62
Prepared by: Assoc. Prof. Dr Bahaman Abu Samah Department of Professional Development and Continuing Education Faculty of Educational Studies Universiti Putra Malaysia Serdang

Prepared by: Assoc. Prof. Dr Bahaman Abu Samahpsm.upm.edu.my/5950/LearningMaterials/5950 P15 Simple...2 6 66 10 3 9 94 4 10 98 5 8 87 6 7 72 7 5 45 8 6 63 Σ9 7.5 85 10 5 77 Summary

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Page 1: Prepared by: Assoc. Prof. Dr Bahaman Abu Samahpsm.upm.edu.my/5950/LearningMaterials/5950 P15 Simple...2 6 66 10 3 9 94 4 10 98 5 8 87 6 7 72 7 5 45 8 6 63 Σ9 7.5 85 10 5 77 Summary

Prepared by:

Assoc. Prof. Dr Bahaman Abu Samah Department of Professional Development and Continuing Education

Faculty of Educational Studies

Universiti Putra Malaysia

Serdang

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– An extension to Pearson correlation analysis

– Used to:

1. Determine relationship between

variables

2. Make prediction

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– Regression analysis is a parametric statistic

– To apply regression analysis

1. DV must be interval or ratio

2. IV must also be interval or ratio.

– If IV is non-metric, need to transform into

dummy variable (assign as 0 and 1)

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To apply regression analysis

1. The independent and dependent variables

are bivariately normally distributed in the

population

2. The cases represents a random sample from

the population

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Derive regression/

prediction equation

Hypothesis Testing

Regression

Model Slope

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22

1

n

XX

n

YXXY

SSX

SXYb

)(

)()(

xbyb 10

Y 0b 11 Xb

– Calculate b1 and b0

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21 884.184.533.7ˆ XXY

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Regression Model

Slope

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Regression equation: Ŷ = b0 + b1X1 + b2X2

Multiple correlation coefficient (R)

Coefficient of Determination (R2)

Descriptive

Inferential

Components of

Hypothesis Tests:

Assessing Regression Model-Fit

Assessing the Predictor Variable (Slope)

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Regression Model

HO: Y = β0 + ei

HA: Y = β0 + β1X1 + ei

Slope

HO: β1 = 0

HA: β1 ≠ 0

β1 > 0

β1 < 0

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– Equation of a straight line:

Y = mx + c

– Regression assumes a linear relationship

between variables

– Regression equation:

Yi = b0 + b1Xi + i

Y

X

b1

b0 ΔX

ΔY

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Average assignment scores

1110987654

Te

st

sco

res

100

90

80

70

60

50

40

A plot of paired observations of X and Y

The best fit line

Use the least squares

method to identify the

line

The line is called the

least squares

regression line

This method will

minimize SSE

Which one is the

best-fit line?

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The line that minimize the sum of squared difference

● ●

● ●

+

+

+

+

-

-

-

-

-

Y

X

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Regression Analysis Steps in

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– Calculate b1

22

1

n

XX

n

YXXY

SSX

SXYb

)(

)()(

xbyb 10

– Calculate b0

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XbbY 10 ˆ

– Present the regression/prediction equation

Y

X

b1

b0 ΔX

ΔY

Predicted value of Y

b0 Y-intercept

b1 Slope (regression

coefficient)

Y

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– Once you have determined the best fit line,

you may want to assess how well the line fits

the actual data

– You are assessing the Goodness-of-Fit of

the regression model

– Use F-ratio to test on the regression model

fit

– Calculate three sum of squares:

1. Sum of square Total

2. Sum of square Regression

3. Sum of square Residual/Error

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● ●

● ●

● Y

X SST

● ●

● ●

● Y

X

SSR

● ●

● ●

● ●

Y

X SSE

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SST uses the differences between the observed

data and the mean value of Y

SST = Σ (Y - )2 Y

●●

●●

●YY

XX

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● ●

●●

YY

XX

●●

SSE uses the differences between the observed

data and the regression line

SSE = Σ (Y - )2 Y

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SSR uses the differences between the mean

value of Y and the regression line

SSR = Σ ( )2 YY ˆ

●●

●●

●YY

XX

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– The basic approach to predict outcome ( ) is

to use mean

– If the value of SSR is large, the regression

model produces better improvement in the

prediction over use of mean

– If the value of SSR is small, the regression is

no better than using mean

– Coefficient of determination, R2 is a measure

of proportion of improvement due to the

regression model

Y

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– Indicated the proportion of improvement due

to the regression model

– R2 ranges between 0 to 1

– To express as percentage, multiply R2 by 100

– Constitute the amount of variance in the

dependent variable explained by the model

OR independent variable

– Formula to calculate R2:

