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Projectiles Chapter 5

Projectiles Chapter 5. If we ignore the effects of air resistance an object in the air has a horizontal acceleration of ax = 0 m/s 2 and a vertical acceleration

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Page 1: Projectiles Chapter 5. If we ignore the effects of air resistance an object in the air has a horizontal acceleration of ax = 0 m/s 2 and a vertical acceleration

Projectiles

Chapter 5

Page 2: Projectiles Chapter 5. If we ignore the effects of air resistance an object in the air has a horizontal acceleration of ax = 0 m/s 2 and a vertical acceleration

If we ignore the effects of air resistance an object in the air has a horizontal acceleration of ax = 0 m/s2 and a vertical acceleration of ay = −9.8 m/s2.

Since ax = 0 the horizontal velocity is constant throughout the flight.The vertical acceleration of −9.8 m/s2 causes the vertical velocity to decrease on the way up, be 0 at the peak of the flight and increase in the negative direction on the way down.

Page 3: Projectiles Chapter 5. If we ignore the effects of air resistance an object in the air has a horizontal acceleration of ax = 0 m/s 2 and a vertical acceleration

𝑉𝑦 𝑓=𝑉𝑦𝑖+𝑎𝑡

(𝑉𝑦 𝑓 )2=(𝑉𝑦 𝑖)

2+2𝑎(𝑦 𝑓 − 𝑦 𝑖)

𝑦 𝑓=𝑦 𝑖+𝑉𝑦𝑖 (𝑡 )+ 12𝑎(𝑡)2𝑥=𝑉𝑥(𝑡)

Explanation of the Variables for Projectile Motion

a = −9.8 m/s2

a is vertical accelerationVyi Initial Vertical VelocityVyf Final Vertical Velocityyi Initial Heightyf Final Heightt Timex Horizontal Distance

If we assume air resistance is negligible, then Ax horizontal acceleration is zero.

Page 4: Projectiles Chapter 5. If we ignore the effects of air resistance an object in the air has a horizontal acceleration of ax = 0 m/s 2 and a vertical acceleration

𝑉𝑦 𝑓=𝑉𝑦𝑖+𝑎𝑡

(𝑉𝑦 𝑓 )2=(𝑉𝑦 𝑖)

2+2𝑎(𝑦 𝑓 − 𝑦 𝑖)

𝑦 𝑓=𝑦 𝑖+𝑉𝑦𝑖 (𝑡 )+ 12𝑎(𝑡)2

𝑥=𝑉𝑥(𝑡)

Vertical Motion Equations

Horizontal Motion Equation

Page 5: Projectiles Chapter 5. If we ignore the effects of air resistance an object in the air has a horizontal acceleration of ax = 0 m/s 2 and a vertical acceleration

𝑉𝑦 𝑓=𝑉𝑦𝑖+𝑎𝑡Vertical Motion Equations

• Use to solve for time between velocity points.

• Use to solve for initial or final velocity when given time.

Page 6: Projectiles Chapter 5. If we ignore the effects of air resistance an object in the air has a horizontal acceleration of ax = 0 m/s 2 and a vertical acceleration

(𝑉𝑦 𝑓 )2=(𝑉𝑦 𝑖)

2+2𝑎(𝑦 𝑓 − 𝑦 𝑖)

Vertical Motion Equations

Use to find any of the following variablesVyi Initial Vertical VelocityVyf Final Vertical Velocityyi Initial Heightyf Final Height

Page 7: Projectiles Chapter 5. If we ignore the effects of air resistance an object in the air has a horizontal acceleration of ax = 0 m/s 2 and a vertical acceleration

Vertical Motion Equations

This equation is used to find the height at some time point.

Page 8: Projectiles Chapter 5. If we ignore the effects of air resistance an object in the air has a horizontal acceleration of ax = 0 m/s 2 and a vertical acceleration

𝑥=𝑉𝑥(𝑡)

This equation can be used to find: • The horizontal distance traveled in some time interval.• The time to travel a horizontal distance.• The horizontal velocity needed to travel a distance in a

given time interval.

Horizontal Motion Equation

Page 9: Projectiles Chapter 5. If we ignore the effects of air resistance an object in the air has a horizontal acceleration of ax = 0 m/s 2 and a vertical acceleration

Takeoff and landing height effects the time to the peak and the time down.

Page 10: Projectiles Chapter 5. If we ignore the effects of air resistance an object in the air has a horizontal acceleration of ax = 0 m/s 2 and a vertical acceleration
Page 11: Projectiles Chapter 5. If we ignore the effects of air resistance an object in the air has a horizontal acceleration of ax = 0 m/s 2 and a vertical acceleration

A ball is kicked with an initial vertical velocity (Vyi) of 14 m/s, find the vertical velocity of the ball after 2.4 seconds.

Page 12: Projectiles Chapter 5. If we ignore the effects of air resistance an object in the air has a horizontal acceleration of ax = 0 m/s 2 and a vertical acceleration

A football is punted with an initial vertical velocity (Vyi) of 18 m/s, find the time to the peak.

Page 13: Projectiles Chapter 5. If we ignore the effects of air resistance an object in the air has a horizontal acceleration of ax = 0 m/s 2 and a vertical acceleration

A golf ball lands with a final vertical velocity (Vyf) of −23 m/s, find the time down (peak to landing).

Page 14: Projectiles Chapter 5. If we ignore the effects of air resistance an object in the air has a horizontal acceleration of ax = 0 m/s 2 and a vertical acceleration

A javelin is thrown with an initial height (yi) of 1.3 m, initial vertical velocity (Vyi) of 18 m/s, find the peak height (yf).

Page 15: Projectiles Chapter 5. If we ignore the effects of air resistance an object in the air has a horizontal acceleration of ax = 0 m/s 2 and a vertical acceleration

A baseball lands with a final height (yf) of 0 m, final vertical velocity (Vyf) of −37 m/s, find the peak height (yi).

Page 16: Projectiles Chapter 5. If we ignore the effects of air resistance an object in the air has a horizontal acceleration of ax = 0 m/s 2 and a vertical acceleration

A pole vaulter falls from peak height (yi) of 4.1 m to a final height (yf) of 1.1 m, find the final vertical velocity (Vyf) of the pole vaulter.

Page 17: Projectiles Chapter 5. If we ignore the effects of air resistance an object in the air has a horizontal acceleration of ax = 0 m/s 2 and a vertical acceleration

A golf ball is hit with an initial height (yi) of 1.8 m, initial vertical velocity (Vyi) of 23 m/s, a horizontal velocity (Vx) of 32 m/s find the height (yf) of the ball after 3.6 seconds.

Compute the horizontal distance (x) the ball covers during the 3.6 seconds.