¾Ôð.

(d) Åé²™Äå ÁµæÐÔå¸Áµå ÁµåÐÔåϲµæØ ÔåêÒ¦ê˜µå µð¶²ìåê ÁµåÐÔåϲµæØ ™Ò¼åÑë ßðôåê¢.

11. † ÔåêêÒÁ™Äå ßðéâ–’ð˜µåâÿåÑ–Ó ÜÈæ²µå¦Äå’å ƒ¸êÕÄå ŠÑð’æ±øÄó˜µåâ– µð ÜÈåÒÊÒÁ·™ÜÝÁµåÒ¼ð ²ìåìæÔå ßðéâ–’ð ÜÈå²™ ?

(a) 2p ŠÑð’æ±øÄó Äå ²µðªêÇ·Èó ˜™Ò¼å 1s ŠÑð’æ±øÄó Äå ²µðªêÇ·Èó ’å ™Ôðê

(b) 2p Ôåê¼åê¾ 1s ŠÑð’æ±øÄåê µåâÿå ²µðªêÇ·Èó §ÒÁµðé.

(c) 2p ŠÑð’æ±øÄóÄå ²µðëéÁ·µå’å ÜÝÀ²µæÒ’å“”Ò¼å 1s ŠÑð’æ±øÄóÄå ²µðëéÁ·µå’å ÜÝÀ²µæÒ’å ßðôåê¢

(d) 1s ŠÑð’æ±øÄóÄå ²µðëéÁ·µå’å ÜÝÀ²µæÒ’å 2s Ôåê¼åê¾ 2p ŠÑð’æ±øÄ嘵åâÿåÄåêÆ ƒÔåÑÒÊ–Üݲµåê¼å¾Áµð.

12. O2, O+

2, O–

2 Ôåê¼åê¾ O2–

2 ˜µåâÿå ÊÒÁ·µå ÊÑÁµå ÜÈå²™²ìåìæÁµå ’åÐÔåê _____

(a) O2–

2 > O–

2 > O2 > O+

2

(b) O2–

2 > O–

2 > O+

2 > O2

(c) O2 > O+

2 > O2–

2 > O–

2

(d) O+

2 > O2 > O–

2 > O2–

2

41 (5 - A)

6. K2Cr2O7 is a powerful

oxidising agent what would be

the oxidation state of Cr in the

reduced form

(a) Cr+1 (b) Cr+2

(c) Cr+3 (d) Cr+6

7. The EAN (Effective Atomic

Number) of iron in

K4[Fe(CN)6] is

(a) 35 (b) 36 (c) 54 (d) 86

8. Equivalent weight of an

oxidising agent is given by the

molecular weight of the

substance divided by

(a) The number of electrons

gained by it per ion.

(b) The oxidation number of it.

(c) The number of electrons

lost by it per ion.

(d) The total negative charge

on it.

9. The modern diving apparatus

makes use of a mixture of 80%

Helium and 20% Oxygen

instead of ordinary air because

of the following property of

Helium

(a) At that depth in the sea,

Helium assists or helps

improve breathing.

(b) Helium is non-inflammable.

(c) Unlike Nitrogen, Helium is

not soluble in blood even

under pressure.

(d) The buoyancy of Helium

has a small difference with

hydrogen.

10. The density of liquid water is

higher than that of ice due to

(a) Contraction of water when

heated between 0 °C and

4 °C.

(b) The hydrogen bonding

present in water which

causes holes.

(c) The strong covalent bonds

are shorter and bring the

water molelcules closer in

the liquid state.

(d) Mass of the liquid water is

higher than that of ice.

11. Which of the following

statements regarding the

electrons of nitrogen atom is

correct ?

(a) Zeff for a 2p electron is

less than Zeff for a 1s

electron.

(b) Zeff for 2p and 1s

electrons is the same.

(c) Screening constant for 1s

electron is greater than that

of 2p electron.

(d) Screening constant for 1s

electron depends on 2s and

2p electrons.

12. The correct sequence of bond

strength for O2, O+

2, O–

2 and O2–

2 is :

(a) O2–

2 > O–

2 > O2 > O+

2

(b) O2–

2 > O–

2 > O+

2 > O2

(c) O2 > O+

2 > O2–

2 > O–

2

(d) O+

2 > O2 > O–

2 > O2–

2

41 (6 - A)

13. ½Ð¦Ï ÇÈåÐÔåìæ¸ Å²ìåêÔåê’ð” ƒÄåêÜÈæ²µåÔæ ™ † ÔåêêÒÁ™Äå ²ìåìæÔå „²ìðê” ÜÈå²™²ìåìæ ™ ßðëÒÁµæº’ð²ìåì昙ÑÓ ?

(a) NaCl ƒÚÈå±Ôåêê•–é²ìåê (b) CsCl ›åÅé²ìåê (c) ZnS ÜÈð”þÖé²µó ÇÈðÓéÄå²µó (d) B2O3 ÇÈðÓéÄå²µó ðÐûñ˜µðëéÄåÑó

14. ’æÛ²™é²ìåê Ñðëéß嘵åâÿåê ¦Ñ²µåà¼å ƒÔðëéŲìåê ÁµæÐÔå¸ÁµåÑ–Ó ’岵嘵åê¼å¾Ôð. † ÔåêêÒÁ™ÄåÔåíú˜µåâÿåÑ–Ó ƒÔåíú˜µåâÿå ÁµæÐÔå¸Áµå ʘµð˜™Äå ²ìåìæÔå ßðéâ–’ð ŦÔåÑÓ ?

(a) ƒ²ìåìæÄó µåâÿåê ÁµæÐÔå“é’å²™ÜÈåÑæ ™²µåê¼å¾Ôð. (b) ÁµæÐÔå µåâÿåê ÅéÑ– Ê »Áµæ ™²µåê¼å¾Ôð. (c) ÁµæÐÔ帘µåâÿåê ÇÈåÐÊÑ

‡¼å”ÚÈ夸’æ²™ ‹¦ÿðҮ꘵åâÿåê (d) ÁµæÐÔ帘µåâÿåê ÕÁµåêϽ¾Äå Ôæßå’嘵åâÿåê

15. µðñÊðëé²µðéÄó Äå ²µåôåÄð²ìåêÄåêÆ ÕÔå²™ÜÈåêÔå „²ìðê” ___ (a) ŠÑæÓ ¦Ñ¦Äå’åÁµå ƒ¸ê µåâÿåê §ÒÁµåê

ÜÈåÔåê¼åÑÁµå ÔðêéÑ–²µåê¼å¾Ôð Ôåê¼åê¾ Êðëé²µæÄó ƒ¸ê µåâÿåê ƒÔåíú µåâ– µð ÜÈåÔåê¼åÑÑÒÊ Ôæ ™²µåê¼å¾Ôð.

(b) Š²µå µåë Êðëé²µæÄó ƒ¸ê˜µåâÿåê Ôåê¼åê¾ ÄæÑê” ®Õê¤ÄåÑó ¦Ñ¦Äå’åÁµå ƒ¸ê˜µåâÿåê §ÒÁµåê ÜÈåÔåê¼åÑÁµåÑ–Ó²µåê¼å¾Ôð Ôåê¼åê¾ Š²µå µåê ¦ÿðëé ™ÜÈåêÔå ¦Ñ¦Äå’åÁµå ƒ¸ê˜µåâÿåê ƒÁµå’ð” ÜÈåÔåê¼åÑ ÑÒÊÔ昙²µåê¼å¾Ôð

(c) ÄæÑê” ¦ÿðëé ™ÜÈåêÔå ¦Ñ¦Äå’åÁµå ƒ¸ê˜µåâÿåê Ôåê¼åê¾ Š²µå µåê Êðëé²µæÄó ƒ¸ê µåâÿåê §ÒÁµåê ÜÈåÔåê¼åÑÁµåÑ–Ó²µåê¼å¾Ôð Ôåê¼åê¾ Š²µå µåê ®Õê¤ÄåÑó ¦Ñ¦Äå’åÁµå ƒ¸ê˜µåâÿåê ƒÁµå’ð” ÜÈåÔåê¼åÑ Ñ²ìåêÔ昙²µåê¼å¾Ôð.

(d) ŠÑæÓ ƒ¸ê˜µåâÿåê §ÒÁµðé ÜÈåÔåê¼åÑÁµå ÔðêéÑ–²µåê¼å¾Áµð.

16. Ç·ÈåùíúÑðÓ²™Äó C60 ’åê²™¼å ÔåêêÒÁ™Äå ßðé▒𠘵åâÿåÄåêÆ ÇÈå²™ØéÑ–ÜÝ Ôåê¼åê¾ ÜÈå²™²ìåìæÁµå „²ìðꔲìåêÄåêÆ „²™ÜÝ.

1. ƒÁµåê ˜µðëéѲµåëÇÈåÁµå ¦ÿæÏÕê½²ìåêÄåêÆ §âÿå µðëÒ ™Áµð.

2. ƒÁµå²µå ¦ÿæÏÕê½²ìåêê µæÐÇ·Èðñ®ÄåêÆ ßðëéÑê¼å¾Áµð.

3. ×æ•’ð” ÜÈåÒÊÒÁ·™ÜÝÁµåÒ¼ð ƒÁµåê µæÐÇ·Èðñ¯ó ™Ò¼åÑë ßðôåê¢ ÜÝÀ²µå¼ð ßðëÒÁ™Áµð.

4. ×æ•’ð” ÜÈåÒÊÒÁ·™ÜÝÁµåÒ¼ð ƒÁµåê Ôå¦Ð“”Ò¼åÑë ’å ™Ôðê ÜÝÀ²µå¼ð ßðëÒÁ™Áµð.

Codes :

(a) 1 Ôåê¼åê¾ 2 ÜÈå²™²ìåì昙Áµð

(b) 2 Ôåê¼åê¾ 3 ÜÈå²™²ìåì昙Áµð

(c) 1 Ôåê¼åê¾ 3 ÜÈå²™²ìåì昙Áµð

(d) 1 Ôåê¼åê¾ 4 ÜÈå²™²ìåì昙Áµð

17. ßðëÒÁ™ÜÝ Ê²µðÎê²™ : ÜÈåÒ²ìåêê’å¾ ¦ÿæÏÕê½

A. XeOF2 1. ôò’å ÇݲµåÕê´µåÑó

B. XeF4 2. Õ²µåëÇÈå µðëÒ´µå ðÐûñ˜µðëéÄåÑó

ÊðñÇݲµåÕê µåÑó

C. XeO2F2 3. ôå¼åêÚÈæÉ×åÖ¤

D. XeOF4 4. °-„’æ²µå

5. ÜÈð”þÖé²µó ÇÈðÓéÄå²µó ÜÈå²™²ìåìæÁµå ÇÈå²µæϲìåêÔåÄåêÆ „²™Üݲ™.

A B C D

(a) 4 3 2 1

(b) 4 5 2 1

(c) 1 3 5 2

(d) 2 5 3 1

41 (7 - A)

13. Which of the following options

shows mismatch according to

radius ratio rule ?

(a) NaCl Octahedral

(b) CsCl Cubic

(c) ZnS Square Planar

(d) B2O3 Planar trigonal

14. Alkali metals dissolve in

anhydrous liquid ammonia.

Which of the following

statements about their solution

is untrue ?

(a) The ions are solvated.

(b) The solutions are blue in

colour.

(c) The solutions are strong

oxidising agents.

(d) The solutions conduct

electricity.

15. The option which describes the

structure of diborane is :

(a) All hydrogen atoms lie in

one plane and the boron

atoms lie in a plane

perpendicular to it.

(b) Two boron atoms and four

terminal hydrogen atoms

lie in one plane and two

bridging hydrogen atoms

lie in a plane perpendicular

to it.

(c) Four bridging hydrogen

atoms and two boron

atoms lie in one plane and

two terminal hydrogen

atoms lie in a plane

perpendicular to it.

(d) All the atoms lie in the

same plane.

16. Consider the statements about

fullerene C60 listed below and

choose the right option.

1. It has spherical geometry.

2. It’s geometry resembles

graphite.

3. It is thermally more stable

than graphite.

4. It is thermally less stable

than diamond.