SST

SSRR 2

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1. State the null and alternative hypotheses:

HO: Y = β0 + ei

HA: Y = β0 + β1X1 + ei

2. Calculate the test statistics

F-ratio

3. Determine critical value

4. Decision making

5. Conclusion

Steps in Hypothesis test:

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1. Calculate Sum of Squares

a. Total sum of squares

b. Regression sum of squares

c. Error (Residual) sum of squares

22

n

YYSST

)(

2

SSX

SXYSSR

)(

SSRSSTSSE

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2. Calculate Degrees of Freedom (df)

a. Regression

dfReg = p

b. Error (Residual)

dfError = n – p – 1

c. Total

dfTotal = n – 1

3. Calculate Mean Squares

a. Mean squares Regression (MSR)

b. Mean squares Error (MSE)

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4. Prepare Summary ANOVA Table

Source SS df MS F

Regression

Error

Total

MSE

MSRSSR p MSR

SSE n-p-1 MSE

SST n-1

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)(ppnF 1

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Criteria Decision

Fcal > Fcritical Reject HO

Fcal ≤ Fcritical Fail to reject HO

Manual

Criteria Decision

Sig-F < α Reject HO

Sig-F ≥ α Fail to reject HO

SPSS

Decision Criteria:

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Reject HO:

Regression model fits the data

(or there is a significant relationship

between X and Y)

Fail to reject HO:

Regression model does not fit data

(or there is no significant relationship

between X and Y)

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From the Summary ANOVA table:

Coefficient of determination, R2

SST

SSRR 2

Multiple correlation

coefficient, R

2RR

SSY

SXYbR

)(1

Amount of variance in Y

explained by X

Ranges: 0 ≤ R2 ≤ 1

Relationship between

X and Y

Ranges: 0 ≤ R ≤ 1

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– Test on the regression coefficient (b1) or Slope

i.e. Testing contribution of X on Y

– b1 represents the change in Y resulting from a

unit change in X

– Use t-test for the hypothesis test

– Steps in hypothesis testing

1. Hypotheses

HO: β1 = 0

HA: β1 ≠ 0

β1 > 0

β1 < 0

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1. State the null and alternative hypotheses

2. Calculate the test statistics

t-value

3. Determine critical value

4. Decision making

5. Conclusion

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HO: β1 = 0

HA: β1 ≠ 0

β1 > 0

β1 < 0

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SSX

MSE

bt 11

Summary ANOVA Table

Source SS df MS F

Regression

Error

Total

MSE

MSRSSR p MSR

SSE n-p-1 MSE

SST n-1

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dfdf

tORt ,,

2

df = n - 2

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Criteria Decision

|tcal| > |tcritical| Reject HO

|tcal| ≤ |tcritical| Fail to reject HO

Manual

Criteria Decision

Sig-t < α Reject HO

Sig-t ≥ α Fail to reject HO

SPSS

Decision Criteria:

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Reject HO:

There is significant contribution of X

towards Y (or there is a significant

relationship between X and Y)

Fail to reject HO:

There is no significant contribution of

X towards Y (or there is no significant

relationship between X and Y)

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Example 1:

Data were collected from a randomly selected sample to

determine relationship between average assignment scores

and test scores in statistics. Distribution for the data is

presented in the table below. Data set:

Scores

ID Assign Test

1 8.5 88

2 6 66

3 9 94

4 10 98

5 8 87

6 7 72

7 5 45

8 6 63

9 7.5 85

10 5 77

Data: 5950 SL Regression 1 Class

1. Calculate b1 and b0 and

derive the prediction equation

2. Test the hypothesis for the

regression model at α = .05

3. Calculate coefficient of

determination and multiple

correlation coefficient.

