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Quadrupole Transverse Beam Optics
Chris Rogers
2 June 05
Plan
1. Equations of Motion
2. Transfer Matrices
3. Beam Transport in FoDo Lattices
4. Bunch Envelopes
5. Emittance Invariant• I haven’t had time to do numerical techniques (e.g. calculating beta
function)
• I had hoped to introduce Hamiltonian dynamics but again no time.
• This is quite a mathsy approach - not many pictures
• I don’t claim expertise so apologies for mistakes!
Quadrupole Field
• Quad Field “hyperbolic”
• Transverse focusing & defocusing• Used for beam containment
0
)(
)(
1
1
zxB
zyB
Bquad
Hyperbolicpole faces
Field gradientr
B
Equations of Motion - in z• Lorentz force given by
• Constant energy in B-field => relativistic constant
)( EBvqdt
pdm
Equations of Motion - in z• Lorentz force given by
• Constant energy in B-field => relativistic constant
• Use chain rule so d/dt = vzd/dz
)( EBvqdt
pdm
yzz Bqvxmv ''2 xzz Bqvymv ''2and
dt
pd Bv
Equations of Motion - in z• Lorentz force given by
• Constant energy in B-field => relativistic constant
• Use chain rule so d/dt = vzd/dz
• Substitute for B-field to get SHM (Hill’s equation)
)( EBvqdt
pdm
yzz Bqvxmv ''2
0'' 1 xBp
qx
z
0'' 1 yBp
qy
z
and
xzz Bqvymv ''2and
zzvp
Focusing strength K (dependent on m/q)Signs!
• Recall solution of SHM
• Take e.g. K>0 solution with
Transfer Matrices 1
• Recall solution of SHM
)cosh(
)cos(
)( 0
za
yaz
za
zyK>0
K=0
K<0
)sin(' zKaKy
Transfer Matrices 1
• Recall solution of SHM
• Take e.g. K>0 solution with
• Use double angle formulae
)cosh(
)cos(
)( 0
za
yaz
za
zyK>0
K=0
K<0
)sin(' zKaKy
zKazKay coscossinsin zKKazKKay cossinsincos'
Transfer Matrices 1
• Recall solution of SHM
• Take e.g. K>0 solution with
• Use double angle formulae
)cosh(
)cos(
)( 0
za
yaz
za
zyK>0
K=0
K<0
)sin(' zKaKy
zKazKay coscossinsin zKKazKKay cossinsincos'
)0( zyK )0(' zy
K
zy )0(' )0( zy
Transfer Matrices 2
• This is tidily expressed as a matrix
• This is no coincidence– Actually, this is the first order solution of a
perturbation series– Can be seen more clearly in a Hamiltonian
treatment
• What do the matrices for K=0, K<0 look like?
)0('
)0(
cossin
sin1
cos
)('
)(
y
y
zKzKK
zKK
zK
zy
zy
0101 YMY
Transfer Matrices for other K
• Quote:
• Assumes K is constant between 0 and z– Introduce “effective length” l to deal with fringe fields
)0('
)0(
cossin
sin1
cos
)('
)(
y
y
zKzKK
zKK
zK
zy
zy
)0('
)0(
10
1
)('
)(
y
yz
zy
zy
)0('
)0(
coshsinh
sinh1
cosh
)('
)(
y
y
zKzKK
zKK
zK
zy
zy
K=0
K<0
K>0
FoDo Lattice - an example• It is possible to contain a beam transversely using
alternate focusing and defocusing magnetic quadrupoles (FoDo lattice)
• This is possible given certain constraints on the spacing and focusing strength of the quadrupoles
• We can find these constraints using certain approximations
Thin Lens Approximation
• In thin lens approximation,
• Define focusing strength
• Then
0lK
Klf
1
1cosh
cos
lK
lK
0
sinh1
sin1
lKK
lKK
fKl
lKK
lKK 1
sinh
sin
Thin Lens Transfer Matrices
• Transfer matrices become
• Should be recognisable from light optics
1
101
cossin
sin1
cos
fzKzKK
zKK
zK
1
101
coshsinh
sinh1
cosh
fzKzKK
zKK
zK
Multiple Components
• We can use the matrix formalism to deal with multiple components in a neat manner
• Say we have transport matrices M10 from z0 to z1 and M21 from z1 to z2 so
• What is transfer matrix from z0 to z2?
