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Postulates of Quantum Mechanics (from “quantum mechanics” by Claude Cohen- Tannoudji) 6 th postulate : The time evolution of the state vector is governed by the Schroedinger equation where H(t) is the observable associated with the total energy of the system. ψ ( t 0 ) i h d dt ψ( t) = H ( t) ψ( t) 1 st postulate : At a fixed time t 0 , the state of a physical system is defined by specifying a ket ψ ( t)

Postulates of Quantum Mechanics

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Postulates of Quantum Mechanics. (from “quantum mechanics” by Claude Cohen-Tannoudji). 6 th postulate : The time evolution of the state vector. is governed by the Schroedinger equation. where H(t) is the observable associated with the total energy of the system. - PowerPoint PPT Presentation

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Page 1: Postulates of Quantum Mechanics

Postulates of Quantum Mechanics(from “quantum mechanics” by Claude Cohen-Tannoudji)

6th postulate: The time evolution of the state vector

is governed by the Schroedinger equation

where H(t) is the observable associated with the total energy of the system.

ψ(t0)

ihd

dtψ (t) = H(t)ψ (t)

1st postulate: At a fixed time t0, the state of a physical system is defined by specifying a ket

ψ(t)

Page 2: Postulates of Quantum Mechanics

Postulates of Quantum Mechanics(from “quantum mechanics” by Claude Cohen-Tannoudji)

2nd postulate: Every measurable physical quantity

ˆ Q .

Qis described by an operator This operator is an observable.

3rd postulate: The only possible result of the measurement of a physical quantity is one of the eigenvalues

Q

ˆ Q .of the corresponding observable

4th postulate (non-degenerate): When the physical quantity

Qis measured on a system in the normalized state

ψ the probability of

obtaining the eigenvalue

an of the corresponding observable

ˆ Q is

where is the normalized eigenvector of

associated with the eigenvalue

an .

ˆ Q

un

P an( ) = un ψ2

Page 3: Postulates of Quantum Mechanics

Physical interpretation of

ψ

ψ 2=ψ *ψ is a probability density. The probability of

finding the particle in the volume element at time is

dxdydz

t

ψ x,y,z, t( )2dxdydz.

General solution for

ψ x,y,z, t( )

Try separation of variables:

ψ x, y,z, t( ) =ψ n x,y,z( )θn t( )

Plug into TDSE to arrive at the pair of linked equations:

θn t( ) = e−iEnt / hand

ˆ H ψ n = Enψ n

Page 4: Postulates of Quantum Mechanics

Orthogonality:

For which are different eigenvectors of

ψa , ψ b

Hψ n = Enψ n

we have orthogonality:

ψa*ψ b = 0∫

Let us prove this to introduce the bra/ket notation used in the textbook