Interpret the two values.

4. Test hypothesis for the slope

at .05 level of significance.

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1. Derive Regression/Prediction equation

ID X Y

1 8.5 88

2 6 66

3 9 94

4 10 98

5 8 87

6 7 72

7 5 45

8 6 63

9 7.5 85

10 5 77

Summary stat:

n 10

ΣX 72

ΣY 775

ΣX2 544.5

ΣY2 62,441

ΣXY 5,795.5

xy 257.805.18ˆ

Prediction equation:

Ex 1 – Deriving prediction equation

257.81.26

5.215

2

10

)72(5.544

10

)775()72(5.795,5

22

1)(

)()(

n

XX

n

YXXY

b

050.18

)2.7(257.85.77

xbyb 10

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Interpretation of the regression equation

X

Y

18.05

ΔX

ΔY

| | | | | |

xy 257.805.18ˆ

For every 1 unit increase

in X, Y will increase by

8.257 units

Ex 1 – Deriving prediction equation

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2. Hypothesis test – Regression model

HO: Y = β0 + ei

HA: Y = β0 + β1X1 + ei

22 )(

n

YYSST

b. Calculate test statistic

Sum of squares

a. Hypotheses

5.378,2

5.062,60441,62

2

10

775441,62

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320.779,1

1.26

5.215

)(

2

2

SSX

SXYSSR

180.599

320.779,15.378,2

SSRSSTSSE

Prepare Summary ANOVA table

Source SS df MS F

Regression

Error

Total

1,779.320 1 1,779.320

599.180 8 74.898

2,378.500 9

23.757

Ex 1 – Deriving prediction equation

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c. Critical value

32.5)05(.18 F

d. Decision

Criteria Decision

Fcal > Fcritical Reject HO

Fcal ≤ Fcritical Fail to reject HO

Decision criteria

Since Fcal (23.757) is bigger than Fcritical (5.32)

Reject HO

e. Conclusion

The regression model fits the data

i.e. There is significant contribution of X

towards Y

Ex 1 – Deriving prediction equation

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3. R2 and R

748.

5.378,2

320.779,1

2

SST

SSRR

About 75% of variance in test scores

is explained by assignment scores

865.

748.

2

RR

There is a positive and high correlation

between assignment scores and test

scores

865.

748.

5.378,2

)5.215(257.8

)(1

SSY

SXYbR

Source SS df MS F

Regression

Error

Total

1,779.320 1 1,779.320

599.180 8 74.898

2,378.500 9

23.757

Source SS df MS F

Regression

Error

Total

1,779.320 1 1,779.320

599.180 8 74.898

2,378.500 9

23.757

OR

Ex 1 – R and R2

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Source SS df MS F

Regression

Error

Total

1,779.320 1 1,779.320

599.180 8 74.898

2,378.500 9

23.757

Source SS df MS F

Regression

Error

Total

1,779.320 1 1,779.320

599.180 8 74.898

2,378.500 9

23.757

a. Hypotheses

HO: β1 = 0

HA: β1 ≠ 0

b. Calculate test statistic

874.4694.1

257.8

1.26

898.74

0257.8

11

SSX

MSE

bt

4. Hypothesis test – Slope

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c. Critical value

306.28,025. t

d. Decision

Criteria Decision

|tcal| > |tcritical| Reject HO

|tcal| ≤ |tcritical| Fail to reject HO

Decision criteria

Since |t cal| (4.874) is bigger than |t critical| (2.306)

Reject HO

e. Conclusion

There is significant contribution of assignment

scores towards test score

i.e. there is a significant relationship between

assignment scores and test scores)

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Variables Entered/Removedb

Average

assignme

nt scoresa

. Enter

Model

1

Variables

Entered

Variables

Remov ed Method

All requested v ariables entered.a.

Dependent Variable: Test scoresb.

Model Summary

.865a .748 .717 8.65433

Model

1

R R Square

Adjusted

R Square

Std. Error of

the Estimate

Predic tors : (Constant), Av erage assignment scoresa.

