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Problem 1 (25 points)
A diving board consists of a uniform
plank of length L = 1.5 m and a m
ass M = 3.0 kg. If
a man (m
ass m = 70 kg) stands on his toes at the end of the board, w
hat will be the force
exerted on the plank by a support at B and by the pivot at A?
A
B
L/4m
M
Problem 2 (25 points)
A uniform
plastic ball of mass m
= 0.50 kg and radius R = 0.020 m
is rolling down w
ithout slipping on an inclined plane. It has a linear velocity v = 0.8 m
/s when it is at a height h =
0.40 m.
a) C
alculate the velocity of the ball when it reaches the floor.
b) K
nowing that the plane is inclined by an angle ����= 30
0, find the linear acceleration of the ball on the inclined plane.
c) H
ow the answ
ers to a) and b) change if the radius R of the ball is two tim
es larger. d)
When the ball reaches the floor it m
akes a completely inelastic collision w
ith a block of m
ass M = 2.0 kg, w
hat is the velocity after the collision? (If you don’t know how to solve a), put a velocity by hand and you can work on the other questions.)
h
Problem 3 (25 points)
Problem 2 (25 points)
You design three pulley w
ith radius R = 0.160 m and m
ass M = 10.0 kg. The rope does not slip on
pulley rim. U
se the energy methods to calculate the speed of the 4.00-kg block just before it strikes
the floor if the pulley is (a) Solid disk, (b) Solid sphere, or (c) Thin-walled hollow
cylinder. (d) If you re-design the pulleys w
ith Rnew = 0.320 m
, but maintaining the sam
e mass, w
hich pulley design w
ould give the fastest speed for the 4.00-kg block?
m1 m
2
(a) Solid disk
(b) Solid sphere
(c) Thin-walled hollow
cylinder
Problem 2 (25 points) - C
hapter 9 Y
ou design three pulley with radius R = 0.160 m
and mass M
= 10.0 kg. The rope does not slip on pulley rim
. Use the energy m
ethods to calculate the speed of the 4.00-kg block just before it strikes the floor if the pulley is (a) Solid disk, (b) Solid sphere, or (c) Thin-w
alled hollow cylinder. (d) If
you re-design the pulleys with R
new = 0.320 m, but m
aintaining the same m
ass, which pulley design
would give the fastest speed for the 4.00-kg block?
m1 m
2
(a) Solid disk
(b) Solid sphere
(c) Thin-walled hollow
cylinder
ghm
U
vm
vm
IK
Kgh
mU
KU
KU
f f
ii
ff
ii
2
22
21
2
1
2 12 1
2 10
; where�
��
�
��
��
�
�
22
21
2
22
21
22
1
2 12 1
2 1J
98
2 12 1
2 1
J 98
vm
vm
R vI
vm
vm
Igh
mgh
m
KU
Uf
fi
��
�� ��
��
��
��
�
��
�
��
��
���
�
m/s
50
3)2
410
(2 198
(c)
m/s
43
4)2
4(4
2 198
5 2
(b)
m/s
22
4)2
45(
2 198
2 1
(a)
22
22
22
.v
vM
RI
.v
vM
RI
.v
vM
RI
�
��
�
�
�
��
�
�
�
��
�
�
I = 0.560 kg*m2
sphere
Solid.
of
independet is
answer
The
(d)new
�
R
From textbook
15 pts for correct setup
4 pts for correct concept &
answer
2pts 2pts 2pts
Problem 3 (25 points)
A large w
ooden turntable in the shape of a flat uniform disk has a radius of R
= 2.00 m and a total
mass of M
= 120.0 kg. The turntable is initially rotating at �� = 3.00 rad/s about a vertical axis though its center. Suddenly, a m
= 70.0-kg parachutist makes a soft landing on the turntable at a point near
the outer edge. (a) (15 pts) find the angular speed of the turntable after the parachutist lands. Assum
e that you can treat the parachutist as a particle. (b) (10 pts) com
pute the kinetic energy of the system
before and after the parachutist lands. Why are these kinetic energies not equal?
