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UNIVERSITATEA DIN CRAIOVA FA CULT A TEA DE “INGI NERIE ELECTRI CĂ SEC IA E.I.B Ț GRUPA 9.305 ANUL III PROIECT TEORIA I CONSTRUC IA APA RA TELOR DE Ș Ț BORD  CÎRSTEA FLORENT INA-PA ULINA

Proiect Avion Cvadrimotor Turbopropulsor

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UNIVERSITATEA DIN CRAIOVA

FACULTATEA DE “INGINERIE ELECTRICĂ “

SEC IA E.I.BȚ

GRUPA 9.305

ANUL III

PROIECTTEORIA I CONSTRUC IA APARATELOR DEȘ Ț

BORD

CÎRSTEA FLORENTINA-PAULINA

8/19/2019 Proiect Avion Cvadrimotor Turbopropulsor

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1. MOTOR TURBOPROPULSOR

Turbopropulsorul (e!"e#$ turboprop% &')e#$ turbopropulseur *e+,e ,/ e 2,2' ,"#, 4 ț )4"$ ",'$.șC2/2e, /')/"$ ,'2/'2/"+2'" e+,e 2 ,'$ ) !#e ")'e e+,e'e ,'$ +e &)e /6$ " /'e+e ,2+&e')$% +,&e")6, ,' e7,'!e &"7" e !#e '+e 2 /,e'e 'e e)6, )ee)e+'$ ,'e$' )2/'e+2'". A)e+,$ /,e'e +/"e,'$ e+,e&2"2+,$ " ,'e'e e e")e /"+,e & 2,2'"% +,&e" )6,ț,'2/'2/"+2'" /2,e & e&,% ,'- 2 +/"% ) 2 e")e,'e,$ e 2 ,'$ ) !#e.

E")e e+,e )/",$ " ,'$ /' ,e'e" 'e),2' )'e,'+&2'$ ,' '),$ ,'e (e )/" 'e",4 )* " 2 ,' eț ț+)$#,$% ' ) )/" 'e. E")e /'2/'-#+$ e+,e e 2)e 2e")e ) /+ 4'"% e ,/ +"' ) )e"e &2"2+,e " 2,2'e"e e4 e ) /+,2.ț

T'2/'2/"+2'" e+,e e+,, 42e"2' )e /')'! +, e ' )ț4,e#e ++2)e% /'2&,6 e 4,8" ,') ) 'e) e " 4,e#eț ț' e )e" " ,') ) e")e " e)2"'e " 4,e#e ).ș ț ș :;

Schema unui turbopropulsor

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:. PROIECTAREA TERMOMETRULUI PENTRUMOTOR

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E A B (t , t 0)=e AB (t )+eBA( t 0)

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"i#.'.' Conetarea aparatului de asurat la lipiturile terouplului

F!.:.3 Conetarea aparatului eletri de asurat la unul din

ondutoare

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)'), ) ' e7+, )'e, ' 2 /+,e )'), +-' )"# + )e"",+-' ') )e+, ' +e ) 'e "2) ,'&e' e )"' e " /',e'e)e " )e )" &' +e )2+ ")' e)) e7,e'2'

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A) + &.e. ,'- )'), )+ &2', ,'e )2),2'&e', ) )ee+ ,e/e',' " "2)" e "/'e e+,e e!" ) #e'2.

F!.:. Cuplu teroeletri "orat din trei ondutoare

De +eee % )e+, 'e#", )<

e AB (t )=e AC (t )+eCB( t )

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I,'2) )e+, e), @ +e 2,e<

E=e AB (t )+eBA(t 0) (9*

A) )2)e )2/"e, ) e), :

F!.:.5. $hea terouplului u ondutorul C onetat la

lipiturile aestuia

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E=e AB (t )+eBC (t 1 )+eCB (t

1 )+eBA(t 0) (10*

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F! :. $hea terouplului u ondutorul C onetat la un

teroeletrod

E) 10 +e /2,e ,'+&2' 2' ,'-2 e) e )'e +$ )2)$ )ț ș ț

(:.:* )$ +e 4 4e 4ee'e )$<

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s i U ; ,')),

e/ee, " Ec e U e+,e "' %/e,' U +e 42' "e!e 2 4"2'

% 'e (/ " : V * + ) (+ 10 V * + +e 42' )")")2'e),"e / e,2 e+)'+ ++ %' +e "e!e ,e+e /e,' )'e )2'e),"e +, /'2/,e e )e"e ,e2'e,)e / "!e'e,e+ %)e+, +e e,e )2+,, + +e 42' 2&) 4"2'"e

'e#+,e,e"2' R1

si R4 / )e +e 2, )2'e), ), /'2/,e e )e"e

,e2'e,)e .

