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Current Transformers
Sreenatha Rao R.S.N.V
Manager Training
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> Current Transformers January 20043 3
Current Transformer Function
Reduce power system current to lower value formeasurement.
Insulate secondary circuits from the primary.
Permit the use of standard current ratings for secondaryequipment.
REMEMBER :
The relay performance DEPENDS on the C.T which
drives it !
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Instrument Transformer Standards
IEC IEC 185:1987 CTsIEC 44-6:1992 CTs
IEC 186:1987 VTs
EUROPEAN BS 7625 VTs
BS 7626 CTs
BS 7628 CT+VT
BRITISH BS 3938:1973 CTs
BS 3941:1975 VTs
AMERICAN ANSI C51.13.1978 CTs and VTs
CANADIAN CSA CAN3-C13-M83 CTs and VTs
AUSTRALIAN AS 1675-1986 CTs
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Polarity
P2P1
Is
S2S1
Ip
Inst. Current directions :-
P1 P2
S1 S2 Externally
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Flick Test
P1
S1
+
V
-
S2
P2
I
sIpFWD kick on application,
REV kick on removal oftest lead.
Battery (6V) + to P1
AVO +ve lead to S1
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Basic Theory
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Basic Theory (1)
IP
IS
R
1 Primary TurnN Secondary Turns
For an ideal transformer :-
PRIMARY AMPERE TURNS = SECONDARY AMPERE TURNS
IP = N x IS
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Basic Theory (2)
IP
IS
RES
For IS to flow through R there must be some potential -ES = the E.M.F.
ES = IS x R
ES is produced by an alternating flux in the core.
ES ddt
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Basic Formulae
Circuit Voltage Required :
ES = IS (ZB + ZCT + ZL) Volts
where :-
IS = Secondary Current of C.T. (Amperes)
ZB = Connected External Burden (Ohms)
ZCT = C.T Winding Impedance (Ohms)
ZL = Lead Loop Resistance (Ohms)
Require EK > ES
L R D i
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Low Reactance Design
With evenly distributed winding the leakage
reactance is very low and usually ignored.
Thus ZCT ~ RCT
K P i t V lt D fi iti
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> Current Transformers January 200413 13
Knee-Point Voltage Definition
Iek
+10% Vk
+50% Iek
Vk
Exciting Current (Ie)
E
xcitingV
oltage(V
S)
C T E i l t Ci it
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> Current Transformers January 200414 14
C.T. Equivalent Circuit
ZbN
P1
ZCT
S1
VtZe
Is
Ip
Ip/N Ie
Es
Ip = Primary rating of C.T. Ie = Secondary excitation current
N = C.T. ratio Is = Secondary current
Zb = Burden of relays in ohms Es = Secondary excitation voltage
(r+jx) Vt = Secondary terminal voltageZCT = C.T. secondary winding across the C.T. terminals
impedance in ohms (r+jx)
Ze = Secondary excitationimpedance in ohms (r+jx)
Ph Di
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> Current Transformers January 200415 15
Phasor Diagram
IcEp
Ip/N
Ie
IsIe
Im
Es
Ep = Primary voltage Im = Magnetising current
Es = Secondary voltage Ie = Excitation current
= Flux Ip = Primary current
Ic = Iron losses (hysteresis & Is = Secondary currenteddy currents)
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> Current Transformers January 200416 16
Saturation
Steady State Saturation (1)
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> Current Transformers January 200417 17
Steady State Saturation (1)
100A
100/1
1A
E 1 ohm
E =1V
100A
100/1
1A
E10ohm E =
10V
100A
100/1
1A
E 100ohm
E =100V
100A
100/1
1A
E1000ohm
E = ?
