Perfect Score Physics (Sec 1-7)

8/3/2019 Perfect Score Physics (Sec 1-7)

1/31

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SAHAGIAN PENGURUSAN SE:KOLAH BERASRAMA PENUHDANSEKtiLAHKECEMERLANGAN

MODULPERFECTSCORESEKOLAH BERASRAMA PENUH

TAHUN 2011

I'IIf---iIIiL -iI,----!

SKEMAPHYSICS

Panel Penyedia:

NOR SAIOAH BT CHE HASSAN (Kolej Tunku Kurslah) - Ketua-------------------------~

PN JENNYTA BT NOORBI (SMS Tuanku Munawir:HASLINA BT ISMAIL (SMS Hulu Selangor),------------_--.---_------_-~PN KAMARIAH BT MOHO ARSYAD lMCKK)

EN JAMALUDIN BIN ABO GHANI (SSPI Batu Raklt)


2/31

1. When the boiled water is poured onto the ping pong ball,The temperature of the air/gas wil l increase/ the kinetic energy increase

2. The rate of collision between molecules and wall of the ball will increase so the pressurewill increase,the ball will expand, so the volume will increase

Total'mark

4

.. , _,. .'~ .~ r: .....UNOERSTJl:NiJING1. runner has Inertia2. to continue moving forward3: the legs stop, body continue moving forward4. Unstable and fall

2

1. When the ballon one end is pulled up and let to fall, it strikes the secondball which is at. rest and comes to a dead slop

2. The momentum of the ball becomes zero asits velocity is zero.' .. '3. The Principle of Conservation of Momentum slates that in acolllsion betw~entwo objects

the total morrientum of the objects in the system remains unchanged.4. The energy and momentum from the first ball is transferred to the second ball and then

transmitted through the balls at rest-to the ball on the other end.5. Because-the momentum and energy is maintained in this system, the ball on the opposite

side will move at the same velocity as the ball that were in initial motion[Any four]

3

1 The boat floats. so Weight of the boat = Weight f the water displaced= Buoyant force2. As the weigh of the boat is the same so the weight of water displaced in the river and the

sea water also the same3. Density of sea water is higher than river water4. Volume of water displaced in the sea IS less than Inthe river, level of the boat is higher inthe sea than in the river

4

4

4

4

4

4

4

1. For the fish. the light is refracted f change direction at B.2. the light is refracted away from normal, towards the observer's eyes3. For the dragon-fly, the light is reflected by water surface at A.4. Reflected angle = incidence angle, reflected towards the observer's eyes----~--------~--~~------------_,--------~1. the air close to the surface is much colder than the air above it.2. Light travels from denser to less dense medium3. Light rays refracted away from normal line and bent downward toward the surface4. thus tricking our eyes into thinking an object IS located higher in appearance than it

actually is - the observer will see the image of ihe ship due to light travels in a straight lineI-----t------

4

when the volume increased, area of collision increased. so lastly the pressure will remainthe same

6

radiator3 The same time the fan in the radiator push the heat out of the car.4 Water has high specific heat capacity

When water in tube pass through the engine it can absorb large amount of heat energy2 Once water reach the radiator, the heat of the water absorbed by the fin blade of the

5

7

From the ray diagram[1.different medium (water/air), f ish and

observer2. Ltght refracted away from normal3. Extrapolation to show position of theobserving image]

4 so, he should shoot the target at the lower position of the image

8


3/31

9

1 A parallel CIrcuit can run several devices using the full voltage of the supply.2. If one device fails, theothers will continue running normally3 A failure of one component does not lead to the failure of the other components4 More components maybeadded in parallel without the need for more voltage5 Each electrical appliance In the circuit has it ownSWitch

5

screen

Ullage

1 - parallel ray between the condenser lens2 - Two rays from condenser lens touching the end of the object3 two rays comes out fromthe convex lens reflected bythe mirror4 - image formed on the screen5 - magnified, real, inverted1 waves move from deeper to shallow area2. the speed decreases

10 3. the wave refracted towards the normal line4. the wave front which perpendicular to the direction of propagation of waves resulting thewave front following the shapeof the beach

4

11

1 wa'/es move from deeper to shallow area2 the speed decreases IIlhe wave refracted towards normall1ne3. the depth at cape decreases abruptly resu1tlngwaves focused at cape4. the depth at bay decreases slowly resulting waves spread out5 the energy of waves is smaller at bay resulting calmer region compared to at cape

4

121. Use ultrasound, ultrasound is transmitted to the sea bed2 a receiver will then detectthe reflected pulses3 the time taken bythepulse to travel to the seabed and return to the receiver beingrecorded, t4 the depth of the sea can be calculated using the formula, d =0 vtJ2