De2'e)e )"#,"e )'e +e +2' ,e/e',' ,e %'e+/e),4e/ ,' +, e +e),e )')"' %+e 42' /e ,e'2)/"' +e'e%+/+e /e )')&e', )"#,e %" +,,e e!"e .

A)e+,e ,e'2)/"' 42' 'e"# 2 ee ,e/e','"2' )"e+e )e"e /),e )'e +, 2,,e %'e#", " e+'e 2 ,e/e','eee /e,' #2 )'e +, 2,,e ,e'2)/"'"e .

S- /'e+/+ ) ,e/e','e "/,'"2' 'e) 4'# ,'e 0 si 50

% ) &/," ) +e &2"2+e+) )"' e /'e"!'e %/e,' 'e"# 2)2/e+'e " 4', e4', " ,e/e',' "/,' 'e)

.)'e /2,e & /"8 10 si 40 .Ce"e ,e'2)/"' 42' & 2,,e

) &!' <

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1i#. 2.3 4ontarea terouplului

T )2, ) ,e'2)/"" &2+, !', " t 0=20 %'e#", <

Pe,' t 0' =0

t 0'

→ Ec ( t 0'

, t 0 )= Ec(0 ,20 )=− Ec (20 ,0)

−4 E AB (20 ,0 )=−4∗0.8=−3.2mV (3.13*

Pe,' t 0' =10

Ec ( t 0'

, t 0 )= Ec(10 ,0 )= Ec

(10 ,0 )− Ec(20 ,0 )=¿

−4 [ E AB (10 , 0 )− E c (20 , 0 ) ]=¿

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−4∗(0.4−0.8 )=−1.6 V

Pe,' t 0'

=30

Ec ( t 0'

, t 0 )= Ec(30 ,20 )= Ec

(30 ,0 )− Ec(20 ,0 )=¿

¿−4 [ E AB (30 ,0 )− Ec (20 ,0 ) ]=4∗(1.2−0.8 )=1.6mV

Pe,' t 0' =40

Ec ( t 0' , t 0 )= Ec (40 ,20 )= Ec (40 ,0 )− Ec (20 ,0 )=4 [ E AB (40 ,0 )− E AB (20 ,0 ) ]

Pe,' t 0' =50

E AB (50 ,0 )− E AB (20 ,0 )=(2.02−0.8 )=4.88mV

Ec ( t 0'

, t 0 )= Ec (50 ,20 )= Ec (50 ,0 )− Ec (20 ,0 )=4¿

V"2'"e

E AB (10 ,0 )… … .. E AB (50 ,0 ) ,

&2+, ",e ,e"e )'e )'),e'+,) ,e'2)/"" "e+%/ ) 'e# <

E AB (10 ,0 )=0.4mV

E AB (20 ,0 )=0.8mV

E AB (30 ,0 )=−1.2mV

E AB (40 ,0 )=1.61mV

E AB (50 ,0 )=2.02mV

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C2'e),"e )")",e ) 'e","e e ++ + +,e,#,e ,e"" 3.1%+, )2'e),"e ,e2'e,)e /e )'e ' ,'e + "e ,'2) /,e e)2/e+'e .

Te"" 3.1 C2'e),"e ,e2'e,)e /e )'e ,'ee + "e ,'2) /,e /e,' &e',e 4"2' "e ,e/e',' "/,' 'e)

t 0' =0 t 0

' =10 t 0' =30 t 0

' =40 t 0' =50

Ec ( t 0

' ,20) -3.:V -1.V 1.V 3.:V .V

A"e! : 4"2' %

=5V

U ' =25 V siU ¿ %/e,' ,e+e e "e,'e /,

+ 'e#+,e,e"e R1 , R2 , R3( R1=2Ω , R2=3, R3=4) % )2, ) " t 0=20

/,e + &e e)"', %'e#", <

R1∗¿ R 3

R2

=2∗4

2 =4Ω

R420=¿

(3.:3*

Re#+,e,e"e R1 , R2 si R3 +, ! %' R4 )/' 4

)2e&)e," e 4',e 'e#+,4,, ) ,e/e',' ∝=0,0004−1

.