SPSS: Regression Analysis

The method used in the

regression analysis is

ENTER

Multiple correlation

coefficient

Independent variable

Dependent variable

Coefficient of

determination

Ex 1: SPSS Analysis output

Ex 1 – SPSS analysis output

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ANOVAb

1779.320 1 1779.320 23.757 .001a

599.180 8 74.898

2378.500 9

Regression

Residual

Total

Model

1

Sum of

Squares df Mean Square F Sig.

Predictors: (Constant), Average assignment scoresa.

Dependent Variable: Test scoresb.

Coefficientsa

18.052 12.500 1.444 .187

8.257 1.694 .865 4.874 .001

(Constant)

Average ass ignment

scores

Model

1

B Std. Error

Unstandardized

Coeff icients

Beta

Standardized

Coeff icients

t Sig.

Dependent Variable: Test scoresa.

Summary ANOVA table

Hypothesis – Regression model Report F-ratio

However decision is

based on sig-F

Since sig-F (.001) is

smaller than α (.05),

reject HO

Conclude that the

regression model fits the

data

Prediction equation

bO

b1

Hypothesis - Slope

Report t-value

Ŷ = 18.052 + 8.257X

Decision is

based on sig-t

Conclude assignment scores

(X) contributes significantly

towards test scores (Y) Since sig-t (.001) <

α (.05), reject HO

Ex 1 – SPSS analysis output

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Example 2:

Dr Imran is conducting a study on subordinates’ perception on superior as

autocratic and their job satisfaction. Summary data collected from a

randomly selected sample is presented in the table below.

1. Calculate b1 and b0 and derive the prediction equation

2. Test the hypothesis for the regression model at α = .01

3. Calculate coefficient of determination and multiple correlation coefficient.

Interpret the two values.

4. Test hypothesis for the slope

at .01 level of significance. Descriptive Statistics

12 143.00 11.9167

12 168.00 14.0000

12 1785.00 148.7500

12 2396.00 199.6667

12 1962.00 163.5000

12

Perception

Job satisf act ion

X_SQ

Y_SQ

XY

Valid N (listwise)

N Sum Mean

Data: 5950 SL Regression2 Class

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1. Derive Regression/Prediction equation

891.19

)9167.11(49434.14

10

xbyb

494.

9167.80

40

12

)143(785,1

12

)168()143(962,1

)(

)()(

2

22

1

n

XX

n

YXXY

b

xy 494.891.19ˆ

Prediction equation:

Descriptive Statistics

12 143.00 11.9167

12 168.00 14.0000

12 1785.00 148.7500

12 2396.00 199.6667

12 1962.00 163.5000

12

Perception

Job satisf act ion

X_SQ

Y_SQ

XY

Valid N (listwise)

N Sum Mean

Ex 2 – Deriving prediction equation

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Interpretation of the regression equation

X

Y

19.891

ΔX

ΔY

| | | | | |

xy 494.891.19ˆ

For every 1 unit increase in

X, Y will decrease by .494

unit

Ex 2 – Deriving prediction equation

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2. Hypothesis test – Regression model

a. Hypotheses

HO: Y = β0 + ei

HA: Y = β0 + β1X1 + ei

44

352,2396,2

12

168396,2

)(

2

22

n

YYSST

b. Calculate test statistic

Sum of squares

Ex 2 – Hypothesis test (Regression model)

Descriptive Statistics

12 143.00 11.9167

12 168.00 14.0000

12 1785.00 148.7500

12 2396.00 199.6667

12 1962.00 163.5000

12

Perception

Job satisf act ion

X_SQ

Y_SQ

XY

Valid N (listwise)

N Sum Mean

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773.19

9167.80

)40(

)(

2

2

SSX

SXYSSR

227.24

773.1944

SSRSSTSSE

Prepare Summary ANOVA table

Source SS df MS F

Regression

Error

Total

19.773 1 19.773

24.227 10 2.423

44.000 11

8.162

Ex 2 – Hypothesis test (Regression model)

494.