Problem 3 (25 points) – C
hapter 10 A
large wooden turntable in the shape of a flat uniform
disk has a radius of R = 2.00 m
and a total m
ass of M = 120.0 kg. The turntable is initially rotating at �� = 3.00 rad/s about a vertical axis though
its center. Suddenly, a m = 70.0-kg parachutist m
akes a soft landing on the turntable at a point near the outer edge. (a) (15 pts) find the angular speed of the turntable after the parachutist lands. A
ssume
that you can treat the parachutist as a particle. (b) (10 pts) compute the kinetic energy of the system
before and after the parachutist lands. W
hy are these kinetic energies not equal?
15 pts
2pts off per major m
istake
10 pts
Problem 4 (25 points)
A loaded cement m
ixer truck drives onto an old drawbridge (length of L = 40.0 m
and mass of M
B = 18,000 kg), w
here it stalls with its center of gravity three-quarters of the w
ay across the span. The truck driver sets the handbrake. Then the bridge is raised by m
eans of a cable attached to the end opposite to the hinge. The truck w
ith the driver has a mass of M
T = 30,000 kg. When the bridge has
been raised to an angle of 30.0o above the horizontal, the cable m
akes an angle of 70.0o w
ith the surface of the bridge. (a) W
hat is the tension T in the cable when the bridge is held in the position.
(b) What are the horizontal and vertical com
ponents of the force the hinge exerts on the span?
Problem 4 (25 points) – C
hapter 11 A loaded cem
ent mixer truck drives onto an old draw
bridge (length of L = 40.0 m and m
ass of MB =
18,000 kg), where it stalls w
ith its center of gravity three-quarters of the way across the span. The
truck driver sets the handbrake. Then the bridge is raised by means of a cable attached to the end
opposite to the hinge. The truck with the driver has a m
ass of MT = 30,000 kg. W
hen the bridge has been raised to an angle of 30.0
o above the horizontal, the cable makes an angle of 70.0
o with the
surface of the bridge. (a) What is the tension T in the cable w
hen the bridge is held in the position. (b) W
hat are the horizontal and vertical components of the force the hinge exerts on the span?
15 pts
2pts off per major m
istake
10 pts
Pro
blem
1
A w
ire of length l0 and cross-sectional area A supports a hanging w
eight W. (a) Show
that if the wire obeys H
ooke’s law, behaving like
a spring of force constant AY/l0 , where Y is Y
oung’s modulus for the
material of w
hich the wire is m
ade. (b) What w
ould the force constant be for a 75.0-cm
length of 16-gauge (diameter = 1.291 m
m) copper
wire? See Table 11.1. (c) W
hat would W
have to be to stretch the wire
in part (b) by 1.25 mm
?
11
Pro
blem
1 S
olu
tion
A
wire of length l0 and cross-sectional area A supports a hanging
weight W
. (a) Show that if the w
ire obeys Eq. (11.7), it behaves like a spring of force constant AY/l0 , w
here Y is Young’s m
odulus for the m
aterial of which the w
ire is made. (b) W
hat would the force constant
be for a 75.0-cm length of 16-gauge (diam
eter = 1.291 mm
) copper w
ire? See Table 11.1. (c) What w
ould W have to be to stretch the w
ire in part (b) by 1.25 m
m?
22
Pro
blem
2
In lab tests on a 9.25-cm cube 0f a certain
material, a force of 1375 N
directed at 8.50o to
the cube causes the cube to deform through an
angle of 1.24o. W
hat is the shear modulus of
the material?
33
���
�tan
h x
��
S = (F|| /A
)/(x/h).
Pro
blem
2 S
olu
tion
In lab tests on a 9.25-cm
cube 0f a certain m
aterial, a force of 1375 N directed at 8.50
o to the cube causes the cube to deform
through an angle of 1.24
o. What is the shear m
odulus of the m
aterial?
44
[11.38]
���
�tan
h xS = (F
|| /A)/(x/h).
A. m
ore stress and more strain.
B. the sam
e stress and more strain.
C. the sam
e stress and less strain.
D. less stress and less strain.
E. the sam
e stress and the same
strain.
