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Lesson 12.notebook September 29, 2015
PS #10
PS #11
When algebraic equations contain a symbol whose value has not yet been determined, we use analysis to determine whether: 1. The equation is true for all the possible values of the variable(s), or
2. The equation is true for a certain set of the possible value(s) of the variable(s), or
3. The equation is never true for any of the possible values of the variable(s).
Example 2(x + 3) = 2x + 6
Example x + 5 = 11
Example 5x 3 = 4 + 5x
Lesson 12: Solving Equations
Objective
To solve equations using a formal process by starting from the assumption that the original equation has a solution
To explain each step as following from the properties of equality
To identify equations that have the same solution set
Lesson 12.notebook September 29, 2015
Equations created (by applying the Commutative and
Associative Properties to one or both expressions)consist of expressions
equivalent to those in the original equation.
If x is a solution to an equation, then it will also be a solution to any new equation we make by applying the Commutative and Associative Properties to the expressions in
that equation.
We will use ALL properties to solve!
Example #13a + (2a 5) + 2(a + 2) = 13
Lesson 12.notebook September 29, 2015
Example #22d + 36 = 3d 54
Example #3 x = 9 x + 6
Example #4 5x = x + 3 2 5
Example #5 6 + x = x 3 8 2
Lesson 12.notebook September 29, 2015
Example #6 3m 5m 12 = 7m 88 5
EXIT ticket: Describe what it mean if an equations end like this: a) 5 = 5 b) x = x
c) 12 = 42 d) r = 32