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Physics 212 Lecture 13, Physics 212 Lecture 13, Slide Slide 1 Physics 212 Physics 212 Lecture 13 Lecture 13 Forces and Torques on Currents

Physics 212 Lecture 13, Slide 1 Physics 212 Lecture 13 Forces and Torques on Currents

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Page 1: Physics 212 Lecture 13, Slide 1 Physics 212 Lecture 13 Forces and Torques on Currents

Physics 212 Lecture 13, Slide Physics 212 Lecture 13, Slide 11

Physics 212Physics 212Lecture 13Lecture 13

Forces and Torques on Currents

Page 2: Physics 212 Lecture 13, Slide 1 Physics 212 Lecture 13 Forces and Torques on Currents

Physics 212 Lecture 13, Slide Physics 212 Lecture 13, Slide 44

Today’s Plan:Today’s Plan:

• Review of cross productReview of cross product• Forces & TorquesForces & Torques• Magnetic dipole momentMagnetic dipole moment• Example problemExample problem

Key Concepts:Key Concepts:

• Forces & Torques on loops of current Forces & Torques on loops of current due to a magnetic field.due to a magnetic field.

• The magnetic dipole moment.The magnetic dipole moment.

05

Page 3: Physics 212 Lecture 13, Slide 1 Physics 212 Lecture 13 Forces and Torques on Currents

Physics 212 Lecture 13, Slide Physics 212 Lecture 13, Slide 55

F qv B

Last Time: force on chargeLast Time: force on charge

06

yz

x

BF

I

This Time: force on wireThis Time: force on wire

F IL B

BvqFii

BvqNF avg

avgqnAvI

nALN

Page 4: Physics 212 Lecture 13, Slide 1 Physics 212 Lecture 13 Forces and Torques on Currents

Physics 212 Lecture 13, Slide Physics 212 Lecture 13, Slide 66

F IL B

ACT

08

A square loop of wire is carrying current in the counterclockwise direction. There is a horizontal uniform magnetic field pointing to the right.

What is the force on section a-b of the loop?A. Zero B. Out of the page C. Into the page

Page 5: Physics 212 Lecture 13, Slide 1 Physics 212 Lecture 13 Forces and Torques on Currents

Physics 212 Lecture 13, Slide Physics 212 Lecture 13, Slide 77

F IL B

ACT

10

A square loop of wire is carrying current in the counterclockwise direction. There is a horizontal uniform magnetic field pointing to the right.

What is the force on section b-c of the loop?A. Zero B. Out of the page C. Into the page

Page 6: Physics 212 Lecture 13, Slide 1 Physics 212 Lecture 13 Forces and Torques on Currents

Physics 212 Lecture 13, Slide Physics 212 Lecture 13, Slide 88

F IL B

ACT

12

A square loop of wire is carrying current in the counterclockwise direction. There is a horizontal uniform magnetic field pointing to the right.

What is the force on section d-a of the loop?A. Zero B. Out of the page C. Into the page

Page 7: Physics 212 Lecture 13, Slide 1 Physics 212 Lecture 13 Forces and Torques on Currents

Physics 212 Lecture 13, Slide Physics 212 Lecture 13, Slide 99

Checkpoint 1a

13

A square loop of wire is carrying current in the counterclockwise direction. There is a horizontal uniform magnetic field pointing to the right.

What is the direction on the net force on the loop?A. Out of the page B. Into of the pageC. The net force on the loop is zero

“The net force on any closed loop is zero.”

Check simulations if in doubt.

Page 8: Physics 212 Lecture 13, Slide 1 Physics 212 Lecture 13 Forces and Torques on Currents

Physics 212 Lecture 13, Slide Physics 212 Lecture 13, Slide 1010

x

y

15

Checkpoint 1bA square loop of wire is carrying current in the counterclockwise direction. There is a horizontal uniform magnetic field pointing to the right.

In which direction will the loop rotate (assume the z axis is out of the page)?

A. Around the x axis B. Around the y axisC. Around the z axis D. It will not rotate

Page 9: Physics 212 Lecture 13, Slide 1 Physics 212 Lecture 13 Forces and Torques on Currents

Physics 212 Lecture 13, Slide Physics 212 Lecture 13, Slide 1111

R F

RF

Checkpoint 1c

17

y

A square loop of wire is carrying current in the counterclockwise direction. There is a horizontal uniform magnetic field pointing to the right.

What is the direction of the net torque on the loop?

A. Up B. DownC. Out of the page D. Into the pageE. The net torque is zero

Page 10: Physics 212 Lecture 13, Slide 1 Physics 212 Lecture 13 Forces and Torques on Currents

Physics 212 Lecture 13, Slide Physics 212 Lecture 13, Slide 1212

Magnetic Dipole Moment

Area vectorMagnitude = AreaDirection uses R.H.R.