4

131 Wave length depends ondepth of water2. Increasing/decreasing of depth will cause thewave to refract3 Refraction will increase/decrease the length of wavelength4. The nodal/antinodalline Willbe affected

4

14

15

6 Less effective resistance of the circuit[any 4]

4

1. The lighted candle / the heat from the candle causes the air molecules to be ionized.2. The positive charges would be attracted to the negative plate and/or the negative charges

would be attracted to the positive plate3. Tile flame of the candlewould be dispersed (flattened) into two parts II suitable diagram4 POSitivecharges are heavier than negative charges5. More of the flame is attracted to the negative plate IIdiagram

(any 4 correct)

4

2


4/31

16

1 Radioactive ray enter the tube through the mica window2. ionizes argon gas under low pressure3. The ions accelerate towards respective electrodes4 Produce a current pulses5. Pulses are recorded by rate meter[Any 4]

:~;):r\


5/31

~>~~tJq~l l; i . - " " "Question 1 [Force and Pressure]

Ch,a:tact~ristj~s.. ".". , . ..:~Streamlined shape To reduceHigh strength of metal To withstaWide base cross section area So that shisink deepeHigh volume of air space in the ship Increase b

" .. .Structure; U Because it.. ' cross secti

Question 2 [Force and Pressure]Characteristics

Material made from glass Glass doeSmall diameter of stem To increasHigh density of shot Makes theBig diameter of bottom bulb To obtaineChoose N N IS madeshots and

Question 3 [Force and Pres-sure]

SpecificationWith ASS To reducedirection cWide tyres Better supLow mass Lighter. caLow seat height LowercenC It has A8S

Question 4 [Force and Pressure]Specification

High specific heat capacity The rate 0High melting point Does notDifficult to compress PressureUse ceramic Can withstS Because itbe compre

. " _: . 'i

water resistancend high water pressurep can floatl lprevent from overturn 1 / ship more stable 1 / ship notuoyant forcehas streamlined shape, 'high strength of metal, wide baseon area, high volume of air space jn the ship

ExplanationS not corrode with acide the sensitivity of the hydrometerhydrometer stays uprighta bigger upthrust.from glass, has small diameter of capillary tube, high density ofa big diameter of bottom bulb,

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - ,Explanationjerking when it is stopped immediately / can be controlled ifhangesl does not move side waysport I more stable Isafer when turnn move faster !Iow inertia,tre of gravity! more stable. wide tyres, low mass, low seat height.

Explanation,f temperature increased caused by friction is low

easily change in shape when the temperature is highwill be transmitted uniformly in all directionsand high temperature II less dust producedhas high specific heat capacity, high melting point. difficult tossed and use ceramic,

4


6/31

Question 5 [Heat]

High boiling paint.'~." ~

It will not easily change into gas when absorb heat from the engineLow viscosity It wi ll not freeze during cold weatherl fcan flow at low temperatureHigh specific heat capacity It can absorb a big quantity of heat with small rise in temperatureA low ability to react with metalsK is the most suitabte liquid

The metal parts of the engine will not corrode easilyBecause of its low freezing poin(high boiling point, high specific of heatcapacity and low ability to react with metals

Question 6 [LightlReason

Type of objective lens is convex lens To converge the light and produce real image.Focal length of the objective lens isbig To get higher magnif ication powerD < fa + fe To get virtual and magnified imageDiameter of the objective lens islargeLens S

More light can be captured. the image formed is brighterBecause lens used is convex lens, focallengtil of the objective lens is big,o < fo + fe and.diameter of the objective lens is large

Question 7 (Electromagnetism]

Characteristic ExplanationLow resistivity To reduce heat loss in the cablesLow density The cables will be lighterLow rate of oxidation Not easily rust / corrodeLow rate of thermal expansion The cables will not expand under hot weatherCable Q Low resistivity, low density, tow rate of oxidation, low rate of thermalExpansion

Question 8 [ElectromagnetismJElectronic]

CharacteristicLow density of the coilHigh frequency of rotationUse 4 diodesHas capasitor in the circuitCircuit I

ReasonLighter (less massThe rate of change of magnetic field is higher, more current inducedFull wave rectification to get a d.c.To smooth the direct current obtainedBecause it has low density coil, high frequency of rotation, consist 4diodes and has capasitor in the circuit.

