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oil sump pit
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Design as a uncracked section as per IS 3370
Oil capacity = Litres.Taking 30% more = Litres
Volume of tank required = CuM
Cap. of tank = x x
Volume = CuM OK
Density of oil = T/m3
Data: For M25 and Fe 500
Perm Stress in concrete (c) = N/mm2 ( IS 456 Table 21) For M25 concrete
Perm Stress in steel (t) = N/mm2 ( IS 3370 Part II - Table 2)
m = 280/3c =
mc/t = nc / (d-nc) therefore nc = d
4.40
9
3.70
35000
40.32.7
0.8040250
0.79 0.79
150
43.2
0.9
4 4 2.7
11
0.62
ALIF ENGINEERS ANDPLANNERS Design calculation For Burnt Oil pit
DOC.NO:M2011EP008A-88
REV R0
c
c
c
c
c
c
c
c
1Sterling Wilson Ltd.
a = d - nc/3 = d therefore j =
MR = b nc c/2 a = bd2 therefore Q =
Density of soil = T/m3
Angle of repose = deg Ka =
Case I - When tank is full. (Neglecting earth pressure)
Using design charts of IS 3370 Part IV - considering top and bottom hinged.
As per Table 1 IS 3370 (Part IV) - 1967
a = height of wall = m Density of liquid w =
b = Width of wall = m Depth of wall below ground = m
c = Width of wall = m
c/a = b/a =
Moment coefficients (Taking Maxm values) for b/a =
Mx = My = Table 6 - IS 3370 Part IV
1.25
0.79 0.79
2.08
1.70
10 0.7
2.08
3.7 0.9
4.4
4.4
1.2 1.2
0.030 0.019-0.010 -0.045
3.4
c
c
c
c
c
c
c
c
1Sterling Wilson Ltd.
ALIF ENGINEERS ANDPLANNERS Design calculation For Burnt Oil pit
DOC.NO:M2011EP008A-88
REV R0
c
c
c
c
c
c
c
c
Maximum Horizontal moment = Mx w a ^3= x x ^3= TM (Inside face)
Maximum Horizontal moment = Mx w a ^3 Oil Press.= x x ^3 Horzt. Moment= TM (Outside face)
Maximum Vertical moment = My w a ^3= x x ^3= TM (Outside face)
Maximum Vertical moment = My w a ^3 Oil press.= x x ^3= TM (Inside face)
Vert. Moment
Case II - When tank is empty (Full earth pressure)
Soil pressure Ka = x = T/m2
Using design charts of IS 3370 Part IV - considering top and bottom hinged.
As per Table 1 IS 3370 (Part IV) - 1967
2.7
2.7
2.7
1.2
0.030 0.90.53
0.010 0.9
0.045 0.9 2.7
0.34
0.8
0.019 0.9
0.70 1.70
0.18
2Sterling Wilson Ltd.
As per Table 1 IS 3370 (Part IV) - 1967
Moment coefficients (Taking Maxm values) for b/a =
Mx = My = Table 1 - IS 3370 Part IV Soil Press.
Maximum Horizontal moment = Mx w a ^3= x x ^3= TM (Outside face) Horzt. Moment
Maximum Horizontal moment = Mx w a ^3= x x ^3= TM (Inside face)
Maximum Vertical moment = My w a ^3= x x ^3= TM (Inside face) Soil Press.
Maximum Vertical moment = My w a ^3= x x ^3 Vert. Moment= TM (Outside face)
1.25
3.2
3.21.2
0.030 1.2
0.030 0.019-0.010 -0.045
1.18
0.39
0.045
0.010 1.2 3.2
0.019 1.2 3.2
1.77
0.75
c
c
c
c
c
c
c
c
2Sterling Wilson Ltd.
ALIF ENGINEERS ANDPLANNERS Design calculation For Burnt Oil pit
DOC.NO:M2011EP008A-88
REV R0
c
c
c
c
c
c
c
c
Depth of wall required = Sqrt ( M/Q b)
d = x 107
x
Required d = Provide overall depth = mm
Provided d = - - = mm
Shear due to oil pressure will cause tension in walls and slab.
Shear coefficients (Taking Maxm values) for b/a =
Sx = Table 7 - IS 3370 Part IV
Tension in wall = Coefficient x x a^2 = x ^2 (depth of oil considered) =
Area of horzt. steel required = M-Tx / t j d + T/t (For Maxm Values of BM)
Horizontal steel outside face = Ast1 + Ast2
1.25
w0.90
3.3592
0.512
0.512 x
200
200 25 12 163
92
0.100x
1000
2.7
1.772.08
c
c
c
c
c
c
c
c
3Sterling Wilson Ltd.
