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Projectile Motion Formula 2
We often experience many kinds of motions in our daily life.
Projectile motion is one among them. A projectile is
some object thrown in air or space. The Curved path along which
the projectile travels is what is known as
trajectory.
Projectile Motion is the free fall motion of any body in a
horizontal path with constant velocity.
Projectile Motion Formula (trajectory formula) is given by
Where Vx is the velocity along x-axis,
Vxo is the initial velocity along x-axis,
Vy is the velocity along y-axis,
Vyo is the initial velocity along y-axis.
g is the acceleration due to gravity and
t is the time taken.
Equations related to trajectory motion (projectile motion) are
given by
Projectile Motion Problems
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Projectile Motion Formula
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Projectile Motion Problems Back to Top
Where Vo is the initial Velocity,
sin is the component along y-axis,
cos is the component along x-axis.
Projectile Motion formula is used to find the distance, velocity
and time taken in the projectile motion.
Below are given some problems based on projectile motion which
may help you in your assignments.
Solved Examples
Question 1: A body is projected with a velocity of 20 ms-1 at
50o to the horizontal. Find
(i) Maximum height reached
(ii) Time of flight and
(iii) Range of the projectile.
Solution:
Initial Velocity Vo = 20 ms-1,
= 50o
Time of flight, t =
=
= 3.126 s.
Maximum Height reached, H =
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Free Fall Formula Gravitational Potential Energy Formula
=
= 11.97 m.
Horizontal Range R =
= = 40.196 m.
Question 2: John is on top of the building and jack is down. If
john throws a ball at an angle of 60o and
with initial velocity 20 m/s. At what height will the ball reach
after 2 s?
Solution:
Given: Vyo = 20 m/s,
t = 2s,
The Vertical velocity in y direction is given by Vy = Vyo sin
60o
= 20
= 17.32 m/s.
Vertical distance, y = Vyo t - gt2
= 20 2 - 0.5 9.8 4
= 20.4 m.
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