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Grade 11 Physics Fair Example
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Wed. Nov. 27/13 Physics of Skating Celine Yau
Physics of SkatingFigure skaters and speed skaters have a basic understanding of physics. On ice, Newton’s
second law is so obvious; it is almost comical that it takes a few physics class to see the relationship
between pushing backwards and moving forwards. Most figure skaters do not comprehend why they
pull their arms in during a spin or jump, yet, they know by doing so, they will have more rotations in
a shorter time.Additionally, in jumps, skaters experience a change in energy causing their jumps to
have a parabolic path. Even the simple things, such as what angle to push off with has a technical
explanation.Figure skating and speed skating tie in so nicely because not only do both require ice but,
they both require the principal of centripetal acceleration. Unfortunately, the physics of skating does
not cover the artistic ability of figure skaters or the speed skaters’ passion, but it is a start to covering
this magnificent winter sport.
Sometimes, friction makes it harder to do certain jobs, however, in skating, without friction,
it would be impossible to move. When skaters move forward, they must push backwards with the
pushing foot, but what most people do not realize is that friction keeps the pushing foot from
slidingout. This form of friction is called static friction. The friction that allows skater to slow down
and stop is called kinetic friction. Skaters turn out their foot and push down against the ice to increase
the amount of friction between the ice and skate.
Furthermore, while most people believe that skaters glide simply because ice is slippery, the
truth is that friction and pressure also play a big role to allow the skater to glide. Skates are designed
so that all your body weight is supported by one -occasionally two- thin blades. Becausethere is a
high amount of pressure from your weight transferred onto the thin blade, the melting point of ice is
reduced. On top of that, the kinetic friction from the skate blade against the ice causes a thin layer of
water, thus it is not the ice that makes the skater glide so smoothly but actually the thin layer of water
on top of the ice. Arenas do not drop the temperatures way below 0⁰ because not only is it a waste of
energy but it would also be harder to produce a thin layer of water with excruciatingly low
temperatures.
Wed. Nov. 27/13 Physics of Skating Celine Yau
Next, skating is an excellent way to explain Sir Isaac Newton’s laws of physics. To start off
simple, the easiest law to explain is Newton’s third
law: for every action there is an equal and opposite
reaction. When figure skaters wish to move forward,
they must push backwards against the ice. In the
diagram, it shows the skater is moving forwards by
pushing backwards and causing the ice to exert a force
(F) perpendicular to the blade. To jump, ice skaters
push down on the ice and the ice pushes back up (this
is also known as the normal force).
As for Newton’s first law: the law of inertia
“A body moving on a level surface will continue in the same direction at a constant speed unless
disturbed,” can be explained through spins or jumps. These two tricks have a few things in common;
the first thing is angular momentum. Several things determine angular momentum: the torque,
moment of inertia, and angular velocity. To understand angular velocity –also known as an omega
(ω)-, you must be familiar with angular displacement. Angular displacement is nearly the same as
linear displacement the difference is that angular displacement deals with angles. In other words,
The graph shows that around 0⁰C, there
needs to be around 1 P(atm) to change ice
into water. The P in the graph represents
atmospheric pressure which is the force per
unit area exerted by the air above it. This
explains why ice under more pressure will
melt more easily. Also, as the temperature
drops, more pressure is needed to convert
ice into water.
http://www.real-world-physics-problems.com/images/physics_ice_skating_8.png
Wed. Nov. 27/13 Physics of Skating Celine Yau
angular displacement is the angle that a rotating body goes through; this is measured in degree or
radians.
Just like angular displacement is to linear displacement, angular velocity is the equivalent to
linear velocity. Angular velocity (ω) is the rate of change of angular displacement,to simplify: how
fast an object is rotating. Angular velocity is measured in radians/second or degrees/seconds.
The next component to angular momentum is the moment of inertia.As explained by
Newton’s first law, an object at rest stays at rest and an object in motion stays in motion unless an
outside force is applied. Once that law is explained, the name for moment of inertia is quite simple;
moment of inertia is the measure of an object’s resistance to changes in its rotation (it is measured in
m4 or kbm2). When the mass is spread out, it is less likely to tip over; the opposite is true for when
the mass is closer to the center. For example, tight rope walkers hold onto a pole (horizontally), this
helps them maintain balance and not fall over as easily.
In this picture, the arrow started on the x-axis and
moved to red line, then the purple line. Just like linear
displacement, a direction must be shown. For this case
we can choose counter clockwise, this makes counter
clockwise motion positive and clockwise motion
negative. The displacement can be expressed with the
equationθ=θ1+(−θ2).