0101 YMY 1212 YMY and
Multiple Components
• We can use the matrix formalism to deal with multiple components in a neat manner
• Say we have transport matrices M10 from z0 to z1 and M21 from z1 to z2 so
• Then– with 020010212 YMYMMY
0101 YMY 1212 YMY
102120MMM
and
Transfer matrix for FoDo Lattice
• Wrap it all together then we find that the transfer matrix for a FoDo lattice is
10
11
101
10
11
101 l
f
l
fM
FoDo
f
l
f
l
f
lf
ll
f
l
421
2
421
2
2
2
Stability Criterion• What are the requirements for beam containment - is
FoDo really stable?
• Transfer Matrix for n FoDos in series:
• For stability re quire that Mtot is finite & real for large n.
• Route is to solve the Eigenvalue equation (mathsy)
• Then use this to get a condition on f and l
n
FoDototMM
YYM
Eigenvalues of FoDo lattice• Standard way to solve matrix equation like this - take the
determinant
• Then we get a quadratic in
• Neat trick - define such that• Giving eigenvalues
– Try comparing with quadrupole transport M
0 YYM
0)()( 2112221122112 mmmmmm
2cos 2211 mm
iei sincos1
iei sincos2
Transfer Matrix ito eigenvalues
• Then we recast the transfer matrix using eigenvalues, and remaining entirely general
• Here I is the identity matrix and J is some matrix with parameters
• Then state the transfer matrix for n FoDos
sincos JIM
J
)sin()cos( nJnIM n
Stability Criterion• For stability we require cos(n), sin(n) are finite for
large n, i.e.
• Recalling the transfer matrix for the FoDo lattice, this gives
• or
2)(2
1
FoDoMtrace
14
f
l
242
12
12
2
f
l
f
l
f
l
Bunch Transport• We can also transport beam envelopes using the transfer
matrices
• Say we have a bunch with some elliptical distribution in phase space (x, x’ space)– i.e. density contours are elliptical in shape
• Ellipse can be transported using these transfer matrices
Density contour
Contour equation• General equation for an ellipse in (x,x’)
given by
• Or in matrix notation
1'
)'(
x
x
ca
abxx
11
0 XVX T
Transfer Matrices for Bunches
• We can transport this ellipse in a straight-forward manner– We have
– What will V1, the matrix at z1, look like?
xMx10
Transfer Matrices for Bunches
• We can transport this ellipse in a straight-forward manner– We have– Define the new ellipse using
– So that
xMx10
TMVMV100101
110
1
110 XMVXM T
Emittance• Define un-normalised emittance as the area
enclosed by one of these ellipses in phase space– E.g. might be ellipse at 1 rms (so-called rms
emittance)• Or ellipse that contains the entire/95%/whatever of the
bunch
• Area of the ellipse is given by
• e.g. for rms emittanceV
2222 )',()'()( xxxxV
Emittance Conservation• Claim: Emittance is constant at constant momentum
– 0=1 if |V1| = |V0|
– Use |A B| = |A| |B|
– Then requirement becomes |M10|=1
• Consider as an example
– State principle that to 1st order |M|=1 for all “linear” optics1sincoscossin
sin1
cos 22
zKzKzKzKK
zKK
zK
Normalised emittance
• Apply some acceleration along z to all particles in the bunch– Px is constant
– Pz increases
– x’=Px/Pz decreases!
• So the bunch emittance decreases– This is an example of something called
Liouville’s Theorem
– ~“Emittance is conserved in (x,Px) space”
• Define normalised emittance
m
p zn
Summary• Quadrupole field => SHM• We can transport individual particles through
linear magnetic lattices using transfer matrices• Multiple components can be strung together by
simply multiplying the transfer matrices together• We can use this to contain a beam in a FoDo
lattice• We can understand what the bunch envelope
will look like• We can derive a conserved quantity emittance