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pathology. * Recognition(identify) : emphysema * What you should know about it : - widened air spaces. - Ruptured and thinned alveolar septa. 1. * Recognition(identify): lobar pneumonia * What you should know about it : 1- Alveolar capillaries: - PowerPoint PPT Presentation
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* Recognition(identify) : emphysema
* What you should know about it : - widened air spaces
- Ruptured and thinned alveolar septa
1
* Recognition(identify): lobar pneumonia
* What you should know about it : 1- Alveolar capillaries:
2- Alveolar walls:
3-Alveolar spaces:
Congested
Thickened -Lymphocytes-Macrophages-inflammatory cells
2
terminal bronchioles
* Recognition(identify) : Alveoli
* What you should know about it : 1-Type of epithelium :
if Type I Pneumocytes Simple squamous
If Type II Pneumocytes cuboidal
2-Types of cells :
1
* Cont Recognition(identify) : Alveoli 2-Types of cells :- Alveolar macrophages- Pneumocytes :
-Terminal bronchioles with clara cells -Divide to regenerate the bronchiolar epith
Type II Pneumocytes(cuboidal) 1- secretion of surfactant.2- divide to regenerate both type I & type II pneumocytes..
Type I Pneumocytes(Simple squamous ) 1- exchange gases.
1
* Recognition(identify) : trachea
* What you should know about it : 1-Type of epithelium :
Pseudo-stratified ciliated columnar epithelium with goblet cells (Respiratory epithelium).
2-Types of cells :
Hyaline cartilage
2
* cont Recognition(identify) : trachea
* What you should know about it : 2-Types of cells :
(1) Mucosa.
(2) Submucosa
(3) Adventitia.
(1) Epithelium: Pseudo-stratified ciliated columnar epithelium with goblet cells ( basal , brush cells )
(2) Lamina propria. loose fibro elastic c.t with ( mucus
glands , serous glands , lymph nods )
(3) Elastic lamina: It is formed of elastic fibers.
(1) Dense fibro elastic c.t with ( mucus glands , serous glands , lymph nods )
(1) Fibroelastic C.T. (2) C-shaped rings of hyaline cartilage. (3) (bundle of smooth muscle fibers) 2
Sphenoidal air sinus
Frontal air sinus
uvula
Nasal septum
Nostrils (anterior nares)
Vocal cords
posterior nasal aperture ( Quana )
Hyoid bone
Thyroid cartilage
Trachea Left lung Right lung
Oblique fissure
Transverse fissure
Oblique fissure
Diaphragm Ribs
Thyroid cartilage
Hyoid bone
Cricoid cartilage
Epiglottic cartilage
Thyrohyoid membrane
Cricothyroid membrane
Vocal cords
Thyroid cartilage
Cricithyroid membraneCricoid cartilage
trachea
Tertiary bronchioles
Descending aorta
esophagus
Secondary bronchiolesPrimary bronchi
Esophagus
Esophageal Opening at T10
Right crus
central tendon
right copula left copula
openings in the diaphragm :T 8 : IVC opening :
T10 : Esophageal opening
T12 : Aortic opening
Manubrium
Body
Xiphoid process
Ster
num
First rib
Second rib
clavicle
Costal cartilage
Ribs are classified as Typical from 3 to 9
Atypical 1, 2, 10, 11, 12
Upper 7 true ribs
Lower 5 false ribs
Hyoid bone
Thyroid cartilage Thyrohyoid membrane
Cricoid cartilage
Epiglottic cartilage
Arytenoid cartilage
Corniculate cartilage
Bronchopulmonary Segments right lung Superior lobe / Apical , Anterior , Posterior meddle lobe / Medial , LateralInferior lobe / Apical basal , Medial basal Lateral basal , Anterior basal , Posterior basal
Apical
Anterior
Post
erio
r
MedialLateral
medial basal
Apical basal Anterior basal
Lateral basal
Posterior basal
Bronchopulmonary Segments left lung Superior lobe / Apicoposterior ,Anterior , Sup. lingular , Inf. lingular
Apicoposterior
AnteriorSup. lingular
Inf. lingular
Inferior lobe / Apical basal , Lateral basalAnteromedial basal , Posterior basal
Apical basal
Anteromedial
basal
Late
ral b
asalPosterior basal
* the Answer of question1: (FEV1/FVC)*100=
(4.3/4.8)*100=89% NORMAlNOTE: اعلى النسبة ان صحيح
ولكن80من حدود في المعطاة القيم
الطبيعي
Q3: THE SAME WAY =80%جدا طبيعية فعال كويسالنتيجة ركزوا هنا
جدا منخفضة المعطاة القيم ولكن restrictive lung disease
الجواب عطول هيكون
Ex: pulmonary fibrosis
OTHER CAUSES TO HAVE LESSCHEST EXPANSION :Myasthenia gravis
Phrenic injuryobesity
واجب االحتياط ولكن ماهيجي عاالغلب
Plateau
FVC = 5 المنحنى عندها يكون التي القيمة Plateau هي
FEV1 = 4عند خرج الذي الهواء حجم هي
األولى الثانية
FEV1% = (FEV1/FVC) * 100= (4/5) *100=80 %
FEV1% = (FEV1/FVC) * 100
Normal
FEV1% = (FEV1/FVC) * 100
FVC = 2
FEV1 = 1.8
FEV1% = (FEV1/FVC) * 100= (1.8/2) *100=90 %
Restrictive
Plateau
1.8
؟ عرفنا مو كيف أصال ال النقليل مره ! طبيعي
FVC = 2
FEV1% = (FEV1/FVC) * 100
FVC = 3.5
FEV1 = 1.9
FEV1% = (FEV1/FVC) * 100= (1.9/3.5) *100=54 %
obstructive
3.5
Plateau
1.9