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Positive Semidefinite matrix. A is a positive semidefinite matrix. (also called nonnegative definite matrix). Positive definite matrix. A is a positive definite matrix. Negative semidefinite matrix. A is a negative semidefinite matrix. Negative definite matrix. - PowerPoint PPT Presentation
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Positive Semidefinite matrix nHA
nCzAzz 0*
A is a positive semidefinite matrix(also called nonnegative definite matrix)
Positive definite matrix
nHA
nCzAzz 0*
A is a positive definite matrix
Negative semidefinite matrix nHA
nCzAzz 0*
A is a negative semidefinite matrix
Negative definite matrix
nHA
nCzAzz 0*
A is a negative definite matrix
Positive semidefinite matrix
nT RxAxx 0
A is a positive semidefinite matrix
A is real symmetric matrix
Positive definite matrix
nT RxAxx 0
A is a positive definite matrix
A is real symmetric matrix
Question
nT RxAxx 0nCzAzz 0*
Yes
Is It true that)(RMALet n
?
Proof of Question
)(
)()()()(
))(()()(
)(
,,,
0)()(
***
*
yAxAxyiAyyAxxAxiyyAxiAyyAxx
yAxixAyiyAyxAxyAyyAixxAiyxAx
yiAxAiyxiyxAiyx
zAzAzziyxz
RyxwhereiyxzwritecanweCzanyForRxAxxthatAssume
clearisIt
TTTT
TTTT
TTTTTTTTTTTT
TTTTTTTT
TTTT
TTT
T
TT
n
n
nT
?
Proof of Question
)(
))(()()(*
AxyyAxiAyyAxxAxiyyAxiAyyAxxAyyyAixAxiyAxx
iAyxAiyxiyxAiyxAzz
TTTT
TTTT
TTTT
TT
TT
?
Fact 1.1.6 The eigenvalues of a Hermitian (resp. positive semidefinite , positive definite) matrix are all real (resp. nonnegative, positive)
Proof of Fact 1.1.6
edeifnegativeisAifesemideifnegativeisAif
edeifpositiveisAifesemideifpositiveisAif
andRzAzz
numberrealaisAzzAzzzAzAzzSince
zwherezAzz
zzzAzz
CzzAzthenreigenvectongcorresponithebez
andAofeigenvalueanbeLetHALet
n
n
int0int0
int0int0
,
.,)(
0,
0,,
.
2
*
*
*****
2
2
*
2**
Exercise n
n CzRAzzHA *
)(CMH n
nCzHzz 0*
From this exercise we can redefinite:
H is a positive semidefinite
注意 )(RMA n
nT RxAxx 0
A is symmetric
注意 之反例 2
2
1
1
2
21
2
1
21 00110
R
01
10But is not
symmetric
Proof of Exercise
n
n
n
n
n
n
n
HAHenceAAAA
CzzAAzCzAzzzAzCzAzzAzzthen
CzRAzzthatAssumenumberrealaisAzz
thenAzzzAzAzz
CzanyForHAthatAssume
00
0)(
)(
)(.
,)(
.)(
*
*
**
***
***
*
*
*****
RemarkLet A be an nxn real matrix.
If λ is a real eigenvalue of A, then there must exist a corresponding real eigenvector.
However, if λ is a nonreal eigenvalue of A, then it cannot have a real eigenvector.
Explain of Remark p.1A, λ : real
Az= λz, 0≠z (A- λI)z=0 By Gauss method, we obtain that z is a real vector.
