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Precalculus
Parametric Equations
graphs
Parametric Equations
Graph parametric equations. Determine an equivalent rectangular
equation for parametric equations. Determine the location of a moving
object at a specific time.
Graphing Parametric Equations
We have graphed plane curves that are composed of sets of ordered pairs (x, y) in the rectangular coordinate plane. Now we discuss a way to represent plane curves in which x and y are functions of a third variable t.One method will be to construct a table in which we choose values of t and then determine the values of x and y.
822
Example 1 Graph ParametricGraph the curve represented by the equations
x 1
2t, y t 2 3; 3 t 3.
Solve for x when t=-3 and t=3
Solve for y when t=-3 and t=3
These are the restrictions on x and y – now make a table for all values of t… 822
Example 1 Graph ParametricGraph the curve represented by the equations
x 1
2t, y t 2 3; 3 t 3.
Find the rectangular equation by eliminating t: First, solve for t in the first equation 822
Example 1 Graph ParametricGraph the curve represented by the equations
x 1
2t, y t 2 3; 3 t 3.
t = 2x – substitute 2x for t in the second equation…
822
Example 1 Graph ParametricGraph the curve represented by the equations
x 1
2t, y t 2 3; 3 t 3.
The rectangular equation is:y 4x2 3,
3
2x
3
2.
822
Parametric Equations
If f and g are continuous functions of t on
an interval I, then the set of ordered pairs
(x, y) such that x = f(t) and y = g(t) is a plane curve.
The equations x = f(t) and y = g(t) are parametric equations for the curve.
The variable t is the parameter.
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Determining a Direct Relationship for Given Parametric Equations
Solve either equation for t.
Then substitute that value of t into the other equation.
Calculate the restrictions on the variables x and y based on the restrictions on t.
823
Example 2 Find Rectangular
Find a rectangular equation equivalent to
x t 2 , y t 1; 1 t 4Calculate the restrictions:
−1≤t ≤4
x=t2; 0 ≤x≤16y=t−1; −2 ≤y≤3
823
Example 2 Find Rectangular
Find a rectangular equation equivalent to
Solution
x t 2 , y t 1; 1 t 4
The rectangular equation is:
y t 1
t y 1
Substitute t y 1 into x t 2 .
x y 1 2
Calculate the restrictions:
−1≤t ≤4
xt2; 1≤x≤16yt−1; −2 ≤y≤3
x y1 2 ; 0 ≤x≤16.
823
Example 3
• X = 2cos t
• Y = 2sin t
• Square both equations and add together
• (This one we will handle differently)
0 ≤t ≤2π
Example 3
• X = 2cos t
• Y = 2sin t
• Add the squares….
• A circle of radius 2
x2 + y2 =4 cos2 t+ 4sin2 t
x2 + y2 =4(cos2 t+sin2 t)
x2 + y2 =4
= 1
0 ≤t ≤2π
Determining Parametric Equations for a Given Rectangular Equation
Many sets of parametric equations can represent the same plane curve. In fact, there are infinitely many such equations.
The most simple case is to let either x (or y)
equal t and then determine y (or x).
826
Example 4 Find Parametric EquationsFind three sets of parametric equations for the parabola y 4 x 3 2
.
SolutionIf x t, then y 4 t 3 2 t 2 6t 5.
If x t 3, then y 4 t 3 3 2 t 2 4.
If x t
3, then y 4
t
3 3
2
t
9
2
2t 5.
826
Parametization of a line
• Find the parametric equations going through the points, p (-2,2) and q (3,6)
• Step 1: Find the vector
• Step 2: Find the vector from p to (x,y)
• Step 3: set up:
pqu vu
solution
pqu ru
= 3−−2,6 −2 = 5,4
pxuru
= x−−2, y−2 = x+ 2, y−2
so...
x+ 2, y−2 =t 5,4
Set x’s and y’s equal, separately:
X+2 = 5tY-2 = 4t
Solve for x and y:
X = 5t – 2Y = 4t + 2