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Appendix-V ( Case 4 - API 579 Part 13 Level -2 ASSESSMENT FOR LAMINATION)For Item# 12-D-02, HDT SEPERATOR

[ s: 240, c:340, Ls: 80mm, Lw: 100 mm ]Equipment Data :Tag 12-D-02Material : SA-516 Gr.70Design Pressure : 368.3846 Psig 25.4 BargInside Diameter, D : 98.425 in 2500.0 mmNominal Thickness : 1.18 in 30.0 mmCorrosion Allowance : 0.1181 in 3.0 mmLOSS : 0.019 inAllowable Stress : 20000 Psi (28.5 % of UTS of API 5L Gr. 65)Weld Joint Efficiency : 1.00

a) Step - 1 Determine if there is any surface bulging on either the inside or the outside surface of the component at the location of the lamination. If there is surface bulging, then evaluate the lamination as a blister using the Level 2 Assessment method in Part 7.

→ The inspection report indicates no surface bulging on outside surface of the componentat the location of the lamination.

b) Step - 2Determine the information in paragraph 13.3.3.1.

Table E13.1-1 Size, Location, Condition and Spacing for Laminations

Enter the data obtained from a field inspection on this form

Inspection Date : 17-04-2012Equipment Identification :Equipment Type :

X Pressure Vessel Storage Tank Piping Component

Component Type & Location :Component type A, pressure vessel shell, two damage areas located away from any majorstructural discontinuities, subject to internal pressure loads, supplemental loads are negligible.Vessel is in hydrogen charging service.

t (nom) = 1.18 in 30.0 mmLOSS = 0.019 in 0.5 mmFCA = 0.0984 in 2.5 mmtrd = 1.161 in 29.5 mm

Data Required for Level 2 Assessment Lamination Identification : 1

Dimension s : 9.450 in 240 mmDimension c : 13.380 in 340 mm

Lamination Height Lh : 0.122 in 3.1 mm

: 3.149 in 80 mm

: 0.512 in 13 mm

: 3.937 in 100 mm

: 27.56 in 700 mm

: No

Edge to Edge Spacing to the nearest Lamination Ls

Minimum Measured Thickness tmm

Spacing to the nearest weld joint Lw

Spacing to the nearest Major Structural Discontinuity Lmsd

Through-Wall Cracking ( Yes / No )

c) Step - 3 Page 2 of 3If there are two or more laminations on the same plane, there is no indication of through thickness crackingand the spacing does not satisfy Equation (13.1), then the laminations shall be combined into a single larger lamination in the assessment. If there are two or more laminations at different depths in the wall thickness of the component and the spacing does not satisfy Equation (13.1), then the group of laminations shall be evaluated as equivalent HIC damage using the Level 2 Assessment method in Part 7. In applying this criterion, the spacing shall be measured parallel to the wall thickness. Applying Equation (13.1):

Ls > 2 x tc Equation 13.12 tc = 2 x ( trd - FCA )

= 2.1252 inWhere

Ls = 3.149 inTherefore

As Ls is greater than 2tc therefore Equation-13.1 is Satisfied

Both laminations are on the same plane

There is no indication of through thickness cracking

d) Step - 4If Equation (13.2) is satisfied, proceed to STEP 5; otherwise, evaluate the through-thicknesscomponent of the lamination as a crack-like flaw using the Level 2 Assessment method in Part 9. In thisevaluation, the crack depth shall be equal to 2a = Lh and the crack length shall be equal to2c = max[s,c]. Applying Equation (13.2):

i) Lamination 1Lh < 0.09 . Max [ s,c ] Equation 13.2

= 0.09 . Max [ s,c ]= 1.20 in

WhereLh = 0.122 in

ThereforeAs Lh < 0.09.max[s,c] therefore Equation-13.2 is Satisfied for Lamination -1

e) Step - 5Determine the wall thickness to be used in the assessment using Equation (13.3) or Equation(13.4), as applicable. Applying Equation (13.3):

tc = trd - FCA Equation 13.4= 1.0626 in

f) Step - 6If all of the following conditions are satisfied, proceed to STEP 7; otherwise, the lamination isnot acceptable per the Level 2 Assessment procedure.

1) There is no indication of through-thickness cracking.

↘ Inspection report confirmed that no evidence of through-thickness cracking.

Page 3 of 32) The lamination is not surface breaking in accordance with Equation (13.5):

tmm > 0.10 x tc Equation 13.5

i) Lamination - 1

0.10 x tc = 0.10 x ( trd - FCA )= 0.106 in

Where

tmm = 0.512 in

Therefore

As tmm > 0.10tc therefore Equation-13.5 is satisfied for Lamination -1

3)

Lw > max [ 2tc , 1 inch ] Equation 13.6

2tc = 2.1252 inmax [ 2tc , 1 inch ] = 2.1252

i) Lamination - 1

Lw = 3.937 in

As Lw > max[2tc,1 inch] therefore Equation-13.6 is satisfied for Lamination -1

4) The distance from any edge of the lamination to the nearest major structural discontinuity satisfiesEquation (13.7):

Lmsd > 1.8 x ( D x tc )^0.5 Equation 13.7

(1.8 x ( D x tc ))^0.5 = 18.408 in

Lamination - 1Lmsd = 27.56

As Lmsd > 1.8 x (D x tc) ^ 0.5 therefore Equation-13.7 is satisfied for Lamination -1

5)

The distance between any edge of the lamination and the nearest weld seam satisfies Equation (13.6). Lamination do not satisfy the spacing criteria of Equation (13.6) are acceptable if it is determine that through-thickness cracking does not occur and there is no indication of cracking in the direction towards the inside and outside surface. Apply Equation (13.6):

Equipment is in Hydrogen Charged service, therefore assessment should be made in accordance with Part - 5