Ast1 = M-Tx / t j d
Ast1 = x 10 ^7 - 10^4 xx 10 ^7 x
= mm2
Ast2 = T/t ` = x 10 ^4
= mm2
Total Ast = Ast1 + Ast2 = + = mm2
Horizontal steel inside face = Ast1 + Ast2Ast1 x 10 ^7
x 10 ^7 x
= mm2
Ast2 = x 10 ^4 `
= mm2Total Ast = Ast1 + Ast2
= + = mm2
Provide Y @ c/c Ast provided = mm2 > mm2 OK
151
3.36
=
295
754
467.22
150
150 0.79
0.53
467
220
12 150 686.9
x
0.79 151
150
219.7
295
224
223.9
1503
519.3
1.18
687
3.36 100
3Sterling Wilson Ltd.
ALIF ENGINEERS ANDPLANNERS Design calculation For Burnt Oil pit
DOC.NO:M2011EP008A-88
REV R0
c
c
c
c
c
c
c
c
Area of Vertical steel required = M / t j d (For Maxm values of BM)
Vertical steel x 10 ^7 = mm2(Outside face) x 10 ^7 x
Vertical steel x 10 ^7 = mm2(Inside face) x 10 ^7 x
Provide Y @ c/c Ast provided = mm2 (Inside face)
Provide Y @ c/c Ast provided = mm2 (Outside face)
Mimimum steel required 0.3 for 100mm to 0.2% for 450mm (Cl. 7.1 IS 3370 part IV)
For thickness of mm mimimum steel shall be = % (10% reduction for HYSD steel)
Minm Area of steel required = x x = mm2
< OK
Design of top slab.Thick =Loads -Span = m d = mm
Self weight = x = T/m2
100
410
0.244
9000.79 163
200
150
100
163
12 100
12
0.25
1501.77
65
0.80.79
200
=
=
1131
1131
11314.40
0.244 4891000
100
4.20
0.100 2.50.1
c
c
c
c
c
c
c
c
4Sterling Wilson Ltd.
Self weight = x = T/m2Live Load = T/m2
Total Load = T/m2
Designing as a two way slab for Ly/Lx = x = Table 26 IS 456
Maximum BM = x x2
= TM
Area of steel required = M-Tx / t j d + T/t (For Maxm Values of BM)
Ast1 required = x 10 ^7 - 10^4 xx 10 ^7 x
= mm2
Ast2 = x 10 ^4 `
= mm2
Total Ast = Ast1 + Ast2 = + = mm2
Provide Y @ c/c Ast provided = mm2 > mm2 OK
Provide minm reinforcement in bottom of slab For mm p = %
Ast = 0.2 x x = mm2
Provide Y @ c/c Ast provided = mm2 > mm2 OK100
10 200 393
236.6
0.7912.678
10 200 393
3.36 x
3.36
0.200
150224
0.056 0.35
100
0.056
0.35
1000 100
0.25
4.20 0.35
1.0
0.100 2.50.1
150 65
200
0.35
200
100
236.612.7 223.9
c
c
c
c
c
c
c
c
4Sterling Wilson Ltd.
ALIF ENGINEERS ANDPLANNERS Design calculation For Burnt Oil pit
DOC.NO:M2011EP008A-88
REV R0
c
c
c
c
c
c
c
c
Design of base slab. Thick d =
Critical - when tank is full
Weight of Roof slab = x x x 2.5 = TWeight of wall = x x x 2.5 x 2.5 = TWeight of oil = x x x 0.9 = TWeight of base slab = x x x 2.5 = T
Total Load = T
Upward pressure = /2
= T/m2 (250mm projection on each side)
Net pressure = - x - x = T/m2
Designing as a two way slab for Ly/Lx = x = Table 26 IS 456
Maximum BM causing tension on liquid side = x x2
= TM
Area of steel required = M-Tx / t j d + T/t (For Maxm Values of BM)
Ast1 required = x 10 ^7 - 10^4 xx 10 ^7 x
= mm2175.09
170
4.40
200
0.10 4.844.4029.92
4.00 4.00 38.94.40
3.57
4.90 4.90
0.20 3.4
0.69
0.056
4.400.056
0.9 2.7 0.2 2.5
150 170100
0.64
0.64
1.0
0.793.36 x0.69
85.65
85.65
3.6
2.70.2
4
4.90
12.01
c
c
c
c
c
c
c
c
5Sterling Wilson Ltd.
= mm2
Ast2 = x 10 ^4 `
= mm2
Total Ast = Ast1 + Ast2
= + = mm2
Provide Y @ c/c Ast provided = mm2 > mm2 OK
Provide minm reinforcement in bottom of slab For mm p = %
Ast = 0.25x x = mm2
Provide Y @ c/c Ast provided = mm2 > mm2 OK
10 150
175
175.09
399.0
399.0
3.36
0.244
1000 200 488
524 48810 150
200
150224
223.9
524
100
c
c
c
c
c
c
c
c
5Sterling Wilson Ltd.