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Physics 2102 Jonathan Dowling. Physics 2102 Lecture 14. Aurora Borealis. Ch28: Magnetic Forces on Current Wires. Star Quake on a Magnetar!. “I’ll be back…. Crossed Fields E vs. B. q. y. B. E. v. L. F E =qE. F E =ma => y=qEL 2 /(2mv 2 ). F B =vqBF E. - PowerPoint PPT Presentation
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Physics 2102 Physics 2102 Lecture 14Lecture 14
Ch28: Magnetic Forces on Current WiresCh28: Magnetic Forces on Current Wires
Physics 2102
Jonathan Dowling
Star Quake on a
Magnetar!“I’ll be back….
Aurora Borealis
Crossed Fields E vs. BCrossed Fields E vs. B
FE=qE
BEy
q
FB=vqBFE
v
L
FE=ma => y=qEL2/(2mv2)
FB=FE => y=0 => v=E/B
Magnetic force on a wire.Magnetic force on a wire.
dvL
itiq ==
LBvqF d
rrr×=
BLiBqLi
qFrrr
rr
×=×=
BLiFrrr
×=
BLdiFdrrr
×=
Note: If wire is not straight,compute force on differential elements and integrate:
ExampleExample
iLBFF == 31
θiBRdiBdLdF ==
By symmetry, F2 will only have a vertical component,
iBRdiBRdFF 2)sin()sin(00
2 ∫∫ ===ππ
θθθ
)(22321total RLiBiLBiRBiLBFFFF +=++=++=
Notice that the force is the same as that for a straight wire,
L LR R
and this would be true nomatter what the shape of the central segment!.
Wire with current i.Magnetic field out of page.What is net force on wire?
Example 4: The Rail GunExample 4: The Rail Gun• Conducting projectile of length 2cm,
mass 10g carries constant current 100A between two rails.
• Magnetic field B = 100T points outward.
• Assuming the projectile starts from rest at t = 0, what is its speed after a time t = 1s?
B I L
• Force on projectile: F= ILB (from F = iL x B)• Acceleration: a = iLB/m (from F = ma)• v(t) = iLBt/m (from v = v0 + at) = (100A)(0.02m)(100T)(1s)/(0.01kg) = 2000m/s
= 4,473mph = MACH 8!
projectile
rails
Torque on a Current Loop: Principle behind electric motors.
Net force on current loop = 0
iaBFF == 31
)sin(1 θFF =⊥
)sin(θτ iabBbFTorque === ⊥
For a coil with N turns,τ = N I A B sinθ, where A is the area of coil
Rectangular coil: A=ab, current = i
But: Net torque is NOT zero!
nNiA ˆ)(=μr n̂,μr
Magnetic Dipole MomentMagnetic Dipole Moment
N = number of turns in coilA=area of coil.
We just showed: τ = NiABsinθRight hand rule:
curl fingers in direction of current;
thumb points along μDefine: magnetic dipole moment μ
Brrr
×=μτ
As in the case of electric dipoles, magnetic dipoles tend to align with the magnetic field.
Electric vs. Magnetic DipolesElectric vs. Magnetic Dipoles
Eprrr
×=τ
-Q
θQE
QE
+Q
p=Qa
Brrr
×=μτ
nNiA ˆ)(=μr