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8/9/2019 Physics - Spring Oscillations Lab
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8/9/2019 Physics - Spring Oscillations Lab
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Introduction:
The purpose of this lab was to examine Hookes law and inestigate the proportionalit! of force"
distance traelled" and the uni#ue properties of an oscillating spring with an attached mass$ Hookes law "
gien b! the e#uation % & kx" states that the restoring force '%( of an extended or compressed spring is
proportional to the distance of compression or elongation 'x(" and is affected b! the springs constant of
proprtionalit! 'k($ The experiments were designed to inestigate whether real-world spring behaior
would conform to Hookes law$ )t is h!pothesi*ed that obserations of the oscillations of a mass moing
the spring 'harmonic motion( can be used to calculate the spring constant uni#ue to the spring$ Minimal
error between experimental 'obsered( and theoretical 'actual" calculated( spring constants will support
the h!pothesis$
Procedure:
The experiment consisted of
two exercises inestigating
oscillations of a mass on a spring$ +
force sensor was mounted to a ring
stand and base" with the force
measuring hook pointed
perpendicular to the table surface$ +
spring was hung from the hook" with
a mass suspended from the spring$
,ulling down on the mass initiated
ertical oscillating motion" with data
recorded b! ata Studio on the computer through an S./01 interface$
Data:
T : period of Oscillation 's(
m: mass 'kg(
x: distance 'm(
t: time 's(
2: initial drop angle 'degrees(
g: 3$45 'm6s7(
% & ma '8(
% & kx
k & mg6x '86m(
= km and =2 Tkm=2T
(2
T)2
=
k
mk=m
(2
T)2
Sinusoidal function:
Asin [ 2 (xC)B ]+D 9 & T
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,ercent rror: |ObservedExpectedExpected |x100
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xercise 5:
Table 5:
Mass (kg) Force (N) Displacement (cm) Displacement (m)
1$15 1$134 ;$; 1$1;;
1$17 1$53<
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xercise 7:
Table 7:
Mass (kg) Period (s) T2/42
1$17 1$0;4 1$11/
1$1; 1$raph 7: Linear
0.01 0.01 0.02 0.02 0.03 0.03 0.04 0.04 0.05 0.050
0.02
0.04
0.06
0.08
0.1
0.12
0.14
0.16
f(x) = 3.29x - 0
R = 1
Exercise 2: Mass vs T2/42
T2/42
Mass (k)
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>raph ; ? 0cm displacement 'Sinusoidal function: Sine of best fit(
>raph = - 71cm displacement 'Sinusoidal function: Sine of best fit(
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nal!sis
xercise 5 recorded the force and displacement of the spring$ Hookes law" F=kx " can be
rewritten as k=F
x 'where % is e#ual to the mass times grait!( to sole for the unknown spring
constant$ +nal!sis of the slope of >raph 5 reeals the expected spring constant 'k( to be ;$7raph 7 reeals the obsered spring constant 'k( to be ;$7435 86m$
The percent difference between the experimental and theoretical k alues was calculated as
1$41C" indicating that the spring behaed according to Hookes law and all measurements were recorded
accuratel!$
|ObservedExpectedExpected |x100|3.2891N/m3.263N/m3.263N/m |x 100=0.80 Error
"onclusion:
@omparison of the resistance to force 'k( of the spring and the springs behaior during harmonic
oscillations reealed conformance to Hookes constant within expected error and standard deiation$
Theoretical calculations assume the spring to be massless and hae no effect on the period$ The percent
error between k alues" howeer slight" reeals that the spring mass is important in real-world conditions$
Successful experimental identification of the spring constant within standard deiation of the theoretical
alue supports the h!pothesis that obserations of the oscillations of a mass moing the spring 'harmonic
motion( can be used to calculate the spring constant uni#ue to the spring$ )mproements to consistenc!
when inducing oscillations and inclusion of the spring mass will further minimi*e the experimental error$
Oerall the experiments successfull! demonstrated the conformit! of harmonic spring motion to Hookes
law$
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#ncertaint! $ummar!
Predicted (a%k%a% &'pected) alue:
;$7
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>raph 0 ? Max6Min for xercise 5
0 0.05 0.1 0.15 0.2 0.25 0.3 0.35 0.4 0.45 0.5
0.000
0.200
0.400
0.600
0.800
1.000
1.200
1.400
1.600
f(x) = 3.25x - 0.01
R = 1
f(x) = 3.27x - 0.01
R = 1
f(x) = 3.26x - 0.01
R = 1
Exercise 1: Force vs. Displacement
Displacement (m)
Force (N)
>raph < ? Max6Min for xercise 7
0 0.01 0.02 0.03 0.04 0.05 0.06
0
0.02
0.04
0.06
0.08
0.1
0.12
0.14
0.16
0.18
f(x) = 2.73x + 0.01
R = 1
f(x) = 4.12x - 0.02
R = 1f(x) = 3.29x - 0
R = 1
Exercise 2: Mass vs T2/42
T2/42
Mass (k)