Explain of Remark p.2A: real, λ is non-real
Az= λz, 0≠z z is real, which is impossible
Elementary symmetric function
nnS 21211 ),,,(
21211
212 ),,,( iinii
nS
kiii
nkiiinkS
21
21121 ),,,(
kth elementary symmetric function
KxK Principal Minor
nxnijaALet niiianyFor k 211
kikiikiiki
kiiiiii
kiiiiii
aaa
aaaaaa
21
22212
12111
det
kxk principal minor of A
Lemma p.1nMALet
AofvectorcolumnithbeaLet i
niiianyFor k 211
kj
kj
j iiijifeiiijifa
bLet,,,,,,
21
21
vectordardsithbeeLet i tan
Lemma p.2 nbbbThen 21det
kiiibyindexedcolumnsand
rowswithorprincipalthe
,,,
min
21
Explain Lemma
4442
3432
2422
4442
3432
2422
1412
010
det
00100001
detaaaaaa
aaaaaaaa
4442
2422detaaaa
The Sum of KxK Principal Minors
AoforsprincipalkxkallofsumthebeAELet k
min)(
Theorem nMALet
AofpolynomialsticcharacterithebexcLet A )(
in
n
n
ii
in
A tSttcThen
),,,()1()( 211
AofseigenvaluethebeLet n ,,, 21
inn
ii
in tAEt
)()1(1
Proof of Theorem p.1
inn
ini
in
in
ijjj
n
i nijjj
n
nA
tSt
tt
ttttc
121
211 211
21
),,,()1(
)())((
)())(()()1(
Proof of Theorem p.2
LemmapreviousbytAEt
jjjkiftejjjkifa
bwhere
bbbt
ateateateAtItc
eeeILetAofvectorcolumnithisawhere
aaaALet
inn
ii
in
ik
ik
k
n
n
i nijjj
n
nn
A
n
i
n
,)()1(
,,,,,,
det
det)det()(
,)2(
1
21
21
211 211
2211
21
21
Rank P.1 rankA:=the maximun number of linear independent column vectors =the dimension of the column space = the maximun number of linear independent row vectors =the dimension of the row space
result
result
Rank P.2 rankA:=the number of nonzero rows in a row-echelon (or the reduced row echlon form of A)
Rank P.3
rankA:=the size of its largest nonvanishing minor (not necessary a principal minor) =the order of its largest nonsigular submatrix.
See next page
Rank P.4
0010
A
1x1 minorNot principal
minor
rankA=1
Theorem Let A be an nxn sigular matrix.Let s be the algebraic multiple of eigenvalue 0 of A.Then A has at least one nonsingular(nonzero)principal submatrix(minor) oforder n-s.
Proof of Theorem p.1
snorderoforprincipalnonzerooneleastathasA
AEtAEtAEt
formtheofistcsmultipleoftcofzeroaisSince
tAEttc
sn
s
sn
snnn
A
A
n
i
in
i
in
A
min
0)()()1()(
)(,)(0
)()1()(
1
1
1
Geometric multiple Let A be a square matrix and λ be aneigenvalue of A, then the geometric multiple of λ=dimN(λI-A) the eigenspace of A corresponding to λ
Diagonalizable
matrixdiagonalaisAPP
tsPgularnon
ifablediagonalizisA
1
.sin
Exercise A and have the same characteristic polynomial and moreover the geometric multiple and algebraic multiple are similarily invariants.
APP 1
Proof of Exercise p.1
)()det(
det)det(det))(det()det(
)det()()1(
1
1
11
1
1
xcAxI
PAxIPPAxIPAPPxPP
APPxIxc
A
APP
Proof of Exercise p.2 (2)Since A and have the same characteristic polynomial, they have the same eigenvalues and the algebraicmultiple of each eigenvalue is the same.
APP 1
Proof of Exercise p.3
)(dim)(dim)(dim)(dim
)(dim)(dim,,,,
)()(
)(,,2,1
)(,,,)(dim
)3(
1
1
1
21
1
1
21
1
1
APPEAEHenceAEAPPEhaveweSimilarly
APPEAEntindenpendelinearllyisPXPXPXSince
AEXPPXXPAXXAPP
riForAPPEforbasisabeXXXLet
APPErLetAPPandAofeigenvalueanbeLet
r
i
ii
ii
r
Explain: geom.mult=alge.mult in diagonal matrix
2lg325
))1,0,0,1,0((5))1,0,0,1,0((dim
))3,2,2,3,2()2,2,2,2,2((dim))3,2,2,3,2(2(dim2
32lg)3,2,2,3,2(2
ofmultipleebraicaThe
diagrankdiagN
diagdiagNdiagIN
ofmultiplegeometricTheofmultipleebraicaThediagofeigenvalueanis
Fact For a diagonalizable(square) matrix,the algebraic multiple and the geometric multiple of each of its eigenvalues areequal.
Corollary Let A be a diagonalizable(square) matrixand if r is the rank of A, then A has at least one nonsingular principalSubmatrix of order r.
Proof of Corollary p.1
rsnorderofsubmatrixprincipalnonsigularoneleastathasA
TheorempreviousBysn
ofmultipleebraicanofmultiplegeometricn
ANnrankArAofeigenvalueofmultiple
ebraicathebesLet
0lg0
)(dim0
lg