Codes :

(a) 1 and 2 are correct

(b) 2 and 3 are correct

(c) 1 and 3 are correct

(d) 1 and 4 are correct

17. Match the following :

Compound Geometry

A. XeOF2 1. Square

pyramidal

B. XeF4 2. Distorted

trigonal

bipyramidal

C. XeO2F2 3. Tetrahedral

D. XeOF4 4. T-Shaped

5. Square

planer

Choose the correct alternative

A B C D

(a) 4 3 2 1

(b) 4 5 2 1

(c) 1 3 5 2

(d) 2 5 3 1

41 (8 - A)

18. (NH4)2 [Pt(SCN)6] Äå IUPAC

ßðÜÈå²µåê

(a) ´µðñ ƒÔðëéŲìåêÒ ßð’æÞÁ¿·™²ìðëÜÝ-Äæ ðë-ÇÈæÓ°ÄåÔåìó (iv)

(b) ƒÔðëéŲìåêÒ ßð’æÞÁ¿·™²ìðëÜÝ-Äæ ðë-ŠÜÈó ÇÈæÓ°Äðé¯ó (iv)

(c) ƒÔðëéŲìåêÒ ßð’æÞÁ¿·™²ìðëÜÝ-Äæ ðë-ŠÄó ÇÈæÓ°Äðé¯ó (iv)

(d) ´µðñ ƒÔðëéŲìåêÒ ÇÈæÓ°Äðé¯ó (iv) ßð’æÞÁ¿·™²ìðëÜÝÄð¯ó

19. La, Gd Ôåê¼åê¾ Lu ¼ðëé²™ÜÈåêÔå ‡¼å”ÚÈ夸’æ²™ ÜÝÀ½˜µåâÿåê :

(a) + 3 Ôåê¼åê¾ + 4

(b) + 3

(c) + 2 Ôåê¼åê¾ + 3

(d) + 2, +3 Ôåê¼åê¾ + 4

20. † ÔåêêÒÁ™Äå Á·µæ¼å꘵åâÿå ˜µåêÒÇÝÄåÑ–Ó ²ìåêê²µðéŲìåêÒÄåҼ岵åÁµå Á·µæ¼å꘵åâÿåê ___

(a) Np, Pu, Cf, Es

(b) La, Ce, Pr, Nd

(c) Hf, Ta, W, Re

(d) Er, Tm, Yb, Lu

21. ÁµåÐÔå ƒÔðëéŲìåìæÁµåÑ–ÓÄå ²ìåêë²™²ìåìæ _____ ÄåÒ¼ð Ô彤ÜÈåê¼å¾Áµð.

(a) „ÔåêÓ

(b) ÇÈåмæÏÔåêÓ

(c) ÑÔå¸

(d) Á™ÖÇÈåмæÏÕêÓé²ìåê ÑÔå¸

22. ßæ´µó¤ Ñ–ÕéÜÈó „ÜÝ µó˜µåâÿåê † ’ðâÿå ™Äå ²ìåìæÔåíúÁµåÄåêÆ §âÿ嘵ðëÒ ™²µåê¼å¾Ôð ?

(a) ƒÁ·™’å Á·µåÄå „Ôðé×å Ôåê¼åê¾ Á·µåïÕé’å²µå¸ Ôåê¼åê¾ ‡¼å”ÚÈ夸 Ô昵åêÔåíúÁµåÄåêÆ ÜÈåêÑʷ嘵ðëâ–ÜÈåêÔåíúÁµåê

(b) ’å ™Ôðê …ÒÁ·µåÄåÁµå LUMo „Áµå²µð ÕÜÈæ¾²µå Êïßå¼ó ÇÈåÐÔåìæ¸Áµå LUMo µåê¹æÒ’å

(c) ƒÁ·™’å Á·µåÄå „Ôðé×å Ôåê¼åê¾ ÇÈåÐÊÑÔ昙 Á·µæÐÔå“é’å²™ÜÈåêÔåíúÁµåê

(d) ƒÔåíú˜µåâÿå ÔðéÑðÄóÞ ÚÈðÑóÄåÑ–Ó ŠÑð’æ±øÄó ¦ÿðëé ™

23. ÔðéÑðÄóÞ ÊÒÁ·µå ÜÝÁµæÂÃÒ¼åÁµå ƒÄåêÜÈæ²µåÔæ ™

[Ni(CN)4]2– ÜÈåғ鸤’æ” ™ † ’ðâÿå ™Äå

²ìåìæÔåíúÁµåê ÜÈå²™²ìåìæÁµåêÁµåÑÓ ?

(a) ÊâÿåÜݲµåêÔå Ñ–˜µæÒ µó ÇÈåÐÊÑÔæÁµå ’ðÛé¼åÐ Ñ– µæÒ´µó „˜™²µåêÔåíúÁµåê

(b) ÜÈåғ鸤 ÜÈåÒ²ìåêê’å¾Ôåíú ʸ»ÔåíúâÿåäÁµæ˜™²µåêÔåíúÁµåê

(c) „²ìåêÜÈæ”Ò¼å ÜÈåÖ²µåëÇÈåÁµå „Á·µæ²µåÁµå ÔðêéÑð §âÿå Ôåê¼åê¾ ßðë²µå ™Äå ’å’ðÛ²ìåêÑ–ÓÄå Ô嘙¤é’å²µå¸Ôåíú ¼åïÇݾÁµæ²ìåê’åÔæÁµåêÁµæ˜™²µåêÔåíúÁ™ÑÓ

(d) ÜÈåғ鸤Áµå EAN 34

24. Ñ–˜µæÒ´µó ƒÄåêÆ “ÐÜÈå±Ñó Ç·ÝéÑó¶ £ðéÁµåÄå 10 DQ ²µå ‹²™’ð ’åÐÔåêÁµåÑ–Ó † ’ðâÿå ™Äå ²ìåìæÔå ²™é½ ÔåÏÔåÜÈðÀ µðëâ–ÜÈåÊßåêÁµåê.

(a) Br– < I– < Co < F–

(b) I– < Br– < Cl– < Co

(c) Co < F– < I – < Br–

(d) F– < I – < Br– < Co

41 (9 - A)

18. The IUPAC name of the

complex (NH4)2 [Pt(SCN)6] is :

(a) Diammonium

hexathiocyanato platinum

(iv)

(b) Ammonium

hexathiocyanato-

S Platinate (iv)

(c) Ammonium

hexathiocyanato – N

platinate (iv)

(d) Diammonium Platinum

(iv) hexathiocyanate

19. The oxidation states exhibited

by La, Gd and Lu are :

(a) +3 and +4

(b) +3

(c) +2 and +3

(d) +2, +3 and +4

20. Transuranic elements amongst

the following set of elements

is :

(a) Np, Pu, Cf, Es

(b) La, Ce, Pr, Nd

(c) Hf, Ta, W, Re

(d) Er, Tm, Yb, Lu

21. Urea in liquid ammonia acts as :

(a) an acid

(b) a base

(c) a salt

(d) a dibasic salt

22. Hard Lewis acids have

(a) High positive charge &

easy to polarize & oxidize.

(b) Low energy LUMo but

large magnitude LUMo

coefficient.

(c) High positive charge &

strongly solvated.

(d) Electron pair in their

valence shell.

23. According to valence bond

theory which’s is not correct for

the complex [Ni(CN)4]2–

(a) Ligand used is strong field

Ligand.

(b) The complex compound is

coloured.

(c) Classification of inner &

outer orbital on the basis of

magnetic nature is not

satisfactory.

(d) EAN of the complex 34.

24. The ligand which can be

arranged in increasing order of

crystal field splitting 10 DQ as

follows.

(a) Br– < I– < Co < F–

(b) I– < Br– < Cl– < Co

(c) Co < F– < I – < Br–

(d) F– < I – < Br– < Co

41 (10 - A)

25. [Ti(H2O)6]3+ ÜÈåғ鸤ÁµåÑ–Ó “ÐÜÈå±Ñó ’ðÛé¼åÐ ÜÝÁµæÂÃÒ¼åÁµå ƒÄåêÜÈæ²µåÔ昙 † ’ðâÿå ™Äå ²ìåìæÔå ʸ» àé²™’ðëâÿåäÑÉ µåê¼å¾Áµð ?

(a) ÅéÑ–-ßåÜݲµåê (b) ’ðÒÇÈåíú

(c) ’ðÒÇÈåíú-Äðé²µåâÿð (d) ßåâÿåÁ™

26. ÔðëÁµåÑ ÜÈåÒ’åÐÔåê¸ ×ðÐéº µåâÿå Á™ÖÔðéÑðÅÞé²ìåê Ñðëéßå ƒ²ìåìæÄó ÜÝÀ²µå¼ð²ìåêê † ’ðâÿå ™Äå ²ìåìæÔåíúÔåíú „ ™²µåê¼å¾Ôð ?

(a) Fe(II) < Mn(II) < Cu(II) <

Zn(II)

(b) Mn(II) < Fe(II) < Cu(II) <

Zn(II)

(c) Mn(II) < Cu(II) < Fe(II) <

Zn(II)

(d) Zn(II) < Fe(II) < Cu(II) <

Mn(II)

27. ÁµåêϽ ÜÈåÒ×ðÓéÚÈå¹ð²ìåêÑ–Ó ’åʖ̸ÔåÄåêÆ ßðëÒÁ™²µåêÔå ÔåÜÈå꾘µåâÿåÄåêÆ † ’ðâÿ嘙Äå ²ìåìæÔå ßðÜÈå²™ÅÒÁµå ’å²µð²ìåêÑ昵åêÔåíúÁµåê ?

(a) ÇÈðîǷݤ²™Äó ÜÈåғ鸤

(b) Œ²µåÄó ÜÈåÑɲµó ÇÈðîÐé°éÄó

(c) ÇÈæÓÜÈðë±é ÜݲìåìæÅÄó

(d) ÜÈðñ ðë’ðëÐéÔåìó Ôåê¼åê¾ Ç·Èð²µð µæ“ÞÄó

28. Ñ–Á¿·™²ìåêÔåìó µðñÕêÁ¿·™Ñó’æÇÈå²µó n-ßðÇÈðî±Ñó ÊðëÐÔðêñ ™ÄðëÒÁ™ µð ¦ÿðëé ™²ìåìæÁµæ µå n-

„’ð±ûñ éÄó Áµðë²µð²ìåêê¼å¾Áµð. † ÇÈåн“вìðê²ìåêê

(a) ŠÑð’ðë±øéÇ·ÈðùîéÅ’ó ÇÈåн²ìðëé¦Äð

(b) ßðôåê¢Ôå²™ ÇÈåн“вìðê

(c) ÄåëÏ“Ó²ìðëé Ç·ÝÑ–ÜÝ’ó ÇÈåн²ìðëé¦Äð

(d) F C ÇÈåн“вìðê

29. ÇݲìåêÜÈå¤Äó Äå HSAB ÇÈå²™’åÑÉÄð²ìåê ÇÈåÐ’æ²µå, † ÔåêêÒÁ™ÄåÔåíú˜µåâ–ÒÁµå ÔðêÁµåê „ÔåêÓÔåÄåêÆ „²™Üݲ™.

(a) H+ (b) Li+

(c) Mg2+ (d) Cu+

30. [Ti(H2O)6]3+ Äå ¦Ñ–é²ìåêÁµæÐÔå¸Ôåíú _____ ’åÒ´µåê ʲµåê¼å¾Áµð.

(a) ßåÜݲµåê-ßåâÿåÁ™ ʸ»

(b) ÅéÑ– ʸ»

(c) ’ðÒÇÈåíú Ê »

(d) Äðé²µåâÿð Ê »

31. † ÔåêêÒÁ™ÄåÔåíú˜µåâÿåÑ–Ó ²ìåìæÔåíúÁµåê Ñðëéßå Õ²µåêÔå ’æʤŒå Ñòà’å ÜÈåÒ²ìåêê’å¾ ?

(a) Ñ–Á¿·™²ìåêÒ ÔðêÁ¿·µæ’ðÞûñ µó

(b) Ñ–Á¿·™²ìåêÒ ƒÜÝ ðé¯ó

(c) Ñ–Á¿·™²ìåêÒ µðñÕêÁ¿·µðñÑó Ç·ÈæÔåìæ¤Ôðêñ µó

(d) ÕêÁ¿·µðñÑó Ñ–Á¿·™²ìåêÒ

32. Ôðê®ÑðëÓÇ·ÈæǷݤ²™Äó ˜µåâÿåÑ–Ó Ç·ÈæǷݤ²™Äó ‡Ò˜µåê²µåÔåíú _____ ßðëÒÁ™²µåê¼å¾Áµð.

(a) ÜÈåÒ²ìðëé¨ÜÝÁµå Á™ÖÊÒÁ·µå˜µåâÿðëÒÁ™ µð Çݲ™ µðñÄó ÔåÏÔåÜÈðÀ˜µåâÿåê

(b) ÜÈåÒ²ìðëé¨ÜÝÁµå Á™ÖÊÒÁ·µå˜µåâÿðëÒÁ™ µð ÇݲµðëÐéÑó ÔåÏÔåÜÈðÀ˜µåâÿåê

(c) ÜÈåÒ²ìðëé¨ÜÝÁµå Á™ÖÊÒÁ·µå˜µåâÿðëÒÁ™ µð Ç·ÈåùîϲµåÄó ÔåÏÔåÜÈðÀ µåâÿåê

(d) ÜÈåÒ²ìðëé¨ÜÝÁµå Á™ÖÊÒÁ·µå˜µåâÿðëÒÁ™ µð Á¿·™²ìðëéÇÈðéÄó ÔåÏÔåÜÈðÀ˜µåâÿåê

41 (11 - A)

25. In case of the complex

[Ti(H2O)6]3+, according to

crystal field theory, which

colour is absorbed ?

