OOPinCPP - Chapter 3- Solutions

8/7/2019 OOPinCPP - Chapter 3- Solutions

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Solutions to Exercises (Chapter No. 3

Loops and Decisions)

Object Oriented Programming in C++ by Robert Lafore

Solutions provided by Muhammad Anas

Question No. 1

#include#include

usingnamespace std;

int main(){

char exit = 'n';do {int number;cout > number;for (int i=1; i


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cout choice;if (choice == 1){

cout > f;c = 5.0/9.0*(f - 32);cout


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} while (exit != 'y' && exit != 'Y');return 0;

}Question No. 4

#include

usingnamespace std;

int main(){

char exit = 'y';do {float first_num, second_num, result;char operation;cout > first_num >> operation >> second_num;switch(operation){case'+':

result = first_num + second_num;cout


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for (int j = 1; j


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cin >> initial_amount;cout > years;cout > interest_rate;for (int n=1; n > dot >> pence1;cout > pounds2 >> dot >> shillings2 >> dot >> pence2;pencer = pence1 + pence2;shillingsr = shillings1 + shillings2;poundsr = pounds1 + pounds2;if (pencer >= 12){

pencer -= 12;shillingsr++;

}if (shillingsr >=20){

shillingsr -= 20;poundsr++;

}cout


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cin >> exit;} while (tolower(exit) != 'y');return 0;

}Question No. 9

#include

usingnamespace std;

int main(){

char exit = 'n';do {int num_of_guests, num_of_chairs;double possible_arrangements;cout > num_of_chairs;cout > num_of_guests;possible_arrangements = num_of_guests;for (int i = 1; i < num_of_chairs; i++){

num_of_guests--;possible_arrangements *= num_of_guests;cout


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cout > interest_rate;while (initial_amount shillings1 >> dot >> pence1;cout > pounds2 >> dot >> shillings2 >> dot >> pence2;

poundsr = pounds1 + pounds2;shillingsr = shillings1 + shillings2;pencer = pence1 + pence2;if (pencer >= 12){

shillingsr++;


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pencer -= 12;}if (shillingsr >= 20){

poundsr++;shillingsr -= 20;

}cout > dot >> pence1;cout > pounds2 >> dot >> shillings2 >> dot >> pence2;

poundsr = pounds1 - pounds2;shillingsr = shillings1 - shillings2;

pencer = pence1 - pence2;/*while (poundsr < 0 || shillingsr < 0 || pencer < 0){*/

if (pencer < 0){

shillingsr--;pencer = 12 + pencer;

}if (shillingsr =0){

poundsr--;}else{

poundsr++;}shillingsr = 20 + shillingsr;

}/*}*/cout dot >> pence1;

cout > float_num;decimal_pounds = ((((pounds1 * 20) + shillings1) * 12) +

pence1)/(20*12);decimal_pounds *= float_num;//multiply amount entered with

the floating point numberpoundsr = static_cast(decimal_pounds);fractional_part = decimal_pounds - poundsr;decimal_shillings = fractional_part * 20;shillingsr = static_cast(decimal_shillings);


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fractional_part = decimal_shillings - shillingsr;pencer = fractional_part * 12;cout operation >> c >> slash >> d;switch(operation){case'+':

e = a*d + b*c;f = b*d;cout


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return 0;}

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OOPinCPP - Chapter 3- Solutions