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University of Bath
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PH20014: Electromagnetism1: Dr Paul Snow
Poynting’s Theorem in Source Free Vacuum
Maxwell’s Equations: B
Et
(M3) and
DH J
t
(M4).
For a source free vacuum, 0 , 0 and 0J . Thus, as 0B H and 0D E ,
0
HE -
t
0
EH
t
.
We take a scalar product of E
with both sides of Maxwell 4 gives,
0
EE H E
t
.
For any vector field, a standard result says that (A B) B A A B
So, here letting A
= H
and B
= E
allows us to change the LHS:
0
EH E (H E) E .
t
(1)
But, 0
HE -
t
so, 0 0
H 1 (H H)H E H
2t t
The factor of ½ arises from linking H
Ht
and
t
H
2
. Thus, we can return to (1) and write
it as,
2 2
00
1E H
2 2
H E
t t
where we have changed the order of H
and E
and also simplified the term with E
t
.
Now, we rearrange the terms and take the volume integral of both sides. We get –
2 2
0 0
1 1
2 2v v
E H dv E H dvt
We can now apply the divergence theorem to simplify the left hand side and we obtain the
following equation – and assign the meaning of the terms as shown below,
2 2
0 0
1 1
2 2S v
E H dS E H dvt
= Total power leaving the volume through
the closed surface
Rate of decrease of the
energy stored in electric and magnetic
fields