(a) Blue-Green

(b) Red

(c) Red-Purple

(d) Yellow

26. The stability of divalent metal

ion of the first transition series

is

(a) Fe(II) < Mn(II) < Cu(II) <

Zn(II)

(b) Mn(II) < Fe(II) < Cu(II) <

Zn(II)

(c) Mn(II) < Cu(II) < Fe(II) <

Zn(II)

(d) Zn(II) < Fe(II) < Cu(II) <

Mn(II)

27. In photosynthesis iron

containing substances are called

(a) Porphyrin complex

(b) Iron sulphur protein

(c) Plastocyanin

(d) Cytochrome & ferredoxine

28. When lithium dimethylcopper is

coupled with n-heptylbromide,

n-octane is obtained. The above

reaction is

(a) Electrophonic substitution

(b) Addition reaction

(c) Nucleophilic substitution

(d) F C reaction

29. According to Pearson’s HSAB

concept, pick out the soft acid

from the following.

(a) H+ (b) Li+

(c) Mg2+ (d) Cu+

30. An aqueous solution of

[Ti(H2O)6]3+ appears

(a) Greenish-yellow in colour

(b) Blue in colour

(c) Red in colour

(d) Purple in colour

31. Which of the following is an

organometallic compound ?

(a) Lithium methoxide

(b) Lithium acetate

(c) Lithium dimethyl

formamide

(d) Methyl Lithium

32. In metalloporphyrins, the

porphyrin ring consists of

(a) Pyridine systems with

conjugated double bonds

(b) Pyrrole systems with

conjugated double bonds

(c) Furan systems with

conjugated double bonds

(d) Thiophene systems with

conjugated double bonds

41 (12 - A)

33. ÜÝÑ–’ðëéÄó ˜µåâÿå ²µåôåÄð²ìåêÑ–Ó † ÔåêêÒÁ™Äå ²ìåìæÔå Ôåì昵å¤ÔåÄåêÆ ƒÄåêÜÈå²™ÜÈåÑ昵åê¼å¾Áµð ?

(a) ²™²ìåìæ’å±Ò¯óÞ → ÜÝÑÄåÑó(silanal)

→ ’ðëÓé²µðëéÜÝÑðéÄóÞ → ÜÝÑ–’ðëéÄóÞ

(b) ²™²ìåìæ’å±Ò¯óÞ → ’ðëÓé²µðëéÜÝ ÑðéÄóÞ

→ ÜÝÑÄåÑó(silanal) →ÜÝÑ–’ðëéÄóÞ

(c) ²™²ìåìæ’å±Ò¯óÞ → ’ðëÓé²µðëéÜÝÑðéÄóÞ

→ ÜÝÑÄæÑóÞ (silanols) → ÜÝÑ–’ðëéÄóÞ

(d) ²™²ìåìæ’å±Ò¯óÞ → ÜÝÑÄæÑóÞ

(silanols) → ’ðëÓé²µðëéÜÝÑðéÄóÞ →

ÜÝÑ–’ðëéÄóÞ

34. ßðë²µå ŠÑð’æ±øÅ’ó ÕÄæÏÜÈåÁµðëÒÁ™ µð ÜÈåÒ’åÐÔåê¸ ÑðëéßåÔåíú ¼ðëé²™ÜÈåêÔå ƒ¼åÏÁ·™’å ƒ²ìåêÜÈæ”Ò½é²ìåê ÇÈåÐÔåï½¾ _____

(a) 3d2 (b) 3d5

(c) 3d7 (d) 3d9

35. ÔåêÄåêÚÈåϲµåÑ–Ó, §ÒÁµåê ÅÁ™¤ÚÈå± ƒÒ×åÁµå ƒÜÈåÔåê¼ðëéÑÄåÔåíú “²™’ð¯óÞ” ’æÎêÑð ²ìåêÄåêÆ ‡Ò®ê Ôåìæ´µåê¼å¾Áµð. „ ƒÒ×åÔåíú _____

(a) ÔåÄå ™²ìåêÒ (b) ÜÈðëé´™²ìåêÒ

(c) ’æÏÑ–Þ²ìåêÒ (d) ÇÈðî¯æÏزìåêÒ

36. ’æʤÄó, ’æʤÄó ÊæÒ µó ‡ÁµåÂÔåíú µå²™ÚÈå³Ôæ ™²µåêÔåíúÁµåê

(a) HC ≡ CH

(b) CH2 = CH2

(c) CH3 – CH3

(d)

37. ˜™ÓÜÈå²µæÑ–¶ßðñ µó ÄåÑ–Ó † ’ðâÿå ™Äå ²ìåìæÔåíúÁµåê R Ôåê¼åê¾ S ÄðëéÚÈåÄó˜µæ˜™ „ÁµåÏ¼æ ’åÐÔåêÔ昙Áµð ?

(a) – CH2OH > – CHO > –

OH > H

(b) – OH > – CH2OH > –

CHO > H

(c) – OH > – CHO > –

CH2OH > H

(d) – CH2OH > – OH > –

CHO > H

38. † ’ðâÿå ™Äå ²ìåìæÔåíúÁµåê ‘Z’ ŒÜÈðëéÔåê²µó „˜™Áµð ?

(a)

CH3

H

(

'C = C

'

(

Cl

CH3

(b)

CH3

H

(

'C = C

'

(

CH3

Cl

(c)

CH3

H

(

'C = C

'

(

CH3

CCl3

(d)

CH3

H

(

'C = C

'

(

H

CH3

39. (CH3)3 C – CH = CH2 ²µå ÜÈå²™²ìåìæÁµå IUPAC ßðÜÈå²µåÄåêÆ „²ìðê” Ôåìæ´™.

(a) 2, 2-´µðñÕêÁ¿·µðñÑó-3 – ÊëÏ°éÄó

(b) 3, 3-´µðñÕêÁ¿·µðñÑó -1- ÊëÏ°éÄó

(c) 1, 1, 1- ðÐûñÕêÁ¿·µðñÑó-2- ÇÈðîÐÇÝéÄó

(d) 3, 3, 3- ðÐûñÕêÁ¿·µðñÑó -2- ÇÈðîÐÇÝéÄó

41 (13 - A)

33. Which one of the following

pathway is followed for the

formation of silicones ?

(a) Reactants → silanal →

chlorosilanes → silicones

(b) Reactants → chlorosilanes

→ silanals → silicones

(c) Reactants →

cholorosilanes → silanols

→ silicones

(d) Reactants → silanols →

chlorosilanes → silicones

34. The highest magnetic moment

is shown by the transition metal

with outer electronic

configuration

(a) 3d2 (b) 3d5

(c) 3d7 (d) 3d9

35. An imbalance of a particular

element in humans, causes the

disease “Rickets”. The element is

(a) Vanadium (b) Sodium

(c) Calcium (d) Potassium

36. The Carbon-Carbon bond length

is maximum in

(a) HC ≡ CH

(b) CH2 = CH2

(c) CH3 – CH3

(d)

37. In glyceraldehyde, The order of

priority for R and S notation is

(a) – CH2OH > – CHO > –

OH > H

(b) – OH > – CH2OH > –

CHO > H

(c) – OH > – CHO > –

CH2OH > H

(d) – CH2OH > – OH > –

CHO > H

38. Which of the following is a ‘Z’

isomer ?

(a)

CH3

H

(

'C = C

'

(

Cl

CH3

(b)

CH3

H

(

'C = C

'

(

CH3

Cl

(c)

CH3

H

(

'C = C

'

(

CH3

CCl3

(d)

CH3

H

(

'C = C

'

(

H

CH3

39. Choose the correct IUPAC

name for (CH3)3 C – CH = CH2

(a) 2, 2-dimethyl-3 – butene

(b) 3, 3-dimethyl-1-butene

(c) 1, 1, 1-trimethyl-2- propene

(d) 3, 3, 3-trimethyl-2-propene

41 (14 - A)

40. † ’ðâÿå’åÒ´µå ÇÈåн“вìðê²ìåê ßðÜÈå²µåê ½â–ÜÝ.

CH2 = CH – CH = CH2 +

(a) ÇÈæÑ–Ôðê²µðñÜÈðéÚÈåÄó

(b) ßæÇ·ÈóÔåêÄó ŠÑ–ÕêÄðéÚÈåÄó

(c) ´µðñ²ìåêÑóÞ „Ѷòµó ÇÈåн“вìðê

(d) ’ðëé²™ ßòÜÈó ÇÈåн“вìðê

41. „²µðëéÔåìæÏ°ÜÝ°²ìåêÄåêÆ ¼ðëé²™ÜÈåêÔå ²µåôåÄð µåâÿåÄåêÆ ÇÈå°±Ôåìæ´™.

(a) (i), (iii) (b) (iii), (iv)

(c) (ii), (iii) (d) (ii), (iv)

42. † ’ðâÿå ™Äå ²ìåìæÔåíúÁµåê SN2 ÇÈåн“вìðê µåâÿåÑ–ÓÄå „Ñó’ðñÑó ßæÑðñ µóÞÄå ÜÈåÒÊÒÁ·µæ¼åÍ’å ÇÈåн“вìåìæ¼åÍ’å¼ð ’åÐÔåêÔæ ™Áµð.

(a) ðÚݤ²ìåê²™ ßæÑðñ µóÞ > Á™Ö½é²ìåê ßæÑðñ´µóÞ > ÇÈæÐÁ¿·µåÕê’å ßæÑðñ µóÞ >

ÕêÁ¿·µðñÑó ßæÑðñ µóÞ

(b) ÕêÁ¿·µðñÑó ßæÑðñ µóÞ > ÇÈæÐÁ¿·µåÕê’å ßæÑðñ´µóÞ > Á™Ö½é²ìåê ßæÑðñ µóÞ >

ðÚݤ²ìåê²™ ßæÑðñ µóÞ

(c) ÇÈæÐÁ¿·µåÕê’å ßæÑðñ µóÞ > ðÚݤ²ìåê²™ ßæÑðñ´µóÞ > Á™Ö½é²ìåê ßæÑðñ µóÞ >

ÕêÁ¿·µðñÑó ßæÑðñ µóÞ

(d) ÇÈæÐÁ¿·µåÕê’å ßæÑðñ µóÞ > Á™Ö½é²ìåê ßæÑðñ´µóÞ > ÕêÁ¿·µðñÑó ßæÑðñ µóÞ >

ðÚݤ²ìåê²™ ßæÑðñ µóÞ

43. † ’ðâÿå ™ÄåÔåíú µåâÿåÑ–Ó ßæÑðñ´µó Äå ÇÈåн“вìåìæ¼åÍ’å¼ð ’åÐÔåêÁµåÑ–Ó ¦ÿðëé ™ÜÝ.

i. ƒÑð”þñÑó ßæÑðñ µó ii. ÕÄðñÑó ßæÑðñ µó iii. ƒÑðÓé²ìåêÑó ßæÑðñ µó iv. ƒ²™Ñó ßæÑðñ´µó v. ÊðÒ¨Ñó ßæÑðñ´µó (a) i > iii > v > ii > iv

(b) iii > v > ii > iv > i

(c) ii > iv > i > iii > v

(d) v > iii > i > ii > iv

44. ’ðëÆÔðÄð˜µåÑó ÇÈåн“вìðê²ìåêê †

²ìåìæÔåíúÁµå²µå Äå µåêÔð ›åÅé’å²µå¸ ‡Ò®ê

Ôåìæ´µåê¼å¾Áµð ?

(a) CH3CHO + CH3CHO OH

–

→

CH3 – CH(OH) – CH2 – CHO

(b) CH3 – CHO +

CHO OH

–

→

CH(OH) – CH2 – CHO

(c) CH3 – CHO + CH2

(COO C2H5)2 pyridine

→

CH3 – CH = CH – COOH

(d) COCH3 + CH2O

+ (CH3)2 NH Base

→

C6H5 – CO – CH2 – CH2 .

N(CH3)2

41 (15 - A)

40. Name the following reaction

CH2 = CH – CH = CH2 +

(a) Polymerisation

(b) Hofmann elimination

(c) Diel’s – alder reaction

(d) Corey-house reaction

41. List the structures which shows

aromaticity

(a) (i), (iii)

(b) (iii), (iv)

(c) (ii), (iii)

(d) (ii), (iv)

42. The order of relative reactivities

of alkyl halides in SN2 reactions

are

(a) Tertiary halides >

Secondary halides >

Primary halides > Methyl

halides

(b) Methyl halides > Primary

halides > Secondary

halides > Tertiary halides

(c) Primary halides > Tertiary

halides > Secondary

halides > Methyl halides

(d) Primary halides >

Secondary halides >

Methyl halides > Tertiary

halides

43. Arrange the following in the

order of reactivity of halides

i. Alkyl halide

ii. Vinyl halide

iii. Allyl halide

iv. Aryl halide

v. Benzyl halide

(a) i > iii > v > ii > iv

(b) iii > v > ii > iv > i

(c) ii > iv > i > iii > v

(d) v > iii > i > ii > iv

44. Knoevenagal reaction is

condensation between

(a) CH3CHO + CH3CHO OH

–

→

CH3 – CH(OH) – CH2 – CHO

(b) CH3 – CHO +

CHO OH

–

→

CH(OH) – CH2 – CHO

(c) CH3 – CHO + CH2

(COO C2H5)2 pyridine

→

CH3 – CH = CH – COOH

(d) COCH3 + CH2O

+ (CH3)2 NH Base

→

C6H5 – CO – CH2 – CH2 .