Pe,' 4"2'"e /e )'e "e /2,e " t 0'

%'e+/e),4e /e,' 0 %10

,30 ,40 si50 %4 4ee'e &2'" e 4',e " R4 )

,e/e',' % R4= R420[1+∝ ( t 0

' −20 )] %+e )")"e# R4 - )2'e+/#,2'

&e)'e ,e/e','e%'e+/e),4 A%B+ C+ &2"2+ 'e", (3.9*+e

)")"e# 4"2'e "

R0

' si R

0

¿ /e,' &e',e 4"2' "e ,e+.

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Pe,' t 0' =0

R4= R

420 1 ∝(0−20) ;10%000(0 −20 *;3%9X (3.:*

Pe,' t 0' =10

R4= R

420[1+∝ (10−20 ) ]=4 [1+0,0004 (10−20 ) ]=2,982Ω

(3.:5*

Pe,' t 0'

=30

R4= R420[1+α (30−20 ) ]=4 [1+0,0004 (30−20 ) ]=4,016Ω

(3.:*

Pe,' t 0' =40

R4= R420

[1+α (

40−20

) ]=4

[1+0,0004

(40

−20

) ]=4,032

Ω

(3.:@*

Pe,' t 0' =50

R4= R

420[1+α (50−20 ) ]=4 [1+0,0004 (50−20 ) ]=4,048Ω

(3.:*V"2'"e 'e#",,e /e,' 'e#+,e, R4 +, /'e#e,,e ,e"" 3.:

t 0' =0 t 0

' =10 t 0' =30 t 0

' =40 t 0' =50

R4 [Ω] 3%9 :%9 %01 %03: %0

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P2' e " 4"2'"e R4 %) 'e","e (3.10*%(3.11*%(3.1:*%+e

)")"e# /'e,' A%B%C +,&e" <

Pe,' t 0' =0

A R2 R4− R1 R3=2∗3,968−8=0,064 Ω2

(3.:9*

B ( R1+ R4 )( R2+ R3 )=(2+3,968 ) (2+4 )=35,808Ω2

C R1+ R2+ R3+ R4=11,968Ω

Pe,' t 0' =10

A R2 R4− R1 R3=2∗2,984−8=−0,032Ω2

B ( R1+ R4 )( R2+ R3 )=(2+2,984 ) (2+4 )=29,90Ω2

(3.30*

C

R1+ R2+ R3+ R4=10,984Ω

Pe,' t 0' =30

A R2 R4− R1 R3=2∗4,016−8=0,032Ω2

B ( R1+ R4 )( R2+ R3 )=(2+4,016 ) (2+4 )=36,96Ω2

C R1+ R2+ R3+ R4

1:%01X

Pe,' t 0' =40

A R2 R4− R1 R3=2∗4,032−8=0,064Ω2

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B ( R1+ R4 )( R2+ R3 )=(2+4,032 ) (2+4 )=26,19 Ω2

(3.31*

C R1+ R2+ R3+ R4=12,032 X

Pe,' t 0' =50

A R2 R4− R1 R3=2∗4,048−8=0,048Ω2

B ( R1+ R4 )( R2+ R3 ) (:%0*(:*3%: Ω2

C R1+ R

2+ R

3+ R

4=12,048Ω

C 'e", (3.9* )")"

R0

' , R0

¿ %)2'e+/#,2'e )e"2' 2 ,e+

=5

U ' =25 si U

¿ e "e,'e "e /, .Re#", <

Pe,' t 0' =0

R0

' =

U '

E c

∗ A−B

C =

25

−3,2∗10−3∗(−0,064 )−35,808

11,968=51,66Ω

R0

' '

=

U ' '

Ec

∗ A−B

C =

5

−3,2∗10−3∗(−0,064 )−35,808

11,968 =7,144Ω (3.3*

Pe,' t 0' =10

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R10

' =

U '

Ec

∗ A−B

C =

25

−3,2∗10−3∗(−0,032 )−29,904

10,984 =51,612Ω

R10

' ' =

U ' '

Ec

∗ A−B

C =

5

−3,2∗10−3∗(−0,032 )−29,904

10,984=7,098Ω (3.35*

Pe,' t 0' =30

R30

' =

U '

Ec

∗ A−B

C =

25

−3,2∗10−3∗(0,032)−36,96

12,016 =51,50Ω

R30

' ' =

U ' '