Magnetic Dipole moment

NIA

19

Page 11: Physics 212 Lecture 13, Slide 1 Physics 212 Lecture 13 Forces and Torques on Currents

Physics 212 Lecture 13, Slide Physics 212 Lecture 13, Slide 1313

Makes Torque Easy!

B

The torque always wants to lineThe torque always wants to line up with up with BB ! !

BB

B

turnsturns toward toward BB

x

y

z

BB

B

turnsturns toward toward BBx

y

z

21

Page 12: Physics 212 Lecture 13, Slide 1 Physics 212 Lecture 13 Forces and Torques on Currents

Physics 212 Lecture 13, Slide Physics 212 Lecture 13, Slide 1414

B

B

In this caseIn this case is out of the page (using right hand rule)is out of the page (using right hand rule)

I

BB

B

x

y

z

is up (turnsis up (turns toward B)toward B)

22

Practice with and

Page 13: Physics 212 Lecture 13, Slide 1 Physics 212 Lecture 13 Forces and Torques on Currents

Physics 212 Lecture 13, Slide Physics 212 Lecture 13, Slide 1515

B

Biggest when B

24

Checkpoint 2aThree different orientations of a magnetic dipole moment in a constant magnetic field are shown below. Which orientation results in the largest magnetic torque on the dipole?

Page 14: Physics 212 Lecture 13, Slide 1 Physics 212 Lecture 13 Forces and Torques on Currents

Physics 212 Lecture 13, Slide Physics 212 Lecture 13, Slide 1616

Magnetic Field can do Work on Current

W d sin( )B B

From Physics 211:

sin( ) cos( )W B d B B

U W

From Physics 212:

-1.5

-1

-0.5

0

0.5

1

1.5

0 30 60 90 120 150 180

B

27

U B

Define U = 0 at Define U = 0 at position of maximum position of maximum

torquetorque

Page 15: Physics 212 Lecture 13, Slide 1 Physics 212 Lecture 13 Forces and Torques on Currents

Physics 212 Lecture 13, Slide Physics 212 Lecture 13, Slide 1717

U B

Checkpoint 2b

30

U = 0U = -Bcos

U = +Bcos

Three different orientations of a magnetic dipole moment in a constant magnetic field are shown below. Which orientation has the most potential energy?

Page 16: Physics 212 Lecture 13, Slide 1 Physics 212 Lecture 13 Forces and Torques on Currents

Physics 212 Lecture 13, Slide Physics 212 Lecture 13, Slide 1818

ACT

30

c

a

a

Three different orientations of a magnetic dipole moment in a constant magnetic field are shown below. We want to rotate the dipole in the CCW direction.

B

First, consider rotating to position c. What are the signs of the work done by you and the work done by the field?

A)Wyou > 0, Wfield > 0B)Wyou > 0, Wfield < 0C)Wyou < 0, Wfield > 0D)Wyou < 0, Wfield < 0

• U > 0, so Wfield < 0. Wyou must be opposite Wfield

• Also, torque and displacement in opposite directions Wfield < 0

fieldW U

Page 17: Physics 212 Lecture 13, Slide 1 Physics 212 Lecture 13 Forces and Torques on Currents

Physics 212 Lecture 13, Slide Physics 212 Lecture 13, Slide 1919

ACT

30

c

a

a

Three different orientations of a magnetic dipole moment in a constant magnetic field are shown below. Consider rotating the dipole to each of the three final orientations shown.

B

Do the signs depend on which position (a, b, or c) the dipole is rotated to?

A)YesB)No

The lowest potential energy state is with dipole parallel to B. The potential energy will be higher at any of a, b, or c.

U B

Page 18: Physics 212 Lecture 13, Slide 1 Physics 212 Lecture 13 Forces and Torques on Currents

Physics 212 Lecture 13, Slide Physics 212 Lecture 13, Slide 2020

Checkpoint 2c

30

c

a

a

Three different orientations of a magnetic dipole moment in a constant magnetic field are shown below. In order to rotate a horizontal magnetic dipole to the three positions shown, which one requires the most work done by the magnetic field?

B

Page 19: Physics 212 Lecture 13, Slide 1 Physics 212 Lecture 13 Forces and Torques on Currents

Physics 212 Lecture 13, Slide Physics 212 Lecture 13, Slide 2121

Checkpoint 2c

30

fifieldby UUUW _

U B

(b): (b): BBW fieldby 0_

(c): (c): )cos1()cos(_ ccfieldby BBBW

c

(a): (a): )cos1()cos(_ aafieldby BBBW

a

a

Three different orientations of a magnetic dipole moment in a constant magnetic field are shown below. In order to rotate a horizontal magnetic dipole to the three positions shown, which one requires the most work done by the magnetic field?