N(CH3)2

41 (16 - A)

45. „¦ÿðëá ’åÇÝÓÒ µó ÇÈåн“вìðê µåâÿå ¦ÿðë¼ð ™Äå ÇÈåн“вìåìæ¼åÍ’å¼ð²ìåê ’ðâÿå ™ÄåÔåíú µåâÿåÄåêÆ ‹²™’ð ’åÐÔåêÁµåÑ–Ó ¦ÿðëé ™ÜÝ.

i. CH3 N+

≡ N

ii. CH3O N+

≡ N

iii. O2N N+

≡ N

(a) ii, i, iii (b) iii, i, ii

(c) ii, iii, i (d) i, ii, iii

46. ²ìåìæÔå ÜÈåÒ²ìåêê’å¾ ÔåÜÈåê¾Ôåíú ˜µå²™ÚÈå³ Œ„²µó àé²™’ð „Ôå¼å¤ÄåÔåÄåêÆ ¼ðëé²™ÜÈåê¼å¾Áµð ?

(a) ƒÜÝ ðëéÄó (b) ÕêÁ¿·µðñÑó †Á¿·µðñÑó ’ðé ðëéÄó (c) ÜÈðñ’ðëÓé ÊêÏ®ÄðëéÄó (d) ÕêÁ¿·µðñÑó ÕÄðñÑó “é ðëéÄó

47. log10 IO

I = ∈ Cl † ÜÈåÕêé’å²µå

_____ Äå ƒÊ–·ÔåÏ“¾ (a) Ê–é²µóÄå Ñæ (b) ÑæÏÒʯó¤ Äå Ñæ (c) Ê–é²µó- ÑæÏÒʯó¤ Äå Ñæ (d) ßåê’ó Äå Ñæ

48. ŠÁ¿·™Ñ–éÄó ˜µðñ’æÑóÄåêÆ HIO4 ÄðëÒÁ™ µð ‡¼å”ÚÈ夸 µðëâ–ÜÝÁµæ˜µå ____

(a) Ç·ÈæÔåìæ¤Ñ–¶ßðñ µó Äå 2 ÔðëéÑó ˜µåâÿåê ²µåôåÄð²ìåì昵åê¼å¾Ôð.

(b) Ç·ÈæÕꤒó „ÔåêÓÁµå 2 ÔðëéÑó ˜µåâÿåê ²µåôåÄð²ìåì昵åê¼å¾Ôð.

(c) Ç·ÈæÔåìæ¤Ñ–¶ßðñ µó Äå 1 ÔðëéÑó Ôåê¼åê¾ Ç·ÈæÕꤒó „ÔåêÓÁµå 1 ÔðëéÑó ²µåôåÄð²ìåì昵åê¼å¾Ôð.

(d) CO2 + H2O ²µåôåÄð²ìåì昵åê¼å¾Áµð

49. (i) CO2→(ii) 140 °C, 6-7 atm

‘X’

(iii) H2O / H+

(NaOH + CaO)→

∆ ‘Y’

ÔðêéÑ–Äå “Ð²ìðê²ìåêÑ–Ó ‘Y’ ÄåêÆ ˜µåê²µåê½ÜÝ. (a) ÊðÒ¨éÄó (b) ÜÈæÑ–ÜÝÑ–’ó „ÔåêÓ (c) ÊðÒ¦ÿæÎê’ó „ÔåêÓ (d) Ç·ÝÄæÑó

50. †Á¿·µå²µó ˜µåâÿåÄåêÆ ’åÒÁµåê Êæ®Ñ–˜µåâÿåÑ–Ó ÜÈåÒ˜µåÐàÜݲµåê¼æ¾²µð. ‹’ðÒÁµå²µð †Á¿·µå²µó µæâ– Ôåê¼åê¾ Êðâÿå“ µð ¼ð²µðÁµåê’ðëÒ´µå²µð, ƒÁµåê _____ „˜™ ÔåìæÇÈ头µåê¼å¾Áµð.

(a) ÇÈð²µæ’ðÞûñ µóÞ (b) „’ðëÞéŲìåêÒ ƒ²ìåìæÄó˜µåâÿåê (c) õ²µðªëéÄðñ µó˜µåâÿåê (d) ŠÑð’ðëÐéÇ·ÈðñÑó˜µåâÿåê

51. ÁµåêϽ ÜÈåÔåìæÒ µå¼ð²ìåêÄåêÆ ____ ¼ðëé²™ÜÈåê¼å¾Áµð. (a) ŠÄó-ÊëÏ ðñÑó ’ðëÓé²µðñ µó (b) ÜÈð’ó-ÊëÏ ðñÑó ’ðëÓé²µðñ µó (c) ð¯ó¤-ÊëÏ ðñÑó ’ðëÓé²µðñ µó (d) ŒÜÈðëé-ÊëÏ ðñÑó ’ðëÓé²µðñ µó

52. Êðé²ìåê²µó Äå ÜÈð±øéÄó ¼å¼åÖÁµå ÇÈåÐ’æ²µå, ƒÁ·™’å ÜÝÀ²µå¼ð ßðëÒÁ™²µåêÔå ÜÈåÒ²ìåêê’å¾ÔðÒÁµå²µð ___

(a) ÜÈðñ’ðëÓ ÇÈðîÐéÇÈðéÄó (b) ÜÈðñ’ðëÓ ÊëÏ ðéÄó (c) ÜÈðñ’ðëÓ ÇÈðÒ ðéÄó (d) ÜÈðñ’ðëÓ ßð’ðÞéÄó

ONa

41 (17 - A)

45. Arrange the following species

in the increasing order of

reactivity towards azo coupling

reactions

i. CH3 N+

≡ N

ii. CH3O N+

≡ N

iii. O2N N+

≡ N

(a) ii, i, iii (b) iii, i, ii

(c) ii, iii, i (d) i, ii, iii

46. Which compound will show

maximum IR absorption

frequency ?

(a) Acetone

(b) Methyl Ethyl Ketone

(c) Cyclo butanone

(d) Methyl Vinyl Ketone

47. The equation log10 IO

I = ∈ Cl is

an expression of

(a) Beer’s law

(b) Lambert’s law

(c) Beer-Lambert’s law

(d) Hooke’s law

48. When ethylene glycol is

oxidised with HIO4 ?

(a) 2 moles of formaldehyde

are formed.

(b) 2 moles of formic acid are

formed.

(c) 1 mole of formaldehyde

and 1 mole of formic

acid are formed.

(d) CO2 + H2O are formed.

49. (i) CO2→(ii) 140 °C, 6-7 atm

‘X’

(iii) H2O / H+

(NaOH + CaO)→

∆ ‘Y’

Identify ‘Y’ in the above

reaction

(a) Benzene

(b) Salicylic acid

(c) Benzoic acid

(d) Phenol

50. Ethers are stored in brown

bottles. This is because on

exposure to air and light Ethers

are converted into

(a) Peroxides

(b) Oxonium ions

(c) Ozonides

(d) Electrophiles

51. Optical isomerism is shown by

(a) n-butyl chloride

(b) sec-butyl chloride

(c) tert-butyl chloride

(d) Iso-butyl chloride

52. According to Bayer’s Strain

theory, the most stable

compound is

(a) Cyclo propane

(b) Cyclo butane

(c) Cyclo pentane

(d) Cyclo hexane

ONa

41 (18 - A)

53.

† “вìðê²ìåêÄåêÆ _____ ŠÄåêÆÔå²µåê. (a) ´™éÑó Äå „Ñ¶²µó “вìðê (b) ßæÇ·ÈóÔåêÄóÄå ŠÑ–ÕêÄðéÚÈåÄó “вìðê (c) ’ðëé²™-ßòÜÈó “вìðê (d) ÇÈæÑ–Ôåê²µðñÜÈðéÚÈåÄó

54. Ôåìæ’ðë¤Å’ðëéÇ·Èó Äå HBr Äå ÜÈåÒ’åÑÄå “Ð²ìðê _____ ˜µð ƒÄåÖÎêÜÈåêÔåíúÁ™ÑÓ.

(a) ÇÈðîÐéÇÈðéÄó (b) 1-ÇÈðÒ ðéÄó (c) 2-ÊëÏ ðéÄó (d) 1-ÊëÏ ðéÄó 55. † ÔåêêÒÁ™Äå ²ìåìæÔå ÜÈåÒ²ìåêê’å¾ ÔåÜÈåê¾

„Ñðë”éßæÑ–’ó AgNO3 ÁµæÐÔå¸ ÁµðëÒÁ™ µð Ê–â–²ìåê ƒÔå’ðÛéÇÈåÔåÄåêÆ Åé´µåê¼å¾Áµð ?

(a) ƒÑðñÑó ’ðëÓé²µðñ µó (b) ’ðëÓé²µðë ÊðÒ¨éÄó (c) ÕÄðñÑó ÊðÒ¨éÄó (d) ÕÄðñÑó ’ðëÓé²µðñ µó

56. ²µæÜÈæ²ìåêÅ’å ÊÁµåÑæÔå¹ð²ìåêÄåêÆ Áµæ•Ñ–ÜÈåêÔåíúÁµå’ð” TMS §ÒÁµåê ÇÈæÐÔåì溒å ÇÈåÁµæÁ¿·µå¤Ô昙Áµð. ‹’ðÒÁµå²µð

(a) …Áµåê 12 ÜÈåÔåìæÄå ÇÈðîÐé¯æÄó à阵昙 ÜÈå²™²ìåìæÁµå ÜݘµåÆÑó ßðëÒÁ™Áµð

(b) …Áµåê ²µæÜÈæ²ìåêÅ’åÔæ ™ ÅÚÝ”ø²ìåê (c) …Ò˜µæÑ“”Ò¼åÑë ÜÝÑ–’ðëéÄóÄå

ŠÑð’ðë±øé Äð˜µð°Õ° ’å´™Ôðê²ìåì昙Áµð (d) ÔðêéÑ–ÄåÔåíú˜µåâÿåÑ–Ó ²ìåìæÔåíúÁµåë …ÑÓ

57. ÜÈåÔåìæÄå ÇÈðîÐé¯æÄó ²ìåìæÔåíúÔåíú ? (a) ƒÁµðé ÇÈå²™ÜÈå²µåÁµåÑ–Ó ƒ¸êÕÄå

ÇÈðîÐé¯æÄåšâÿåê ƒÁµðé ƒ²ìåêÜÈæ”Ò½é²ìåê ×哾²ìåêÑ–Ó àé²™’ðëâÿåêä¼å¾Ôð.

(b) ƒ¸êÕÄå ÇÈðîÐé¯æÄåšâÿåê ƒÁµðé ÇÈå²™ÜÈå²µå ßðëÒÁ™ÑÓÁµå „²ìåêÜÈæ”Ò½é²ìåê ×哾²ìåêÄåêÆ àé²™’ðëâÿåêä¼å¾Ôð.

(c) (a) Ôåê¼åê¾ (b) Š²µå µåë

(d) ÔðêéÑ–ÄåÔåíú˜µåâÿåÑ–Ó ²ìåìæÔåíúÁµåë ƒÑÓ

58. ŠÚÈåê± ŠÄóŠÒ„²µó ÜÈåÒ’ðé¼å µåâÿåÄåêÆ (CH3)2 CHCH2CH3 Åé´µåêÔåíúÁµåê

(a) 3 (b) 4

(c) 5 (d) 2

59. ’ðâÿå µð Åé ™²µåêÔå ’æʤÅÄå Ñòà’å ÜÈåÒ²ìåêê’å¾ µåâÿå ÇÈåн“вìåìæ¼åÍ’å¼ð²ìåêÄåêÆ …â–’ð²ìåê ’åÐÔåêÁµåÑ–Ó ¦ÿðëé´™ÜÝ.

1. R – Li 2. R2 – Cd

3. R – Mg – x 4. R2Zn

’ðâÿå µð ’ðë°±²µåêÔå ÜÈåÒ’ðé¼å µåâ–ÒÁµå ÜÈå²™²ìåìæÁµå ‡¼å¾²µåÔåÄåêÆ „²ìðê” Ôåìæ´™.

ÜÈåÒ’ðé¼å µåâÿåê : (a) 1 > 2 > 3 > 4

(b) 1 > 3 > 4 > 2

(c) 1 > 3 > 2 > 4

(d) 4 > 3 > 2 > 1

60. Grignard ’æ²µå’å Ôåê¼åê¾ „ÔåêÓ¦Äå’åÁµå Äå´µåêÕÄå ÇÈåн“вìðê²ìåê ßðñ µðëÐéÑ–ÜÝÜÈó Mg(OH)Br Ôåê¼åê¾ _____ Åé´µåê¼å¾Áµð

(a) methanol

(b) methanal

(c) methane

(d) methanoic „ÔåêÓ

41 (19 - A)

53.