Q11.5 Tw
o rods are made of the
same kind of steel and have
the same diam
eter. F
F
length 2L
F
F
length L
A force of magnitude F is applied to the end of each rod.
Com
pared to the rod of length L, the rod of length 2L has
5
Y = (F� /A
)(l0 /�l)
A. m
ore stress and more strain.
B. the sam
e stress and more strain.
C. the sam
e stress and less strain.
D. less stress and less strain.
E. the sam
e stress and the same
strain.
A11.5 Tw
o rods are made of the
same kind of steel and have
the same diam
eter. F
F
length 2L
F
F
length L
A force of magnitude F is applied to the end of each rod.
Com
pared to the rod of length L, the rod of length 2L has
6
Y = (F� /A
)(l0 /�l)
A. m
ore stress and more strain.
B. the sam
e stress and more strain.
C. the sam
e stress and less strain.
D. less stress and less strain.
E. the sam
e stress and the same
strain.
Q11.6 Tw
o rods are made of the
same kind of steel. T
he longer rod has a greater diam
eter. F
F
length 2L
F
F
length L
A force of magnitude F is applied to the end of each rod.
Com
pared to the rod of length L, the rod of length 2L has
7
Y = (F� /A
)(l0 /�l)
A. m
ore stress and more strain.
B. the sam
e stress and more strain.
C. the sam
e stress and less strain.
D. less stress and less strain.
E. the sam
e stress and the same
strain.
A11.6 Tw
o rods are made of the
same kind of steel. T
he longer rod has a greater diam
eter. F
F
length 2L
F
F
length L
A force of magnitude F is applied to the end of each rod.
Com
pared to the rod of length L, the rod of length 2L has
8
Y = (F� /A
)(l0 /�l)
Oscillations
11
Oscillations
xm k
ax
�
�x
kF
x
���
An
alyzin
g Sprin
g+B
lock
System
vmax , a
x =0
Mechanical Energy Conservation
2
Oscillations
Con
cepts o
f S.H
.M..
Dynam
ics & Kinematics
Spring+block �
F = m
a & (x, v, a)
Pendulum
� a part of circular m
otion���� =
I ���& (�, �, �)
Force: C
onservative force R
estoring force
Conservation:�
K + U = constant
+ S.H.M
. (��as angular frequency)
3
Oscillations
Example 2(A
)
+
+
+
+
+ 0
T/4
T/2
3T/4
T
Equilibrium
Positions
A
4
Oscillations
Example 2(B
)
Ea = E
b = Ec = E
d
5
Oscillations
Example 5
You holdthe block
at x = A (= 0.030 m
) by applying 6.0 N
. T
hen, the block was
released.
The m
otion of the block undergoes SHM
. C
an you show that a = –(k/m
) x ? A
lso find: (a) k
(b)��
(c) T
(d) vm
ax (where?, w
hen?)
(e) x, v and a at t = 2 sec
k 0.50 kg
6
An object on the end of a spring is oscillating in simple
harmonic m
otion. If the amplitude of oscillation is doubled,
how does this affect the oscillation period T and the object’s
maxim
um speed v
max ?
A. T and vm
ax both double.
B. T remains the sam
e and vm
ax doubles.
C. T and vm
ax both remain the sam
e.
D. T doubles and v
max rem
ains the same.
E. T remains the sam
e and vm
ax increases by a factor of
Q14.1
2.
An object on the end of a spring is oscillating in simple
harmonic m
otion. If the amplitude of oscillation is doubled,
how does this affect the oscillation period T and the object’s
maxim
um speed v
max ?
A. T and vm
ax both double.
B. T remains the sam
e and vm
ax doubles.
C. T and vm
ax both remain the sam
e.
D. T doubles and v
max rem
ains the same.
E. T remains the sam
e and vm
ax increases by a factor of .
A14.1
2.
This is an x-t graph for an object in sim
ple harmonic
motion.
A. t = T/4
B. t = T/2
C. t = 3T/4
D. t =
T
Q14.2
At which of the follow
ing times does the object have the
most negative velocity v
x ?
This is an x-t graph for an object in sim
ple harmonic
motion.