Steady State Saturation (2)
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> Current Transformers January 200418 18
Steady State Saturation (2)
Time
+V
-V
0VA
Assume :- Zero residual flux
Switch on at point A
Steady State Saturation (3)
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> Current Transformers January 200419 19
Steady State Saturation (3)
Time
+V
-V
0VC
Assume :- Zero residual flux
Switch on at point C
Steady State Saturation (4)
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> Current Transformers January 200420 20
Steady State Saturation (4)
Time
+V
-V
0VB
Assume :- Zero residual flux
Switch on at point B
Steady State Saturation (5)
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> Current Transformers January 200421 21
Steady State Saturation (5)
Mag CoreSaturation
+V
-V
0V
Mag CoreSaturation
Time
Steady State Saturation (6)
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> Current Transformers January 200422 22
Steady State Saturation (6)
Time
+V
-V
0V
+V
-V
0V
Mag CoreSaturation
Mag CoreSaturation
Output lost due tosteady statesaturation
Actual Output
Voltage
ProspectiveOutput Voltage
Transient Saturation
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> Current Transformers January 200423 23
Transient Saturation
L1R1
Z1
i1
v = VM sin (wt + )
v = VM sin (wt + )
TRANSIENTSTATESTEADY
e.)-(sin-)-(wtsin
e.)-(sinZ
V)-(wtsin
Z
Vi
1L/t1R-11
1L/t1R-
1
M
1
M1
+=
++=
=++=
1
M1
1
11-
12
11
Z
V
R
wLtan
LwRZ-:where
=
=
+=
22
Transient Saturation : Resistive Burden
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> Current Transformers January 200424 24
Transient Saturation : Resistive Burden
FLUX
CURRENT
Primary CurrentSecondary Current
Actual Flux
Mag Current
Required Flux
SAT
0
010 20 30 40 50 60 70 80 M
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> Current Transformers January 200425 25
CT Types
Current Transformer Function
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> Current Transformers January 200426 26
Two basic groups of C.T.
Measurement C.T.s
Limits well defined
Protection C.T.s
Operation over wide range of currents
Note : They have DIFFERENT characteristics
Measuring C.T.s
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> Current Transformers January 200427 27
g
B
Protection C.T.
Measuring C.T.
H
Measuring C.T.s Require good accuracy up to
approx 120% rated current.
Require low saturation level toprotect instruments, thus use
nickel iron alloy core with low
exciting current and knee
point at low flux density.
Protection C.T.s
Accuracy not as important as
above.
Require accuracy up to many
times rated current, thus use
grain orientated silicon steel
with high saturation flux
density.
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Current Transformer Ratings (1)
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> Current Transformers January 200429 29
g ( )
Rated Burden
Value of burden upon which accuracy claims are based
Usually expressed in VA
Preferred values :-
2.5, 5, 7.5, 10, 15, 30 VA
Continuous Rated Current
Usually rated primary current
Short Time Rated Current
Usually specified for 0.5, 1, 2 or 3 secs
No harmful effects Usually specified with the secondary shorted
Rated Secondary Current
Commonly 1, 2 or 5 Amps
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Choice of Ratio
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> Current Transformers January 200431 31
Clearly, the primary rating
IP normal current in the circuit
if thermal (continuous) rating is not to be exceeded.
Secondary rating is usually 1 or 5 Amps (0.5 and 2 Amp are
also used).
If secondary wiring route length is greater than 30 metres -1 Amp secondaries are preferable.
A practical maximum ratio is 3000 / 1.
If larger primary ratings are required (e.g. for largegenerators), can use 20 Amp secondary together with
interposing C.T.
e.g. 5000 / 20 - 20 / 1
Current Transformer Designation
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> Current Transformers January 200432 32
Class P
Specified in terms of :-
i) Rated burden
ii) Class (5P or 10P)
iii) Accuracy limit factor (A.L.F.)
Example :-
15 VA 10P 20
To convert VA and A.L.F. into useful volts
Vuseful VA x ALF
IN
BS 3938
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> Current Transformers January 200433 33
Classes :- 5P, 10P. X
Designation (Classes 5P, 10P)
(Rated VA) (Class) (ALF)
Mult iple of rated current (IN) up to which declared
accuracy will be maintained with rated burden
connected.
5P or 10P.
Value of burden in VA on which accuracy claims
are based.
