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7/23/2019 Presentation Simplex
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Maarten Abbink (TU Delft) Beamer Sample April 1, 2014 1 / 16
Sample presentation using BeamerDelft University of Technology
Maarten Abbink
April 1, 2014
7/23/2019 Presentation Simplex
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Outline
1 First SectionSection 1 - Subsection 1Section 1 - Subsection 2Section 1 - Subsection 3
2 Second SectionSection 2 - Subsection 1Section 2 - Last Subsection
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Next Subsection
1 First SectionSection 1 - Subsection 1Section 1 - Subsection 2Section 1 - Subsection 3
2 Second SectionSection 2 - Subsection 1Section 2 - Last Subsection
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Section 1 - Subsection 1 - Page 1
Example
0 1 2 3 4 5 6 7 8n
0123
456u(n)
u(n) = [3, 1, 4]n
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Section 1 - Subsection 1 - Page 2
DefinitionLet n be a discrete variable, i.e. n Z. A 1-dimensional periodicnumber is a function that depends periodically on n.
u(n) = [u0, u1, . . . , ud1]n =
u0 ifn 0 (mod d)
u1 ifn 1 (mod d)...
ud1 ifn d 1 (mod d)
d is called the period.
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Section 1 - Subsection 1 - Page 3
Example
f(n) =
12 , 13nn2 + 3n [1, 2]n
=
13 n
2 + 3n 2 ifn 0 (mod 2)
12 n2 + 3n 1 ifn 1 (mod 2)
0 1 2 3 4 5 6 7n
3
2
1
0
1
2
3
4
5
f(n)=
1 2
,1 3
n
n2
+
3n
[1,
2]n
1
2n2 + 3n 1
1
3n2 + 3n 2
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Section 1 - Subsection 1 - Page 4
Definition
A polynomial in a variable xis a linear combination of powers ofx:
f(x) =
gi=0
cixi
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Section 1 - Subsection 1 - Page 4
Definition
A polynomial in a variable xis a linear combination of powers ofx:
f(x) =
gi=0
cixi
DefinitionA quasi-polynomial in a variable x is a polynomial expression withperiodic numbers as coefficients:
f(n) =
g
i=0 u
i(n)n
i
with ui(n) periodic numbers.
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Next Subsection
1 First SectionSection 1 - Subsection 1Section 1 - Subsection 2Section 1 - Subsection 3
2 Second SectionSection 2 - Subsection 1Section 2 - Last Subsection
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Section 1 - Subsection 2 - Page 1
Example
0 1 2 3 4 5 6 7x
0
1
2
3
4
5
6
7
y
p =3
x+yp
p f(p)
3 5
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Section 1 - Subsection 2 - Page 1
Example
0 1 2 3 4 5 6 7x
0
1
2
3
4
5
6
7
y
p =4
x+yp
p f(p)
3 54 8
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Section 1 - Subsection 2 - Page 1
Example
0 1 2 3 4 5 6 7x
0
1
2
3
4
5
6
7
y
p =5
x+yp
p f(p)
3 54 85 10
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Section 1 - Subsection 2 - Page 1
Example
0 1 2 3 4 5 6 7x
0
1
2
3
4
5
6
7
y
p =6
x+yp
p f(p)
3 54 85 106 13
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Section 1 - Subsection 2 - Page 1
Example
0 1 2 3 4 5 6 7x
0
1
2
3
4
5
6
7
y
p =6
x+yp
p f(p)
3 54 85 106 13
5
2p+
2,
5
2
p
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Section 1 - Subsection 2 - Page 2
The number of integer points in a parametric polytope Pp ofdimension n is expressed as a piecewise a quasi-polynomial ofdegree n in p(Clauss and Loechner).
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Section 1 - Subsection 2 - Page 2
The number of integer points in a parametric polytope Pp ofdimension n is expressed as a piecewise a quasi-polynomial ofdegree n in p(Clauss and Loechner).
More generalpolyhedral counting problems:
Systems of linear inequalities combined with ,,,,or (Presburger formulas).
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Section 1 - Subsection 2 - Page 2
The number of integer points in a parametric polytope Pp ofdimension n is expressed as a piecewise a quasi-polynomial ofdegree n in p(Clauss and Loechner).
More generalpolyhedral counting problems:
Systems of linear inequalities combined with ,,,,or (Presburger formulas).
Many problems instatic program analysiscan be expressed aspolyhedral counting problems.
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S
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Next Subsection
1 First SectionSection 1 - Subsection 1Section 1 - Subsection 2Section 1 - Subsection 3
2 Second SectionSection 2 - Subsection 1Section 2 - Last Subsection
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S i 1 S b i 3 P 1
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Section 1 - Subsection 3 - Page 1A picture made with the package TiKz
Example
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N t S b ti
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Next Subsection
1 First SectionSection 1 - Subsection 1Section 1 - Subsection 2Section 1 - Subsection 3
2 Second SectionSection 2 - Subsection 1Section 2 - Last Subsection
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S ti 2 b ti 1 1
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Section 2 - subsection 1 - page 1
AlertblockThis page gives an example with numbered bullets (enumerate)in an Example window:
Example
Discrete domain evaluate in each pointNot possible for
1 parametric domains
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S ti 2 b ti 1 1
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Section 2 - subsection 1 - page 1
AlertblockThis page gives an example with numbered bullets (enumerate)in an Example window:
Example
Discrete domain evaluate in each pointNot possible for
1 parametric domains
2 large domains (NP-complete)
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Ne t S b e ti
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Next Subsection
1 First SectionSection 1 - Subsection 1Section 1 - Subsection 2Section 1 - Subsection 3
2 Second SectionSection 2 - Subsection 1Section 2 - Last Subsection
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Last Page
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Last Page
Summary
End of the beamer demowith a tidyTU Delft lay-out.
Thank you!
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