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8/10/2019 PETE_663_RESIST_THEORY.pdf
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FORMATION EVALUATION
PETE 663
RESISTIVITY THEORY / SATURATION
Summer 2010
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IDEALIZEDLOG SET
= 0.30
= 0.35
= 0.07
R = 0.4
R = 0.3
R = 4
R = 8
Sand
Shale
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FOUR COMPONENTS OF SANDSTONE
MATRIXFRAMEWORK
(QUARTZ)
FRAMEWORK
(FELDSPAR)
CEMENT
PORE
Note different use of matrix
by geologists and engineers
0.25 mm
1. Framework
2. Matrix3. Cement
4. Pores
Engineering
matrix
Geologists Classification
Ayers, 2001
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FLUID SATURATIONS
Grain Water Gas Oil
Initially, water fills pores and wets the rock surface
Hydrocarbons migrate into the reservoir rock, displacing some water
Hydrocarbon distribution determined by gravity and capillary forces,and by wettability
Modified from NExT, 1999
and matrix
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RESISTIVITY OF ROCKS CONTAINING FLUID
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RESISTIVITY DEFINITION OF THE
OHM-METER
From Halliburton (EL 1007)
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RESISTIVITY
Resistivity
The voltage required to cause one amp to passthrough a cube having a face area of one
square meter
Units are ohm-m / m; usually ohm-m (.m)2
tyConductivi
1yResistivit =
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RESISTIVITY MEASUREMENT
Resistivity
( )( )
( )mL
mAohms
I
V
metersohmR
2*)(
=
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RESISTIVITY OF EARTH MATERIALS
tyConductivi
1yResistivit =
Incr
easing
Res
istivity
(1) Rock
(2) Gas
(3) Oil
(4) Fresh Water
(5) Salt Water
Inc
reasing
Co
nductivity
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Resistivity of water Porosity of the formation,
Pore geometry - tortuosity
Lithology of the formation
Degree of cementation, and
Type and amount of clay in the rock
FACTOR AFFECTING RESISTIVITY
From J. Jensen, PETE 321 Lecture Notes
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ELECTRICITY AND EARTH MATERIALS - 1
Conduction is by ions in water
Na+ and Cl- are very common
Other monovalent ions K+ and OH-
Common bivalent ions: Ca++, Mg++
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Water resistivity
controlled by
Ion concentrations
What type of ions
What temperature
Chart GEN-4 toconvert to NaCl
equiv
Chart GEN-5 fortemperature/resist
for NaCl
Electricity and Earth Materials - 2
From Schlumberger
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Resistivity
of NaClSolutions
____
GEN-5 H
orGEN-9 S
From Schlumberger
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Ca = 460 ppm
S04 = 1,400
Na + Cl = 19,000
TDS = 20,860
TDS = 20,850 ppm
0.81
0.45
(460)(0.81)+(1,400)(0.45)+(1)(19,000) = 20,000 ppm
T = 75 deg. F
H, GEN-4; SLB, GEN-8
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75 deg. F
SLB, GEN-9
H, GEN 5
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ARCHIES FIRST EQUATION
Relates rock resistivity to Rw
Ro
= F Rw
, where:
Ro = Resistivity of a rock that is 100%saturated with formation water
Rw
= Resistivity of formation water
F = Formation factor (formation resistivity factor)
As the salt water content increases, the formationresistivity will decrease.
A rock containing oil or gas will have a higherresistivity than the same rock completely saturatedwith salt water.
As the shale content increases, the rock matrix willbecome more conductive.
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Rt
Ro
Rw
Cube of water
having resistivity,
Rw
Non-shaly rock, 100% saturated
with water having resistivity,
Rw
Rock containing pores saturated
with water and hydrocarbons
Inc
reasing
Re
sistivity
(1) Rock
(2) Gas
(3) Oil
(4) Fresh Water
(5) Salt Water
Increasing
Conductivity
= 100%
Sw = 100%
= 20%
Sw = 100%
= 20%
Sw = 20%
SHC =80%
mw
o aR
RF
==
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The formation factor (F) depends on:
Porosity of the formation;Pore geometry;
Lithology of the formation;
Degree of cementation; and
Type and amount of clay in the rock.
FORMATION FACTOR
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For a clean formation (no shale), the formation factor can
usually be empirically correlated with porosity.
a = constant 1.0 for most formations
m = cementation factor 2 for most formations
Common values
F = 0.8/2 (Tixier) or 0.62/2.15 (Humble) for sandstones
F = 0.8/2 for carbonates
m
aF
=
FORMATION FACTOR
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FormationResistivity
Factor
VersusPorosity
mw
o a
RRF
==
As
increases, more ofthe rock volume is
comprised of pores
filled with conductive
fluid
Therefore, Ro and Fdecrease
RELATION OF FORMATION FACTOR
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RELATION OF FORMATION FACTOR
TO VOLUMETRIC POROSITY
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RESISTIVITY FACTOR TO SHALINESS
The formation factor (F) is constant for a clean
sand; F decreases for shaly sand as value of Rwincreases.
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SATURATION
Amount of water per unit volume = Sw
Amount of hydrocarbon per unit volume = (1 - Sw)
Matrix
Water
Hydrocarbon(1-Sw)
Sw
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Relates Sw to Rt
If Rt = R0, then the formation is 100% saturated
with formation water. However, if Rt > Ro, thenthe formation contains oil or gas.
General formula:
t
m
w
t
w
t
on
w
R
Ra
R
RF
R
RS
**===
For clean sands, n = 2 is common.
Like a and m, n is measured in the lab.
ARCHIES SECOND EQUATION
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LAB EVALUATION OF N
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Archies equation is based on the following
relationships
How Archies Equation Works
Rock type 1
Rock type 2
1000
100
10
1 .01 .1 1.0
FR
When water saturation is 100%
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Determining Rw Directly: from measured water sample
Indirectly: from openhole well logs
SP logs
Pickett plotsRwa technique
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Rw Using the Rwa Technique
t
m
waRR
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Example Log
GRC0 150
SPCMV-160 40
ACAL6 16
ILDC0.2 200
SNC0.2 200
MLLCF0.2 200
RHOC1.95 2.95
CNLLC0.45 -0.15
DTus/f150 50
001) BONANZA 1
10700
10800
10900
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Rw Using Pickett Plots
For water sands
n1
tm
w
w R
Ra
S
/
wwt SlognRaloglogmRlog
wt aRloglogmRlog
y InterceptxSlope
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Well: Bonanza 1
Zone: 10690.000 - 10980.000 ft
Date: 27 Apr 1998 @ 11:31
VCL < .3Deep Induction
5000.01 0.1 1 10 100
Porosity
0.0
1
0.1
1
Ap
parentRt
0.2
200
0.6
32456
2
6.3
24555
20
63.2
45553
1.00
Rw = 0.073
a = 1
m = 2
n = 2
Example Pickett Plot
Pi k tt Pl t S l ti F S
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Pickett Plot Solution For Sw
1.00
.8
.6
.4
.2
.1
Well: Bonanza 1
Zone: 10690.000 - 10980.000 ft
Date: 27 Apr 1998 @ 11:32
VCL < .3Deep induction
5000.01 0.1 1 10 100
Porosity
0.0
1
0.1
1
Ap
parentRt
0.2
200
0.6
32456
2
6.3
24555
20
63.2
45553
Rw = 0.073
a = 1
m = 2
n = 2
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SUMMARY - RESISTIVITY
Resistivity important property
Depends on ions in water
Water resistivity depends onConcentration
Temperature Ion species
Archies First Equation relates rock
resistivity to Rw Archies Second Equation relates Sw to Rt