A. t = T/4
B. t = T/2
C. t = 3T/4
D. t =
T
A14.2
At which of the follow
ing times does the object have the
most negative velocity v
x ?
This is an x-t graph for an object in sim
ple harmonic
motion.
A. t = T/4
B. t = T/2
C. t = 3T/4
D. t =
T
Q14.3
At which of the follow
ing times does the object have the
most negative acceleration a
x ?
This is an x-t graph for an object in sim
ple harmonic
motion.
A. t = T/4
B. t = T/2
C. t = 3T/4
D. t =
T
A14.3
At which of the follow
ing times does the object have the
most negative acceleration a
x ?
A.t = T/8
B.t = T/4
C. t = 3T/8
D. t = T/2
E. more than one of the above
This is an x-t graph for an object connected to a spring and m
oving in sim
ple harmonic
motion.
Q14.6
At which of the follow
ing times is the potential
energy of the spring the greatest?
This is an x-t graph for an object connected to a spring and m
oving in sim
ple harmonic
motion.
A14.6
At which of the follow
ing times is the potential
energy of the spring the greatest?
A.t = T/8
B.t = T/4
C. t = 3T/8
D. t = T/2
E. more than one of the above
A.t = T/8
B.t = T/4
C. t = 3T/8
D. t = T/2
E. more than one of the above
This is an x-t graph for an object connected to a spring and m
oving in sim
ple harmonic
motion.
Q14.7
At which of the follow
ing times is the kinetic
energy of the object the greatest?
A.t = T/8
B.t = T/4
C. t = 3T/8
D. t = T/2
E. more than one of the above
This is an x-t graph for an object connected to a spring and m
oving in sim
ple harmonic
motion.
A14.7
At which of the follow
ing times is the kinetic
energy of the object the greatest?
To double the total energy of a mass-spring
system oscillating in sim
ple harmonic m
otion, the am
plitude must increase by a factor of
A. 4.
B.
C. 2.
D.
E.
Q14.8
�2
1.414.
�42
1.189.
�2
22.828.
A. 4.
B.
C. 2.
D.
E.
To double the total energy of a mass-spring
system oscillating in sim
ple harmonic m
otion, the am
plitude must increase by a factor of
A14.8
�2
1.414.
�42
1.189.
�2
22.828.
A simple pendulum
consists of a point mass
suspended by a massless, unstretchable string.
If the mass is doubled w
hile the length of the string rem
ains the same, the period of the
pendulum
A. becomes 4 tim
es greater.
B. becomes tw
ice as great.
C. becomes greater by a factor of .
D. rem
ains unchanged.
E. decreases.
Q14.9
2
A simple pendulum
consists of a point mass
suspended by a massless, unstretchable string.
If the mass is doubled w
hile the length of the string rem
ains the same, the period of the
pendulum
A. becomes 4 tim
es greater.
B. becomes tw
ice as great.
C. becomes greater by a factor of .
D. rem
ains unchanged.
E. decreases.
A14.9
2
This is an ax -t graph
for an object in sim
ple harmonic
motion.
A. t = 0.10 s
B. t = 0.15 s
C. t = 0.20 s
D. t =
0.25 s
Q14.4
At which of the follow
ing times does the object have the
most negative displacem
ent x?
This is an ax -t graph
for an object in sim
ple harmonic
motion.
A. t = 0.10 s
B. t = 0.15 s
C. t = 0.20 s
D. t =
0.25 s
A14.4
At which of the follow
ing times does the object have the
most negative displacem
ent x?
This is an ax -t graph
for an object in sim
ple harmonic
motion.
A. t = 0.10 s
B. t = 0.15 s
C. t = 0.20 s
D. t =
0.25 s
Q14.5
At which of the follow
ing times does the object have the
most negative velocity v
x ?
This is an ax -t graph
for an object in sim
ple harmonic
motion.
A. t = 0.10 s
B. t = 0.15 s
C. t = 0.20 s
D. t =
0.25 s
A14.5
At which of the follow
ing times does the object have the
most negative velocity v
x ?
Oscillations
2 25
Oscillations
2 26