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Penn-Delco School District / Homepage...Find the area of the 1500 sector. m AB Fractional part of circle is Area of circle is A = Tcr2 = 7182 1500 5 3600 — 12 = sq.ft. 1. 3207t 83.76

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Page 1: Penn-Delco School District / Homepage...Find the area of the 1500 sector. m AB Fractional part of circle is Area of circle is A = Tcr2 = 7182 1500 5 3600 — 12 = sq.ft. 1. 3207t 83.76
Page 2: Penn-Delco School District / Homepage...Find the area of the 1500 sector. m AB Fractional part of circle is Area of circle is A = Tcr2 = 7182 1500 5 3600 — 12 = sq.ft. 1. 3207t 83.76
Page 3: Penn-Delco School District / Homepage...Find the area of the 1500 sector. m AB Fractional part of circle is Area of circle is A = Tcr2 = 7182 1500 5 3600 — 12 = sq.ft. 1. 3207t 83.76