This reaction is called

(a) Diel’s Alder reaction

(b) Hofmann’s elimination

reaction

(c) Corey-House reaction

(d) Polymerisation

54. Markownikoff’s addition of

HBr is not applicable to

(a) Propene (b) 1-pentene

(c) 2-Butene (d) 1-Butene

55. Which of the following

compound will give a white

precipitate with Alcoholic

AgNO3 solution ?

(a) Allyl chloride

(b) Chloro benzene

(c) Vinyl benzene

(d) Vinyl chloride

56. TMS as a standard substance for

recording chemical shift

because

(a) It has 12 equivalent proton

and thus sharp signal.

(b) It is chemically inert.

(c) Electronegativity of silicon

is lower than that of

carbon.

(d) None of these.

57. What are equivalent proton ?

(a) Protons in a molecule and

the same environment

absorbed at the same

magnetic field strength.

(b) Protons in a molecule not

having same environment

absorbed magnetic field

strength.

(c) Both (a) and (b)

(d) None of these

58. How many NMR signals would

be given by the compound :

(CH3)2 CHCH2CH3

(a) 3 (b) 4

(c) 5 (d) 2

59. Arrange the reactivity of given

organo-metallic compounds in

decreasing order

1. R – Li 2. R2 – Cd

3. R – Mg – x 4. R2Zn

Select the correct answer from

the codes given below :

Codes :

(a) 1 > 2 > 3 > 4

(b) 1 > 3 > 4 > 2

(c) 1 > 3 > 2 > 4

(d) 4 > 3 > 2 > 1

60. Reaction between Grignard

reagent and oxygen followed by

hydrolysis gives Mg(OH)Br and

(a) methanol

(b) methanal

(c) methane

(d) methanoic acid

41 (20 - A)

61. Êðé’åÑðñ¯ó ²ìåìæÔåíúÁµå²µå Äå µåêÔå ÇÈåн“вìðêÎêÒÁµåêÒ¯æ˜µå ‡¼åÉÄåÆÔ昙Áµð

(a) Ç·ÈæÔåìæ¤Ñ–¶ßðñ µó Ôåê¼åê¾ ÜÈðëé´™²ìåêÒ ßðñ µæÐ’ðÞûñ µó

(b) ƒÅÑðñÄó Ôåê¼åê¾ ²ìåêë²™²ìåìæ (c) Ç·ÝéÄæÑó Ôåê¼åê¾ Methanal

(d) Ç·ÝéÄæÑó Ôåê¼åê¾ ’ðëÓé²µðëé Ç·ÈæÔåìó¤

62. ×æÖÜÈå’ðëé×åÁ™ÒÁµå ƒÒ µæÒ×å µåâ– µð „ÔåêÓ¦Äå’å (O2), ƒÒ µæÒ×å µåâ–ÒÁµå ×æÖÜÈå’ðëé×å’ð” (CO2)

µåâÿåÄåêÆ ²ìåìæÔåíúÔåíú ÜÈæ ™ÜÈåê¼å¾Ôð ? (a) ÑëÏÜÈðñ¯óÞ (b) Š²™Á¿·µðëÐéÜÈðñ¯óÞ (c) Á¿·µðëÐéÒÊðëéÜÈðñ¯óÞ (d) Ç·ÈðñÊ–ÐÄðëé¦ÿðÄó

63. ’ðâÿå ™Äå ²ìåìæÔå ßðéâ–’ð²ìåêÑ–Ó §ÒÁµåê Ŧ ? (a) ¼ðñÑ ÜÈæÊëÅé’å²µå ™²ìðëéÑó

ÄåêÆ Åé´µåê¼å¾Áµð (b) ¼ðñÑ §¸˜™ÜÈåêÕ’ð²ìåêê ¦ÑÕôð¥éÁµåÄå

(ßðñ´µæÐÑ–ÜÝÜÈó) ÔåÄåêÆ §âÿ嘵ðëÒ´™²µåê¼å¾Áµð

(c) ¼ðñÑ’ð” „Ò° „“Þ µðÒ¯óÄåêÆ ÜÈðéÇÈå¤ µð Ôåìæ µåêÔåíúÁµå²™ÒÁµå ’åÔåê®ê ÔæÜÈåÄð²ìåêÄåêÆ ’å´™Ôðê Ôåìæ´µåê¼å¾Áµð

(d) ¼ðñÑÔåÄåêÆ ÜÈåÒÜÈ唲™ÜÈåêÔåíúÁµåê ßðñ µðëÐé¨ÄðéÚÈåÄó §âÿå µðëÒ ™²µåê¼å¾Áµð

64. µåÒÁ·µå’æÔåêÓ Ôåê¼åê¾ Äðñ ðëÐéÊðÅÞéÄó µåâÿå ‡ÇÈåÜÝÀ½ ²ìåêÑ–Ó ƒÅÑðñÄóÄåêÆ ™ÓÜÈå²µæÑóÄðëÒÁ™ µð Ê–ÜÝ Ôåìæ ™Áµæ µå, …Áµåê QUINOLINE ÄåêÆ Åé µåê¼å¾Áµð. † “вìðê²ìåêÄåêÆ ‹ÄðÒÁµåê ’å²µð²ìåêÑæ µåê¼å¾Áµð.

(a) Ç·ÝÚÈå²µó ÜÈåÒ×ðÓéÚÈå¹ð (b) Skraup ÜÈåÒ×ðÓéÚÈå¹ð (c) Diazotisation

(d) ’ðëé²µð ÔåêÄð ÜÈåÒ×ðÓéÚÈå¹ð

65. ÇÈðñ²™ ™éÄó˜™Ò¼åÑë ÇÈðñ²µðëéÑó ’å ™Ôðê ÔåêëÑÁµåê ‹’ðÒÁµå²µð ÇÈðñ²µðëéÑóÄåÑ–ÓÄå ÜÈæ²µå¦Äå’å ƒ¸êÕÄå ÔðêéÑ–Äå ‹’ðñ’å ŠÑð’æ±øÄó˜µåâÿå ¦ÿðëé ™

(a) delocalized ÇÈðñ „ºÖ’å ’å’ðÛ²ìåê ʷ昵åÔ昙Áµð

(b) delocalized ÇÈðñ „ºÖ’å ’å’ðÛ²ìåê ʷ昵åÔåÑÓ

(c) sp2 ßðñʖдµó ’å’ðÛ²ìåêÑ–Ó ÔæÜÈåÔ昙Áµð (d) sp ßðñʖдµó ’å’ðÛ²ìåêÑ–Ó ÔæÜÈåÔ昙Áµð

66. †Á¿·µðñÑó acetoacetate † ÔåêëÑ’å ¼å²ìåìæ²™ÜÈåÊßåêÁµåê

(a) Rosenmund’s ÇÈåн“вìðê (b) ’ðÓé²ìåêÞÄó ›åÅé’å²µå Á™ÒÁµå (c) ’ðëéÑðÌÄå ŠÑð’ðë±øéÑðñ¯ó ÕÁ·µæÄå (d) Grignard ’æ²µå’å

67. Mutarotation ²ìåìæÔåíúÁµåÄåêÆ §âÿ嘵ðëÒ ™²µåê¼å¾Áµð

(a) ²µðÜÝÕêé’å²µå

(b) ²µåôåÄð²ìåê ÕÇÈå²ìåꤲìåê (c) ÁµåêϽé²ìåê Äå µðÔåâ– (d) Diastereo isomerization

68. ÔåìæÏÑ’ðñ¯ó ßåÜݲµåÄåêÆ † ’ðâÿ嘙Äå ²ìåìæÔåíúÁµå²µå ›åÅé’å²µå¸Á™ÒÁµå ÇÈå´µð²ìåêÑ昵åê¼å¾Áµð.

(a) Benzaldehyde Ôåê¼åê¾ dime-

thylaniline

(b) Ç·ÈæÔåìæ¤Ñ–¶ßðñ µó Ôåê¼åê¾ dime-

thylaniline

(c) Benzaldehyde Ôåê¼åê¾ ŠÄó-methylaniline

(d) Ç·ÈæÔåìæ¤Ñ–¶ßðñ µó Ôåê¼åê¾ ŠÄó –methylaniline

41 (21 - A)

61. Bakelite is a product of the

reaction between

(a) Formaldehyde and sodium

hydroxode

(b) Aniline and Urea

(c) Phenol and Methanal

(d) Phenol and Chloroform

62. Transport of molecular oxygen

(O2) from lungs to tissues and

CO2 (carbon dioxide) from

tissues to lungs is accomplished

by :

(a) Leucytes

(b) Erythrocytes

(c) Thrombocytes

(d) Fibrinogen

63. Which one of the following

statements is true ?

(a) Saponification of Oil

yields a diol.

(b) Drying of oil involves

hydrolysis.

(c) Addition of anti-oxidant to

oil minimizes rancidity.

(d) Refining of oil involves the

hydrogenation.

64. When Aniline is heated with

glycerol in the presence of

sulphuric acid and nitrobenzene,

it gives quinoline. This reaction

is called

(a) Fischer synthesis

(b) Skraup synthesis

(c) Diazotisation

(d) Corey-house synthesis

65. Pyrrole is less basic than

pyridine because the lone pair

of electrons on nitrogen atom in

pyrrole

(a) is part of the delocalized Pi

molecular orbital.

(b) is not part of the

delocalized Pi molecular

orbital.

(c) resides in sp2 hybrid

orbital.

(d) resides in sp hybrid orbital.

66. Ethyl acetoacetate can be

prepared by

(a) Rosenmund’s reaction

(b) Claisen condensation

(c) Kolbe’s electrolytic

method

(d) Grignard reagent

67. Mutarotation involves

(a) Racemization

(b) Conformational inversion

(c) Optical resolution

(d) Diastereo isomerization

68. Malachite green is obtained by

the condensation of

(a) Benzaldehyde and dime-

thylaniline

(b) Formaldehyde and dime-

thylaniline

(c) Benzaldehyde and N-

methylaniline

(d) Formaldehyde and N-

methylaniline

41 (22 - A)

69. ²µæÜÈæ²ìåêÅ’å ÇÈåн“вìðêÎêÒÁµå ²ìåìæÔå Ç·Èðñʲµó Ô帤˜µåâÿåê Äæ²™ÄðëÒÁ™ µð ÜÈðé²™’ðëâÿåêä¼å¾Ôð

(a) „ÔåêÓ Ô帤˜µåâÿåê

(b) Äðé²µå Ô帤˜µåâÿåê

(c) ôåÁµåê²µåêÔå Ô帤˜µåâÿåê

(d) ÔðêéÑ–ÄåÔåíú˜µåâÿåÑ–Ó ²ìåìæÔåíúÁµåë ƒÑÓ

70. ’ðâÿå ™ÄåÔåíú˜µåâÿåÑ–Ó ²ìåìæÔåíúÔåíú „˜µæϤÄðëÜÈåÑÉòµó ÜÈåÒ²ìåêê’å¾ µåâÿ昙ÑÓ ?

(a) ÜÈåÑðëÉÃéÅ’ó „ÔåêÓ µåâÿåê

(b) Thio „Ñðë”éßæÑó˜µåâÿåê

(c) Thio †Á¿·µå²µó˜µåâÿåê

(d) ¼åï½é²ìåê ƒÔðêñÄåê µåâÿåê

71. §ÒÁµåê ‡¼åÉÄåÆÔæ’åÏ f(x) Äå ƒÁ·™’å ÔåìòÑÏÔåíú x = a „Áµæ˜µå

(a) f(a) < f(x) (b) f(a) > f(x)

(c) f(a) ≤ f(x) (d) f(a) ≠ f(x)

72. ∫ (…Ò° µåÐÑó) ÜÈåëôå’åÔåÄåêÆ ÇÈå²™ôåÎêÜÝÁµå ˜µåº¼å¦ö

(a) Ñ–éÊŦÿó 1675 ²µåÑ–Ó

(b) ²µæÔåìæÄåê¦Äó 1675 ²µåÑ–Ó

(c) ¦ÿæÄóÔðÄó 1675 ²µåÑ–Ó

(d) „²ìåê¤Ê·å® 1675 ²µåÑ–Ó

73. 27 °C ÄåÑ–Ó „ÔåêÓ¦Äå’åÁµå ÔåêëÑ ÔåìæÁ·µåùÏ ôò’å ÔðÑæÜÝ°²ìåêê

(a) 483.56 ms–1

(b) 394.83 ms–1

(c) 491.86 ms–1

(d) 484.76 ms–1

74. “ÊæИµóÞÄå ŲìåêÔåêÁµå ÇÈåÐ’æ²µå ’åÛ-“²µå -˜µåâÿåê ÜÈåÉð’åÁµå Ôåêê•Áµå ÔðêéÑð Ê–Áµæ µå ƒÔåíú ÜÈåÉð’åÁµå §âÿå µð ÄåêÜÈåêâ– ƒ¸ê˜µåâÿåÄåêÆ Ê´™²ìåêê¼å¾Ôð” † ’ðâÿå’åÒ´µå ²ìåìæÔå ÜÈåÔåê¼åÑÁµåÑ–Ó Ê´™²ìåêê¼å¾Ôð ?