In this case, to determine the angular velocity:
ω=(θ2−θ1)/∆ t
Wed. Nov. 27/13 Physics of Skating Celine Yau
To review, the chart below shows the connections between translational quantities to the
rotational equivalent mentioned in this report:
Translational Quantities Rotational Equivalent
Force F (N)Mass m (kg)Time t (s)Displacement d (m)Velocity v (m/s2)
Torque I (N∙m)Moment of Inertia I (kg m2)Time t (s)Angular displacement θ (rad)Angular Velocity ω (rad/s 2)
Back to the original topic, angular momentum (H) measures
the tendency of an object to keep moving.The equation for angular
momentum is H=Iω where Irepresents the moment of inertia and ω
is angular velocity. Similar to energy, angular momentum is
conserved unless an outer force acts upon it. When figure skaters start
spinning, they spread out their arms and extend their legs; this causes
them to have a higher moment of inertia because their mass is further
away from their axis of
rotation –the centre of where a
skater rotates.
To spin faster, figure skaters
bring their arms into their axis
of rotation; this will cause
their moment of inertia to
lower. Since angular
momentum is conserved,
naturally, their angular
velocity will increase, meaning the figure skater will have more rotations in a shorter amount of time.
There are two ways a skater can stop: by increasing their moment of inertia or waiting for
friction to do it for them. By increasing the moment of inertia, the angular velocity lowers because
http://www.einstein-online.info/spotlights/angular_momentum
http://www.freewebs.com/ayxl/figureskate.jpg
Wed. Nov. 27/13 Physics of Skating Celine Yau
(Iω)=(Iω)1. Next, do recall how angular momentum is conserved unless an external force acts upon
the object. For figure skating, the only external forces are gravity and friction. Since gravity acts
vertically through the skater’s centre of mass, it does not change the skater’s angular momentum. So,
only when the force of friction overcomes the force applied will the skater slow down and come to a
stop.
There are several parts to generating angular momentum for spinning on ice. The first part
would be applying a force against the ice then -as mentioned earlier-, the ice would push back against
the skater and propel them forwards. This force must be applied a certain distance away from the
axis of rotation. If the force is applied directly through the skater’s axis of rotation, the skater will not
spin. In addition to that factor, the force must cause a torque.Another way to look at torque is that it
is like a force (push/pull in a specific direction that moves an object), except it is applied to gain
angular momentum. A torque –which is measured in N∙m-, is the tendency of a force to rotate an
object around an axis, it can be thought of as a twist to an object. To find torque use the equation:
T=r × F where r is the position vector starting from where the torque is to the point of the applied
force; F is the force. Because torque is dealing with the multiplication of vectors, × can be used. In
terms of spinning, × can be substituted withsin θ, therefore the equation becomesT=rF sin θ.
Figure skaters want to start off with a large moment of inertia so that later on, they can
increase their angular velocity. Keep in mind, with a larger
moment of inertia, the more force it takes to start
spinning. If there is a larger F value, and same r value,
naturally, the product (torque) will be larger. As a result
of the torque being larger, the angular momentum will be
greater too, allowing the skater to spin faster.
Another major component to figure skating is the
jumps. Figure skaters want their jumps to be both high and long. The key factors that come into play
when trying to achieve a high and long jump are take-off angle, take-off velocity and take-off height.
http://zonalandeducation.com/mstm/physics/mechanics/forces/torque/torque2.gif
Wed. Nov. 27/13 Physics of Skating Celine Yau
If figure skaters take off at around 80⁰there jumps will be very high but not very long. Also, when
figure skaters take off at around 20⁰ there jumps will be longer but not high. Ultimately, to have a
nice balance of height and length, the take-off angle should be around 45⁰; this allows the skater
enough height and time to finish all their rotations in the air.
When people jump forwards, their path is
in a parabolic shape. This is because the gravity
is constantly causing an acceleration of
approximately 9.8m/s2 [down]. When skaters
push off the ice, they have Kinetic Energy –which
is energy due to motion. Then, as the skater increases their height, the Kinetic Energy is converted
into Gravitational Potential Energy –which is energy an object possesses because of its position in
the gravitational field.When all the Kinetic Energy (Ek) has transformed into Gravitation Potential
Energy (Eg), this is the max height that the skater will reach and for a millisecond, the skater’s
velocity will be 0. Lastly, gravity will accelerate the skater’s velocity back down to the ice.
