Upload
oscar-workman
View
41
Download
7
Embed Size (px)
DESCRIPTION
Orbit Orbit condition Example Whiteboards. Orbit. m s v 2 r or m s 4 2 r T 2. m s. =. Gm s m c r 2. m c. Example 1 - What is the velocity of orbit 250 miles above the earth? r = 6.38x10 6 m + (250 mi)(1609 m/mi) = 6782250 m - PowerPoint PPT Presentation
Citation preview
Orbit• Orbit condition• Example• Whiteboards
Gmsmc
r2
TOC
Example 1 - What is the velocity of orbit 250 miles above the earth?r = 6.38x106 m + (250 mi)(1609 m/mi) = 6782250 mmc = 5.97 x 1024 kg, use mv2/r = Gmm/r2
Do algebra first!!!!!!!!How to enter on calculator
=
msv2
r
or
ms42r T2
mc
ms
Orbit
Gmsmc
r2
TOC
Example 2 - What is the radius of a geosynchronous orbit?T = 23:56:04 = 23(3600) + 56(60) + 4 = 86164 smc = 5.97 x 1024 kg, use m42r/T2 = Gmm/r2
Algebra
=
msv2
r
or
ms42r T2
mc
ms
Orbit
Whiteboards: Orbit
1 | 2 | 3 | 4
TOC
What is the velocity of orbit 7.2 x 106 m from the earth’s center for a 23.5 kg object? Me = 5.97 x 1024 kg
W
= Gmsmc
r2
msv2
r
7436 m/s
7400 m/s
r
Gmv c
At what distance from the moon’s center is the orbital velocity 52.5 m/s? Mm = 7.36 x 1022 kg
1.78 x 109 m W
= Gmsmc
r2
msv2
r
1781086621 m
r = Gmc
v2
You are orbiting 2.3 km from the center of an asteroid in a 24,600 kg spacecraft with a period of 2500 seconds. What must be the mass of the asteroid?
1.2 x 1015 kg W
= Gmsmc
r2
ms42r T2
1.15223E+15 kg
mc = 42r3
GT2
You are orbiting 8.5 x 106 m from the center of a planet with a mass of 4.5 x 1024 kg. Your spaceship has a mass of 45,120 kg. What is your period of motion?
9.0 x 103 s W
= Gmsmc
r2
ms42r T2
8987.5 s
42r3
Gmc
T =