(a) §ÒÁµðé ¼å²µåßåÁµå ÜÈåÔåê¼åјµåâÿåê (b) ‹’å ÜÈåÔåê¼åÑ

(c) Êðé²µð Êðé²µð ÜÈåÔåê¼åјµåâÿåê (d) Š²µå µåê ÜÈåÔåê¼åÑ µåâÿåê

75. CsCl Äå ²µåôåÄð²ìåêê † ’ðâÿå’åÒ´µåÒ½²µåê¼å¾Áµð (a) BCC ²µåôåÄð (b) FCC ²µåôåÄð (c) ð¯æÐßð´µåÐÑó ²µåôåÄð (d) „’å±ßð µæÐÑó ²µåôåÄð

76. ÇÈåнÜÈåÉð’åÁµå ƒ¸êÕÄåÑ–Ó Êðâÿå“Äå ôåÁµåê²µåê-Õ’ð²ìåêê † ’ðâÿå’åÒ´µå “вìðê²ìåì昙Áµð.

(a) ÊòÐŲìåêÄó ôåÑÄð (b) °Ò´µæÑó ÇÈå²™¹æÔåê (c) Êðд™ µóÞÄå ŠÑð“±ø’ó ÇÈå²™¹æÔåê (d) ’ðñÄð°’ó ÇÈå²™¹æÔåê

77. ÜÈæÔåìæÄåÏÔ昙 “вìðê²ìåê Áµå²µåÔåíú ŠÑæÓ ƒÒ×å ˜µåâ–ÒÁµå ƒÁ·™’åÔ昵åê¼å¾Áµð „Áµå²µð ’ðâÿå ™ÄåÔåíú- ˜µåâÿåÑ–Ó §ÒÁµåÒ×åÔåÄåêÆ ßðë²µå¼åê ÇÈå ™ÜÝ

(a) “вìåìæ’æ²µå’å µåâÿå ÜÈ沵岙’å¾¼ð²ìåêÄåêÆ ƒÁ·™’å µðëâ–ÜÈåêÔåíúÁµåê

(b) ÇÈå²µåÔåìæ¸ê µåêÒÇÈåÄåêÆ ƒÁ·™’å ˜µðëâ–ÜÈåêÔåíúÁµåê

(c) „Ï“±ÔðéÚÈåÄó ×哾²ìåêÄåêÆ ƒÁ·™’å ˜µðëâ–ÜÈåêÔåíúÁµåê

(d) “вìðê²ìåê Áµå²µåÔåÄåêÆ ƒÁ·™’å ˜µðëâ–ÜÈåêÔåíúÁµåê

41 (23 - A)

69. Which dyes become linked to

the fibre by chemical reaction ?

(a) Acid dyes

(b) Direct dyes

(c) Disperse dyes

(d) None of these

70. Which of the following are not

organosulphur compounds ?

(a) Sulphonic acids

(b) Thio alcohols

(c) Thio ethers

(d) Tertiary Amines

71. A function f(x) is said to have

maximum value at x = a if

(a) f(a) < f(x)

(b) f(a) > f(x)

(c) f(a) ≤ f(x)

(d) f(a) ≠ f(x)

72. The symbol ∫ (integral) was

introduced by a mathematician

(a) Leibniz in 1675

(b) Ramanujam in 1675

(c) John Ven in 1675

(d) Aryabhatta in 1675

73. The root mean square velocity

of oxygen at 27 °C is

(a) 483.56 ms–1

(b) 394.83 ms–1

(c) 491.86 ms–1

(d) 484.76 ms–1

74. According to Bragg’s law when

X-rays are incident on crystal

face, they penetrate into the

crystal and strike the atoms in

(a) Same planes

(b) Single planes

(c) Different planes

(d) Two planes

75. CsCl has

(a) BCC structure

(b) FCC structure

(c) Tetrahedral structure

(d) Octahedral structure

76. The process of scattering of

light by colloidal particle is

called

(a) Brownian movement

(b) Tyndall effect

(c) Bredig’s electric effect

(d) Kinetic effect

77. In general rate of reaction can

be increased by all factors

except

(a) Increasing the dilution of

reactants

(b) Increasing the molecularity

(c) Increasing the activation

energy

(d) Increasing the order of

reaction

41 (24 - A)

78. Fe2O3 + Cr2O3 ÄåêÆ Ôðé µåÔåÁ·µå¤’å „ ™ ‡ÇÈå²ìðëé ™ÜÈåÑÉ µåêÔå “Ð²ìðê²ìåêê …Áµæ ™Áµð.

(a) ßåʲµóÄå ƒÔðëéŲìåìæ ÜÈåÒ×ðÓéÚÈå “Ð²ìðê

(b) „ÜÈó±ÔæÑó¶üÞ Äå Äðñ°Ð’ó „ÔåêÓ ‡¼æÉÁµåÄæ “Ð²ìðê

(c) ÊæÚÈóÄå ¦Ñ¦Äå’å ‡¼æÉÁµåÄæ “Ð²ìðê (d) ’æÒ¯æ’ó± ÇÈåГвìðê²ìåê

˜µåÒÁ·µå’æÔåêÓÁµå ‡¼æÉÁµåÄæ “Ð²ìðê

79. Ôåêê¡¢Áµå ÔåÏÔåÜÈðÀ²ìåêÑ–Ó ’åÒ´µåê ʲµåêÔåíúÁµåê ______

(a) ÔåÜÈåê¾ Ôåê¼åê¾ ×哾 µåâÿð²µå µåë ÇÈå²™ÜÈå²µå ÁµðëÒÁ™ µð ÕÅÔåê²ìåê ˜µðëâÿåêä¼å¾Áµð

(b) ’ðéÔåÑ ×哾 Ôåìæ¼åÐ ÕÅÔåê²ìåê ˜µðëâÿåêä¼å¾Áµð „Áµå²µð ÔåÜÈåê¾Ôåíú ÇÈå²™ÜÈå²µå ÁµðëÒÁ™ µð ÕÅÔåê²ìåê Ô昵åêÔåíúÁ™ÑÓ

(c) ’ðéÔåÑ ‡ÚÈå»Ôåíú ÇÈå²™ÜÈå²µåÁµðëÒÁ™ µð ÕÅÔåê²ìå꘵ðëâÿåêä¼å¾Áµð

(d) ’ðéÔåÑ ÔåÜÈåê¾Ôåíú ÇÈå²™ÜÈå²µåÁµðëÒÁ™ µð ÕÅÔåê²ìå꘵ðëâÿåêä¼å¾Áµð ×哾²ìåêê ÕÅÔåê²ìå꘵ðëâÿåêäÔåíúÁ™ÑÓ

80. ∆U = q + w …Áµåê ’ðâÿå’åÒ´µå ²ìåìæÔå ŲìåêÔåêÁµå ˜µåº¼åÁµå ²µåëÇÈå

(a) Á¿·µåÔðë¤é µðñÄæÕê’óÞ Äå ¨é²µðëé ŲìåêÔåê (b) Á¿·µåÔðë¤é µðñÄæÕê’óÞ Äå Ôåêë²µåÄð ŲìåêÔåê (c) ¦ÿòÑóÞ Äå ŲìåêÔåê (d) Á¿·µåÔðë¤é´µðñÄæÕê’óÞÄå ÔðëÁµåÑÄðé

ŲìåêÔåê

81. „´™²ìåìæÊæ°’ó “вìðê²ìåêÑ–Ó ŠÒ ðëÐéÇݲìåê ÊÁµåÑæÔå¹ð²ìåêê ²ìåìæÔ昵åÑë

(a) ∆S < O (b) ∆S > O

(c) ∆S = O (d) ∆S ≠ O

82. §ÒÁµåê ’æÄæ¤ ó ŠÒ¨Äó 0° Ôåê¼åê¾ 100 °C

Äå µåêÔð ’ðÑÜÈå Ôåìæ µåê½¾Áµåê ƒÁµå’ð” 1900 kJ

¼æÇÈåÔåÄåêÆ Åé µåÑæ ™Áµð. ßæ µæÁµå²µð, „ ŠÒ¨Äó Ôåìæ µåêÔå ’ðÑÜÈåÔðÚÈåê± ?

(a) 509.4 kJ (b) 508.2 kJ

(c) 507.4 kJ (d) 600.1 kJ

83. Pb – Ag ÜÝÜÈå±ÔåìóÄåÑ–Ó 576 K Ôåê¼åê¾ ²ìåêê ð“’ó ÜÈåÒ²ìðëé¦Äð˜µð ÜÈåÒÊÒÁ·™ÜÝÁµå ²ìåêê 𓱒ó Ê–ÒÁµåêÔåíú

(a) 96.4% Pb and 3.6% Ag

(b) 97.6% Pb and 2.4% Ag

(c) 97.1% Pb and 2.9% Ag

(d) 97.0% Pb and 3.0% Ag

84. “ÜÝÀ²µå ‡ÚÈå»ÁµåÑ–Ó, ÁµåÐÔåÁµåÑ–ÓÄå ƒÅÑÁµå ’岵嘵åêÕ’ð²ìåêê ÁµæÐÔå ÁµåÑ–Ó ƒÅÑÁµå ƒ²µð §¼å¾ µå’ð” Äðé²µå ƒÄåêÇÈæ¼åÁµåÑ–Ó²µåê¼å¾Áµð” † ŲìåêÔåêÔåíú

(a) Êæ²ìåìóÓüÞ Äå ŲìåêÔåê (b) ²µòÑó±ûÞ Äå ŲìåêÔåê (c) ßðÅвìåê ŲìåêÔåê (d) ôæÑóÞ¤ Äå ŲìåêÔåê

85. ÜÈåÖ¼åÒ¼åÐ ×哾²ìåêê (–∆G) ’å ™Ôðê²ìåì昵åêÔåíú- ÁµåÄåêÆ ’ðâÿå’åÒ µå ²ìåìæÔåíúÁµåê ÜÈåë¡ÜÈåê¼å¾Áµð ?

(a) ’åÅÚÈå± Ôðë¼å¾Áµå ’ðÑÜÈå (b) ’å ™Ôðê Ôðë¼å¾Áµå ’ðÑÜÈå (c) ˜µå²™ÚÈå³ Ôðë¼å¾Áµå ’ðÑÜÈå (d) ²ìåìæÔå ’ðÑÜÈåÔåî …ÑÓ

86. ÅÁ™¤ÚÈå± Ôæßå’å¼ð²ìåê ‹’åÔåìæÄåÔåíú (a) ÔðëéÑó

(b) sm2/ ÔðëéÑó

(c) ÜÝéÔåêÄó/m ƒÁ¿·µåÔæ sm–1

(d) kg/m3

41 (25 - A)

78. Fe2O3 + Cr2O3 is used as

catalyst in

(a) Haber’s process for the

synthesis of ammonia.

(b) Ostwald’s process for the

manufacture of Nitric acid.

(c) Bosch’s process for the

manufacture of Hydrogen.

(d) Contact process for the

manufacture of sulphuric

acid.

79. Closed system is a system

which can

(a) exchange both matter and

energy with the

surroundings.

(b) exchange only energy not

matter with the

surrounding.

(c) exchange only heat with

the surrounding.

(d) exchange only matter not

energy with surrounding.

80. ∆U = q + w this mathematical

expression is

(a) Zeroth law of

Thermodynamics

(b) Third law of

Thermodynamics

(c) Joule’s law

(d) First law of

Thermodynamics

81. The change in entropy is an

adiabatic process is always

(a) ∆S < O (b) ∆S > O

(c) ∆S = O (d) ∆S ≠ O

82. How much useful work can be

done by a carnot engine

working between 0° & 100 °C

and heat supplied is 1900 kJ ?

(a) 509.4 kJ (b) 508.2 kJ

(c) 507.4 kJ (d) 600.1 kJ

83. For Pb – Ag system the eutectic

point corresponds to 576 K and

Eutectic composition is

(a) 96.4% Pb and 3.6% Ag

(b) 97.6% Pb and 2.4% Ag

(c) 97.1% Pb and 2.9% Ag

(d) 97.0% Pb and 3.0% Ag

84. “The solubility of gas in a liquid

is directly proportional to the

partial pressure of the gas above

the solution at constant

temperature” is

(a) Boyle’s law

(b) Roult’s law

(c) Henry’s law

(d) Charle’s law

85. The decrease in free energy

(–∆G) represents the

(a) minimum amount of work.

(b) less amount of work.

(c) maximum amount of work.

(d) No work.

86. The unit of specific

conductivity is

(a) mole

(b) sm2/mole

(c) Seimen/m or sm–1

(d) kg/m3

41 (26 - A)

87. ´µðéŲìåêÑó ’ðëé×åÔåíú ’ðâÿå’åÒ´µå ²ìåìæÔå ÜÈåÖ²ìåêÒÇÈðÐé²™¼å ²µð µæ’óÞ ÇÈåн“вìðê²ìåì昙Áµð ?