“What goes up must come down.” –Isaac Newton
As for the horizontal displacement, according to Newton’s third law, when the skater jumps,
he/she must push down and backwards on the ice. However, in reality, the skater has already
converted chemical potential energy (muscles power) into kinetic energy, thus the skater already has
quite a bit of horizontal velocity. So in actuality, the skater mainly needs to focus on pushing down.
Once the figure skater has hit the ground, the gravitational potential energy they had at the peak of
the jump is converted into kinetic energy.
Just like spinning, the skater needs to start with a high moment of inertia so that they can
increase their angular velocity. After take-off, skaters cannot change their angular momentum
because the only external force acting on the skater is air resistance. However, due to the small
amount of height (relative to the Earth’s atmosphere) that the skater reaches, air resistance does not
affect the skater’s angular momentum.Since there is only so much a person can spread out their mass,
http://farm3.staticflickr.com/2769/4215796779_a80fb5c170.jpg
Wed. Nov. 27/13 Physics of Skating Celine Yau
the more complex the jumps become (doubles, triples, and quadruples spins in the air) the tighter the
skater must squeeze to yield enough angular velocity.
Moving away fromfigure skating, the next progression for the physics of skating is speed
skating. Speed skating seems quite simple, but just like every sport, there is a technique that goes into
the exercise. When skaters push back with their foot, they don’t actually push off at perpendicular
angle to the blade. They push back 35° -as illustrated in figure (b)- from the blade. This allows 77%
of the force to be transferred into movement compared to the 70% energy transfer if they pushed
perpendicular to the blade (illustrated in figure (a)).
The max speed that a skater can reach is
influenced by how fast the skater can move their legs.
The average maximumhumanspeed for runners is 43
kph. However, skaters can reach up to 50kph. The
reason for this is because the 43kph is relative to the
ground. While skating, the skate on the ice is gliding
forwards while the skater is moving their other foot
forwards. This means that during one step the skater’s
gliding foot moves about 0.7v because:Gliding for Gold: The Physics of Winter Sports
By usingcosθ=ah
, you can find the speed of the
skater relative to the direction they are going.
Wed. Nov. 27/13 Physics of Skating Celine Yau
The next stride allows the skater to move back towards
the way they want to go thus, the next stride contributes
to the skater’s speed. Therefore the total speed will be
1.4v. And if the max leg speed is around 43 kph, then
skaters’ theoretical max speed will be 1.4 ( 43 )=60.2 (not
including friction).
Once the skater reaches the maximum speed, the
skater does not need to overcome friction or drag, and there is no need for the skater to increase
speed thus, less energy is needed.On top of that, at maximum speed, it becomes harder for the skater
to push against the ice. When the skater’s speed reaches the speed of his/her legs, it results in no
force exerted on the ice.
When watching speed skating, you will notice how skaters will lean towards the centre of the
rink. They must do this because of centripetal acceleration (ac).Centripetal acceleration is the rate of
change of tangential velocity.Tangential velocity is the instantaneous linear velocity of an object
moving in a circular path, and its direction is tangential to the circle at that point. At the ends of the
ice rinks, speed skaters must travel in a semicircle, during that time, they are travelling in uniform
circular motion. Because the direction of velocity is always changing, there is always acceleration
during uniform circular motion. This acceleration is pointed towards the center of rotation, and is
where centripetal (“center seeking”) acceleration receives its name from. To calculate the direction of
the change in velocity, two directions of the velocity of an object are picked and inputted into
ac=∆ v /∆ t.
Next, to calculate the magnitude:triangles ABC and
PQR are similar triangles thus∆ vv1∨2
=∆ sr and is rearranged to
find Δv: ∆ v= vr
∆ s. We divide the equation above by the Δt
http://cnx.org/content/m42084/latest/
Wed. Nov. 27/13 Physics of Skating Celine Yau
producing: ∆ v∆ t
= vr
×∆ s∆ t
. That is the same as ac=v2
rbecause centripetal acceleration is
∆ v∆ t
. This
equation can become more simplified into
ac=(rω)2
r=r ω2.
