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A 1.30-kg toaster is not plugged in. The coefficient of static friction between the toaster and a horizontal countertop is 0.350. To make the toaster start moving, you carelessly pull on its electric cord. (a) For the cord tension to be as small as possible, you should pull at what angle above the horizontal? (b) With this angle, how large must the tension be? In[2388]:= sumForcesX@forces_D := Apply@Plus, Map@Function@elt, elt@@1DD * Cos@elt@@2DDDD, forcesDD sumForcesY@forces_D := Apply@Plus, Map@Function@elt, elt@@1DD * Sin@elt@@2DDDD, forcesDD In[2391]:= forces = 88Fc, Θ<, 8Fn, 90 °<, 8Fsf, 180 °<, 8Fg, 270 °<<; In[2412]:= 8 sumForcesX@forcesD m * 0, sumForcesY@forcesD m * 0, Fsf Μs * Fn, Fg m * g, Fc 0, m 0, g 0, Sin@ΘD 0, Cos@ΘD 0 <; Reduce@%, 8Fc, Fn, Fsf<D Out[2413]= Fg gm&&Cos@ΘD s Sin@ΘD 0&&Fc gm Μs Cos@ΘD s Sin@ΘD && Fn gm - Fc Sin@ΘD &&Fsf Fc Cos@ΘD &&gm Μs Cos@ΘD Sin@ΘD 0 In[2439]:= gm Μs Cos@ΘD s Sin@ΘD ; % . 8g 9.8, m 1.3, Μs 0.35<; Plot@%, 8Θ,0°,90°<D Out[2441]= 0.5 1.0 1.5 6 8 10 12

Pse 5e Problem 5.63

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Pse 5e Problem 5.63

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Page 1: Pse 5e Problem 5.63

A 1.30-kg toaster is not plugged in. The coefficient of static friction between the toaster and a horizontal

countertop is 0.350. To make the toaster start moving, you carelessly pull on its electric cord. (a) For

the cord tension to be as small as possible, you should pull at what angle above the horizontal? (b)

With this angle, how large must the tension be?

In[2388]:= sumForcesX@forces_D :=

Apply@Plus, Map@Function@elt, elt@@1DD * Cos@elt@@2DDDD, forcesDDsumForcesY@forces_D :=

Apply@Plus, Map@Function@elt, elt@@1DD * Sin@elt@@2DDDD, forcesDD

In[2391]:= forces = 88Fc, Θ<, 8Fn, 90 °<, 8Fsf, 180 °<, 8Fg, 270 °<<;

In[2412]:= 8sumForcesX@forcesD � m * 0,

sumForcesY@forcesD � m * 0,

Fsf � Μs * Fn,

Fg � m * g,

Fc ¹ 0, m ¹ 0, g ¹ 0, Sin@ΘD ¹ 0, Cos@ΘD ¹ 0

<;

Reduce@%, 8Fc, Fn, Fsf<D

Out[2413]= Fg � g m && Cos@ΘD + Μs Sin@ΘD ¹ 0 && Fc �

g m Μs

Cos@ΘD + Μs Sin@ΘD &&

Fn � g m - Fc Sin@ΘD && Fsf � Fc Cos@ΘD && g m Μs Cos@ΘD Sin@ΘD ¹ 0

In[2439]:=

g m Μs

Cos@ΘD + Μs Sin@ΘD;

% �. 8g ® 9.8, m ® 1.3, Μs ® 0.35<;

Plot@%, 8Θ, 0 °, 90 °<D

Out[2441]=

0.5 1.0 1.5

6

8

10

12

Page 2: Pse 5e Problem 5.63

In[2442]:= DBg m Μs

Cos@ΘD + Μs Sin@ΘD, ΘF;

% �. 8g ® 9.8, m ® 1.3, Μs ® 0.35<;

Plot@%, 8Θ, 0 °, 90 °<D

Out[2444]=

0.5 1.0 1.5

5

10

15

20

In[2491]:= DBg m Μs

Cos@ΘD + Μs Sin@ΘD, ΘF � 0;

Reduce@%, ΘD;

% �. 8g ® 9.8, m ® 1.3, Μs ® 0.35, C@1D ® 0<Out[2493]= Θ � -2.80492 ÈÈ Θ � 0.336675

In[2464]:= 0.33667481938672716` � °

Out[2464]= 19.29

In[2469]:= Fc �

g m Μs

Cos@ΘD + Μs Sin@ΘD;

% �. 8g ® 9.8, m ® 1.3, Μs ® 0.35, Θ -> 0.337<

Out[2470]= Fc � 4.20866

2 PSE 5E PROBLEM 5.63.nb