(a) Zn(s) + Cu2+

(aq) → Zn2+

(aq)

+ Cu(s)

(b) Zn(s) + Cu2+

(aq) → Zn+

(aq)

+ Cu(s)

(c) Zn(aq) + Cu2+

(s) → Zn(s) +

Cu2+

(aq)

(d) Zn(s) + Cu2+

(aq) → Zn(aq)

+ Cu(s)

88. §ÒÁµåê ÜÈðÉÜÝÔåêÄó ÄåÑ–Ó ŠÑð’æ±øÄó ˜µåâÿåê ¼åâÿåʷ昵åÁ™ÒÁµå ÔðêéÑðÍþñ µð ôåÑÄð ßðëÒÁµåê¼å¾Ô𠄘µå ¼åê’åê” ‡¼åÉÄåÆÔåíú † ’ðâÿå’åÒ µå ʷ昵åÁµåÑ–Ó ‡Ò¯æ˜µåê¼å¾Áµð.

(a) ’æÏÁ¿·µðëé´µóÄåÑ–Ó

(b) „ÏÄðëé´µóÄåÑ–Ó

(c) ’æÏÁ¿·µðëé µó Ôåê¼åê¾ „ÏÄðëé µó Äå µåêÔð

(d) „Ï“±Ôó ŠÑð’ðë±øé µó Äå µåêÔð

89. §ÒÁµåê ÔåÜÈåê¾Ôåíú ÜÈåÉð’å ÁµåÐÔåÁµå Ñ’åÛ¸ µåâÿåÄåêÆ † ’ðâÿå’åÒ µåÒ¼ð ¼ðëé²™ÜÈåê¼å¾Áµð

(a) ’å ™Ôðê ÜÝÀ²µå Ôåê¼åê¾ ’æÎêÜÝÁµæ µå ÕÊ·å¦Äð ßðëÒÁµåêÔåíúÁµåê

(b) ¼åêÒÊæ ’å ™Ôðê ’å²µå˜µåêÔå Ê–ÒÁµåê ÔåÄåêÆ ßðëÒÁ™²µåêÔåíúÁµåê

(c) ßðôåê¢ ÜÝÀ²µå Ôåê¼åê¾ ÇÈåвìðëé µæѲìåêÁµå ¼æÇÈåÁµåÑ–Ó ’æÎêÜÝÁµæ µå ÕÊ·å¦Äð ßðëÒÁµåÁµð …²µåêÔåíúÁµåê

(d) Åé²™ÄåÑ–Ó ÜÈåêÑÊ·åÔ昙 ’å²µå µåêÔåíúÁµåê

90. ÜÈð±é¯ó „Ç·Èó …“ÖÑ–Ê–²ìåêÒÄå ÊÁµåÑæÔå¹ð ²ìåêê ’ðâÿå’åÒ µå ²ìåìæÔå Ôåêë²µåê Ôåêê•Ï ƒÒ×嘵åâ–ÒÁµæ˜µåê¼å¾Ôð ?

(a) ’æÄåÞÄó ðÐéÚÈåÄó, ÜÈæÒÁµåмð Ôåê¼åê¾ ÜÝÆ µåÂüð (b) §¼å¾ µå, ‡ÚÈ廼ð Ôåê¼åê¾ ÔðêéÑðÍþñ §¼å¾ µå (c) ²™Ç·ÈæГ±Ôó ÜÈåëôå’å, §¼å¾ µå, µæ¼åÐ (d) ’æÄåÞÄó ðÐéÚÈåÄó, ‡ÚÈ廼ð Ôåê¼åê¾ §¼å¾ µå

91. ¦Äå¦Äå’åÁµå ÇÈå²µåÔåìæ¸êÕÄåÑ–Ó ÔðëÁµåÑ ’å’ðÛ²ìåê ½Ð¦ÏÔåíú

0.529 × 10–10 m „ ™Áµð. Ôåêë²µåÄðé ’å’ðÛ²ìåê ½Ð¦ÏÔåÄåêÆ ’ðâÿå’åÒ µåÒ¼ð ½â–ÜÈåÊßåêÁµåê

(a) 1

3 × 0.529 A°

(b) 3 × 0.529 A°

(c) 9 × 0.529 A°

(d) 0.3× 0.529 A°

92. ÇÈåн²ìðëÒÁµåê ÇÈåÐÁ·µæÄå Ôåê®±ÁµåÑëÓ §®ê± ‡ÇÈåÔåê®±˜µåâÿå ÜÈåÒ•ÿðϲìåêê † ’ðâÿ嘙ÄåÁµå’ð” ÜÈåÔåêÔ昙²µåê¼å¾Áµð.

(a) ƒ¨ÔåêëÁ¿·µåÑó ’æÖÒ®Ôåìó ÜÈåÒ•ÿðÏ (b) ÜÝÉÄó ’æÖÒ®Ôåìó ÜÈåÒ•ÿðÏ (c) ’æÒ½é²ìåê ’æÖÒ®Ò ÜÈåÒ•ÿðÏ (d) ÇÈåÐÁ·µæÄå ’æÖÒ®Ò ÜÈåÒ•ÿðÏ

93. 4p ’å’åÛ’åÔåíú 5s ’å’åÛ’å“”Ò¼å ’å ™Ôðê ×哾 ßðëÒÁ™²µåê¼å¾Áµð. ²ìåìæ’ðÒÁµå²µð 4p ’å’åÛ’åÔåíú

(a) (n + l) Äå ’å ™Ôðê ÔåìòÑÏÔåÄåêÆ ßðëÒÁ™²µåê¼å¾Áµð

(b) l Äå ’å´™Ôðê ÔåìòÑÏÔåÄåêÆ ßðëÒÁ™²µåê¼å¾Áµð

(c) n Äå ’å ™Ôðê ÔåìòÑÏÔåÄåêÆ ßðëÒÁ™²µåê¼å¾Áµð

(d) …Ôåíú ²ìåìæÔåíúÔåî ƒÑÓ

41 (27 - A)

87. The Daniell cell is based on the

following spontaneous redox

reaction

(a) Zn(s) + Cu2+

(aq) → Zn2+

(aq)

+ Cu(s)

(b) Zn(s) + Cu2+

(aq) → Zn+

(aq)

+ Cu(s)

(c) Zn(aq) + Cu2+

(s) → Zn(s) +

Cu2+

(aq)

(d) Zn(s) + Cu2+

(aq) → Zn(aq)

+ Cu(s)

88. Electrons pass from the bottom

to the top of the specimen, then

the corrosion product will be

formed

(a) at cathode.

(b) at anode

(c) between Anode and

cathode.

(d) on active electrode.

89. The substances showing liquid

crystal character are

(a) Less stable and

decomposes on heating.

(b) Having very low melting

point.

(c) Highly stable and do not

decompose on heating at

lab temperature.

(d) Easily soluble in water.

90. What are the three main factors

which alter the state of

equilibrium ?

(a) Concentration, density and

viscosity.

(b) Pressure, temperature and

surface tension.

(c) Refractive index, pressure

and volume.

(d) Concentration, temperature

and pressure.

91. The radius of first orbit in

hydrogen atom is

0.529 × 10–10 m. The radius of

third orbit is given by

(a) 1

3 × 0.529 A°

(b) 3 × 0.529 A°

(c) 9 × 0.529 A°

(d) 0.3× 0.529 A°

92. The total number of sublevels in

each principal level is equal to

(a) azimuthal quantum number.

(b) spin quantum number.

(c) magnetic quantum number.

(d) principal quantum number.

93. 4p orbital has lesser energy than

5s orbital because 4p orbital has

(a) lesser value of (n + l)

(b) lesser value of l

(c) lesser value of n

(d) none of these

41 (28 - A)

94. h = 10–34 Js ŠÒÁµåê Ê·æÕÜÝ

’ðëÒ´µæ˜µå, 10–31 ’ð¨ ÁµåÐÔåϲµæØÎêÁµåêÂ

109 cms–1 Ôð阵åÁµåÑ–Ó ôåÑ–ÜÈåê½¾²µåêÔå §ÒÁµåê ’å Áµå ´™ÊðëИ™Ó ¼å²µåÒ µæҼ岵åÔåíú ŠÚÈåê± ?

(a) 0.1 nm (b) 1 nm

(c) 10 nm (d) 100 nm

95. LCAO ÕÁ·µæÄå’ð” ÜÈåÒÊÒÁ·™ÜÝÁµåÒ¼ð † ’ðâÿå ™ÄåÔåíú˜µåâÿåÑ–Ó ²ìåìæÔåíúÁµåê ÜÈå²™²ìåêÑÓ ?

(a) ÇÈå²µåÔåìæºÖ’å ’å’åÛ’å µåâÿå ×哾˜µåâÿåê ¼åêÑÄæßå¤Ô昙²µåÊðé’åê

(b) ÜÈåÒ²ìðëé¦Äð˜µðëâÿåêäÔå ’å’åÛ’å µåâÿå ÜÈåÕêͽ²ìåêê §ÒÁµðé ²™é½Îê²µåÊðé’åê

(c) Ç·ÈåÑ–¼åÔ昙 ʲµåêÔå §ÒÁµåê Õ²µðëéÁ·µå’å ’å’åÛ’åÁµå ×哾²ìåêê ÊÒÁ·µå’å ’å’åÛ’åÁµå ×哾˜™Ò¼å ’å´™Ôðê …²µåê¼å¾Áµð

(d) ÇÈå²µåÔåìæºÖ’å ’å’åے嘵åâÿåê ÜÈæ’åÚÈåê± ÔæÏÇݾ²ìåêÔå²µð µð §ÒÁµå²µå ÔðêéÑðëÒÁµåê ÔæÏÇÝÜݲµåÊðé’åê

96. ƒÒÁµðëéÑÄåÁµåÑ–Ó²µåêÔå §ÒÁµåê µðñƒ¯æÕê’ó ƒ¸êÕÄå ×åëÄåÏ Ê–ÒÁµåê ×哾²ìåêê

(a) ÜÈðëÄðÆ (b) 1

2 hν

(c) hν (d) 2 hν

97. HCl Ôåê¼åê¾ H2O ƒ¸ê˜µåâÿå ’åÒÇÈåÄå µåâÿå ÜÈæÔåìæÄåÏ ÜÈæÁ·µåùϼæ Ôðëé´µó˜µåâÿåê ƒÄåê’åÐÔåêÔ昙

(a) §ÒÁµåê Ôåê¼åê¾ Ôåêë²µåê (b) Ôåêë²µåê Ôåê¼åê¾ §ÒÁµåê (c) §ÒÁµåê Ôåê¼åê¾ ÄæÑê” (d) ÄæÑê” Ôåê¼åê¾ §ÒÁµåê

98. §ÒÁµåê ƒÅÑ ²µåëÇÝé ´µðñƒ¯æÕê’ó ƒ¸êÕÄå Ôðêñ’ðëÐéÔðéÔó ²µðëéà¼åÁµåÑ–Ó ƒÄåê’åÐÔåê ²µðé•ÿð˜µåâÿå Äå µåêÕÄå ÜÈåÀâÿæÔå’æ×å

Ôåíú 20 cm–1 „˜™Áµð. „Áµå²™ÒÁµå ƒ¸êÕÄå ÇÈ岙ʷåùÐÔåê’å ÜÝÀ²µæÒ’åÔåíú

(a) 10 cm–1 (b) 20 cm–1

(c) 40 cm–1 (d) 80 cm–1

99. ’ðëé×å ‡Áµå (l) ÁµåÑ–Ó²µåêÔå §ÒÁµåê

ÇÈåÁµæÁ¿·µå¤Ôåíú ÇÈå¼åÄå Êðâÿå“Äå 20% ÄåÚÈåê±

àé²™’ðëâÿåêä¼å¾Áµð. ‡ÁµåÂÔåÄåêÆ 5 l µ ð ÊÁµåÑæÎêÜÝÁµå²µð ƒÁµåê àé²™’ðëâÿåêäÔå ÇÈå¼åÄå Êðâÿå“Äå Ê–·ÄæÆÒ×åÔåíú (fraction)

(a) ÊÁµåÑ昵åêÔåíúÁ™ÑÓ

(b) ’å ™Ôðê²ìåì昵åê¼å¾Áµð

(c) ßðô梘µåê¼å¾Áµð

(d) …Ôåíú ²ìåìæÔåíúÔåî ƒÑÓ

100. Øé¼å›åÅé’å²µå¸ Ê–ÒÁµåêÔåíú 2 °C ²ìåêÚÈåê±

’ðâÿå ™â–²ìåêÊðé’æÁµå²µð 1 kg ²ìåêÚÈåê± Åé²™ µð

ŠÚÈåê± ÇÈåÐÔåìæ¸Áµå KCl ÜÈðé²™ÜÈåÊðé’åê ?

(Åé²™Äå Kf = 1.86 °C mol–1)

(a) 8.01 g

(b) 0.801 g

(c) 0.0801 g

(d) 80.1 g

41 (29 - A)

94. Assuming that h = 10–34 Js, the

de Broglie wavelength of a

particle of mass 10–31 kg

moving with a velocity of

109 cms–1 is

(a) 0.1 nm (b) 1 nm

(c) 10 nm (d) 100 nm

95. Which of the following is not

true regarding LCAO method ?