Fy is 0 because there is no vertical
acceleration. To deal with the horizontal
force, we combine the equation for centripetal
acceleration and Newton’s second law
yieldingF x=mv2
R (equation 1). Because θ is
constant, this means the skater is in a state of
rotational equilibrium –which means the total angular acceleration is 0.To show this mathematically:
F x sinθ ∙ L−F y cosθ ∙ L=0 (equation 2).Onceequation 1, equation 2 and centripetal acceleration are
combined, it produces the equation tanθ=Rg
v2 and can be used to calculate how much a speed skater
must lean so that they can turn around the rink. For example, if a skater going 20m/s around a
semicircle with a radius of 8.5m, the skater has a lean of 11.8°.
Key for the photo:
g is the acceleration due to gravity, which is equal
to 9.8 m/s2 on earth.
G is the center of mass of the system (including
the skater’s skates).
P is the approximate contact point between the
skater's blades and the ice.
L is the distance between point P and point G.
Fxis the horizontal contact force, with the ice,
acting on the skater's blade at point P.
Fy is the vertical contact force with the ice acting
on the skater's blade at point P.
R is the radius of the turn, measured from the
center of the turn to the center of mass.
ac is the centripetal acceleration of point G.
θ is the angle between the horizontal and the line
passing through points P and G. This measures
the “lean” that the speed skater has.
Wed. Nov. 27/13 Physics of Skating Celine Yau
By understanding centripetal acceleration, we can move back into figure skating and more
specifically, the death spiral (shown in the image below) presented in pairs figure skating.
This famous position deals with
centripetal and centrifugal force. The man in the
picture pulls the woman into the pivot point (P);
he acts like the centripetal force in this system.
Centrifugal force comes from the words centrum
–which means “center”- and “fugere” - “to flee”.
In this system, the woman acts like centrifugal
force. However, in reality, the performers will
skate into this position and thus the only reason
the woman is pulling away is because of her
inertia.
For the two skaters to maintain rotating around a point on ice, the man must use one foot to
push against the ice. A free body diagram that shows the skaters as one body (as drawn bellow) helps
determine the amount of force that the man must exert on the ice.
ac is the centripetal acceleration of the center of
mass M due to the rotation rate v. As discussed in the
speed skating section, centripetal acceleration points
towards the center of the circle.
FP is the force exerted by the ice on the male skater's
blade at point P. This force acts in the direction of the
centripetal acceleration ac.
Then, because of Newton’s second rule,∑ F=ma,Fp can be seen as F p=m ac. Since centripetal
acceleration isac=ω2 R, the equation becomesF p=(mA +mB)ω2 R. To put this equation to use, the
women has an approximate mass of 50 kg (mA = 50 kg) and the man has 80 kg (mB = 80 kg), ω is 308
Wed. Nov. 27/13 Physics of Skating Celine Yau
rad/s, and R is 0.4 m. As a result,Fp equals 750 N indicating the man must push down with a force of
750N to stay in place.
Skating has many different things happening at the same time; even the most beginner thing
like taking a “step” forward causes melting, friction, and proves one of the three most important laws
of physics. Athletes who skate at home have a greater advantage because they know the temperature
and the amount of pressure they must apply to melt the ice.Figure skating isan excellent example of
angular acceleration and torque; by watching the Olympics,these different elements can be spotted in
the figure skaters’ spins.With the understandingof angular acceleration, comes the knowledge of
understanding angular velocity, and moment of inertia.The greatest thing about understanding energy
transfer from kinetic to potential is that while watching figure skaters, you realizethe amount offorce
that a skater must overcome during their jumps. This really puts some perspective inwatching the
athletes perform. Once again, angular momentum is another physics element that is incorporated in
jumps; the more complex the jumps are, the tighter the skater must pull in.
Once you know how to skate, it iseasier than running because at maximum speed, the skater
does not need to use as much force to move forward.At maximum speed,the skater does not need to
overcome friction/drag. The complexity of speed skating comes in when skaters need to turn around
at the end of the rink. Due to centripetal acceleration, skaters must lean a certain degree in order to
complete the turn; this “lean” depends on the radius of the semicircle, and the speed.
Moving back into figure skating, during a death spiral, the couple experiences a centripetal
force. So that the pair continues to turn around on an axis, the man must apply a force against the ice
with one foot.The pressure of this force is based on how much the couple weighs, how big their
circle is, and how fast their angular velocity is. Understanding the physics to speed skating and figure
skating can make it easier to fix the small errors in skating techniques. Still, just like every other
sport, there is a reason why the nerds (despite their knowledge of physics) still do not fare so well in
competitive skating. The jumps, spins, and the speed all require practice, plus some cuts and bruises
to achieve.
Wed. Nov. 27/13 Physics of Skating Celine Yau
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