5


7/31

Question 9 [Electronic]"-.~-~:--. -

The valency of the intrinsicsemiconductor is 4 When il is doped, the conductivity of the semiconductor increaseThe valency of the doping substanceare 3 or 5

Valency of 3 is used to produce hole as majority charge carrier (P type)and valency of 5 IS used to produce electron as majority charge carrier (Ntype)

Size of the atom of the dopingsubstance is almost same as the

. size of the substanceCan maintain the crystalline structure of the substance! Give good effectin the doping processB~oause the valency of the intr insicsemiconductor is 4, The valency ofthe doping substance are 3 or 5 and the size of the doping substance is

,,'almost the same as the size of the substance

Type of pure semiconductor is Silicon. Because it has greater power handling (its not easy to get overheated)

Question 10 {Radioactivity]Properties Reason

Type of radiation is gamma Has high penetrating powerLong half-life Long lastingSolid Easy to handleLow ionizing power Does not ionize healthy cells / does not cause cell mutation

K Because it radiates gamma ray. the half-life is long, the state of matter issolid and it has low iomzinq power

6


8/31

(a) 1.17 em, 1.173 cm 2(b) (i) The reading in Diagram 1.1 is less accurate than the reading in Diagram 1.2

(ii) The smallest scale in Diagram 1.1 is larger than the smallest scale in.D iagram 1.2(iii) The smaller the smallest scale of an instrument, the more accurate the measurement

(v) The higher the sensitivity the instrument, the more accurate of the measurement 1(iv) The smaller the smallest scale of an instrument, the more sensitive the instrument

TOTAL 7

Ouestion

(ii)For any action, there is a reaction.which has the same magnitude but acts in the opposite direction.

Mark

5

(a)(i)

2The direction of tile two forces involved in both diagrams are opposite to each other.

(iii)(iv) Newton third Law of Motion

TOTAL

Question(i)(a) (ii)

3(b)

AnswerThe total mass of the lorry and the load in Q is larger than in P.

Mark1

TOTAL

Question Answer

4

The difficulties in stopping the lorry Q is more than lorry PWhen the mass of the lorry and the load is larger, the more difficult to stop it.The difficulties in stopping tile lorry is due 10 the inertia which tend to maintain thestate of motion.When the mass of the object larger, the inertia is greater.

7

Mark(a )O) Density of salt solution is higher than density of water

(ii) The portion of the block immersed in salt solution is less than in water(iii) Buoyant force acted in both liquid are same

Factors affect the buoyant force in diagram 4 are density and volume of l iquid displaced(b) For the same buoyant force, when the density of the liquid is higher, the volume of liquid

displaced is less(c) Archimedes' Principle

TOTAL 6

Question Answer MarkTemperature is the measurement of the average kinetic energy of the molecules in an 1(a) object / system

(b)(i) Temperature of trap air in diagram 5.2 is higher than in diagram 5.1 15 (ii) Pressure of trap air in diagram 5.2 is higher than in diagram 51 1(iii) Volume of trap air in diagram 5.2 and 5.1 are equal 1

(c) When the temperature of the air increase, the volume is also increase 1(d) Pressure Law 1

TOTAL 6

7


9/31

Object distance in Diagram 6.1 is shorter than that in Diagram 6.2Image distance in Diagram 6.1 is longer than that in Diagram 6.2Size of image in Diagram in 6.1 is larger than that in Diagram 6.2When the object distance is longer, the image distance is shorterWhen the image distance is shorter, the size of image is smaller

6

Q~~~ipR''". . . . . . .m f 1 p : 4 ~ t ; ; .. . Mark. .. '. . . . . '" - - ' .-(a) (i) . In diagram 7:1..l ight propagates from lowdenslty medium 10 high density medium 1In diagram 7.2, light propaqates frcim'high density. rnediurnto low density medium 1

(ii) In diagram 7.1 direction 'of light travel' towards normal but in diagram 7.2 direction of 17 light is away from normal(b) When light travels from low density medium to high density medium. light bends towards 1

normal and when light travels from high density medium to low density medium, it willbend away from normal 1

(b) Refraction of light 1TOTAL 6

QUestion Answer MarkIn diagram B.1, density of layer of air close to ground is lower than density of layer of air

(a)(i) at upper part. In diagram 8.2, density of layer of air close to ground is higher than layer 1of air upper part

(ii) Direction of propagation of sound waves in diagram 8.1 is away from the earth (upward) 18 but in diagram 8.2 it propagates toward the earth (downward)

(iii) The loudness of sound that can be heard in diagram 8.2 is greater than that in Diagram 18.1If the densityof air close to the ground is higher than the air at the upper part. the

(b) direction of propagation of the sound is directed towards the ground. 1therefore the sound can be heard louder I vice versa