Ec

∗ A−B

C =

5

−3,2∗10−3∗(0,032 )−36,96

12,016=7,094Ω (3.3*

Pe,' t 0' =40

R40

' =

U '

Ec

∗ A−B

C =

25

−3,2∗10−3∗(0,064)−26,194

12,032 =50,758Ω

R40

' ' =

U ''

E c

∗ A−B

C =

5

−3,2∗10−3∗(0,032 )−36,96

12,032=6,94Ω (3.3@*

Pe,' t 0' =50

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R50

' =

U '

Ec

∗ A−B

C =

25

−3,2∗10−3∗(0,096)−36,28

12,048 =50,478Ω

R50

' ' =U

' '

Ec∗ A−B

C =

5−3,2∗10

−3∗(0,032 )−36,28

12,048=9,878Ω (3.3*

C2,2'# 4"2'"e 'e#",,e /e,' /'e,' A%B%C + /e,'

'e#+,e,e"e

R' si R

¿ " &e', 4"2' "e ,e/e',' "/,' 'e) %'e#",

tabelul 2.3

t 0'

t 0'

t 0'

t 0'

t 0'

A Ω2

; -0%03: -0%01 0.01 0%03: 0%0

B Ω

2

¿ ; 35%0 :9%90 3%9 :%19 3%:

[¿¿2]¿

11%9 10%9 1:%01 1:%03: 1:%0

R

' 51,66Ω 51,612Ω 51,50Ω 50,758Ω 50,478Ω

R' ' 7,144Ω 7,098Ω 7,094Ω 6,94Ω 9,878Ω

I )2,'e +e 4 )")" 4"2'e ee 'e#+,e,e"2' e+2,e,e'2'.

Re#",

Rmed

' = R0

' + R10

' + R30

' + R40

' + R50

'

5 (3.39*

C 4"2'e e')

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Ec 0

' ' =U ' ' A

B+C ∗ Rmed

' ' =

5∗−0,064

35,808+11,968∗7,6308

¿−0,002517041 V (3.*

Pe,' t 0' =10

Ec 10

' =U ' A

B+C ∗ Rmed

' =

25∗−0,032

29,904+10,984∗51,20=−0,00135070V

Ec10

' ' =U ' ' A

B+C ∗ Rmed'' =

5∗−0,032

29,904+10,984∗7,6308=−0,000281392V

Pe,' t 0' =30

Ec30

' =U ' A

B+C ∗ Rmed' =

25∗0,032

36,96+12,016∗51,20=0,001226656V

Ec 30

' ' =U ' ' A

B+C ∗ Rmed

'' =

5∗0,032

36,96+12,016∗7,6308=0,00024733 V

Pe,' t 0' =40

Ec 40

' =U ' A

B+C ∗ Rmed

' =

25∗0,064

26,194+12,032∗51,20=0,00099652V

Ec40

' ' =U ' ' A

B+C ∗ Rmed' ' =

5∗0,064

26,194+12,032∗7,6308=0,002711703V

Pe,' t 0' =50

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Ec 50

' =U ' A

B+C ∗ Rmed

' =

25∗0,096

36,28+12,048∗51,20=0,00367457 V

Ec50

' ' =U ' ' A

B+C ∗ Rmed'' =

5∗0,096

36,28+12,048∗7,6308=0,00374311V

Ue A%B%C +, )e"e )")",e ,e'2' /e,' &e',e 4"2' "e " t 0'

.

C 4"2'e ,e+ e "e,'e "e+ + e, )2+,,

'e#+,e,e"e R1 , R2 , R3 si R420

%42 )")" e'2'"e e +''e )'e +e 42'

&)e /e,' 4', ,e/e',' 'e) " t =t max .

Fe t 0'

≠ 20=t 0 .

L t =t min=200 + t 0=20 %)e"e /,' ,e'2)/"' ,.,.e.

E AB (200 ,0 )− E AB (20 ,0 )=4 (8,13−0,8 )=29,32mV

E (t min ,20 )= E (t min ,0 )− E (20 ,0 )=4 [ E AB (t min ,0 )− E AB (20 ,0 ) ]=4 ¿

(3.50*

D,2', 2&)' ,e/e',' t 0lat 0'

, )e+,e 42' e ,.,.e. .

E (t min , t 0' )=4∗ E AB (t min ,0 )−4∗ E AB (t 0

' ,0 )=4 E AB[ (200 ,0 )−4 E AB (t 0

' ,0 )]

(3.51*

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C2'e), ,'2+ e /,e 4 & Ec'

)2'e+/#,2'e 4"2' " t 0'

.