9167.80

40

12

)143(785,1

12

)168()143(962,1

)(

)()(

2

22

1

n

XX

n

YXXY

b

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c. Critical value

04.10)01(.110 F

d. Decision

Criteria Decision

Fcal > Fcritical Reject HO

Fcal ≤ Fcritical Fail to reject HO

Decision criteria

Since Fcal (8.162) is smaller than Fcritical (10.04)

Fail to reject HO

e. Conclusion

The regression model does not fit the data at .01 level

of significance.

i.e. There is no significant contribution of X towards Y

Ex 2 – Hypothesis test (Regression model)

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3. R2 and R

449.

0.44

773.19

2

SST

SSRR

About 45 of variance in job satisfaction is explained

by perception towards superior as autocratic

670.

449.

2

RR

The is a negative and moderate correlation between

assignment scores and test scores 670.

449.

44

)40(494.

)(1

SSY

SXYbR

OR

Source SS df MS F

Regression

Error

Total

19.773 1 19.773

24.227 10 2.423

44.000 11

8.162

Source SS df MS F

Regression

Error

Total

19.773 1 19.773

24.227 10 2.423

44.000 11

8.162

Ex 1 – R and R2

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a. Hypotheses

HO: β1 = 0

HA: β1 ≠ 0

b. Calculate test statistic

855.2

1770.

494.

9167.80

423.2

0494.

11

SSX

MSE

bt

4. Hypothesis test – Slope

Source SS df MS F

Regression

Error

Total

19.773 1 19.773

24.227 10 2.423

44.000 11

8.162

Source SS df MS F

Regression

Error

Total

19.773 1 19.773

24.227 10 2.423

44.000 11

8.162

Ex 2 – Hypothesis test (Slope)

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c. Critical value

169.310,005. t

d. Decision

Criteria Decision

|tcal| > |tcritical| Reject HO

|tcal| ≤ |tcritical| Fail to reject HO

Decision criteria

Since |t cal| (2.855) is smaller than |t critical| (3.169)

Fail to reject HO

e. Conclusion

There is no significant contribution of perception

towards superior on job satisfaction at .01 level of

significance

i.e. there is a no significant relationship between

perception towards superior and job satisfaction

Ex 2 – Hypothesis test (Slope)

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Model Summary

.670a .449 .394 1.55649

Model

1

R R Square

Adjusted

R Square

Std. Error of

the Estimate

Predic tors : (Constant), Percept iona.

Variables Entered/Removedb

Perceptiona . Enter

Model

1

Variables

Entered

Variables

Remov ed Method

All requested v ariables entered.a.

Dependent Variable: Job sat isf actionb.

SPSS: Regression Analysis

The method used in the

regression analysis is

ENTER

Multiple correlation

coefficient

Independent variable

Dependent variable

Coefficient of

determination

Ex 2 – SPSS analysis output

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Coefficientsa

19.891 2.110 9.425 .000

-.494 .173 -.670 -2.857 .017

(Constant)

Perception

Model

1

B Std. Error

Unstandardized

Coeff icients

Beta

Standardized

Coeff icients

t Sig.

Dependent Variable: Job sat isf actiona.

ANOVAb

19.773 1 19.773 8.162 .017a

24.227 10 2.423

44.000 11

Regress ion

Residual

Total

Model

1

Sum of

Squares df Mean Square F Sig.

Predic tors: (Constant), Perceptiona.

Dependent Variable: Job sat isf act ionb.

Summary ANOVA table

Hypothesis – Regression model Report F-ratio However decision is

based on sig-F

Since sig-F (.017) is

larger than α (.01),

fail to reject HO

Conclude that the

regression model fits the

data

Prediction equation

bO

b1

Hypothesis - Slope

Report t-value

Ŷ = 19.891 - .494 X

Decision is

based on sig-t

Conclude perception towards

superior (X) does not

contributes significantly

towards job satisfaction (Y) Since sig-t (.017) >

α (.01), fail to

reject HO

Ex 2 – SPSS analysis output

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Prepared by:

Assoc. Prof. Dr Bahaman Abu Samah Department of Professional Development and Continuing Education

Faculty of Educational Studies

Universiti Putra Malaysia

Serdang

Simple