TOTAL 4

8


10/31

C:~~) . i~S:( iRg~:; i' q " , ," t ' . ' .' Answ , lO r ' .:~ : < ' - . '< ~ ; " ' .\,?:;;M'~ )~-~~;~~:~. . " : . - .'.-(a) Negative 1(b)(i) In Diagram 10.1, there is n o electric field while In diagram 10.2, the electric field exist 1

between the plates 1(ii) The voltage of EHT between two plates in diagram 10.2 (a) is smaller than that in

10 Diagram 102 (b) 1(iii) The angle of deflection of the cathode ray in diagram 10.2 (a) is smaller than that in

Diagram 10.2 (b)(c) (i) When the voltage between EHT is higher, the strength of electric field is stronger 1

(ii) The stronger the electric f ield, the bigger the deflection of the cathode ray 1TOTAL 6

'. SECTI.~N'fV"-.PROI3I,..EMSOLVlNG (QUALITATIVE)_QUESTION 1

Characteristics ExplanationThe valency of the intrinsic When It is doped, the conductivity of the semiconductor increasesemiconductor is 4The valency of the doping substance Valency of 3 is used to produce hole as majority charge carrier (P type)are 3or 5 and valency of 5is used to produce electron as majority charge carrier (Ntype)Size of the atom of the doping Can maintain the crystalline structure of the substance/ Give good effectsubstance is almost same as thesize of the substance in the doping process

Because the valency of the intrinsic semiconductor is 4, The valency ofSubstance T the doping substance are 3or 5 and the size of the doping substance is

almost the same as the size of the substance

QUESTION 2

/

7(a)(i)(ii)

InterferenceConstructive mterference

No Answer Mark

(b)2000

= 0.17 rnc Increase

f a 1lf and x 0 II II x a 1lf(d) (i) speaker

to convert and produce wave which has same frequency and amplitude(ii) destructive interference

+

9


11/31

QUESTION 3. '~ -,

Thin fuse has high resistancelow specificheat capacity It take shorter time to heat upl to reach melting point Iblow the fuseCeramic catridge Can withstand higher temperatureFuse rating 13 A Normal current of device is 2400/240 '" 10 A. Maximum rating must behigher than normal current.

Easyto melt (blow faster).elting point must be low

QUESTION 4suggestion reason

Attach one fuse to the live wire in the To break /switeh off the circuit when large current before the wire becomeconsumer uniU fuse box. hotter and produce fireUsing the insulating wires /I thicker To prevent short circuit // To reduce resistance, improve efficiencywiresAttach switch for each lamp To allows each lamp to be switched on and off independentlyConnect the metal fitting lamp to the To flows electron (extra) to earth to avoid lethal shockearth wire/cableUsing only 240 V light bulb. To ensure the bulbs light up with normal brightness

QUESTION 5suggestion reason

Handle made from insulator The rate of heat flow to the handle is less, does not easily heatedThe body is made from low density Reduce mass. iightermaterialCoiled wire for the filament Can fit longer Wife inside, more heat is releasedMaterial for heating filament is High melting pointnichromeConnection to earth II fuse Flow the excess /overload current to earth if there is a short circuit I blownwhen it is excess of current flow

QUESTION 6

suggestion reasonSoft spring Give a greater sensitivity/ can detect small changesSmall density Small mass IlighCurve In shape of the magnet Radial magnetic field. create unifonn strength of magnetic field around thecoilLow resistance material of the coil To reduce energy lossPlace the seismometer in direct to convert very small motions of the earth into electrical signalscontact with the earth

10


12/31

QUESTION 7

reason-.'" . - - - : ;~;,;- ~.~~t".::.:_:, ." :.::._. - v , ; _.use thin diaphragm Easy to vibrateUse strong material Not easy to break

More number of turns of coil Increase the rate of change of magnetic flux linkage II The magnitude ofthe induced current or is also increased

Thicker diameter of wire of coil reduce the resistance of the coilUsing more powerfulmagnet toincrease the strength of thernaqneticfielo ...

QUESTION 8

. Increase the rate of change of magnetic flux linkage Jffhe magnituc;leofthe induced current or induced electromotive force is also increased

suggestion reasonOR gate The gate's output IS ON if either on.esensor is ONOne of the input X is connected to+6 V To supply an ON signal to gate X . so the current flow into the base of thetransistorPlace the resistor in base circuit To limit the current flow in the base circuit. The current amplification of thetransistor is higherUse buzzer in the cotlector cucuit It converts the electrical signal into sound energyRelay switch To switch on tile buzzer which is use a greater voltage

11


13/31

3

(a)

(b)

L!-Ua "'- t0-4

'" -2 m S-2

s = = y, (0+4) x2=4 m.

