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CSC 412 HW1 (Sample) Marcus Schaefer Problem 2 The system to solve is x -2 y = 5 -2x+4y = -10 Applying E 21 (2) yields: x – 2y = 5 0 = 0 So the system is consistent, and the solution is not unique. All solutions can be found by choosing y arbitrarily, and then letting x = 5+2y. Here is verification of my work using Matlab: Or here is another way of presenting the solution: Problem 2

ovid.cs.depaul.eduovid.cs.depaul.edu/Classes/CSC412-W20/hwexample.d… · Web viewCSC 412 HW1 (Sample) Marcus Schaefer Problem 2 The system to solve is x -2 y = 5-2x+4y = -10 Applying

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Page 1: ovid.cs.depaul.eduovid.cs.depaul.edu/Classes/CSC412-W20/hwexample.d… · Web viewCSC 412 HW1 (Sample) Marcus Schaefer Problem 2 The system to solve is x -2 y = 5-2x+4y = -10 Applying

CSC 412HW1 (Sample)

Marcus Schaefer

Problem 2

The system to solve is

x -2 y = 5 -2x+4y = -10

Applying E21(2) yields:

x – 2y = 5 0 = 0

So the system is consistent, and the solution is not unique. All solutions can be found by choosing y arbitrarily, and then letting x = 5+2y. Here is verification of my work using Matlab:

Or here is another way of presenting the solution:

Problem 2

I did the problem by hand (with Matlab verification):

Page 2: ovid.cs.depaul.eduovid.cs.depaul.edu/Classes/CSC412-W20/hwexample.d… · Web viewCSC 412 HW1 (Sample) Marcus Schaefer Problem 2 The system to solve is x -2 y = 5-2x+4y = -10 Applying

Problem 3

3a: The augmented matrix is as follows:

3b) Applying E4(1/2) yields:

Next step is E34(1):

Page 3: ovid.cs.depaul.eduovid.cs.depaul.edu/Classes/CSC412-W20/hwexample.d… · Web viewCSC 412 HW1 (Sample) Marcus Schaefer Problem 2 The system to solve is x -2 y = 5-2x+4y = -10 Applying

and so on ….