(Preferred values :- 2.5, 5, 7.5, 10, 15, 30 VA)
ZB = rated burden in ohms
= Rated VAIN
2
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> Current Transformers January 200434 34
Interposing CT
Interposing CT
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> Current Transformers January 200435 35
NP NS ZB
ZCT
LINE
CT
Burden presented to line CT
= ZCT + ZB x NP2
NS2
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> Current Transformers January 200437 37
Current Transformer Designation
Current Transformer Designation
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> Current Transformers January 200438 38
Class X
Specified in terms of :-
i) Rated Primary Current
i i) Turns Ratio (max. error = 0.25%)
iii) Knee Point Voltage
iv) Mag Current (at specified voltage)
v) Secondary Resistance (at 75C)
Choice of Current Transformer
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> Current Transformers January 200439 39
Instantaneous Overcurrent Relays
Class P Specif ication
A.L.F. = 5 usually sufficient
For high settings (5 - 15 times C.T rating)
A.L.F. = relay setting
IDMT Overcurrent Relays
Generally Class 10P
Class 5P where grading is critical
Note : A.L.F. X V.A < 150
Differential Protection
Class X Specif ication
Protection relies on balanced C.T output
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> Current Transformers January 200440 40
Selection Example
Burden on Current Transformers
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> Current Transformers January 200441 41
1. Overcurrent : RCT + RL + Rr 2. Earth : RCT + 2RL + 2Rr
RCT
RCT
RCT
IF
IFRLRL RLRL
Rr Rr RrRr
RCT
RCT
RCT
IF
IF RLRL RLRL
Rr Rr RrRr
Overcurrent Relay VK Check
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> Current Transformers January 200442 42
Assume values : If max = 7226 A RCT = 0.26C.T = 1000 / 5 A Rr = 0.02
7.5 VA 10P 20 RL = 0.15
Check to see if VK is large enough :
Required voltage = VS = IF (RCT + Rr + RL)
= 7226 x 5 (0.26 + 0.02 + 0.15) = 36.13 x 0.43 = 15.54 Volts
1000
Current transformer VK approximates to :-
VK VA x ALF + RCT x IN x ALF
In
= 7.5 x 20 + 0.26 x 5 x 20 = 56 Volts
5
VK > VS therefore C.T VK is adequate
Earth Fault Relay VK Check
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> Current Transformers January 200443 43
Assume values : As per overcurrent.
Note For earth fault applications require to be able to pass
10 x relay setting.
Check to see if VK is large enough : VK = 56 Volts
Total load connected = 2RL + RCT + 2Rr= 2 x 0.15 + 0.26 + 2 x 0.02
Maximum secondary current= 56 = 93.33A
0.6
Typical earth fault setting = 30% IN= 1.5A
Therefore C.T can provide > 60 x setting
C.T VK is adequate
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> Current Transformers January 200444 44
Voltage Transformers
Voltage Transformers
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> Current Transformers January 200445 45
Provides isolation from high voltages
Must operate in the linear region to prevent
accuracy problems - Do not over specify VT
Must be capable of driving the burden, specified by
relay manufacturer
Protection class VT wil l suffice
Typical Working Points on a B-H Curve
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> Current Transformers January 200446 46
Flux DensityB
Magnetising ForceAT/m
Power Transformers
Saturation
V.T.s
Protection C.T. (at full load)H
1000 2000 3000
1.6
1.0
0.5
Tesla
Types of Voltage Transformers
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> Current Transformers January 200447 47
Two main basic types are available:
Electromechanical VT`s
Similar to a power transformer
May not be economical above 132kV
Capacitor VT`s (CVT)
Used at high voltages
Main difference is that CVT has a
capacitor divider on the front end.
Electromagnetic Voltage Transformer
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> Current Transformers January 200448 48
ZB(burden)
NP / NS= K
n
VP
RP
IP
LP
LM
IM IC
Re VSEP = ES
Ie
RS
IS
LS
Basic Circuit of a Capacitor V.T.
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> Current Transformers January 200449 49
C1
C2
VP
VC2 Vi
L
T
VSZB
Ferro-resonance
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> Current Transformers January 200450 50
The exciting impedance of auxil iary transformer T and the
capacitance of the potential divider form a resonant circuit.
May oscillate at a sub normal frequency
Resonant frequency close to one-third value of system
frequency
Manifests itself as a rise in output voltage, r.m.s. value
being 25 to 50 per cent above normal value
Use resistive burden to dampen the effect
VT Earthing
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> Current Transformers January 200451 51
Primary Earthing
Earth at neutral point
Required for phase-ground measurement at relay
Secondary Earthing
Required for safety
Earth at neutral point
No relevance for protection operation
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VT Connections
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> Current Transformers January 200453 53
a b c
a b cA B C N
da dn
a b c n
V ConnectedBroken Delta
VT Construction - Residual
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> Current Transformers January 200454 54
Used to detect earthfault
Useful where current operated protection cannot beused
Connect all secondary windings in series
Sometimes referred to as `Broken Delta`
Residual Voltage is 3 times zero sequence voltage
VT must be 5 Limb or 3 single phase units
Primary winding must be earthed
Voltage Factors Vf
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> Current Transformers January 200455 55
Vfis the upper limit of operating voltage.
Important for correct relay operation.
Earthfaults cause displacement of system neutral,
particularly in the case of unearthed or impedance
earthed systems.
Protection of VTs
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> Current Transformers January 200456 56
H.R.C. Fuses on primary side
Fuses may not have sufficient interrupting capabil ity
Use MCB
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