2

(3)m , ih+m2u2= n 1 , V , + m 2 v Z .(Oei5)(08) + (0.03)(0) ' " 0 + (0.03) V2V2 = 1.33 m S-1

'.. 2

2

22b)

m,v, ., iniU2 ~ 0 - (0.05)(0.8)",'-0.04 kg m s'. (c) Impulsive force = -0.04 I 0.05 = 08 N

JJ

R esultan t \4

4(a)

r -,

,,.f

I

/J.

\

"V .

- \ : " )1 mark for correct paral lelogram lines (measurement & angle)1 mark for correct diagonal line.1 mark for direction of the resultant force.1 mark for magnitude with correct unit. 138cm X 2.5 = 34.5NI 52 c= ~5B = 375 N

2

2( b )2x21=Bx15

B=2.8cm

5

(a)

(b)

P = F I AF = 400 x 50F '" 20000 N

2

Resultant Force = 20 000 - 900(10)= 11000 N 3Direction of force: upwards

6 (a)Mass = density x volumeMass = 0.169 kg m -3 x 12 m3 '" 020 kg 2

-----------_.---------

12


14/31

-:Q ~:E~s riO t(:e~~;;;~~r%1\;"":f;~,~,:~:::,


15/31

~ @ i0 f 2 $ T i; w ~ "{a)

14

2 = 1(1+5) ~iI = 0.33 A 2

15

(b)

(a)

(c)

R= (1 /5+ 1112) -= 3.530

2 = I( 1 + 3.53)I = 0.44 A

3

12 V.. ! :: i l l. . . = '{Q. Ns Vs

Np = 240 X 200' -12. = 4000Efficiency = Po x J 00P i;. 240 x 0 .2 x 100

48""100%1=24/12

(a) = 2A (with unit)

16(b)

Efficiency = Output power x 100 %Input powerInput powef=- 24x00

40= 60W

2

17

18

(a)

1 ( . I l 'J ' -19.Y .o X .1' - 1 . 0 0 0 3

3

(b)

(a)

\ 9.1

2

19 (b)

7 1V = 3_75 x 10 m s

v; = 500 = 0.48 V

2

20 (a)

(c)

12 12000+ 500The bulb not light up

1 = 50012

2

2

R 1 = 5500 D

3 alpha part icles2 beta particles

t = 33.5/6.7 = 5 T 1/232 ~ 16 ~ 8 ~ 4 ~ 2 ~ 1 gM = (230.0331) - (2260254 + 4.0026)

= 0.0051 u- 0.0051 x 1.66x 1027 kq = 8466 X 10.30 kg 14


16/31

E=mc= 8.466 x 10.30 X (3 X 108) 2= 7.619 X 10.13 J

2(b)

E=2.9 x 10 _11 = m X (3.0 x 108)2m = 3.22 x 10.28 kg

2(a)Power obtained P '" Eft= 29 x 10 -11/1.5 X 10-3=1.93x108W

2(b)

SECTION VI " :: 'P A P .ER 3QUE?TIO.N 1NO

Height, hAcceleration, aII

1II The frequency of the ticker timer, fCalculate the acceleration, a

a = 9.010.1 - 7.8/0.1 = 120 ems"= 20.0 cm 0.1a = 9.8/0.1 - 7.4/0.1 240 ems"= 30.0 cm =0.1a = 1 0 .2 / 0 1 - 6 6 / 0 .1 360 ems"b h = 40.0 em = 201a = 11.0/0.1-6.2/0.1 480 ems"=50.0em 01a = 1 1.4fO .1 - 54/0.1 600 ems"=60.0em =0.1Note: 1. All 5 values correct - 2 marks

2. 3 or 4 values correct - 1mark

15

_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ ~ -


17/31

Initial velocity, Final velocity, Acceleration, au em S O ' ) v (em S-1) (em S-2)78.0 90.0 120.074.0 98.0 240.066.0 102.0 360.0

500 62.0 110.0 480.0600 54.0 114.0 600.0Give a tick (v J based on the.followingA a table which hash, U , v and a ./ .B state name, symbol and correct .unit for each column. ../ .C Atl values o'hare correct ./o All values of u are correct ;/E All values of v are correct ./F All the values are consistent in 1d.p Dr 2 dp. . r :

Marks awarded:Number of ./ Marks6 4

4-5 32-3 21 1

4

16


18/31

d a increases linearly with hAvoid parallax error by making sure eyes are

e perpendicular to the scale of metre rule when measuringthe height.

c

10) (;: 0:; . 19Q .:(,I~ ! ' t !~" " ~'(I 70GhC. . . . ;n\ ,,:,-m!