(a) The energies of atomic

orbitals should be

comparable.

(b) The symmetry of

combining orbitals should

be the same.

(c) The energy of resulting

antibonding orbital is less

than that of bonding

orbital.

(d) The atomic orbitals should

overlap to a considerable

extent.

96. The zeropoint energy of an

oscillating diatomic molecule is

(a) zero (b) 1

2 hν

(c) hν (d) 2 hν

97. The possible normal modes of

vibrations of HCl and H2O

molecules are respectively

(a) one and three

(b) three and one

(c) one and four

(d) four and one

98. The spacing between the

successive lines in the

microwave spectrum of a

gaseous diatomic molecule is

20 cm–1. Hence the rotational

constant of the molecule is

(a) 10 cm–1

(b) 20 cm–1

(c) 40 cm–1

(d) 80 cm–1

99. A substance in a cell length (l)

absorbs 20% of incident light. If

the cell length in changed to 5 l,

the fraction of incident light that

will be absorbed is

(a) unchanged

(b) decreased

(c) increased

(d) none of these

100. What is the amount of KCl,

which must be added to one kg

of water so that the freezing

point is depressed by 2 °C.

(Given Kf for water = 1.86 °C

mol–1)

(a) 8.01 g

(b) 0.801 g

(c) 0.0801 g

(d) 80.1 g

¡¼åê¾ Ê²µåßå’攘™ ÜÈåÀâÿåSPACE FOR ROUGH WORK

41-A (30 - A)

¡¼åê¾ Ê²µåßå’攘™ ÜÈåÀâÿåSPACE FOR ROUGH WORK

(31 - A) 41-A

ÔåÚÈå¤Äó ’ðëé µó

† ÇÈåÐ×ðÆÇÈåíúÜݾ’ð²ìåêÄåêÆ ¼ð²µð²ìåêêÔåÒ¼ð ÅÔå꘵ð ½â–ÜÈåêÔåÔå²µð˜µåë …ÁµåÄåêÆ ¼ð²µð²ìåê’åë´µåÁµåê.

ÇÈåÐ×ðÆÇÈåíúÜݾ’ðÅÁ™¤ÚÈå± ÇÈå½Ð’ð

(ÇÈå½Ð’ð-II)úúúúú

µå²™ÚÈå³ ÜÈåÔåê²ìåê ‘ 2 µåÒ ð µåâÿåê µå²™ÚÈå³ ƒÒ’å µåâÿåê ‘ 200

DA

ÕÚÈå²ìåê ÜÈåÒ’ðé¼å : 41

ÜÈåëôåÄð˜µåâÿåê1. ÇÈå²™é’ðÛ ÇÈæвµåÒÊ·å µðëÒ µå ¼å’åÛ¸Ôðé õ.ŠÒ.„²µó. ‡¼å¾²µå ßæâÿð²ìåêÑ–Ó ÇÈåÐ×ðÆ ÇÈå½Ð’ð ×ðÐ麲ìåêÄåêÆ µåê²µåê¼åê Ôåìæ µåêÔå

ÔðëÁµåÑê, † ÇÈåÐ×ðÆ ÇÈåíúÜݾ’ð²ìåêÑ–Ó ÔåêêÁ™Ð¼åÔæ µåÁµå ƒÁ¿·µåÔæ ßå²™Á™²µåêÔå ƒÁ¿·µåÔæ ²ìåìæÔåíúÁµðé ÇÈåíú® …ÑÓÁ™²µåêÔå ƒÁ¿·µåÔæÔåêêÁ™Ð¼åÔæ µåÁµå ÇÈåÐ×ðÆ µåâÿåê …¼æÏÁ™ §âÿå µðëÒ ™ÑÓÔðÒÊêÁµåÄåêÆ ÅéÔåíú ÇÈå²™é“ÛÜÈå¼å’å”ÁµåêÂ. ÔðêéÑ–Äå ²ìåìæÔåíúÁµðé ÁµðëéÚÈå’åÒ µåêÊÒÁµåÑ–Ó ƒÁµåÄåêÆ àÒ½²µåê ™ÜÝ ÑÊ·åùÏÕ²µåêÔå ×ðÐ麲ìåê ÇÈå²™ÇÈåÔæÁµå Êðé²µð ÇÈåÐ×ðÆ ÇÈåíúÜݾ’ð²ìåêÄåêÆ ÇÈå µð²ìåê¼å’å”ÁµåêÂ.

2. ƒÊ·åùÏÁ¿·™¤²ìåêê ÇÈåÐ×ðÆ ÇÈåíúÜݾ’ð²ìåê ÔåÚÈå¤Äó ’ðëé µó A, B, C ƒÁ¿·µåÔæ D, ƒÄåêÆ Ôåê¼åê¾ ÄðëéÒÁµåº ÜÈåÒ•ÿðϲìåêÄåêÆ OMR

‡¼å¾²µå ÇÈå½Ð’ð²ìåêÑ–Ó ƒÁµå’æ” ™ §Áµå ™ÜÈåÑæ ™²µåêÔå ÜÈåÀâÿåÁµåÑ–Ó Ê²µðÁµåê ÜÈåÒ’ðé¼å (ŠÄó ’ðëé µó) µðëâ–ÜÈåÊðé’åê. ßæ µåëصåÁ™¼å ÜÈåÀâÿåÁµåÑ–Ó ¼æÔåíú Ôåê¼åê¾ ÜÈåÒÕé’åÛ’å²µåê ÜÈåà Ôåìæ´™²µåêÔåíúÁµåÄåêÆ •¡¼å ÇÈå´™ÜÝ’ðëâÿåäÊðé’åê. õ.ŠÒ.„²µó.ßæâÿð²ìåêÑ–Ó ½â–ÜݲµåêÔå ²ìåìæÔåíúÁµðé ÔåìæིìåêÄåêÆ Ê·å½¤ Ôåìæ µåêÔåíúÁµåê/ŠÄó ’ðëé µó Ôåìæ µåêÔåíúÁµåê ƒÊ·åùÏÁ¿·™¤ µåâÿå¦ÔæÊæ²™²ìåìæ ™²µåê¼å¾Áµð. §ÒÁµåê Ôðéâÿð ʷ彤 Ôåìæ µåÁ™ÁµåÂÑ–Ó/¼åÇÝÉÁµåÂÑ–Ó ƒÒ¼åßå õ.ŠÒ.„²µó. ‡¼å¾²µå ßæâÿð²ìåêÄåêƽ²µåÜÈ唲™ÜÈåÑæ µåêÔåíúÁµåê.

3. ÇÈå’å”ÁµåÑ–Ó §Áµå ™ÜݲµåêÔå ôò’åÁµåÑðÓé ÅÔåêÍ ÄðëéÒÁµåº ÜÈåÒ•ÿðϲìåêÄåêÆÄåÔåêëÁ™ÜÈåÊðé’åê. ÇÈåÐ×ðÆ ÇÈåíúÜݾ’ð²ìåêÑ–Ó Êðé²µð ‹ÄåÄåëÆ Ê²µð²ìåêÊæ²µåÁµåê.

4. † ÇÈåÐ×ðÆ ÇÈåíúÜݾ’ð 100 ÇÈåÐ×ðÆ µåâÿåÄåêÆ §âÿå µðëÒ ™²µåê¼å¾Áµð. ÇÈåн²ìðëÒÁµåê ÇÈåÐ×ðƲìåêê 4 ‡¼å¾²µå µåâÿåÄåêÆ §âÿå µðëÒ ™²µåê¼å¾Áµð.ÅéÔåíú ‡¼å¾²µå ÇÈå½Ð’ð²ìåêÑ–Ó µåê²µåê¼åê Ôåìæ µåÊðé’ðÒÁ™ÅÜÈåêÔå ‡¼å¾²µåÔåÄåêÆ „²ìðê” Ôåìæ ™’ðëâ–ä. §ÒÁµåê Ôðéâÿð ƒÑ–Ó §ÒÁµå“”Ò¼åßðôåê¢ ÜÈå²™²ìåìæÁµå ‡¼å¾²µå µåâ–Ôð²ìðêÒÁµåê ÅéÔåíú Ê·æÕÜÝÁµå²µð ƒ¼åêϼå¾ÔåêÔðÅÜÈåêÔå ‡¼å¾²µå’ð” µåê²µåê¼åê Ôåìæ ™. ‹Äðé „Áµå²µåëÇÈåн ÇÈåÐ×ðÆ µð ÅéÔåíú ’ðéÔåÑ §ÒÁµåê ‡¼å¾²µåÔåÄåêÆ Ôåìæ¼åÐ „²ìðê” Ôåìæ µåÊðé’åê.

5. ŠÑæÓ ‡¼å¾²µå µåâÿåÄåêÆ ÅÔåê µð §Áµå ™ÜÈåÑæ ™²µåêÔå ÇÈåмðÏé’å ‡¼å¾²µå ÇÈå½Ð’ð²ìåêÑ–ÓÓ (OMR Sheet) ’ðéÔåÑ ’åÇÈåíþÉ ƒÁ¿·µåÔæ ÅéÑ–×æÎê²ìåê ÊæÑóÇÈæÎêÒ¯ó ÇÈðÅÆÄåÑ–Ó Ôåìæ¼åÐ µåê²µåê¼åê Ôåìæ µåÊðé’åê. ‡¼å¾²µå ÇÈå½Ð’ð ßæâÿð²ìåêÑ–ÓÄå ÜÈåëôåÄð µåâÿåÄåêÆ

µåÔåêÅÜÈåêÔåíúÁµåê.6. ŠÑæÓ ÇÈåÐ×ðÆ µåâ– µð ÜÈåÔåìæÄå ƒÒ’å µåâÿåê. ŠÑæÓ ÇÈåÐ×ðÆ µåâ– µåë ‡¼å¾²™Üݲ™.7. ¡¼åê¾ ’ðÑÜÈå’攘™ ßæâÿð˜µåâÿåÄåêÆ ÇÈåÐ×ðÆ ÇÈåíúÜݾ’ð²ìåê ’ðëÄð²ìåêÑ–Ó ÜÈðé²™ÜÈåÑ昙Áµð. ÇÈåÐ×ðÆÇÈåíúÜݾ’ð²ìåê …ÄåêÆâ–Áµå ²ìåìæÔå

Ê·æ µåÁµåÑ–Ó²ìåêë ÅéÔåíú ²ìåìæÔå ²™é½²ìåê µåê²µåê¼åÄåêÆ Ôåìæ µå¼å’å”ÁµåÂÑÓ.8. ÇÈå²™é’ðÛ²ìåê Ôåêê’æ¾²ìåêÔåÄåêÆ ÜÈåë¡ÜÈåêÔå ƒÒ½Ôåê µåÒ ð Êæ²™ÜÝÁµå ¼å’åÛ¸Ôðé ‡¼å¾²µå ÇÈå½Ð’ð²ìåê ßæâÿð²ìåêÑ–Ó …ÄæÆÔåíúÁµðé

µåê²µåê¼åêÔåìæ µåêÔåíúÁµåÄåêÆ ÅÑ–ÓÜÈåÊðé’åê. ÜÈåÒÕé’åÛ’å²µåê ÊÒÁµåê ÅÔåêÍÑ–Ó²µåêÔå ‡¼å¾²µå ÇÈå½Ð’ð²ìåê ßæâÿð²ìåêÄåêÆ ¼åÔåêÍ Ôå×å’ð”¼ð µðÁµåê’ðëÒ µåê Ñð’å”’ð” ¼ð µðÁµåê’ðëâÿåêäÔåÔå²µð µåë ÅÔåêÍ ÅÔåêÍ „ÜÈåÄåÁµåÑ–Ó²ìðêé ’åêâ–½²µå¼å’å”ÁµåêÂ.

9. ÇÈåÐ×ðÆ µåâÿåê ’åÄåÆ µå Ôåê¼åê¾ „Ò µåÓ Ê·æÚÈð²ìåêÑ–Ó²µåê¼å¾Ôð. ’åÄåÆ µå ÇÈåÐ×ðÆ µåâÿåÑ–Ó ÜÈåÒÁµðéßå ‡Ò¯æÁµå²µð, Áµå²ìåêÕ®ê± „Ò µåÓ Ê·æÚÈð²ìåêÇÈåÐ×ðƘµåâÿåÄåêÆ ˜µåÔåêÅÜÈåêÔåíúÁµåê. ÇÈåÐ×ðÆ ÇÈå½Ð’ð²ìåê ÇÈåÐ×ðƘµåâÿåÑ–Ó ²ìåìæÔåíúÁµðé ˜µðëÒÁµåјµåâ–Áµå²µåë „Ò˜µåÓÊ·æÚÈð²ìåê ÇÈåÐ×ðƘµåâÿðéƒÒ½ÔåêÔæ ™²µåê¼å¾Ôð.

ÄðëÒÁµåº ÜÈåÒ•ÿðÏ

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Note : English version of the instructions is printed on the front cover of this booklet.41-A