B

Page 20: Physics 212 Lecture 13, Slide 1 Physics 212 Lecture 13 Forces and Torques on Currents

Physics 212 Lecture 13, Slide Physics 212 Lecture 13, Slide 2222

CalculationCalculationA square loop of side a lies in the x-z plane with current I as shown. The loop can rotate about x axis without friction. A uniform field B points along the +z axis. Assume a, I, and B are known.

How much does the potential energy of the system change as the coil moves from its initial position to its final position. • Conceptual Analysis

– A current loop may experience a torque in a constant magnetic field

• = X B– We can associate a potential energy with the orientation of loop

• U = - ∙ B

z

x

y

B .30˚

y

z

I

initialfinal

• Strategic Analysis– Find – Calculate the change in potential energy from initial to final

a

B

32

Page 21: Physics 212 Lecture 13, Slide 1 Physics 212 Lecture 13 Forces and Torques on Currents

Physics 212 Lecture 13, Slide Physics 212 Lecture 13, Slide 2323

CalculationCalculation

• What is the direction of the magnetic moment of this current loop in its initial position?

(A) (A) +x (B) (B) -x (C) (C) +y (D) (D) -yz

x ●●y

A square loop of side a lies in the x-z plane with current I as shown. The loop can rotate about x axis without friction. A uniform field B points along the +z axis. Assume a, I, and B are known.

z

x

y

B .30˚

y

z

I

initialfinal

a

B

IA

z

y

.

X

Right Hand Rule34

Page 22: Physics 212 Lecture 13, Slide 1 Physics 212 Lecture 13 Forces and Torques on Currents

Physics 212 Lecture 13, Slide Physics 212 Lecture 13, Slide 2424

CalculationCalculation

• What is the direction of the torque on this current loop in the initial position?

(A) (A) +x (B) (B) -x (C) (C) +y (D) (D) -y

A square loop of side a lies in the x-z plane with current I as shown. The loop can rotate about x axis without friction. A uniform field B points along the +z axis. Assume a, I, and B are known.

z

x

y

B .30˚

y

z

I

initialfinal

a

B

Bz

y

.

X

36

Page 23: Physics 212 Lecture 13, Slide 1 Physics 212 Lecture 13 Forces and Torques on Currents

Physics 212 Lecture 13, Slide Physics 212 Lecture 13, Slide 2525

CalculationCalculation

U B

• What is the potential energy of the initial state?

(A) (A) Uinitial < 0 < 0 (B) (B) Uinitial = 0 = 0 (C) (C) Uinitial > 0 > 0

090

A square loop of side a lies in the x-z plane with current I as shown. The loop can rotate about x axis without friction. A uniform field B points along the +z axis. Assume a, I, and B are known.

z

x

y

B .30˚

y

z

I

initialfinal

a

B

z

y

B

38

0 B

Page 24: Physics 212 Lecture 13, Slide 1 Physics 212 Lecture 13 Forces and Torques on Currents

Physics 212 Lecture 13, Slide Physics 212 Lecture 13, Slide 2626

CalculationCalculation

• What is the sign of the potential energy in the final state?

(A) (A) Ufinal < 0 < 0 (B) (B) Ufinal = 0 = 0 (C) (C) Ufinal > 0 > 0

A square loop of side a lies in the x-z plane with current I as shown. The loop can rotate about x axis without friction. A uniform field B points along the +z axis. Assume a, I, and B are known.

z

x

y

B .30˚

y

z

I

initialfinal

a

B

initial final

z

y

B

z

y

B

U B

40

0120

U B

0 B

Check: moves away from B

Energy must increase !

Page 25: Physics 212 Lecture 13, Slide 1 Physics 212 Lecture 13 Forces and Torques on Currents

Physics 212 Lecture 13, Slide Physics 212 Lecture 13, Slide 2727

CalculationCalculation

2U Ia B(A) (B) (C) (A) (B) (C)

• What is the potential energy of the final state?

A square loop of side a lies in the x-z plane with current I as shown. The loop can rotate about x axis without friction. A uniform field B points along the +z axis. Assume a, I, and B are known.

z

x

y

B .30˚z

I

initialfinal

a

B

1cos(120 )

2oU B B B

z

y

B

1cos(120 )

2o

U B

21

2U Ia B

2Ia

21

2U Ia B

44

BIaU 2

2

3