Give a tic (./) based on the following.A Title of the graphB a at the y-axis, h at the x-axisC Name, symbol and unit for aD Name, symbol and unit for hE Uniform scale at both axisF 5 points plotted correctly

[Note: 4 points plotted correctly: ./]G Straight line of best fit is drawnH Size of the graph is ~ ~ size of the graph paperMarks awarded:

Number of ./ Marks9 68 5

6 - 7 44-5 32-3 21 1

TOTAL 16

6

17


19/31

QUESTION 2

jj

TOTAL 12

h ; ,tfl!i)~c;;::i~, ::''0~r~1.;:..';' MAR~~'RG'.CRIJERr1\.7:- : o ; 7 - ~ ~ : / ~ r ' 7 ~ ; z g .jts~;~:,::~~!'~)r:,::'tG:c'~~l#m1{FliJ~J!'~{[~~T\a r' is directly proportional to m1

Extrapolate the line to 0.75 or beyondm = 620g

1

Draw line from m = = 25 9 to the given line and from the 1b given line to the T2_ axis

2 '1T = 0.30, T=0.S477s(2-4dp.)

c

Draw osufficiently tarqetrianqteCorrect substitution (Follow candidate's triangle)

0.60/50State the correct value and unit

0.012 S2g.L

1

iim / T2 =' 1!0.012k = 39.45 (1 1 0 0 1 2 )k:= 3287.5 gS2

11

dAvoid parallax error by making sure eyes areperpendicular to the scale of stop watch whenmeasuring the height.

1

18


20/31

Question1 [Force and Motion]

No Answer mark1 (a) State a suitable inference

The speed of the boyan reaching the ground depends on the height of the top of a slide1

(b) States arelevants hypothesis .The.higher' the top o f a slide the higher ihe speed of the boyan reaching the ground: 1

States the method of measuring the responding variableThe power supply is switched on and the ticker-timer is started the trolley is released and 1the final speed, v of trolley is determined by analysing the ticker-tapeRepeat the experiment at least 4 timesThe experiment is repeated by using different values of h '" 15 ern, 1h '" 20 cm , h '" 25 em and h '" 30 em. The final velocity of the trolley reaches the ground iscaeulated from the dots made on ticker- tape.

(c State the' aim of experimentTa study the retationship between the speed of an object 00 reaching the.qround and theheight of the top of the slide.

State the manipulated variable and the responding variableManipulated variable : Height of slide (the slooping runway)Responding variable Speed of the object

State ONE variable that kept constant.Fixed variable Mass of the trolley ! angle of inclination

of the.runway board.

Complete list of apparatus and materialsA trolley, runway board, ticker- timer, ticker-tape, power supply.metre rule, cellophan tapeand wooden block

States the workable arrangement of the apparatus

a.c power supply

States the method of controlling the manipulated variableThe height of the trolley from the ground! fioor, h = 10 cm is measure using the metre rule.

Tabulating of dataVelocity of trolley, v ferns

1

1

Height hfem101520

19


21/31

I 25 I ]I 30 I I 1State how datawill be analysedPlot graph of velocity against height

v/cms -1

112marks

Total h/cm:-

-Question 2 [Force and Pressure]

Question Answer Marks2 _ (a) State a suitable inference

The pressureexerted on the surface depends on the area of contact. 1(b) State a relevant hypothesis

When the area decrease, the pressure increases 1State the aim of experiment

(c) (i) To investigate the relationship between the area of contact and 1pressure (depth of hole).State the suitable manipulated variables and responding variable (Quantity

(ii) that can bemeasured)Manipulated variable Area of contact object.

1Responding variable _ pressure exerted (depth of hole)

State the constant variable

Force applied (using 1 kg load) 1(iii) State the complete list of apparatus and materials

Vernier caliper, soft plasticine, ruler, Load 1 kg, theobject with different surface 1area but sameweight.

(iv)Draw the functional arrangement of the apparatus

20


22/31

----------------.._

(v)

State the method to control the manipulated variableMeasure the bottom area of the woodenblockwith verniercaliper/ruler, A1 cm2

Place the wooden block on the plasticine.Place the 1g load on the top of !hewooden blockState the method to measure the responding variableRemove the load and wooden block. Measure the depth of hole using verniercaliper and record it .Repeat the experiment at least 4 times with the valuesProcedure 2 and Procedure 3 are repeated using A2,A3,~,and As(Note. Based on SPM standard, at least five manipulated values required.)State how the datatabulated with the title MVand RV

Area of contact/ ern" Depth,x fmmA1Az

A 3

~As

State how the data is analysed, plot agraph RVagainst MV

Depth.x/rnrn I ,.Area of contact,AI cmz

TOTAL

1

1

12

21


23/31

Question 3 [Force and Pressure]3(a)

1

(b'. ) State a relevant hypothesisThe pressure of liquid increases as its density increases.