P' ''e e'2'e 'e",4e )e+, )# +e e,e' %+e e,e' )'e",

E (t min , t 0' )+ Ec

'

¿− E (t min ,20 )+¿

¿

(3.5:*

V"2'e e'2' !'e )")"-+e )<

∆ t =α 0∗t min (3.53*

L t =t max=1000 + t 0=20 %)e"e /,' ,e'2)/"' ,.,.e.

E (t max ,20 )= E (t max ,0 )− E (20 ,0 )=¿

4 [ E AB ( t max ,0 )− E AB (20 ,0 ) ]=¿

E AB (1000 ,0 )− E AB (20 ,0 )=¿

4¿

4 (41,32−0,8 )=162,08 mV (3.5*

E (t max , t 0' )=4∗ E AB ( t max ,0 )−4∗ E AB ( t 0

' ,0)

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¿4 E AB[ (1000 ,0 )−4 E AB(t 0'

,0)] (3.55*

C2'e), ,'2+ 4 & Ec'

)2'e+/#,2'e 4"2' " t 0'

.P' ''e

e'2'e 'e",4e )e+, )# +e e,e' ) 'e", <

E (t max , t 0' )+ Ec

'

¿− E (t max ,20 )+¿

¿

V"2'e e'2' !e )")"-+e ) < ∆ t = 0∗t max(3.57)

I )2,'e )")" e'2'"e 'e",4e α 0 + e'2'"e !e Ce"++

/e,' &e)'e 4"2'"e 0 ,10 ,30 ,40 ,50 "e " t 0'

%"

,e/e','e "/,' 'e) )"e e!" ) t min ) :00 .A+,&e"

2,e +))e+4 <

Pe,'t 0

' =0

E (t min ,0)=4 E AB (t min ,0 )=4∗8,13=32,52mV

α 0=−29,32+32,52−2,46

29,32 =−0,00252∗100=−0,252

∆ t min=0,252∗200

100 =0,504

Pe,' t 0' =10

E (t min ,10 )=4 E AB (200 ,0 )−4 E AB (10 ,0 )=4 (8,13−0,4 )=30,92mV

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α 0=−29,32+30,92−1,35

29,32=0,0085∗100=0,85

∆ t min10=−0.85∗200

100=1,7

Pe,' t 0' =30

E (t min ,30 )=4 E AB (200 ,0 )−4 E AB (30 ,0 )=¿ (%13-1%:0*:@%@:V

α 0=−29,32+27,72−1,22

29,32=−0,0096∗100=−0.96

∆ t min30=−0.96∗200100

=1,92

Pe,' t 0' =4 0

E (t min ,40 )=4 E AB (200 ,0 )−4 E AB (40 ,0 )=4 (8,13−1,61 )=26,08mV

α 0=−29,32+26,08−0.99

29,32 =0,00144∗100=0,144

∆ t min40=−0,144∗200

100 =0.288

Pe,' t 0' =50

E (t min ,50 )=4 E AB (200 ,0 )−4 E AB (50 ,0 )=4 (8,13−2,02 )=24,44mV

α 0=−29,32+24,44−3,6

29,32 0%00:9Y1000%:9

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0=−162,08+160,4 8−1,35

162,08 =0,018200∗100=−1,8200

∆ t max30=0,18200

Pe,' t 0' =4 0

E (t max ,40 )=4 E AB (1000 ,0 )−4 E AB (40 ,0 )=4 (41,32−1,61 )=158,84

0=−162,08+158,84−1,35

162,08 =0,02831∗100=−2,831

∆ t max30=0,2831

Pe,' t 0' =50

E (t max ,50 )=4 E AB (1000 ,0 )−4 E AB (50 ,0 )=4 (41,32−2,02 )=157,2

0=−162,08+157,2−2,02

162,08=0,042571∗100=−4,2571

∆ t max30=0,42571

I )2)"#e " +,"'e ',e),' /, e )2/e+'e e'2'"2',2',e 4',e ,e/e',' 'e) +- 2/,, /e,' 4', &!

3.1."e,, " ,e+e )2+,, U ' =25V .

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3.: ALEGEREA DIMENSIUNILOR SI CALCULULREZISTENTELOR TERMOCUPLURILOR SI A CABLURILOR DE

LEGATURA

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1i#ura 2.5.$hea eletria a teroetrului in teroupluri