1

State a suitable inferenceThe pressure of liquid isdepends on its density.

(c) State the aim of experiment.To investigate the relationship between the pressure ~nd its density .

. " . "

1

State. the manipulated variableand.therespondinq variableManipulated: Density 1 / p -Responding: The pressure ofliquid

1

State ONE variable that kept constantThe depth of liquidl Nolume of water

Complete list of apparatus and materialsBeaker, thistle funnel, manometer, metre rule and salt

Arrangement of apparatus:

State the method of controlling the manipulated variable1. Apparatus is set as shownin the above figure.2 20 9 of salt is dissolvedin 100 ml of water.3. The thistle funnel is lowered into the water at constant h.4State the method of measuring the responding variable5. The value of y is measured by using metre rule.Repeat the experiment at least 4 times6. The experiment is repeated using 30g, 40g. 50g and 60gTabulation of data:

Pressure f Yass of saltfOensity

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A....alysethe data .Pressure/y

Mass of salt/Density

Question 4 [Heat]

1

Total marks12

4 . State a suitable inference(a)' ... The' rate otcoolinq of ail object depends on its masses.

1

(b) State a relevant hypothesisThe rate of cooling of water increases as its mass decreases .

1

(c) State the aim of experimentTo investigate the relationship between the rat e of cooling of water and Its mass.State the manipulated variable and the responding variableManipulated: mass of water /I mHesponding : Rate of cooling

1

State ONE variable that kept constantInitial temperature I Final temperature

1

Complete list of apparatus and materialsBeaker 250 crrr', measuring cylinder, water. electric neater.stopwatch, thermometer.

1

Arrangement of apparatus .

ThermometerBeaker

Stoowatch -~ , ~ o ~ ~ = = ~ ~water

State the method of controlling the manipulated variable 17. Apparatus is set as shown in the above figure. 18. Water /s healed to 55C. 19. 50 cm3 of water is placed in a 250 ml beaker with a thermometer Immersed in the

water.State the method of measuring the responding variable

10. The stopwatch is started when the temperature of the water ISat 50cC. Thestopwatch is stopped when the temperature reaches 35C. The time, t is recorded.

Repeat the experiment at least 4 times5. The experiment is repeated using volumes of water 100 cm ' , 150 ern", 200 ernand

250 cm3

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Tabulation of data: tMass, m (g) Time. t (s)

Analyse the data. 1Time, t (s)

I '._ - _ - _ :. -

Mass, m.(g) ../

- Total marks 12Question 5 {Heat]

5 1 State a suitable inference(a) The volume of gas depend on its temperature(b) 1 State a relevant hypothesis

.Thevolume of gas Increases as its temperature increases(c) 1 State the aim of experiment

To investigate the relationship between the volume of gas and its temperature1 State the manipulated variable and the respondinq variable

Manipulated: TemperatureResponding: The volume of gas

1 State ONE variable that kept constantMass of gas

I 1 Complete list of apparatus and materialsCapillary tube, thermometer, water, metre rule and sulphuric acid

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1

Temperature

A~an(Jement of apparatus:

1 State the method of controlling the manipulated variable1 11. Apparatus is set as.shown inthe above figure.

12. Water is heated to 30C.State the method of measuring the responding variable13. Thevertical column of trapped air is measured by using metre rule.

Repeatthe experiment at least 4 times4. The experiment IS repeated using the temperature 40oe. so'c. 600e and 70oe.

1 Tabulation of data:Volume of gasemperature

1 Analyse thedata.Volumeof gas

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Question 6 [Light]

(b) 1

6 (a) 1 State a suitable inferenceThe size of the image depends on the object distance

states a relevants hypothesisThe longer the object distance, the smaller the image(e) .

1State the aim of experimentTo study the relationship between the object distance and the heiqhtofthe.irnaqe

1 State!he manipulated variable and the responding variableManipulated variable : Object distance

. Responding variable : Height of the imageState ONE variable that kept constantFixed variable Power of lens.Complete list of apparatus and materialsConvex lens, meter rule, screen, lens holder, object

1States the workable arrangement of the apparatus

1 States the method of controlling tile manipulated variableThe object distance is measured to be u = 20cm.States the method of measuring the responding variable

1 The height of the image that formed on the screen is measured using the ruler.Repeat the experiment at least 4 timesThe experiment is repeated by usinq different values of u '" 25 em, 30 ern. 35 em, 40ern dan 45 ern.Tabulating of dataObject distance/em Height of image/cm20

25303540

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State how data will be analysedPlot graph ofobject distance against height .of image

1 Height of imaqe/crns "

12Total marks

.u/cm

7 (a) Inference: The Crane (b) had attracted more load of scrapped irons than the crane 1because of its larger no of coils/turns of the solenoid 1 / the strength of the magnetic f ielddepends on the no. of turns/coils of the solenoid.

(b) Hypothesis: Bigger number of turns in the solenoid, the stronger will be itselectromagnetic field strength 1

(c) Aim: To investigate the relationship between the number of turns and theelectromagnetic field strength 1

Variables. Manipulated: number of turns In the solenoidResponding .etectrornaqnetic field strength / no" of pins attracted 1

Constant Variable: Current: soft iron core" 1List of apparatus: Solenoid, PVC tube f large iron nail , iron nails! pins/paper clips, 1

ammeter, rheostat and power supply.Arrangement of apparatus:

:'l~_/~J : r ~c . . . , . . . , .~~I ~ 1

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Control of Manipulated Variable: Wind the insulated wire around the large iron nail/PVC tube, starting with 50 coils.

Measurement of RV: Lower the solenoild until it touches the iron nailsRecord the number of iron nails attracted by it

Repeat the experiment & procedure 4 more times with no. of coils at 100 . 150,200 and 250 .

. No. of t u r n s Noaf riails attracted50100

15020 0

250

Analysis of data.Sketch the graph of no. of coils against no. of nails attracted

TOTAL 12

Question 8 [Electricity](a) The heating effect of a conductor is affected by magnitude of the current.(b) The larger the current, the higher the temperature of the water which IS being heated(c) (i) To investigate the effect of current on heating

(ii) MV: current ,I

RV . temperature,/}

CV : volume of water(iii) Beaker, ammeter, immersion heater, thermometer, connecting Wire, rheostat and stop watch(iv) Draws a labeled and functional diagram of the set up of the apparatus(v) Pour 200cm3 of water into the beaker and measure its temperature

Switch on the circuit and adjust the rheostat until the reading of ammeter is 1.0 A.

The stop watch is started. The final temperature IS recorded after 2 minutes.Step repeated byadjusting the rheostat so that the ammeter readings are 2.0 A, 3.0 A, 40 A and

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5.0 A.

(vi) Tabulate the data

C u r r e l t , I J A m C I e as ed in T e m pe n . t l I e , 6 rc1 .0103 .04 .05 .0

(vii) The graph of increased in temperature against current is drawn:

.Question 9 [Waves](a) The loudness of the sound depends on the distance (between the source and the observer)(b) The smaller the distance (between the source and the observer). the louder the sound(c) To investigate the relationship between the loudness of a sound and. the distance (between the

source and the observer)(ii) Manipulated variable distance, d

Responding variable . loudness of sound (amplitude, a)Constant variable' wavelength or frequency

(iii) Audio signal generator, loudspeaker, cathode ray oscilloscope (CRO), microphone, meter rule!measuring tape

(iv)

eRG

1v)The microphone is placed at a distance. d = 20.0 cm from the loudspeaker1

The amplitude, B, of the trace on the screen of the is measuredThe procedure was repeated for the values of distance, d = 30.0 e rn , 40.0 em, 50.0 em and600 em

(vi)

Distance,d fern Awplitu&,aJO D30040 D50 D600

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(vii) A graph of a against d is drawnQuestion 10 [Waves](a) The distance between 2 loud speaker affect the distance between 2 loud or soft sound(b) When the distance between two coherent sources abound is Increase, the distance between two

consecutive constructive or destructive interference is decrease(c) (i) To investigate the relationship between two coherent sources and the distance between two

consecutive constructive and destructive interference.( ii ) , Manipulated: Distance between two coherent sources, a

. Respondinq 6i~t~ncebeiween~o~onsecutive constructive or destructive Interference 1Constant: Distance between the source and the screen.

(iii) Loud speaker, audio signal/frequency generator, connection wire, power supply, measuring- 'tape,(iv)

(v) By using a metre rule the distance between the listener from the loudspeaker is measured= DThe aodio-frequency generator is switched on,Use a distance between two loud speaker, a= 10m,The listener is requested to walk in a straight path from left to right.The distance between two successive loud regions is measured by a metre rule = xThe experiment is repeated using a distance between two loud speaker a= 1 .Sm, 20m,2.5m and 30m

(vi) Tabulate the dataa/m xfln

lD15~D253.0

(vii)

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Perfect Score Physics (Sec 1-7)